Hey, I’m new to this app i download the app today, and i hope if is there people who can help me with this question in the picture above!!

Answer:

The rate of change of f(x) is faster than the rate of change of g(x).

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

*Note:

Rate of Change is determined by slope.

Step 1: Define

f(x) = 3x + 5

↓ Compare to y = mx + b

Slope m = 3

g(x) = 2x + 5

↓ Compare to y = mx + b

Slope m = 2

Step 2: Answer

We can see that the slope of f(x) is greater than g(x).

∴ the rate of change of f(x) would be greater than g(x).

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (- 4, 2 ) into the partial equation

2 = - 8 + c ⇒ c = 2 + 8 = 10

y = 2x + 10 ← equation of line

Answer:

(+5)=S , be the correct answer

Answer: s = +5

Step-by-step explanation: Since s is being multiplied by -7, to get s by itself, we need to divide by -7 on both sides of the equation.

So we get s = +5 which is the solution to our equation.

Answer:

15/16 (93.75%)

Step-by-step explanation:

List of Possible Combinations:

BBBB, BBBG, BBGB, BBGG, BGBB, BGBG, BGGB, BGGG, GBBB, GBBG, GBGB, GBGG, GGBB, GGBG, GGGB, GGGG

As you can see, only 1 out of 16 of the possible combinations is all boys. This means that the chance of at least 1 girl among the 4 children is 15 out of 16 (15/16) or 93.75%

Given:

The rational function is:

[tex]f(x)=\dfrac{5-x}{x^2+5x+6}[/tex]

To find:

The points on the graph at the function value [tex]f(x)=3[/tex].

Solution:

We have,

[tex]f(x)=\dfrac{5-x}{x^2+5x+6}[/tex]

Substituting [tex]f(x)=3[/tex], we get

[tex]3=\dfrac{5-x}{x^2+5x+6}[/tex]

[tex]3(x^2+5x+6)=5-x[/tex]

[tex]3x^2+15x+18=5-x[/tex]

Moving all the terms on one side, we get

[tex]3x^2+15x+18-5+x=0[/tex]

[tex]3x^2+16x+13=0[/tex]

Splitting the middle term, we get

[tex]3x^2+3x+13x+13=0[/tex]

[tex]3x(x+1)+13(x+1)=0[/tex]

[tex](3x+13)(x+1)=0[/tex]

Using zero product property, we get

[tex](3x+13)=0\text{ or }(x+1)=0[/tex]

[tex]x=-\dfrac{13}{3}\text{ or }x=-1[/tex]

Therefore, the required values are [tex]-\dfrac{13}{3},-1[/tex].

what? ;-;.............

Answer:4 ma boi

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

because I am god at meth and very smart

Answer:

-2

Step-by-step explanation:

2x-y=-8-1equation

2x=-8+y

x=-8+y -2equation

2

then, taking 1st equation;

2x-y=-8

2(-8+y/2)-y=-8

-16+2y-y=-8

4

-16+2y-4y=-8

4

-16-2y=-8*4

-2y=-32+16

y=-16/-2

y=4

for x

x=-8+y

2

x=-8+4

2

x=-4

2

x=-2

Answer:

option 2 4x²- 8x -4 ghhhhhhhhhhj8

Answer:

[tex] {4}^{m} = \frac{1}{16} [/tex]

[tex] {4}^{m} = {4}^{ - 2} [/tex]

[tex]same \: base \: so[/tex]

[tex]m = - 2[/tex]

[tex]hope \: this \: help \: u[/tex]

Answer:

Answer:

{4}^{m} = \frac{1}{16}4

m

=

16

1

{4}^{m} = {4}^{ - 2}4

m

=4

−2

same \: base \: sosamebaseso

m = - 2m=−2

hope \: this \: help \: uhopethishelpu

Answer:

The numerical limits for a C grade are 60.6 and 69.1.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 67 and a standard deviation of 7.3.

This means that [tex]\mu = 67, \sigma = 7.3[/tex]

Find the numerical limits for a C grade.

Below the 100 - 38 = 62th percentile and above the 18th percentile.

18th percentile:

X when Z has a p-value of 0.18, so X when Z = -0.915.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.915 = \frac{X - 67}{7.3}[/tex]

[tex]X - 67 = -0.915*7[/tex]

[tex]X = 60.6[/tex]

62th percentile:

X when Z has a p-value of 0.62, so X when Z = 0.305.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.305 = \frac{X - 67}{7.3}[/tex]

[tex]X - 67 = 0.305*7[/tex]

[tex]X = 69.1[/tex]

The numerical limits for a C grade are 60.6 and 69.1.

Answer: i think its the last one bc if you multiply 9 and 3 in its gets you 18

Step-by-step explanation:

Answer:

V=(1/3)πr²h

v=

[tex] \frac{1}{3} \times {3}^{2} \times 9 \times \pi \\ = 27\pi[/tex]

27pi in³

27pi in³First option

Brainliest please~

The percent decrease on a TV after the markdown to the nearest tenth​ is 23.6%.

The percent decrease formula can be expressed as:

Percent decrease = [( original value - new value ) / original value ] × 100%

Given the data in the question:

The original value of the TV = $550

New value after markdown  = $420

Percent decrease =?

Plug the given values into the above formula and solve for the percent decrease.

Percent decrease = [( original value - new value ) / original value ] × 100%

Percent decrease = [( 550 - 420 ) / 550 ] × 100%

Percent decrease = [ 130 / 550 ] × 100%

Percent decrease = 0.2363 × 100%

Percent decrease = 23.6%

Therefore, the percent decrease is 23.6%.

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Answer:

-2,2

Step-by-step explanation:

Let

[tex]y_1=4x^2-c^2[/tex]

[tex]y_2=c^2-4x^2[/tex]

We have to find the value of c such that the are of the region bounded by the parabolas =32/3

[tex]y_1=y_2[/tex]

[tex]4x^2-c^2=c^2-4x^2[/tex]

[tex]4x^2+4x^2=c^2+c^2[/tex]

[tex]8x^2=2c^2[/tex]

[tex]x^2=c^2/4[/tex]

[tex]x=\pm \frac{c}{2}[/tex]

Now, the area bounded by two curves

[tex]A=\int_{a}^{b}(y_2-y_1)dx[/tex]

[tex]A=\int_{-c/2}^{c/2}(c^2-4x^2-4x^2+c^2)dx[/tex]

[tex]\frac{32}{3}=\int_{-c/2}^{c/2}(2c^2-8x^2)dx[/tex]

[tex]\frac{32}{3}=2\int_{-c/2}^{c/2}(c^2-4x^2)dx[/tex]

[tex]\frac{32}{3}=2[c^2x-\frac{4}{3}x^3]^{c/2}_{-c/2}[/tex]

[tex]\frac{32}{3}=2(c^2(c/2+c/2)-4/3(c^3/8+c^3/28))[/tex]

[tex]\frac{32}{3}=2(c^3-\frac{4}{3}(\frac{c^3}{4}))[/tex]

[tex]\frac{32}{3}=2(c^3-\frac{c^3}{3})[/tex]

[tex]\frac{32}{3}=2(\frac{2}{3}c^3)[/tex]

[tex]c^3=\frac{32\times 3}{4\times 3}[/tex]

[tex]c^3=8[/tex]

[tex]c=\sqrt[3]{8}=2[/tex]

When c=2 and when c=-2 then the given parabolas gives the same answer.

Therefore, value of c=-2, 2

Answer:

the measurement of N is D, 81.

Step-by-step explanation:

The angle measurement of a Right Angled Triangle is 90 degrees. And based off the angle dimension given in the image above ( 9 degrees ), you need to subtract 90 ( the angle dimension of the triangle) with the angle dimension given (9 degrees) which gets you to an answer of 81 degrees.

Answer:

104 m²

Step-by-step explanation:

Area of the whole shape = area of the triangle + area of the rectangle

= ½*b*h + L*W

Where,

b = 8 m

h = 6 m

L = 10 m

W = 8 m

Plug in the values into the equation

Area of the whole shape = ½*8*6 + 10*8

= 24 + 80

= 104 m²

Answer:

72 in. sq.

Step-by-step explanation:

6 x 6 = 36

6 x 6 = 36 / 2 = 18

6 x 6 = 36 / 2 = 18

18 + 18 + 36 = 72.

Hope this helps!

If there is something wrong just let me know.

Answer:

the number before the first variable (first term)

Step-by-step explanation:

this appears to be an incomplete question. The numerical coefficient of a term is the number before the variable.

the constant is the number without a variable.

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

[tex](a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) = Q(x)[/tex]  is a differential equation.

If [tex]Q(x) \neq 0[/tex]

It is non homogeneous then,

The general solution  = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution =  complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

[tex]$(2D^3+15D^2+24D+11)y=0$[/tex]

Auxiliary equation,

[tex]$2m^3+15m^2+24m +11 = 0$[/tex]

-1  | 2    15    24     11

    | 0   -2    - 13    -11  

      2    13    11       0

∴ [tex]2m^2+13m+11=0[/tex]

The roots are

[tex]$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$[/tex]

[tex]$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$[/tex]

[tex]$=\frac{-13\pm9}{4}$[/tex]

[tex]$=-5.5, -1$[/tex]

So, [tex]m_1, m_2, m_3 = -1, -1, -5.5[/tex]

Then the general solution is :

[tex]$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$[/tex]

9514 1404 393

Answer:

Step-by-step explanation:

Let x represent the amount invested at 8%. Then the total interest earned is ...

  0.06(7000 -x) +0.08x = 480

  420 +0.02x = 480 . . . . . . . . . eliminate parentheses

  0.02x = 60 . . . . . . . . . . subtract 420

  x = 60/0.02 = 3000 . . . . . divide by the coefficient of x

$3000 was invested at 8%; $4000 was invested at 6%.

The width of the actual garden patio according to the scale drawing is 14 meters.

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.

Given the scale of 1 cm : 2 m

For a patio of 7 cm, then:

Actual patio = 7 cm / (1 cm/ 2m) = 14 m

The width of the actual garden patio according to the scale drawing is 14 meters.

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Answer:

A --> y=cot(x)

Step-by-step explanation:

if you graph tan(x), it has a period of just PI, because tan(x) is just sin(x)/cos(), and cot(x) is the same because it is just sec(x)/csc(x).

9514 1404 393

Answer:

Step-by-step explanation:

a) For payments made at the beginning of the period, the annuity is called an "annuity due." The formula in the first attachment tells how to compute the payment for a given present value ($500,000), number of periods (N=10), and interest rate (i=0.08).

  pmt = $500,000/(1 +(1 -(1 +i)^(-N+1))/i) = $500,000/(1 +(1 -(1.08^-9))/.08)

  pmt ≈ $68,995.13 . . . . annual payment

__

b) After the first payment, the account balance is ...

  $500,000 -68,995.13 = $431,004.87

After subsequent payments, the account balance will be ...

  $431,004.87×1.08 -68,995.13 = $396,490.13 . . . after 2nd payment

  $396,490.13×1.08 -68,995.13 = $359,214.21 . . . after 3rd payment

The payment amount that can be made in perpetuity is the amount of the monthly interest on this balance:

  X = $359,214.21 × (0.08/12) = $2394.76

Complete question is;

Regarding the violation of multicollinearity, which of the following description is wrong?

a. It changes the intercept of the regression line.

b. It changes the sign of the slope.

c. It changes the slope of the regression line.

d. It changes the value of F-tests.

e. It changes the value of T-tests

Answer:

a. It changes the intercept of the regression line

Step-by-step explanation:

Multicollinearity is a term used in multiple regression analysis to show a high correlation between independent variables of a study.

Since it deals with independent variables correlation, it means it must be found before getting the regression equation.

Now, looking at the options, the one that doesn't relate with multicollinearity is option A because the intercept of the regression line is the value of y that is predicted when x is 0. Meanwhile, multicollinearity from definition above does in no way change the intercept of the regression line because it doesn't predict the y-value when x is zero.

Answer:

x = 2 - sqrt(19/6)

x = 2 + sqrt(19/6)

Step-by-step explanation:

Answer:

add 4

subtract 24 from 5

2

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 30 = x/8

8 sin 30 =x

8 (1/2) = x

4

Answer:

The answet is A. 4

Step-by-step explanation:

Answer:

I think the power is 4

Step-by-step explanation:

480J / 120 = 4

Put 2 mins into seconds which is 120 seconds

Sorry if it is wrong :)

Answer:

[tex]4\text{ watts}[/tex]

Step-by-step explanation:

In physics, the power of a machine is given by [tex]P=\frac{W}{\Delta t}[/tex], where [tex]W[/tex] is work in Joules and [tex]\Delta t[/tex] is time in seconds.

Convert 2 minutes into seconds:

2 minutes = 120 seconds.

Substitute [tex]W=480[/tex] and [tex]\Delta t=120[/tex] to solve for [tex]P[/tex]:

[tex]P=\frac{480}{120}=\boxed{4\text{ watts}}[/tex]