please help me with this

Step-by-step explanation:

You didn't put the graph, but you can compare between your graphs and the picture.

Brainliest please

The graph that represents this inequality y ≥ 4x − 3 is attached below.

If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true. Such values are called solution to that equation or inequality. Set of such values is called solution set to the considered equation or inequality.

We are given that the inequality is;

y ≥ 4x − 3

The slope of the inequality is 4.

The equation of the red line is y = 4x − 3  

The shading is above the line and the line is solid, that means  y is greater than or equal 4x − 3

The graph of this inequality y ≥ 4x − 3 is attached below.

Learn more about inequalities here:

https://brainly.com/question/27425770

#SPJ2

Answer:

D. x = 4,  y = 4, z = 2

Step-by-step explanation

Plugged in given answers as trying to substitute is impossible, already tried all combinations

9514 1404 393

Answer:

Step-by-step explanation:

Let x represent the amount invested at 8%. Then the total interest earned is ...

  0.06(7000 -x) +0.08x = 480

  420 +0.02x = 480 . . . . . . . . . eliminate parentheses

  0.02x = 60 . . . . . . . . . . subtract 420

  x = 60/0.02 = 3000 . . . . . divide by the coefficient of x

$3000 was invested at 8%; $4000 was invested at 6%.

Answer:

vertical line

Step-by-step explanation:

because horizontal means horizon which goes left to right across a board

Hi there!

The y-intercept of a line represents its initial value. On a graph, the y-intercept would represent the value of y when the line crosses the y-axis.

For example, if an equation were to model the amount of money someone had in their bank account overtime starting from the day they opened their account, the y-intercept would represent the original amount of money they had.

I hope this helps!

Answer:

A) quadratic

Step-by-step explanation:

ax2 + bx+c=0

Since the highest power of the equation is 2

A) quadratic -2

B) quartic- 4

C) linear- 1

D) cubic-3

Answer:

Step-by-step explanation: you got trolded

Answer:4 ma boi

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

because I am god at meth and very smart

Answer:

The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.

Step-by-step explanation:

The confidence interval for population variance is given as below:

[tex][(n - 1)\times S^{2} / X^{2} \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2} / X^{2} 1- \alpha/2, n- 1 ][/tex]

We are given

Confidence level = 98%

Sample size = n = 81

Degrees of freedom = n – 1 = 80

Sample Variance = S^2 = 3.23

[tex]X^{2}_{[\alpha/2, n - 1]} = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401[/tex]

(By using chi-square table)

[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]

[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]

2.3004 < σ^2 < 4.8263

Lower limit = 2.30

Upper limit = 4.83.

Step-by-step explanation:

here's the answer to your question

Answer: Distance = 11

Step-by-step explanation:

Concept:

Here, we need to know the idea of the distance formula.

The distance formula is the formula, which is used to find the distance between any two points.

If you are still confused, please refer to the attachment below for a clear version of the formula.

Solve:

Find the distance between A and B, where:

[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]Distance=\sqrt{(4+7)^2+(-4+4)^2}[/tex]

[tex]Distance=\sqrt{(11)^2+(0)^2}[/tex]

[tex]Distance=\sqrt{121+0}[/tex]

[tex]Distance=\sqrt{121}[/tex]

[tex]Distance=11[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

104 m²

Step-by-step explanation:

Area of the whole shape = area of the triangle + area of the rectangle

= ½*b*h + L*W

Where,

b = 8 m

h = 6 m

L = 10 m

W = 8 m

Plug in the values into the equation

Area of the whole shape = ½*8*6 + 10*8

= 24 + 80

= 104 m²

Answer:

C. 11x² - 3x

Step-by-step explanation:

(12x² - 5x) - (x² - 2x)

12x² - 5x - x² + 2x

12x - x² - 5x + 2x

11x² - 3x

Answer:

The number of ways of selecting the team is 26,400 ways.

Step-by-step explanation:

Given;

total number boys in the gym, b = 10 boys

total number of girls in the gym, g = 12 girls

number of team to be selected, n = 6

If there must equal number of boys and girls in the team, then the team must consist of 3 boys and 3 girls.

Number of ways of choosing 3 boys from the total of 10 = [tex]10_C_3[/tex]

Number of ways of choosing 3 girls from a total of 12 = [tex]12_C_3[/tex]

The number of ways of combining the two possibilities;

[tex]n = 10_C_3 \times 12_C_3\\\\n = \frac{10!}{7!3!} \ \times \ \frac{12!}{9!3!} \\\\n = \frac{10\times 9 \times 8}{3\times 2} \ \times \ \frac{12\times 11 \times 10}{3\times 2} \\\\n = 120 \times 220\\\\n = 26,400 \ ways[/tex]

Therefore, the number of ways of selecting the team is 26,400 ways.

Answer:

Step-by-step explanation:

Combination of 4 out of 5 + 7 = 12 is:

Combination of 1 man and 3 women is:

Required probability:

Correct choice is B

Answer:

VERY NICE RACK U HAVE MAM

Step-by-step explanation:

Answer:

Its a

Step-by-step explanation:

found on another thing and im taking test

Answer:

I think the power is 4

Step-by-step explanation:

480J / 120 = 4

Put 2 mins into seconds which is 120 seconds

Sorry if it is wrong :)

Answer:

[tex]4\text{ watts}[/tex]

Step-by-step explanation:

In physics, the power of a machine is given by [tex]P=\frac{W}{\Delta t}[/tex], where [tex]W[/tex] is work in Joules and [tex]\Delta t[/tex] is time in seconds.

Convert 2 minutes into seconds:

2 minutes = 120 seconds.

Substitute [tex]W=480[/tex] and [tex]\Delta t=120[/tex] to solve for [tex]P[/tex]:

[tex]P=\frac{480}{120}=\boxed{4\text{ watts}}[/tex]

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (- 4, 2 ) into the partial equation

2 = - 8 + c ⇒ c = 2 + 8 = 10

y = 2x + 10 ← equation of line

Answer:

If you are using a calculator, simply enter 45÷100×200 which will give you 90 as the answer.

Mark me brainliest plz.

Answer:

a = -6

b = 1

Step-by-step explanation:

The gradient of the tangent to the curve y = ax + bx^3, will be:

dy/dx = a + 3bx²

at (2, -4)

dy/dx = a+3b(2)²

dy/dx = a+12b

Since the gradient at the point is 6, then;

a+12b = 6 ....1

Substitute x = 2 and  y = -4 into the original expression

-4 = 2a + 8b

a + 4b = -2 ...2

a+12b = 6 ....1

Subtract

4b - 12b = -2-6

-8b = -8

b = -8/-8

b = 1

Substitute b = 1 into equation 1

Recall from 1 that a+12b = 6

a+12(1) = 6

a = 6 - 12

a = -6

Hence a = -6, b = 1

Answer:

c. [tex]\frac{334}{365}[/tex]

Step-by-step explanation:

May has 31 days and a normal year is 365 days, so the probability is [tex]\frac{31}{365}[/tex]

The probability that isn't in May is: 1 - [tex]\frac{31}{365}[/tex] = [tex]\frac{334}{365}[/tex]

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

[tex](a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) = Q(x)[/tex]  is a differential equation.

If [tex]Q(x) \neq 0[/tex]

It is non homogeneous then,

The general solution  = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution =  complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

[tex]$(2D^3+15D^2+24D+11)y=0$[/tex]

Auxiliary equation,

[tex]$2m^3+15m^2+24m +11 = 0$[/tex]

-1  | 2    15    24     11

    | 0   -2    - 13    -11  

      2    13    11       0

∴ [tex]2m^2+13m+11=0[/tex]

The roots are

[tex]$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$[/tex]

[tex]$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$[/tex]

[tex]$=\frac{-13\pm9}{4}$[/tex]

[tex]$=-5.5, -1$[/tex]

So, [tex]m_1, m_2, m_3 = -1, -1, -5.5[/tex]

Then the general solution is :

[tex]$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$[/tex]

Answer:

The solutions are w=0 ,7

Step-by-step explanation:

3w^2 – 21w = 0

Factor out 3w

3w(w-7) =0

Using the zero product property

3w=0  w-7=0

w =0    w=7

The solutions are w=0 ,7

In an arithmetic sequence, every pair of consecutive terms differs by a fixed number c, so that the n-th term [tex]a_n[/tex] is given recursively by

[tex]a_n=a_{n-1}+c[/tex]

Then for n ≥ 2, we have

[tex]a_2=a_1+c[/tex]

[tex]a_3=a_2+c = (a_1+c)+c = a_1 + 2c[/tex]

[tex]a_4=a_3+c = (a_1 + 2c) + c = a_1 + 3c[/tex]

and so on, up to

[tex]a_n=a_1+(n-1)c[/tex]

Given that [tex]a_3=126[/tex] and [tex]a_{64}=3725[/tex], we can solve for [tex]a_1[/tex]:

[tex]\begin{cases}a_1+2c=126\\a_1+63c=3725\end{cases}[/tex]

[tex]\implies(a_1+63c)-(a_1+2c)=3725-126[/tex]

[tex]\implies 61c = 3599[/tex]

[tex]\implies c=59[/tex]

[tex]\implies a_1+2\times59=126[/tex]

[tex]\implies a_1+118 = 126[/tex]

[tex]\implies \boxed{a_1=8}[/tex]

We know

[tex]\boxed{\sf P(x,y)=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)}[/tex]

[tex]\\ \sf\longmapsto p(x,y)=\left(\dfrac{3(7)+5(-1)}{3+5},\dfrac{3(7)+5(1)}{3+5}\right)[/tex]

[tex]\\ \sf\longmapsto p(x,y)=\left(\dfrac{21-5}{8},\dfrac{21+5}{8}\right)[/tex]

[tex]\\ \sf\longmapsto p(x,y)=\left(\dfrac{16}{8},\dfrac{26}{8}\right)[/tex]

[tex]\\ \sf\longmapsto p(x,y)=\left(2,\dfrac{13}{4}\right)[/tex]

m:n=3:5

We know

[tex]\boxed{\sf M(x,y)=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)}[/tex]

[tex]\\ \sf\longmapsto M(x,y)=\left(\dfrac{3(7)+5(-1)}{3+5},\dfrac{3(7)+5(1)}{3+5}\right)[/tex]

[tex]\\ \sf\longmapsto M(x,y)=\left(\dfrac{21-5}{8},\dfrac{21+5}{8}\right)[/tex]

[tex]\\ \sf\longmapsto M(x,y)=\left(\dfrac{16}{8},\dfrac{26}{8}\right)[/tex]

[tex]\\ \sf\longmapsto M(x,y)=\left(2,\dfrac{13}{4}\right)[/tex]

Answer:

sorry I don't know the answer

Answer:

For the equation y=log(x-k), the domain depends on the value of K. Sliding K moves the left bound of the domain interval. The range and the right end behavior stay the same. For the equation y=log x+k, the domain is fixed, starting at an x-value of 0. The vertical asymptote is also fixed. The range of the equation depends on K.

Step-by-step explanation:

Answer:

x = 2 - sqrt(19/6)

x = 2 + sqrt(19/6)

Step-by-step explanation:

Answer:

add 4

subtract 24 from 5

2

Step-by-step explanation:

Answer:

The numerical limits for a C grade are 60.6 and 69.1.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 67 and a standard deviation of 7.3.

This means that [tex]\mu = 67, \sigma = 7.3[/tex]

Find the numerical limits for a C grade.

Below the 100 - 38 = 62th percentile and above the 18th percentile.

18th percentile:

X when Z has a p-value of 0.18, so X when Z = -0.915.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.915 = \frac{X - 67}{7.3}[/tex]

[tex]X - 67 = -0.915*7[/tex]

[tex]X = 60.6[/tex]

62th percentile:

X when Z has a p-value of 0.62, so X when Z = 0.305.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.305 = \frac{X - 67}{7.3}[/tex]

[tex]X - 67 = 0.305*7[/tex]

[tex]X = 69.1[/tex]

The numerical limits for a C grade are 60.6 and 69.1.

Answer:

3/11

Step-by-step explanation:

Answer:

the number before the first variable (first term)

Step-by-step explanation:

this appears to be an incomplete question. The numerical coefficient of a term is the number before the variable.

the constant is the number without a variable.

Answer:

A --> y=cot(x)

Step-by-step explanation:

if you graph tan(x), it has a period of just PI, because tan(x) is just sin(x)/cos(), and cot(x) is the same because it is just sec(x)/csc(x).