with what force will Annabella’s car hit a tree if her car has a mass of 5000 kg and an acceleration of 2 m/s2

Answer:

• Average current = 25,000 Amperes

• Time = 0.80 seconds

a)

[tex]{ \rm{quantity \: of \: charge = current \times time}} \\ { \rm{q = 25000 \times 0.80}} \\ { \boxed{ \mathfrak{answer : \: { \rm{quantity \: of \: charge = 20000 \: coulombs}} }}}[/tex]

b)

[tex]{ \rm{number \: of \: electrons = \frac{current}{charge \: quantity} }} \\ \\ { \rm{n = \frac{25000}{20000} }} \\ \\ { \boxed{ \mathfrak{ \: answer : \: { \rm{n = 1.25 \: }}}}}[/tex]

[tex]{ \underline{ \mathfrak{ \green{Good \: grace}} \: \:⚜ \: \: { \blue{ \mathfrak{Good \: God}}}}}[/tex]

The given kinematic equations of motion are derived from Newton's Laws

of Motion.

Reasons:

The direction the ball is kicked = Upwards in the air

Maximum height to which the ball rises = 6.25 m

A) The speed of the ball the instant it left the soccer player's foot

Solution:

The equation to use is; v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)

[tex]a_y[/tex] = The acceleration due to gravity ≈ -9.81 m/s²

At the maximum height, y - y₀ = 6.25 m

The velocity at the maximum height, v = 0

v₀ = The speed of the ball the instant it left the soccer player's foot

Which gives;

v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)

0 = v₀² - 2 × 9.81 × (6.25) = v₀² - 122.625

v₀² = 122.625

v₀ = √(122.625) ≈ 11.074

The ball's speed the instant it left the soccer player's foot, v₀ ≈ 11.074 m/s.

B) Required:

The time it takes the soccer ball to rise to the maximum height.

Solution:

The equation of motion required is v = v₀ + [tex]a_y[/tex]·t

At the maximum height, v = 0

v₀ ≈ 11.074 m/s

v = v₀ + [tex]a_y[/tex]·t

Which gives;

0 = 11.074 - 9.81 × t

[tex]t \approx \dfrac{11.074}{9.81} \approx 1.129[/tex]

The time it took the ball to rise to its maximum height, t ≈ 1.129 seconds

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Answer:

A

Explanation:

Explanation:

All motions are relative to some frame of reference. Saying that a body is at rest, which means that it is not in motion, merely means that it is being described with respect to a frame of reference that is moving together with the body

Answer:

Motion is always described in relation to a reference point.

Explanation:

For example, if a car is driving at the speed of 30 miles per hour and you are standing by the road, to you, the car appears to be moving 30 miles per hour down the road. However, if you were in a car also driving at 30 miles per hour next to the truck, the same truck wouldn't appear to move.

Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun. The answer is option C

According to Kepler's third law of planetary motion for planets and satellites, he described circular orbit about the same center body stating that:

The squared of the period is directly proportional to the cube of the radius. That is,

[tex]T^{2} \alpha r^{3}[/tex]

The orbital period formula is expressed as :

[tex]T^{2}[/tex] = 4[tex]\pi ^{2}[/tex] [tex]r^{3}[/tex]  ÷ GM

Suppose a planet orbits a star at the same distance as Earth (1 AU) but with a period of roughly 200 Earth days. The mass of the central star will be greater than the mass of our sun based on the formula given above.

In a geostationary orbit, whatever the mass of the satellite may be, they will travel at the same speed in a particular orbit. mass M in the above formula becomes the mass of the sun or the center mass.

Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun.

Therefore, the correct answer is option C

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Answer:

Alice works with natural rubber and Julio works with vulcanised rubber.

Explanation:

Answer:

B. Alice works with natural rubber, and Julio works with vulcanized rubber.

Explanation:

I just took the test and got 100 percent.

I hope this helps you!!!!

Please mark my answer the Brainiset. Thank You!!!!!

Answer:

Given equation

[tex]\\ \sf\longmapsto Zn+HCl\longrightarrow ZnCl_2+H_2[/tex]

Balanced equation

[tex]\\ \sf\longmapsto Zn+2HCl=ZnCl_2+H_2[/tex]

Reactant side:-

Product side:-

Hence balanced

Answer:

1 2 1 1

Explanation:

Answer:

The entire electromagnetic spectrum, from the lowest to the highest frequency (longest to shortest wavelength), includes all radio waves (e.g., commercial radio and television, microwaves, radar), infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.

By Newton's third law, we will see that the force that block A exerts on block B is equal in magnitude but in opposite direction than the force that block B exerts on block A.

Remember that Newton's third law says that whenever two objects interact, they exert equal and opposite forces on each other.

The force that block B exerts on block A is equal to block B's weight, which is:

[tex]W_b = 0.05kg*9.8m/s^2 = 0.49 N[/tex]

Then the force that block A exerts on block B is equal in magnitude but in opposite direction, thus it will be equal to:

F' = -0.49N

Then the diagram is the one that you can see below.

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Answer:

1. The magnetic pole is the region at each end of a magnet where the external magnetic field is the strongest.

2. magnetic line of force - a line of force in a magnetic field. field line, line of force - an imaginary line in a field of force; direction of the line at any point in the direction of the force

Explanation:

Answer:

I think it's true,,

Explanation:

maybeee truee

Answer:

False -    

F = G M1 M2 / R^2

So F depends on M1 and M2 and as long either is not zero there will be a gravitational force between them.

Answer:

It is important to use renewal resources because we use so many non- renewable resources that we may lose the ability to make a lot of things like gasoline or power for our cities.

Answer:

2400m/s , 2240,2080,1920m/s

Answer:

The rocket travelled 37km per minute

Explanation:

185÷5=37

Answer:

[tex]V_{2.2} =2.2V[/tex]

Fast and loose: that's a classic voltage divider. the drop from the i-th resistor is [tex]R_i \over {\sum R}[/tex] of the drop across the whole series. In our situation, it's [tex]2.2\cdot 10^3 \over {2.2\cdot10^3 + 6.8\cdot 10^3[/tex] of 9 V. By plugging numbers in a calculator, it's 22/90 of 9V, or 2.2V

With Ohm's Law

The series is equivalent of a single resistor of Resistance [tex]2.2\cdot 10^3+6.8\cdot 10^3 \Omega = 9.0 k\Omega[/tex]. By Ohm's first Law ([tex]V=Ri[/tex]) the current flowing through the resistor is [tex]9V = 9*10^3\Omega i \rightarrow i=1mA[/tex]. At this point, the drop across the first resistor is, again by Ohm's law[tex]V = 2.2 \cdot 10^3 \Omega \cdot 1\cdot 10^{-3} A = 2.2V[/tex]

Answer:

Two positively charged particles

Explanation:

I said two positively charged particles because if I say c or d what ever it is for you guy it can be wrong so just pick the one that says Two positively charged particles

Answer: C  Two positively charged particles.

Explanation:

just trust me on it, i've done the same quiz.

The acceleration of the car over the 2 minutes is 0.07 m/s².

The acceleration of an object is the rate of change of velocity of the object with time.

The acceleration of the car over the 2 minutes is calculated as follows;

a = Δv/t

a = (v - u) / t

where;

a = (22.22 - 13.89) / 120

a = 0.07 m/s²

Thus, the acceleration of the car over the 2 minutes is 0.07 m/s².

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Answer: The free - body diagrams for blocks A and B. frictionless surface by a constant horizontal force F = 100 N. Find the tension in the cord between the 5 kg and 10 kg blocks. The string that attaches it to the block of mass M2 passes over a frictionless pulley of negligible mass. The coefficient of kinetic friction Hk between M.

Explanation: Hope this helped :)

Answer:

The sum of vectors P and Q is given by the vector R, the resultant sum vector using the parallelogram law of vector addition. If the resultant vector R makes an angle ϕ with the vector P, then the formulas for its magnitude and direction are: |R| = √(P2 + Q2 + 2PQ cos θ) β = tan-1[(Q sin θ)/(P + Q cos θ)]

Answer:

Sorry I need points [tex] \boxed{}[/tex]

Answer:

A - Juan

Explanation:

I took the test!

Answer:

"H" is a chemical symbol and "H2" is chemical formula.

Answer:

I think its

10 kg

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If the mass of an object is approximately 60 kg on earth then its mass remains the same on Mars which is 60 kg because mass does not change from place to place.

Mass in physics is a numerical representation of inertia, a fundamental property of all matter. What a body of matter is fundamentally is the resistance it offers to a change in its speed or location brought on by the application of a force. The more mass a body has, the less of a change a force exerts results. The kilogram is the unit of mass in the International System of Units, and it is defined by Planck's constant as being equal to 6.62607015 × 10⁻³⁴ joules second (SI).

According to the question, the weight of an object depends on gravity which is different from place to place so weight also varies from place to place but the mass is constant everywhere it does not change. So, if the mass of an object is 60 kg on earth then it remains the same on mars also.

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Answer:

120km

Explanation:

To get speed you divide distance by time.

Answer: decreases by 7.5

Explanation: