Answer:
-3/4
Step-by-step explanation:
Slope = Rise/Run
Between -4 and 8, the line runs 12 units. Between -3 and -9, the line rises -9 units.
-9/12 = -3/4
Answer:
-3/4
Step-by-step explanation:
I need help on this question!!!
Answer:
The answer is 17.
Step-by-step explanation:
200/3 is approximately 67, and divided by 4 again to represent the second checkpoint will become 16.75. Obviously there can't be a fraction of a bag, so the answer is 17.
Answer:
16
Step-by-step explanation:
the lcm for 3 and 4 is 12
200 ÷ 12 = 16.667
≈16
Write the slope-intercept form of the equation for the line. (-1,-3) (1,1)
Answer:
y = 2 x − 1
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
We can find the slope from the slope equation
m = (y2-y1)/(x2-x1)
= ( 1- -3)/(1 - -1)
= (1+3)/(1+1)
= 4/2
=2
what is the sum of the interior angles of a regular hexagon
Answer:
see below
Step-by-step explanation:
The sum of the interior angles of any polygon can be found with the formula 180(n - 2) where n = number of sides. In this case, n = 6 so the answer is 180(6 - 2) = 180 * 4 = 720°.
Answer:
The sum of the interior angles of a regular hexagon is 720°
Step-by-step explanation:
As we know that the sum of interior angle is 180(n-2). So the number of sides of hexagon is 6. Now, 180(6-2)=180*4=720°
PLS HELP I WILL GIVE BRAINLIST AND A THANK YOU!!!!!!!! Pls help me :)
Answer:
67°
Step-by-step explanation:
CGE + AGC + AGG = 180 (angles on a straight line)
23°+90°+x=180°
x=67°
A line passes through point (5, –3) and is perpendicular to the equation y = x. What's the equation of the line?
Answer:
y = -x +2
Step-by-step explanation:
y =x has a slope of 1
Perpendicular lines have slopes that multiply to -1
m* 1 = -1
The slope of the perpendicular line is -1
We have a slope and a point
y = mx+b
y= -1x+b
Substitute the point into the equation
-3 = -1(5) +b
-3 =-5 +b
Add 5 to each side
-3+5 = b
2 =b
y = -x +2
ASAP PLZ ANSWER 50 POINTS How do I determine if -3x+y =8 is a function?
Answer:
To determine if Y=-8 is a function, you must do the vertical line test. If you were to plot Y=-8 on a coordinate plane, you would see that at the point of (0,-8)[which is what Y=-8 is also] is on the Y axis and makes a horizontal linet hat passes through (o,-8).
Step-by-step explanation:
Answer:
graph
Step-by-step explanation:
did you mean in graph
A family club keeps a small amount of money on hand for members to borrow for short periods of time. The simple interest charged is 7.5%. Stephen borrowed $5,000 for 3 months. How much, to the nearest dollar, was he required to pay back at the end of 3 months?
Answer:
$6125
Step-by-step explanation:
5000 x 3 x .075 = 1,125
5000 + 1125 = 6125
Divide a 7-inch line into three parts so that each part is 1 inch longer than one before it.
Answer:
Hey there!
We can write an equation:
x+x+1+x+2=7
3x+3=7
3x+4
x=4/3
The lines are 4/3, 7/3, and 10/3.
Let me know if this helps :)
4.
Aliyah, Brenda and Candy share a sum of money in the ratio of 3:5:6. After
Candy gives $100 to Aliyah and $50 to Brenda, the ratio becomes 2 : 3:3.
(a) Suppose Aliyah has $3x at the start, express Candy's initial sum of money in
terms of x.
(b) Find the value of x.
(c) Hence, how much money does Brenda have in the end?
Answer:
(a) Candy's initial sum as a terms of x is $6x
(b) x = $60
(c) $350
Step-by-step explanation:
The given parameters are;
The ratio in which Aliyah, Brenda and Candy share the sum of money = 3:5:6
The amount Candy later gives Aliyah = $100
The amount Candy later gives Brenda = $50
The new ratio of the sum of the shared money between Aliyah, Brenda and Candy = 2:3:3
(a) Whereby Aliyah has $3x at the start, we have;
Total sum of mony = Y
Amount of Aliyah's initial share = Y × 3/(3 + 5 + 6) = Y×3/14
Therefore, Y×3/14 = $3x
x = Y×3/14 ÷ 3 = Y/14
Amount of Candy's initial share = Y × 6/14
Therefore Candy's initial sum as a terms of x = $6x
(b) Given that Aliyah's and Candy's initial sum as a function of x are $3x and $6x, therefore, in the ratio 3:5:6, Brenda's initial sum as a function of x = $5x
Which gives;
Total amount of money = $14x
With
6x - 150, 3x + 100, and 5x + 50, the ratio =is 2:3:3
Therefore, we have;
14·x × 2/(2 + 3 + 3) = (6·x - 150)
14·x × 2/(8) = (6·x - 150)
14·x × 1/4 = (6·x - 150)
7·x/2 = (6·x - 150)
12·x - 300 = 7·x
12·x - 7·x = 300
5·x = 300
x = $60
(b) The final amount of money with Brenda = 5x + 50 = 5 × 60 + 50 = $350
The final amount of money with Brenda = $350.
CAN U PLS HELP ME OUT I WILL GIVE BRAINLIST AND A THANK YOU!!!!!! :)
Answer:
Step-by-step explanation:
Vertically opposite angles are equal
x = 25°
PLEASE help me with this question! No nonsense answers please. This is really urgent.
Answer:
32
Step-by-step explanation:
This is because you would want the feet and the radium kinda meeting up in a way and would need to make sure you can fill it in with th e drive way as it will be on a horizontal base so you would need X2 of the driveway to make it into a standing up horizontal base
Hope this helps
If this seems incorrect please comment with the answer that it should be and I shall change my answer thanks you :)
Theresa volunteers at a food shelf. Today she is filling bags of oranges. When she started, there were 213 oranges. After filling x bags with 3 oranges each, there were fewer than 51 oranges left. How many bags of oranges did Theresa fill? Part c
Answer:
Step-by-step explanation:
So we know that there are 213 oranges and Theresa fills each bag with 3 oranges, so we can represent each bag as 3x. She keeps filling until she reaches 51 oranges.
First. let's write this as an equation, She is starting with 213 oranges and filling x bags with 3 oranges to the point she has less than 51 oranges.
213 - 3x < 51
Now add 3x to both sides,
213 - 3x + 3x < 51 + 3x
213 < 51 + 3x
Now we subtract 51 from both sides,
213 - 51 < 51 - 51 + 3x
162 < 3x
Now we divide both sides by 3,
162/3 < 3x/3
We find the answer,
54 < x
x > 54 bags
last one hopefullly hahah
you are correct. all angles (except central) are not equal (iff TU and CB are not parallel)
the triangles are not similar
Answer:
it's A
They don't give you enough information to determine if they are similar or not
a farmer has 40 4/5 of beans 3/4 of the beans are pinto beans how many pounds of pinto bean are there
Answer: Amount of pinto beaks [tex]=30\dfrac{3}{5}\text{ pounds}[/tex]
Step-by-step explanation:
Given: Amount of beans a farmer has = [tex]40\dfrac{4}{5}\text{ pounds}=\dfrac{40\times5+4}{5}\text{ pounds}[/tex]
[tex]=\dfrac{204}{5}\text{ pounds}[/tex]
Also, [tex]\dfrac{3}{4}[/tex] of the beans are pinto beans .
Amount of pinto beaks = [tex]\dfrac 34\times[/tex] (Amount of beans a farmer has)
= [tex]\dfrac34\times\dfrac{204}{5}=\dfrac{153}{5}\text{ pounds}[/tex]
[tex]=30\dfrac{3}{5}\text{ pounds}[/tex]
Amount of pinto beaks [tex]=30\dfrac{3}{5}\text{ pounds}[/tex]
Show that the 9x^2-24xy+16y^2-12x+16y-12=0 represents a pair of parallel lines .Find the distance between the lines.
First of all u will 9x^2-24xy+16y^2-12×16y-12=0 u will add the 9x^ then u will subtract 2-24
cost of putting a fence around a square field rupees 35 rupees is
4480 find the each side of the field
Answer:
cost of one side= 1120
Step-by-step explanation:
Given. total cost=4480
cost per meter=35
So,perimeter=total cost/cost per metre
perimeter=4480/35
perimeter=128
perimeter of square=4*side
128/4=side
side=32
given cost of one meter=35
So,cost of 32 meter=35*32
So,cost of one side=1120
Answer:
the cost of fencing a square field at the rate of ₹35 per m is ₹4480.
so the perimeter of the square field = 4480/35
= 128m
Length of each side = 128/4
= 32m
Hope this helps! (づ ̄3 ̄)づ╭❤~
A delivery truck company just bought a new delivery truck and they need to know the maximum volume it can carry. In the front of the truck, there is an extra ledge that sticks out over the driver's cab for extra storage space. What is the maximum amount of cargo that can fit into the new truck?
Answer:
The answer is below
Step-by-step explanation:
To find the maximum amount of cargo the truck can carry, we need to find the volume of the truck.
Volume = length × width × height.
Firstly 1 feet (1') = 12 inches (12"),
For the extra ledge that sticks out, the height = 7'8" = 7.667 feet, the width = 16'9" - 14'3" = 16.75 - 14.25 = 2.5 feet, the length = 2'7" = 2.583 feet
Volume of extra ledge = length × width × height = 2.583 × 2.5 × 7.667 = 49.5 feet³
For the truck, the height = 7'8" = 7.667 feet, the length = 14'3" = 14.25 feet, the width = 6'6" = 6.5 feet
Volume of truck = length × width × height = 14.25 × 6.5 × 7.667 = 710.16 feet³
The maximum volume = volume of extra ledge + volume of truck = 49.5 + 710.16 = 759.66 feet³
calculate the amount and compound interest on rupees 4000 at the rate of 8% per annum compounded annually for 2 years
Step-by-step explanation:
To calculate the compound interest we use the formula
C = A - PWhere
A is the amount
P is the principal
C is the compound interest
To find the amount we use the formula
[tex]A = P(1 + \frac{r}{100} ) ^{n} [/tex]where P is the principal
r is the rate
n is the period
From the question
P = 4000 rupees
rate = 8%
n = 2 years
Substitute the values into the above formula
That's
[tex]A = 4000( 1 + \frac{8}{100} )^{2} [/tex][tex]A = 4000 ({1 + 0.08})^{2} [/tex][tex]A = 4000 ({1.08})^{2} [/tex]A = 4665.6
The amount is 4665.60 rupeesSince the amount is found we can now find the compound interest
C = 4665.60 - 4000
C = 665.6
The compound interest is 665.60 rupeesHope this helps you
solve for x and y plz 12x - 5y = -20 x + 4 = y
Answer:
(0,4)
Step-by-step explanation:
System of Equations:
[tex]\left \{ {{12x-5y=-20} \atop {x+4=y}} \right.[/tex]
x= y-4 .... Change format so you can substitute to first equation
12(y-4)-5y=-20 .... Plug in x= y-4 to first equation
12y - 48 -5y = -20 ..... Distributed
7y -48 =-20 .... Added like terms
7y=28 .... Added 48 to both sides
y=4
.... Plug y into the second equation to find x
x + 4=y
x +4 = 4 .... Plugged in y
x = 4-4 .... Subtracted 4 from both sides
x=0
Your answer is (0,4)
Hope this helps:)
Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $1.25 for a delivery made within 1 1/2 mi, $1.70 for a delivery of at least 1 1/2 mi but less than 1 3/4 mi, $2.15 for a delivery of at least 1 3/4 mi but less than 2 miles, and so on. If tim raised his rates by 10% what would he be paid to deliver a package 3 1/8 miles
Answer:
$4.84
Step-by-step explanation:
Given that
For delivery within [tex]1\frac{1}2[/tex] mi, charges = $1.25
For delivery within [tex]1\frac{1}2[/tex] mi - [tex]1\frac{3}4[/tex] mi, charges = $1.70
For delivery within [tex]1\frac{3}4[/tex] mi - 2 mi, charges = $2.15
and
so on.
i.e.
For delivery within 2 mi - 2[tex]\frac{1}4[/tex] mi, charges = $2.60
For delivery within 2[tex]\frac{1}4[/tex] mi - 2[tex]\frac{1}2[/tex] mi, charges = $3.05
For delivery within 2[tex]\frac{1}2[/tex] mi - 2[tex]\frac{3}4[/tex] mi, charges = $3.50
For delivery within 2[tex]\frac{3}4[/tex] mi - 3 mi, charges = $3.95
For delivery within 3 mi - 3[tex]\frac{1}4[/tex] mi, charges = $4.40
So, every 0.25 mi or [tex]\frac{1}4[/tex] mi increase in distance, there is an increase of $0.45 in the charges.
It is given that there is increase of 10% in the rates.
i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.
The distance of [tex]3\frac{1}8[/tex] miles lies within the range 3 mi - 3[tex]\frac{1}4[/tex] mi.
So actual charges after increase of 10%
[tex]\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}[/tex]
For the function f(x) = -12x + 7, find the
matching value for x when f(x) = 17. Write
your answer as a fraction.
Answer:
[tex]\large\boxed{x=-\frac{5}{6}}[/tex]
Step-by-step explanation:
f(x) is the same value as y. Therefore, y = 17. We can place this into slope intercept form (except with a defined value for y) and solve for x.
Start by subtracting 7 from both sides. Then, divide by -12 to solve for x. Finally, simplify the fraction.
17 = -12x + 7
10 = -12x
-10/12 = x
-5/6 = x
[tex]\large\boxed{x=-\frac{5}{6}}[/tex]
find the multiplicative inverse of 3 by 4 minus 5 by 7
Answer:
28
Step-by-step explanation:
[tex]\frac{3}{4}-\frac{5}{7}[/tex]
Least Common Denominator of 4 & 7 is 4 * 7 = 28
[tex]\frac{3}{4}-\frac{5}{7}=\frac{3*7}{4*7}-\frac{5*4}{7*4}\\\\\\=\frac{21}{28}-\frac{20}{28}\\\\\\=\frac{21-20}{28}\\\\\\=\frac{1}{28}[/tex]
Multiplicative inverse of [tex]\frac{1}{28}[/tex] is [tex]\frac{28}{1} = 28[/tex]
PLEASE help me with this question!!! REALLY URGENT!
Answer:
B
Step-by-step explanation:
So we have a table of values of a used car over time. At year 0, the car is worth $20,000. By the end of year 8, the car is only worth $3400.
We can see that this is exponential decay since each subsequent year the car depreciates by a different value.
To find the rate of change the car depreciates, we simply need to find the value of the exponential decay. To do this (and for the most accurate results) we can use the last term (8, 3400).
First, we already determined that the original value (year 0 value) of the car is 20,000. Therefore, we can say:
[tex]f(t)=20000(r)^t[/tex]
Where t is the time in years and r is the rate (what we're trying to figure out).
Now, to solve for r, use to point (8, 3400). Plug in 8 for t and 3400 for f(t):
[tex]3400=20000(r)^8\\3400/20000=17/100=r^8\\r=\sqrt[8]{17/100}\approx0.8[/tex]
In other words, the rate of change modeled by the function is 0.8.
As expected, this is exponential decay. The 0.8 tells us that the car depreciates by 20% per year.
A.) Pinky bought 1. 1/2 kg of apples and 5. 1/4 kg of mangoes 1. 1/2 kg of oranges. Find the total weight of fruits B.) if her family eats 3/4 kg of apples and 2. 1/2 kg of mangoes and 1/2 kg of oranges. Find the weight of fruits left (Please say the answer with explanation who says the answer first I will mark them as the brainliest)
Answer:
A. Total weight of the fruits is 2.25 kg
B. There are no more fruits left.
Step-by-step explanation:
A.
To get the total weight of the fruits, we will first of all have to sort out the fruits and multiply the weight of the fruits by the number available.
Weight of apples:
we have one 1apple weighing 1/2 kg. The weight will be 1 |X 1/2 = 1/2 kg
Weight of mangoes:
We have five mangoes weighing 1/4 kg. Total weight will be 5 X 1/4 = 5/4 kg
Weight of oranges:
We have one orange weighing 1/2 kg. Total weight will be 1X 1/2 = 1/2 kg
Total weight of the fruits will be total weight of Mangoes + oranges + apples
= 1/2 + 5/4 + 1/2 = 2.25kg
B.
If her family begins to eat off some portions of the fruits, we will have to calculate the sum total of all the weights of fruits eaten
The portion eaten will be 3/4 + (2 X 1/2) + 1/2 = 2.25kg
If this happens the family would have eaten all of the fruits because
the original weight present is only 2.25kg of fruits to start with
PLZ HELP!!!!!!!!!!!!!! WILL MARK BBRAINLIST
Answer:
B. The second choice.
Step-by-step explanation:
A function cannot have two points with the same x-coordinate.
If you graph two different points that have the same x-coordinate, they will both lie on the same vertical line. Therefore, if in a relation, more than one point lie on the same vertical line, then the relation is not a function.
3m-2-5n+p terms and coefficients
Answer: Answers are in the steps.
Step-by-step explanation:
The coefficients are 3, -5, and 1
The terms are, 3m, -2,-5n and p
For the function f(x) = x + 7, what is the ordered pair for the point on the graph where x = 2b? (2b, 2b + 7) (2b, x + 7) (x, x + 7) (x, 2b + 7)
Answer:
(2b, 2b + 7).
Step-by-step explanation:
y = x + 7 and x = 2b ,
therefore y = 2b + 7.
Answer:
(2b, 2b + 7)
Step-by-step explanation:
Use mathematical induction to prove the statement is true for all positive integers n. 8 + 16 + 24 + ... + 8n = 4n(n + 1)? Please show work
Answer:
The sum of the series is Sₙ = n/2 [2·a + (n - 1)·d] where a = 8 and d = 8, therefore 8 + 16 + 24 + ... + 8·n = 4·n·(n + 1)
Step-by-step explanation:
The parameters given are;
8 + 16 + 24 + ... + 8·n = 4·n·(n + 1)
The given series of numbers can be checked to find;
16 - 8 = 24 - 16 = 8
Therefore, the series of numbers is an arithmetic progression with first term = 8, and common difference = 8, we have;
The sum of n terms of an arithmetic progression, Sₙ, is given as follows;
Sₙ = n/2 [2·a + (n - 1)·d]
Where;
a = The first term of the series of numbers = 8
d = The common difference = 8
∴ Sₙ = n/2 × [2×8 + (n - 1)×8] = n [2×8/2 + (n - 1)×8/2] = n × [8 + (n - 1)×4]
Sₙ = n × [8 + (n - 1)×4] = n × [8 + 4·n - 4] = n × [8 - 4 + 4·n] = n × [4 + 4·n]
Sₙ =n × [4 + 4·n] = 4 × n×(n + 1) = 4·n·(n + 1).
have two one-quart jars; the first is filled with water, and the second is empty. I pour half of the water in the first jar into the second, then a third of the water in the second jar into the first, then a fourth of the water in the first jar into the second, then a fifth of the water in the second jar into the first, and so on. How much water in quarts is in the first jar after the $10^{\textrm{th}}$ pour? Express your answer as a common fraction.
Answer:
water in quarts is in the first jar after 10th pour = 12/11
Step-by-step explanation:
Let X represent first jar and Y represents second jar.
have two one-quart jars; the first is filled with water, and the second is emptyLets give the initial value of 2 to the first jar which is filled with water. Lets say there are two liters of water in first jar.
Lets give the initial value of 0 to the second as it is empty.
So before any pour, the values are:
X: 2
Y: 0
pour half of the water in the first jar into the secondAfter first pour the value of jar X becomes:
Previously it was 2.
Now half of water is taken i.e. half of 2
2 - 1 = 1
So X = 1
The value of jar Y becomes:
The half from jar X is added to second jar Y which was 0:
After first pour the value of jar Y becomes:
0 + 1 = 1
Y = 1
a third of the water in the second jar into the firstAfter second pour the value of jar X becomes:
Previously it was 1.
Now third of the water in second jar Y is added to jar X
1 + 1/3
= (3 + 1)/3
= 4/3
X = 4/3
After second pour the value of jar Y becomes:
Previously it was 1.
Now third of the water in Y jar is taken and added to jar X so,
1 - 1/3
= (3 - 1)/3
= 2/3
Y = 2/3
a fourth of the water in the first jar into the secondAfter third pour the value of jar X becomes:
Previously it was 4/3.
Now fourth of the water in the first jar X is taken and is added to jar Y
= 3/4 * (4/3)
= 1
X = 1
After third pour the value of jar Y becomes:
Previously it was 2/3
Now fourth of the water in the second jar X is added to jar Y
= 2/3 + 1/4*(4/3)
= 2/3 + 4/12
= 1
Y = 1
a fifth of the water in the second jar into the firstAfter fourth pour the value of jar X becomes:
Previously it was 1
Now fifth of the water in second jar Y is added to jar X
= 1 + 1/5*(1)
= 1 + 1/5
= (5+1) / 5
= 6/5
X = 6/5
After fourth pour the value of jar Y becomes:
Previously it was 1.
Now fifth of the water in Y jar is taken and added to jar X so,
= 1 - 1/5
= (5 - 1) / 5
= 4/5
Y = 4/5
a sixth of the water in the first jar into the secondAfter fifth pour the value of jar X becomes:
Previously it was 6/5
Now sixth of the water in the first jar X is taken and is added to jar Y
5/6 * (6/5)
= 1
X = 1
After fifth pour the value of jar Y becomes:
Previously it was 4/5
Now sixth of the water in the first jar X is taken and is added to jar Y
= 4/5 + 1/6 (6/5)
= 4/5 + 1/5
= (4+1) /5
= 5/5
= 1
Y = 1
a seventh of the water in the second jar into the firstAfter sixth pour the value of jar X becomes:
Previously it was 1
Now seventh of the water in second jar Y is added to jar X
= 1 + 1/7*(1)
= 1 + 1/7
= (7+1) / 7
= 8/7
X = 8/7
After sixth pour the value of jar Y becomes:
Previously it was 1.
Now seventh of the water in Y jar is taken and added to jar X so,
= 1 - 1/7
= (7-1) / 7
= 6/7
Y = 6/7
a eighth of the water in the first jar into the secondAfter seventh pour the value of jar X becomes:
Previously it was 8/7
Now eighth of the water in the first jar X is taken and is added to jar Y
7/8* (8/7)
= 1
X = 1
After seventh pour the value of jar Y becomes:
Previously it was 6/7
Now eighth of the water in the first jar X is taken and is added to jar Y
= 6/7 + 1/8 (8/7)
= 6/7 + 1/7
= 7/7
= 1
Y = 1
a ninth of the water in the second jar into the firstAfter eighth pour the value of jar X becomes:
Previously it was 1
Now ninth of the water in second jar Y is added to jar X
= 1 + 1/9*(1)
= 1 + 1/9
= (9+1) / 9
= 10/9
X = 10/9
After eighth pour the value of jar Y becomes:
Previously it was 1.
Now ninth of the water in Y jar is taken and added to jar X so,
= 1 - 1/9
= (9-1) / 9
= 8/9
Y = 8/9
a tenth of the water in the first jar into the secondAfter ninth pour the value of jar X becomes:
Previously it was 10/9
Now tenth of the water in the first jar X is taken and is added to jar Y
9/10* (10/9)
= 1
X = 1
After ninth pour the value of jar Y becomes:
Previously it was 8/9
Now tenth of the water in the first jar X is taken and is added to jar Y
= 8/9 + 1/10 (10/9)
= 8/9 + 1/9
= 9/9
= 1
Y = 1
a eleventh of the water in the second jar into the firstAfter tenth pour the value of jar X becomes:
Previously it was 1
Now eleventh of the water in second jar Y is added to jar X
= 1 + 1/11*(1)
= 1 + 1/11
= (11 + 1) / 11
= 12/11
X = 12/11
After tenth pour the value of jar Y becomes:
Previously it was 1.
Now eleventh of the water in Y jar is taken and added to jar X so,
= 1 - 1/11
= (11-1) / 11
= 10/11
Y = 10/11
Answer:
6/11
Step-by-step explanation:
1/2 + (1/2)(2/11) = 6/11
sus
Use a trigonometric ratio to find the value of x. Round your answer to the nearest tenth.
3.1
3.4
4.8
2.6