HELPPPP ME ASAP
If f(x) = x2, g(x) = 5x, and h(x) = x +4, find each value.
Find g[h(-2)]
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Answer:
10
Step-by-step explanation:
Put the values where the arguments are and do the arithmetic.
g(h(-2)) = g(-2+4) = g(2) = 5(2)
g(h(-2)) = 10
Which law would you use to simplify the expression?
Answer:
A. quotient of Powers
Step-by-step explanation:
hope it helps
Answer:
A. Quotient of powers
Step-by-step explanation:
Hope it helps
on the provided graph, plot the points where the following function crosses the x-axis and the y-axis g(x) = -5^x + 5, what does the graph look like?
Answer:
see image
Step-by-step explanation:
A plane flying horizontally at an altitude of 2 miles and a speed of 410 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 5 miles away from the station.
Answer:
[tex]82\sqrt{21}\text{ or approximately 375.77 miles per hour}[/tex]
Step-by-step explanation:
Please refer to the diagram below. R is the radar station and x is the distance from the station to the plane.
We are given that the plane is flying horizontally at an altitude of two miles and at a speed of 410 mph. And we want to find the rate at which the distance from the plane to the station is increasing when it is five miles away from the station.
In other words, given da/dt = 410 and x = 5, find dx/dt.
From the Pythagorean Theorem:
[tex]a^2+4=x^2[/tex]
Implicitly differentiate both sides with respect to time t. Both a and x are functions of t. Hence:
[tex]\displaystyle 2a\frac{da}{dt}=2x\frac{dx}{dt}[/tex]
Simplify:
[tex]\displaystyle a\frac{da}{dt}=x\frac{dx}{dt}[/tex]
Find a when x = 5:
[tex]a=\sqrt{5^2-2^2}=\sqrt{21}[/tex]
Therefore, dx/dt when da/dt = 410, x = 5, and a = √(21) is:
[tex]\displaystyle \frac{dx}{dt}=\frac{(\sqrt{21})(410)}{5}=82\sqrt{21}\approx 375.77\text{ mph}[/tex]
The rate at which is distance from the plane to the radar station is increasing at a rate of approximately 375.77 miles per hour.
The figure shown represents a roof truss
design. Based on the markings on the figure,
which of the triangles can you prove are
congruent?
OPTION C is the correct answer.
The ΔAFE ≅ ΔBHG by the angle, side and angle theorem are congruent. Option (A) is correct.
What is the triangle?Triangle is a polygon that has three sides and three angles. The sum of the angle of the triangle is 180 degrees.
The figure shows models of a roof truss. Based on the markings, there is enough information to prove that
ΔAFE ≅ ΔBHG
∠EFA=∠GHB (90 degrees )
EF = GH (equal side)
EAF = GBH (the side opposite to the angle is equal)
ΔAFE ≅ ΔBHG (ASA )
Thus, ΔAFE ≅ ΔBHG by the angle, side and angle theorem are congruent.
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A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression. How many people clicked on the banner ad
Answer:
300
Step-by-step explanation:
[tex] \frac{1.5}{100} = 20000 \\ 20000 \div 100 = 200 \\ 200 \times 1.5 = 300[/tex]
if A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression then 300 people clicked on the banner ad
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression.
We need to find how many people clicked on the banner ad.
Let us find the value of 1.5% of 20000
Convert 1.5 % to decimal
1.5/100=0.015
Now multiply 0.015 with 20000
0.015×20000
300
Hence, if A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression then 300 people clicked on the banner ad
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Graph the solution set to this Inequality.
-2x + 9 < 51 12
Answer:
X<-2551.5
Step-by-step explanation:
-2x<5112-9
-2x/-2<5103/-2
x<-2551.5
Which property is demonstrated by this expression? 142 x 1 = 142 One Associative Commutative
Step-by-step explanation:
It is Associative property, I have seen this somewhere
An arch is in the form of a parabola given by the function h = -0.06d^2 + 120, where the origin is at ground level, d meters is the horizontal distance and h is the height of the arch in meters.
Graph this function on your graphing calculator then complete the following statements.
The height of the arch is: ------- m
The width to the nearest meter, at the base of the arch is ------ m
Answer:
See attachment for graph
The height of the arch is: 120 m
The width to the nearest meter, at the base of the arch is 22 m
Step-by-step explanation:
Given
[tex]h = -0.06d^2 + 120[/tex]
Solving (a): The graph
See attachment for graph
Variable h is plotted on the vertical axis while variable d is plotted on the horizontal axis.
Solving (b): The height
The curve of [tex]h = -0.06d^2 + 120[/tex] opens downward. So, the maximum point on the vertical axis represents the height of the arch,
Hence:
[tex]height = 120[/tex]
Solving (c): The width
The curve touches the horizontal axis at two different points.
[tex]x_1 = -11[/tex]
[tex]x_2 = 11[/tex]
The absolute difference of both points represents the width.
So:
[tex]Width = |x_2 - x_1|[/tex]
[tex]Width = |11 - -11|[/tex]
[tex]Width = |11 +11|[/tex]
[tex]Width = |22|[/tex]
Hence:
[tex]Width = 22[/tex]
A person is standing close to the edge on a 56 foot building and throws the ball vertically upward. The quadratic function h(t)=-16^2+104t+56 models the balls height above the ground,h(t),in feet, T seconds after it was thrown
what is the maximum height of ball.=
How many seconds did it take to hit the ground=
Please help!
Answer:
Part 1)
225 feet.
Part 2)
7 seconds.
Step-by-step explanation:
The height h(t) of the ball above the ground after t seconds is modeled by the function:
[tex]h(t)=-16t^2+104t+56[/tex]
Part 1)
We want to determine the maximum height of the ball.
Notice that the function is a quadratic with a negative leading coefficient, so its maximum will be at its vertex point.
The vertex of a parabola is given by:
[tex]\displaystyle \text{Vertex} = \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)[/tex]
In this case, a = -16, b = 104, and c = 56.
Find the x- (or rather t-) coordinate of the vertex. So:
[tex]\displaystyle t=-\frac{(104)}{2(-16)}=\frac{104}{32}=\frac{13}{4}=3.25\text{ seconds}[/tex]
In other words, the ball reaches its maximum height after 3.25 seconds.
To find the maximum height, substitute this value back into the function. Hence:
[tex]\displaystyle h(3.25)=-16(3.25)^2+104(3.25)+56=225\text{ feet}[/tex]
The maximum height of the ball is 225 feet in the air.
Part 2)
We want to find the amount of time it took for the ball to hit the ground.
When the ball hit the ground, its height above the ground is zero. Therefore, we can set h(t) to 0 and solve for t:
[tex]0=-16t^2+104t+56[/tex]
We can simplify a bit. Divide both sides by -8:
[tex]0=2t^2-13t-7[/tex]
We can factor. Find two numbers that multiply to 2(-7) = -14 and add to -13.
-14 and 1 works! Therefore, split the second term into -14 and 1:
[tex]\displaystyle 0=2t^2-14t+t-7[/tex]
Factor out a 2t from the first two terms and group the last two terms:
[tex]0=2t(t-7)+(t-7)[/tex]
Factor by grouping:
[tex]0=(2t+1)(t-7)[/tex]
Zero Product Property:
[tex]2t+1=0\text{ or } t-7=0[/tex]
Solve for each case:
[tex]\displaystyle t=-0.5\text{ or } t=7[/tex]
Since time cannot be negative, we can ignore the first case.
Therefore, it takes seven seconds for the ball to hit the ground.
Does the expression represents a positive or negative 3(-2 1/3)
Answer:
Positive
Step-by-step explanation:
This is an equation, with distribution in it. The number on the outside is positive, and the one inside is negative. Furthermore, since the number on the outside is larger than the one inside, the outcome will be positive.
Answer:
positive
Step-by-step explanation:
when both positive and negative will multiply then will makes negatives. so negative is correct option.
HELP AGAIN sorry
What is the measure of ∠AOB?
The measure of angle ∠AOB is 180°. The correct option from the following is (A).
A turn's angle is quantified using degrees or °. A full turn encompasses 360°. A protractor can be used to determine the size of an angle. The term "acute" refers to an angle smaller than 90°. Obtuse refers to an angle between 90° and 180°. Reflex is an angle larger than 180 degrees. Right angles have an angle of exactly 90 degrees.
A quadrilateral is an enclosed form created by uniting four points, any three of which cannot be collinear. A quadrilateral is a polygon that has four sides, four angles, and four vertices. Let us study more about quadrilaterals' shapes, their characteristics, and the various kinds of quadrilaterals, as well as some examples of quadrilaterals.
For the given quadrilateral, the sum of angles is:
∠A + ∠O + ∠B = ∠AOB
60° + 60° + 60° = 180°
Hence, the correct option is (A).
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What angles can you construct using just a pair of compasses and a ruler?
Answer:
By using a pair of compasses and a ruler you can draw all angles
Solve for x in the triangle. Round your answer to the nearest tenth.
Answer:
7.3 units
Step-by-step explanation:
Hi there!
We're given an angle and one leg of this right triangle and we must solve for the other leg. Given this circumstance, we can use the tangent ratio:
[tex]tan\theta=\frac{opposite}{adjacent}[/tex]
Plug in all values
[tex]tan39=\frac{x}{9}\\9*tan39=x\\7.3=x[/tex]
Therefore, the value of x when rounded to the nearest tenth is 7.3 units.
I hope this helps!
I'm not sure how to do this so I'm just asking for help.
Answer:
C
Step-by-step explanation:
In ∆DEG, we are given that all the three angles are congruent.
This means that all the three angles have equal measure. Thus,
<D = <E = <F
An equilateral triangle has equal angle measure. ∆DEF is an equilateral triangle.
Since the sum of a triangle is 180°, therefore, each angle in ∆DEF = 60°
m<D = 60°
Calculate the difference and enter it below
-6 - 12
Answer:
-18
Step-by-step explanation:
Answer: -18 is the difference
Step-by-step explanation:
Evaluate = -18
How many students rank themselves as introverts? Demonstrate your work.
Answer:
36 introverts
Step-by-step explanation:
Total number of adults in the survey = 120
Ratio of introverts to extroverts = 3:7
Number of introverts = ratio number of introverts / ratio total × 120
Ratio number of introverts = 3
Ratio total = 3 + 7 = 10
Number of introverts = 3/10 × 120
= 36
. a) In a group of 75 students, 20 liked football only, 30 liked cricket only and 18 did not like any of two games? (i) How many of them liked at least one game? (ii) Find the number of students who liked both the games. (iii) How many of them liked football? (iv) How many of them liked cricket? (v) Represent the result in a Venn diagram.
i)50
Steps
30+20=50
ii)7
Steps
75-(30+20)-18
=75-(50)-18
=7
iii)20
Steps
From the available data from the question
iv)30
Steps
From the available data from the questionl
v)From the attcged image file
If f(1) =160 and f(n+1)=-2f(n),
What is f(4)?
Answer:
f(n+1=-2f(n)
f(x)=-2f(n)
f(4)
f(4)=-2f(4)
Answer:
f(4) = - 1280
Step-by-step explanation:
Using the recursive rule and f(1) = 60 , then
f(2) = - 2f(1) = - 2 × 160 = - 320
f(3) = - 2f(2) = - 2 × - 320 = 640
f(4) = - 2f(3) = - 2 × 640 = - 1280
Please help me i will give you brainlest
Answer:
a speaker receive credibility is a combination of competence trustworthiness and caring
Can anyone help me please? I've been trying for so long, but I can't figure out the answer to this problem. Picture attached. Thank you so much.
Answer:
C
Step-by-step explanation:
Start by simplifying what you can in each radicalfor example, the
∛(xy⁵)= y∛(xy²)
and
∛(x⁷y¹⁷)=x²y⁵∛(xy²)
So know our equation looks like
y∛(xy²)*x²y⁵∛(xy²)
Now because what's inside the radical is the same we can combine them
y⁶x²∛(xy²)²
distribute the square
so
∛(xy²)²= ∛(x²y⁴)= y∛(x²y)
and finally,
y⁶x²*y∛(x²y)= y⁷x²∛(x²y)
this is equal to option C
Where does the graph of f(x)=2√-x+2 start?
A. (−2,0)
B. (2,0)
C. (0,2)
D. (0,−2)
With a.b.c=1 and a+b+c=1
Prove that:
Answer:
HOPE IT HELPS PLZ MARK ME BRAINLIEST
Step-by-step explanation:
abc=1
⟹c=1/ab
1/(1+a+1/b)+1/(1+b+1/c)+1/(1+c+1/a)
=1/(1+a+1/b)+1/(1+b+ab)+1/(1+1/ab+1/a)
=b/(1+b+ab)+1/(1+b+ab)+ab/(1+b+ab)
=1+b+ab/(1+b+ab)
=1
Drag the label to the correct location on the image
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Answer:
-∞ < y ≤ 12
Step-by-step explanation:
The range is the vertical extent of the graph of the function. Here the function values range from -∞ to a maximum of about 12. An appropriate description is ...
-∞ < y ≤ 12
Evaluate double integral of f(u,v)=∬dudv over region R where R is bounded by v^2-nu=0 , v^2-(n+1)u=0 and uv=n,uv=(n+1). Sketch neat graph and shade the bounded region. Clearly mention the points of intersection. Reverse the order of integration then evaluate. Where n is 100.
Answer:
5670272728262728227627
How do you graph this helppp and explain
Answer:
bottom graph
Step-by-step explanation:
f(x) = |3q-6|
because you have absolute value there are 2 possibilities
y= +(3q-6) and y= -(3q-6)
to find where the graph intersects the x-axis make y=0 because there the y coordinate is 0, so we have...
3q-6 =0 and -3q+6 =0
3q= 6 and -3q =-6
q=2 and q=2
the bottom graph has the intersection with x-axis only at 2, so is the correct one
9514 1404 393
Answer:
bottom graph shown
Step-by-step explanation:
It can be helpful to rearrange the equation to either of the equivalent forms ...
f(x) = |3(x -2)|
or ...
f(x) = 3|x -2|
_____
The first of these forms represents a horizontal compression of the absolute value function by a factor of 3, then a right-shift by 2 units. This matches the bottom graph shown.
__
The second of these forms represents a horizontal right-shift by 2 units, and a vertical expansion by a factor of 3. This matches the bottom graph shown.
__
The attached graph shows the function given here along with the absolute value parent function.
_____
Additional comment
The transformations we're usually interested in are ...
g(x) = k·f(x) . . . . vertically scaled (stretched) by a factor of k
g(x) = f(kx) . . . . .horizontally compressed by a factor of k
g(x) = f(x) +k . . . shifted up by k units
g(x) = f(x -k) . . . . shifted right by k units
In many cases, as here, horizontal scaling and vertical scaling are indistinguishable as to which caused a given effect.
What is the range of the given set of ordered pairs?
(9,-2) (4,3) ( 8, 10) (-4, 8)
Answer:
(-2,3,10,8)
Step-by-step explanation:
eg
(x,y)=(domain,range)
x components are domain and y components are range in the given set of ordered pairs
This Bar Chart shows the number of DVDs sold at a local music store during one week.
Which measure(s) of central tendency can be used to determine the average number of DVDs sold each day?
A. the median
B. the mean
C. the mean and the median
D. the mode
Answer:
B. the mean
Step-by-step explanation:
According to the Bar Chart shown, the number of DVDs sold at a local music store during one week are displayed.
Therefore, the measure(s) of central tendency that can be used to determine the average number of DVDs sold each day is the mean.
This is because the mean is the sum total of the number of DVDs sold, divided by the number, which gives the average.
Answer:
The Mean
Step-by-step explanation:
I took the test
solve 5x^2-2=-12 by taking the square root
Answer:
[tex]x = \sqrt{-2} = 2i[/tex]
Step-by-step explanation:
[tex]5x^2-2=-12[/tex]
[tex]5x^2 =-10[/tex]
[tex]x^2 =-2[/tex]
[tex]x = \sqrt{-2} = 2i[/tex]
Find the solution of the differential equation that satisfies the given initial condition. (dP)/(dt)
Answer:
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
Step-by-step explanation:
Given
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]P(1) = 2[/tex]
Required
The solution
We have:
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]\frac{dP}{dt} = (Pt)^\frac{1}{2}[/tex]
Split
[tex]\frac{dP}{dt} = P^\frac{1}{2} * t^\frac{1}{2}[/tex]
Divide both sides by [tex]P^\frac{1}{2}[/tex]
[tex]\frac{dP}{ P^\frac{1}{2}*dt} = t^\frac{1}{2}[/tex]
Multiply both sides by dt
[tex]\frac{dP}{ P^\frac{1}{2}} = t^\frac{1}{2} \cdot dt[/tex]
Integrate
[tex]\int \frac{dP}{ P^\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Rewrite as:
[tex]\int dP \cdot P^\frac{-1}{2} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the left hand side
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{-1}{2}+1} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]2P^{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the right hand side
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{1}{2} +1 }}{\frac{1}{2} +1 } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{3}{2}}}{\frac{3}{2} } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex] ---- (1)
To solve for c, we first make c the subject
[tex]c = 2P^{\frac{1}{2}} - \frac{2}{3}t^\frac{3}{2}[/tex]
[tex]P(1) = 2[/tex] means
[tex]t = 1; P =2[/tex]
So:
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1^\frac{3}{2}[/tex]
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1[/tex]
[tex]c = 2\sqrt 2 - \frac{2}{3}[/tex]
So, we have:
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + 2\sqrt 2 - \frac{2}{3}[/tex]
Divide through by 2
[tex]P^{\frac{1}{2}} = \frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3}[/tex]
Square both sides
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
