Find the value of f(3) given f(x) = − 5x + 2​

Answer:

enlarge it

Step-by-step explanation:

I ft = 12 inches

Thus 8 in → 12 in makes the transformation larger.

Thus going from 8 in to 12 in is an enlargement

Answer:

Hello,

[tex]\boxed{Answer: 75}[/tex]

Step-by-step explanation:

x,y integers, x,y >0 ,x≠y

[tex]\dfrac{1}{x} +\dfrac{1}{y} =\dfrac{1}{18}\\\\\dfrac{x+y}{xy} =\dfrac{1}{18}\\\\x+y=\dfrac{xy}{18}\\\\x=\dfrac{18y}{y-18}\\x=\dfrac{18y-324 +324}{y-18}\\x=18+\dfrac{324}{y-18}\\[/tex]

[tex]\dfrac{1}{x} +\dfrac{1}{y} =\dfrac{1}{18}\\\\\dfrac{x+y}{xy} =\dfrac{1}{18}\\\\x+y=\dfrac{xy}{18}\\\\x=\dfrac{18y}{y-18}\\x=\dfrac{18y-324 +324}{y-18}\\x=18+\dfrac{324}{y-18}\\\begin{array}{|c|c|c|c|}y-18&y&x&x+y\\---&---&---&---\\1&19&18+324=342&362\\2&20&18+162=180&200\\3&21&126&147\\4&22&99&121\\6&24&108&132\\12&30&45&75\\18&36&36&72\\\end{array}\\\\\\\boxed{Answer: 75}\\\\[/tex]

Answer:

B

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here the vertex = (- 2, - 3 ) , then

y = a(x - (- 2))² - 3 , that is

y = a(x + 2)² - 3

To find a, substitute any point on the graph into the equation

Using the coordinates of the y- intercept (0, 5 )

5 = a(0 + 2)² - 3 ( add 3 to both sides )

8 = a(2)² = 4a ( divide both sides by 4 )

2 = a

y = 2(x + 2)² - 3 → B

Answer:

To determine the type of triangle using side lengths, you could use the converse of the Phythagorean theorem, acute triangle inequality theorem, and the obtuse inequality theorem. For example, if the square of the longest side of a triangle is greater than the sum of the squares of the other two sides, than its obtuse. And if the square of the longest side is less than the sum of the squares of the other two sides, then it would be acute. And if the square of the longest side is equal to the sum of the squares of the two other sides, then it would be a right triangle.

Step-by-step explanation:

it marks it correct on edge and it is not a sample answer.

have a jolly day!

Answer:

B.

[tex] \frac{275\pi}{6} {m}^{2} [/tex]

Step-by-step explanation:

[tex]area \: of \: sector \: is \\ \frac{the \: angle}{360} \times \pi {r}^{2} \\ hence \: we \: have \\ \frac{165}{360} \times {(10m)}^{2} = \frac{275\pi}{6} {m}^{2} [/tex]

Answer:

15.75 ft^3

Step-by-step explanation:

The volume of a cone is given by

V = 1/3 pi r^2 h where r is the radius and h is the height

We know the diameter is 3 so the radius is 1/2 the diameter or 3/2

The height is 7 and we will use 3 for pi

V = 1/3 (3) (3/2)^2 *7

V = 15.75 ft^3

Answer:

0.23923444976

The equation your teacher has given you is an identity. We can prove this by transforming one side into the other. I'll transform the right hand side (RHS) into the left hand side (LHS).

This means I'll keep the LHS the same for each line. I'll only change the RHS. The goal is to get the same thing on both sides (I could go the other way around but I find this pathway is easier).

[tex]\tan^4(\theta)+\sec^2(\theta) = \sec^4(\theta)-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\sec^2(\theta)\right)^2-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\tan^2(\theta)+1\right)^2-\tan^2(\theta) \ \text{ ... see note 1}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+2\tan^2(\theta)+1-\tan^2(\theta)\\\\[/tex]

[tex]\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\tan^2(\theta)+1\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta)-1+1 \ \text{ ... see note 2}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta) \ \ \Large \checkmark\\\\[/tex]

So because we've arrived at the same thing on both sides, the original equation is an identity. It always true no matter what theta value you plug in, as long as theta is in the domain. So something like theta = pi/2 won't work because tan(pi/2) = undefined and sec(pi/2) = undefined. It's based on how cos(pi/2) = 0 and this value is in the denominator. Dividing by zero is undefined.

Consequently, this means all solutions to cos(theta) = 0 will be excluded from the domain. Everything else works.

Answer:

y = 250 + 810x

Step-by-step explanation:

Let

y = total charges

x = cost per hour

Sally: building

y = 100 + 420x

Mia: painting

y = 150 + 390x

Find their total charges of building and painting

Add the total charges of both of them

y = 100 + 420x + 150 + 390x

y = 250 + 810x

Answer:

Geometric mean of a and b: Square root of axb.

16x64 = 1024

Square root of 1024: 32.

So, the geometric mean is 32.

Hope this helps!

Answer:

Step-by-step explanation:

Find the slope of the line AB.

The slope:

Since the altitude is perpendicular to AB, it has a slope of -2.

The line with the slope of -2 and passes through point C(6, 16).

Use point-slope equation to find the line:

A = 2, B = 1, C = 28

Answer:

Solution given:

A(7,9)

B(11,11)

C(6,16)

Slope of AB=[tex]\frac{11-9}{11-7}=\frac{2}{4}=½[/tex]

since altitude is perpendicular to it .

so its slope becomes negative reciprocal to the slope of base

so

slope of altitude(m) =-2

now

equation of a line passing through C(6,16) perpendicular to its base is:

By using formula

[tex]y-y_{1}=m(x-x_{1})[/tex]

y-16=-2(x-6)

solve it

y-16=-2x+12

y+2x=12+16

in the form of Ax +By=C is:

2x+y=28

:.

B=1

C=28

Answer: The expression is 7/2.

Answer jose needs to get 7 more A's because 5+7=12 so if 50+70=120 then he will need to get 7 more a's hope this helps :)

Step-by-step explanation:

Answer:

He needs 7 A's.

Step-by-step explanation:

The pictures.

Hope this helps!!! :)

SEE THE IMAGE FOR SOLUTION

HOPE IT HELPS

HAVE A GREAT DAY

Answer:

XY = 17

Step-by-step explanation:

Intersect secant theorem, EX * EY = EZ*EW

34 * EY = 25.5 * 68

      [tex]EY = \frac{25.5*68}{34}\\\\ = 25.5* 2\\\\ = 51.0 = 51[/tex]

EY  = 51

EX + XY = 51

 34 + XY = 51

        XY = 51 - 34 = 17

Answer:

χ² = 6.75

χ² Critical = 11.07

Step-by-step explanation:

Given the data :

Expected winnings ;

1/n * total number of wins

Total number of wins = 240

n = number of starting positions = 6

Expected winnings = 1/6 * 240 = 40

Using χ² test :

χ² = Σ(O - E)² / E

O = Observed ; E = Expected

χ² = (32 - 40)^2 / 40 + (33 - 40)^2 / 40 + (45 - 40)^2 / 40 + (44 - 40)^2 / 40 + (50 - 40)^2 / 40 + (36 - 40)^2 / 40

= 6.75

χ² Critical at α = 0.05 ; df = n - 1 ; df = 5

χ² Critical = 11.07

Since χ² < χ² Critical ; WE fail to reject H0.

Answer:

its C  option which is 12

Answer:

A

Step-by-step explanation:

Using Pythagoras' identity in either of the 2 right triangles

a² = (4[tex]\sqrt{3}[/tex] )² + (8[tex]\sqrt{3}[/tex] )² = 48 + 192 = 240 ( take square root of both sides )

a = [tex]\sqrt{240}[/tex] → A

9514 1404 393

Answer:

  27.932 in

Step-by-step explanation:

The initial angle (or height) is not shown, so we have assumed it is 30°. The equation for the height of the valve cap can be written as a function of angle:

  y = 15.375 +14.5·sin(x +30) . . . . . . where x is in degrees

The angle measured from the +x axis is already 30° when the rotation angle is zero. Evaluating the above equation with x = 390° gives an angle of 420°, or 60° beyond one full rotation.

  y = 15.375 +14.5·sin(60°) ≈ 27.932 . . . . inches above the ground.

The valve cap is 27.932 in. above the ground.

Answer:

108 squared centimeters

Step-by-step explanation:

Let's exchange π for 3:

area = πr^2

        = 3r^2

Now, as you can see, the radius of this circle is 6. Let's plug in the value of r:

area = 3r^2

        = 3 · 6^2

Simplify 6^2:

area = 3 · 6^2

        = 3 · 36

Multiply 3 by 36:

area = 3 · 36

area = 108

108 squared centimeters

Answer: Prime Factors for 18: 2, 3, and 3

Prime Factors for 19: 19

Prime Factors for 20: 2, 2, and 5

Can you mark brainlest

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

-10 x 12 x -4 + 40 x -2 x 6 - 2

-120 x -4 - 80 x 6 - 2

480 - 480 - 2

0 - 2

-2

Answer:

the answer is 5 for blank

Step-by-step explanation:

30=6×blank

blank = 30÷6

blank= 5

Answer:

Given,

[tex] \sqrt{ {x}^{2} + 4x + 4} - 3 = 0 \\ = > \sqrt{ {x}^{2} + 4x + 4} = 3 \\ = > {( \sqrt{ {x}^{2} + 4x + 4} })^{2} = {3}^{2} \\ = > {x}^{2} + 4x + 4 = 9 \\ = > {x}^{2} + 4x + 4 - 9 = 0 \\ = > {x}^{2} + 4x - 5 = 0 \\ = > {x}^{2} + 5x - x - 5 = 0 \\ = > x(x + 5) - 1(x + 5) = 0 \\ = > (x - 1)(x + 5) = 0 \\ \\ \sf \: either \: x - 1 = 0 \: \: \: \: \\ = > x = 1 \: \: \\ \\ \sf \: or \\ x + 5 = 0 \\ = > x = - 5 \\ \\ \green{ \boxed{ \bf \: \: \: \: \: x = 1 \: \: or \: - 5}}[/tex]

But if we put the value of x = 5 then it doesn’t satisfy the equation.

So,

X = 1

Answer:

The answer is [tex]x=1[/tex].

Step-by-step explanation:

To solve this problem, start by factoring the equation using the perfect square trinomial rule, which is states that the middle term is the first term multiplied by the last term, and then multiplied by 2. The formula for the perfect square trinomial rule looks like [tex]a^2+2ab+b^2[/tex], where [tex]a=x[/tex] and [tex]b=2[/tex]. The equation will look like [tex]\sqrt{(x+2)^2}-3=0[/tex].  

Next, pull out the terms from under the radical, assuming positive real numbers, which will look like [tex]x+2-3=0[/tex]. Then, simplify the equation by subtracting 3 from 2, which will look like [tex]x-1=0[/tex]. Finally, add 1 to both sides of the equation, and the answer will be [tex]x=1[/tex].

Answer:

2,196;    549;     131.76;     8;     175.68;      1339.56

Step-by-step explanation:

2,196 is the biggest number, so use that as the first number.

.25x2196=549

.06x2196=131.76

.08x2196=175.68

2196-(549+131.76+175.68)=1339.56

Solution :

Case I :

If Collen is late on [tex]0[/tex] out of [tex]5[/tex] days.

[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} $[/tex]

[tex]$=\frac{1}{32}[/tex]

Case II :

When Collen is late on [tex]1[/tex] out of [tex]5[/tex] days.

[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_1$[/tex]

[tex]$=\frac{1}{32} \times 5$[/tex]

[tex]$=\frac{5}{32}[/tex]

Case III :

When Collen was late on [tex]2[/tex] out of [tex]5[/tex] days.

[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_2$[/tex]

[tex]$=\frac{1}{32} \times 10$[/tex]

[tex]$=\frac{5}{16}[/tex]

Therefore, the [tex]\text{probability}[/tex] that Collen will arrive late to work no more than [tex]\text{twice}[/tex] during a [tex]\text{five day workweek}[/tex] is :

[tex]$=\frac{1}{32} + \frac{5}{32} + \frac{5}{16} $[/tex]

[tex]$=\frac{1}{2}$[/tex]

Answer:

i) where the digits can repeat

1. 30

2. 50

3. 33

4. 55

5. 35

6. 53

ii) where the digits cannot be repeated

1. 30

2. 50

3. 35

4. 53