22. f(x) is stretched horizontally by a factor of 2 and reflected across the x-axis. Which choice shows the correct representation of f(x) after these transformations?
Options:

A. –f(1/2x)

B. f(–2x)

C. –f(2x)

D. f(–1/2x)

Answer:

Option (D) : (3.5, 8.75)

Answer:

45.35

Step-by-step explanation:

From the above question, we are told that the annual effective rate = 10% = 0.10

Note also that payment is been made every 2 years

Hence , we apply the formula of effective interest rate for a period of 2 years.

Effective Interest rate(j) = (1 + r)² - 1

= (1 + 0.10)² - 1

= 1.10² - 1

= 1.21

= 0.21

Present value of perpetuality = t/[j × j/(1 + r)²]

Where t = time in years = 2

r = 0.10

= 2/ [0.21 × 0.21/(1 + 0.10)²

= 54.87528

Present value at time t = 0

= 54.87528(1 + r)^-2

= 54.87528(1 + 0.10) ^-2

= 54.87528(1.10)^-2

= 45.35

Therefore, the present value at time (t) is 0 = 45.35

Answer:

5^3  y^5

125 y^5

Step-by-step explanation:

5y^3/(5y)^-2​

Distribute the exponent in the denominator

5y^3/(5 ^-2 y^-2)

A negative exponent in the denominator brings it to the numerator

5y^3 5 ^2 y^2​​

Combine like terms

5 * 5^2  * y^3 5^2

We know that a^b * a^c = a^(b+c)

5^(1+2) * y^( 3+2)

5^3  y^5

125 y^5

Answer:

42.7 mm

Step-by-step explanation:

To the nearest tenth of a mm, 42.67 mm would be 42.7 mm.

After estimate of this value rounded to the nearest tenth of a millimeter,

⇒ 42.67 ≈ 42.7

We have to given that,

According to the United States Golf Association, the diameter of a golf ball should not be less than 42.67 millimeters.

Hence, After estimate of this value rounded to the nearest tenth of a millimeter, we get;

⇒ 42.67

As, 7 is grater than 5, so we can add 1 to the tenth place.

⇒ 42.67 ≈ 42.7

Therefore, After estimate of this value rounded to the nearest tenth of a millimeter,

⇒ 42.67 ≈ 42.7

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Answer:

[tex]-1 \frac{3}{4}[/tex]

Step-by-step explanation:

Using this number line, we can plot our original number - [tex]\frac{3}{4}[/tex] (see picture attached)

Adding a negative is the same thing as subtracting - so we are subtracting [tex]2\frac{1}{2}[/tex] from  [tex]\frac{3}{4}[/tex].

To subtract this, we can break up [tex]2\frac{1}{2}[/tex]  into 3 parts: 1, 1, and [tex]\frac{1}{2}[/tex]. We can subtract each of these from the current number and see where we land up. (again see picture)

We land up at [tex]-1 \frac{3}{4}[/tex].

Hope this helped!

Answer:

45

Step-by-step explanation:

multiply 9 by 5 to get 45

then, multiply 45 by 5 to get 225

The geometric sequence is 5(previous number)

Answer:

see explanation

Step-by-step explanation:

(f - g)(x) = f(x) - g(x) , that is

f(x) - g(x)

= - 5x³ - 4x² + 8x - (- 4x² + 8) ← distribute parenthesis by - 1

= - 5x³ - 4x² + 8x + 4x² - 8 ← collect like terms

= - 5x³ + 8x - 8

Substitute x = - 2 into this expression, thus

(f - g)(- 2)

= - 5(- 2)³ + 8(- 2) - 8

= - 5(- 8) - 16 - 8

= 40 - 16 - 8

= 16

Answer:

300

Step-by-step explanation:

We need to find 12/37 of 444.

12/37 * 444 = 12/37 * 444/1 = (12 * 444)/(37 * 1) = 5328/37 = 144

She sat in the back seat 144 times out of 444.

444 - 144 = 300

She sat in the front seat 300 times.

The answer is 1/2 because there are total 10 questions. So, the probability of getting 5 correct answers is 5/10 that is 1/2.

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Answer:

a number, r, added to 6

Step-by-step explanation:

a number, r, added to 6

Answer:

a number, r, added to 6

Step-by-step explanation:

a number, r, added to 6

Answer:

[tex]\boxed{\sf B. \ All \ real \ numbers}[/tex]

Step-by-step explanation:

The domain is all possible values for x.

[tex]f(x)=(\frac{1}{4} )^x[/tex]

There are no restrictions on x.

The domain is all real numbers.

Answer:

B.All real number

hope you have unterstand

Answer:

H0:  u = 185      against     Ha: u > 185

or

H0:  u ≤ 185      against     Ha: u > 185

Step-by-step explanation:

The null and alternative hypotheses for this experiment would be

H0:  u = 185      against     Ha: u > 185

or

H0:  u ≤ 185      against     Ha: u > 185

This is a one tailed test .

If the results are such that we reject the null hypothesis and accept the alternative hypothesis it means that the Americans are getting fatter as the mean weight is increasing day by day.

The null hypothesis deals with all the values equal to or less than 185 pounds and the alternative with all the values greater than 185  pounds.

Answer:

13

Step-by-step explanation:

let the number be x

how Cindy worked it out :

(x -6) ÷ 3 = 25

x -6 = 75

x = 81

How she should have worked it out:

(x - 3) ÷ 6

(81 - 3) ÷ 6

78 ÷ 6 = 13

Answer:

[tex]S = 3 h[/tex]

Step-by-step explanation:

Let M represent Michaela hair tier and S represents Michaela  sister's

Given

M = h

S = Triple of M

Required

Determine an expression for S

From the given parameters, we have that;

S = Triple of M

Mathematically, this implies;

[tex]S = 3 * M[/tex]

Substitute h for M

[tex]S = 3 * h[/tex]

[tex]S = 3 h[/tex]

Hence, the expression for Michaela  sister' is [tex]S = 3 h[/tex]

Answer:

In MATH:

Empowerment - Gaining the skills required in language and practices to fully understand math.

Radication - The process of extracting a number's root.

In ENGLISH:

Empowerment - The process of gaining more power over anything, including yourself, others, society, government, and corporations.

Ex - In the spirit of empowerment, the company has implemented a new system that asks employees to nominate one another for bonuses.

Radication - The process of establishing, fixing, or creating.

Ex - The high prestige of the premier is radicated in the hearts of the people.

Answer:

Part a ) The degrees of freedom for the given two sample non-pooled t test is 24

Part b ) The degrees of freedom for the given two sample non-pooled t test is 30

Part c ) The degrees of freedom for the given two sample non-pooled t test is 30

Part d ) The degrees of freedom for the given two sample non-pooled t test is 25

Step-by-step explanation:

Degrees of freedom for a non-pooled two sample t-test is given by;

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Now given the information;

a) :- m = 12, n = 15, s₁ = 4.0, s₂ = 6.0

we substitute

Δf =  {[ 4²/12 + 6²/15 ]²} / {[( 4²/12)²/12-1] + [(6²/15)²/15-1]}

Δf  = 30184 / 1241

Δf  = 24.3223 ≈ 24 (down to the nearest whole number)

b) :- m = 12, n = 21, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/12 + 6²/21 ]²} / {[( 4²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 56320 / 1871

Δf = 30.1015 ≈ 30 (down to the nearest whole number)

c) :- m = 12, n = 21, s₁ = 3.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 3²/12 + 6²/21 ]²} / {[( 3²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 29095 / 949

Δf = 30.6585 ≈ 30 (down to the nearest whole number)

d) :- m = 10, n = 24, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/10 + 6²/24 ]²} / {[( 4²/10)²/10-1] + [(6²/24)²/24-1]}

Δf = 1044 / 41  

Δf = 25.4634 ≈ 25 (down to the nearest whole number).

Answer:

Segment LM Corresponds to RQ    

Segment R corresponds to angle M

Answer:

Step-by-step explanation:

six hundred men,six hundred men with big mouths to feed

[tex]f(f(3))=2\cdot3^2+1=19\\f(f(f(f(3))))=2\cdot19^2+1=723[/tex]

Answer:

[tex]$\mathbf{\frac{1}{19} }[/tex]

Step-by-step explanation:

[tex]$$\bullet \Nth \ Term;\\$$$\frac{n+2}{2n^{2} +3n-2}[/tex]

[tex]$$\bullet U_{10} \ Term;\\\\$$\boxed{\frac{(10+2) }{2*10^{2} +3*10-2}= \frac{1}{19} }[/tex]

Answer:

[tex]\boxed{\displaystyle \frac{1}{19}}[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{n+2}{2n^2 +3n-2}[/tex]

Replace n with 10 to find the 10th term.

[tex]\displaystyle \frac{10+2}{2(10)^2 +3(10)-2}[/tex]

Evaluate.

[tex]\displaystyle \frac{12}{2(100) +30-2}[/tex]

[tex]\displaystyle \frac{12}{200 +30-2}[/tex]

[tex]\displaystyle \frac{12}{228}[/tex]

Simplify.

[tex]\displaystyle \frac{1}{19}[/tex]

Answer:

Y=2(1)+4

Y=2+4

Y=6

Step-by-step explanation:

Please follow me

Answer:

mass = 9a^5

center of mass = [tex]\frac{7a}{12}, \frac{7a}{12}, \frac{7a}{12}[/tex]

Step-by-step explanation:

Finding the mass of the solid E

given density function : p ( x,y,z ) = [tex]9x^2 + 9y^2 + 9z^2[/tex]

Mass =   [tex]\int\limits^a_0 \int\limits^a_0 \int\limits^a_0 {9(x^2+y^2+z^2)} \, dx dydz[/tex]   [tex]= \int\limits^a_0 \int\limits^a_0 {9(\frac{a^3}{3}+ay^2+az^2 )} \, dydz[/tex]

         [tex]= \int\limits^a_0 {9(\frac{a^4}{3}+\frac{a^4}{3} +a^2z^2 )} \, dz[/tex]  [tex]= \int\limits^a_0 {9(\frac{2a^4}{3}+a^2z^2 )} \, dz[/tex]  [tex]= 9 ( \frac{2a^5}{3} + \frac{a^5}{3} )[/tex]  

( taking limits as a and 0 )

hence Mass = 9 [tex](a^5)[/tex]

finding the center of mass

attached below is solution

Answer:the one area < with line underneath then -4

St-by-step explanation: I’m pretty sure this is correct

Answer:

Step-by-step explanation:

[tex] \mathrm{16x - 7 \leqslant - 71}[/tex]

Move constant to Right hand side and change its sign

[tex] \mathrm{16x \leqslant - 71 + 7}[/tex]

Calculate

[tex] \mathrm{16x \leqslant - 64}[/tex]

Divide both sides of the equation by 16

[tex] \mathrm{ \frac{16x}{16} \leqslant \frac{ - 64}{16} }[/tex]

Calculate

[tex] \mathrm{x \leqslant - 4}[/tex]

Hope I helped!

Best regards!

Answer:

d = s x t

Step-by-step explanation:

The formula for distance.

Answer:

1,377/2 and 688 1/17

Step-by-step explanation:

Answer:

x=3

Step-by-step explanation:

(segment piece) x (segment piece) =   (segment piece) x (segment piece)

3x(x+1) = 4x(x)

Divide each side by x

3x(x+1)/x = 4x(x)/x

3(x+1) = 4x

Distribute

3x+3 = 4x

Subtract 3x

3x+3-3x= 4x-3x

3 =x

Answer:

x = 3

Step-by-step explanation:

0 is a rediculas answer 9 and 12 are to big.

The lines are supposed to have a simular length:

3(3) + 4 = 13

4(3) + 3 = 15

These are the best answers that fit.

Answer:

a

Step-by-step explanation:

its a

The answer is m = 3000 - 40h

m = 1200 + 50h.

The answer is option A.

Problem-solving is the act of defining a problem; figuring out the reason for the hassle; identifying, prioritizing, and selecting options for an answer; and enforcing an answer.

Problem-solving begins with identifying the issue. For example, a teacher would possibly need to parent out a way to enhance scholar performance on writing scalability take a look at it. To do this, the trainer will assess the writing tests seeking out regions for improvement.

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Answer:

So first you do $0.50 x 3 = 1.5

then you add that to $12.00

$12.00 + 1.5 = 13.5

13.5 is the cost of one pizza.

Since they bought 12:

The total cost of the 12 pizza is $162 <== not important

13.5 divided by 8 is 1.687

round 1.56875 to the nearest cent 1.7 = $2

so each slice costs $2

Answer:

B) 2

/////////////////

Answer:

a

   The  90%  confidence interval is  [tex]52561.13 < \mu < 57540.8[/tex]

b

Confidence interval for the population men between $52561.13  up to $57540.8

Step-by-step explanation:

From the question we are told that

   The sample size is  [tex]n = 25[/tex]

     The  sample mean is  [tex]\= x = \$ 55,051[/tex]

     The standard deviation is  [tex]\sigma = \$ 7,568[/tex]

Given that the confidence level is  90% then the level of confidence is mathematically represented as

             [tex]\alpha = 100 -90[/tex]

              [tex]\alpha = 10\%[/tex]

             [tex]\alpha = 0.10[/tex]

Next we obtain the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table the values is  

               [tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]

Generally the margin of error is mathematically  represented as

               [tex]E = Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }[/tex]

substituting values

               [tex]E = 1.645 * \frac{ 7568}{ \sqrt{ 25} }[/tex]

             [tex]E = 2489.9[/tex]

The 90% confidence interval is mathematically evaluated as

       [tex]\= x -E < \mu < \= x +E[/tex]

substituting values

     [tex]55051 - 2489.8 < \mu < 55051 + 2489.8[/tex]

     [tex]52561.13 < \mu < 57540.8[/tex]

Step-by-step explanation:

Let minimum score on the final exam to earn an A be X

[tex]mean \: = \frac{sum \: of \: observation}{number \: of \: observation} [/tex]

[tex]90 = \frac{83 + 97 + 89 + 82 + x}{5} [/tex]

Further solving :

X = 99 marks