If the quadratic formula is used to find the solution set of 3x + 4x-2 = 0, what are the solutions? ​

Answer:

€3,551.05

Step-by-step explanation:

31*29=899

899*3.65=€3,551.05

the school will get an estimate of €3,551.05

Answer:

in jh ynhtym

hunt ghb JBL iggmmjuu ki ju nu j

Answer:

x = 5

arcEF = 58degrees

arcGH = 55degrees

Step-by-step explanation:

Find the diagram attached

The sum of angle on the straight line EH is 180degrees

Hence arcEF+ arcFG + arcGH = 180

10x+8 + 67 + 11x = 180

21x + 75 = 180

21x = 180 - 75

21x = 105

x = 105/21

x = 5

Since EF = 10x+8

arcEF = 10(5) + 8

arcEF = 50+8

arcEF = 58degrees

Also, arcGH = 11x

arcGH = 11(5)

arcGH = 55degrees

Answer:

2x² - 6x

Step-by-step explanation:

(3x² - 4x + 8) + (- x² - 2x - 8) ← remove both parenthesis

= 3x² - 4x + 8 - x² - 2x - 8 ← collect like terms

= 2x² - 6x

Answer:

Answer 1 :-

[tex]\implies m_1 = -3 [/tex]

[tex]\implies y - intercept = 7 [/tex]

Answer 2 :-

[tex]\implies m_1 = -\dfrac{1}{2} [/tex]

[tex]\implies y - intercept = -4 [/tex]

Step-by-step explanation:

The Slope Intercept Form of the line is given to us . The equations given are ,

[tex]\implies y + 3x = 7 [/tex]

[tex]\implies y + \dfrac{1}{2}x = -4 [/tex]

Now we know the standard equation of slope intercept form , is

[tex]\implies y = mx + x [/tex]

Where ,

So , we can write about the equations as ,

[tex]\implies y = -3x + 7 [/tex]

[tex]\implies y = - \dfrac{1}{2}x -4 [/tex]

On comparing to the Standard form ,

Answer 1 :-

[tex]\implies m_1 = -3 [/tex]

[tex]\implies y - intercept = 7 [/tex]

Answer 2 :-

[tex]\implies m_1 = -\dfrac{1}{2} [/tex]

[tex]\implies y - intercept = -4 [/tex]

Answer:

B

Step-by-step explanation:

plss pa brainliest me thanks

Answer:

Step-by-step explanation:

Use the formulas that allow us to find the point that divides the segment into a ratio which is

[tex]x=\frac{bx_1+ax_2}{a+b}[/tex]  and  [tex]y=\frac{by_1+ay_2}{a+b}[/tex] where a is 1 (comes from the ratio) and b is 3 (comes from the ratio as well). Filling in:

[tex]x=\frac{3(9)+1(6)}{1+3}=\frac{27+6}{4}=\frac{33}{4}[/tex] and then y:

[tex]y=\frac{3(-1)+1(-10)}{1+3}=\frac{-3-10}{4}=-\frac{13}{4}[/tex] so the coordinates in question are

[tex](\frac{33}{4},-\frac{13}{4})[/tex]

Answer:

Step-by-step explanation:

the answer would be (7,-7)

Answer:

12,-2

Step-by-step explanation:

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]

Here 5 is a constant so it can come out . So that,

[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]

Now we can write √x as ,

[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]

Simplify ,

[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]

On simplifying we will get ,

[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]

Answer:

41

Step-by-step explanation:

Answer:

Hello there,

The correct answer to this question would be D 1/6

Step-by-step explanation:

I had took the test and it said it was correct.

Anyways hope this helps

if the answer is correct pls mark Brainliest

thank you, have a nice day

Answer:

there are 6 units

hope this help

Answer:

Step-by-step explanation:

B/c  the bigger triangle is a copy of the smaller we can say

8[tex]\sqrt{3}[/tex] / 12  = x / 8[tex]\sqrt{3}[/tex]

then, solve for x

8[tex]\sqrt{3}[/tex](8[tex]\sqrt{3}[/tex]/12) = x

(64 *3) 12 = x

192 /12 = x

16 = x

nice,  the first answer looks good , then :P

Answer:

16

Step-by-step explanation:

Answer:

d=3

Step-by-step explanation:

13d=39

d=39/13

d=3

Hello!

6d + 7d = 39 <=>

<=> 13d = 39 <=>

<=> d = 39 : 13 <=>

<=> d = 3 => 6 × 3 + 7 × 3 = 39

Good luck! :)

Answer:

% change in perimeter = 43. 44 %

% change in area = 16 %

Step-by-step explanation:

initial perimeter of the rectangle = 2(2p + p)

= 6p

initial area of the rectangle = 2p × p

= 2p²

therefore,

= 2p + 0.8p = 2.8 p

= p - 0.4p

= 0.6 p

= 3.4 p

= 1.68 p²

% change in perimeter

[tex] = \frac{6p - 3.4p}{6p} \times 100 \\ = \frac{2.6p}{6p} \times 100 \\ = 43.33\%[/tex]

% change in area

[tex] \frac{2 {p}^{2} - 1.68 {p}^{2} }{2 {p}^{2} } \times 100 \\ = \frac{0.32}{2} \times 100 \\ = 16\%[/tex]

Answer:

Step-by-step explanation:

Step-by-step explanation:

w = 34° (alternate interior angles)

x = 34° (vertically opposite angles)

y = 101°

z = 79° (corresponding angles)

Answer:

C) 3 times the sq root of 3

Step-by-step explanation:

In a right angle triangle, the COS is definned as the ajacent side over the hypotenuse. So

COS 60 = JK/JL

COS 60 = JK/(6*sq root 3)

.5 = JK/(6*3**1/2)

JK = .5 *(6*3**1/2)

JK = 3*3**1/2

Answer:

x = 63.9

Step-by-step explanation:

We have:

[tex]\frac{QR}{sin35}[/tex] = [tex]\frac{78}{sin90}[/tex]

=> QR × sin90 = 78 × sin35

=> QR × sin90 = 44.7

=> QR = 44.7

But, we also have: [tex]x^{2}[/tex] + [tex]QR^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] + [tex]44.7^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] = 6084 - 1998.09

=> [tex]x^{2}[/tex] = 4085.91

=> x = [tex]\sqrt{4085.91}[/tex] = 63.9211.. = 63.9

<3 Have a nice day!!

9514 1404 393

Answer:

  3.31227766..., irrational

Step-by-step explanation:

  3/20 +√10 = 0.15 + 3.16227766017...

The root of 10 is irrational, so adding that to a rational number will give an irrational sum.

The sum is about 3.31227766017..., an irrational number.

Answer:

A

Step-by-step explanation:

Answer:

y = - 35

Step-by-step explanation:

Expressing as a fraction , that is

[tex]\frac{y}{-7}[/tex] = 5 ( multiply both sides by - 7 to clear the fraction )

y = - 35

Answer:

rs. 81

Step-by-step explanation:

given,

mp. = 1620

sp. = 1539

now,

discount = mp - s.p = 1620 - 1539 = 81

Answer:

1 hour

Step-by-step explanation:

hope it helps ....

Hello,

we are going to use the theorem of the bissectrice. (if this word is good in english)

[tex]\dfrac{KL}{LM} =\dfrac{KN}{NM} \\\\\dfrac{8}{x} =\dfrac{14}{20-x} \\\\8(20-x)=14x\\\\160-8x=14x\\\\22x=160\\\\x=\frac{160}{22} \\\\x=\frac{80}{11} \\\\\\x=7.\overline{27}[/tex]

Answer:

[tex]\frac{5\sqrt{2} }{2}[/tex]

Step-by-step explanation:

Divide 5 by [tex]\sqrt{2}[/tex] , then rationalize denominator

Answer:

Solution given:

Since the given triangle is isosceles and right angled triangle

perpendicular [p]=base[b]=x

hypotenuse [h]=5

we have

by using Pythagoras law

p²+b²=h²

x²+x²=5²

2x²=25

x²=25/2

x²=18

x=[tex]\sqrt{\frac{25}{2}}[/tex]

x=[tex]\bold{\frac{5\sqrt{2}}{2}}[/tex]

Answer:

The answer would be

Step-by-step explanation:

you multiple 8 and 5 then you multiple 12 (inches) then subtract the inch that makes up 12 let me know if you need help

Answer:

1  4/5

Step-by-step explanation:

3/4 ÷ 5 /12

Copy dot flip

3/4 * 12/5

Rewriting

3/5 * 12/4

3/5 * 3

9/5

1 4/5

Answer:

Step-by-step explanation:

Prime factorize 8 and 64

8 = 2* 2 * 2 = 2³

64 = 2*2*2 *2*2*2 = 2⁶

2*8*64 = 2* 2³ *2⁶ = 2¹⁺³⁺⁶ = 2¹⁰

In exponent multiplication, if base are same, then add the exponents.