SAT High School

You deposit $2200 into three separate bank accounts that each pay 3% annual interest. How much interest does each
account earn after 6 years?

Answers

Answer 1
396.
Basically just multiply $2200 By 3% and six years to find your answer. Hope I helped! :D

Related Questions

Write a scientific explanation describing if the night sky looks the same all year.


claim:


evedince:


resoning:

Answers

Answer:

The night sky is different at different times of the year. You see different constellations every now and then. This change is due to the motion of the Earth in its orbit around the Sun. Each day a few stars are visible in the east that were not visible the night before.

Explanation:

Who is required by the GDL law to wear a seat belt in the vehicle?

Answers

Answer:

Humans

Explanation:

Order smallest to biggest 7, -18, -15, 1, 7, -7, 14, -10, -11

Answers

Answer:

1,7,7,7,10,11,14,15,18

Answer:

-18, -15, -14,-11, -10, -7,1,7,7

Explanation:

If 2(−3x+c)=−3(2c2+cx)c+5c, what is the value of x in terms of c?

Answers

Answer:x-264.62

Explanation:you can set up a proportion

16.0/130 = x/2150

by cross multiplying you get

130x = 34400

divide by 130 and get

x-264.62

The value of the variable x in terms of c will be x = (7c − 6c³) / (3c² − 6).

What is the solution to the equation?

The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.

Making anything easier to accomplish or comprehend, as well as making it less difficult, is the definition of simplification.

The equation is given below.

2(−3x + c) = −3(2c² + cx)c + 5c

Simplify the equation for x, then the equation will be

2(−3x + c) = −3(2c² + cx)c + 5c

−6x + 2c = −6c³ − 3c²x + 5c

3c²x − 6x = 2c + 5c − 6c³

(3c² − 6)x = 7c − 6c³

x = (7c − 6c³) / (3c² − 6)

The value of the variable x in terms of c will be x = (7c − 6c³) / (3c² − 6).

More about the solution of the equation link is given below.

https://brainly.com/question/545403

#SPJ6

What date is UCLA’s deadline for their regular applications for the 2019-2020 school year?

Answers

Answer:

you can submit them from November 1 to November 30 but they open at August 1

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