The statements that are true are:
B) The 10MSun protostar will reach the main sequence cooler and fainter than the 0.5MSun protostar.
E) The 10MSun protostar will be much more luminous than the 0.5MSun protostar.
To understand why, we need to know that a star's mass determines its temperature, luminosity, and lifespan. More massive stars are hotter, more luminous, and have shorter lifespans than less massive stars.
In this case, the 15MSun protostar is much more massive than the 0.5MSun protostar. Therefore, statement B is true because the 10MSun protostar is closer in mass to the 15MSun protostar, and therefore it will have a higher temperature during the protostar phase, making it cooler and fainter when it reaches the main sequence.
Statement E is true because more massive stars are more luminous than less massive stars. The 10MSun protostar is closer in mass to the 15MSun protostar, and therefore it will be much more luminous than the 0.5MSun protostar.
Hence b and e are correct option.
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amanda weighs about 600 n on earth, but would only weigh about 100 n on the moon. which best explains why amanda would weigh less on the moon than on earth? A. the mass of the moon is less than that of earth, therefore it has a weaker gravitational force. B. the circumference of the moon is smaller than earth, therefore it has less gravity. C. the pull from the gravity from earth decreases the pull of gravity from the moon. D. the lack of air pressure on the moon weakens the gravitational force of the moon.
Option A is the correct answer. The mass of the moon is less than that of earth, therefore it has a weaker gravitational force.
The correct option that explains why Amanda would weigh less on the moon than on earth is "A. the mass of the moon is less than that of the earth, therefore it has a weaker gravitational force." This is because weight is the result of the gravitational force that acts on an object, which is determined by both the mass of the object and the gravitational force acting on it. Therefore, the weight of an object varies depending on the mass and gravity.
The gravity of an object is the force that attracts it towards the center of the earth or the celestial object. The amount of gravity an object has depends on its mass and the mass of the object that it is attracting. The moon has a smaller mass than the earth, which means that it has a weaker gravitational force.
Consequently, the pull of gravity on the moon is weaker than on earth. The weight of Amanda is less because pull of gravity on the moon is weaker than on earth. Therefore, option A is the correct answer.
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two blocks with masses 4m and 7m are on a collision course with the same initial speeds vi. the block with mass 4m is traveling to the left, and the 7m block is traveling to the right. they undergo a head-on elastic collision and each bounces back, retracing its original path. find the final speeds of the particles. (enter your answers in terms of
The final speeds of the particles expressed in terms of the initial velocity are |v1'| = |v1| = 27/8|vi| and |v2'| = |v2| = 27/14|vi|
The conservation of momentum can be applied. The total momentum of the system before the collision is:
P before = m1v1 + m2v2
where m1 and v1 are the mass and velocity of the 4m block and m2 and v2 are the mass and velocity of the 7m block. Since the two blocks have the same initial speed, the momentum before the collision is:
P before = (4m)(-vi) + (7m)(vi)
P before = 3mvi
After the collision, the two blocks bounce back, so their final velocities are:
v1' = -v1
v2' = -v2
where v1 and v2 are the velocities of the blocks after the collision. Using the conservation of momentum again, the total momentum of the system after the collision is:
Pafter = m1v1' + m2v2'
Pafter = -4mv1 - 7mv2
Pafter = -4m(-v1) - 7m(-v2)
Pafter = 4mv1 + 7mv2
Since the collision is elastic, the total kinetic energy of the system is conserved. Therefore, the kinetic energy before the collision is equal to the kinetic energy after the collision:
Kbefore = Kafter
where Kbefore is the kinetic energy of the system before the collision and Kafter is the kinetic energy of the system after the collision. The kinetic energy can be expressed as:
K = 1/2mv²
Therefore, the total kinetic energy of the system before the collision is:
Kbefore = 1/2(4m)(vi)² + 1/2(7m)(vi)²
Kbefore = 27/2m(vi)²
The total kinetic energy of the system after the collision is:
Kafter = 1/2(4m)(-v1)² + 1/2(7m)(-v2)²
Kafter = 1/2(4m)(v1)² + 1/2(7m)(v2)²
Using the conservation of kinetic energy, Kbefore = Kafter:
27/2m(vi)² = 1/2(4m)(v1)² + 1/2(7m)(v2)²
Simplifying, the final velocities can be expressed in terms of the initial velocity:
v1 = 27/8vi
v2 = 27/14vi
Therefore, the final speeds of the particles are: |v1'| = |v1| = 27/8|vi| and |v2'| = |v2| = 27/14|vi|
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A student produces severa standing waves on string by adjusting the (requency vibration at ona end olthe string: The student measures the wavelength and frequency for each standing wave produced Which of the following procedures and calculations will allow the student I0 determine Ihe wave speed on the string? a.Graph function of 1\f The slope of the Iine equal t0 the wave speed;
b. Graph a5 a function of f The slope of the Ilne equal to he wave speed:
c. Graph A a5 function of 1\f The area under Ihe Iine I5 equal to Ihe wave speed d. Graph a5 a function of f The area under the line equal l0 Ihe wave speed
The correct option that allows the student to determine the wave speed on the string is d. Graph a5 a function of f The area under the line equal l0 Ihe wave speed.
Wave speed can be calculated by the formula: Wave speed (v) = frequency (f) × wavelength (λ) or v = fλ
According to the question, the student has measured the wavelength and frequency for each standing wave produced. Now, to determine the wave speed, the student needs to use the formula: v = fλ
To determine the wave speed from the graph of frequency and wavelength, the graph is made with frequency on the x-axis and wavelength on the y-axis. The slope of the line gives the speed of the wave. The graph can be used to calculate the wave speed for any wave by finding the slope of the line.
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if you are looking at a photo with a grayscale filter, what can you likely conclude about the light waves emitted from the filtered photo relative to the original color photo?
A grayscale filter will reduce the intensity of, and in some cases completely remove, all the colors in an image. This means that the visible light waves emitted from the photo with a grayscale filter are less intense than the light waves emitted from a photo without the filter.
What is grayscale filter?A grayscale image is one in which each pixel's value is a single sample carrying just information about the intensity of the light. Shades of grey make up only grayscale images, a type of black-and-white or grey monochrome. Black at the lowest intensity contrasts with white at the highest.
An picture with a defined grayscale color-space that maps the sample values to the achromatic channel of a standard color-space, which is based on the observed characteristics of human vision, is said to be colorimetric (or, more precisely, photometric).
There is no specific mapping from such a color image to a grayscale image if the original color image has no defined color-space or if the grayscale image is not meant to have the same human-perceived achromatic intensity as the color image.
Define pixel.The smallest addressable element in a raster image, or the smallest point in an all points addressable display device, is called a pixel or picture element. The smallest component in most digital display systems that can be changed by software are pixels.
Each pixel serves as a sample of the original image; as more samples are used, the original is often more faithfully reproduced. Every pixel has a different level of intensity. The three or four component intensities of a color, such as red, green, and blue, or cyan, magenta, yellow, and black, are often used in color imaging systems to depict a color.
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when a 2.75-kg fan, having blades 18.5 cm long, is turned off, its angular speed decreases uniformly from 10.0 rad/s to 6.30 rad/s in 5.00 s. (a) what is the magnitude of the angular acceleration of the fan?
The angular acceleration of the fan is 0.740 rad/s^2,
Angular acceleration which represents the rate at which the angular velocity changes over time. The unit used to measure angular acceleration is radians per square second (rad/s2), according to the International System of Units. The Greek alphabet symbol alpha (α) is used to denote angular acceleration.
To calculate the angular acceleration of the fan, the formula α = Δω/Δt is used. Here, α represents angular acceleration, Δω represents the change in angular speed, and Δt represents the change in time.
In this scenario, Δω is equal to 10.0 - 6.30 = 3.70 rad/s, and Δt is equal to 5.00 s. By substituting these values into the formula, we obtain α = 3.70/5.00 = 0.740 rad/s^2.
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Can anyone help me please ..I need it hurry within 6 hrs.please.
Brainliest for the first best answer.
(i) Switch k1 is closed:
The current passing through the circuit is: 0.25 amps
R_total = R1 + R2 = 3 + 5 = 8 ohms
The current passing through the circuit is:
i = V / R_total = 2 / 8 = 0.25 amps
(ii) Switches k1 and k2 are closed:
The current passing through the circuit is: 1.07 amps
1/R_total = 1/R1 + 1/(R2 + R3) = 1/3 + 1/(5 + 0) = 8/15
R_total = 15/8 ohms
The current passing through the circuit is:
i = V / R_total = 2 / (15/8) = 1.07 amps
(iii) Switch k1 is open and k2 is closed:
The current passing through the circuit is: 1.07 amps
1/R_total = 1/R2 + 1/(R1 + R3) = 1/5 + 1/(3 + 0) = 1/5 + 1/3 = 8/15
R_total = 15/8 ohms
The current passing through the circuit is:
i = V / R_total = 2 / (15/8) = 1.07 amps
So the current passing through the circuit depends on which switches are closed, and can range from 0.25 amps to 1.07 amps.
What is current?
Crrent refers to the flow of electric charge through a conductor, such as a wire. It is measured in amperes (A) and is defined as the rate at which electric charge flows past a given point in a circuit. current is caused by the movement of charged particles, such as electrons or ions, through a conductor.
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suppose the ring rotates once every 4.10 s . if a rider's mass is 51.0 kg , with how much force does the ring push on her at the top of the ride?
The ring rotates once every 4.10 s. If a rider's mass is 51.0 kg, how much force does the ring push on her at the top of the ride is 500 N.
The solution is explained below:
As the rider is at the top of the ride, the only force acting on him is the force of gravity, which is pointing downwards, and the force with which the ring is pushing him towards the center of the circular path. By equating both forces, we can determine the required force to maintain the rider at the top of the ride.
Hence, the answer to the question is that the force with which the ring pushes the rider at the top of the ride is equal to the force of gravity, which is given as F = mgF = (51.0 kg)(9.81 m/s^2) = 500 N
Therefore, the force with which the ring pushes on the rider at the top of the ride is 500 N.
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the maximum energy of photoelectrons from aluminium is 2.3 ev for radiation of 2000 a and 0.90 ev for radiation of 3130 a. use this data to calculate plancks constant and the work function of aluminium
The maximum energy of photoelectrons from aluminium is 2.3 eV for radiation of 2000 Å and 0.90 eV for radiation of 3130 Å.
To calculate Planck's constant and the work function of aluminium, we need to use the equation:
h = E2 - E1/ λ2 - λ1
Where h is Planck's constant, E1 and E2 are the maximum energy of photoelectrons for each wavelength, and λ1 and λ2 are the wavelengths.
Using the given data, we have:
h = (2.3 - 0.90) / (2000 - 3130)
Therefore, h = -1.4 eV / -930 Å, which simplifies to h = 0.0015 eVÅ.
The work function of aluminium is equal to the maximum energy of the photoelectrons for the longest wavelength, in this case, 0.90 eV. Therefore, the work function of aluminium is 0.90 eV.
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why do nuclear reactors have three separate water loops instead of just a single one that runs from the water source, through the reactor, then back to the cooling tower?
Nuclear reactors have three separate water loops instead of just a single one that runs from the water source, through the reactor, then back to the cooling tower because the water running through the reactor is highly radioactive.
What are nuclear reactors?A nuclear reactor is a device that controls and maintains a sustained nuclear chain reaction for the purpose of generating heat or power, as well as the materials that make up a nuclear reactor.
The water running through the reactor is highly radioactive, which means that it cannot be released into the atmosphere or allowed to come into touch with humans or the environment. As a result, nuclear reactors are designed with three separate water loops.
The first loop circulates ordinary water that passes through the reactor and generates heat. The second loop, which is a separate circuit, brings this water to a steam turbine. The third loop, which is also a closed circuit, recovers the cooling water after it has passed through the turbine and transports it back to the reactor's inlet.In summary, nuclear reactors have three separate water loops instead of a single one that runs from the water source, through the reactor, and back to the cooling tower because the water running through the reactor is highly radioactive.
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2.2 VECTORS IN TWO 120 N bearing 70° and 160 N bearing 40°
Answer:
Explanation:
Assuming you want to find the resultant vector of the two given vectors:
We can use the graphical method or the component method to find the resultant vector. Here, I will demonstrate the component method:
Step 1: Convert the given vectors into their component form (i.e., horizontal and vertical components).
Vector 1: 120 N bearing 70°
Horizontal component = 120 cos(70°) ≈ 38.23 N
Vertical component = 120 sin(70°) ≈ 113.41 N
Vector 2: 160 N bearing 40°
Horizontal component = 160 cos(40°) ≈ 122.15 N
Vertical component = 160 sin(40°) ≈ 103.08 N
Step 2: Add the horizontal components and vertical components separately to get the components of the resultant vector.
Horizontal component of resultant vector = 38.23 N + 122.15 N ≈ 160.38 N
Vertical component of resultant vector = 113.41 N + 103.08 N ≈ 216.49 N
Step 3: Use the Pythagorean theorem to find the magnitude of the resultant vector.
Magnitude of resultant vector = √(160.38 N)^2 + (216.49 N)^2 ≈ 268.15 N
Step 4: Find the direction of the resultant vector.
Direction of resultant vector = tan^-1(216.49 N / 160.38 N) ≈ 53.12°
Therefore, the resultant vector of the two given vectors is approximately 268.15 N at a bearing of 53.12°.
Three objects interact in a system that has a total initial momentum of 236 kg-m/s directed in the southeast direction. If there is no friction (external force) acting on the two objects, what is their momentum after 12 s?
The momentum of the objects after 12 seconds of the interaction is -236 kg-m/s
Step by step Explanation:
The three objects of a system that has a total initial momentum of 236 kg-m/s directed in the southeast direction.
If there is no friction (external force) acting on the two objects, the momentum of the object is the product of the mass and velocity of the object.
The formula for momentum is P = mv,
where P is momentum, m is mass, and v is velocity.
Furthermore, the direction of momentum is similar to the direction of velocity. The given initial momentum is [tex]P_1[/tex] = 236 kg-m/s directed in the southeast direction.
According to the law of conservation of momentum, the total momentum of the system must remain constant if there is no external force. As a result, the total momentum of the system will be the same before and after the interaction.
[tex]P_1 = P_2 + P_3[/tex]
Where, [tex]P_1[/tex] = Initial momentum of the system
[tex]P_2[/tex] = Momentum of the object after the interaction
[tex]P_3[/tex] = Momentum of the object after the interaction
Let [tex]P_2[/tex]be the momentum of object 2 and [tex]P_3[/tex] be the momentum of object 3.
P_2 = m_2v_2
[tex]P_2 = m_2v_2[/tex]
[tex]P_3 = m_3v_3[/tex]
After the interaction, the momentum of the system is:
[tex]P = P_2 + P_3[/tex]
Let's find P_2 and P_3 in terms of time since the direction and mass of the objects are not given.
[tex]P_1 = P_2 + P_3[/tex]
⇒ [tex]P_2 = P_1 - P_3[/tex]
We must discover the momentum of object 3. The initial momentum is southeast. It indicates that the momentum is in the opposite direction of northwest. If we call the north and west direction negative, then the southeast direction will be positive. This indicates that the momentum is negative.
Therefore, [tex]P_1 = P_2 + P_3[/tex] ⇒ -236 =[tex]-P_3 + P_2[/tex]
We are supposed to calculate their momentum after 12 seconds after the interaction. So, the external force will act on them during this interval of time. Due to the absence of external forces, the momentum of the objects will remain constant.
Hence, the momentum of the objects after 12 seconds of the interaction will remain the same as the momentum of the objects after the interaction.Therefore,
[tex]P = P_2 + P_3 = P_1P[/tex] = -236 kg-m/s
the momentum of the objects after 12 seconds of the interaction.
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This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Pin A, which is attached to link AB, is constrained to move in the circular slot CD. At t=0, the pin starts from rest and moves so that its speed increases at a constant rate of 1.2 in/s2 D 3.5 in. А B Determine the magnitude of its total acceleration when t= 0. The magnitude of its total acceleration is in/s2
The magnitude of the total acceleration of the pin when t=0 is 1.2 in/s^2.
To explain further, the acceleration of the pin is the sum of two components: tangential acceleration and centripetal acceleration. The tangential acceleration is responsible for increasing the speed of the pin, and its magnitude is constant at 1.2 in/s^2.
The centripetal acceleration is due to the circular motion of the pin in the slot CD and is directed towards the center of the circle.
To find the magnitude of the total acceleration at t=0, we need to first find the magnitude of the tangential acceleration and the centripetal acceleration separately. We know that the tangential acceleration is 1.2 in/s^2, and we can use the formula for centripetal acceleration, a_c = v^2/r, where v is the velocity of the pin and r is the radius of the circle. At t=0, the velocity of the pin is zero, and the radius of the circle is 3.5 inches.
Therefore, the centripetal acceleration is also zero.
Since the centripetal acceleration is zero, the magnitude of the total acceleration is equal to the magnitude of the tangential acceleration, which is 1.2 in/s^2.
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questionwhen you heat an air-filled balloon, what happens inside with regard to the movement of air molecules?
When you heat an air-filled balloon, the movement of air molecules inside the balloon increases, causing the air to expand and the balloon to inflate.
Heating the air inside the balloon increases the temperature of the air molecules, causing them to move more rapidly and collide with each other more frequently.
This increased movement and collision between molecules causes them to spread out and fill a larger volume, which leads to the expansion of the air inside the balloon.
As the air inside the balloon expands, it exerts a greater pressure on the walls of the balloon, causing it to inflate.
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Is an object moving with a constany speed around a circular path veloctiy? why? why not?
Answer: The motion of a body with constant speed in a circular path is said to be accelerated, because it is moving with uniform speed, but not with uniform velocity, as velocity is a vector quantity, it can be represented in magnitude as well the direction.
Explanation:
In which of the following cases does a car have a negative velocity and a positive acceleration? A car that is traveling in the ................. (A) -x direction at a constant 10 m/s. (B) - direction increasing in speed. (C) +x direction increasing in speed. (D) - direction decreasing in speed. (E) +x direction decreasing in speed.
In the case where the car is traveling in the -x direction and decreasing in speed, it has a negative velocity and a positive acceleration. Therefore, option D is the correct answer. In this case, the car is traveling in the - direction and decreasing in speed. Therefore, it has a negative velocity and a positive acceleration.
Let's discuss the given options one by one:
(A) In this case, the car is traveling in the -x direction at a constant speed. Therefore, it has a negative velocity and zero acceleration. This option is incorrect.
(B) In this case, the car is traveling in the - direction and increasing its speed. Therefore, it has a negative velocity and a positive acceleration. However, the given direction is not specified, and thus this option is not accurate.
(C) In this case, the car is traveling in the +x direction and increasing in speed. Therefore, it has a positive velocity and a positive acceleration. This option is incorrect.
(D) In this case, the car is traveling in the - direction and decreasing in speed. Therefore, it has a negative velocity and a positive acceleration. This option is correct.
(E) In this case, the car is traveling in the +x direction and decreasing in speed. Therefore, it has a positive velocity and a negative acceleration. This option is incorrect.
Therefore, Option D ( - direction decreasing in speed) is correct.
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Four protons (each with mass 1.7 10-27 kg and charge 1.6 10-19 C) are initially held at the corners of a square that is 4.9 10-9 m on a side. They are then released from rest. What is the speed of each proton when the protons are very far apart?
a square with a side length of 4.9 10-9 m, each with mass 1.7×10⁻²⁷ kg and charge 1.6×10⁻¹⁹ C. And they are let go of their sleep. When the protons are very far apart, the speed of each proton is 7.0e5 m/s.
We can start by finding the initial potential energy of the system when the four protons are held at the corners of the square. The potential energy is given by:
U_i = (1/4πε₀) * (q₁q₂/r)
where ε₀ is the permittivity of free space, q₁, and q₂ are the charges of the two protons, and r is the distance between them.
Since all four protons are identical and equidistant, we can calculate the initial potential energy of the system by summing up the potential energies of each pair of protons:
U_i = 2 * [(1/4πε₀) * ((1.6e-19 C)² / (4.9e-9 m))] + 2 * [(1/4πε₀) * ((1.6e-19 C)² / (4.9e-9 m * √2))]
where the factor of 2 in front of each term takes into account the fact that there are two pairs of protons.
Evaluating this expression gives U_i = 1.55e-17 J.
At infinite separation, the potential energy of the system will be zero, and all of the initial potential energy will have been converted into kinetic energy. Therefore, we can use the conservation of energy to find the speed of each proton when they are very far apart:
U_i = K_f
where K_f is the final kinetic energy of the system.
K_f = (1/2) * m * v²
where m is the mass of a proton, and v is its speed.
Setting U_i equal to K_f and solving for v gives:
v = √(2U_i/m)
Substituting the values we obtained earlier, we get:
v = √[(2 * 1.55e-17 J) / (1.7e-27 kg)]
v ≈ 7.0e5 m/s
Therefore, the speed of each proton when they are very far apart is approximately 7.0e5 m/s.
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a cliff diver drops from rest to the water below. how many seconds does it take for the driver to go from 0 mi/h to 60 mi/h? (for comparison, it takes about 3.5 s to 4.0 s for a powerful car to go from 0 to 60 mi/h.)
Assuming that the only force acting on the diver is gravity and neglecting air resistance, we can use the kinematic equations of motion to determine that it takes 2.7 s for the diver to reach a speed of 60 mi/h (or 88 ft/s).
Since the diver starts from rest, we can use the kinematic equation:
[tex]$$v_f = v_i + at$$[/tex]
where [tex]$v_i$[/tex] is the initial velocity (0 mi/h), [tex]$v_f$[/tex] is the final velocity (60 mi/h or 88 ft/s), [tex]$a$[/tex] is the acceleration due to gravity [tex](32.2 ft/s$^2$)[/tex], and [tex]$t$[/tex] is the time it takes to reach the final velocity.
Converting the final velocity to feet per second, we get:
[tex]$$v_f = 60\ \text{mi/h} \times \frac{5280\ \text{ft/mi}}{3600\ \text{s/h}} = 88\ \text{ft/s}$$[/tex]
Substituting the given values, we get:
[tex]$$88\ \text{ft/s} = 0\ \text{ft/s} + (32.2\ \text{ft/s}^2)t$$[/tex]
Solving for [tex]$t$[/tex], we get:
[tex]t = \frac{88\ \text{ft/s}}{32.2\ \text{ft/s}^2}[/tex]
Therefore, it takes approximately 2.73 seconds for the diver to go from 0 mi/h to 60 mi/h.
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the end result of a theory that is not verified is
Unproven theories ultimately cannot be regarded as scientific facts or principles and are not generally recognised by the scientific community.
A well-supported explanation of a natural occurrence in science that has passed rigorous examination and is backed by empirical data is referred to as a theory. A hypothesis, however, cannot be regarded as a scientific fact or principle if it is not backed up by empirical data or if it has not undergone extensive testing and verification. The scientific community frequently rejects unproven notions with scant empirical backing and may even label them as pseudoscientific or non-scientific. This is so that scientific theories and findings may be evaluated and verified frequently. Science does this by using evidence-based reasoning and critical thinking. Unproven theories are therefore eventually not regarded as being a part of the corpus of scientific knowledge.
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A 900.0kg car is traveling at 11.0m/s. What is the momentum of this car?
The momentum of the car is 9900 kg m/s.
What is momentum?
The momentum of an object is defined as the product of its mass and velocity. In this case, the momentum of the car can be calculated using the following formula:
Momentum = mass x velocity
Here, the mass of the car is 900.0 kg and its velocity is 11.0 m/s. Substituting these values into the formula, we get:
Momentum = 900.0 kg x 11.0 m/s
Momentum = 9900 kg m/s
Therefore, the momentum of the car is 9900 kg m/s.
Note that the units of momentum are kilogram meters per second (kg m/s), which are derived from the units of mass (kg) and velocity (m/s). Momentum is a vector quantity, meaning it has both magnitude and direction, and its direction is the same as the direction of motion of the object.
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A 2. 00-kg object is attached to an ideal massless horizontal spring of spring constant 100. 0 N/m and is at rest on a frictionless horizontal table. The spring is aligned along the x-axis and is fixed to a peg in the table. Suddenly this mass is struck by another 2. 00-kg object traveling along the x-axis at 3. 00 m/s, and the two masses stick together. What are the amplitude and period of the oscillations that result from this collision? 0. 300 m, 1. 26 s 0. 424 m, 5. 00 s 0. 424 m, 0. 889 s 0. 300 m, 0. 889 s 0. 424 m, 1. 26 s
The correct option is A, the amplitude and period of the oscillations that result from this collision are 0.300 m in 1.26s.
The expression for Period of spring is,
[tex]T = 2\pi\sqrt{\frac{2m}{k} }[/tex]
Here, m is the mass of the spring and k is the spring constant
Substitute 2 kg
for m
and 100N/m
for k
in equation [tex]T = 2\pi\sqrt{\frac{2m}{k} }[/tex]
and solve for T .
[tex]T = 2\pi\sqrt{\frac{(2)2 kg}{100 N/m} }[/tex]
T = 1.26s
In physics, amplitude refers to the maximum displacement or distance moved by a wave from its equilibrium or mean position. It is a measure of the intensity or strength of a wave, and it is usually represented as the height of the crest or depth of the trough of the wave.
The amplitude of a wave can be measured in various units, depending on the type of wave and the context in which it is being studied. For example, the amplitude of a sound wave is measured in decibels (dB), while the amplitude of an electromagnetic wave is measured in volts per meter (V/m). Amplitude plays an important role in the behavior of waves. It determines the energy carried by the wave and affects other properties such as frequency, wavelength, and phase.
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Complete Question: -
A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table. The spring is aligned along the x-axis and is fixed to a peg in the table. Suddenly this mass is struck by another 2.00-kg object traveling along the x-axis at 3.00 m/s, and the two masses stick together. What are the amplitude and period of the oscillations that result from this collision
A) 0.300 m, 1.26 s
B) 0.300 m, 0.889 s
C) 0.424 m, 0.889 s
D) 0.424 m, 1.26 s
E) 0.424 m, 5.00 s
the car passes over the top of a vertical curve at a with a speed of 50 km/hr and then passes through the bottom of a dip at b. the radii of curvature of the road at a and b are both 70 m. find the speed of the car at b if the normal force between the road and the tires at b is twice that at a. the mass center of the car is 1.2 meter from the road.
The speed of the car at b if the normal force between the road and the tires at b is twice that at a is about 44.1 km/h.
What is Speed?Speed of the car at A = 50 km/h
Radius of curvature at A = 70 m
Radius of curvature at B = 70 m
Normal force between the road and the tires at B = 2 × Normal force between the road and the tires at A= 2N
Mass center of the car = 1.2 m
The speed of car at B be v km/h
From the conservation of energy at the point A and B, we get:
1/2 mv² + mgh = 1/2 m(50)² + mg(70 - r)
1/2 mv² + mg(70 + r) = 1/2 m(50²)
1/2 mv² = 1/2 m50² - mg(70 + r) …… equation (1)
From the conservation of energy at point B, we get:
1/2 mv² + mg(2r + 1.2) = 1/2 m(50)² + mg(70 - r)
2× Normal force between the road and the tires at A = Normal force between the road and the tires at B
Normal force between the road and the tires at B = 2 × Normal force between the road and the tires at A
Therefore, mg - 2 × N = mv²/rmg - N = mv²/2r
2mg - 4N = mv²/rmg - 2N = mv²/2r
Subtracting, we get:
N = mg/3
Normal force between the road and the tires at A = mg/3
Normal force between the road and the tires at B = 2mg/3
Normal force between the road and the tires at B = 2(mg/3) = mg/3
From the above equations, we get the value of v. Putting the values, we get:
1/2 mv² = 1/2 m(50)² - mg(70 + r) - mg(2r + 1.2) + mg(70 - r)1/2 v² = 1/2(50)² - g(70 + r) - g(2r + 1.2) + g(70 - r)v = 44.1 km/h
Therefore, the speed of the car at B is 44.1 km/h.
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Review your answer to part c. In addition, reread the portion of your physics text that discusses Newton's third law. Then consider a book on a level table: e. Which force completes the Newton's third law (or action-reaction) force pair with the normal force exerted on the book by the table?
In this case, the normal force exerted by the table on the book is the action force and the reaction force is the force that the book exerts on the table. This force is equal in magnitude to the normal force and acts in the opposite direction.
Newton's third law states that for every action, there is an equal and opposite reaction. This means that when one object exerts a force on another object, the second object exerts a force back on the first object that is equal in magnitude and opposite in direction.
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Ceteris paribus, which of these events would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall?
• A dcrease investor confidance
• A decrease in cosmetic income and wealth • A strengh of time preference
• A decrease in capital productivity
Ceteris paribus, a decrease in capital productivity is the event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. The correct answer is option C.
Ceteris paribus is a Latin expression that means "all other things being equal." Ceteris paribus is a model in which economists use to analyze the effect of one independent variable on a dependent variable while keeping all other independent variables constant. This implies that only one variable is allowed to change while all other variables are held constant at their current level or position.
Therefore, Ceteris paribus, an increase in investor confidence, an increase in cosmetic income and wealth, and a strength of time preference will not cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. However, a decrease in capital productivity is an event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall.
When capital productivity is low, firms are unable to produce goods and services efficiently, and as a result, the demand for investment falls. When the demand for investment falls, the equilibrium quantity of investment will also decrease, leading to a decrease in the equilibrium interest rate.
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A light bulb used in a slide projector draws a current of 6 amperes when operating on 120 volts.. the power consumed by th light bulb in watts is? B.)a light bulb used in a slide projector draws a cuurent of 6 amperes when operating on 120 volts. the resistance of the light bulb in ohms is?
a..05
b.20
c.720
d.none
When a light bulb used in a slide projector draws a current of 6 amperes while operating on 120 volts, the power consumed by the light bulb in watts is 720, and the resistance of the light bulb in ohms is 20. Thus, the correct option is B.
Why the resistance of a light bulb is 20 ohms?When we know that the current drawn by a light bulb is 6 amperes and the voltage applied to it is 120 volts, we can easily calculate the resistance of the light bulb, as follows:
Resistance (R) = Voltage (V) / Current (I)
here, V = 120V and I = 6A
Therefore, the resistance of the light bulb is:
R = V/I = 120/6 = 20 Ohms
The formula used to calculate the power (P) consumed by a light bulb is:
P = V × I
Here, the voltage (V) applied to the light bulb is 120 volts and the current (I) drawn by the light bulb is 6 amperes. So, the power consumed by the light bulb is:
P = 120 × 6 = 720 watts
Hence, the power consumed by the light bulb in watts is 720, and the resistance of the light bulb is 20 ohms.
Therefore, the correct option is B.
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if the 2 currents are same direction and forces are attractive, what is the direction of force wire 1 on wire 2
The direction of the force from wire 1 on wire 2 is attractive, as the two currents are in the same direction.
If two currents are flowing in the same direction and the forces between the wires are attractive, then the direction of the force on wire 2 due to wire 1 will be towards wire 1. This is because the magnetic field created by the current in wire 1 will induce a magnetic field in wire 2, and the interaction between these two magnetic fields will result in an attractive force between the wires.
In summary, if two currents are flowing in the same direction and the forces are attractive, the direction of the force on wire 2 due to wire 1 will be towards wire 1.
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discuss whether the values found in parts (a) and (b) seem consistent with the fact that tidal effects with earth have caused the moon to rotate with one side always facing earth.
Yes, the values found in parts (a) and (b) are consistent with the fact that tidal effects with earth have caused the moon to rotate with one side always facing earth.
This is because part (a) states that the moon rotates on its axis in the same amount of time it takes to complete one orbit around the Earth, which is a phenomenon known as tidal locking. Part (b) further indicates that the same side of the moon always faces the Earth, further supporting the notion that tidal effects have caused the moon to rotate with one side always facing Earth.
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Calculate the translational speed of a cylinder when it reaches the foot of an incline 7.20 m high. Assume it starts from rest and rolls without slipping.
Express your answer using three significant figures and include the appropriate units. Thank you!!
The translational speed of the cylinder when it reaches the foot of the incline is approximately 9.43 m/s.
We can use conservation of energy to solve this problem. The initial energy of the cylinder is all potential energy, and the final energy is all kinetic energy. The potential energy at the bottom of the incline is zero.
The potential energy of the cylinder at the top of the incline is given by:
PE = mgh
where m is the mass of the cylinder, g is the acceleration due to gravity, and h is the height of the incline. Substituting the given values, we get:
PE = (mass of cylinder) x (acceleration due to gravity) x (height of incline) = mgh
The kinetic energy of the cylinder at the bottom of the incline is given by:
KE = (1/2)mv^2
where v is the translational speed of the cylinder at the bottom of the incline.
According to the conservation of energy, the initial potential energy is equal to the final kinetic energy, so we can set these two expressions equal to each other:
mgh = (1/2)mv^2
We can cancel the mass of the cylinder from both sides, and solve for v:
v = sqrt(2gh)
Substituting the given values, we get:
v = sqrt(2 x 9.81 m/s^2 x 7.20 m) ≈ 9.43 m/s
Therefore, the translational speed of the cylinder when it reaches the foot of the incline is approximately 9.43 m/s.
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A spring attached to a mass is at rest in the initial position (not shown). The spring is compressed in position A and is then released, as shown in position B. Which equation describes the conservation of energy in position A?
[tex]E=\frac{1}{2} mv^{2} \\E=mgh\\E=\frac{1}{2} kx^{2} \\E=\frac{1}{2} k2kx^{2}[/tex]
Answer:
Explanation:
The energy conservation is equal to half of the product of the spring constant and the square of displacement of the spring, so option C is correct.
: suppose a planet has a mass of 10 times that of the Earth and a radius that is 100 times that of the Earth. The acceleration of gravity on the surface of the planet, expressed in units of the Earth's acceleration of gravity, g, is 1000 g. g/1000 10 g.
The acceleration of gravity on the surface of the planet, expressed in units of the Earth's acceleration of gravity, g, is g/1000.
Given,Mass of the planet, m = 10m_Earth Radius of the planet, r = 100r_Earth Acceleration of gravity on the surface of the planet, g' = 1000 g_Earth To find, the acceleration of gravity on the surface of the planet, expressed in units of the Earth's acceleration of gravity, g.
Assuming the planet to be a perfect sphere, the acceleration due to gravity on the surface of the planet, g' is given by,g' = GM / r²where M is the mass of the planet, r is the radius of the planet and G is the gravitational constant.We know that, the acceleration of gravity on the surface of the Earth, g_Earth is given by,g_Earth = GM_Earth / r_Earth²Thus, we have the ratio of g' and g_Earth,g' / g_Earth = GM / r² × r_Earth² / GM_Earth= r_Earth / r = 1 / 100∴ g' = 1 / 100 × g_Earth = g_Earth / 1000.Hence, the acceleration of gravity on the surface of the planet, expressed in units of the Earth's acceleration of gravity, g is g/1000. Therefore, the answer is g/1000.
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of the three states of matter, which one has the most kinetic energy?
Of the three states of matter (solid, liquid, and gas), gas has the most kinetic energy. This is because the particles in a gas have the highest average speed compared to the particles in solids and liquids.
In a gas, the particles are in constant motion, colliding with each other and the walls of the container. This motion generates kinetic energy, which is proportional to the speed and mass of the particles. In contrast, solids have the lowest kinetic energy because their particles are tightly packed and have limited movement. The particles in a solid vibrate around a fixed position, and only experience small oscillations. Liquids have an intermediate amount of kinetic energy. The particles in a liquid are less tightly packed than in a solid, and can move more freely, resulting in more kinetic energy. However, liquids have more intermolecular forces between the particles compared to gases, which restricts their movement and reduces their average speed. Therefore, of the three states of matter, gases have the most kinetic energy, followed by liquids and then solids.
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