Answer:
3.5 cm
Step-by-step explanation:
v = πr²h
r = radius
π = 22/7
h = height
192.5 = 22/7 x 5 x r²
divide both sides of the equation by (7/22 x 1/5)
192.5 x 7/22 x 1/5 = r²
r² = 12.25
find the square root of both sides
r = 3.5cm
Given the a center (-1, -2) and a radius r = 2. Identify the circle.
Answer:
1st option
1st graph has the centre on (-1,-2) and the distance of the circumference from the centre is 2
Answered by GAUTHMATH
Deion is saving up to buy a new phone. He already has $95 and can save an additional $7 per week using money from his after school job. How much total money would Deion have after 6 weeks of saving? Also, write an expression that represents the amount of money Deion would have saved in w weeks.
The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137.
What is an expression?A statement expressing the equality of two mathematical expressions is known as an equation.
A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.
An expression is a mathematical proof of the equality of two mathematical expressions.
As per the given,
Initial fixed money = $95
Per week saving $7/week
Total money = fixed money + money in w weeks.
⇒ 95 + 7w
For 6 weeks, w = 6
⇒ 95 + 7× 6 = $137.
Hence "The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137".
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Which could be the first step in simplifying this expression? Check all that apply.
Answer:
[tex](x^{-3})^2[/tex]
Step-by-step explanation:
applying the exponent rule to the inside of the bracket, x^3 x x^-6 = x^-3 since you add the exponents
pls help me asap !!!!
Answer:
9--7
Step-by-step explanation:
PLEASE HELP, solve for X
Answer:
27
Step-by-step explanation:
(whole secant) x (external part) = (tangent)^2
(48+x) * 48 = 60^2
(48+x)48=3600
Divide each side by 48
48+x =75
Subtract 48
48+x-48 = 75-48
x =27
With the aid of an illustrative example, discuss the relationship between the area of a region and the definite integral. *
Suppose there is a function f(x), the definite integral of the function is the difference between the upper and lower x-values.
There are three relationships between the definite integral and the area of the region. The relationships are:
Positive functionNegative functionRegion between two functionsPositive function
The area between the function itself and the x-axis represents the definite integral.
Negative function
The area between the function itself and the x-axis, multiplied by -1 represents the definite integral.
Region between two functions
The definite integral of the function is the difference between the region of both functions.
See attachment for further illustration
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Chris drives 240 miles from his home in Atlanta, Georgia, at 60 miles per hour. How many minutes longer would the return trip take if he travels at 50 miles per hour
Answer:
48 minutes
240 at 60mph = 4 hrs.
240 at 50 mph = 4.8 hrs.
it would take an extra 60*.8 or 48 minutes
Step-by-step explanation:
The trip will be of 48 minutes longer when the speed is decreased by 10 miles per hour.
What is the formula for time?
The time is given by distance/speed. The unit of time is minutes or seconds.
What will be the time difference?When distance of 240 miles is cover by the speed of 60 miles per hour then the time take to travel this distance will be 240/60=4 hours
When distance of 240 miles is cover by the speed of 50 miles per hour then the time take to travel this distance will be 240/50=4.8 hours
The difference between 4.8 hours and 4 hours is of 0.8 hours or 0.8*60=48 minutes.
Therefore, the trip will be of 48 minutes longer.
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Factorize :solve no g and h
Answer:
Hello,
do you mean factorise but not solve ?
Just one formula:
[tex]\boxed{a^2-b^2=(a-b)(a+b)}[/tex]
Step-by-step explanation:
[tex]g)\\\\16x^3y-81xy^5\\\\=xy(16x^2-81y^4)\\\\=xy(4x^2+9y^2)(4x^2-9y^2)\\\\=xy(2x-3y)(2x+3)(4x^2+9y^2)\\\\\\\\h)\\\\x^8-y^8\\\\=(x^4+y^4)(x^4-y^4)\\\\=(x^4+y^4)(x^2+y^2)(x^2-y^2)\\\\=(x-y)(x+y)(x^2+y^2)(x^4+y^4)\\[/tex]
Answer:
here only one formula to use in both question
a^2+b^2= (a+b)(a-b)
i need help with this question pls! :)
Hi there!
[tex]\large\boxed{\text{9 quarters}}[/tex]
We can let x = dimes and y = quarters.
We know that one dime = $0.10 and a quarter = $0.25, so:
$3.05 = $0.10x + $0.25y
And:
17 = x + y
Solve the system of equations. We can rearrange the bottom equation to create an expression equal to y:
17 - x = y
Substitute this into the top equation for y:
3.05 = 0.10x + 0.25(17 - x)
Distribute and simplify:
3.05 = 0.10x + 4.25 - 0.25x
3.05 = 4.25 - 0.15x
Solve for x:
-1.2 = -0.15x
x = 8
Find y using the above expression:
17 - 8 = y
y = 9
Calculus!
The volume of a substance, A, measured in cubic centimeters increases according to the exponential growth model dA/dt = 0.3A, where t is measured in hours. The volume of another substance, B, also measured in cubic centimeters increases at a constant rate of 1 cm^3 per hour according to the linear model dB/dt = 1. At t = 0, substance A has a volume A(0) = 3 and substance B has size B(0) = 5. At what time will both substances have the same volume?
Would it be correct to write the growth model of substance B as x + 5? And how could I write the growth model of substance A? Thank you in advance, and sorry for the poor formatting.
Answer:
The two substances will have the same volume after approximately 3.453 hours.
Step-by-step explanation:
The volume of substance A (measured in cubic centimeters) increases at a rate represented by the equation:
[tex]\displaystyle \frac{dA}{dt} = 0.3 A[/tex]
Where t is measured in hours.
And substance B is represented by the equation:
[tex]\displaystyle \frac{dB}{dt} = 1[/tex]
We are also given that at t = 0, A(0) = 3 and B(0) = 5.
And we want to find the time(s) t for which both A and B will have the same volume.
You are correct in that B(t) is indeed t + 5. The trick here is to multiply both sides by dt. This yields:
[tex]\displaystyle dB = 1 dt[/tex]
Now, we can take the integral of both sides:
[tex]\displaystyle \int 1 \, dB = \int 1 \, dt[/tex]
Integrate. Remember the constant of integration!
[tex]\displaystyle B(t) = t + C[/tex]
Since B(0) = 5:
[tex]\displaystyle B(0) = 5 = (0) + C \Rightarrow C = 5[/tex]
Hence:
[tex]B(t) = t + 5[/tex]
We can apply the same method to substance A. This yields:
[tex]\displaystyle dA = 0.3A \, dt[/tex]
We will have to divide both sides by A:
[tex]\displaystyle \frac{1}{A}\, dA = 0.3\, dt[/tex]
Now, we can take the integral of both sides:
[tex]\displaystyle \int \frac{1}{A} \, dA = \int 0.3\, dt[/tex]
Integrate:
[tex]\displaystyle \ln|A| = 0.3 t + C[/tex]
Raise both sides to e:
[tex]\displaystyle e^{\ln |A|} = e^{0.3t + C}[/tex]
Simplify:
[tex]\displaystyle |A| = e^{0.3t} \cdot e^C = Ce^{0.3t}[/tex]
Note that since C is an arbitrary constant, e raised to C will also be an arbitrary constant.
By definition:
[tex]\displaystyle A(t) = \pm C e^{0.3t} = Ce^{0.3t}[/tex]
Since A(0) = 3:
[tex]\displaystyle A(0) = 3 = Ce^{0.3(0)} \Rightarrow C = 3[/tex]
Therefore, the growth model of substance A is:
[tex]A(t) = 3e^{0.3t}[/tex]
To find the time(s) for which both substances will have the same volume, we can set the two functions equal to each other:
[tex]\displaystyle A(t) = B(t)[/tex]
Substitute:
[tex]\displaystyle 3e^{0.3t} = t + 5[/tex]
Using a graphing calculator, we can see that the intersect twice: at t ≈ -4.131 and again at t ≈ 3.453.
Since time cannot be negative, we can ignore the first solution.
In conclusion, the two substances will have the same volume after approximately 3.453 hours.
Help me quick i need helppp
[tex]\\ \sf\longmapsto (m-8)+(m-8)+(m-8)+(m-8)+(m-8)+(m-8)=12[/tex]
[tex]\\ \sf\longmapsto 6(m-8)=12[/tex]
[tex]\\ \sf\longmapsto 6m-48=12[/tex]
[tex]\\ \sf\longmapsto 6m=12+48[/tex]
[tex]\\ \sf\longmapsto 6m=60[/tex]
[tex]\\ \sf\longmapsto m=\dfrac{60}{6}[/tex]
[tex]\\ \sf\longmapsto m=10[/tex]
Answer:
M=14
Step-by-step explanation:
First make an equation - m÷6 =8Then shift 6 to 8 - m=6×8Answer - m=14Determine the period
Answer:
16 units
Step-by-step explanation:
period = length of an interval that contains exactly one copy of the repeating pattern, so from one peak to another peak.
in this graph its the peaks are 1 and 17, hence the period is 16
maths class 9
Multiply: 4√12 2√12
Answer:
[tex]4 \sqrt{122} \sqrt{12} \\ (4 \times 2) \times ( \sqrt{12} \times \sqrt{12} ) \\ (4 \times 2) \times 12 \\ 8 \times 12 \\ 96[/tex]
Pls help ———————————-
Please help solve for x
Answer:
8.49
Step-by-step explanation:
there is a little formula related to the famous formula of Pythagoras.
it says that the height of a triangle is the square root of the product of both segments of the baseline (the segments the height splits the baseline into).
so, x is actuality the height of the triangle.
x = sqrt(3×24) = sqrt(72) = 8.49
Someone help please
Answer: Choice A
[tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex]
============================================================
Explanation:
Recall that [tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex] and [tex]\cot(x) = \frac{\cos(x)}{\sin(x)}[/tex]. The connection between tangent and cotangent is simply involving the reciprocal
From this, we can say,
[tex]\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]
In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.
All of this shows why [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is identical to [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]
Therefore, [tex]\tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.
You can visually confirm that [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is the same as [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.
There were 642 students enrolled in a freshman-level chemistry class. By the end of the semester, the number of students who passed was 5 times the number of students who failed. Find the number of students who passed and the number who failed.
Answer:
535 students passed and 107 students failed
Step-by-step explanation:
Create a system of equations where p is the number of students who passed and f is the number of students who failed:
p + f = 642
p = 5f
Solve by substitution by plugging in 5f as p into the first equation, then solving for f:
p + f = 642
5f + f = 642
6f = 642
f = 107
So, 107 students failed.
Find how many students passed by multiplying this by 5:
107(5)
= 535
535 students passed and 107 students failed.
Which of the following best describes the slope of the line below?
A. Zero
B. Negative
C. Positive
< PREVIOUS
Answer:
A. Zero.
Step-by-step explanation:
Technically, the correct answer is "undefined", as there will be infinite change in the slope amount. However, of all the given choices, Zero should be the best answer. However, if it is wrong, do ask your teacher, and state that undefined should be the answer choice, and that credit should be rewarded for such.
In ATUV, Y is the centroid. If TY = 30, what is YW?
A.15
B.45
C.30
D.60
We know at centroid medians bisect each other in the ratio 2:1.
TY=30Let YW be x[tex]\\ \sf\longmapsto TY=2x[/tex]
[tex]\\ \sf\longmapsto 2x=30[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{30}{2}[/tex]
[tex]\\ \sf\longmapsto x=15[/tex]
Answer:
A
Step-by-step explanation:
On the median TW the distance from the vertex to the centroid is twice the distance from the centroid to the midpoint , then
YW = [tex]\frac{1}{2}[/tex] × TY = [tex]\frac{1}{2}[/tex] × 30 = 15
What is the shaded area of the figure?
Answer:
Step-by-step explanation:
The idea here is to find the area of the circle and then subtract from it the area of the triangle. That will give you the area of what's left in the circle (the shaded part). The area of a circle is:
[tex]A_c=\pi r^2[/tex] so
[tex]A_c=(3.14)(12.4)^2[/tex] where 12.4 is the radius.
[tex]A_c=482.81[/tex] rounded to the nearest tenth. I used 3.14 for pi.
Now for the area of the triangle. The formula is
[tex]A_t=\frac{1}{2}bh[/tex] where h is the height of 12.4 and the base is the diameter which is 12.4 * 2 = 24.8
[tex]A_t=\frac{1}{2}(24.8)(12.4)[/tex] so
[tex]A_t=153.76[/tex]
Now subtract the triangle's area from the circle's area:
482.81 - 153.76 = 329.05 mm²
what's the median of -13.78, -3.01, -2.41, -0.28, 0.66, 0.67, 1.05, 1.39, 2.03, 2.2, 2.64, 4.02
Find the values of the missing sides. You must use exact answers! PLEASE HURRY AND HELP
Answer:
x=4sqrt3 a=4 b=3 ,y=8sqrt3 c=8 d=3
Step-by-step explanation:
because this is a 30-60-90 triangle, it is easy to find the side lengths. the longer leg is sqrt(3) times the shorter leg so x= 12/sqrt(3) or 4sqrt(3). the hypotenuse is 2 times the shorter leg so y= 8sqrt(3)
Answer choices:
A. 216
B. 367.2
C. 297.4
D. 432
pls help me!!
Answer:
216
Step-by-step explanation:
Volume of prism = BH
B -> Base area
Area of base:
b = 10 mi
h = 3.6mi
Area of the triangular base = [tex]\dfrac{1}{2}*b*h[/tex]
[tex]=\dfrac{1}{2}*10*3.6\\\\= 18 \ mi^{2}[/tex]
H = 12 mi
Volume of prism = 18 * 12 = 216 cubic mi
16. What is the measure of ZAOB?
2t(t-1)-t+1 factorise
Answer:
this is the answer of this question
hoping it will help u
Tell whether the number pair (2,1) is a solution to the equation y = 3x - 5.
Answer:
Yes
Step-by-step explanation:
Plugging in the values in the equation, we have
1=3*(2)-5, 1=1 which is TRUE
find the slope of the tangent line of the curve r = cos (3theta) at theta = pi / 3
The slope of the tangent line to the curve at a point (x, y) is dy/dx. By the chain rule, this is equivalent to
dy/dθ × dθ/dx = (dy/dθ) / (dx/dθ)
where y = r(θ) sin(θ) and x = r(θ) cos(θ). Then
dy/dθ = dr/dθ sin(θ) + r(θ) cos(θ)
dx/dθ = dr/dθ cos(θ) - r(θ) sin(θ)
Given r(θ) = cos(3θ), we have
dr/dθ = -3 sin(3θ)
and so
dy/dx = (-3 sin(3θ) sin(θ) + cos(3θ) cos(θ)) / (-3 sin(3θ) cos(θ) - cos(3θ) sin(θ))
When θ = π/3, we end up with a slope of
dy/dx = (-3 sin(π) sin(π/3) + cos(π) cos(π/3)) / (-3 sin(π) cos(π/3) - cos(π) sin(π/3))
dy/dx = -cos(π/3) / sin(π/3)
dy/dx = -cot(π/3) = -1/√3
Which equation is equivalent to x^2 +24-8=0?
A.(x+12)^2 =152
B.(x-12)^2=136
C.(x+8)^2=144
D.(x+12)^2 =144
Answer:
D) is your correct answer
Alex wants to test the reliability of “lie detector tests,” or polygraph tests. He performs a polygraph test on a random sample of 12 individuals. If there is more than a 50% chance that the tests result in no false positives (that is, the test does not result in a true statement being recorded as a lie), Alex will conclude that the tests are reliable. If the probability of a lie detector test resulting in a false positive is 5.5%, what will Alex conclude? Use Excel to find the probability, rounding to three decimal places.
The correct statement is test is reliable and authentic as the probability of no false positives is more than 0.5
Given that
[tex]H_o:P= 0.50\\\\H_1:P>0.50[/tex]
Now following calculations to be done to reach the conclusion:
There is no false positive as
= 100 - 5.5
= 94.5%
[tex]\hat P =0.945, n = 12[/tex]
Now
[tex]z = \frac{\hat P - P}{\sqrt\frac{P(1-P)}{n} }\\\\=\frac{0.945-0.5}{\sqrt\frac{0.5\times0.5}{12} } \\\\= 3.08[/tex]
So
P value = P(z >3.08) = 0.0010
Therefore we can conclude that test is reliable and authentic as the probability of no false positives is more than 0.5
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√3 is a polynomial of degree ________.
Step-by-step explanation:
Therefore, the degree of polynomial √3 is zero.
[tex]\sf\huge\underline\color{pink}{༄Answer:}[/tex]
[tex]\tt{\sqrt{3}}[/tex] is a polynomial of degree 0
[tex]\sf\huge\underline\color{pinl}{༄Note:}[/tex]
The expression is constant, which means it can be rewritten with a factor of x^0. The degree is the largest exponent on the variable.[tex]\color{pink}{==========================}[/tex]
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