Answer:
Answer to the following question is as follows.
Explanation:
Budding is indeed an asexual reproduction method in which an individual emerges from a reproductive anatomical site of the parent organism. During budding, a genetically identical new creature develops connected to the parent Hydra's body before eventually separating. A bud emerges as an extension of recurrent cellular division at one specific location during the budding process.
Try this for yourself. Suppose you want to estimate the number of field mice in a small field. One day you capture 500 mice, mark all of them and release them. The next week you capture 200 mice of which 40 were marked by you yesterday. What is your estimate of the population size?
Answer:
The approximate size of the field mice population is 2500 individuals.
Explanation:
There are different methods to study population density. There are direct methods and indirect methods. Among these last ones, we might find the "Mark-Recapture technique".
The Mark-Recapture technique assumes that the population is closed, during the sampling season there is no mortality nor natality, marks in the individual last the whole sampling season, and these do not affect the marked individual or their behavior. These marked individuals are randomly distributed in the population, and all the individuals have the same probability of being sampled.
The method consists of capturing a sample of individuals belonging to the population under study, in this case, the field mice population. After capturing the individuals, the researcher marks them and release them again. The third step is to sample again, capture a new amount of individuals, and count how many of them are marked. These marked individuals belong to the first sample. We can calculate the population size by using the Lincoln Index or any other index.
The Lincolns Index states that to obtain the population size, the research must follow the following procedure:
1) Take an initial sample with n1 number of individuals
2) Mark all the sampled individuals and release them
3) Take a second sample with n2 number of individuals
4) Count the number of marked individuals m
To estimate the total number of individuals in this population, N, the following equation must be considered:
N = (n1 x n2)/m
In the exposed example, this is:
• n1= 500 individuals in the first sample
• n2= 200 individuals in the second sample
• m= 40 individuals in the second sample that were previously marked
as they were part of the first sample
N = (n1 x n2)/m = (500 x 200) / 40 = 2500 individuals
The approximate size of the field mice population is 2500 individuals.
What is silk thread?
Why do scientists study seismographs?
To analyse mineral content from earth's crust
Answer:
To determine the location of an epicenter
Explanation:
A seismogram is a graph output by a seismograph ; a record of the shaking and vibration of the ground. By studying seismograms, scientists learn a lot about Earth's internal structure, like how fast the waves are moving and what type of material the waves are passing through.
Erosion and deposition constantly change Earth’s surface. Erosion carries natural materials like rock and soil from one place to another. Through deposition, these natural materials may be deposited in areas where they build up over time.
Which landform results from the deposition of materials in a valley during volcanic eruptions?
A.sill
B.mud pot
C.caldera
D.lava plateau
(Science)
The main structural unit of the cell membrane is the protein molecule
Answer:
The cell membrane consists of a double layer of lipid molecules covered by two layers of proteins. The lipid molecules are parallel to each other and perpendicular to the membrane.
What methods help control pollution source
Practicing conservation tillage traps contaminants from Runoff water. Practicing conservation tillage helps prevent BLANK
A. Air pollution
B. Water pollution
C. Soil erosion
Which of the following statement(s) is/are true regarding the adrenal glands' relationship with the autonomic nervous system?
a. The adrenal cortex is an extension of the parasympathetic nervous system.
b. The adrenal medulla secretes norepinephrine when stimulated by the sympathetic nervous system.
c. The adrenal glands are strictly nerve tissue.
d. The parasympathetic division stimulates the adrenal cortex to secrete glucocorticoids.
e. The adrenal medulla is penetrated by the fibers of the sympathetic nervous system.
Answer:
The true statements regarding the adrenal glands' relationship with the autonomic nervous system are:
a. The adrenal cortex is an extension of the parasympathetic nervous system.
c. The adrenal glands are strictly nerve tissue.
d. The parasympathetic division stimulates the adrenal cortex to secrete glucocorticoids.
e. The adrenal medulla is penetrated by the fibers of the sympathetic nervous system.
Explanation:
The levels of the central nervous system which play important roles in influencing the autonomic nervous system include cerebral cortex, hypothalamus, brain stem, and spinal cord. Usually, epinephrine (adrenaline) and norepinephrine are released into the blood stem when stress or a threat occurs. This alert serves as a warning signal and defense system. The purpose is to maintain homeostasis.
When body temperature increases, thermoreceptors are stimulated and send nerve signals to the CNS. The CNS sends motor signals to sweat glands, which attempt to reduce body temperature. This is an example of a __________ reflex.a. organ.b. stretch.c. withdrawal.d. visceral.
Answer:
d. visceral.
Explanation:
The visceral reflex is one that happens autonomously in the body, aiming to maintain the balance of the body through quick responses to some specific impulses. An example of a visceral reflex is the reduction in body temperature with the release of sweat from the sweat glands.
The visceral reflexes are controlled by the autonomic nervous system, using the sympathetic and parasympathetic nervous system.
Elizabeth was a "granola mom"it was only natural and organic foods and therapies for her
family. She belonged to a food co-op and ordered special foods and home remedies through
the group
Elizabeth was well read and conscientious, and she had a remedy for everything
Little white pills that dissolved under the tongue treated everything from teething to bruising.
When her 8-year-old daughter Samantha had a sore throat, Elizabeth had her gargle with
colloidal silver remedy used before all the new and "dangerous" antibiotics. Samantha did
get over her sore throat, but three weeks later, she broke out in a rash, complained that her
points hurt, and had swollen glands. This worried Elizabeth, and so she consulted a
conventional medical doctor.
Samantha was diagnosed with rheumatic fever, and the doctor prescribed antibiotic treatment.
Elizabeth had read that antibiotics could damage the immune system, and was reluctant to
give them to her daughter
How can you as a nurse, encourage compliance with long-term antibiotie treatment without
abenating Elizabeth? To what extent does a parent have the night to refuse medical advice for
a child? When are alternative therapies helpful?
Answer and Explanation:
1. As nurses, we can inform you that the use of antibiotics according to medical advice is not dangerous, because the doctor is able to prescribe a correct dose, which must be taken at the correct time intervals, to fight the disease without damaging the immune system . In that case, if the girl takes the medicine exactly as the doctor prescribed, she will have no problems and her body will recover completely.
2. Parents only have the right to refuse medical advice, when such advice is clearly abusive, puts the child at proven risk, or presents experimental treatments without scientific evidence, as it may endanger the child.
3. Alternative therapies are beneficial when they are accompanied by traditional medical treatment, or when they seek to promote relaxation and stress reduction, without trying to fight infections and more serious health problems.
What would be the most likely result if humans stopped burning fossil fuels?
Answer:
It allows an ozone layers not to be greatly in big holerelease fresh airAnswer:
If human stop burning fossil fuels then the condition and pollution will desperate. There would be more carbon dioxide and less oxygen.
hope it helps you!!!7. The sun's surface is about
a. 2000 °C
b. 3000 °C
c. 4000 °C
d. 5000 °C
(;´༎ຶٹ༎ຶ`)
Answer:
5778C ...................,.....
explain water cycle with the help of diagram
Explanation:
The water cycle is defined as a natural process of constantly recycling the water in the atmosphere. It is also known as the hydrological cycle or the hydrologic cycle. During the process of the water cycle between the earth and the atmosphere, water changes into three states of matter – solid, liquid and gas.hope it helps.stay safe healthy and happy...Which way do the chlorophyll bands move on the chromatography paper?
Answer:
They move up the chromatography paper.
Because the movement of the chlorophyll bands on the chromatography paper is dependent on the stationary phase and the mobile phase, the pigment separates different colors when moving the top of the paper.
What is the significance of chromatography?Chromatography is a technique that is used to separate and analyze a mixture of chemical substances and is a powerful tool in various fields such as chemistry and biochemistry. The significance of chromatography is that it allows scientists to identify and quantify individual components in a mixture and these techniques are helpful for the synthesis of drugs and other chemical products.
Hence, because the movement of the chlorophyll bands on the chromatography paper is dependent on the stationary phase and the mobile phase, the pigment separates different colors when moving the top of the paper.
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How has the natural environment in your area been affected by the human environment?
Answer:
animals are dying :( and people are hunting
Explanation:
Question 9
What is the main difference between a prokaryote and eukaryote cell?
Answers:
The presence of a cell wall
The presence of genomic DNA
The absence of genomic DNA
Crossing over
The absence of a cell wall
Question 10
Please choose 1
the presence of genomic DNA
Membrane proteins: are sometimes covalently attached to lipid moieties. are sometimes covalently attached to carbohydrate moieties. are composed of the same 20 amino acids found in soluble proteins. diffuse laterally in the membrane unless they are anchored All of the answers are correct.
Answer: All of the answers are correct.
Explanation:
Membrane proteins are sometimes covalently attached to lipid moieties. They're also composed of the same 20 amino acids found in soluble proteins and diffuse laterally in the membrane unless they are anchored. They're sometimes covalently attached to carbohydrate moieties as well.
Therefore, the correct option is All of the above.
Quick quick !!
Which problem affects the global economy in addition to a local economy?
A. A citywide power outage
B. Drought on an island
C. Water pollution in a lake
D. Pollution of the atmosphere
Answer:
D. Pollution of the atmosphere
Explanation:
All the other answers would seem to only affect the designated local area. However, option D would affect both the local and global economy.
P is an autosomal dominant allele that produces a pigment, p is a recessive allele that produces no pigment. A pigmented and a non-pigmented organism mate and produce a pigmented offspring. They then mate and produce a non-pigmented offspring. What is the probability the next offspring will be pigmented
Answer:3/4
Explanation:4 possibilities, 3 dominant
If a pigmented and non-pigmented organism mate and produce a pigmented organism, which mate again and produce non-pigmented organisms, the probability that the next offspring will be pigmented is ¾ as P is the dominant, pigment-producing allele.
What are dominant alleles?The association between two genetic variants is referred to as dominant. Each gene has two alleles that an individual inherits from each parent. One allele of a gene, known as the dominant gene, will be expressed if the alleles are different. The impact of the additional allele, known as the recessive one, is concealed.
If one is in charge, the other must be recessive. Then it is referred to as recessive. A dominant gene, or dominant form of a gene, is a specific variant of a gene that expresses itself more powerfully on its own than any other version of the gene that the individual is carrying—in this example, the recessive—for a variety of reasons.
Now, it mainly refers to patterns of inheritance typically used in combination with a Punnett square, where if a person has two copies of a gene and one is shown to frequently be passed down from one generation to another, it is referred to as dominant.
According to biochemistry, what is happening in this situation is that the genetic variant may, for a variety of reasons, cause a cell to perform a very advantageous or very disadvantageous function that the other version of the gene cannot cover up or counteract.
Therefore, the probability that the next offspring will be pigmented is ¾ as P is the dominant, pigment-producing allele.
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Methylene blue can be used to stain DNA because it: (2 pts) forms ionic bonds with DNA changes the pH and therefore the structure of DNA makes DNA electron dense is an effective chemical fixative for cells is none of the above
Answer: Methylene blue can be used to stain DNA of a cell because it (forms ionic bonds with DNA).
Explanation:
To examine the components of a cell usually under a microscope, a stain or dye is being used to provide a clear and defined view of the area under study.
The deoxyribonucleic acid (DNA) of a cell which contains the hereditary information of the cell is located in the nucleus.
Methylene blue is a type of stain used by biologists which helps them view microscopic life in brilliant color. It is a cationic stain (positively charged blue dye); and binds to negatively charged parts of the cells, such as nucleus (DNA) and RNA in the cytoplasm (with lower affinity).
When DNA of a cell comes in contact with methylene blue on a slide, their opposite charges attract, causing methylene blue's "rings" to slide in between the "rungs" of the DNA "ladder." As a result, a rich blue stain that identifies the location of the cell nucleus can be observed. This produces a photosensitive reaction which can then be viewed under the microscope.
Therefore is can be used to stain the DNA of cell because it forms ionic bonds with DNA.
¿Qué nombres reciben los tejidos que dan
origen a los tejidos adultos de las plantas?
a. Tejidos diferenciados
b. Tejidos indiferenciados (meristemos)
c. Tejidos vegetales
Answer:
D
Explanation:
how do humans impact the biodiversity of ecosystems
Answer:
Humans affect biodiversity by their population numbers, use of land, and their lifestyles, causing damage to habitats for species. Through proper education, and by demanding that governments make decisions to preserve biodiversity, the human population will be able to sustain life on earth longer.
Explanation:
Human population levels, land usage, and lifestyles all have an impact on biodiversity, causing damage to species' habitats. The human population will be able to maintain life on Earth for longer if adequate knowledge is provided and governments are forced to make decisions that protect biodiversity.
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Several genes in humans in addition to the ABO gene (I ) give rise to recognizable antigens on the surface of red blood cells. The MN and Rh genes are two examples. The Rh locus can contain either a positive or a negative allele, with positive being dominant to negative. M and N are codominant alleles of the MNgene. Suppose a child's blood type is B MN Rh(neg). The mother's blood type is O N Rh(neg). Check all of the blood types below that the father could have. (Assume no involvement of the Bombay phenotype; everyone is HH.)
a) O M Rh(neg)O M Rh(neg)
b) B MN Rh(pos)B MN Rh(pos)
c) A M Rh(pos)A M Rh(pos)
d) O MN Rh(pos)O MN Rh(pos)
e) B MM Rh(pos)B MM Rh(pos)
f) B NN Rh(neg)
An adult giraffe (Giraffa camelopardalis) has a heart that lies approximately 2 m below the top of the head when its neck is fully extended. Calculate the minimum diastolic pressure that a giraffe must have (in mm Hg). Hint: what is the absolute minimum blood pressure a giraffe could have at the very top of its head
Answer:
159.01 mmHg
Explanation:
position of Heart = 2m below the top of the head given that the neck is fully extended
Determine the minimum diastolic pressure
Minimum diastolic Pressure = 1060 kg/m^3 * 10 m/s^2 * 2m
= 21200 kg/m^2
convert the value to Pa
21200 kg/m^2 = 21200 Pa
( 1 pa = 0.00750062 mmHg )
Therefore : minimum diastolic pressure = 21200 * 0.00750062 = 159.01 mmHg
The minimum diastolic pressure that a giraffe must have is 150 mmHg
Diastolic Blood pressureDiastolic Blood pressure is the pressure on the walls of your arteries between heartbeats, that is when the heart is resting.
The minimum diastolic diastolic blood pressure = absolute minimum blood pressure a giraffe could have at the very top of its head.Pressure formulaP = hpg
where;
P = pressure
h = height difference
p = density
g = acceleration due to gravity
Density of blood = 1000 kg/m^3
h =2.0 m
g = 10 m/s^2
Pressure = 1000 × 2.0 × 10
Pressure = 20000 Pascal or 20 kpa
Converting to mmHg1 kpa = 7.50 mmHg
20 kpa = 20 × 7.50
Pressure = 150 mmHg
Therefore, the minimum diastolic pressure that a giraffe must have is 150 mmHg
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Writing an Equation in Slope-Intercept Form
Q
Check
y
Determine the equation for the given line in
slope-intercept form
4
O y = -5x-1
=-1
2
X
-6
-4
-2
2
LO
O y = x+1
O y = 3x+1
O y=-x-1
-2
-4
Hint
Answer:
need a full picture plzzz
Chemical rocks are formed by ____ that grow out of a solution.
Answer:
crystals
Explanation:
it is usually measured in m/s
Explanation:
The speed of light in vacuum is 299 792 458 meters per second. unit of acceleration is the meter per second per second (m/s2). unit of area is the square meter (m2).
...
Units of Length
10 millimeters (mm) = 1 centimeter (cm)
10 centimeters = 1 decimeter (dm)
10 centimeters = 100 millimeters
10 decimeters = 1 meter (m)
what precautions should you take to avoid exposure to blood borne pathogens
Explanation:
The Bloodborne Pathogens standard (29 CFR 1910.1030) and CDC's recommended standard precautions both include personal protective equipment, such as gloves, gowns, masks, eye protection (e.g., goggles), and face shields, to protect workers from exposure to infectious diseases.
Answer:
The Bloodborne Pathogens standard (29 CFR 1910.1030) and CDC's recommended standard precautions both include personal protective equipment, such as gloves, gowns, masks, eye protection (e.g., goggles), and face shields, to protect workers from exposure to infectious diseases.
Normal diploid somatic cells of the mosquito Culex pipiens contain six chromosomes. The G1 nucleus of a mosquito cell contains 3.0 x 10^-12 grams of DNA. How much nuclear DNA would be expected in metaphase I of meiosis?
a. 6.0 x 10^-12 g.
b. 1.5 x 10^-12 g.
c. 12 x 10^-12 g.
d. 3.0 x 10^-12 g.
e. 0.75 x 10^-12 g.
Answer:
a. 6.0 x 10^-12 g.
Explanation:
The interphase is the previous step before the cell divission occurs. The interphase is formed of the G1, S, and G2 stages.
• During the G1 stage, it occurs a high intense biochemical activity. The cell duplicates its size, and the organelles and other molecules and cytoplasmatic structures duplicate too. Some structures, such as microtubules and actin filaments, are synthesized from zero. The endoplasmic reticulum increases in size and produces a membrane for the Golgi apparatus and vacuoles, lysosomes, and vesicles. During this stage, the pair of centrioles separate, and each centriole duplicates. Mitochondria and chloroplasts also replicate.
• During the S stage occurs the DNI replication process. It also occurs the synthesis of histones and other associated proteins. This is the only stage where the DNI molecule is replicated.
• G2 stage is the final one before the cellular division. Here begins the slow process of DNI condensation. Duplication of centrioles completes. Structures such as spindle fibers are assembled.
Through the process of Meiosis, a diploid germ cell (2n) divides and originates four daughter cells with a haploid chromosome number (n). Each daughter cell has half of the chromosomes of the original one. Meiosis is completed in two phases. During the first phase, and after replication, occurs the chromosome´s reduction division. During the second phase, the cell suffers a new, not reductive division.
1. In the first phase, Meiosis I:
Prophase I: Chromosomes condensate and became visible. Occurs crossing-over between homologous chromosomes. Crossin-over makes the daughter cells to be genetically different from the original one. Metaphase I: The pairs of homologous chromosomes randomly align in the equatorial plane. Anaphase I: occurs the independent separation of homologous chromosomes that migrate to opposite poles of the cell. This separation generates different chromosomal combinations in the daughter cells. Telophase I: Each of the homologous pairs chromosomes is already in the corresponding poles, and the nuclear membrane forms again in each pole.2. In the second phase, Meiosis II:
Prophase II: Chromosomes condensate again and become visible. Metaphase II: Chromosomes join the spindle apparatus and migrate to the equatorial plane, where they randomly line up. Sister chromatids are holden together until they reach the Anaphase. Anaphase II: Centromeres divide, chromatids get separated, and each of them goes forward an opposite cellular pole. Telophase II: Once in the poles, the chromosomes became lax again, and cytokinesis occurs.In the exposed example, DNI in the G1 nucleus of a mosquito cell still has not suffered replication (3.0 x 10^-12 grams). The replication process occurs during the S stage, which follows the G1 stage. After the S stage, the cell has 6.0 x 10^-12 g of DNI.
During meiosis, the reduction in chromosomes number occurs in anaphase where homologous chromosomes migrate to different poles. But during metaphase I, the cell still has 6.0 x 10^-12 g of DNI.
based on the 1:2:1 proportions of carbon, hydrogen and oxygen, it can be determined that a glucose molecule is a
Answer:
Carbohydrate (monosaccharide)
Explanation:
Carbohydrates are one of the four biological molecules in nature. Carbohydrates are structurally composed of carbon, hydrogen and oxygen elements. However, these elements (C,H,O) are present in each carbohydrate in the ratio 1:2:1 respectively.
As stated in this question, glucose is an organic molecule made up of carbon, hydrogen and oxygen in the 1:2:1 proportion, hence, it is a CARBOHYDRATE. Since glucose possess one sugar component, it is classified as a MONOSACCHARIDE with a chemical formula C6H12O6.
Complete each sentence by dragging each word or phrase to the proper position. Then arrange the sentences into the order of occurrence of motor impulses of the ANS.
1. Action potentials travel along the nerve fiber and enter the__________.
2. Fibers exiting the take one of three routes: the spinal nerve route, the sympathetic nerve route, and the _________nerve route.
3. Arriving at target cells_______ nerve fibers release acetylcholine or norepinephrine into the synaptic cleft.
4. Also known as the________ division, the sympathetic nervous system exits the preganglionic CNS via the spinal nerves from T1-L2.
5. The effect of norepinephrine binding to_______ receptors stimulates cardiac muscle cells. i. postganglionic
ii. sympathetic chain ganglia,
iii. craniosacral
iv. thoracolumbar
v. cholinergic
vi. preganglionic
vii. adrenergic
viii. splanchnic
Answer:
1. vi. Preganglionic
2. vii. adrenergic
3. ii. sympathetic chain ganglia
4. iii. Craniosacral
5. viii. splanchnic
Explanation:
Action potential travel down preganglionic nerve fibre. They travel towards Vagus Nerve near the effector organ. These impulses arrive at cardiac plexus, which create action potential in postganlianic.
A cell that connects the body to receive the signal from the brain to do the action is called a neuron and the tissue system is called the nervous system.
The answer to the following question is as follows:-
Action potentials travel along with the nerve fiber and enter the Preganglionic Fibers exiting take one of three routes: the spinal nerve route, the sympathetic nerve route, and the adrenergic nerve route. Arriving at target cells sympathetic chain ganglia nerve fibers release acetylcholine or norepinephrine into the synaptic cleft. Also known as the Craniosacral division, the sympathetic nervous system exits the preganglionic CNS via the spinal nerves from T1-L2.The effect of norepinephrine binding to splanchnic receptors stimulates cardiac muscle cells.Hence, these are the answer to the question.
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