An arch is in the form of a parabola given by the function h = -0.06d^2 + 120, where the origin is at ground level, d meters is the horizontal distance and h is the height of the arch in meters.
Graph this function on your graphing calculator then complete the following statements.
The height of the arch is: ------- m
The width to the nearest meter, at the base of the arch is ------ m

Answers

Answer 1

Answer:

See attachment for graph

The height of the arch is: 120 m

The width to the nearest meter, at the base of the arch is 22 m

Step-by-step explanation:

Given

[tex]h = -0.06d^2 + 120[/tex]

Solving (a): The graph

See attachment for graph

Variable h is plotted on the vertical axis while variable d is plotted on the horizontal axis.

Solving (b): The height

The curve of [tex]h = -0.06d^2 + 120[/tex] opens downward. So, the maximum point on the vertical axis represents the height of the arch,

Hence:

[tex]height = 120[/tex]

Solving (c): The width

The curve touches the horizontal axis at two different points.

[tex]x_1 = -11[/tex]

[tex]x_2 = 11[/tex]

The absolute difference of both points represents the width.

So:

[tex]Width = |x_2 - x_1|[/tex]

[tex]Width = |11 - -11|[/tex]

[tex]Width = |11 +11|[/tex]

[tex]Width = |22|[/tex]

Hence:

[tex]Width = 22[/tex]

An Arch Is In The Form Of A Parabola Given By The Function H = -0.06d^2 + 120, Where The Origin Is At

Related Questions

if 7a - 11b = 0, what will be the value of a:b​

Answers

Answer:

11:7

Step-by-step explanation:

Solution

Here

7a-11b=0

a:b=?

we know that

a=7

b=11

ans =11:7

Hence proved

Answer:

[tex]thank \: you[/tex]

An electronic switching device occasionally malfunctions, but the device is considered satisfactory if it makes, on average, no more than 0.20 error per hour. A particular 5-hour period is chosen for testing the device. If no more than 1 error occurs during the time period, the device will be considered satisfactory.
(a) What is the probability that a satisfactory device will be considered unsatisfactory on the basis of the test? Assume a Poisson process.
(b) What is the probability that a device will be accepted as satisfactory when, in fact, the mean number of errors is 0.25? Again, assume a Poisson process.

Answers

Solution :

It is given that the device works satisfactorily if it makes an average of no more than [tex]0.2[/tex] errors per hour.

The number of errors thus follows the Poisson distribution.

It is given that in [tex]5[/tex] hours test period, the number of the errors follows is

= [tex]0.2 \times 5[/tex]

= 1 error

Let X = the number of the errors in the [tex]5[/tex] hours

[tex]$X \sim \text{Poisson } (\lambda = 0.2 \times 5 =1)$[/tex]

Now that we want to find the [tex]\text{probability}[/tex] that a [tex]\text{satisfactory device}[/tex] will be misdiagnosed as "[tex]\text{unsatisfactory}[/tex]" on the basis of this test. We know that device will be unsatisfactory if it makes more than [tex]1[/tex] error in the test. So we will determine probability that X is greater than [tex]1[/tex] to get required answer.

So the required probability is :

[tex]P(X>1)[/tex]

[tex]$=1-P(X \leq 1)$[/tex]

[tex]$=1-[P(X=0)+P(X=1)]$[/tex]

[tex]$=1- \left( \frac{e^{-1} 1^0}{0!} + \frac{e^{-1} 1^0}{1!} \right) $[/tex]

[tex]$=1-(2 \times e^{-1})$[/tex]

[tex]$=1-( 2 \times 0.367879)$[/tex]

[tex]$=1-0.735759$[/tex]

[tex]=0.264241[/tex]

So the [tex]\text{probability}[/tex] that the [tex]\text{satisfactory device}[/tex] will be misdiagnosed as "[tex]\text{unsatisfactory}[/tex]" on the basis of the test whose result is 0.264241

−5x−9y=3 added to 5x−9y=−2


Answers

Answer:

the 5s cancel out the -9s become -18y and 3-2 is 1

Step-by-step explanation:

so -18y=1

Answer From Gauth Math

find the value of x. help with geometry pls

Answers

Answer:

Find the value of x:-

To find Y, use Pythagorean theorem:- [tex]c^{2} =a^{2} +b^{2}[/tex]

[tex](2.1)^{2} =y^{2} +(1.4)^{2}[/tex]

[tex]2.1^{2}=4.41[/tex]

[tex]1.4^{2} =1.96[/tex]

[tex]4.41=y^{2} +1.96[/tex]

subtract 1.96 from both sides

[tex]2.45=y^{2}[/tex]

[tex]y=1.5652[/tex]

Now, to find x:-

[tex]x=y+y[/tex]

[tex]= 1.5632+1.5652[/tex]

[tex]x=3.1 \: ft[/tex]

~OAmalOHopeO

Which one of the following graphs is the graph of f(x) = 1∕4x2 + 3?

Answers

Answer:

A

f(x) = 1/4 x^2 + 3

Resultado

f(x) = x^2/4 + 3

x^2 + 12 = 4 f(x)

Forma alternativa

f(x) = 1/4 (x^2 + 12)

Raíces complejas

x = -2 i sqrt(3)

x = 2 i sqrt(3)

Write the equation of the trigonometric graph

Answers

Answer:

y = sin(4(x+π/8)) + 1

Step-by-step explanation:

For a trigonometric equation of form

y = Asin(B(x+C)) + D,

the amplitude is A, the period is 2π/B, the phase shift is C, and the vertical shift is D (shifts are relative to sin(x) = y)

First, the amplitude is the distance from the center to a top/bottom point (also known as a peak/trough respectively). The center of the function given is at y=1, and the top is at y=2, Therefore, 2-1= 1 is our amplitude.

Next, the period is the distance between one peak to the next closest peak, or any matching point to the next matching point. One peak of this function is at x=0 and another is at x= π/2, so the period is (π/2 - 0) = π/2. The period is equal to 2π/B, so

2π/B  = π/2

multiply both sides by b to remove a denominator

2π = π/2 * B

divide both sides by π

2 = 1/2 * B

multiply both sides by 2 to isolate b

4 = B

After that, the phase shift is the horizontal shift from sin(x). In the base function sin(x), one center is at x=0. However, on the graph, the closest centers to x=0 are at x=± π/8. Therefore, π/8 is the phase shift.

Finally, the vertical shift is how far the function is shifted vertically from sin(x). In sin(x), the centers are at y=0. In the function given, the centers are at y=1, symbolizing a vertical shift of 1.

Our function is therefore

y = Asin(B(x+C)) + D

A = 1

B = 4

C = π/8

D = 1

y = sin(4(x+π/8)) + 1

Answer(s):

[tex]\displaystyle y = sin\:(4x + \frac{\pi}{2}) + 1 \\ y = -cos\:(4x \pm \pi) + 1 \\ y = cos\:4x + 1[/tex]

Explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{8}} \hookrightarrow \frac{-\frac{\pi}{2}}{4} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\frac{\pi}{2}} \hookrightarrow \frac{2}{4}\pi \\ Amplitude \hookrightarrow 1[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = sin\:4x + 1,[/tex] in which you need to replase “cosine” with “sine”, then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{8}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACK [tex]\displaystyle \frac{\pi}{8}\:unit,[/tex] which means the C-term will be negative, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{8}} = \frac{-\frac{\pi}{2}}{4}.[/tex] So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = sin\:(4x + \frac{\pi}{2}) + 1.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [0, 2],[/tex] from there to [tex]\displaystyle [\frac{\pi}{2}, 2],[/tex] they are obviously [tex]\displaystyle \frac{\pi}{2}\:unit[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \frac{\pi}{2}.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex] in which each crest is extended one unit beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

√10 Multiple √15 is equal to

(a) 6√5

(b) √30

(c) √25






step by step








Solve :-​

dont answer stantham​

Answers

[tex]\\ \sf\longmapsto \sqrt{10}\times \sqrt{15}[/tex]

[tex]\\ \sf\longmapsto \sqrt{10\times 15}[/tex]

[tex]\\ \sf\longmapsto \sqrt{2\times 5\times 3\times 5}[/tex]

[tex]\\ \sf\longmapsto \sqrt{5\times 5\times 6}[/tex]

[tex]\\ \sf\longmapsto 5\sqrt{6}[/tex]

None of the above should be 4th option

Given: AABC, AC = 5
m C = 90°
m A= 22°
Find: Perimeter of AABC
A
C
B

Answers

9514 1404 393

Answer:

  perimeter ≈ 12.4 units

Step-by-step explanation:

The side adjacent to the angle is given. The relationships useful for the other two sides are ...

  Tan = Opposite/Adjacent

  Cos = Adjacent/Hypotenuse

From these, we have ...

  opposite = 5·tan(22°) ≈ 2.02

  hypotenuse = 5/cos(22°) ≈ 5.39

Then the perimeter is ...

  P = a + b + c = 2.02 + 5 + 5.39 = 12.41

The perimeter of ∆ABC is about 12.4 units.

Find the 100th term of the sequence 4, 7, 10, 13...

a) 301
b) 313
c) 281
d) 279

Answers

Answer:

A

Step-by-step explanation:

The first term of the sequence is 4, the common difference is 3. So the equation of this sequence is 4+(n-1)*3 or 1+3*n. Plug in n=100

3 coins Priya spends $45 on gas, $10 on dinner, and $8 on a video game. How much money did Priya spend on variable expenses?​

Answers

Answer:

3x=63

Step-by-step explanation:

3 coins means a coin is x and total expenditure is equal to 63

Question Which of the following is a benefit of using email to communicate at work ? a) You can express yourself in a limited number of characters b) You don't have to worry about using proper grammar. c) You always get a response right away. d ) You can reach a large audience with one communication .

Answers

Answer:

d) you can reach a large audience with one communication

Step-by-step explanation:

common sense

a car completes a journey in 8hours it covers half the distance at 40kms per hours and the rest at 60 km per hour. what is the total distance of the journey?​

Answers

Answer:

384 kmph

Step-by-step explanation:

Identify the decimals labeled with letters A B and C on the scale

Answers

Answer:

A. 37.39 B. 37.41 C. 37.27

Please help me with this, But I can’t decide if it’s A or B. Please explain !!!

Answers

I think it's the letter A.

Answer:

[tex]m=\frac{M}{\sqrt{1-\frac{v^{2} }{c^{2} } } } \\\\\\m{\sqrt{1-\frac{v^{2} }{c^{2} } }=M[/tex]

[tex]\sqrt{1-\frac{v^{2} }{c^{2} }} =\frac{M}{m} \\\\\\1-\frac{v^{2} }{c^{2} }=\frac{M^{2}}{m^{2}} \\\\\\-\frac{v^{2} }{c^{2} }=\frac{M^{2}}{m^{2}} -1\\\\v^{2}=(-c^{2}) (\frac{M^{2}}{m^{2}} -1)\\\\v=\sqrt{(-c^{2}) (\frac{M^{2}}{m^{2}} -1)} =\sqrt{(c^{2})(-1)(\frac{M^{2}}{m^{2}} -1)} =c\sqrt{(-1)(\frac{M^{2}}{m^{2}} -1)} =c\sqrt{1-\frac{M^{2}}{m^{2}}}[/tex]

I would think it's A ¯\_ (ツ)_/¯

(x
3
+y
3
)(xy
4
+7)

Answers

Answer:

question is not proper

Step-by-step explanation:

question is

.2333 repeating as a fraction

Answers

Answer and Step-by-step explanation:

0.2333...

First, multiply the number by 10 (because there is 1 number being repeated.

2.333.....

Now subtract by the original number.

   2.333...  

-   0.2333...

   2.10

Write this as an equation:

(10 x fraction) - fraction = 2.1           (10 x fraction) - fraction = 9 x fraction

9 x fraction = 2.1  (Divide both sides by 9)

[tex]\frac{2.1}{9}[/tex] = [tex]\frac{7}{30}[/tex]

[tex]\frac{7}{30}[/tex] is the answer.

(To check, do 7 divided by 30 in a calculator, and you will get 0.233 repeating)

#teamtrees #PAW (Plant And Water)

I hope this helps!

Kinsey has a plan to save $60 a month for 16 months so that she can purchase a new television. After 11 months Kinsey has saved $600. If the most that Kinsey can possibly save is $80 per month, which of the following statements is true? a. Kinsey will meet her goal and does not need to adjust her plan. b. Kinsey must save $72 per month to achieve her goal. c. Kinsey must save $75 per month to achieve her goal. d. Kinsey will not be able to achieve her goal. Please select the best answer from the choices provided A B C D

Answers

Answer:

b. Kinsey must save $72 per month to achieve her goal.

Step-by-step explanation:

Goal over 16 months: $60 x 16 = $960

Collected after 11 months: $600

$360 still needed5 months lefts

$360 ÷ 5 = $72

Kinsey must save $72 per month to achieve her goal. The answer we got by converting the sentence to Equation and solving.b is the required answer.

Kinsey has a plan to save $60 a month for 16 months so that she can purchase a new television. After 11 months Kinsey has saved $600. If the most that Kinsey can possibly save is $80 per month, which of the following statements given is true.

What is an Equation?

Two expressions with equal sign is called equation.

Goal over 16 months: $60 x 16 = $960

Collected after 11 months: $600

$360 still needed

5 months lefts

$360 ÷ 5 = $72

Therefore Kinsey must save $72 per month to achieve her goal.

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Evaluate the line integral
Soydx + zdy + xdz,
[»= f (t)=dw= f'(t)dt
where C is the parametric curve
x=t, y=t, z=ť, Ost<1.

Answers

It looks like you're asked to compute

[tex]\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz[/tex]

where C is parameterized by ⟨t, t, t⟩ with 0 ≤ t ≤ 1.

In other words, x = y = z = t, so dx = dy = dz = dt, and the integral reduces to

[tex]\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz = \int_0^1 t\,\mathrm dt + t\,\mathrm dt + t\,\mathrm dt \\\\ = 3 \int_0^1 t\,\mathrm dt \\\\ =\frac32t^2\bigg|_{t=0}^{t=1} \\\\ =\boxed{\frac32}[/tex]

Complete the coordinate table for the given equation.
Xy=-4

Answers

Step-by-step explanation:

X= -4,-2,2,4 (respectively)

Y=4,-4 (respectively)

hope it helps

3. Find the least common denominator for the group of denominators using the method of prime numbers. 45, 75, 63​

Answers

We have to find LCM

3 | 45,75,63

3 | 15,25,21

5 | 5,25,7

5 | 1,5,7

7 | 1,1,7

LCM=3×3×5×5×7=1575

The least common denominator for the group of denominators using the method of prime numbers is 1575.

What is least common multiple?

LCM stands for Least Common Multiple. It is a method to find the smallest common multiple between any two or more numbers.  A factor is one of the numbers that multiplies by a whole number to get that number.

For the given situation,

The numbers are 45, 75, 63​

Prime factors of 45 = [tex]3,3,5[/tex]

Prime factors of 75 = [tex]3,5,5[/tex]

Prime factors of 63 = [tex]3,3,7[/tex]

Then the LCM can be found by, first take the common factors then multiple the remaining factors as,

⇒ [tex](3)(3)(5)(5)(7)[/tex]

⇒ [tex]1575[/tex]

Hence we can conclude that the least common denominator for the group of denominators using the method of prime numbers is 1575.

Learn more about least common multiple here

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Which subset(s) of numbers does 5 3/8 belong to ?

Answers

Answer:

Rational number

Step-by-step explanation:

Given

[tex]5\frac{3}{8}[/tex]

Required

The subset it belongs to

Express as improper fraction

[tex]5\frac{3}{8} = \frac{43}{8}[/tex]

The above number is rational because it is represented by the division of 2 integers, i.e. 43 and 8 are integers

Express as decimals

[tex]5\frac{3}{8} = 5.375[/tex]

The above number cannot be classified as integers or whole because it has decimal parts

Express the speed of 0.0000000015 seconds in scientific notation

Answers

[tex]\\ \sf\longmapsto 0.0000000015[/tex]

[tex]\\ \sf\longmapsto 0.0015\times 10^{-6}s[/tex]

[tex]\\ \sf\longmapsto 0.015\times 10^{-7}s[/tex]

[tex]\\ \sf\longmapsto 0.15\times 10^{-8}s[/tex]

[tex]\\ \sf\longmapsto 1.5\times 10^{-9}s[/tex]

Answer: 0.0000000015 = 1.5 × 10⁻⁹

Concept:

When converting an integer to scientific notation:

- If the number is ≥1, then count the moves of the decimal point to the right until the number is 0<number<10. The number of moves will be the exponent that is positive.

- For example: If converting 300, since there are two moves until it is left with 0<3<10. Thus, the scientific notation will be 3 × 10²

- If the number is <1, then count the moves of the decimal point to the left until the number is 0<number<10. The number of moves will be the exponent that is negative.

- For example: If converting 0.004, since there are three moves until it is left with 0<4<10. Thus, the scientific notation will be 4 × 10⁻³

Solve:

0.0000000015

The decimal point needs to move 9 times to the left to get a number that is between 0 and 10. The number is 1.5.

Thus, the scientific notion of 0.0000000015 will be 1.5 × 10⁻⁹

Hope this helps!! :)

Please let me know if you have any questions

a certain number plus two is five find the number​

Answers

x=3

Step-by-step explanation:

x+2=5

x=5-2

x=3

Question 6 of 11 Step 1 of 6 No Time Limit The table below gives the list price and the number of bids received for five randomly selected items sold through online auctions. Using this data, consider the equation of the regression line, û = bo + bjx, for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.
Price in Dollars 23 34 44 46 50
Number of Bids 1 2 4 9 10
Step 1 of 6: Find the estimated slope. Round your answer to three decimal places.​

Answers

The estimated slope is approximately 2.344

The given table is presented as follows;

[tex]\begin{array}{ccc}Number \ of Bids &&Price \ in \ Dollars\\1&&23\\2&&34\\4&&44\\9&&46\\10&&50\end{array}[/tex]

The regression line formula to be considered = [tex]\bar u = b_0 + b\cdot \bar x[/tex]

The required parameter is;

The estimated slope

The method to find the estimate slope;

The least squares regression formula (method) is presented as follows;

[tex]\bar u = b_0 + b\cdot \bar x[/tex]

Where;

b₀ = The y-intercept

[tex]\mathbf{ b = \dfrac{\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right) }{\sum \left(x_i - \bar x\right )^2 } = The \ estimated \ slope}[/tex]

From MS Excel, we have;

[tex]\bar x[/tex] = 5.2, [tex]\bar u[/tex] = 39.4

[tex]\sum \left(x_i - \bar x\right) \times \left(u_i - \bar u\right)[/tex] = 156.6

[tex]{\sum \left(x_i - \bar x\right )^2 }[/tex] = 66.8

Therefore;

The estimated slope, b = 156.6/66.8 ≈ 2.344 (by rounding the answer to three decimal places)

Learn more about regression line here;

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(X^2 + 6x + 8) divided (x + 2)

Answers

Answer:

x+ 4

Step-by-step explanation:

      ____x__+4___

x+2 | [tex]x^2 + 6x + 8[/tex]

        [tex]x^2 + 2x[/tex]

        ------------

                [tex]4x + 8\\[/tex]

                 [tex]4x + 8\\[/tex]

                  --------

                     0

Answer:

x+4

Step-by-step explanation:

a. 1140
b. 1130
c. 1120
d. 115

Answers

Answer:

1130

Step-by-step explanation:

1109+7 = 1116

1116+7 = 1123

Adding 7 each time

1123+7 = 1130

Knowing that AQPT = AARZ, a congruent side pair is:

Answers

Answer:

A. QT ≅ AZ

Step-by-step explanation:

When writing a congruence statement of two triangles, the order of arrangement of the letters used in naming the triangles are carefully considered. Corresponding sides and angles of both triangles are arranged accordingly in the order they appear.

Given that ∆QPT ≅ ∆ARZ, we have the following sides that correspond and are congruent to each other:

QP ≅ AR

PT ≅ RZ

QT ≅ AZ

The only correct one given in the options given above is QT ≅ AZ

Find the slope of the line passing through the points (9, 1) and (9,-4).

Answers

Answer:

slope is undefined

Step-by-step explanation:

(9, 1 ) and (9, - 4 )

Since the x- coordinates of the 2 points are 9, then the line is vertical and parallel to the y- axis with slope being undefined.

Slope is the change in y over the change in x.

Slope = (-4 - 1) / (9 -9) = -5/0 you cannot divide by 0,so the slope is undefined. This means it is a vertical line

Lynbrook West, an apartment complex, has 100 two-bedroom units. The monthly profit (in dollars) realized from renting out x apartments is given by the following function. p(x)=-12x^2+2160x-59000 To maximize the monthly rental profit, how many units should be rented out? units What is the maximum monthly profit realizable?

Answers

Answer:

To maximize the monthly rental profit, 90 units should be rented out.

The maximum monthly profit realizable is $38,200.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

[tex]f(x) = ax^{2} + bx + c[/tex]

It's vertex is the point [tex](x_{v}, y_{v})[/tex]

In which

[tex]x_{v} = -\frac{b}{2a}[/tex]

[tex]y_{v} = -\frac{\Delta}{4a}[/tex]

Where

[tex]\Delta = b^2-4ac[/tex]

If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]y_{v}[/tex].

In this question:

Quadratic equation with [tex]a = -12, b = 2160, c = -59000[/tex]

To maximize the monthly rental profit, how many units should be rented out?

This is the x-value of the vertex, so:

[tex]x_{v} = -\frac{b}{2a} = -\frac{2160}{2(-12)} = \frac{2160}{24} = 90[/tex]

To maximize the monthly rental profit, 90 units should be rented out.

What is the maximum monthly profit realizable?

This is p(90). So

[tex]p(90) = -12(90)^2 + 2160(90) - 59000 = 38200[/tex]

The maximum monthly profit realizable is $38,200.

Simplify the following expression.

3(2k + 3) -8k + 5 + 5

Answers

Answer:

Step-by-step explanation:

3*(2k + 3) - 8k + 5 + 5           Remove the brackets on the left

6k + 9 - 8k + 5 + 5                Combine like terms

6k-8k+9 + 5 + 5

-2k + 19

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