Enter the equation of the line in slope-intercept form.
Slope is -3, and (4,2) is on the line.
The equation of the line is

60° because it's an equilateral triangle

Answer:

[tex]5\sqrt{5}[/tex]

Step-by-step explanation:

1. [tex]5^2 +10 ^2 = c^2[/tex]

2. [tex]c^2 = 125[/tex]

3. [tex]c = 5\sqrt{5}[/tex]

Answer:

approximately 11.18 inches or [tex]5\sqrt{5[/tex] inches

Step-by-step explanation:

We have to use Pythagorean Theorem for this problem. a^2 + b^2 = c^2, where c is the hypotenuse and a/b are legs of the right triangle.

5^2 + 10^2 = c^2, 25 + 100 = c^2, 125 = c^2, sqrt125 = c

sqrt125 can be simplified to 5sqrt5 (25 * 5 = 125, sqrt25 = 5)

The hypotenuse is approximately 11.18 inches or [tex]5\sqrt{5[/tex] inches.

Answer: 5/3

5/8÷3/8​ =

5/8 * 8/3 =

40/24​ = 20/12 = 10/6 = 5/3

Step-by-step explanation:

Answer:

Hello,

[tex]16\pi[/tex]

Step-by-step explanation:

[tex]I=\dfrac{Area}{4} =\int\limits^4_0 {\sqrt{16-x^2} } \, dx \\\\Let\ say\ x=4*sin(t),\ dx=4*cos(t) dt\\\\\displaystyle I=\int\limits^\frac{\pi }{2} _0 {4*\sqrt{1-sin^2(t)} }*4*cos(t) \, dt \\\\=16*\int\limits^\frac{\pi }{2} _0 {cos^2(t)} \, dt \\\\=16*\int\limits^\frac{\pi }{2} _0 {\frac{1-cos(2t)}{2}} \, dt \\\\=8*[t]^\frac{\pi }{2} _0-[\frac{sin(2t)}{2} ]^\frac{\pi }{2} _0\\\\=4\pi -0\\\\=4\pi\\\\\boxed{Area=4*I=16\pi}\\[/tex]

Answer:

Total chairs = 18×22= 396

so no. of extra chairs need = 468-396 = 72

Now( 72/18) rows = 4 rows

Therefore 4 more rows are needed here

Hope it helps you

Answer: 4

Step-by-step explanation:

The amount of chairs in the hall can be found by multiplying 22 by 18 and getting 396. The amount of chairs needed is 468, so 468-396 gets you the amount of chairs still needed and the number 72. There are 18 chairs in each row, and 72/18 is 4. So 4 more rows are needed.

Answer:

sin A = 12 /13

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin A = opp / hyp

sin A = 12 /13

[tex]\sf \: {x}^{2} + 4xy - 21 {y}^{2} [/tex]

[tex]\sf \: Rewrite \: the \: equation⟹( {x}^{2} - 3xy) + (7xy - 21y {}^{2} )[/tex]

[tex]\sf \: 1)( {x}^{2} - 3xy) = x(x - 3y)[/tex]

[tex]\sf2) \: (7xy - 21 {y}^{2} ) = 7y(x - 3y)[/tex]

[tex]\sf \: Now \: the \: equation \: becomes \: ⟹ \\ \sf \: x(x - 3y) + 7y(x - 3y)[/tex]

[tex]\sf \: Factor \: out \: the \: common \: term \: (x - 3y) \\ \sf =( x - 3y) + (x + 7y) \\ [/tex]

Answer ⟶ [tex]\boxed{\sf {B) (x-3y)(x+7y)}}[/tex]

============================================

Explanation:

We have 12 oz of 50% chocolate syrup, which means we have 0.50*12 = 6 oz of pure chocolate from this bottle. We add on x more ounces of pure chocolate from the second batch. So we have 6+x ounces of pure chocolate.

This is out of 12+x ounces of mixed syrup (chocolate + other stuff) overall.

The fraction (6+x)/(12+x) represents the proportion of pure chocolate to the mixed syrup batch. Set this equal to 0.75 and solve for x.

(6+x)/(12+x) = 0.75

6+x = 0.75(12+x)

6+x = 0.75(12)+0.75(x)

6+x = 9+0.75x

x-0.75x = 9-6

0.25x = 3

x = 3/0.25

x = 12

So we must add 12 ounces of pure chocolate to the mix

--------------------

We can think of this problem in terms of colored blocks.

Let's say a brown block represents a unit of pure chocolate, while a blue block is something else (say sugar or whatever other ingredients).

Currently we have 6 brown blocks (the 6 oz of pure chocolate) out of 12 blocks overall (6 brown + 6 blue).

If we add on 12 more brown blocks, then we get 6+12 = 18 brown blocks overall out of 12+12 = 24 blocks (brown+blue).

Then notice how 18/24 = 0.75 = 75% to represent the fact that 75% of the blocks are brown. So 75% of the syrup is pure chocolate.

This thought experiment is one way to help verify the answer.

Answer:

12

Step-by-step explanation:

.5 * 12 = 6

(6 + x) /( 12 + x)

[tex]\frac{x+6}{x+12} = .75[/tex]

x + 6 = .75(x+12)

x = 12

Answer:

5m-n-4p

4a^2+6x-3

Step-by-step explanation:

3m-4n +7p

-5m +9n -6p

+7m -6n -5p

----------------------

Combine like terms

3m-4n +7p

-5m +9n -6p

+7m -6n -5p

----------------------

(3-5+7)m  +(-4+9-6)n  +(7-6-5)p

5m-n-4p

a^2  -3x +1

a^2   +9x -6

2a^2 +0x +2

----------------------

Combine like terms

a^2  -3x +1

a^2   +9x -6

2a^2 +0x +2

----------------------

(1+1+2)a^2 +(-3+9+0)x +(1-6+2)

4a^2+6x-3

#1

[tex]\\ \sf\longmapsto 3m-4n+7p+(-5m+9n-6p)+7m-6n-5p[/tex]

[tex]\\ \sf\longmapsto 3m-4n+7p-5m+9n-6p+7m-6n-5p[/tex]

[tex]\\ \sf\longmapsto 3m-5m+7m-4n+9n-6n+7p-6p-5p[/tex]

[tex]\\ \sf\longmapsto 5m-n-4p[/tex]

#2

[tex]\\ \sf\longmapsto a^2-3x+1+a^2+9x-6+2a^2+2[/tex]

[tex]\\ \sf\longmapsto a^2+a^2+2a^2-3x+9x+1-6+2[/tex]

[tex]\\ \sf\longmapsto 4a^2+6x-3[/tex]

Answer:

3

Step-by-step explanation:

(40/5)-7+2

PEMDAS says parentheses first, so divide inside the parentheses

(8)-7+2

Then add and subtract from left to right

1 +2

3

Answer:

3

Step-by-step explanation:

Using PEMDAS:

(40/5)-7+2

- > 40/5 - 8

8 - 7 + 2

1 + 2

3

Hope this helps you.

Answer:

3053.63

Step-by-step explanation:

Not sure how to explain-

but i hope it helps c:

Answer:

B

Step-by-step explanation:

Domain is the set of x values

Looking at the table we can say that the set of x values ( domain ) is {1,2,3,4}

Answer:

[tex]{ \tt{ \frac{4 {x}^{5} }{2 {x}^{2} + 5 } = 59 }}[/tex]

Cross multiply the variables:

[tex]{ \tt{4 {x}^{5} = 59(2 {x}^{2} + 5)}} \\ { \tt{4 {x}^{5} = 118 {x}^{2} + 295}} \\ { \tt{4 {x}^{5} - 118 {x}^{2} = 295}}[/tex]

Factorise the equation:

[tex]{ \tt{ {x}^{2}(4 {x}^{3} - 118) = 295 }}[/tex]

Either x² or ( 4x³ - 118 ) is equal to 295:

For x²:

[tex]{ \tt{ {x}^{2} = 295}} \\ { \tt{first \: answer : \: x =17.2 }}[/tex]

For ( 4x³ - 118 ):

[tex]{ \tt{4 {x}^{3} = 413 }} \\ { \tt{ {x}^{3} = 103.25}} \\ { \tt{second \: answer : \: x = 4.7 }}[/tex]

Answer:

3x

Step-by-step explanation:

factoring it we get

3x(4x-3)

Answer:

0.125

Step-by-step explanation:

1=40000

x-5000

x=5000÷40000=1/8=0.125

Answer: yes

A prime factor is number that can only divided by itself and one

Since, 17 can only be divided by 17 and 1, the student is correct

Step-by-step explanation:

Answer:

add 2 equations given

3y+x+2y- x = 10

5y =10

y = 2

find x using the value of y

x = - 2

these values of x and y are can satisfy both equations .so (-2,2) lies on both lines

Answer:

-4/5

Step-by-step explanation:

sin theta = opp/ hyp

sin theta = -3 /5

Using the Pythagorean theorem

opp ^2 + adj ^2 = hyp ^2

(-3) ^2 + adj ^2 = 5^2

9+ adj ^2 = 25

adj ^2 = 25 - 9

adj ^2 = 16

Taking the square root of each side

adj = ±4

Since we are in the 3rd quadrant  sin and cos are both negative so adj must be negative

adj = -4

cos theta = adj / hyp

cos theta = -4/5

Answer:

I am pretty sure $750

Step-by-step explanation:

Since there are 10 slices of cake, you would have to divded the cost ($2,500) by 10 to find out the cost per slice (you would get $250). Since we are finding the cost of 3 slices, you would mulitply 250 by 3, then you get your answer

Answer:

11

Step-by-step explanation:

a+b^2

Let a=2 and b=3

2+3^2

2 + 9

11

Answer: 11

2 + (3 x 3 )

2 + 9

The required answer would be 11 :)

Step-by-step explanation:

hope it was helpful, aby questions u have u r welcome

Answer: where's the pic?

Step-by-step explanation:

Answer: 3000 stamps

Step-by-step explanation:

Given

Chris and Josh have 1800 stamps

Josh and Jessica have 2200 stamps

Jessica and Chris have 2000 stamps

Suppose Chris, Josh, and Jessica have [tex]x,y, \text{and}\ z[/tex] stamps

[tex]\therefore x+y=1800\quad \ldots(i)\\\Rightarrow y+z=2200\quad \ldots(ii)\\\Rightarrow z+x=2000\quad \ldots(iii)\\\text{Add (i), (ii), and (iii)}\\\Rightarrow 2(x+y+z)=1800+2200+2000\\\Rightarrow x+y+z=3000[/tex]

Thus, all three have 3000 stamps

Given:

The function are:

[tex]f(x)=Kx^2+4x-3[/tex]

[tex]g(x)=2x-7[/tex]

The graph of f(x) intersect the line g(x) at one point.

To find:

The value of K.

Solution:

The graph of f(x) intersect the line g(x) at one point. It means the line g(x) is the tangent line.

We have,

[tex]f(x)=Kx^2+4x-3[/tex]

Differentiate this function with respect to x.

[tex]f'(x)=K(2x)+4(1)-(0)[/tex]

[tex]f'(x)=2Kx+4[/tex]

Let the point of tangency is [tex](x_0,y_0)[/tex]. So, the slope of the tangent line is:

[tex][f'(x)]_{(x_0,y_0)}=2Kx_0+4[/tex]

On comparing [tex]g(x)=2x-7[/tex] with slope-intercept form, we get

[tex]m=2[/tex]

So, the slope of the tangent line is 2.

[tex]2Kx_0+4=2[/tex]

[tex]2Kx_0=2-4[/tex]

[tex]x_0=\dfrac{-2}{2K}[/tex]

[tex]x_0=-\dfrac{1}{K}[/tex]

Putting [tex]x=x_0,g(x)=y_0[/tex] in g(x), we get

[tex]y_0=2x_0-7[/tex]

Putting [tex]x=-\dfrac{1}{K}[/tex] in the above equation, we get

[tex]y_0=2(-\dfrac{1}{K})-7[/tex]

[tex]y_0=-\dfrac{2}{K}-7[/tex]

Putting [tex]x=-\dfrac{1}{K}[/tex] and [tex]f(x)=-\dfrac{2}{K}-7[/tex] in f(x).

[tex]-\dfrac{2}{K}-7=K\left(-\dfrac{1}{K}\right)^2+4(-\dfrac{1}{K})-3[/tex]

[tex]-\dfrac{2}{K}-7=\dfrac{1}{K}-\dfrac{4}{K}-3[/tex]

[tex]-\dfrac{2}{K}-7=\dfrac{-3}{K}-3[/tex]

Multiply both sides by K.

[tex]-2-7K=-3-3K[/tex]

[tex]-2+3=7K-3k[/tex]

[tex]1=4k[/tex]

[tex]\dfrac{1}{4}=K[/tex]

Therefore, the value of K is [tex]\dfrac{1}{4}[/tex].

Answer:

It must be a positive number since it represents a number of hours.

Step-by-step explanation:

Given Pieter's equation :

7h – 5(3h – 8) = –72

Opening up the bracket

7h - 15h + 40 = - 72

7h - 15h = - 72 - 40

-8h = - 112

Divide both sides by -8

-8h / -8 = - 112 / - 8

h = 14

Since, h represents the number of hours, and the value of h equals 14 (h cannot be negative), hence, option 2 is correct.

Answer:

B.It must be a positive number since it represents a numbers of hours.

Step-by-step explanation:

Answer:

Please check explanations

Step-by-step explanation:

The diameter is twice the height;

if diameter is d and height is h

Then;

d = 2h

But, we know that the radius is half the diameter size. Which means that the diameter is twice the radius

Thus;

2r = 2h

Then r = h

Mathematically the total surface area of a cylinder is;

2pi r (r + h)

substitute h for r

2pi h(h + h)

= 2pi * h * 2h

= 4 pi h^2 (QED)

Answer:

140

Step-by-step explanation:

Angles 1, 2 and 3 are in a straight line,

Straight line has 180 degrees,

∠1 = ∠3 = 20

∠1 + ∠2 + ∠3 = 180

20 + ∠2 + 20 = 180

∠2 + 40 = 180

∠2 = 180 - 40

∠2 = 140

Answer:

4

Step-by-step explanation:

use pemdas.

4+4-4x4/4

4+4-16/4

4+4-4

8-4

4