Answer:
ClF₃(g) + 2 H₂O(l) ⇒ 3 HF(aq) + HCl(aq) + O₂(g)
Explanation:
Let's consider the unbalanced equation for the reaction between chlorine trifluoride and water to form hydrofluoric acid, hydrochloric acid and oxygen gas.
ClF₃(g) + H₂O(l) ⇒ HF(aq) + HCl(aq) + O₂(g)
We will balance it using the trial and error method.
First, we will balance F atoms by multiplying HF by 3.
ClF₃(g) + H₂O(l) ⇒ 3 HF(aq) + HCl(aq) + O₂(g)
Then, we will balance H atoms by multiplying H₂O by 2.
ClF₃(g) + 2 H₂O(l) ⇒ 3 HF(aq) + HCl(aq) + O₂(g)
This equation is balanced.
21.5g of sodium chloride dissolves in 60g of water at25C. Calculate the concentration of the solution.
The table below provides data about a gas sample.
Volume
1.0 L
Pressure
303.9 kPa
Temperature
323 K
Which of the following can be determined using the data?
A the chemical composition of the gas
B. the condensation temperature of the gas
C. the distance between gas molecules in the sample
D. the number of gas molecules in the sample
Answer:
the number of gas molecules in the sample
PLEASE is possible to calculate the theoretical yield without a balanced equation?
No, you absolutely need a balanced equation because you need the coefficients to figure out the molar ratios plus you need the amount of one reactant or product to determine the theoretical yield.
No, it's not possible to calculate the theoretical yield without a balanced equation.
What is the theoretical yield?Theoretical yield is the yield that is calculated by the complete reaction of the limiting reagent. This is called expected or calculated amount of product.
[tex]\rm percent\; yield = \dfrac{(actual\; yield)}{(theoretical\; yield)} \times 100\\\\[/tex]
Thus, No, it's not possible to calculate the theoretical yield without a balanced equation.
Learn more about theoretical yield
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At a fixed volume, a four-fold increase in the temperature of a gas will lead to _______ in pressure.
Question 2 options:
A)
no change
B)
a two-fold decrease
C)
a four-fold decrease
D)
a four-fold increase
Answer:
D) a four-fold increase
Explanation:
According to Gay-Lussac's law, which states that the pressure of a given amount of gas is directly proportional to the temperature at a constant volume, the pressure increases with an increase in temperature.
According to this question, at a fixed volume, a four-fold increase in the temperature of a gas will lead to a four-fold increase in the pressure as well.
This reaction was at equilibrium when 0.2 atm of iodine gas was pumped into the container, what happened to the equilibrium and the partial pressures of the gases
Answer:
Q was < K. Partial pressure of hydrogen decreased, iodine increased
Explanation:
After iodine was added the Q was [Select] K so the reaction shifted toward the Products [Select] ,The partial pressure of hydrogen [Select], Iodine [Select] |,and hydrogen iodide Decreased
Based on the equilibrium:
H2(g) + I2(g) ⇄ 2HI(g)
K of equilibrium is:
K = [HI]² / [H2] [I2]
Where [] are concentrations at equilibrium
And Q is:
Q = [HI]² / [H2] [I2]
Where [] are actual concentrations of the reactants.
When the reaction is in equilibrium, K=Q.
But as [I2] is increased, Q decreases and Q was < K
The only concentration that increases is [I2], doing partial pressure of hydrogen decreased, iodine increased
38. Consider the following equilibrium:
2CO(g) + O2(g) =2CO2
Keg=4.0 x 10-10
What is the value of Key for 2CO2(g) + 2COR + O2g) ?
Answer:
[tex]Key=2.5x10^{-9}[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:
[tex]2CO_2(g) \rightleftharpoons 2CO(g) + O_2(g)[/tex]
By knowing that the equilibrium expression is actually:
[tex]Key =\frac{[CO]^2[O_2]}{[CO_2]^2} =\frac{1}{Keg}[/tex]
Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:
[tex]Key =\frac{1}{4.0x10^{-10}}\\\\Key=2.5x10^{-9}[/tex]
Regards!
Name an alkene that would yield the alcohol above on hydration. (Submit a single name even if there is more than one correct answer. Ignore double bond stereochemistry.) Name: fill in the blank 75a878faaf91fe7_1 2,3-Dimethylpentane . Specify whether you would use hydroboration/oxidation or oxymercuration.
Answer:
Enzyme ? ...............
1) 7.269 moles of oxygen gas are used in combusting butane (C H..). How many moles of carbon dioxide
gas are produced? You must start with a balanced chemical equation. Start with a balanced equation
Explanation:
C4H10 + 13/2O2 ---------> 4CO2 + 5H2O
so u can work out the amount of moles by doing
moles=mass/mr
mr of C4H10 is 12 × 4 + 10 =58
=7.269/58
= 0.125moles
Then u can use the molar ratio which is
6.5:4
0.125 ÷6.5 × 4 = 0.0769moles
hope this helps:)
Acetylide ions react with aldehydes and ketones to give alcohol addition products.
a. True
b. False
Answer:
a
Explanation:
At a constant temperature of 30 °C, an ideal gas occupies 2.78 Liters at a pressure of 1.27 atm. What will be the volume (L) at a pressure of 3.95 atm?
Answer:
[tex]V_2=0.894L[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the Boyle's law for an inversely proportional relationship between pressure and volume at constant temperature, as described in the problem statement:
[tex]P_2V_2=P_1V_1[/tex]
Thus, we solve for V2, final volume, to obtain the following result:
[tex]V_2=\frac{P_1V_1}{P_2} \\\\V_2=\frac{1.27atm*2.78L}{3.95atm}\\\\V_2=0.894L[/tex]
Regards!
In the presence of excess iodide ions, the iodine formed by reaction of iodide with NBS will react further to form triiodide ions. What does the triiodide combine with to form the blue color of the endpoint
Answer:
Starch.
Explanation:
When the triiodide combine with starch, it forms dark blue colour. Amylose in starch is responsible for the occurrence of a deep blue color when the iodine is combine with the starch. The iodine molecule goes inside of the amylose coil which makes a linear triiodide ion complex that goes into the coil of the starch that leads to an intense blue-black color in the end so we can say that starch turns the colour into blue.
What is the colour of red cabbage in vinegar?
Answer:
When red cabbage is treated with an acid or a base, it produces anthocyanin, a water-soluble pigment that changes color. In acidic situations with a pH less than 7, the pigment turns red, whereas in alkaline (basic) situations with a pH more than 7, the pigment turns bluish-green.
Explanation:
For the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression is: _________
a. K = [ H+] [NO2-] / [HNO2]
b. K = [ H+] [N] [O]2 / [HNO2]
c. K = [ H+] [NO2-] / [HNO2]
d. K = [H+]2 [NO2-] / [HNO2]
e. None of these
Answer: For the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression is K = [ H+] [NO2-] / [HNO2].
Explanation:
An expression that depicts the ratio of products and reactants raised to the power of their coefficients at equilibrium is called equilibrium constant.
An equilibrium constant is denoted by the symbol 'K'.
For example, the dissociation of nitrous acid in aqueous solution is as follows.
[tex]HNO_{2} \rightleftharpoons H^{+} + NO^{-}_{2}[/tex]
Hence, its expression for equilibrium constant is as follows.
[tex]K = \frac{[H^{+}][NO^{-}_{2}]}{[HNO_{2}]}[/tex]
Thus, we can conclude that for the equilibrium that exists in an aqueous solution of nitrous acid (HNO2, a weak acid), the equilibrium constant expression is K = [ H+] [NO2-] / [HNO2].
Define pure substance. How is it classified on the basid of chemical properties?
Answer:
if it is pure, the substances is either an element or a compound. if a substance is not chemically pure, it is either a heterogeneous mixture or a homogeneous mixture. if its composition is uniform throughout, it is a homogeneous.
If 4.00 moles of O2 occupies a volume of 5.0 L at a particular temperature and pressure, what volume will 3.00 moles of oxygen gas occupy under the same condition?
Answer: Volume occupied by 3.00 moles of oxygen gas under the same condition is 3.75 L.
Explanation:
Given: [tex]n_{1}[/tex] = 4.00 moles, [tex]V_{1}[/tex] = 5.0 L
[tex]n_{2}[/tex] = 3.00 moles, [tex]V_{2}[/tex] = ?
Formula used is as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{5.0 L}{4.00 mol} = \frac{V_{2}}{3.00 mol}\\V_{2} = 3.75 L[/tex]
Thus, we can conclude that volume occupied by 3.00 moles of oxygen gas under the same condition is 3.75 L.
Which expression gives the standard enthalpy
change of formation for methanol?
Answer:
25
Explanation:
bec
How to change τhe color of silver mercury to red???
Answer: This is the hue of mercury if you're looking for it. Mercury reacts with sulphur to generate a crimson hue. In the past, they always used a thermometer.
Explanation: However, due of its toxicity, individuals have switched to using alcohol in glass thermometers, which work similarly to mercury thermometers.
hope this helped best of luck mate! :) if this helped make sure to mark me Brainliest!
I need to summarize each type of radioactive decay.
Answer:
1. alpha - decreased mass by 4 - decrease atomic number by 2
2. beta electron - no change - increase by 1
3 - beta positron - no change - decrease by 1
4. gamma - no change - no change
5. electron capture - no change - decrease by 1
Explanation:
There are five main types of radioactive decay, a process where the nucleus loses energy by emitting radiation, these radiation or type of radioactive decay are alpha particles, beta particles, positron or beta positron, gamma particles and electron capture.
The effect of these particles causes a change in the number of subatomic which leads to different atomic mass and atomic numbers after the decay -
1. alpha - decreased mass by 4 - decrease the atomic number by 2
2. beta electron - no change - increase by 1
3 - beta positron - no change - decrease by 1
4. gamma - no change - no change
5. electron capture - no change - decrease by 1
I need the answer please
Answer:
the answer is the first one
Na+
If you have a cation Az +4 and an anion Cy-2 which of the following is the correct formula for an ionic compound?
A) Az4Cy2
B) Az2Cy4
C) AzCy2
D) Az2Cy8
Answer:
Az2Cy4
Explanation:
Ionic substances are composed of an ion pair. We arrive at the formula of an ionic substance by exchange of valency between the two ions involved in the compound.
In this case we have Az +4 and Cy-2. If we ignore the charges and the two ions and exchange the valency of the ions, the exchanged valencies are written as subscripts hence we arrive at the formula; Az2Cy4 as the formula of the ionic compound formed by the two ions.
4. Complete the following equations:
CuCl2 + Na2CO3 → 2 NaCl +............
FeSO4 + BaCl2 →
Cu(NO3)2 + CaCO3
Answer:
2NaCl + CuCO3
FeCl2 + BaSO4
CuCO3 + Ca(NO3)2
Explanation:
Presumably this is a double replacement reaction.
A+B + C+D → A+D + C+B
It seems I may be wrong so please try to work out the problem yourself to double check, keeping in mind the charges of each compound.
Phosphate buffers are commonly used in biological research. If a small amount of strong acid is added to a buffer solution that is 0.700 M H3PO4 and 0.700 M KH2PO4, which of the following statements is true?
A) [H3PO4] will increase, [KH2PO4] will decrease, and pH will slightly decrease.
B) [H3PO4] will increase, [KH2PO4] will decrease, and pH will not change.
C) [H3PO4] will decrease, [KH2PO4] will increase, and pH will slightly decrease.
D) [H3PO4] will decrease, [KH2PO4] will increase, and pH will slightly increase.
E) [H3PO4] will increase, [KH2PO4] will decrease, and pH will slightly increase.
F) [H3PO4] will decrease, [KH2PO4] will increase, and pH will not change
Answer:
A) [H3PO4] will increase, [KH2PO4] will decrease, and pH will slightly decrease.
Explanation:
A buffer is a solution which resists changes to its pH when a small amount of acid or base is added to it.
Buffers consist of a weak acid (HA) and its conjugate base (A–) or a weak base and its conjugate acid. Weak acids and bases do not completely dissociate in water, and instead exist in solution as an equilibrium of dissociated and undissociated species. When a small quantity of a strong acid is added to a buffer solution, the conjugate base, A-, reacts with the hydrogen ions from the added acid to form the weak acid and a salt thereby removing the extra hydrogen ions from the solution and keeping the pH of the solution fairly constant. On the other hand, if a small quantity of a strong base is added to the buffer solution, the weak acid dissociates further to release hydrogen ions which then react with the hydroxide ions of the added base to form water and the conjugate base.
For example, if a small amount of strong acid is added to a buffer solution that is 0.700 M H3PO4 and 0.700 M KH2PO4, the following reaction is obtained:
KH₂PO₄ + H+ ----> K+ + H₃PO₄
Therefore, [H₃PO₄] will increase, [KH₂PO₄] will decrease, and pH will slightly decrease.:
what will happen if atom hit earth with speed of light?
Answer:
A little atom will leave a big hole and a big atom cant travel that fast
Explanation:
Chemosynthesis and photosynthesis are both processes that produce food.
True or false?
Answer:
true
Explanation:
probably true
a) If we have a 4.5 L container of CH 10 gas at a temperature of 178 K and a pressure of 0.50 atm, then how many moles of CaHio do
we have?
b) How many grams of C4H1o do we have?
Answer:
a) 0.15 mol.
b) 8.95 g.
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to infer this problem is solved by using the ideal gas equation:
[tex]PV=nRT[/tex]
And proceed as follows:
a) Here, we solve for the moles, n, as follows:
[tex]n=\frac{PV}{RT} \\\\n=\frac{0.50atm*4.5L}{0.08206\frac{atm*L}{mol*K}*178K} \\\\n=0.15mol[/tex]
b) for the calculation of the mass, we recall the molar mass of butane, 58.12 g/mol, to obtain:
[tex]0.15mol*\frac{58.12g}{1mol} =8.95g[/tex]
Regards!
select the two atomic models that belong to the same element !
Answer:
The second and the third atomic model.
Explanation:
An element is identified by the no. of protons in the said element. Proton number cannot be changed. Both second and third atomic model have 5 protons, so they are of the same element.
Calculate the volume of 0.320-M NaOH solution needed to completely neutralize 74.0 mL of a 0.230-M solution of the monoprotic acid HBr. mL NaOH.
Answer:
53.2 mL
Explanation:
As this problem deals with the neutralization of a strong monoprotic acid and a strong base, we can solve it by using the following formula:
Ca * Va = Cb * VbWhere in this case:
Ca = 0.230 MVa = 74.0 mLCb = 0.320 MVb = ?We input the data:
0.230 M * 74.0 mL = 0.320 M * VbAnd solve for Vb:
Vb = 53.2 mLmolar mass of Beryllium
Answer:
The molar mass of Beryllium is 9.012182 u
What's 2+7 hehdhenbeidbnejdbdbdbdi
Answer:
Answer
9......
Explanation:
Explaination:
Obtain 2 test tubes. 2. Add 2 mL of animal blood plasma into the first test tube a. Use a pH test strip to measure the pH of the blood plasma. ______
Answer:
7.4
Explanation:
Plasma proteins are part of the buffer systems of blood plasma. Plasma contains both positively and negatively charged amino and carboxyl groups. These compounds' charged portions can attract and link hydrogen(H) and hydroxyl ions(OH-), therefore act as buffers.
Plasma serves as a weak and ineffective buffer. The pH of a buffer should always be around 7.4 which is nearly neutral. As such we may deduce from the first experimental observation that there is no change in pH.
