Explain a principal of moments of a force
The principle of moments states that when a body is balanced the total clockwise moment about a point equals the total anticlockwise moment about the same point.Equation.Moment=Force F×perpendicular distance from the pivot do.
Write an equation of the line in slope-intercept form.
Please explain.
Answer:
y = [tex]-\frac{1}{4}[/tex]x + 3
Explanation:
The equation of a straight line is given as:
y = mx + c
y and x are the coordinates
m is the slope
c is the y -intercept
The y-intercept = 3;
Slope = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
x₁ = 0
x₂ = 4
y₁ = 3
y₂ = 2
Slope = [tex]\frac{2-3}{4 -0 }[/tex] = [tex]-\frac{1}{4}[/tex]
y = mx + c
y = [tex]-\frac{1}{4}[/tex]x + 3
PLZ EXPLAIN THE EQUATION AND I WILL GIVE BRAINLIST You are out and about in the country and your father sees a rock that he really wants in the yard. Now you must get the very heavy rock into the back of a truck. The truck bed is 3 feet off the ground. Your father pulls out a 5-foot plank and begins to set up a ramp. At the same time, you (who know about mechanical advantage!) have found a plank that is 8 feet long, and you show it to your father. Which plank will give you the most mechanical advantage? Calculate the MA for each plank
Answer:
The 8 foot long plank
Explanation: hope this helps :)
On the moon, the gravity is 1/6 that of Earth. While on the moon, Buzz Aldrin carried on his back a support system that would weigh over 1760 N on Earth. a) What did the backpack weigh on the moon? b) What was its mass on the moon? please show the work
Answer:
a) 293.[tex]\bar 3[/tex] N
b) Approximately 179.41 kg
Explanation:
The given parameters are;
The gravity (gravitational acceleration) on the moon = 1/6 × The gravity on Earth
The weight of the support system Buzz Aldrin carries = 1760 N
a) Given that the weight of the support system on Earth = Mass of the support system, m × Gravity, g (Acceleration due to gravity) = m·g
The weight of the support system on Earth = m·g
We have;
The gravity on the moon = 1/6 × g
∴ The weight of the support system on the moon = Mass of the support system, m × 1/6 × g = m·g/6
∴ The weight on the of the support system on the moon = m·g/6 = 1/6 × m·g = 1/6 × m·g = 1/6 × The weight of the support system on Earth
The weight on the of the support system on the moon = 1/6 × 1760 N = 880/3 N = 293.[tex]\bar 3[/tex] N
b) The mass, m, of the support system on the moon = The mass, m, of the support system on Earth
The mass, m, of the support system on Earth = Weight of the support system/(Gravity(acceleration due to gravity))
∴ The mass, m, of the support system on Earth = 1760/9.81 ≈ 179.41 kg
∴ The mass, m, of the support system on the moon ≈ 179.41 kg.
A skydiver jumps from a plane and falls for 5 seconds before reaching his terminal velocity. During this 5 seconds interval, describe his acceleration before reaching terminal velocity?
Answer:
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m
Explanation:
The terminal velocity is the maximum steady velocity attained by a body falling freely with increasing velocity from rest in a fluid, such as air or water
The net force, F acting on the body falling through the fluid is given as follows;
F = Weight force, W, from gravity - Drag force, D, from the fluid
F = W - D
Given that F = Mass, m × Acceleration, a, we have;
F = m × a
The acceleration, a = F/m = (W - D)/m
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m.
An object with a mass of 15 kg accelerates 10.0 m/s2 when an unknown force is applied to it. What is the
amount of the force
Answer:
f=mass × acceleration
=15×10
=150
The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.0059 m/s/s, what is the sun’s acceleration toward the Earth?
Answer:
this is the answer according to my calculations
Explanation:
0.001.9
Unit 2 kinetic energy mastery test
Answer: kinetic energy is Energy of motion.
Explanation:
A motorist, traveling east on an open highway, sets his cruise control at 90.0 km/h. How far will he travel in 0.75 hours?
Answer:
The answer is 67.5 kmExplanation:
The distance covered by an object given it's velocity and time taken can be found by using the formula
distance = velocity × time
From the question we have
distance = 90 × 0.75
We have the final answer as
67.5 kmHope this helps you
Answer: 67.5 km
Explanation:
Distance is the velocity and time.
90 x 0.75 = total distance
The distance is represented as 67.5 km/h.
Hope this helps!
Which of the following is true regarding mixtures? a. One substance not combined with any other substances. b. Two or more substances physically mixed and can be separated. c. Two or more substances that are impossible to separate d. One substance that forms a compound alone.
Answer:
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dggzsd
Explanation:
szsdrgzsedg
Calculate the density of a rock that has a mass of 32 grams and a volume of
4.5 mL.
Answer:
85.2ml
Explanation:
