I need to know exactly how to write "find the equation of the line below"

Step-by-step explanation:

A = 690ft + B

A + B = 1.384ft

(690ft + B) + B = 1.384ft

2B = 1.384ft - 690ft

2B = 694ft

B = 694ft ÷ 2

B = 347ft

A = 690ft + B

A = 690ft + 347ft

A = 1.037ft

Tower A → 1.037 feet

Tower B → 347feet

Answer:

16)  7⁻²

17) -1⁻²

Step-by-step explanation:

plug in the x=, y=, and n= into the equation.

Answer:

ans is -n(4n2-3)..........

Answer:

value of r is 6

Step-by-step explanation:

Given that the slope is 1/2

So we can set up the linear equation like this:

y= 1/2x + b

Since it also goes through (-5, 2)

plug in:

[tex]2 = \dfrac12*-5 + b\\b=2 +2.5 = 4.5\\y = \dfrac12x +4.5[/tex]

Then we plug in x=3 to find out the value of r

[tex]r = \dfrac12*3+4.5=1.5+4.5=6[/tex]

Answer:

Distance = 4

Step-by-step explanation:

Given the linear equation of line ℓ, y = 5 which is a horizontal line in which its slope, m = 0 (zero slope), and each of the x-coordinates along the line have the same y-coordinate of y = 5.

In order to determine the distance of the horizontal line from the given point Q, (0, 1), use the following distance formula:

[tex]d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}}[/tex]

Choose any x-coordinate to pair with the y-coordinate, y = 5. Let's use the y-intercept, (0, 5).

Let  (x₁, y₁) = (0, 1)  

      (x₂, y₂) = (0, 5)  

Substitute these values into the distance formula:

[tex]d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}}[/tex]

[tex]d = \sqrt{(0 - 0)^{2} + (5 - 1)^{2}}[/tex]  

[tex]d = \sqrt{(4)^{2}}[/tex]

[tex]d = \sqrt{16}[/tex]

d = 4  

Therefore, the distance of line ℓ from point Q is 4.

Answer:

19j-9

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

10+9=19j

-7-2=9

Answer:

(14.88-1.88) divided by 12

Step-by-step explanation:

hope this helps!

Answer:

5 to the power of 3 5times5times5

Step-by-step explanation:

Answer:

The total value of toys the factory produces in a day is $10,000.

Step-by-step explanation:

One Toy = $10

Workers = 40

Toys Made By Each Worker Per Day = 25

The factory makes 1,000 toys per day and 5,000 toys per week. Each toy has a value of $10 so the value of toys in one day would add up to $10,000. The toy factory would also make $50,000 a week.

Answer:

24

Step-by-step explanation:

S = ½ × 12 × 4

S = 24

._._._._._._.

Answer:

im pretty sure its 2025

Answer:

2025

Step-by-step explanation:

Answer:

About 2.9 minuets

Step-by-step explanation:

I hope this helps

Answer:

v=(-4w)/(-w+2)

Answer:

3

30

24

16

72

14

10

63

Hello!

the answer is C! ( [tex]y=\frac{1}{3} x-6[/tex] )

hope that helps!<3 have a good day!:))

Answer:

-1/7

Step-by-step explanation:

1/5 · (-2/7) = -2/35

= -2/35 · 5/2 = -10/70

simplified -10/70

-1/7

Answer:

He has 31 students

Step-by-step explanation:

You know this because 49.6 ÷ 1.6 = 31

Answer:

130

Step-by-step explanation:

(x - 129) * 129 = 129

x - 129 = 129/129

x - 129 = 1

x = 129 + 1

x = 130

Answer:

x could equal 130 but I'm not sure about this one

Step-by-step explanation:

you take 130-129 which equal 1 then times 1 by 129 and it equals 129... again sorry if it's not right because I'm not entirely sure how to do this I'm pretty sure I did it correct though

The moment generating function is defined by

[tex]M_X(t) = \mathbb E[e^{tX}][/tex]

Recall the power series expansion for the exponential function:

[tex]\displaystyle \sum_{n=0}^\infty \frac{x^n}{n!} = 1 + x + \frac{x^2}2 + \frac{x^3}6 + \cdots[/tex]

Then by extension, the MGF could be similarly written as

[tex]\displaystyle M_X(t) = \mathbb E \left[1 + Xt + \frac{(Xt)^2}2 + \frac{(Xt)^3}6 + \cdots\right][/tex]

There's a certain theorem (due to Fubini, in case you're interested in learning more about it) that let's us exchange the order of integration (recall the definition of expectation for continuous random variables) and summation, so that

[tex]\displaystyle M_X(t) = \mathbb E[1] + \mathbb E[Xt] + \mathbb E\left[\frac{X^2t^2}2\right] + \mathbb E\left[\frac{X^3t^3}6\right] + \cdots[/tex]

and by the linearity of expectation,

[tex]\displaystyle M_X(t) = 1 + \mathbb E[X] t + \frac12 \mathbb E\left[X^2\right] t^2 + \frac16 \mathbb E\left[X^3\right] t^3 + \cdots[/tex]

and here we see where the name MGF comes from: the coefficient of the n-th order term in the series expansion "generates" the n-th moment, which is defined as E[Xⁿ].

Now, recall the definition of variance:

[tex]\mathrm{Var}(X) = \mathbb E\left[\left(X - \mathbb E[X]\right)^2\right][/tex]

[tex]\mathrm{Var}(X) = \mathbb E\left[X^2\right] - \mathbb E[X]^2[/tex]

and this is exactly the difference between the second moment and the square of the first moment.

So if you know the MGF, then you essentially get the variance for free with little effort. By differentiating the MGF, we get

[tex]\displaystyle M_X''(t) = \mathbb E[X] + \mathbb E\left[X^2\right] t + \frac12 \mathbb E\left[X^3\right] t^2 + \cdots[/tex]

and setting t = 0 lets us recover the first moment, E[X].

Differentiating again gives

[tex]\displaystyle M_X'(t) = \mathbb E\left[X^2\right] + \mathbb E\left[X^3\right] t + \cdots[/tex]

and setting t = 0 once again recovers the second moment.

Then in terms of the MGF, we have

[tex]\boxed{\mathrm{Var}(X) = M_X''(0) - M_X'(0)^2}[/tex]

Answer:

metric

Step-by-step explanation:

it's the most widely used and will most likely be the easiest to use

Answer:

answer is a

Step-by-step explanation:

i think hope it helped

The solutions to the questions if y is represented by the formula y = a(x - 100)(x - 200) are:

a) The value of a = -2000

b) The maximum profit the company can make = $5,000,000

To make maximum profit, 150 computers must be produced

c) The company must produce between 140 and 160 computers to make at least $4,800,000

The equation representing the company's profit is:

y = a(x - 100)(x - 200)  for x > 20

If 120  computers are produced, the profit will be $3,200,000

That is, y = 3,200,000 if x = 120

a) Find the value of a

3,200,000 = a(120 - 100)(120 - 200)

3200000 = -16000a

a = -3200000/1600

a = -2000

b) Maximum profit the company can make

The equation becomes:

y = -2000(x - 100)(x - 200)

y = -2000(x² - 200x - 100x + 20000)

y = -2000(x² - 300x + 20000)

y = -2000x² + 600000x - 40000000

dy/dx = -4000x + 600000

dy/dx = 0 at maximum value

-4000x  +  600000 = 0

4000x  =  600000

x  =  600000/4000

x   =  150

To make maximum profit, 150 computers must be produced

Substitute x = 150 into y = -2000x² + 600000x - 40000000 to find the maximum profit

y  = -2000(150²) + 600000(150) - 40000000

y = 5000000

The maximum profit the company can make = $5,000,000

c) Calculate the range of the number of computers to be produced If the company targets to make at least $4,800,000

-2000x² + 600000x - 40000000 ≥ 4800000

-2000x² + 600000x - 40000000 - 4800000 ≥ 0

-2000x² + 600000x - 44800000 ≥ 0

Divide through by -2000

x² - 300x +22400 ≤ 0

(x - 140)(x - 160) ≤ 0

140 ≤ x ≤ 160

The company must produce between 140 and 160 computers to make at least $4,800,000

Learn more here: https://brainly.com/question/25471478

Answer:

try kopo

Step-by-step explanation:

55+1200+300=1555

Answer:

Step-by-step explanation:

start by graphing it (see picture)

formula for a parabola: y=ax²

using the coordinates (600,55) we get

55=a*600²

a=55/(600²)

so now it's just a matter of plugging in 300 for x

(55/600²)*300²= 13.75

Answer:

equilateral triangle is a triangle in which all 3 sides have the same length

The differences between the distances from the receiver to the two

transmitters is a constant.

Reasons:

The location of the transmitters = (-100, 0) and (100, 0)

The difference in the distance from the receiver to the transmitters = 180 miles.

Let the distances from the receiver to the transmitters be d₁ and d₂, we have;

|d₂ - d₁| = 180 = 2·a

[tex]\displaystyle a = \frac{180}{2} = 90[/tex]

c = The x-coordinates of the transmitters = 100

b² = c² - a²

∴ b² = 100² - 90² = 1900

b = √(1900) = 10·√(19)

Therefore;

The general form of the equation of an hyperbola is presented as follows;

[tex]\displaystyle \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1[/tex]

The standard form of the hyperbola that the receiver sits on if the transmitters behave as foci of the hyperbola is; [tex]\displaystyle \underline{\frac{y^2}{90^2} - \frac{x^2}{10\left(\sqrt{19} \right)^2} = 1}[/tex]

Learn more here:

https://brainly.com/question/4515332

Answer:

I think it is parallel

Step-by-step explanation:

Answer:

[tex]60[/tex]

60

Step-by-step explanation:

boys 10 ×10 100

------- = ---- ------

girls 6×10 60

Answer:the answer is 50

Step-by-step explanation:

75-140=65

65-45=20

75-35=45

45+45=90

30+20=50

In total there are 50 GREEN JOLOS I couldn’t get the answer myself so I sat down and actually wrote the problem out I’m taking a exam so I’ll let you guys know if it’s accurate.

Answer:

6lbs

Step-by-step explanation:

7.50 can only go into 20, two times

7.50

×   2

-------

15.00