Answer:
B = 4.5 x 10⁻⁷ T = 0.45 μT
Explanation:
From Ampere's law the magnetic field at a certain radius from straight current-carrying wire is given by the following formula:
[tex]B = \frac{\mu_oI}{2\pi r}[/tex]
where,
B = magnetic field = ?
[tex]\mu_o[/tex] = permeability of free space = 4π x 10⁻⁷ H/m
I = current = 180 A
r = radius = 80 m
Therefore,
[tex]B=\frac{(4\pi\ x\ 10^{-7}\ H/m)(180\ A)}{2\pi (80\ m)}\\\\[/tex]
B = 4.5 x 10⁻⁷ T = 0.45 μT
A navy diver hears the underwater sound wave from an exploding ship across the harbor. They immediately lift their head out of the water. The sound wave from the explosion propagating through the air reaches the diver 4.00 s later. The sound velocity is 1440 m/s in water How far away is the ship?
Answer:
s = 1800 m = 1.8 km
Explanation:
The distance, the speed, and the time of reach of the sound are related by the following formula:
[tex]s = vt[/tex]
where,
s = distance
v = speed
t = time
FOR WATER:
[tex]s = v_wt[/tex] ---------------------- eq (1)
where,
s = distance between ship and diver = ?
[tex]v_w[/tex] = speed of sound in water = 1440 m/s
t = time taken by sound in water
FOR AIR:
[tex]s = v_a(t+4\ s)[/tex] ---------------------- eq (2)
where,
s = distance between ship and diver = ?
[tex]v_a[/tex] = speed of sound in water = 344 m/s
t + 4 s = time taken by sound in water
Comparing eq (1) and eq (2),because distance remains constant:
[tex]v_wt=v_a(t+4\ s)\\\\(1440\ m/s)t = (344\ m/s)(t+4\ s)\\(1440\ m/s - 344\ m/s)t=1376\ m\\t = \frac{1376\ m}{1096\ m/s}[/tex]
t = 1.25 s
Now using this value in eq (1):
[tex]s = (1440\ m/s)(1.25\ s)[/tex]
s = 1800 m = 1.8 km
The elastic extensibility of a piece of string is .08. If the string is 100 cm long, how long will the string be when it is stretched to the point where it becomes plastic?
Answer:
The elastic extensibility of a piece of string is .08. If the string is 100 cm long, how long will the string be when it is stretched to the point where it becomes plastic? is your ansewer dont take tension
The string will be 108 cm long when it is stretched to the point where it becomes plastic.
What is elasticity?Elasticity in physics and materials science refers to a body's capacity to withstand a force that causes distortion and to recover its original dimensions once the force has been withdrawn.
When sufficient loads are applied, solid objects will deform; if the material is elastic, the object will return to its original size and shape after the weights have been removed. Unlike plasticity, which prevents this from happening and causes the item to stay deformed,
Given parameters:
The elastic extensibility of a piece of string is 0.08.
The string is 100 cm long.
Hence, it becomes plastic, after it is stretched up to = 100 × 0.08 cm = 8 cm. The string will be 108 cm long.
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A milliammeter has an internal resistance of 5ohms and
reads upto 20 millianmeter, cal the value of the resistance
that should beconnected to it to enable to read up to
5A
Answer:
Rs = 0.02008 Ω = 20.08 mΩ
Explanation:
The range of an ammeter can be increased by connecting a small shunt resistance to it in a series combination. This shunt resistance can be calculated by the following formula:
[tex]Rs = \frac{I_gR_g}{I - I_g}[/tex]
where,
[tex]R_s[/tex] = value of shunt resistance = ?
[tex]I_g[/tex] = current range of ammeter = 20 mA = 0.02 A
I = Required range of ammeter = 5 A
[tex]R_g[/tex] = Resistance of ammeter = 5 ohms
Therefore,
[tex]R_s = \frac{(0.02\ A)(5\ ohms)}{5\ A-0.02\ A}[/tex]
Rs = 0.02008 Ω = 20.08 mΩ
A bicycle wheel has a diameter of 63.4 cm and a mass of 1.86 kg. Assume that the wheel is a hoop with all of the mass concentrated on the outside radius. The bicycle is placed on a stationary stand and a resistive force of 123 N is applied tangent to the rim of the tire. What force is required if you shift to a 5.60-cm-diameter sprocket?
Answer:
Njfjrhrjrkrirkehrbrhrrhrhehrhrhejejebrbrhrbrbbbrhje
You could make an air purifier by pumping air through a region that has an electric field. What kinds of particles would you be able to remove with this machine
Answer:
We can remove ions and water molecules
Explanation:
We can remove ions and water molecules because both of them have an electric field . So this will help in repelling or attractive the above mentioned particles. Water is polar so it has an electric field due to net dipole moment.
The acceleration vector of a particle in uniform circular motion:___________
a) points outward from the center of the circle.
b) points toward the center of the circle.
c) is zero.
d) points along the circular path of the particle and opposite the direction of motion.
e) points along the circular path of the particle and in the direction of motion.
(B)
Explanation:
Centripetal means "towards the center" so the acceleration vector of an object undergoing UCM is always pointed towards the center.
The acceleration vector of a particle in a uniform circular motion points toward the center of the circle, The correct option is option (b).
Centripetal force is the force acting on an object in curvilinear motion directed towards the axis of rotation or center of curvature. The unit of centripetal force is Newton.
Centripetal means "towards the center" so the acceleration vector of an object undergoing circular motion is always pointed towards the center.
Therefore, The acceleration vector of a particle in a uniform circular motion points toward the center of the circle, The correct option is option (b).
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A negative point charge q1 = 25 nC is located on the y axis at y = 0 and a positive point charge q2 = 10 nC is located at y =14 cm. Find the y coordinate of the points where the net electric potential due to these two charges is zero.
Answer:
y = 0.1 m
Explanation:
The electrical power for point loads is
V = [tex]k \sum \frac{q_i}{r_i}[/tex]k Sum qi / ri
in this case
V = k ([tex]- \frac{q_1}{r_1 } + \frac{q_2}{r_2}[/tex])
indicate that V = 0
[tex]\frac{q_1}{r_1} = \frac{q_2}{r_2}[/tex]
r₂ = [tex]\frac{q_2}{q_1} r_1[/tex]
the distance r1 is
r₁ = y -0
the distance r2
r₂ = 0.14 -y
we substitute
0.14 - y = [tex]\frac{10}{25}[/tex] y
y ( [tex]\frac{10}{25} + 1[/tex]) = 0.14
y 1.4 = 0.14
y = 0.14 / 1.4
y = 0.1 m
Consider a wave along the length of a stretched slinky toy, where the distance between coils increases and decreases. What type of wave is this
"Longitudinal wave" is the wave where the difference between the coils increases as well as decreases.
Generating waves whenever the form of communication being displaced in a similar direction as well as in the reverse way of the wave's designated points, could be determined as Longitudinal waves.A wave running the length of something like a Slinky stuffed animal, which expands as well as reduces the spacing across spindles, produces a fine image or graphic.
Thus the above answer is correct.
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(b) If the object is at 330 feet and its instantaneous velocity is 3 feet per minute at 30 minutes, what is the approximate position of the object at 32 minutes
Answer:
The final position is 36 feet.
Explanation:
initial position, d = 330 feet
speed, v = 3 feet per minute
time, t = 30 minute
now the time is 32 minute
time interval = 2 minute
So, the distance in 2 minutes is
d' = 2 x 3 = 6 feet
So, the final position is
D = 30 + 6 = 36 feet
Do all substances conduct heat ?Why/ Why not ?
Answer:
no, all substances doesnot conduct heat
Answer:
No, all substances do not conduct heat easily because it depends on the nature of the substance. Some are good conductors of heat and some are bad. Therefore, it depends on their characteristics and their ability to conduct heat.
The bad conductors of heat are water, air, plastic, wood, etc.
Gold, Silver, Copper, Aluminium, Iron, etc. are good heat conductors as well as electrical conductors.
22) A driver traveling at 80 km/h brakes her 2000 kg truck to stop for a red light. How much internal energy is produced
Answer:
[tex]E=4.9\times 10^5\ J[/tex]
Explanation:
Given that,
The speed of a driver, v = 80 km/h = 22.22 m/s
The mass of the truck, m = 2000 kg
We need to find how much internal energy is produced. The internal energy produced by a truck is its kinetic energy and it is given by :
[tex]E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\cdot22.22^{2}\cdot2000\\\\E=493728.4\ J[/tex]
or
[tex]E=4.9\times 10^5\ J[/tex]
So, [tex]4.9\times 10^5\ J[/tex] of internal energy is produced.
4. Which of the following statements best describes the relationship
between mechanical, kinetic and potential energies of an object of mass
m kg that is thrown vertically upwards with in initial velocity of v. m/s.
A. Kinetic energy increases while potential energy decrease and mechanical
energy remains constant.
B. Kinetic energy decreases, while potential energy increases and mechanical
energy remains constant.
C. Both kinetic and potential energies decrease while mechanical energy
increases.
D. Both kinetic and potential energies increase while mechanical energy
remains constant.
(1)
21
Answer:
D
Explanation:
increase while mechanical energy remains constant
the product 17.10 ✕
Explanation:
pls write the full question
if a voltage v(t) = 150sinwt in volts at an operating frequency of 100hz. determine the I. dc value ii.rms value iii.period of the voltage signal
Answer:
(a) The dc value is 95.5 volts
(b) The rms value is 106.1 volts
(c) The period is 0.01s
Explanation:
Given
[tex]V(t) = 150\sin(wt)[/tex]
[tex]f = 100Hz[/tex]
Solving (a): The dc value
[tex]V(t) = 150\sin(wt)[/tex] implies that
[tex]V_{max} = 150[/tex]
So, the dc value is:
[tex]V = \frac{2}{\pi} * V_{max}[/tex]
[tex]V = \frac{2}{\pi} * 150[/tex]
[tex]V = \frac{300}{\pi}[/tex]
[tex]V = 95.5V[/tex]
Solving (b): The RMS value
This is calculated as:
[tex]V_{rms} = \frac{1}{\sqrt 2} * V_{max}[/tex]
So, we have:
[tex]V_{rms} = \frac{1}{\sqrt 2} * 150[/tex]
[tex]V_{rms} = \frac{150}{\sqrt 2}[/tex]
[tex]V_{rms} = 106.1V\\[/tex]
Solving (c): The period
This is calculated as:
[tex]T = \frac{1}{f}[/tex]
So, we have:
[tex]T = \frac{1}{100Hz}[/tex]
[tex]T = 0.01s[/tex]
How do hydrogen bonds affect boiling points?
A. Molecules with hydrogen bonds will have very high boiling points.
B. Molecules with hydrogen bonds will have very low boiling points.
C. Molecules with hydrogen bonds will have higher boiling points than molecules with dipole forces, but lower boiling points than molecules with van der Waals forces.
D. Boiling points are not affected by hydrogen bonds.
Reset Selection
▲ Question Progress ▲
Answer:
I would say A but am not sure
Option A. Molecules with hydrogen bonds will have very high boiling points.
What are hydrogen bonds?A hydrogen bond exists as an especially electrostatic force of attraction between a hydrogen atom which stands covalently bound to a more electromotive "donor" atom or group, and another electronegative atom carrying a lone pair of electrons—the hydrogen bond acceptor.
A hydrogen bond (or H-bond) exists as an especially electrostatic force of inducement between a hydrogen (H) atom which exists covalently bound to a more electronegative "donor" atom or group, and another electronegative atom maintaining a lone pair of electrons—the hydrogen bond acceptor (Ac).
Hydrogen bonding exists as a special kind of dipole-dipole attraction between molecules, not a covalent bond to a hydrogen atom. It results from the engaging force between a hydrogen atom covalently bonded to the same electronegative atom such as an N, O, or F atom and another very electronegative atom.
Molecules with hydrogen bonds will consistently have higher boiling points than also sized molecules that don't have an -O-H or an -N-H group. The hydrogen bonding creates the molecules "stickier," such that more heat (energy) exists needed to separate them.
Hence, Option A. Molecules with hydrogen bonds will have very high boiling points.
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What is the result of (305.120 + 267.443) x 0.50? How many answers can be written based on the principle of significant digits?
Answer:
The answer is 286.2815.
An upright cylindrical tank with radius 5 m is being filled with water at a rate of 2 m3/min. How fast is the height of the water increasing? (Round the answer to four decimal places.)
Answer:
The height of water increasing is 8.5 x 10^-4 m/s.
Explanation:
radius, r = 5 m
Volume per second, dV/dt = 2 m^3/min = 2/60 m^3/s
Let the height of cylinder is h.
The volume of the cylinder is given by
[tex]V = \pi r^2 h \\\\\frac{dV}{dt} = \pi r^2 \frac{dh}{dt}\\\\\frac{2}{30} = 3.14\times 5\times 5\times \frac{dh}{dt}\\\\\frac{dh}{dt}=8.5 \times 10^{-4} m/s[/tex]
A dog statue is standing in the bed of a pickup truck. The bed is coated with ice, causing the force of friction between the statue and the truck to be zero. The truck is initially at rest, and then accelerates to the right, moving along a flat road. As seen from a stationary observer (watching the truck move to the right), the dog statue Group of answer choices moves to the right, but not as quickly as the truck is moving to the right, causing it to slide towards the back of the truck. does not move left or right, but the back of the truck moves towards the statue. moves to the left, as the truck moves to the right, causing the statue to slide towards the back of the truck. moves to the right at the same rate as the truck, so it doesn't slide.
Answer:
Moves towards left
Explanation:
When the truck is moving towards right then there is pseudo force acting on the fog statue which is acting left wards.
A seen from the stationary observer, the dog statue moves towards left.
fraternity hazing is acceptable because it is an initational rite to the brotherhood
Answer:
that is the right answer
Explanation:
The deflection of a 160-cm-long beam in bending will be _____ times the deflection of an equivalent 120-cm-long beam.
0.75
2.37
1.33
1.78
0.56
0.42
Answer:
Number of time bend length = 1.33 (Approx.)
Explanation:
Given:
Length of beam = 160 centimeter
Length of beam after deflection = 120 centimeter
Find:
Number of time bend length
Computation:
Number of time bend length = Length of beam / Length of beam after deflection
Number of time bend length = 160 / 120
Number of time bend length = 1.33333
Number of time bend length = 1.33 (Approx.)
The deflection of a 160-cm-long beam in bending will be 1.33 times the deflection of an equivalent 120-cm-long beam.
Length of beam = 160 centimeter
Length of beam after deflection = 120 centimeter
The number of time bend length = Length of beam / Length of the beam after deflection.
Number of time bend length = 160 / 120
Number of time bend length = 1.33
What is deflecting?Deflecting is to turn (something) aside, especially from a direct path or fixed direction armor that deflects bullets deflecting attention from the troubled economy deflecting a question.
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Suppose 2.10 C of positive charge is distributed evenly throughout a sphere of 1.30-cm radius. 1) What is the charge per unit volume for this situation
Answer:
[tex]\rho=2.28\times 10^5\ C/m^3[/tex]
Explanation:
Given that,
Charge, Q = 2.1 C
The radius of sphere, r = 1.3 cm = 0.013 m
We need to find the charge per unit volume for this situation. It can be calculated a follows:
[tex]\rho=\dfrac{Q}{\dfrac{4}{3}\pi r^3}\\\\\rho=\dfrac{2.1}{\dfrac{4}{3}\pi \times (0.013)^3}\\\\\rho=2.28\times 10^5\ C/m^3[/tex]
So, the charge per unit volume is [tex]2.28\times 10^5\ C/m^3[/tex].
A spherical conductor of radius = 1.5 cm with a charge of 3.9 pC is within a concentric hollow spherical conductor of inner radius = 3 cm, and outer radius = 4 cm, which has a total charge of 0 pC. What is the magnitude of the electric field 2.3 cm from the center of these conductors?
Answer:
The answer is "66.351 N/C"
Explanation:
Given:
[tex]a=1.5\ cm= 1.5 \times 10^{-2}\ m\\\\q_1=3.9\ pc\\\\b=3\ cm\\\\c= 4\ cm\\\\q_2=0 \ pc\\\\[/tex]
Using Gauss Law:
[tex]\oint \vec{E} \cdot \vex{dA}= \frac{Q_{enc}}{\varepsilon_0 }[/tex]
[tex]E \times 4 \pi\ r^2=\frac{Q_{enc}}{\varepsilon_0}\\\\E= \frac{Q_{enc}}{4 \pi\ r^2 \varepsilon_0}= \frac{1}{4 \pi \varepsilon_0} \frac{Q_{enc}}{r^2}= \frac{k_e\ Q_{enc}}{r^2}\\\\[/tex]
[tex]=\frac{9\times 10^{9} \times 3.9 \times 10^{-12}}{(2.3\times 10^{-2})^2}\\\\=\frac{35.1\times 10^{-3}\ }{(2.3\times 10^{-2})^2}\\\\=\frac{35.1\times 10^{-3}\ }{5.29 \times 10^{-4}}\\\\=\frac{35.1\times 10 }{5.29 }\\\\=\frac{351}{5.29 }\\\\=66.351\ \frac{N}{C}[/tex]
A wire carrying a 30.0-A current passes between the poles of a strong magnet that is perpendicular to its field and experiences a 2.15-N force on the 4.00 cm of wire in the field. What is the average field strenth?
Answer:
1.79 T
Explanation:
Applying,
F = BILsin∅................ Equation 1
Where F = Force, B = magnetic field, I = current flowing through the wire, L = length of the wire, ∅ = angle between the magntic field and the force
make B the subject of the equation
B = F/ILsin∅............. Equation 2
From the question,
Given: F = 2.15 N, I = 30 A, L = 4.00 cm = 0.04 m, ∅ = 90° (perpendicular to the field)
Substitute these values into equation 2
B = 2.15/(30×0.04×sin90°)
B = 2.15/1.2
B = 1.79 T
Hence the average field strength is 1.79 T
A positive statement is:________. a. reflects oneâs opinions. b. can be shown to be correct or incorrect. c. a value judgment. d. based upon an optimistic judgment.
Answer:
b
Explanation:
A spaceship travels 360km in one hour. Express its speed in m/s
Answer:
Spaceship speed is 36000 km/h
So, in 1 hour spaceship travel 36000 km
Or we can say that in 60×60 second spaceship travel 36000 km
Therefore in 1 sec spaceship travel
=
= 10 km/s
Answer:
Explanation:
360 km/hr(1000 m/km) / 3600 s/hr) = 100 m/s
The airplane hits even worse turbulence and you find yourself pinned against the ceiling of the airplane by a force of 100 N. What is the vertical acceleration vector of the airplane
Answer:
The correct answer is "12 m/s²".
Explanation:
Given:
[tex]F_{app} = 100 \ N[/tex]
As we know,
⇒ [tex]F_{app} = mg-ma[/tex]
Or,
⇒ [tex]a = g-(\frac{F_{app}}{m} )[/tex]
By substituting the values, we get
⇒ [tex]=10-(-\frac{100}{50} )[/tex]
⇒ [tex]=10+2[/tex]
⇒ [tex]=12 \ m/s^2[/tex]
Determinar el flujo de calor a través del piso de losa cuyas medidas 3 X 5 cm y temperaturas superficiales son -20 ºC y 40 ºC, la conductividad térmica del material es de 1,6 X 10 -3 cal/cm s ºC y su espesor es de 10 cm durante 1 hora.
Una aluminio de 12 cm de grosor, pero están perfectamente aislados en las demás paredes. Cada cuarto es un cubo de 4,0 m de arista. Si el aire de uno de los cuartos está a 10 ºC y el otro a 30 ºC. ¿Cuántos calor se conduce durante dos minutos? 1,7X 10 -4 cal/ cm s ºC
Una pared de asbesto de 0,15 cm de espesor 1400°C y 1150 ºC en las superficies interna y externa, respectivamente. ¿Cuál es la perdida de calor a través de una pared que tiene 0,5 m por 3 m de lado, en un tiempo de minuto y medio?
!!!!!!NESECITO AYUDA¡¡¡¡¡
Answer:
0,0560 cal / gºC.
The current loop lies flat on a horizontal surface. Facing the loop from the top, the current moves in a clockwise direction. Which way does the magnetic field point outside the loop?
a) The field points down.
b) The field points down.
c) The field points to the left.
d) The field points up
e) The field points to the right
Answer:
e
Explanation:
the field points to the right
If loop is kept horizontally and direction of current is clockwise , then according to Fleming’s Left Hand Rule the direction of magnetic field will be towards right .
What is Fleming’s Left Hand Rule ?
Fleming’s Left Hand Rule states that if we arrange our thumb, forefinger and middle finger of the left-hand perpendicular to each other, then the thumb points towards the direction of the force experienced by the conductor, the forefinger points towards the direction of the magnetic field and the middle finger points towards the direction of the electric current.
If loop is kept horizontally and direction of current is clockwise , then according to Fleming’s Left Hand Rule the direction of magnetic field will be towards right .
correct answer e) The field points to the right
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The electric power delivered to your home has 110 Volts.
All outlets in your kitchen are connected in parallel.
You always have the lights on for 660 Watts, the toaster has a resistance of 440 Ohms, the stove uses power at the rate of 2200 Watts, and the Blender has a resistance of 220 Ohms.
If all these appliances are running at he same time how much total current are you using?
Answer:
I = 26.80 A
Explanation:
From Ohm's law,
V = IR ............ 1
P = IV ............ 2
where V is the value of the voltage, I is the current, R is the resistance and P is the power.
i. The power of light switched on = 660 Watts.
ii. The power of the toaster = [tex]\frac{V^{2} }{R}[/tex]
= [tex]\frac{(110)^{2} }{440}[/tex]
= 27.5 Watts
iii. The power of the stove = 2200 Watts.
iv. The power of the blender = [tex]\frac{V^{2} }{R}[/tex]
= [tex]\frac{(110)^{2} }{220}[/tex]
= 55 Watts
Total power of the appliances = 660 + 27.5 + 2200 + 55
= 2942.5 Watts
So that,
P = IV
I = [tex]\frac{P}{V}[/tex]
= [tex]\frac{2942.5}{110}[/tex]
= 26.75
I = 26.75 A
The total current being used when all the appliances are running at the same time is 26.80 A.
A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 13 A, while that of the vacuum cleaner is 4.8 A. Determine the power consumed by (a) the blow-dryer and (b) the vacuum cleaner. (c) Determine the ratio of the energy used by the blow-dryer in 15 minutes to the energy used by the vacuum cleaner in 40 minutes.
Answer:
(a) 1560 W
(b) 576 W
(c) 1.01
Explanation:
Voltage, V = 120 V
Current in dryer, I = 13 A
current in vacuum cleaner, i' = 4.8 A
(a) Power consumed by dryer,
P = V I = 120 x 13 = 1560 W
(b) Power consumed by vacuum cleaner
P' = V I' = 120 x 4.8 = 576 W
(c) Energy consumed by dryer
E = P x t = 1560 x 15 x 60 = 1404000 J
Energy consumed by the vacuum cleaner
E' = P' x t' = 576 x 40 x 60 = 1382400 J
the ratio of energies is
E : E' = 1404000 : 1382400 = 1.01
