Answer:
2 × (14 – 9) – (17 – 14) = 7
Step-by-step explanation:
Evaluate the choices to see which is true.
(2 x 14) – 9 – (17 – 14) = 7 ⇒ 28 -9 -3 ≠ 7
2 x (14 – 9) + (– 17 – 14) = 7 ⇒ 2(5) +(-31) ≠ 7
(2 x 14) – (9 – 17) – 14 = 7 ⇒ 28 -(-8) -14 ≠ 7
2 x (14 – 9) – (17 – 14) = 7 ⇒ 2(5)- 3 = 7 . . . . true
Allison is rolling her hula hoop on the playground. The radius of her hula hoop is 35 \text{ cm}35 cm35, start text, space, c, m, end text. What is the distance the hula hoop rolls in 444 full rotations?
Answer: 880 cm
Step-by-step explanation:
Given: Radius of the hula hoop = 35 cm
Hula hoop is circular in shape
Then, Circumference = [tex]2\pi r[/tex] , where r = radius
Now , Circumference of hula hoop = [tex]2\times \dfrac{22}{7}\times35=220\ cm[/tex]
Now , the distance the hula hoop rolls in 4 full rotations = 4 × (Circumference of hula hoop)
[tex]= 4 \times 220=880\ cm[/tex]
Hence, the required distance = 880 cm
Answer:
880
Step-by-step explanation:
What property is demonstrated here? (3x-5) x 4 = 3 x (-5 x 4) A) commutative property of addition B) associative property of multiplication C) commutative property of multiplication D) associative property of addition (haven't learned this yet so I have no clue)
Answer:
B) Associative Property of Multiplication
Step-by-step explanation:
*if it's wrong idk how, but I apologise*
URGENTT PLEASE ANSWER
Answer:
Step 2
Step-by-step explanation:
9 was added to both sided so the equation would remain equal and the 9 would be cancelled out on the left side.
0,2,4,0,2,3,2,8,6
What is the mean?
What is the median?!
What is the first quartile (Q1)?!
What is the third quartile (Q3)?
What is the minimum?
What is the maximum?
What is the interquartile range of the data?!
Answer:
LOOK BELOW
Step-by-step explanation:
Mean= add all of the numbers together and divide by total amount of
numbers
aka=3
Median= put all the numbers in order and find the number in the middle
aka=2.5
Minimum=0
Maximum=8
This data can only be found using a Box and Whisker Plot....
I can't really explain a box and whisker plot so you have to look that up to understand that.. SRY!!!
------------------------------------
First Quartile=1
Third Quartile=5
Interquartile Range=4
Answer:
Mean= add all of the numbers together and divide by total amount of
numbers
aka=3
Median= put all the numbers in order and find the number in the middle
aka=2.5
Minimum=0
Maximum=8
This data can only be found using a Box and Whisker Plot....
I can't really explain a box and whisker plot so you have to look that up to understand that.. SRY!!!
------------------------------------
First Quartile=1
Third Quartile=5
Interquartile Range=4
Step-by-step explanation:
Please solve, will give BRAINLIST!!
Answer:
x = 19 1/3
Step-by-step explanation:
6/14 = 7/(x-3)
Using cross products
6 * (x-3) = 7*14
6x -18 = 98
Add 18 to each side
6x-18+18 =98+18
6x = 116
Divide each side by 6
6x/6 = 116/6
x =58/3
x = 19 1/3
Answer= 58/3
Step by Step
Step 1: Cross-multiply.
6*(x−3)=(7)*(14)
6x−18=98
Step 2: Add 18 to both sides.
6x−18+18=98+18
6x=116
Step 3: Divide both sides by 6.
6x /6 = 116 /6
x= 58 /3
Consider f(x) = 3x2 + 4 and g(x) = 2x − 3. Which statements about f + g are true? Select all that apply. A. The domain is all real numbers. B. The range is all real numbers. C. It is a linear function. D. It is a quadratic function.
PLEASE HELP
Answer:
B. The range is all real numbers. D. It is a quadratic function.Step-by-step explanation:
Given the functions f(x) = 3x² + 4 and g(x) = 2x − 3, to know that statements that is true about f+g, we will need to add the functions together first.
f(x)+g(x) = 3x² + 4 + 2x - 3
f(x)+g(x) = 3x²+2x +4 - 3
f(x)+g(x) = 3x²+2x + 1
The highest degree of a quadratic function is 2 and since the highest degree of the resulting function is 2, hence the resulting sum of the equations is quadratic.
Also the range of the values is all real numbers because the presence of x² in the function will always return a positive value greater than x.
Hence the correct statements are 'the range is all real numbers and it is a quadratic function'
Answer:
B AND D
Step-by-step explanation:
HELP ME PLEASE ASAP! Zoe is making a quilt. The ratio of red squares to green squares is 2 to 3. She uses a total of 55 squares. How many green squares does she use?
Answer: 33
First you divide 55 by 5 to get the total number of squares in one part, which equals 11. Then you multiply by 3 since there are 3 parts of green squares to get your answer, 33.
Which of the following lists of three numbers could form the side lengths of a triangle? A. 10, 20, 30 B. 122, 257, 137 C. 8.6, 12.2, 2.7 D. 1/2, 1/5, 1/6
Answer:
Step-by-step explanation:
The triangle inequality theorem states that the sum of any two sides of a triangle os greater than the third side.
■■■■■■■■■■■■■■■■■■■■■■■■■■
First triangle:
Let a,b and c be the sides of the triangle:
● a = 10
● b = 20
● c = 30
Now let's apply the theorem.
● a+b = 10+20=30
That's equal to the third side (c=30)
●b+c = 50
That's greater than a.
● a+c = 40
That's greater than b.
These aren't the sides of a triangel since the first inequality isn't verified.
■■■■■■■■■■■■■■■■■■■■■■■■■
Second triangle:
● a = 122
● b = 257
● c = 137
Let's apply the theorem.
● a+b = 379
That's greater than c
● a+c = 259
That's greater than b
● b+c = 394
That's greater than a
So 122,257 and 137 can be sides of a triangle.
■■■■■■■■■■■■■■■■■■■■■■■■■■
The third triangle:
● a = 8.6
● b = 12.2
● c = 2.7
Let's apply the theorem:
● a+b = 20.8
That's greater than c
● b+c = 14.9
That's greater than a
● a+c = 11.3
That isn't greater than b
So theses sides aren't the sides of triangle.
■■■■■■■■■■■■■■■■■■■■■■■■■■
● a = 1/2
● b = 1/5
● c = 1/6
Let's apply the theorem.
● a+b = 7/10
That's greater than c
● a+c = 2/3
That's greater than b
● b+c = 11/30
That isn't greater than a
So these can't be the sides of a triangle.
Given the right triangle below, if AB = 4 and BC = 4, find AC.
A
B
C
AC will be 4√2 when AB = 4 and BC = 4, in the given right triangle.
What is Pythagoras' Theorem?According to Pythagoras' Theorem, in a right triangle, the square of the length of the longest side, that is, the hypotenuse, that is, the side opposite to the right angle is equal to the sum of the squares of the lengths of the other two sides.
How to solve the question?In the question, we are given a right triangle, with sides AB = 4 and BC = 4.
We are asked to find AC.
To find AC, we will use the Pythagoras theorem, according to which, we can write:
AC² = AB² + BC²
or, AC² = 4² + 4²,
or, AC² = 16 + 16,
or, AC² = 32,
or, AC = √32,
or, AC = √(16 * 2) = 4√2.
Therefore, AC will be 4√2 when AB = 4 and BC = 4, in the given right triangle.
Learn more about Pythagoras' Theorem at
https://brainly.com/question/231802
#SPJ2
Barry has been watching the geese that live in his neighborhood. The number of geese changes each week. n f(n) 1 56 2 28 3 14 4 7 Which function best shows the relationship between n and f(n)? f(n) = 28(0.5)n f(n) = 56(0.5)n−1 f(n) = 56(0.5)n f(n) = 112(0.5)n−1
Answer:
B. f(n) = 56(0.5)^n-1
Step-by-step explanation:
First, You have to find out the starting population, if you look at the problem you see the population starts at 56
f(x) = 56
Second, you know that the population goes down 50% each week so it has a decay of 0.5
f(x) = 56(0.5)
Third, you need to add the exponent of n to make it exponential. But, if you just add n then the the population would be 28 on week 1 which is incorrect. To fix that you make the exponent n-1 so when you are on week 1 it doesn't become 28 but it stays on 56, and on week 2 it's 28, ect
f(x) = 56(0.5)^n-1
Write your answer in scientific notation.
(6.4 x 10^3 ) + (5.2 x 10^4 )
Answer:
5.84 x10.^4
Step-by-step explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10
If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
What number must be added to the expression for it to equal zero? (–6.89 + 14.52) + (–14.52)
Answer:
The number to be added is 6.89
Step-by-step explanation:
Here, we want to know what number must be added to the expression to make it equal to zero.
Let the number be x
Thus;
-6.89 + 14.52 -14.52 + x = 0
-6.89 + x = 0
x = 6.89
Line m and point P are shown below. Part A: Using a compass and straightedge, construct line n parallel to line m and passing through point P. Leave all construction marks. Part B: Explain the process that you used to construct line n.
Answer:
The steps to construct a a line parallel to another line from a point includes
1) From the given line draw a transversal through the point
2) With the compass, copy the angle formed between the transversal and the given line to the point P
3) Draw a line through the intersection of the arcs of the angle construction to get the parallel line through the point P
Step-by-step explanation:
x - (-20) = 5 _________________
X - (-20) = 5
When you subtract a negative, change it to addition:
X + 20 = 5
Subtract 20 from both sides:
X = -15
Answer:
[tex]\boxed{x=-15}[/tex]
Step-by-step explanation:
[tex]x-(-20)=5[/tex]
[tex]\sf Distribute \ negative \ sign.[/tex]
[tex]x+20=5[/tex]
[tex]\sf Subtract \ 20 \ from \ both \ sides.[/tex]
[tex]x+20-20=5-20[/tex]
[tex]x=-15[/tex]
asap!!
~~~~~~
A line passes through point (–6, –1) and is parallel to the equation y = –2x – 5. What's the equation of the line?
Question 25 options:
y = –2x – 13
y = 12{"version":"1.1","math":"\(\frac{1}{2}\)"}x + 3
y = –12{"version":"1.1","math":"\(\frac{1}{2}\)"}x – 1
y = 2x + 5
click on picture for a, b, c ,or d
Answer:
y=−2x−13.
Step-by-step explanation:
The equation of the line in the slope-intercept form is y=−2x−5.
The slope of the parallel line is the same: m=−2.
So, the equation of the parallel line is y=−2x+a.
To find a, we use the fact that the line should pass through the given point: −1=(−2)⋅(−6)+a.
Thus, a=−13.
Therefore, the equation of the line is y=−2x−13.
state the vertical distance and horizontal distance of the two pairs of points given.
Answer:
the horizontal distance is the x-intercept, and the vertical distance is the y-intercept
1) x-int=1, y-int=1
2) x-int=6, y-int=5
Starting at the same spot on a circular track that is 80 meters in diameter, Hillary and Eugene run in opposite directions, at 300 meters per minute and 240 meters per minute, respectively. They run for 50 minutes. What distance separates Hillary and Eugene when they finish
Answer:
143.32 m
Step-by-step explanation:
Given the following :
Diameter of circular track = 80m
Hillary's speed = 300m per minute
Eugene's speed = 240m per minute
Run time = 50 minutes
Note: they both run in opposite direction.
Calculate the Circumference(C) of the circle :
C = 2πr or πd
Where r = radius ; d = diameter
Using C = πd
C = πd
C = π * 80
C = 251.327
Eugene's distance covered = (240 * 50) = 12000
Hillary's distance covered = (300 * 50) = 15000
Number turns :
Eugene = 12000/ 251.327 = 47.746561
Hillary = 15000/251.327 = 59.683201
Therefore ;
48 - 47.746561 = 0.253439
60 - 59.683201 = 0.316799
(0.253439+0.316799) = 0.570238
Distance which separates Eugene and Hillary when they finish :
0.570238 * 251.327 = 143.32 m
solve for x 5(x+1)=4(x+8)
Answer:
x=27
Step-by-step explanation:
expanding the above expression we get
5x+5=4x+32
grouping numbers with coefficient of x at the left side and constant at the right side we get
5x-4x=32-5
x=27
If you invest $600 at 5% interest compounded continuously, how much would you make after 6 years?
Answer:
809.915$
Step-by-step explanation:
Amount of money = Principal x e^(rate x year)
= 600 x e^(0.05 x 6)
= 809.915$
Answer:
$809.92
Step-by-step explanation:
(see attached for reference)
Recall that the formula for compound interest (compounded continuously) is
A = P e^(rt)
where,
A = final amount (we are asked to find this)
P = principal = given as $600
r = interest rate = 5% = 0.05
t = time = 6 years
e = 2.71828 (mathematical constant)
Substituting the known values into the equation:
A = P e^(rt)
= 600 e^(0.05 x 6)
= 600 (2.71828)^(0.30)
= $809.92
Solve logs (8 - 3x) = log20 for x.
A. X = 14
B. X = -13
C.x = -8
D. X= -4
Answer:
x = -4
Step-by-step explanation:
logs (8 - 3x) = log20
Since we are taking the log on each side
log a = log b then a = b
8 -3x = 20
Subtract 8 from each side
8 -3x-8 =20 -8
-3x = 12
Divide by -3
-3x/-3 = 12/-3
x = -4
Answer:
[tex] \boxed{\sf x = -4} [/tex]
Step-by-step explanation:
[tex] \sf Solve \: for \: x \: over \: the \: r eal \: numbers:[/tex]
[tex] \sf \implies log(8 - 3x) = log 20[/tex]
[tex] \sf Cancel \: logarithms \: by \: taking \: exp \: of \: both \: sides:[/tex]
[tex] \sf \implies 8 - 3x = 20[/tex]
[tex] \sf Subtract \: 8 \: from \: both \: sides:[/tex]
[tex] \sf \implies 8 - 3x - 8 = 20 - 8 [/tex]
[tex] \sf \implies - 3x = 12 [/tex]
[tex] \sf Divide \: both \: sides \: by \: - 3:[/tex]
[tex] \sf \implies \frac{-3x}{-3} = \frac{12}{-3} [/tex]
[tex] \sf \implies x = - 4[/tex]
prove that (3-4sin^2)(1-3tan^2)=(3-tan^2)(4cos^2-3)
Answer:
Proof in the explanation.
Step-by-step explanation:
I expanded both sides as a first step. (You may use foil here if you wish and if you use that term.)
This means we want to show the following:
[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]
[tex]=12\cos^2(\theta)-9-4\cos^2(\theta)\tan^2(\theta)+3\tan^2(\theta)[/tex].
After this I played with only the left hand side to get it to match the right hand side.
One of the first things I notice we had sine squared's on left side and no sine squared's on the other. I wanted this out. I see there were cosine squared's on the right. Thus, I began with Pythagorean Theorem here.
[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]
[tex]3-9\tan^2(\theta)-4(1-\cos^2(\theta))+12\sin^2(\theta)\tan^2(\theta)[tex]
Distribute:
[tex]3-9\tan^2(\theta)-4+4\cos^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]
Combine like terms and reorder left side to organize it based on right side:
[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
After doing this, I since that on the left we had products of sine squared and tangent squared but on the right we had products of cosine squared and tangent squared. This problem could easily be fixed with Pythagorean Theorem again.
[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
[tex]4\cos^2(\theta)-1+12(1-\cos^2(\theta))\tan^2(\theta)-9\tan^2(\theta)[/tex]
Distribute:
[tex]4\cos^2(\theta)-1+12\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
Combined like terms while keeping the same organization as the right:
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
We do not have the same amount of the mentioned products in the previous step on both sides. So I rewrote this term as a sum. I did this as follows:
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
Here, I decide to use the following identity [tex]\cos\theta)\tan(\theta)=\sin(\theta)[/tex]. The reason for this is because I certainly didn't need those extra products of cosine squared and tangent squared as I didn't have them on the right side.
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]
We are again back at having sine squared's on this side and only cosine squared's on the other. We will use Pythagorean Theorem again here.
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8(1-\cos^2(\theta))-9\tan^2(\theta)[/tex]
Distribute:
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8+8\cos^2(\theta)-9\tan^2(\theta)[/tex]
Combine like terms:
[tex]12\cos^2(\theta)-9+3tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)[/tex]
Reorder again to fit right side:
[tex]12\cos^2(\theta)-9+4\cos^2(\theta)\tan(\theta)+3\tan^2(\theta)[/tex]
This does match the other side.
The proof is done.
Note: Reordering was done by commutative property.
What is a 27 of the sequence 15, 10,5,...?
A.O
B. -75
c.
1/625
D. -115
Answer:
B. -75
Step-by-step explanation:
you count backwards from 5, 27 times
What are the domain and range of the real-valued function f(x)=2/(x+5)?
Answer:
Domain is all real numbers, x ≠ -5
Range is all real numbers, y ≠ 0
Step-by-step explanation:
What is another way to write 100,203 in other forms
Answer:
You can write in
Step-by-step explanation:
Lakhs
First write 100,203.
Put ones,tens,hundreds,thousands,ten thousands and lakh on top of each number from the extreme left.
This is how you can write 100,203 in another way. You can't write in any other way than this one.
Hope this helps....
Have a nice day!!!!
In a right angled triangle ABC, ACB =30 and AC=10cm a. calculate BAC b. calculate line AB
Answer:
10 cm is the answer because 30÷3 angles
Using a table of values, determine the solution to the equation below to the nearest fourth of a unit. 2^x=1-3^x
Answer:
Option (1)
Step-by-step explanation:
Given equation is,
[tex]2^x=1-3^x[/tex]
To determine the solution of the equation we will substitute the values of 'x' given in the options,
Option (1)
For x = -0.75
[tex]2^{-0.75}=1-3^{-0.75}[/tex]
0.59 = 1 - 0.44
0.59 = 0.56
Since, values on both the sides are approximately same.
Therefore, x = -0.75 will be the answer.
Option (2)
For x = -1.25
[tex]2^{-1.25}=1-3^{-1.25}[/tex]
0.42 = 1 - 0.25
0.42 = 0.75
Which is not true.
Therefore, x = -1.25 is not the answer.
Option (3)
For x = 0.75
[tex]2^{0.75}=1-3^{0.75}[/tex]
1.68 = 1 - 2.28
1.68 = -1.28
Which is not true.
Therefore, x = 0.75 is not the answer.
Option (4)
For x = 1.25
[tex]2^{1.25}=1-3^{1.25}[/tex]
2.38 = 1 - 3.95
2.38 = -2.95
It's not true.
Therefore, x = 1.25 is not the answer.
The row-echelon form of the augmented matrix of a system of equations is given.Find the solution of the system
Answer:
x = 9/4
y = 3/5
z = 2/3
w = -9/5
Step-by-step explanation:
Technically, the matrix is in reduced row echelon form. If there are zeros above and below the ones, it is RREF. If there are zeros only below the ones, then it's REF.
Since it is in RREF, the augmented numbers to the right of the bar are already your solutions. Simply label the variables.
Which of the following statements about fractions is not true? a. Proper fractions have a greater numerator than denominator b. Improper fractions are percentages greater than 100% c. Mixed fractions can be written as improper fractions d. The product of a fraction and its reciprocal is 1
Answer:
c
Step-by-step explanation:
Answer:
A. Proper fractions have a greater numerator than denominator.
Please help!! Thank you in advance! Will mark Brainliest!
Answer:
F , D, E
Step-by-step explanation:
The smallest angle is opposite the smallest side
The largest angle is opposite the largest side
DE is smallest so F is smallest
Then EF so D
DF is largest so E is the largest angle
Make the biggest possible number using the digits below only once 4 , 5 , 5 answer
Answer:
554
Step-by-step explanation:
The largest number (5) should go in the hundreds place, the second-largest number (also 5) should go in the tens place and the smallest number (4) should go in the units place so the answer is 554.