Answer:
The rate of the forward reaction equals the rate of the reverse reaction.
Explanation:
To know which option is correct, it important that we know what dynamic equilibrium is all about.
We'll begin by defining chemical equilibrium.
A chemical system is said to be in chemical equilibrium when there is no observable change in the properperties of the chemical system.
Dynamic equilibrium on the other hand can be defined as a state in which the forward and backward reaction is occurring at the same time. Thus, in dynamic equilibrium, the rate of the forward reaction is equal to the rate of the backward (i.e reverse) reaction.
An example of a molecular compound that obeys the octet rule in which all atoms have a zero formal charge is:
Answer:
[tex]NCl_3[/tex]
Explanation:
An octet rule is a thumb rule in the chemical sciences in which there is a natural tendency for an atom to prefer eight electrons in the valence shell of the atom. When there are less than eight electrons in the atom, they react with other atoms and form more stable compounds.
In the context, nitrogen trichloride, [tex]NCl_3[/tex], is an example of molecular compound which obeys the octet rule having a zero formal charges on each atom of the compound.
Question 2 10
10 Points
Which of the following chemical equations depicts a balanced chemical equation?
O A. AgNO, Kcro > KNO, Agro,
OB. AgNO3 + Kycro, » 2K NO; + Agro,
C.3AgNO3 + 2K,Cro--> 3KNO3 + 249900,
D. 2AgNO, K Cro-> 2KNO; 1Cro,
Resol Selection
Answer:
2AgNO, K Cro-> 2KNO; 1Cro,
If 11.00 mL of a standard 0.2831 M NaOH solution is required to neutralize 26.86 mL of H2SO4, what is the molarity of the acid solution?
Answer:
0.1159 M
Explanation:
Using the formula below:
CaVa = CbVb
Where;
Ca = concentration/molarity of acid (M)
Cb = concentration/molarity of base (M)
Va = Volume of acid (mL)
Vb = volume of base (mL)
According to this question, the following information were given:
Ca = ?
Cb = 0.2831 M
Va = 26.86 mL
Vb = 11.00 mL
Using CaVa = CbVb
Ca × 26.86 = 0.2831 × 11
26.86Ca = 3.1141
Ca = 3.1141 ÷ 26.86
Ca = 0.1159
The molarity of the acid (H2SO4) solution is 0.1159 M
The decomposition of nitric oxide to molecular nitrogen and oxygen occurs at high temperatures according to the reaction:
N2(g)+O2(g)⟺2NO(g)Kc=0.81
At the start of the reaction, 0.34 mol N2, 0.34 mol O2 and 1.2 mol NO are introduced into a 0.75 L reaction chamber and allowed to equilibrate.
Required:
What is the concentration of NO (in M) at equilibrium?
Explanation:
here's the answer to your question
The concentration of NO at equilibrium is 1.6 M. The quantity of solute that has been dissolved in a certain volume of solvent or solution is measured by the solution's concentration.
What is concentration ?The quantity of a material, like salt, that is present in a specific volume of tissue or liquid, like blood. When there is less water present, the material becomes more concentrated.
A solution that contains a significant amount of dissolved solute is said to be concentrated.
The mental effort you put into whatever you're currently working on or studying is referred to as concentration. Although it's commonly mistaken with attention span, attention span relates to how long
0.34 mol of N₂ / 0.75 L
= ( 0.45 mol of N₂ ) ( 0.45 mol of O₂ )
1.2 mol NO / 0.75 L
= 1.6 M ( NO )
Thus, the concentration of NO at equilibrium is 1.6 M.
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Consider a solution containing 0.100 M fluoride ions and 0.126 M hydrogen fluoride. The concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is ________ M.
A) 0.0735
B) 0.0762
C) 0.0980
D) 0.0709
E) 0.00253
Answer: The concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.
Explanation:
Given: Concentration of hydrogen fluoride = 0.126 M
Concentration of fluoride ions = 0.1 M
Volume of HCl = 9.0 mL
Concentration of HCl = 0.01 M
Volume of HCl = 25.0 mL
Moles of [tex]F^{-}[/tex] ions are calculated as follows.
[tex]Moles of F^{-} = molarity \times volume\\= 0.1 M \times 0.025 L\\= 0.0025 mol[/tex]
Moles of HF are as follows.
[tex]Moles of HF = Molarity \times Volume\\= 0.126 M \times 0.025 L\\= 0.00315 mol[/tex]
Moles of HCl are as follows.
[tex]Moles of HCl = Molarity \times volume\\= 0.01 M \times 0.009 L\\= 0.00009 mol[/tex]
Now, reaction equation with initial and final moles will be as follows.
[tex]H^{+} + F^{-} \rightarrow HF[/tex]
Initial: 0.00009 0.0025 0.00315
Equilibrium: (0.0025 - 0.00009) (0.00315 + 0.00009)
= 0.00241 = 0.00324
Total volume = (9.00 mL + 25.0 mL) = 34.0 mL = 0.034 L
Hence, concentration of fluoride ions is calculated as follows.
[tex]Concentration = \frac{moles}{volume}\\= \frac{0.00241 mol}{0.034 L}\\= 0.0709 M[/tex]
Thus, we can conclude that concentration of fluoride ions after the addition of 9.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.0709 M.
what happens to water molecules when water vapor change to ice
Answer:
When the water vapor is cooled by the ice, the water molecules slow down more than in the cup without the ice. This allows their attractions to bring more molecules together to become liquid water.
When you burn a birthday candle, you may wonder whether the fire you see is matter. The
flame consists of hot, glowing gases, such as oxygen, carbon dioxide, water vapor, and
parts of the candle that have been vaporized. The heat and light given off are forms of
energy. The smoke contains ash and unburned particles.
a. From the above description of a candle flame, list at least three things that are matter and
three things that are not mattel. (6 points)
Matter
Not Matter
Answer:
matter
1. Candle. not matter
1. light
2. Unburned Particles
2. heat
3. Ash
3. energy
Explanation:
1.The candle is experiencing a solid phase into a gas phase because the heat given off causes smoke.
2. Chemical Potential Energy to Heat EnergyThe candle has Chemical Potential Energy then when it gets lit by the flame heat energy is released.
When do epa’s refrigerant management regulations exempt refrigerant from the venting prohibition
The Environmental Protection Agency (EPA) refrigerant management regulations would exempt any refrigerant from venting problem when it determines that the refrigerant in an appliance do not pose a threat to the environment (surrounding) if released.
A refrigerant can be defined as any chemical substance that undergoes a phase change (liquid and gas) so as to enable the cooling and freezing of materials. They are typically used in air conditioners, refrigerators, water dispensers, etc.
In the United States of America, the Environmental Protection Agency (EPA) is a governmental agency which was established by U.S Congress and it is saddled with the responsibility of overseeing all aspects of pollution, environmental clean up, degradation, pesticide use, contamination, and hazardous waste spills. Also, EPA research solutions, policy development, and enforcement of regulations through the resource Conservation and Recovery Act.
Simply stated, the Environmental Protection Agency (EPA) is the governmental agency set up to ensure that various industries, factories and people comply with laws and regulations concerning the environment.
In conclusion, appliances such as a refrigerator, air conditioner (AC), etc., whose refrigerants do not pose a threat (potentially cause damage) to the environment if released are typically exempted by the EPA's refrigerant management regulations.
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Combustion of 5.024 mg of coniine yields 13.90 mg CO2 and 6.048 mg of H2O. What is the empirical formula for coniine, listing the elements in the order C, H, N?
Answer:
C8H17N
Explanation:
Number of moles of c
13.90 × 10^-3/44 g/mol × 1 = 0.000316 moles
Mass of C= 0.000316 moles × 12 = 0.00379 g
Number of moles of H
6.048 × 10^-3/18 × 2 = 0.000672 moles
Mass of H
0.000672 moles × 1 = 0.000672 g
Mass of N
0.005024 - [0.00379 g + 0.000672 g]
= 0.000562 g
Number of moles of N
0.000562 g/14 = 0.00004 moles
Divide through by the lowest ratio;
C= 0.000316/0.00004, H= 0.000672 /0.00004, N= 0.00004/0.00004
C= 8, H = 17, N = 1
Hence the empirical formula is;
C8H17N
What is it?? plzzzz help
What is the difference between acids and strong acids?
a. Strong acids produce all of their H30+ ions
b. Strong acids release all of their H30+ ions
c. Strong acids produce all of their OH- ions
d.Strong acids release all of their OH ions
Answer:
A and b are the both the answers
The smallest atoms can themselves exhibit quantum-mechanical behavior. Calculate the de Broglie wavelength (in picometers) of a hydrogen atom traveling at 490 m/s. Express your answer using three significant figures.
Answer:
810 pm
Explanation:
Step 1: Given and required data
Velocity of the atom (v): 490 m/sMass of a hydrogen atom (m): 1.67 × 10⁻²⁷ kgPlanck's constant (h): 6.63 × 10⁻³⁴ J.sStep 2: Calculate the de Broglie wavelength of the hydrogen atom
We will use de Broglie's equation.
λ = h / m × v
λ = 6.63 × 10⁻³⁴ J.s / 1.67 × 10⁻²⁷ kg × 490 m/s = 8.10 × 10⁻¹⁰ m
Step 3: Convert 8.10 × 10⁻¹⁰ m to picometers
We will use the conversion factor 1 m = 10¹² pm.
8.10 × 10⁻¹⁰ m × 10¹² pm/1 m = 810 pm
Is sucrose classified as aldose or ketose?
Answer:
Because sucrose is a complex disaccharide, it is not classified as either an aldose or a ketone. Instead, it is a compound that contains both. glucose is aldose sugar and fructose is a ketose sugar.
difference between hygroscopic and deliquescent substance with of each
Answer:
The water soluble substance which absorb moisture from the air and then dissolve on the absorbed moisture to change into liquid taste are called deliquescent substances whereas the substances which absorb moisture from air but do not change their state are called hygroscopic substances.
Answer:
Hygroscopic substances absorb moisture from the air but do not dissolve in it, whereas substance that undergo deliquescence dissolves in the water vapour that is absorbed from the air, forming a liquid solution
The number of moles of H in 5 moles of glucose (C6H1206) is
Answer:
60 mols hydrogen
Explanation:
1 mol of glucose contains 12 mols of Hydrogen
5 mols of glucose contains 12 * 5 = 60 moles of hydrogen.
which of these is not a gas? A. hydrogen B. gravity C. Oxygen D. heluim
Answer:
B. Gravity
Explanation:
Gravity is a force, not a gas :)
Answer:
B: Gravity
Explanation:
gravity pulls on the gad
This is the chemical formula for zinc bromate: . Calculate the mass percent of oxygen in zinc bromate. Round your answer to the nearest percentage.
Answer:
30%
Explanation:
This is the chemical formula for zinc bromate: Zn(BrO₃)₂. Calculate the mass percent of oxygen in zinc bromate. Round your answer to the nearest percentage.
Step 1: Determine the mass of 1 mole of Zn(BrO₃)₂
M(Zn(BrO₃)₂) = 1 × M(Zn) + 2 × M(Br) + 6 × M(O)
M(Zn(BrO₃)₂) = 1 × 65.38 g/mol + 2 × 79.90 g/mol + 6 × 16.00 g/mol
M(Zn(BrO₃)₂) = 321.18 g/mol
Step 2: Determine the mass of oxygen in 1 mole of Zn(BrO₃)₂
There are 6 moles of atoms of oxygen in 1 mole of Zn(BrO₃)₂.
6 × m(O) = 6 × 16.00 g = 96.00 g
Step 3: Calculate the mass percent of oxygen in Zn(BrO₃)₂
%O = mO/mZn(BrO₃)₂ × 100%
%O = 96.00 g/321.18 g × 100% ≈ 30%
Calcium carbonate reacts with stomach acid (HCI) according to the following equation:
Caco, (s) + 2 HCl(aq) - CaCl, (aq) + CO2(g) + H20 (1)
Tums, an antacid, contains CaCo3. If Tums is added to 25.7 mL of a 0.738 M HCl solution, how many grams of Co, are produced?
Answer:
0.418 g of CO₂ will be produced
Explanation:
Equation of the reaction is given below:
CaCO₃ (s) + 2HCl (aq) ----> CaCl₂(aq) + CO₂ (g) + H₂O (l)
From the equation of reaction , 1 mole of CaCO₃ reacts with 2 molemolesmof HCl to produce 1 mole of CO₂
Number of moles of HCl in 25.7 ml of a 0.738 M solution of HCl is obtained using the formula below:
Number of moles = molarity × volume (Litres)
Number of moles of HCl = 0.738 M × 25.7 mL × 1 L/1000 mL = 0.0190 moles
Since the antacid, Tums will be excess, the limiting reactant is HCl
2 moles of HCl produces 1 mole of CO₂
0.0190 moles of HCl will produce 0.0190 moles ÷ 2 = 0.0095 molesof CO₂
Mass of 0.0095 moles of CO₂ = Numbe of moles × molar mass of CO₂
Molar mass of CO₂ = 44.0 g/mol
Mass of CO₂ produced = 0.00950 moles × 44.0 g/mol = 0.418 g of CO₂
Therefore, 0.418 g of CO₂ will be produced if Tums is added to 25.7 mL of a 0.738 M HCl solution
Calculate the concentration of ammonium nitrate in a solution prepared by dissolving 3.20 g of the salt in enough water to make 100. mL of solution, then diluting 2.00 mL of this solution to a volume of 25.00 mL.
Answer:
.032 M .
Explanation:
Molecular weight of ammonium nitrate is 80 .
3.2 g = 3.2 / 80 moles
= .04 moles
volume = 100 mL = 0.1 L
Molarity of 100 mL solution = .04 moles / 0.1 L
= 0.4 M solution.
Now 2 mL solution of 0.4 M is diluted to a volume of 25 mL .
Using the formula S₁ V₁ = S₂V₂
0.4 M x 2 mL = S₂ x 25 mL
S₂ = .4 x 2 / 25
= .032 M
Hence required concentration is .032 M .
Curium – 245 is an alpha emitter. Write the equation for the nuclear reaction and identify the product nucleus.
Answer:
Please find the complete solution in the attached file.
Explanation:
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Answer:
please translate in english
What is the specific heat of a substance if 373 J is required to raise the temperature of a 312 g sample by 15°C?
Answer:
0.080 J/g °C
General Formulas and Concepts:
Thermodynamics
Specific Heat Formula: q = mcΔT
q is heat (in J)m is mass (in g)c is specific heat (in J/g °C)ΔT is change in temperature (in °C)Explanation:
Step 1: Define
[Given] q = 373 J
[Given] m = 312 g
[Given] ΔT = 15 °C
[Solve] c
Step 2: Find Specific Heat
Substitute in variables [Specific Heat Formula]: 373 J = (312 g)c(15 °C)Multiply: 373 J = (4680 g °C)cIsolate c: c = 0.079701 J/g °CStep 3: Check
Follow sig fig rules and round. We are given 2 sig figs as our lowest.
0.079701 J/g °C ≈ 0.080 J/g °C
Topic: AP Chemistry
Unit: Thermodynamics
Fructose is an example of a ketohexose. The -hexose part of the name indicates that fructose is a Choose... that contains Choose... carbons. The keto- part of the name indicates that fructose contains Choose... functional group. Fructose can combine with glucose to form sucrose. Therefore, sucrose is a Choose... .
Answer:
carbohydrate, 6, a carbonyl, disaccharide
Explanation:
Fructose is an example of a ketohexose. The -hexose part of the name indicates that fructose is a carbohydrate that contains 6 carbons. There are more isomers that are ketohexoses.
The keto- part of the name indicates that fructose contains a carbonyl functional group. In ketones, the carbonyl is in an inner carbon.
Fructose can combine with glucose to form sucrose. Therefore, sucrose is a disaccharide. Disaccharides are formed by the bonding of 2 monosaccharides.
complete the following steps.
Remember to follow lower numbered rules first.
K2S(aq) + CO(NO3)2(aq) COS (?) + KNO3 (?)
a. Write a balanced chemical equation. (1 pt)
b. If a reaction occurs, write the balanced
chemical equation with the proper states of matter
(i.e. solid, liquid, aqueous) filled in. If no reaction
occurs, write “No reaction.” (1 pt)
c. If a reaction occurs, write the net ionic equatibn
for the reaction. If no reaction occurs, write “no
reaction.” (1 pt)
Answer:
See explanation
Explanation:
a) The balanced reaction equation is;
K2S + CO(NO3)2 ------> COS + 2 KNO3
b) When we include the states of matter, we have;
K2S(aq) + CO(NO3)2(aq) ----> COS(s) + 2 KNO3(aq)
c) The complete ionic equation is;
2K^+(aq) + S^2-(aq) + Co^2+(aq) + 2NO3^-(aq) ----> CoS(s) + 2K^+(aq) + 2NO3^-(aq)
Net ionic equation;
Co^2+(aq) + S^2-(aq) ----> CoS(s)
A gaseous mixture containing 7.00 moles of nitrogen, 2.50 moles of oxygen, and 0.500 mole of helium exerts a total pressure of 0.900 atm. What is the partial pressure of the nitrogen?
Answer:
Partial Pressure = 0.630atm
Explanation:
The total pressure of a mixture of gases is equal to the partial pressure of those gases. The partial pressure of a gas is defined as:
Partial pressure = Mole Fraction * Total pressure
The mole fraction of a gas is the ratio between the moles of the gas and the total moles.
To solve this question we need to find the mole fraction of nitrogen to find its partial pressure:
Mole Fraction nitrogen:
7.00 moles Nitrogen / (7.00moles N2 + 2.50moles O2 + 0.500moles He) = 0.700 = Mole fraction.
Partial Pressure = 0.700* 0.900atm
Partial Pressure = 0.630atmIdentify the most and the least acidic compound in each of the following sets. Leave the remaining answer in each set blank. a) difluoroacetic acid: _______ fluoroacetic acid: _______ trifluoroacetic acid: _______ b) 2-chlorobutanoic acid: _______ 4-chlorobutanoic acid: _______ 3-chlorobutanoic acid: _______ c) cyclohexanol: _______ phenol: _______ benzoic acid:
Explanation:
The given set of options are:
a) difluoroacetic acid: _______ fluoroacetic acid: _______ trifluoroacetic acid: _______
b) 2-chlorobutanoic acid: _______ 4-chlorobutanoic acid: _______ 3-chlorobutanoic acid: _______
c)cyclohexanol: _______ phenol: _______ benzoic acid:
A strong acid is one whose conjugate base is stabilized either by resonance or -I effect.
a) If -I groups are present on the carboxylic acid group then they stabilize the carboxylate anion (the conjugate base of the carboxylic acid) and give more strength to the carboxylic acid group. More the number of -I groups then more will be the strength of the carboxylic acid.
Among the given options,
Trifluoroacetic acid has three fluorine atoms in its structure thus it is a strong acid.
Fluoroacetic acid has only one fluorine atom in its structure. Hence it is the weak acid among the given options.
b) The -I groups should be nearer to the carboxylic acid group then it attains more stability.
If the distance of the -I group increases from the -COOH group then, the strength of the carboxylic acid group decreases.
So, the strongest acid is 2-chlorobutanoic acid.
The weak acid among them is 4-chlorobutanoic acid.
c) Among the given options benzoic acid is the strongest acid because due to resonance benzoate anion is stabilized more.
Here resonance exists in both phenyl group and [tex]-COO^-[/tex] group.
The weak acid is cyclohexanol.
Because cyclohexanolate anion is not stabilized by resonance.
write down any two test for the CH2=CH2[ethene]
Answer:
a) Linear polymerization
b) cyclic polymerization
Help naming this plzzzzzzzzzzzzz
Answer:
A. 3-chloro-1-methylcyclobutane.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to infer that the name of this compound is A. 3-chloro-1-methylcyclobutane because of the fact that the parent chain is a cyclobutane which starts by the methyl radical as it has the priority over the chlorine radical which is actually named first at the third carbon (clockwise).
Therefore the name is given in A, accordingly to the IUPAC rules of nomenclature.
Regards!
Part A
If the theoretical yield of a reaction is 23.5 g and the actual yield is 14.8 g, what is the percent yield?
Answer:
[tex]\boxed {\boxed {\sf 63.0 \%}}[/tex]
Explanation:
The percent yield is the ratio of the actual yield to the theoretical yield.
[tex]percent \ yield = \frac{actual \ yield}{theoretical \ yield} * 100[/tex]
The actual yield is the amount obtained from performing a chemical reaction. For this problem, it is 14.8 grams. The theoretical yield is the potential amount from performing a chemical reaction at maximum performance. For this problem, it is 23.5 grams.We can substitute the known values into the formula.
[tex]percent \ yield= \frac{ 14.8 \ g}{23.5 \ g}*100[/tex]
Divide.
[tex]percent \ yield = 0.629787234043*100[/tex]
Multiply.
[tex]percent \ yield = 62.9787234043[/tex]
The original measurements for the theoretical and actual yields have 3 significant figures, so our answer must have the same. For the number we calculated, that is the tenths place.
The 7 to the right, in the hundredths place, tells us to round the 9 up to a 0. Since we rounded up to 0, we have to move to the next place to the left and round the 2 up to a 3.
[tex]percent \ yield \approx 63.0[/tex]
The percent yield is approximately 63.0 percent.
Determine the type of alcohol corresponding to each given description or name. 1-pentanol 3-ethyl-3-pentanol 2-hexanol An alcohol with two other carbons attached to the carbon with the hydroxyl group_____.An alcohol with one other carbon attached to the carbon with the hydroxyl group____.An alcohol with three other carbons attached to the carbon with the hydroxyl group____.
Answer:
1). 1-pentanol - Primary
2). 3-ethyl-3-pentanol - Tertiary
3). 2-hexanol - Secondary
4). Alcohol with two other carbons attached to the carbon with the hydroxyl group - Secondary
5). Alcohol with one other carbon attached to the carbon with the hydroxyl group - Primary
6). Alcohol with three other carbons attached to the carbon with the hydroxyl group - Tertiary
Explanation:
The distinct types of alcohol have been matched with the categories above as per their descriptions provided. In chemistry, alcohols have been categorized into three different categories namely primary, secondary, and tertiary.
In the primary type, those alcohols are involved in which there is an association of hydroxyl group to a primary atom of carbon along with a minimum of two atoms of hydrogen. Example; ethanol.
In the secondary type, the alcohols have an association of carbon atoms to hydroxyl with a single atom of hydrogen and has a formula of '-CHROH.' Example: 2 - propanol.
In the tertiary alcohols, here the association is between the hydroxyl group with the carbon atom that is saturated and possessing 3 atoms of carbon associated with it. It has a formula of '-CR2OH.' Example: 3-ethyl-3-pentanol, -tert -butyl alcohol, etc.