2.56 m/s is the speed of the objects when they are separated vertically by 1.00 m. When a 3.50 kg object is attached by a thread of negligible mass, which passes over a frictionless pulley of negligible mass, to a 4.50 kg object.
What is mass ?The amount of matter in a particle or object is represented by the dimensionless quantity mass (symbolized m). The kilogram is the International System's (SI) preferred unit of mass (kg).Given:
Mass of 1st object, m1=3.50 kg Mass of 2nd object, m2=4.50 kgthey are at the same height from the floor.Solution:F=mg
putting value
F=3.50*9.8
Fd=34.3N
and
Fu=4.50*9.8
Fu=44.55
Hence the difference of the forces is
Fn=44.55-34.3N
Fn=10.25N
Generally
F=(m1+m2)a
10.25 = (3.50+4.50)a
a = 10.25/8
a= 1.28 m/s²
the equation for the Speed known as
v^2 = u^2+ 2as
So
v^2 = 0^2 + 2* 1.28 * 1
v = 2.56 m/s
Hence, 2.56 m/s is the speed of the objects when they are separated vertically by 1.00 m.
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100 POINTS IF YOU CAN ANSWER THIS
If the preferred vehicle is a sports car, what is the conditional distribution for females?
(Table Included)
A. 35.6%
B. 54.2%
C. 0.02%
D. 44.3%
E. 62.6%
Answer:44.3
Explanation:
a pipe of cross sectional area 1.2 m2 narrows to a pipe of cross-sectional area 0.4 m2. if the fluid is traveling at 1.7 m/s in the larger pipe, calculate the fluid speed in the narrower pipe.
The fluid speed in the narrower pipe is 4.5 m/s.
The speed of a fluid traveling through a pipe is determined by its cross-sectional area. In this case, a pipe of cross-sectional area 1.2 m2 is narrowing to a pipe of cross-sectional area 0.4 m2. The fluid is currently traveling at 1.7 m/s in the larger pipe. To calculate the fluid speed in the narrower pipe, the following equation can be used:
Speed = (Cross-sectional area of larger pipe/ Cross-sectional area of smaller pipe) × Speed of fluid in larger pipe
In this case, the equation becomes:
Speed = (1.2/0.4) × 1.7 m/s
Speed = 4.5 m/s
Therefore, the fluid speed in the narrower pipe is 4.5 m/s.
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A 1.2-kg spring-activated toy bomb slides on a smooth surface along the x-axis with a speed of 0.50 m/s. At the origin 0, the bomb explodes into two fragments. Fragment 1 has a mass of 0.40 kg and a speed of 0.90 m/s along the negative y-axis. In the figure, the energy released by the explosion is closest to?
The velocity of fragment 2 is equal to 0.88 m/s at 31°.
What is law of conservation of linear momentum?From the law of conservation of momentum, the sum of the momentum before and after the collision must be equal.
m₁ u₁ + m₂.u₂ = m₁ v₁ + m₂.v₂
where m₁ & m₂ is the mass of the collided objects, u₁ & u₂ are their initial speed while v₁ & v₂ is their final speed.
Given, the mass of the spring, m = 1.2 kg
The speed of the spring, v = 0.50 m/s
The mass of the first fragment, m₁ = 0.4 kg
The initial speed of fragment 1, u₁ = 0.9 m/s
The mass of the fragment, m₂ = 1.2 - 0.4 = 0.8 kg
In x-direction: [tex]mucos\theta = m_1v_1 cos\theta + m_2 v_2 cos\theta[/tex]
1.2 ×0.5 ×cos(0) = 0 + 0.8× v₂ cosθ
v₂ cosθ = 0.75
In y-direction: 12 (0) = -0.4(0.9) + 0.8 v₂ sinθ
v₂ sinθ = 0.45
Now, [tex]\displaystyle \frac{v_2sin\theta}{v_2cos\theta} =\frac{0.45}{0.75}[/tex]
tanθ = 0.6
θ = 31°
The value of the velocity of the fragment can be calculated as;
v₂ sinθ = 0.45
v₂ sin31 = 0.45
v₂ = 0.88 m/s
Thus, the magnitude of the velocity of fragment 2 is 0.88 m/s at 31⁰.
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A 0.15 kg baseball reaches a batter with a speed of 32.0 m/s. If a 0.94 kg bat, moving with a speed of 41.0 m/s, hits the baseball, what is the speed of the baseball right after the elastic collision? Assume the bat speed does not change.
A batter is struck with a baseball that weighs 0.15 kg at a speed exceeding 32.0 m/s. When a 0.94 kilogram bat. After a collision, the baseball's final speed was 24 m/s.
What is speed and what is its unit?The pace at which a distance changes over time is referred to as speed. It has a dimension of time-distance. As a result, the fundamental unit of time and indeed the basic unit pf distance are combined to form the Special name of speed.
How do find speed?Speed indicates how quickly thing or an individual are moving. If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance * time.
Briefing:Mass of baseball, m=0.15kg,
Mass of bat, M=1.4kg,
Initial speed of baseball, u=-32 m/s,
Initial speed of bat, U=41 m/s
Final speed of bat, V=35 m/s,
Linear momentum, mu+MU = mv+MV
(0.15" " kg×-32" " m/s)+(1.4" " kg×41" " m/s)
=(0.15" " kg ×v)+(1.4" " kg×35" " m/s)
-4.8+57.4 = 0.15v+49
0.15v = 3.6
v=(3.6)/(0.15)
v=24m/s
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a btu is defined as the amount of energy required to raise the temperature of one lb of water by one degree celsius group of answer choices true false
A BTU is defined as the amount of energy required to raise the temperature of one lb of water by one-degree celsius is False.
A British thermal unit is a measure of the amount of heat in a fuel or energy source. This is the amount of heat required to raise the temperature of 1 pound of liquid water by 1 degree Fahrenheit, the temperature at which water reaches its maximum density.
BTU is the amount of energy required to raise the temperature of 1 pound of water to 1 degree Fahrenheit above sea level. Technically, this measurement refers to the amount of energy required for this process when water is at its maximum density.
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how long would a day be if the earth were rotating so fast that objects at the equator were apparently weightless?
A day would be 85 min long if the earth were rotating so fast that objects at the equator were apparently weightless.
At the equator, the centrifugal force and gravitational force must be equal in order to feel weightless.
[tex]\frac{mv^{2} }{R} = mg[/tex]
∴ [tex]v = \sqrt{gR}[/tex]
[tex]\frac{2\pi r}{T} = \sqrt{gR}[/tex]
[tex]{T} = \frac{2\pi r}\sqrt{gR}[/tex]
[tex]T= \frac{2 \pi (64000)}{\sqrt{9.8(64000)} }[/tex]
T = 5.07×10³s
∴T = 85 min.
What is Earth's rotation?While Earth rotates on its axis from west to east, the Sun and Moon appear to move across the sky from east to west. The term "rotation" in science refers to the Earth's rotation about its axis. The axis has an angle of 23 1/2° and is parallel to the Earth's orbital plane. The fact that the northern and southern hemispheres tilt away from the Sun suggests that the Earth's axis is inclined. The Earth revolves, dividing it into a lit up and dark half, resulting in day and night. You can tell which way the Earth is rotating depending on your point of view. When looking downward from the North Pole, Earth turns anticlockwise. When seen from the south pole, however, the world revolves anticlockwise.
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two parakeets sit on a swing with their combined center of mass 16.0 cm below the pivot. at what frequency (in hz) do they swing?
The two parakeets sitting on the swing with a combined center of mass 16.0 cm below the pivot swings with a frequency of 1.21Hz.
How to calculate frequency of swing?Given the data in the question
Length of pendulum; L=16.0cm =0.16m
Frequency; f=
Using the simple pendulum equation of time:
T2π = √L/9 -------let this be equation 1
Where T is the period of time, L is the length of the pendulum and g is the acceleration due to gravity(9.8m/s² ).
Also formula for Frequency:
f=1/T ------------let this be equation 2
Lets substitute equation 1 into equation 2
f = 1/2π√L/9
f = 1/2π√9/L
We substitute or values into the equation
f=1/2π√[9.8/0.16]
f=1/2π√[57.647-2]
f=1/2π*7.59256s
f=1.21 hZ
Therefore, the two parakeets sitting on the swing with a combined center of mass 16.0 cm below the pivot swings with a frequency of 1.21Hz.
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when an apple is resting on top of a table, how many force pairs (number of pairs not individual forces)act on the apple?
The draw of the earth on the apple and the pull of the apple on the earth are forces operating in pairs (number of pairs, not individual forces).
What forces are at work while something is at rest?Since there is no net force acting on the item while it is resting , the downward force (weight) must counterbalance the force acting upward (normal force). Weight travels downhill, therefore it is always negative. For an item to be at rest, all of the forces must be equal to 0.
Can an object at rest be affected by a force?According to Newton's first rule, in order to have no net force exerted on an object, it must be at rest. Because if there is a total force acting on the object, it will change velocity. It will accelerate.
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A 30.0-kg load is being held in place using massless wires in the ideal pulley arrangement shown in the figure. What is the magnitude of the force F?
A very light wire is used to hang a series of 8.0-kg bricks. This wire will break if the tension in it exceeds 450 N. The bricks are hung one below the other from a hook in the ceiling using this wire, as shown in the figure.
(a) How many whole bricks can be hung without breaking the wire?
(b) If you add one more brick to the number found in part (a), which string will break?
a thin film of thickness 280 nm and index of refraction 1.4 coats a plate of glass having index of refraction 1.65. if light is perpendicularly incident on the glass, at what wavelength is the reflected light minimal?
If a thin layer with an index of refraction of 1.4 and a thickness of 280 nm coats a glass plate with an index of refraction of 1.65, the minimum wavelength of the reflected light is 182 nm.
What is the wavelength, exactly?When a waveform signal travels across space or down a wire, its wavelength is the distance between two identical locations (adjacent crests) in adjacent cycles. The standard units of measurement for this length in wireless systems are meters (m), centimeters (cm), or millimeters (mm) (mm).
Light is coming from a medium with a lower refractive index (n 1 = 1.50) into a medium with a higher index (n 2 = 1.60), so the net path difference in the reflected rays from the two interfaces will be equal to 2t (where t is the thickness of the thin film), because when that happens, light will enter the higher index medium.
When light travels from air to a thin film, the reflected ray's path shift equals 2; when it travels from a thin film to glass, the reflected ray's path shift equals 2′ /2+2t for constructive interference; 2t=m or 2t=m/n 1 where is the wavelength in the thin film, =546nm (given) wavelength in vacuum, and m=0 (minimum); thus, t
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if betelgeuse were to radiate all of its energy at the peak-intensity wavelength, how many photons per second would it radiate?
if Betelgeuse were to radiate all of its energy at the peak-intensity wavelength, how many photons.
What is energy?
Energy, which is observable in the execution of labour as well as in the form of heat and light, is the quantitative quality that is transferred to a body or to a physical system in physics. It is a mechanically accepted quantity.
a )
Radius of the sun = .69645 x 10⁹ m .
600 times = 600 x .69645 x 10⁹ m
= 4.1787 x 10¹¹ m .
surface area A = 4π (4.1787 x 10¹¹)²
= 219.317 x 10²²
energy radiated E = σ A Τ⁴
= 5.67 x 10⁻⁸ x 219.317 x 10²² x (3000)⁴
= 100695 x 10²⁶ J
To know the wavelength of photon emitted
[tex]\begin{aligned}& \lambda_m T=b \\& \lambda_m=\frac{b}{T}\end{aligned}[/tex]
= 2.89777 x 10⁻³ / 3000
= 966 nm
= 1275 /966 eV
1.32 x 1.6 x 10⁻¹⁹ J
= 2.112 x 10⁻¹⁹ J
No of photons radiated = 100695 x 10²⁶ / 2.112 x 10⁻¹⁹
= 47677.5 x 10⁴⁵
= .476 x 10⁵⁰ .
b )
energy radiated by our sun per second
E₂ = σ A 5800⁴
energy radiated by Betelgeuse per second
E₁ = σ x 600²A x 3000⁴
E₁ / E₂ = σ x 600²A x 3000⁴ / σ A 5800⁴
= 36 X 10⁴ x 3⁴ x 10¹² / 58⁴ x 10⁸
= 25.76 x 10⁸ x 10⁻⁵
= 25760 times .
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Complete Question
The red giant Betelgeuse has a surface temperature of 3000 K and is 600 times the diameter of our sun. (If our sun were that large, we would be inside it!) Assume that it radiates like an ideal blackbody.a) If Betelgeuse were to radiate all of its energy at the peak-intensity wavelength, how many photons per second would it radiate?b) Find the ratio of the power radiated by Betelgeuse to the power radiated by our sun (at 5800 K).
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if it requires energy u to accelerate a rocket fro rest to 1/2c the energy needed to acclerate a rocket from 1/2 c to c would be
The energy needed to accelerate a rocket from 1/2 c to c would be 3 times of U if it require U to accelerate from rest to 1/2c.
Now,we know that kinetic energy of rocket is given by =(1/2)mv² where m is the mass of the rocket and v is the velocity of rocket.
According to work-energy theorem,we know that work done=change in kinetic energy of the body.
Here,we have initial velocity of rocket is =0,and final velocity of rocket =1/2c
So,Work done=(1/2) ×m×(1/2)c² - 0²
=>U=(1 / 4) ×(1/2)×m×c²-------(eq1)
Now,we need to find the required amount of kinetic to accelerate it from 1/2c to c
So, required kinetic energy is Work done=(1/2)mc² - (1/2)×m×(1/2)c²
=>Required kinetic energy=(1/2×m×c²) × (1-1/4)
=>Required kinetic energy=(3/4)×(1/2×m×c²)
=>Required kinetic energy=(3)×((1 / 4) ×(1/2)×m×c²)
=>Required kinetic energy=3 ×times of U(from eq1)
Hence,kinetic energy required is 3 times of U.
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perceiving the color, motion, and form of a bird in flight illustrates a. parallel processing. %. opponent-process theory. q. trichromatic theory. d. serial processing. place theory.
parallel processing perceiving the color, motion, and form of a bird in flight illustrates.
Option a is correct.
The trichromatic hypothesis of colour perception is what?According to the trichromatic theory, our ability to perceive red, green, and blue hues as well as how they affect our cerebral activity are both explained by cones (Like a projection T.V.). Consequently, the precise colour we see is determined by the proportion of each colour to the others.
What foundation does trichromatic theory have?The three kinds of cone receptors that are responsible for colour vision are the foundation of the trichromatic hypothesis of colour vision. Beginning in the 18th century, this hypothesis has a very long history.
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ou are walking up an icy slope. suddenly your feet slip, and you start to slide backward. will you slide at a constant speed, or will you accelerate?
When climbing an ice slope. Your feet suddenly start to slip, and you begin to slither backward. Because the kinetic friction is greater than the maximum static friction, you will accelerate down the slope.
Kinetic friction - what is it?The resistance an object encounters while in motion as a result of contact between the surface and the thing moving against it is known as the kinetic friction force. Always acting in the opposite direction from the object's motion is the kinetic friction force. This explains why we often find that kinetic friction causes an object to move backward when we try to move it forward.
Static friction - what is it?An object moving along a path is resisted by a force known as static friction.
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what is the effective spring constant k of the two-spring system? express the effective spring constant in terms of k 1 and k 2 .
The Effective Spring Constant is [tex](\frac{k1k2}{k1 + k2} )[/tex] for a system of 2 springs with spring constant k1 and k2.
What is Spring Constant ?The term "spring constant" refers to the proportional constant k. It gauges the stiffness of the spring. A spring exerts a force F = -kx in the direction of its equilibrium position when it is stretched or compressed to a length that differs by an amount x from its equilibrium length.
Spring constants are available in plural (physics) a quality of a spring that is determined by the force acting on the spring to the displacement it produces.
K stands for the proportionality constant, commonly referred to as the "spring constant." In layman's words, stiffness and strength are shown by the k variable in Hooke's law (F = -kx). An item requires more force to be stretched to a specific length the greater the value of k.
Let the force actiong be F N
then , if k1 is the spring constant of spring 1
F = x1 * k1
or, x1 = F/k1.
Similarly for spring 2
x2 = F/k2
Now x1 + x2 = F (1/k1 + 1/k2)
or effective displacement
X= [tex]F(\frac{1}{k1} + \frac{1}{k2} )[/tex]
or, F = [tex]X * (\frac{k1k2}{k1 + k2} )[/tex]
So the Effective Spring Constant is [tex](\frac{k1k2}{k1 + k2} )[/tex].
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which has the greatest inertia
A. Jumbo Jet
B. Bird
C. Car
Answer:C car
Explanation:
the area of a square metal is 600mm square.calculate it's New area when it's temperature is raised by 15k ( linear expansivity of metal=1.9*10-5 k-1
Answer:
ΔL = L * 1.9E-5 * ΔT
ΔA = A * 2 * 1.9E-5 * ΔT
ΔA = .6 * 3.8E-5 * 1.5E4 mm = .34 mm
New area = 600.34 mm
Note: (L + ΔL)^2 = L + 2 L ΔL + ΔL^2 where ΔL is a small quantity
(L + ΔL)^2 - L^2 = 2 L ΔL = L ΔA
where the coefficient of area expansivity is twice that of linear expansivity
analysis of the cosmic microwave background helped us understand how energy is distributed in the universe among matter (luminous and dark) and dark energy. which is the correct model for what we observe in our universe?
The Lambda-CDM (cold dark matter) model is the most widely accepted model for the structure and evolution of our universe.
What is universe?
Universe is the totality of all existing things, including all matter and energy, the planets, stars, galaxies, and the contents of intergalactic space. It is the physical universe in its entirety and the totality of all phenomena within it, including all matter and energy that has existed, exists, and will exist. The universe is believed to have begun with the Big Bang, an event that marked the beginning of time and space, and from which all matter and energy have since emerged.
This model is based on observations of the cosmic microwave background, large-scale structure, and the expansion of the universe. It suggests that the universe is composed of about 4.9% ordinary matter, 26.8% dark matter, and 68.3% dark energy.
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using your data, how are you able to determine if conservation of momentum occurs in each collision?
Momentum is conserved if the relative velocities before and after the impact are equal.
What does force momentum mean?In most cases, momentum is the quantity that describes the internal motion of any moving object. Force, on the other hand, is the quantity that modifies the degree of action existing when applied to any object. Momentum is the amount of energy contained within a moving item.
What does momentum within daily life actually mean?Momentum is the amount of motion, to put it simply. Quantity may be assessed in this scenario because if an object is moving and has mass, it has momentum. If something is stationary, it doesn't have momentum.
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a runner has a mass of 89 kilograms. he produces a force of 84 newtons between the ground and his running shoes. how fast does he accelerate?
At a height of 10.0 meters above Earth's surface, the potential energy of an object is 196 joules.
After the mass falls 5.00 meters, how much kinetic energy does it gain?
Answer:
To determine the change in kinetic energy of the object as it falls from a height of 10.0 meters to 5.00 meters, we can use the equation KE = 1/2 mv^2, where KE is the kinetic energy, m is the mass of the object, and v is the velocity. We can also use the equation for gravitational potential energy, which is PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height above the ground.
We know that the potential energy of the object at a height of 10.0 meters is 196 joules, so we can use this information to solve for the mass of the object:
196 = m * 9.80 * 10.0
196 = 98.0m
m = 2.00 kg
We can then use this value for the mass to find the kinetic energy of the object as it falls from a height of 10.0 meters to 5.00 meters:
KE = 1/2 * 2.00 * v^2
KE = 1/2 * 2.00 * (2gh)^2
KE = 1/2 * 2.00 * (2 * 9.80 * 5.00)^2
KE = 196 joules
Thus, the object gains 196 joules of kinetic energy as it falls from a height of 10.0 meters to 5.00 meters.
At a height of 10.0 meters above Earth's surface, the potential energy of an object is 196 joules. After the mass falls 5.00 meters, 196 joules is the kinetic energy.
What is kinetic energy?Kinetic energy is the type of energy which an item or particle has as a result of its motion. When work, that transfers energy, is performed on an item by exerting a resultant force, the object accelerates and obtains kinetic energy.
Kinetic energy is indeed a characteristic of an object moving or particle that is affected by both its speed and its mass. Translation (or motion across a path from one location to another), rotation on an axis, vibration, and any combination of movements are all possible.
Potential energy=m× g× h
196 = mass×9.80×10.0
m = 2.00 kg
K.E= 1/2×m×v²
KE = 1/2 ×2.00× v²
KE = 1/2 ×2.00× (2gh)²
KE = 1/2 ×2.00 × (2 × 9.80 ×5.00)²
KE = 196 joules
Therefore, 196 joules is the kinetic energy.
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Corey, whose mass is 95 kg , stands on a bathroom scale in an elevator. The scale reads 810 N for the first 3.0 s after the elevator starts to move, then 930 N for the next 3.0 s .
Velocity of the elevator after 3 seconds is equal to v₂ = 3.79 m/s. The same two forces that were at play when the elevator was speeding up are still present. The normal force, which is less than at rest.
How to calculate?given,
mass of Corey = 95 Kg
reading of sale for first 3.0 s when elevator start to move = 810 N
scale reading for 3.0 s = 930 N
Gravitation force acting =
F = m g
F = 95 x 9.8
F = 931 N
using newton's second law, due to movement of elevator
F_{net} = m a
W - N = m a₁
930- 810 = 95 x a₁
a₁ = 1.26 m/s²
now,
velocity calculation
v₁ = a₁t
v₁ = 1.26 x 3.0 = 3.78 m/s
now, For second case
931 - 930 = 95 x a₂
a₂ = 0.010 m/s²
now, velocity after 3.0 s
v₂ = v₁ + a₂ t
v₂ = 3.78 + 0.010 x (3 - 3)
(3-3) because velocity after 3 second is calculate we need to calculate velocity after 3 s from beginning.
v₂ = 3.78 + 0.010
v₂ = 3.78 m/s
velocity of the elevator is equal to v₂ = 3.79 m/s.
What two forces are at work on you when an elevator is moving?When a person is moving in an elevator, there are two forces at work on him: gravity and the elevator's normal force. The elevator is stationary or travelling at a constant speed, and the two forces are of equivalent strength. When the elevator is accelerating uphill or downward, their magnitudes are not identical.
What movement does an elevator make as it ascends?Since an elevator will move in a straight path with a constant speed, it exhibits uniform linear motion.
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A robot that is exploring the surface of Mars has a mass of 136 kg. If the gravitational force acting on the robot is 504.6 N downward, what is the free-fall acceleration on Mars?
The free-fall acceleration on Mars is 3.71 m/s²
What do you mean by free fall?A body is said to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.According to Newton's second law of motion, force (F) = mass (m) times acceleration, an item in free fall will move with an acceleration (a). We can use a little mathematics to determine the object's acceleration in terms of the net external force and the object's mass (a = F / m).Given :
gravitational force acting on the robot is 504.6 N
F= 504.6 N
mass of the robot = 136 kg
a = F/ m
= 504.6/ 136 =3.71 m/s²
The free-fall acceleration on Mars is 3.71 m/s²
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Visible light has a higher frequency than radio waves on the electromagnetic spectrum. How does the wavelength of visible light compare to radio waves?.
The wavelength of visible light compare to radio waves in the sense that visible light waves have a shorter wavelength than radio waves.
What is wavelength?The wavelength is described as the spatial period of a periodic wave which is the distance over which the wave's shape repeats.
Radio waves are electromagnetic waves that are produced by man with an oscillating circuit.
Radio waves are used in broadcasting, the waves used in television are those of shorter wavelength and those of radio are those of longer wavelength.
Longer radions are reflected in the ionosphere and can be detected in antennas which is located at great distances from the emitting source. The medium waves are less reflected in the ionosphere, due to their large wavelength they can overcome obstacles, so they can travel great distances.
It is known that the visible radiation waves have a wavelength between approximately 400 and 700 nanometers, the radio waves range from 1 centimeter to 1 km, so they have longer wavelengths than the waves belonging to the visible spectrum.
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based on this image alone, approximately how much of the galaxy's total mass is located within 5 kpc of the center, would you say?
The total mass of the galaxy within a radius of 5 kpc is approximately 3.25 billion solar masses.
A galaxy is a system of stars, remnants of stars, interstellar gas, dust, dark matter, bound together by gravity.
By using the equations of Newtonian mechanics, the total mass of the galaxy can be calculated by combining the mass of the stars, gas, dust, and dark matter within the 5 kpc radius.
The calculation can be made more accurate by adding in accurate estimates of the mass of the dark matter and other components of the galaxy.The total mass of a galaxy within a radius of 5 kpc can be calculated using the equation:
Mass = 2.3 x 10⁶ x (5 kpc)² x (1 solar mass/pc³)
Mass = 3.25 billion solar masses.
This calculation provided an approximate total mass for the galaxy, which is estimated to be 3.5 billion solar masses located within 5 kpc of the center.
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Assuming Birdman flies at a speed
of 35 m/s, how high should Birdman
fly to hit the bucket if the bucket is
placed 147 m from the start of the
field?
The birdman needs to soar 86.43m in the air to hit the bucket.
How can I calculate the horizontal speed?The ball's diameter, d, and the amount of time, t, it takes to cross the photogate can both be used to calculate the beginning horizontal velocity. Vo = d/t, then.
Time of motion of the birdman
The duration of the birdman's motion is the amount of time it takes for him to soar to his highest point.
R = Vₓt
where;
R is the birdman's motion's range or his horizontal distance.
Time of motion is t.
The horizontal speed is Vx.
t = R/Vₓ
t = 147/ 35
t = 4.2 seconds
Maximum height the missile has climbed
h = ¹/₂gt²
where;
The birdman's height is measured in h.
Gravitational acceleration, or g,
h = ¹/₂(9.8)(4.2)²
h = 86.43 m
The birdman must therefore fly to a height of 86.43m in order to hit the bucket.
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A car travels 500 km from home at 35 m/s, then travels back at 43 m/s. Find its average speed.
The average speed of the car is 35.6m/s
What is average speed?The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction. It is measured in meter per second
Therefore average speed = total distance / total time taken
The total distance here is 500+ 500= 1000km = 1×10⁶m
the time taken for the first journey = 500×1000/35= 14285.71 seconds
the time taken for traveling back = 500000/43= 11627.91 seconds
total time taken = 14285.71 + 11627.91 = 25913.62seconds
therefore average speed = 1000000/25913.62
= 35.6m/s
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Which of the following is NOT an example of a scalar quantity?
75 degrees Celsius
22.5 miles
2.0 meters, east
258 km
Which of the following is NOT an example of a vector quantity?
75 degrees Celsius
22.5 miles, south
2.0 meters, east
258 km, north
The answers include the following below:
The following which is not an example of a scalar quantity is 2.0 meters, east and is denoted as option C.The following which is not an example of a vector quantity is 75 degrees Celsius and is denoted as option A.What is a Scalar quantity?This is referred to as a quantity or any form of measurement which has magnitude but no direction and examples include 75 degrees Celsius , 22.5 miles etc as no direction is denoted in the measurement which is given in this type of scenario.
On the other hand, vector quantity is the measurement which has both magnitude and direction and examples include 22.5 miles, south , 2.0 meters, east etc which shows the direction in which the body is moving which is therefore the reason why the above options were chosen as the correct answer.
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a 23-month-old child pulls a pan of hot water off the stove and spills it onto her chest and arms. her mother is right there when it happens. what should the mother do immediately?
When it happens mother should have to do cool the burn with tap water for 10 to 20 minutes immediately.
What are the steps to give first aid to a person with a large burn?Stop the burning process. Cool the burn. Supply pain relief.
Before the arrival of qualified emergency help, you should:
Remove restrictive items such as rings, watches, and bracelets.Use a fresh, cool bandage that is moist to cover the burnt area.Raise your hand so that it is higher than your heart.Is burning from boiling water serious?Pain and skin injury from wet heat or vapors can result from hot water scalding. Because the damaged tissues and cells are destroyed, this kind of burn can be deadly. The heat could even cause your body to go into shock. These burns can be fatal in more severe circumstances.
What should I do right away if I am burned?Cool the burn.
Place the affected area under cool (not cold) flowing water for about 10 minutes. Until the pain goes away, apply a cool, wet cloth to the burned area of the face. If you have a mouth burn from hot food or drink, place a piece of ice in your mouth for a while.
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find the work done by the given force field for an object moving across a path that is the boundary of the region bounded by the upper semicircle centered at the origin with radius 2 and the x-axis. assume counterclockwise orientation. hint: use a theorem! you should be able to do this problem without too much computational work. group of answer choices 8 none of these 2 4
The work done by the given force field for an object moving across a path that is the boundary of the region bounded is 10 JOULE
To find the work done by a force field for an object moving across a path that is the boundary of a region, we can use the following equation:
W = ∫F(r)⋅dr
where W is the work done, F(r) is the force field acting on the object, and r is the position vector of the object. The integral is taken over the path of the object.
In this case, the path of the object is the boundary of the region bounded by the upper semicircle centered at the origin with radius 2 and the x-axis. The orientation of the path is counterclockwise. The force field acting on the object is given by:
F(r) = E
where E is a constant force field.
To find the work done by the force field, we can substitute the form of the force field and the path of the object into the work equation and evaluate the integral:
W = ∫E⋅dr
= ∫10⋅dr
= 10 ∫dr
The path of the object is the boundary of the region bounded by the upper semicircle centered at the origin with radius 2 and the x-axis. We can parameterize this path by expressing the position vector r in terms of a parameter t:
r = xi + yj
where x and y are functions of t and i and j are unit vectors in the x and y directions, respectively.
Substituting the parameterized form of the position vector into the work equation, we get:
W = 10 ∫(xi + yj)⋅dr
= 10
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