Answer:
On-time Buses: 75%
Running late Buses: 13.46%
Step-by-step explanation:
Part 1: Solve for the probability of Jerry owning an "on-time" bus
Of the 48 buses that run on time, Jerry owns 36 of them. Therefore, the probability of a bus running on time being owned by Jerry will be solved with the ratio of 36 buses to 48 buses.
This is represented by the fraction 36/48. Simplifying this fraction will give us 3/4. Convert to a decimal and then multiply by 100 to get a percentage - 75%.Part 2: Solve for the probability of Jerry owning a "running late" bus
Of the 52 buses that run late, Jerry owns 7 of them. Therefore, the probability of a bus running late & being owned by Jerry will be solved with the ratio of 7 buses to 52 buses.
This is represented by the fraction 7/52.Simplifying this fraction will give us 7/52 (cannot be simplified).Convert to a decimal and then multiply by 100 to get a percentage - 13.46%.A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. The volume of each small box is 9 cubic feet and the volume of each large box is 24 cubic feet. A total of 24 boxes of paper were shipped with a combined volume of 441 cubic feet. Write a system of equations that could be used to determine the number of small boxes shipped and the number of large boxes shipped. Define the variables that you use to write the system.
Answer:
9 small boxes and 15 large boxes
Step-by-step explanation:
x = small box
y = large box
x + y = 24
9x + 24y = 441
-9x - 9y = -216
15y = 225
y = 15
x + 15 = 24
x = 9
Answer:
Let x be the small boxes
Let y be the large boxes
x+y=24
9x+24y=441
Step-by-step explanation:
What type of number is that? Multiple answers.
Answer:
A & C
Step-by-step explanation:
-9 is a whole number is rational
A.) 170
B.) 300
C.)280
D.)155
Please help me
Answer:
Step-by-step explanation:
The formula for this is
∠G = 1/2(arcEH - arcHF)
We have angle G (5x - 10) and we have arcEH (195) so we have to solve for x to find the measure of arcEHF so we can add arcEH + arcHF = arcEHF
Filling in the formula with what we have:
[tex]5x-10=\frac{1}{2}(195-(8x+17))[/tex]
which simplifies down a bit to
[tex]5x-10=\frac{1}{2}(195-8x-17)[/tex] which simplifies down a bit more to
[tex]5x-10=\frac{1}{2}(178-8x)[/tex] Multiply both sides by 2 to get rid of the fraction and get:
2(5x - 10) = 178 - 8x which of course simplifies to
10x - 20 = 178 - 8x. Now add 8x to both sides and at the same time add 20 to both sides to get:
18x = 198 so
x = 11. Now we can find the measure of arcHF:
arcHF is 8x + 17, so arcHF is 8(11) + 17 which is 105°.
arcEH + arcHF = arcEHF so
195 + 105 = arcEHF so
arcEHF = 300°
In a bag of M&MS there are 4 green, 6 yellow and 8 blue candies. What is the probability of drawing a blue then a green if you replace the candy after the draw?
Answer:
8/81
Step-by-step explanation:
8/18 x 4/18 = 32/324 = 8/81
The probability of drawing a blue and then a green and replacing the candy after the draw is 8/81.
What is probability?Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
Probability = Number of favorable outcomes / Number of sample
It is given that in a bag of M&MS there are 4 green, 6 yellow, and 8 blue candies.
The probability for blue = 8/18
The probability for green = 4/18
The probabilities of drawing a blue then green if you replace the candy after the draw will be calculated as below:-
Probability = 8/18 x 4/18
Probability = 32/324
Divide the number 32 by 324 to get the probability.
Probability = 8/81
Therefore, the probability of drawing a blue and then a green and replacing the candy after the draw is 8/81.
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A train covered a certain distance at a uniform speed. If the train would have been 6km/h faster, it would have taken 4 hours less than the scheduled time. And, if the train were slower by 6km/h, it would have taken 6 hours more than the scheduled time. Find the length of the journey.
Answer:Let x km/hr be the speed of train
Let y be the time taken by the train
Distance = speed x time
= x y
To form the first equation let us consider the given information from the question that is If the train had been 6 km/hr faster,it would have taken 4 hours less than the scheduled time.
it clearly says that speed is increased by 6 and time is reduced by 4
So , (x + 6) (y - 4) = x y
x y - 4 x + 6 y - 24 = x y
x y - x y - 4 x + 6 y = 24
- 4 x + 6 y = 24
divided by (-2) => 2 x - 3 y = -12 ----- (1)
To form the second equation let us consider the given information from the question that is If the train were slower by 6km/hr, then it would have taken 6 hours more than the scheduled time.
it clearly says that speed is reduced by 6 and time is increased by 6
So , (x - 6) (y + 6) = x y
x y + 6 x - 6 y - 36 = x y
x y - x y + 6 x - 6 y = 36
6 x - 6 y = 36
divided by (6) => x - y = 6 ----- (2)
2 x - 3 y = -12
(2) x 2 => 2 x - 2 y = 12
(-) (+) (-)
---------------
- y = -24
y = 24
Now we have to apply the value of y in the first equation to get value of x
Substitute y = 24 in the first equation we get
2 x - 3 (24) = -12
2 x - 72 = -12
2 x = -12 + 72
2 x = 60
x = 60/2
x = 30
Speed of the train = 30 km/hr
Time taken by the train = 24 hours
Distance covered by the train = x y = 30 x 24 = 720 km
Verification:
2 x – 3 y = -12
2(30) - 3(24) = -12
60 - 72 = -12
-12 = -12
f(x) = -7x^2+8x+2f(x)=−7x 2 +8x+2
Answer:5
Step-by-step explanation:
The data represents the number of runs allowed by 8 college softball pitchers. {18, 49, 38, 41, 33, 44, 42, 22}
This Question is incomplete
Complete Question:
The data represents the number of runs allowed by 8 college softball pitchers. {18, 49, 38, 41, 33, 44, 42, 22}
What is the five number summary:
a) Minimum
b) Q₁
c) Median
d) Q₃
e) Maximum
Answer:
a) Minimum = 18
b) Q₁ = 27.5
c) Median = 39.5
d) Q₃ = 43
e) Maximum = 49
Step-by-step explanation:
From the above diagram, we were given the following set of data.
{18, 49, 38, 41, 33, 44, 42, 22}
Before answering any of the questions, we have to rearrange the data from the lowest to the highest (ascending order). Hence, we have:
{18, 22, 33, 38, 41, 42, 44, 49}
a) Minimum
{18, 22, 33, 38, 41, 42, 44, 49}
Looking at this set of arranged data, the minimum number is the least or lowest number.
This number is 18
b) Q₁
{18, 22, 33, 38, 41, 42, 44, 49}
Q₁ means First Quartile. The formula is = ¼(n + 1)th value
n = Number of terms in the data set = 8
= ¼(8 + 1)th value
= ¼(9)th value
= 2 1/4 value
= 2.25 value
In the above Question, the 2.25 value is the value between the second and third number.
Hence:
22+33/2 = 55/2 = 27.5
Therefore, Q₁ = 27.5
c) Median
{18, 22, 33, 38, 41, 42, 44, 49}
The median of the number is the number in the middle
For this data, we have 8 number, Hence the median is the sum of the 4th and 5th term divided by 2
4th term = 38
5th term = 41
= 38 + 41/ 2 = 79/2
= 39.5
Hence, the median = 39.5
d) Q₃
{18, 22, 33, 38, 41, 42, 44, 49}
Q₃ means Third Quartile. The formula is = ¾(n + 1)th value
n = Number of terms in the data set = 8
= ¾(8 + 1)th value
= ¾(9)th value
= 6 3/4 value
= 6.75 value
In the above Question, the 6.75 value is the value between the sixth and seventh number.
Hence:
42+44/2 = 86/2 = 43
Therefore, Q₃ = 43
e) Maximum
{18, 22, 33, 38, 41, 42, 44, 49}
Looking at this set of arranged data, the Maximum number is the highest number.
This number is 49
3y=-2x+1593 divide each side by 3
Answer:
y = -2x/3 + 531
Step-by-step explanation:
If the average of 5, 8, b, 9 and 4 is 7. Find the value of b.
A. 9 B. 8 C. 7 D. 5
So our set of numbers is 5,8,b,9,4 . And we know the average is 7. So first, you have to add all the numbers in the set : 5+8+9+4 which gives you 26. We also know that to get the average of a set of numbers you have to add all the numbers and divide that sum by the how many numbers you have, in thsi case we have 5 numbers including b . So our equation now is : 26+b÷5=7. And if you plug in 9 for b you get 26+9÷5=7 and 26+9÷5 does equal 7 so therefore A is your answer
I need Help please answer :((
Answer:
Second option is the correct answer
[tex] {3}^{ - 4} [/tex]
Step-by-step explanation:
[tex] {3}^{ - 8} . {3}^{4} = {3}^{ - 8 + 4} = {3}^{ - 4} [/tex]
Answer:
The answer is D because you multiply the exponents so -8 times 4 is -32
Hope this helps and plz mark branliest!
Step-by-step explanation:
all integers are whole numbers?true or false
Answer:
that would be false
Step-by-step explanation:
all whole numbers are integers, but not all integers are whole numbers
if the sum of two angles is 200 grade and their difference is 20 degree. Find the angle?
Step-by-step explanation:
Formulate an equation to solve for this one.
- I did x+x-20= 200
x represents the larger angle between the two triangles.
x-20 represents the smaller triangle which the problem states is 20 degrees smaller.
- if you solve the equation I gave you above you will get your answer. x= 110
your angles should be 110 and 90. You can check by adding those numbers which will equal to 200.
Hope this helps!
In right triangle ΔABC (m∠C = 90°), point P is the intersection of the angle bisectors of the acute angles. The distance from P to the hypotenuse is equal to 4 in. Find the perimeter of △ABC if AB = 12 in.
Answer:
the perimeter of ΔABC is 32in
Step-by-step explanation:
We know that intersection point of the angle bisectors refers to the incenter of the triangle,.
Given tmthe radius of 4inch for the centre of the incircle.
One of the properties of the incircle is that the distances (d) from vertex C to the nearest touchpoints are equal and have the value
In an incircle , the distances (d) along vertex C and touchpoints have equal value and can be expressed as
d = 1/2(a +b -c)
And a, b, c represent lengths of the sides
We were given the hypotenuse (c) as 12 in, with the radius of 4inch for the
distance from the right-angle vertex C to the incircle touchpoints .
We can determine the sum a+b as
4 = (1/2)(a+b -12) .
4/(1/2)= (a+b -12)
8= (a+b -12)
20=a+b
Which is the addition of length of the two legs of the triangle.
We can determine the perimeter which is the addition of the leg lengths as well as the hypotenuse length.
perimeter = 20 in + 12 in = 32 in
Therefore, the perimeter of ΔABC is 32in
complete the square to solve
f(x)=x^2+6x-7
solve for x 13(x-3)=39
Answer:
x=6
Step-by-step explanation:
13(x-3)=39
Divide each side by 13
13/13(x-3)=39/13
x-3 = 3
Add 3 to each side
x-3+3 = 3+3
x = 6
Answer:
x=6
Step-by-step explanation:
expanding we get
13x-39=39
13x=39+39
13x=78
x=78/13
x=6
what is the value of the angle ?
Answer:
47°
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles
124° is an exterior angle , thus
77 + ? = 124 ( subtract 77 from both sides )
? = 47°
20 points! Thank you :)
Answer:
[tex]\Large \boxed{x=-2 \ \mathrm{and} \ x=3}[/tex]
Step-by-step explanation:
The quadratic expression is given.
[tex]2x^2-2x-12=0[/tex]
Factor the left side of the equation.
[tex]2(x+2)(x-3)=0[/tex]
Set the factors equal to 0.
[tex]x+2=0[/tex]
[tex]x=-2[/tex]
[tex]x-3=0[/tex]
[tex]x=3[/tex]
The two solutions work in the original equation. The solutions make the equation true.
The quadratic expression:
[tex]2 {x}^{2} - 2x - 12[/tex]
★ By split middle term,we get
[tex]2 {x}^{2} - 6x + 4x - 12[/tex]
[tex]2x(x - 3) + 4( x - 3)[/tex]
[tex](2x + 4) (x - 3)[/tex]
[tex]2x + 4 = 0 \: \: and \: \: x - 3 = 0[/tex]
[tex]2 x = - 4 \: \: and \: \: x = 3[/tex]
[tex]x = - 2 \: \: and \: \: x = 3[/tex]
Therefore , the two solution of given quadratic equations is -2 and 3.
Convert 1.2 radians to an
angle in degrees
Answer:
Below
Step-by-step explanation:
Let x be the measure in degrees
● x/180 = 1.2/Pi
Cross multiply the values
● x*Pi = 180×1.2
● x = 216/Pi
Take Pi = 3.14
● x = 68.78 wich is approximatively 69°
To bake 12 cookies, I use 2 quarts of milk. There are 2 pints in a quart. How many pints of milk do I need to bake 3 cookies?
Answer:
1 pint
Step-by-step explanation:
You need 2 * 2 = 4 pints to make 12 cookies. Since 3 cookies is 1/4 of 12 cookies, you would need 1/4 * 4 = 1 pint of milk to make 3 cookies.
Answer:
1 pint
Step-by-step explanation:
12c=4p
divide both sides by 4
3 cookies needs 1 pint!!!!
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
JUST A RANDOM GIRL WANTING TO HELP PEOPLE!
PEACE!
Let f (x) = x – 4 and g(x) = 6 - x
Evaluate g(f(10)).
G(f(10))
First solve f(x) by replacing x with 10:
F(x) = x-4 = 10-4 = 6
Now replace x in g(x) with 6
G(x) = 6-x = 6-6 = 0
So g(f(10)) = 0
Need help and will mark brainlist and thank You
In a circle whose center is O, arc AB contaisn 100 degrees. Find the number of degrees in angle ABO?
Answer:
40
Step-by-step explanation:
Angles ABO, BAO, and AOB are the angles of isosceles triangle AOB. The angles at A and B are equal, so we have ...
AOB +2ABO = 180° . . . . . sum of angles in the triangle
100° +2ABO = 180° . . . . . . use the given value
50° +ABO = 90° . . . . . . . . divide by 2; next, subtract 50°
∠ABO = 40°
Special right triangles
Answer: please find the attached files
Step-by-step explanation:
A unit circle formula and special triangle of 45, 30 and 60 degrees can be used to solve the problem.
Please find the attached files for the solution
Please answer quickly, what is the measure of c
===================================================
Explanation:
The only given number here is the 20 degree angle. So we'll start with that. This is an inscribed angle, which doubles to 2*20 = 40, and this is the measure of the arc the inscribed angle cuts off (inscribed angle theorem). Consequently, it means that central angle b is also 40 degrees.
With b = 40, we can see that c = 180-b = 180-40 = 140. This is because b+c = 180 as the two angles are supplementary.
Answer:
140 degrees
Step-by-step explanation:
If the given angle is 20 degrees then the other unknown angle would also be 20 degrees because this triangle is an isosceles triangle. 20+20+20=180 proving the triangle sum theorem.
Which expression is equivalent 6+7n+4+8n?
Answer: 5(2+3n)
Step-by-step explanation:
Answer:
15n + 10 should be your answer.
Step-by-step explanation:
Plz help Solve: y-17= -37
Answer:
-20
Step-by-step explanation:
First thing you do is set up your equation:
y-17= -37
+17 +17 Next you add 17 to both sides
------------- Follow your integer rules
y= -20
We can check this by putting it back into the solution
-20-17= -37 Integer Rules
You use KCC aka Keep Change Change
= -20+ -17= -37
I WANT TO PASS HIGH SCHOOL PLEASE HELP
Given that the quadrilateral EFGH is a trapezoid, m∠H = 62° and m∠HEG = 64° calculate m∠FEG
Answer:
m∠FEG == 54°
Step-by-step explanation:
you should know that m∠FEG is equal m∠EGH. this is because sides HE and FG are equal this also means opposite angles of this sides (m∠FEG and m∠EGH) are equal.
first find the measure of m∠EGH from triangle EHG.
m∠H + m∠HEG + m∠EGH= 180°
62° + 64° + m∠EGH = 180°
m∠EGH=180° - 126°
m∠EGH=54°
due to the fact that sides HE and FG are equal thus opposite angles of sides HE and FG are also equal.
m∠FEG = m∠EGH = 54°
m∠FEG =54°
max drove 460 miles in 8 hours at a constant speed. How long would it take him to drive 661.25 miles at that speed? speed=d/t Time =d/s
Answer:
x = 11.5 hours
Step-by-step explanation:
Set up a proportion:
[tex]\frac{460}{8}[/tex] = [tex]\frac{661.25}{x}[/tex]
661.25/460 = 1.4375
Multiply 8 by 1.4375 to find x:
8(1.4375) = 11.5
x = 11.5 hours
a. Give Tommy your estimate of 0.27 probability in ratio form.
Answer:
0.27 expressed in ratio form is 27:100
Step-by-step explanation:
Before we give Tommy the estimate of 0.27 probability in ratio form, we shall need to turn 0.27 to fraction
Mathematically, that would be 27/100
Now expressing this in ratio form, we will have 27:100
(2.05 MC) Triangle PQR is transformed to Triangle P'Q'R'. Triangle PQR has vertices P(4,0), Q(0,-4) and R(-8,-4). Triangle P'Q'R' has vertices P'(1,0), Q'(0,-1), and R'(-2,-1). Part A: What is the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' Part B: Write The Coords of triangle P"Q"R" obtained after P'Q'R' is reflected about the y-axis Part C: Are the two Triangles PQR and P"Q"R" congruent?
Answer:
Part A: The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4
Part B:
P''(-1, 0)
Q''(0, -1)
R''(2, -1)
Part C:
The two Triangles PQR and P''Q''R'' are not congruent
Step-by-step explanation:
The coordinates of triangle PQR are;
P(4, 0)
Q(0, 4)
R(-8, -4)
The coordinates of triangle P'Q'R' are;
P'(1, 0)
Q'(0, -1)
R'(-2, -1)
Part A:
The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' can be found from the ratio of the respective coordinates as follows;
The ratio of the x, and y coordinates of the points are;
P'/P = x'/x = 1/4, y'/y =0/0
R'/R = x'/x = -2/-8 = 1/4, y'/y =-1/-4 = 1/4
Therefore, the scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' = 1/4
Part B: For reflection across the y-axis, we have;
Pre-image (x, y) becomes the image, (-x, y)
Therefore, we have;
Reflection of P'(1, 0) about the y-xis becomes P''(-1, 0)
Reflection of Q'(0, -1) about the y-xis becomes Q''(0, -1)
Reflection of R'(-2, -1) about the y-xis becomes R''(2, -1)
Part C:
The two Triangles PQR and P''Q''R'' are similar but they are not congruent as the dimensions of PQR are larger than the dimensions of the sides of triangle P''Q''R''.
(A) The scale factor of the dilation that transforms Triangle PQR to Triangle P'Q'R' is 1/4
(B) Coordinates of Δ P"Q"R"
P" (-1,0)
Q"(0,-1)
R"(2,-1)
(C) Triangles PQR and P"Q"R" are not congruent.
Given
ΔPQR is transformed into ΔP'Q'R'
Coordinates of P, Q, R are
P (4,0),
Q(0,-4)
R(-8,-4)
Coordinates of P'Q'R' are
P'(1,0)
Q'(0,-1)
R'(-2,-1)
(A) By Distance formula we can find the distance between P Q and P'Q'
Distance formula = [tex]D= \sqrt{(X_2-X_1)^2+(Y_2-Y_1)^2 }[/tex]
Where D = Distance between two points [tex](X_1.Y_1) \; and\; (X_2.Y_2)[/tex]
from distance formula we can write that
[tex]PQ = \sqrt{(0-4)^2+ (-4-0)^2} }\\[/tex]
PQ = [tex]4\sqrt{2}[/tex]
Similarly
P'Q'= [tex]\sqrt{2}[/tex]
PQ /P'Q' = 4
hence the scale factor of dilation is 1/4 (Compression)
(B )The Coordinates of Reflection about y axis can be written for a point
[tex](x,y ) \; as \; (-x,y)[/tex]
So the Coordinated of Δ P"Q"R" can be written as
P" (-1,0)
Q"(0,-1)
R"(2,-1)
(C) ΔPQR and ΔP"Q"R" are similar triangles but they are not congruent because their sides are not equal in size.
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