Answer:
(2x + y)(4x² - 2xy + y²)
Step-by-step explanation:
8x³ + y³ ← is a sum of cubes and factors in general as
a³ + b³ = (a + b)(a² - ab + b²) , then
8x³ + y³
= (2x)³ + y³
= (2x + y)((2x)² - 2xy + y²) , that is
(2x + y)(4x² - 2xy + y²)
I really really need help with this
Answer:
c) 21
Step-by-step explanation:
[tex] \sqrt{169} + \sqrt{64} [/tex]
13+8
answer is 21
in the first quarter austin played for 4 minutes and 30 seconds. wyatt played for 310 seconds who had more playing time
Answer:
wyatt
Step-by-step explanation:
4:30 mins is 270 seconds
what's the formula of
(a+b)³ = ?
Answer:
(a+b)³=a³+3a²b+3ab²+b³
Answer:
Step-by-step explanation:
Hello!
(a+b)(a+b)(a+b)
(a+b)(a+b) = a²+2ab + b²
(a²+2ab + b²) (a+b)=
a³ + a²b + 2a²b + 2ab² + ab² + b³ =
a³ + b³ + 2a²b + 2ab² + ab² + a²b
Find the missing side lengths. Leave your answers as radicals in the simplest form.
Answer:
x = 28, y = 14Step-by-step explanation:
Use the property of 30°-60°-90° right triangle.
The ratio of sides:
a : b : c = 1 : √3 : 2Compare with the given:
y : 14√3 : x = 1 : √3 : 2y = 14√3 / √3 = 14x = 2*14 = 28Apply the property of 30-90-60 angle
a:b:c=1:√3:2So
y=14√3/√3=14x=2(y)=2(14)=28If the areas of two similar triangles are equal, prove that they are congruent
Refer the attached image for the answer
HOPE SO IT HELPS YOU
I’m stuck somebody can help me
Answer:
26
Step-by-step explanation:
Answer:
26
Step-by-step explanation:
(g•h)(x) = 2(x²+4)
(g•h)(3)=2(3²+4)
=2(9+4)
=2(13)
=26
f(x) = x+3
g(x) = 2x^2-4
find (f times g) (x)
Step-by-step explanation:
(f*g) (x)=f(x) * g(x)
=(x+3)(2x^2-4)
=2x^3-4x+6x^2-12
If a is an odd integer and b is an even integer, which of the following makes an odd integer?
A.) 3b
B.) a+3
C.) 2(a+b)
D.) a+2b
Explain your answer
9514 1404 393
Answer:
D.) a+2b
Step-by-step explanation:
The integers 'a' and 'b' can be any, so you can choose a couple and evaluate these expressions to see what you get. For example, we can let a=1 and b=0. For these values, the offered expressions evaluate to ...
A) 3(0) = 0 . . . even
B) 1 +3 = 4 . . . even
C) 2(1+0) = 2 . . . even
D) 1 +2(0) = 1 . . . odd
_____
Additional comment
These rules apply to even/odd:
odd × odd = oddodd × even = eveneven × even = evenodd + odd = evenodd + even = oddeven + even = evenThen A is (odd)(even) = even; B is (odd)+(odd) = even; C is (even)(whatever) = even; D = (odd)+(even) = odd.
round 1.89 to one decimal place
Answer:
1.9
Step-by-step explanation:
You round when the numbers behind the decimal are 5 or greater. This being said, you need to round from the number furthest away from the decimal. In this case it would be 9. 9 is greater than 5 so we round 8 up to 9 and get rid of the number behind it. We are left with 1.9
BRAINLEST IF CORRECT!!!!!!!
Answer:[tex]\huge \boxed{x=180-26-90=64}[/tex]
Step-by-step explanation:
Answer:
Step-by-step explanation:
You have the angels 180, 26, 90(right angle) and x. So when you add them all up you should get 360 because there aren’t two straight lines. Only line makes a 180 angle. So...
180 + 26 + 90 + x = 360
296 + x = 360
x = 360 - 296
x = 64
PLEASE HELP I DONT UNDERSTAND
Write the equation of the line in slope-intercept form that is perpendicular to y = x - 2 and that
passes through the point (6,-5). Show all of your work.
Answer:
y = -x + 1
Step-by-step explanation:
eqn of line: y=mx+c
perpendicular, m1 x m2 = -1
m × 1 = -1
m = -1
y=-x+c
sub x=-5, y=6
6 = -(-5) +c
6 = 5 + c
c = 1
y = -x + 1
What are the coordinates of the vertices of the image?
A) A'(9,8), B'(-3,-4), C'(1, 2), and D'(1,-2)
B) A'(3,4), B'(3,-4), C'(-5, 2), and D'(1, 2)
C) A'(3,8), B'(-3, 4), C'(1,-2), and D'(-1,2)
D) A'(-3, 4), B'(3,4), C'(5,-2), and D'(-1,-2)
Answer:
D
Step-by-step explanation:
I took the quiz
I need help with this question
Answer:
m
Step-by-step explanation:
F(x)=2x+1 and g(x)=x2-7, find (f+g)(x)
Answer:
x^2 +2x -6
Step-by-step explanation:
f(x)=2x+1
g(x)=x^2-7,
(f+g)(x) = 2x+1 + x^2 -7
Combine like terms
= x^2 +2x -6
f (x) = 2x + 1
g (x) = x² - 7
(f+g) (x) = 2x+1 + x² - 7
Adding like terms
⇛ x² + 2x - 6
Jia baked two kinds of muffins. She baked 27 blueberry muffins. The number of cranberry muffins she baked is represented by the equation shown.
27 ÷ 3 = 9
Which statement accurately compares the number of blueberry muffins and the number of cranberry muffins?
Jia baked 3 times as many blueberry muffins as cranberry muffins.
Jia baked 9 times as many blueberry muffins as cranberry muffins.
Jia baked 3 times as many cranberry muffins as blueberry muffins.
Jia baked 9 times as many cranberry muffins as blueberry muffins.
Answer:
she baked 3 times as many cranberry than blueberry muffins
Step-by-step explanation:
i think that because 9×3=27
the amount of the cranberry muffins are 9
Correct answer gets brainliest and 5 stars
Answer:
Does the answer help you?
PLEASE PLEASE PLEASE PLEASE HELPME I *REALLY* NEED HELP!!!
(ALL LINKS WILL BE REPORTED)
Which of the following pairs of triangles can be proven similar through SSS similarity? PHOTO ATTACHED :))
Answer:
A
Step-by-step explanation:
since there are 3 corresponding sides shown, the SSS similarity theorem can be utilized.
If f(x)=7 find x=-3
A.4
B.-3
C.7
D.-4
Answer: the answer to your question is 7
Step-by-step explanation:
9.
A rocket is launched from the top of a 76-foot cliff with an initial velocity of 135 ft/s. a. Substitute the values into the vertical motion formula h = –16t2 + vt + c. Let h = 0. b. Use the quadratic formula to find out how long the rocket will take to hit the ground after it is launched. Round to the nearest tenth of a second.
A. 0 = –16t2 + 135t + 76; 0.5 s
B. 0 = –16t2 + 76t + 135; 9 s
C. 0 = –16t2 + 76t + 135; 0.5 s
D. 0 = –16t2 + 135t + 76; 9 s
Answer:
The answer is 2.)
Step-by-step explanation:
Given initial velocity=135 ft/s
& cliff=76 foot
Given quadratic equation
⇒ (let h=0 it is given)
⇒
⇒
⇒ t=8.96≈9 s (the other root is negative)
Hence, rocket will take 9 s to hit the ground after launched.
Answer: Choice D
0 = 16t^2 + 135t + 76; 9 s
==============================================
Explanation:
The equation we start with is
[tex]h = -16t^2 + vt + c\\\\[/tex]
where v is the starting or initial velocity, and c is the starting height.
We're told that v = 135 and c = 76
We let h = 0 to indicate when the object hits the ground, aka the height is 0 ft.
That means the equation updates to [tex]0 = -16t^2 + 135t + 76\\\\[/tex]
Based on that alone, the answer is between A or D
-------------------
We'll use the quadratic formula to solve for t
We have
a = -16b = 135c = 76So,
[tex]t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\t = \frac{-135 \pm \sqrt{135^2 - 4(-16)(76)}}{2(-16)}\\\\t = \frac{-135 \pm \sqrt{23,089}}{-32}\\\\t \approx \frac{-135 \pm 151.9506}{-32}\\\\t \approx \frac{-135 + 151.9506}{-32} \ \text{ or } \ t \approx \frac{-135 - 151.9506}{-32}\\\\t \approx \frac{16.9506}{-32} \ \text{ or } \ t \approx \frac{-286.9506}{-32}\\\\t \approx -0.52971 \ \text{ or } \ t \approx 8.96721\\\\[/tex]
We ignore the negative t value because a negative time duration makes no sense.
The only practical solution here is roughly 8.96721 which rounds to 9.0 or simply 9 when we round to the nearest tenth (one decimal place).
In short, the object will hit the ground at the 9 second mark roughly. Or put another way: the object is in the air for about 9 seconds.
From this, we can see that the final answer is choice D.
Keep in mind that we aren't accounting for any wind resistance. Considering this variable greatly complicates the problem and requires much higher level mathematics. So we just assume that there is no wind at this moment.
Urgent ! Help me please
Answer:
B
Step-by-step explanation:
x -> x and y -> y+5
-1 -> - 1 and - 3 -> 2, so b is the correct answer.
paul leaves for school at 7:25 am he returned home at 3:15 pm how long was paul away from home?
Answer:
8 hours 10 minutes
I hope this answers your question
Answer: paul has been away from home for 7 hours and 50 minutes.
Step-by-step explanation:
Sayad bought a watch and sold to Dakshes at 10% profit. Sayad again sold it to Sahayata for rs 6,050 at 10% profit. i)Find the cost price of Dakshes. ii) Find the cost price of Sayad.
Answer:
The cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.
Step-by-step explanation:
Given that Sayad bought a watch and sold to Dakshes at 10% profit, and Dakshes again sold it to Sahayata for $ 6,050 at 10% profit, to find the cost price of Dakshes and the cost price of Sayad the following calculations must be performed:
6,050 / 1.1 = X
5,500 = X
5,500 / 1.1 = X
5,000 = X
Therefore, the cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.
Analyze the diagram below and complete the instructions that follow.
10
6
B.
'C С
8
Find sin ZA
A 3
5
B. 4
C 1
Answer:
B. 4/5
Step-by-step explanation:
Sin = Opposite/Hypotenuse
Sin∠A = 8/10 = 4/5
Solve BCD. Round the answers to the nearest hundredth, if necessary.
Answer:
B
Step-by-step explanation:
here we use trigonometric ratio involving soh,cah,toa
find the value of a and b if [tex]5+√3/7+2√3=a-b√3[/tex]
Answer:
The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.
Step-by-step explanation:
There are mistakes in the statement, correct form is presented below:
[tex]5+\frac{\sqrt{3}}{7} + 2\sqrt{3} = a - b\cdot \sqrt{3}[/tex].
By direct comparison we have the following system of equations:
[tex]a = 5[/tex] (1)
[tex]\frac{\sqrt{3}}{7}+2\sqrt{3} = -b\cdot \sqrt{3}[/tex] (2)
In (2) we solve for [tex]b[/tex]:
[tex]\left(\frac{1}{7}+2 \right)\cdot \sqrt{3} = -b\cdot \sqrt{3}[/tex]
[tex]b = -\frac{15}{7}[/tex]
The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.
Rachel covered a single lap of 1,210 m in 55 s. Calculate her speed in m/s
Answer:
22 m/s
Step-by-step explanation:
Take the distance and divide by the time
1210 m/55s
22 m/s
Answer:
22m/sStep-by-step explanation:
[tex]speed = \frac{distantce}{time} \\ = \frac{1210m}{55s} \\ = 22m {s}^{ - 1} [/tex]
True or false? Any two points are collinear and coplanar
Answer:
True
Step-by-step explanation:
Any two points are always collinear because you can always connect them with a straight line. Three or more points can be collinear, but they don't have to be. ... Coplanar points: A group of points that lie in the same plane are coplanar. Any two or three points are always coplanar.
pls halp ////////////////
Answer:
9x^2 + 2x - 5
Step-by-step explanation:
7x^2 - 5x + 3
2x^2 + 7x - 8
__________
9x^2 + 2x - 5
Option B is the correct answer.
URGENT+Brainliest. Convert r=2sin(2theta) into rectangular cords.
Answer:
try 14n
Step-by-step explanation:
Answer:
[tex]r \: = 2sin2 \theta \\ = > r = 2.2sin\theta.cos\theta \\ = > r = 4sin\theta.cos\theta \: \\ \\ \sf \: we \: know \: that \: \\ x = r \: cos\theta \: \therefore \: cos\theta = \frac{x}{r} \\ \\ y = r \: sin\theta \: \therefore \: sin\theta = \frac{y}{r} \\ \\ \sf \: now \\ \\ r = 4 \times \frac{y}{r} \times \frac{x}{r} \\ = > {r}^{3 } = 4xy \\ \\ \sf \: again \: \: r = \sqrt{ {x}^{2} + {y}^{2} } \\ \\ = > {( \sqrt{ {x}^{2} + {y}^{2} } })^{3} = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{ \frac{3}{2} } = 4xy \\ = > {( {x}^{2} + {y}^{2} })^{3} = 16 {x}^{2} {y}^{2} [/tex]
Please mark me as Brainliest
Which rules define the function graphed below? (15 points cuz I'm stumped)
y=2x+3; y=-1/3x+3
y=2x; y=-1/3x
y=3x+2; y=3x-1
y=-3x+3; y=x+3
Answer: Choice A
y=2x+3; y=-1/3x+3
==================================================
Explanation:
The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that [tex]x \le 0[/tex] but I'll set that aside for the other portion).
The right portion is the line y = -1/3x + 3 and it's only graphed when [tex]x \ge 0[/tex]
So we could have this piecewise function
[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}[/tex]
Or we could easily swap the "or equal to" portion to move to the first part instead like this
[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}[/tex]
Either way, we're involving the equations mentioned in choice A
