Answer:
A force applied to an object is equal to its mass times acceleration (F=ma)
Explanation:
Answer: The force can be calculated by simply multiplying mass by acceleration
Explanation:
This created the equation F=MA
Critically discuss why the environment in most communities continue to be dirty amidst the existence of local government structures
Explanation:
# Unmanaged population distribution
# lack of sanitation programs
# lack of awareness programs
# lack of implementation of policies and rules
# carelessness of people and government
# Unmanaged waste disposal
what is the relationship between the velocity of a fluid and the size of the sediment that the fluid carries?
The relationship between the velocity of a fluid and the size of the sediment that the fluid carries is directly proportional.
Higher velocity fluids are capable of carrying larger sediments while lower-velocity fluids are capable of carrying smaller sediments. This is due to the fact that higher-velocity fluids have greater kinetic energy, which allows them to overcome the gravitational forces that hold larger sediments in place.
A fluid is a substance that is able to flow and take on the shape of the container it is placed in, with the ability to deform under applied shear stress. Examples of fluids include liquids and gases. In contrast, solids maintain their shape and volume under applied stress.
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which of the following actions will cause the relative humidity of an air parcel to increase? select all that apply
a. Keep the parcel’s temperature constant and increase the parcel’s dew point
b. Decrease the parcels temperature and increasethe parcels dew point
c. Keep the parcel’s temperature constant and keep the parcels dew point constant
d. Increase the parcels temperature and increase the parcels dew point
e. Keep the parcels dew point constant and increase the parcels temperature
The relative humidity of an air parcel will increase if any of the following actions are taken:
Keep the parcel’s temperature constant and increase the parcel’s dew pointDecrease the temperature of the parcel and increase the parcels dew pointIncrease the temperature of the parcel and increase the parcels dew pointKeep the parcels dew point constant and increase the temperature of the parcelWhat is relative humidity?To understand this further, we can look at the formula for relative humidity, which is the amount of water vapor in the air divided by the amount of water vapor that can exist at a particular temperature. When the temperature is kept constant and the dew point increases, the amount of water vapor in the air increases, resulting in an increase in relative humidity.
The followings are the given options and the actions they will take that will cause the relative humidity of an air parcel to increase:
Option A: Keep the parcel's temperature constant and increase the parcel's dew point. This action would increase the RH of the air parcel because it will increase the quantity of water vapor in the air parcel. As the parcel's temperature is constant, the ability of the air to hold water vapor also remains constant.
Option B: Decrease the parcel's temperature and increase the parcel's dew point. This action would also increase the RH of the air parcel. As the temperature of the parcel decreases, the amount of moisture that the air can contain also decreases. When the dew point is raised, the quantity of water vapor in the air parcel rises relative to the amount it can carry.
Option C: Keep the parcel's temperature constant and keep the parcel's dew point constant. In this case, there will be no increase in RH because the quantity of water vapor in the air parcel will remain the same as the ability of the air to hold water vapor remains constant.
Option D: Increase the parcel's temperature and increase the parcel's dew point. Increasing the parcel's temperature will raise the ability of the air to hold water vapor, but it will not increase the amount of water vapor in the air parcel. As a result, the RH of the air parcel will decrease.
Option E: Keep the parcel's dew point constant and increase the parcel's temperature. This action will also decrease the RH of the air parcel as it will increase the amount of moisture that the air can hold. Thus, the relative humidity will decrease.
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A bitmap image is provided in two different resolutions. Image 1 has a resolution of 1500 x 1225. Image 2 has a resolution of 500 x 350. Which of the following statements is true when the sizes of both the files are increased by 25 percent?
Image 1 is sharper than image 2 and has a larger file size than image 2.
The true statement is "Image 1st is sharper than Image 2nd and has a larger file size than Image 2nd"
What is a bitmap image?A bitmap image is a type of digital image that is made up of pixels, which are small squares of color that form an image.
Bitmap image also known as raster images.
Explain image resolution?Image resolution refers to the number of pixels contained in a digital image, typically measured as the number of pixels per inch (PPI) or dots per inch (DPI). The resolution of an image determines the level of detail and clarity that can be seen in the image.
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a train moves from a train station at 30meter per second after 5 seconds its cover the distance of 100 m and the acceleration is ten meters per second square find the speed
The speed of a train that moves from a train station at 30 meters per second after 5 seconds and covers a distance of 100 m with an acceleration of ten meters per second square would be 80 m/s.
Speed of a trainWe can use the equation of motion to solve for the final velocity of the train:
v = u + at
where:
v = final velocityu = initial velocity = 30 m/sa = acceleration = 10 m/s^2t = time = 5 sSubstituting the values, we get:
v = 30 + 10(5)
v = 80 m/s
Therefore, the speed of the train after 5 seconds is 80 m/s.
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a copper wire with a diameter of 1.63 mm and a length of 29.0 m has a current of 15.0 a flowing through the wire. what is the resistance (r) of the wire what is the change in voltage from one end of the wire to the other end
The resistance of the copper wire is approximately 0.026 ohms and the change in voltage from one end of the wire to the other end is approximately 0.39 volts.
To calculate the resistance of the copper wire, we can use the formula:
R = ρL/A
where R is the resistance in ohms, ρ is the resistivity of copper (1.68×10−8 ohm-meters), L is the length of the wire in meters, and A is the cross-sectional area of the wire in square meters.
First, we need to convert the diameter of the wire to meters:
d = 1.63 mm = 0.00163 m
Then, we can calculate the cross-sectional area of the wire:
A = πd2/4 = 2.08×10−6 m2
Now we can plug in the values and solve for R:
R = (1.68×10−8)(29.0)/2.08×10−6 = 0.026 ohms
To calculate the change in voltage from one end of the wire to the other end, we can use Ohm's law:
V = IR
where V is the voltage in volts, I is the current in amperes, and R is the resistance in ohms.
Plugging in the values, we get:
V = (15.0)(0.026) = 0.39 volts
Therefore, the change in voltage from one end of the wire to the other end is approximately 0.39 volts.
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An object is released from rest a height h above the ground. A second object with four times the mass of the first if released from the same height the potential energy of the second object compared to the first is a. four times moors. b. twice as much. c. the same d. sixteen times more.
Answer:
A. Four times
Explanation:
Gravitational Potential Energy (PE) is given as PE=mass*gravity*height
setting the equations of potential energy equal to each other for each object you get
m1gh=m2gh
then you can cancel out the gravity and height and get
m1=m2
then we know the mass of the second object is 4 times the mass of the first object so
m2=4m1
2.1 [2] As more resistors are added in series, the equivalent resistance of the circuit approaches infinity. In contrast, as more resistors are added in parallel, the equivalent resistance a. approaches infinity b. approaches zero c. becomes zero d. approaches 1 Ω
2.2 [2] Kirchhoff's loop rule is equivalent to which of the following principles? a. conservation of charge b. conservation of energy c. conservation of mass d. conservation of force
2.1 As more resistors are added in parallel, the equivalent resistance approaches zero
2.2 Kirchhoff's loop rule is equivalent to the conservation of energy principle.
As more resistors are added in series, the equivalent resistance of the circuit approaches infinity. In contrast, as more resistors are added in parallel, the equivalent resistance approaches zero. This statement is TRUE. The equivalent resistance, Req, of a parallel combination of resistors is less than any of the resistors in the combination, while for a series combination it is equal to the sum of the resistances.
Kirchhoff's loop rule is equivalent to the conservation of energy principle. Kirchhoff's loop rule or Kirchhoff's voltage law (KVL) is a result of the conservation of energy principle. The principle of conservation of energy states that energy can neither be created nor destroyed, it can only be transformed from one form to another. In a closed loop, the total energy gained is equal to the total energy lost, according to the principle of conservation of energy.
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a car is traveling with a velocity of 17.0 m/s on a straight horizontal highway. the wheels of the car have a radius of 48.0 cm. if the car then speeds up with an acceleration of 2.10 m/s for 5.10 s, find the number of revolutions of the wheels make during this period
The wheels make approximately 47.65 revolutions during the 5.10 s period.
What is Linear Speed?
Linear speed, also known as tangential speed, is the distance traveled by an object in a circular path per unit of time, measured in units such as meters per second (m/s) or kilometers per hour (km/h). It is the magnitude of the velocity vector of an object moving in a circular path at a constant speed, and is perpendicular to the centripetal acceleration vector.
The linear speed of the wheels is equal to the velocity of the car:
v = 17.0 m/s
The circumference of the wheels is:
C = 2πr = 2π(0.48 m) = 3.01 m
The angular speed of the wheels is related to the linear speed by:
ω = v/r
Therefore, the initial angular speed of the wheels is:
ω₀ = v/r = 17.0 m/s / 0.48 m = 35.42 rad/s
The final angular speed of the wheels after accelerating for 5.10 s at a constant rate of 2.10 m/s² is given by:
ω = ω₀ + αt
where α is the angular acceleration of the wheels. Since the wheels are assumed to roll without slipping, the linear acceleration of the car is equal to the angular acceleration of the wheels:
α = a/r = 2.10 m/s² / 0.48 m = 4.38 rad/s²
Substituting the given values into the equation for angular speed, we have:
ω = 35.42 rad/s + (4.38 rad/s²)(5.10 s) = 58.64 rad/s
The number of revolutions made by the wheels during this period is equal to the change in the angle of rotation of the wheels:
Δθ = ωt
Substituting the given values, we have:
Δθ = (58.64 rad/s)(5.10 s) = 299.58 rad
The number of revolutions is equal to the angle of rotation divided by 2π:
n = Δθ / 2π = 299.58 rad / 2π ≈ 47.65 revolutions
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What is the length of the x-component of the vector shown below?
The length of the x-component of the vector is approximately 48.55 units.
What is the length of the x-component of the vector?To find the length of the x-component of the vector, we need to use trigonometry.
We can use the angle and the magnitude (length) of the vector to find the x-component using the formula:
x-component = magnitude x cos(angle)
Plugging in the values given, we get:
x-component = 52 units x cos(21⁰)
x-component = 52 units x 0.9336
Multiplying these two numbers, we get:
x-component ≈ 48.55 units
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An asteroid Swift ha 3700 n on Earth what is the masa of the asteroid?
The mass of the asteroid Swift is approximately 377.55 kg.
What is mass?Mass can be best described as the amount of matter present in any object or body.
On Earth, the acceleration due to gravity is approximately 9.8 m/s^2.
To calculate the mass of the asteroid Swift, we will convert its weight from newtons to kilograms (kg), which is the unit of mass in the International System of Units (SI):
Weight = 3700 N
Acceleration due to gravity on Earth (g) = 9.8 m/s^2
Weight = Mass x Acceleration due to gravity
Mass = Weight / Acceleration due to gravity
Mass = 3700 N / 9.8 m/s^2
Mass = 377.55 kg
In conclusion, The mass of the asteroid Swift is approximately 377.55 kg.
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is the current flowing out of a resistor smaller than the current flowing into it. if not, then do resistors not actually slow down the flow of charge. eplain and give exampes\
The current flowing out of a resistor is typically smaller than the current flowing into it. Resistors do not actually slow down the flow of charge, they merely convert electrical energy into heat.
The statement that the current flowing out of a resistor is smaller than the current flowing into it is correct. This is because resistors slow down the flow of charge. The amount of current flowing through a resistor is determined by the amount of voltage across the resistor and the resistance of the resistor. When the voltage across the resistor increases, the current flowing through it also increases.
Conversely, when the resistance of the resistor increases, the current flowing through it decreases. Resistors are used to control the flow of current in electrical circuits. They are used in a variety of applications, such as in voltage dividers, filters, and voltage regulators.
For example, a voltage divider is a circuit that divides a voltage into two or more parts. A voltage divider is made up of two resistors in series, and the output voltage is taken across one of the resistors. The amount of voltage across the output resistor is determined by the values of the two resistors.
If the two resistors are equal, the output voltage will be half the input voltage. If the output resistor is smaller than the input resistor, the output voltage will be less than half the input voltage. Conversely, if the output resistor is larger than the input resistor, the output voltage will be greater than half the input voltage.
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a 421 kg block is puled up a 4.54 degree incline by a constant force f of 3282 n. the coefficient of friction mu between the block and the plane is 0.47. how fast in m/s will the block be moving 6 seconds after the pull is applied?
The block will be moving at 3.97 m/s 6 seconds after the pull is applied.
Given Mass of the block, m = 421 kg, Inclined angle, θ = 4.54°, Force applied, F = 3282 N, Coefficient of friction, μ = 0.47, Time, t = 6 s
Using Newton's second law of motion, F - μmg sin θ = ma
Where,
m = Mass of the block
g = Acceleration due to gravity
a = Acceleration of the block
Substituting the given values,
3282 - 0.47 × 421 × 9.81 × sin 4.54° = 421 × a
a = 0.6614 m/s²
Using kinematic equations of motion,
v = u + at
Where,
u = Initial velocity
v = Final velocity
a = Acceleration
t = Time
Since the initial velocity is zero, the above equation becomes
v = at
Substituting the values,
v = 0.6614 m/s² × 6 s
v = 3.97 m/s
Therefore, the block will be moving at 3.97 m/s 6 seconds after the pull is applied.
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a 3 3-inch candle burns down in 12 hours. if b represents how much of the candle, in inches, has burned away at any time given in hours, t, write a proportional equation for b in terms of t that matches the context.
The proportional equation that matches the context of a 33-inch candle burning down in 12 hours is b = 2.75t.
A candle that is 33 inches long is called a 33-inch candle. Candles are a popular decorative item that is commonly used for lighting, as decoration for weddings, and parties, or to create an aromatic atmosphere. B represents the length of the candle that has burned away at any time given in hours, t.
To find the proportional equation for b in terms of t that matches the context of a 33-inch candle burning down in 12 hours, the following steps should be followed:
Identify the given informationThe length of the candle (l) = 33 inchesThe time taken for the candle to burn down (t) = 12 hours
Determine the rate of burning The rate of burning of the candle is given by l/t. Therefore, the rate of burning = 33/12 = 2.75 inches per hour.
The proportional equation for b in terms of t is given by b = rt where r is the rate of burning. Therefore, b = 2.75t.
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An aircraft of mass 3.2 * 10^5 kg accelerates along a runway. calculate the change in kinetic energy in mega joules when the aircraft accelerates a) 0 to 10m/s b) From 30m/s to 40 m/s c) From 60m/s to 70m/s
Explanation:
E=(mv²)/2 ΔE = E2-E1 = (m(v2²-v1²))/2 = ?
от этогo:
а) ΔE = 16 MДж
б) ΔE = 112 МДж
c) ΔΕ = 208 МДж
Suppose two protostars form at the same time, one with a mass of 0.5 msun and the other with a mass of 15 msun . Which of the following statements are true?
[Select ALL answers that are true in alphabetical order]
A) The 10MSun protostar will have a smaller change in surface temperature during this phase than the 0.5MSun protostar.
B) The 10MSun protostar will reach the main sequence cooler and fainter than the 0.5MSun protostar.
C) The 10MSun star will end its main-sequence life before the 0.5MSun star even completes its protostar stage.
D) The 10MSun protostar will have a smaller change in luminosity during the sequence shown than the 0.5MSun protostar.
E) The 10MSun protostar will be much more luminous than the 0.5MSun protostar.
The two protostars form at the same time, the 10MSun star will end its main-sequence life before the 0.5MSun star even completes its protostar stage, and 10MSun will be much more luminous than the 0.5MSun protostar. Thus, options C and E are correct.
More massive stars have shorter lifetimes because they burn through their nuclear fuel more quickly.
Therefore, the 10MSun star will end its main-sequence life before the 0.5MSun star even completes its protostar stage. Thus, option C is correct.
The luminosity of a star depends on its mass.
More massive stars have higher luminosities than less massive stars. Therefore, option E is correct.
Thus, options C and E are correct.
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A 12100 kg railroad car is coasting on a level, frictionless track at a speed of 19.0 m/s when a 4790 kg load is dropped onto it.
If the load is initially at rest, find the new speed of the car and the % change of the kinetic energy.
Hint 1: If the load is dropped into the car, it is like the car is "colliding� with a stationary load. If the load is stuck in the car, can they have different final velocities from one another?
The percent change in the kinetic energy of the system is [(0.5*(12100 + 4790)*1722) - 5.58 x 106] / (5.58 x 106) x 100% = 4.41%.
The 12100 kg railroad car is initially travelling at a speed of 19.0 m/s and has a kinetic energy of KE = 0.5*12100*1902 = 5.58 x 106 Joules. The 4790 kg load is dropped onto the car from rest, so its initial kinetic energy is 0.
When the load is dropped onto the car, the two objects collide and their velocities after the collision will be equal. Therefore, the final speed of both the railroad car and the load will be v = (12100*19 + 4790*0) / (12100 + 4790) = 17.2 m/s. The percent change in the kinetic energy of the system is [(0.5*(12100 + 4790)*1722) - 5.58 x 106] / (5.58 x 106) x 100% = 4.41%.
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a circuit with a ba[ery and a variable resistor is near a loop of wire as shown. when the resistance r is decreased, the induced current in the loop is
The current in the battery increases and the magnetic field generated is stronger, which causes a larger induced current in the wire loop. This current will also be in the opposite direction of the battery current.
A circuit with a battery and a variable resistor near a loop of wire will cause an induced current in the loop when the resistance of the resistor is decreased. This is known as electromagnetic induction, which occurs when the current in the loop of wire changes, generating a changing magnetic field. This magnetic field then causes a current in the nearby wire loop. In this case, when the resistance of the resistor is decreased,
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The tires of a car make 95 revolutions as the car reduces its speed uniformly 95 km/h to 55 km/h. The tires have a diameter of 0.80 m. (a) what was the angular acceleration of the tires? If the car continues to decelerate at this rate, (b) how much more time is required for it to stop, and (c) how far does it go?
(a) Angular acceleration of the tyres= 7.3 rad/s^2
(b) Time required to stop= 8.9 s
(c) Distance travelled= 492.5 m
The angular acceleration of the tires can be calculated by using the following equation:
Angular acceleration = (Change in angular velocity)/(time).
Using the given information, we can calculate the angular acceleration as follows:
Angular velocity = (95 revolutions)/(95 km/h)
Time = (95 km/h - 55 km/h)/(95 km/h)
Angular acceleration = (95 revolutions)/(Time x 0.80 m)
Angular acceleration = 7.3 rad/s^2
For part b, the amount of time required for the car to stop can be calculated as follows:
Time = (55 km/h)/(7.3 rad/s^2 x 0.80 m)
Time = 8.9 s
For part c, the distance the car travels can be calculated as follows:
Distance = (55 km/h x 8.9 s)
Distance = 492.5 m
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hydroelectric dams generate electricity by question 20 options: a. using the energy of the river to produce steam. b. using run-of-the-river systems, in which turbines are placed into the natural water flow. c. water impoundment, in which dam operators control the rate of water flow to turbines. d. using generators that are placed on the bottom of a river. e. converting the kinetic energy of the water impounded behind a dam into potential energy.
Hydroelectric dams generate electricity through water impoundment, in which dam operators control the rate of water flow to turbines.
c is the correct option.
Hydroelectric dams are dams used to produce electricity. The movement of water drives turbines, which power generators that generate electricity.
The movement of water, generated by gravity, is what drives turbines. Hydroelectric dams are the most widely used renewable energy source, accounting for approximately 16% of global electricity production.
Hydroelectric dams generate electricity through water impoundment, in which dam operators control the rate of water flow to turbines.
This is the process of using turbines that are powered by the movement of water that has been dammed to generate electricity.
Turbines are powered by water that has been dammed to generate electricity, which is then sent to a power station to be used.
The electricity generated from hydroelectric dams is clean and safe, making it an important part of the renewable energy mix. They are also an essential part of the global infrastructure because they provide reliable, low-cost power.
They also assist in the management of rivers, flood control, and irrigation systems in various parts of the world.
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upslope fog hugging the mountain surface occurs when: question 12 options: a. air warms because of decreasing atmospheric pressure
b. eventually air cools to the dew-point temperature air warms because of decreasing atmospheric pressure
c. eventually air warms to the dew-point temperature air cools because of increasing atmospheric pressure
d. eventually air cools to the dew-point temperature air cools because of decreasing atmospheric pressure
e. eventually air cools to the dew-point temperature
A decrease in atmospheric pressure eventually causes air to cool to the dew-point temperature.
How does surface-hugging upslope fog on mountains occur?Fog on an upward slope forms adiabatically. The process through which ascending air cools and sinking air warms is known as adiabatic cooling. The air rises and cools as wet breezes blow in the direction of a mountain. The dew point temperature is reached as a result of the rising air cooling.
Upslope fog: what is it?This type happens when air is lifted by sloping terrain and is adiabatically cooled to its dew point and saturation. Depending on the observer's frame of reference, upslope fog can be seen as either a stratus cloud or a fog.
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A ball rolls across the floor, slowing down with constant acceleration of magnitude . The ball has positive velocity ???? after rolling a distance x across the floor.
Calculate the ball's initial speed ????0 if ????= 4.51 m/s2, ????=11.17 m/s, and x=2.66 m.
A ball rolls across the floor, slowing down with a constant acceleration of magnitude a = 4.51 m/s2.
The ball has positive velocity v after rolling a distance x = 2.66 m across the floor.
To calculate the ball's initial speed v0 if
v = 11.17 m/s.
The initial velocity of the ball, v0 =?
The final velocity of the ball, v = 11.17 m/s
The acceleration of magnitude a = 4.51 m/s2
Distance travelled, x = 2.66 m
If an object has initial velocity v0, constant acceleration a, and travelled distance x, then its final velocity is given by:
v2 = v0² + 2ax
Here, the ball's initial velocity is v0, and its final velocity is v.
After substituting the given values, we have:
v2 = v0² + 2ax
=> (11.17)²
= v0² + 2(4.51)(2.66)
=> 124.57
= v0² + 25.39
=> v0² = 124.57 - 25.39
=> v0² = 99.18 => v0 = √99.18
=> v0 = 9.96 m/s
Hence, the initial velocity of the ball is v0 = 9.96 m/s.
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Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods a)Find the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane (an axis through point O). b)Find the moment of inertia of the system about an axis bisecting two opposite sides of the square (an axis along the line AB). c)Find the moment of inertia of the system about an axis that passes through the centers of the upper left and lower right spheres and through point O.
The moment of inertia of the system for the three situations are 0.026667 kg m2,0.04 kg m2,0.013333 kg .
Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods
a) The moment of inertia of the system about an axis
through the center of the square,
perpendicular to its plane (an axis through point O) is equal to
4 x 0.200 kg x (0.400 m)2/12
= 0.026667 kg m2.
b) The moment of inertia of the system about an axis
bisecting two opposite sides of the square (an axis along the line AB) is equal to
4 x 0.200 kg x (0.400 m)2/8
= 0.04 kg m2.
c) The moment of inertia of the system about an axis
that passes through the centers of the upper left and lower right spheres and
through point O is equal to
2 x 0.200 kg x (0.400 m)2/12
= 0.013333 kg m2.
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water flows through a pipe with a cross-sectional area of 0.002 m2 at a mass flow rate of 4 kg/s. the density of water is 1 000 kg/m3. determine its average velocity. multiple choice question. 0.02 m/s 2 m/s 200 m/s 20 m/s 0.2 m/s
The average velocity of water flowing through a pipe with a cross-sectional area of 0.002 m² at a mass flow rate of 4 kg/s is 2 m/s.
What is the formula for average velocity?The formula for average velocity is:
v = Q / A
Where:
v is the average velocityQ is the volume flow rateA is the cross-sectional area of the pipeThe formula for volume flow rate is:
Q = m / ρ
Where:
m is the mass flow rateρ is the density of the fluidSubstituting the values:
v = Q / Av = (m / ρ) / Av = m / (ρA)Given that the cross-sectional area of the pipe is 0.002 m², the mass flow rate is 4 kg/s, and the density of water is 1000 kg/m³, the average velocity is:
v = 4 / (1000 × 0.002)v = 2 m/sTherefore, the average velocity of water flowing through a pipe with a cross-sectional area of 0.002 m² at a mass flow rate of 4 kg/s is 2 m/s.
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where are pisa and boston in relation to the moon when they have high tides?
The locations of Pisa and Boston in relation to the Moon have no bearing on the times of high tides. High tides are caused by the gravitational pull of the Moon on the Earth's oceans. The Moon's gravitational pull causes the oceans to bulge out towards the Moon, resulting in the two high tides per day.
The two high tides occur about 12 hours and 24 minutes apart, and the location of the Moon in the sky is always changing. During full moon and new moon, when the Moon is in alignment with the Sun, the gravitational pull of both celestial bodies is at its strongest, resulting in higher high tides.
The location of Pisa and Boston has no effect on high tide times, but they may experience higher tides due to local geography. If Pisa or Boston are near the ocean, their local geography may cause the tide to be higher or lower than normal. Additionally, weather conditions can also have an effect on local tide levels.
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if the true stress - true plastic strain curve can be described by the hollomon equation , obtain the true strain at the onset of necking in terms of hollomon equation parameters
The true strain at the onset of necking can be obtained from the Hollomon equation as follows: true strain = (K/S)^(1/n).
Here, K is the strength coefficient, S is the stress, and n is the strain hardening exponent. Thus, given the values of these parameters, we can calculate the true strain at the onset of necking.
The Hollomon equation is a mathematical expression for the true stress-true strain curve that relates the true stress to the true strain in a material. It is expressed as follows: true stress = K(true strain)^n. Here, K is the strength coefficient and n is the strain hardening exponent.
The true strain at the onset of necking is the strain at which the material starts to deform plastically instead of elastically. This can be obtained from the Hollomon equation by rearranging it to the form true strain = (K/S)^(1/n). Thus, given the values of the parameters K, S, and n, we can calculate the true strain at the onset of necking.
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a painter (of mass 68 kg) needs to reach out from a scaffolding to paint the side of a building, so he lays a plank across two bars of the scaffolding, and puts a heavy bucket of mass 29 kg directly over one of the bars (see figure). you can assume the plank is massless, and is long enough to reach to the other building. Otheexpertta.com If the bars are separated by distance 1 how far; d, from the bar on the the right can the painter walk before the plank starts to fall? Numeric A numeric value is expected and not an expression_
0.99. is the distance from the bar on the right the painter walk before the plank fell.
To solve the given problem, we have to use the principle of moments which states that a body is in rotational equilibrium if the sum of clockwise moments is equal to the sum of anti-clockwise moments.
Let the distance between the painter and the bar on the right be x.
Then the distance between the painter and the bar on the left is 1 − x.
We have to find the maximum value of x for which the plank does not tip over.
As the plank is in equilibrium, the net moment about any point should be zero.
Here we will take the moment about the bar on the left so the clockwise moment will be taken as positive and the anticlockwise moment as negative.
The moment due to the painter will be the product of the mass of the painter, the distance of the centre of gravity of the painter from the left bar which is (1−x)/2, and the acceleration due to gravity.
The moment due to the bucket of 29 kg will be the product of the mass of the bucket, the distance of the centre of gravity of the bucket from the left bar which is x, and the acceleration due to gravity.
The moment due to the plank is zero as the plank is massless and the plank's centre of gravity lies at the centre which is midway between the two bars.
The expression for the principle of moments is shown below:-
m1g (1 - x)/2 + m2g x = 0
where, m1 = mass of painter,
m2 = mass of bucket and
g = acceleration due to gravity
Substituting the given values we get:-
68 (9.8) (1 - x)/2 + 29 (9.8) x = 0
Simplifying the above equation, we get:-
333.4x + 330.4 = 0x = 0.99 m
a painter (of mass 68 kg) needs to reach out from a scaffolding to paint the side of a building, so he lays a plank across two bars of the scaffolding, and puts a heavy bucket of mass 29 kg directly over one of the bars (see figure).
you can assume the plank is massless, and is long enough to reach to the other building. f the bars are separated by distance 1 how far; d, from the bar on the the right can the painter walk before the plank starts to fall.
Thus, the painter can walk to a distance of 0.99 m from the right bar before the plank starts to fall.
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I need to figure out the missing boxes and work out the power, work done or time taken
To calculate the missing values in the table, we can use the formulas:
Power = Work Done / Time TakenWork Done = Power x Time TakenTime Taken = Work Done / PowerUsing these formulas, we can fill in the missing values:
Power(W) Work Done(J) Time Taken(s)
For a,. 3000 90000 30
For b,. 20 100 5
For c,. 50 100 2
For d. 700 245 0.35
For e. 25 1875 75
For f. 50000 500000 10
For g. 150 450 3
For h. 0.5 10 20
What is power?
Power is the rate at which work is done or energy is transferred. Mathematically, power is defined as the amount of work done or energy transferred per unit time. The unit of power is the watt (W), which is equal to one joule of work per second.
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To calculate the missing values in the table, we can use the formulas:
Power = Work Done / Time Taken
Work Done = Power x Time Taken
Time Taken = Work Done / Power
Using these formulas, we can fill in the missing values:
Power(W) Work Done(J) Time Taken(s)
For a,. 3000 90000 30
For b,. 20 100 5
For c,. 50 100 2
For d. 700 245 0.35
For e. 25 1875 75
For f. 50000 500000 10
For g. 150 450 3
For h. 0.5 10 20
What is power?
Power is the pace at which labour or energy is done or transferred. Power is described mathematically as the quantity of labour done or energy moved per unit time. The watt (W) is the measure of electricity, and it equals one joule of work per second.
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A plane has an airspeed of 200 mph. The pilot wishes to reach a destination 900 mi due east, but a wind is blowing at 20. 0 mph in the direction 60. 0 ∘ north of east
The plane's heading is 4.61 degrees south of east, which is the direction the pilot needs to steer the plane in order to reach her objective and the trip takes 1.83 hours.
The airspeed of 200 mph can be broken down into its x and y components as follows: Vx = 200 mph * cos (0°) = 200 mph Vy = 200 mph * sin (0°) = 0 mph To solve this problem, we can break down the velocity vectors into their x and y components: The airspeed of 200 mph can be broken down into its x and y components as follows: Vx = 200 [tex]mph * cos (0°) = 200 mph Vy = 200 mph * sin (0°) = 0 mph[/tex]
The wind velocity of 20.0 mph at an angle of 60.0° north of east can be broken down into its x and y components as follows:[tex]Vwx = 20.0 mph * cos(60.0°) = 10.0 mph Vwy = 20.0 mph * sin(60.0°)[/tex] = 17.3 mph The resultant velocity vector is the vector sum of the airspeed and the wind velocity: Vrx = Vx + Vwx = 200 mph + 10.0 mph = 210 mpm Vry = Vy + Vwy = 0 mph + 17.3 mph = 17.3 mph
The speed of the plane relative to the ground is the magnitude of the resultant velocity vector:[tex]|Vr| = sqrt (Vrx^2 + Vry^2) = sqrt ((210 mph) ^2 + (17.3 mph) ^2) ≈ 211[/tex]mph The direction of the plane's velocity relative to the ground is given by the angle that the resultant velocity vector makes with due east:[tex]θ = atan(Vry / Vrx) = atan(17.3 mph / 210 mph) ≈[/tex] 4.7° north of east
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Complete question is :
A Plane Has An Airspeed Of 200 Mph. The Pilot Wishes To Reach Adestination 600 Mi Due East, But A Wind Is Blowing At 50 Mph In Thedirection 30o North Of Eastpart Ain What Direction Must The Pilot Head The Plane In Order To Reachher Destination? (2sig Figs)Part Bhow Long Will The Trip Take?(2 Sig Figs)Thanks!
a plane has an airspeed of 200 mph. the pilot wishes to reach adestination 600 mi due east, but a wind is blowing at 50 mph in thedirection 30o north of east
part A
in what direction must the pilot head the plane in order to reachher destination?
part B
how long will the trip take?
When a person is involved in a car accident, why is the likelihood of injury greater in a head-on collision as opposed to being hit from behind? Answer using the concepts of relative velocity, momentum, and average force. (Select all that apply. )
1. The change in momentum is greater in the head-on collision.
2. The momentum of the driver relative to the ground is greater in a head-on collision.
3. The velocity of the driver relative to the ground is greater in a head-on collision. 4. The average force on the driver is greater in the head-on collision.
5. The collapse of the crumple zone in the front of the car occurs only in the head-on collision
The proper responses are: The head-on collision results in a bigger change in momentum. In a head-on collision, the driver is subjected to a greater average force.
Explanation: When an automobile collides, the external force acting on it causes a change in the vehicle's momentum. ... a The shift in momentum is greater in a head-on collision because the relative speeds of the two vehicles are higher. This increases the probability of injury because more force is being exerted to the car and its occupants. In addition, due of the shorter duration of impact in a head-on collision, the average force on the driver is higher. in a crash with the back. As a result, there is a higher average force since the force is delivered for a shorter period of time. Although this happens in both head-on and rear-end collisions, the collapse of the crumple zone in the front of the automobile also helps to absorb impact energy. The chance of injury in a collision is not primarily determined by the driver's momentum and velocity in relation to the ground, however they may have an impact on the degree of the injury.
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