Write the rule that describes the first transformation?
RED —> BLUE

Answer:

10, 8, 6, 4, 2, ...

Step-by-step explanation:

For this problem, you were given the recursive rule. The recursive rule consists of an equation that represents how the former term is modified to get the current term and the first term of the sequence. F(1) means the first term; in this case, the first term is 10. The equation in the rule shows that 2 is subtracted from the last term to get the current term. This means that the common difference is -2 and each term decreases by 2. Therefore, the last option, 10, 8, 6, 4, 2, ..., is correct.

Answer:

1st blank=[tex]y_{1}[/tex]

2nd blank=[tex]x_{1}[/tex]

3rd blank= [tex]y_{2}[/tex]

3*27=81

so 1*[tex]y_{1}[/tex]=81

hence [tex]y_{1}[/tex]=81

9* [tex]x_{1}[/tex]= 81

[tex]x_{1}[/tex]=9

27*[tex]y_{2}[/tex]=81

[tex]y_{2}[/tex]=3

Thus solved.

Hope this helps.

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The number of new professors needed to hire to keep the ratio of students and professors the same is 16.66  professors.

Given,

A small college has 1200 students and 80 professors.

The college is planning to increase enrollment to 1450 students next year.

We need to find how many new professors should be hired to keep the

ratio of students to professors the same.

If the two ratios are the same then we called it that they are in proportion.

Example:

4/6 = 10/15

2/3 = 2/3

Find the ratio between the students and professors before the increase in enrollment.

= Number of students / Number of professors

= 1200 / 80

Dividing by 8

= 150 / 10

= 15 / 1

This means one professor for 15 students.

Find the number of students after the increase in enrollment.

= 1450

Find the number of new students enrolled.

= 1450 - 1200

= 250

Since the ratio between the students and professor is 15 students for one professor.

For 250 new students, the number of new professors we need is:

= 250 ÷ 15

= 16.66

This means we need around 16.66 new professors.

Thus the number of new professors needed to hire to keep the ratio of students and professors the same is 16.66 professors.

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Answer:

Step-by-step explanation:

[tex]f(x) = \frac{4}{x}\\\\f(a) = \frac{4}{a}\\\\f(a+h) = \frac{4}{a+h}\\\\\frac{f(a+h) - f(a)}{h} = \frac{\frac{4}{a+h} - \frac{4}{a}}{h}[/tex]

                [tex]=\frac{\frac{4(a)}{(a+h)a} - \frac{4(a+h)}{a(a+h)}}{h}\\\\=\frac{\frac{4a - 4a - 4h}{a(a+h)}}{h}\\\\=\frac{\frac{ - 4h}{a(a+h)}}{h}\\\\= \frac{-4h}{a(a+h) \times h}\\\\= -\frac{4}{a(a+h)}\\\\[/tex]

Answer:

Step-by-step explanation:

Your equation is weird. The position equation for this situation is

[tex]s(t)=-4.9t^2+15t+7[/tex] and set it equal to 0 to solve for the time it takes to hit the ground. Those times come out to be

t = 3.47 sec and t = -.411 sec. But since time can never be negative, our time is 3.47 seconds

(What is that -52?)

Answer:

It is indeed y = -4x

Step-by-step explanation:

We see that for every increase of 1 in the x direction, y goes down 4.

Pay attention to the scales of the x and y axes.

Slope = rise/run

we rise -4 and run 1.

so the slope is -4/1 = -4

The y-intercept is at (0,0)

So the equation is y = -4x

Answer:

Hypergeometric

Kindly check explanation

Step-by-step explanation:

For a hypergeometric distribution, the following conditions must be met :

1.) The total number of samples must be fixed.

2.) Sample size will be a portion of the population

3.) The probability of success changes per trial. This is because sampling is done without replacement

The above scenario meets the condition described:

Total number of samples = 210

Sample size, n = 10

Blue balls = 200 ; red balls = 10

P(10 red balls)

Using the hypergeometric distribution function and the calculator :

X ~ H(n, N, M)

X ~ (10, 200, 210) = 0.6072

Answer:

8/15

Step-by-step explanation:

Answer:

8/15

Step-by-step explanation:

when you divide 8/15 its 0.53

Answer:

Step-by-step explanation:

Arrival rate = ∧ = 2.2 customers per hour  

Service rate = u = 5 customers per hour  

1. Probability that one customer is receiving a haircut and one customer is waiting  

P(2 customers)=(∧/u)^2 * (1-∧/u)=(2.2/5)^2 * (1-2.2/5)=0.1936*0.56= 0.108416

2. Probability that one customer is receiving a haircut and two customers are waiting  

P(3 customers)= (∧/u)^3 * (1-∧/u)=(2.2/5)^3 * (1-2.2/5)= 0.085184  

* 0.56= 0.04770304

3. Probability that more than two customers are waiting  

P(more than 3 customers)=1- P(less than 3 customers) =  

1- [P(0)+P(1)+P(2)+P(3)]=  

= 1- [(1-2.2/5) +2.2/5*(1- 2.2/5) + 0.108416+0.04770304]=1-0.9625=0.0375

Answer:

Charge for each bag = 0.65

Step-by-step explanation:

Let the cost of 1 bag be = x

Bags             Cost

750               375.00

 1                     x

[tex]\frac{750}{1} = \frac{375}{x}\\\\x \times 750 = 375 \times 1\\\\x = \frac{375}{750} = 0.50[/tex]

Therefore, the amount Jose paid for each bag = 0.50

He is going to sell each bag for 0.15 more than he paid,

that is , 0.50 + 0.15 = 0.65

Answer:

The standard error of your estimate of the average height in the city is 0.5 inches.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

You begin by collecting the heights of a random sample of 196 people from the city.

This means that [tex]n = 196[/tex]

The standard deviation of the heights in your sample is 7 inches.

This means that [tex]\sigma = 7[/tex]

The standard error of your estimate of the average height in the city is

[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{7}{\sqrt{196}} = 0.5[/tex]

The standard error of your estimate of the average height in the city is 0.5 inches.

Step-by-step explanation:

[tex]G(t) =\displaystyle \int (4 + t + t^2)dt[/tex]

[tex]\:\:\:\:\:\:\:=4t + \frac{1}{2}t^2 + \frac{1}{3}t^3 + C[/tex]

Check:

[tex]\dfrac{d}{dt}(4t + \frac{1}{2}t^2 + \frac{1}{3}t^3+C)= 4 + t + t^2 =g(t)[/tex]

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

↦∠ 3, ∠ 2, ∠ 6, ∠ 5 are the exterior angles in this figure.

↦ They aren't located inside the figure like ∠ 1 & ∠ 4, so they are exterior angles.

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

Answer:

Mean = 33.31

Median = 26

Mode = 17

Step-by-step explanation:

Given the data:

32 44 25 66 27 12 62 9 51 4 17 50 35 99 30 21 12 53 25 2 18 24 84 30 17 17

Reordered data : 2, 4, 9, 12, 12, 17, 17, 17, 18, 21, 24, 25, 25, 27, 30, 30, 32, 35, 44, 50, 51, 53, 62, 66, 84, 99

The mean, xbar = Σx / n = 866 /26 = 33.31

The median = 1/2(n+1)th term

Median = 1/2(27)th term = 13.5th term

Median = (13 + 14)th / 2

Median = (25 + 27) / 2 = 26

The mode = 17 (highest frequency)

Answer:

Step-by-step explanation:

Answer:

[tex]y=(x-7)^2-1[/tex]

Step-by-step explanation:

We want to convert the equation:

[tex]\displaystyle y=x^2-14x+48[/tex]

Into vertex form, given by:

[tex]\displaystyle y=a(x-h)^2+k[/tex]

Where a is the leading coefficient and (h, k) is the vertex.

There are two methods of doing this. We can either: (1) use the vertex formulas or (2) complete the square.

Method 1) Vertex Formulas

Let's use the vertex formulas. First, note that the leading coefficient a of our equation is 1.

Recall that the vertex is given by:

[tex]\displaystyle \text{Vertex}=\left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)[/tex]

In this case, a = 1, b = -14, and c = 48. Find the x-coordinate of the vertex:

[tex]\displaystyle x=-\frac{(-14)}{2(1)}=7[/tex]

To find the y-coordinate, substitute this value back into the equation. Hence:

[tex]y=(7)^2-14(7)+48=-1[/tex]

Therefore, our vertex (h, k) is (7, -1), where h = 7 and k = -1.

And since we already determined a = 1, our equation in vertex form is:

[tex]\displaystyle y=(x-7)^2-1[/tex]

Method 2) Completing the Square

We can also complete the square to acquire the vertex form. We have:

[tex]y=x^2-14x+48[/tex]

Factor out the leading coefficient from the first two terms. Since the leading coefficient is one in this case, we do not need to do anything significant:

[tex]y=(x^2-14x)+48[/tex]

Now, we half b and square it. The value of b in this case is -14. Half of -14 is -7 and its square is 49.

We will add this value inside the parentheses. Since we added 49 inside the parentheses, we will also subtract 49 outside to retain the equality of the equation. Hence:

[tex]y=(x^2-14x+49)+48-49[/tex]

Factor using the perfect square trinomial and simplify:

[tex]y=(x-7)^2-1[/tex]

We acquire the same solution as before, with the vertex being (7, -1).

Step-by-step explanation:

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Answer:

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Answer:

C. -1.5 < -0.5

Step-by-step explanation:

On a number line, the farther a number is to the right away from 0, the greater the number. While the farther it is from 0 to the left, the smaller it is.

Thus, the out of the options given, the only inequality given that is true is:

-1.5 < -0.5

This is because, -1.5 on the numberline is farther away to the left from 0 than -0.5. therefore, -1.5 is lesser than -0.5.

Answer:

[tex]{ \tt{2x + 4y = 8 - - - (a)}} \\ { \tt{x = 3y - 6 - - - (b)}} [/tex]

Substitute for x in equation (a) :

[tex]{ \tt{2(3y - 6) + 4y = 8}} \\ { \tt{6y - 12 + 4y = 8}} \\ { \tt{10y = 20}} \\ y = 2[/tex]

Substitute for y in equation (b) :

[tex]{ \tt{x = (3 \times 2) - 6}} \\ x = 0[/tex]

2x+4y =8

x=3y-6 ——> x–3y=–6

x–3y = – 6 ] ×(–2) ——> –2x +6y=12

2x+4y=8

–2x+6y =12

__o_o____

0+10y=20 —> 10y= 20 —> y= 20/10 —> y= 2

2x+4y=8 —> 2x + 4(2) = 8 —> 2x + 8=8 —> 2x = 0 —> x=0

(x,y) —> (0,2)

Answer:

b) - 3

Step-by-step explanation:

If x = -3 , then

x + 3 = -3 + 3 = 0

So, denominator would become 0. So , anything divided by 0 is undefined

Answer:

Step-by-step explanation:

From the picture attached,

m∠COB = 90° - m∠BOS

              = 90° - 40°

              = 50°

tan(30°) = [tex]\frac{AC}{OC}[/tex]

[tex]\frac{1}{\sqrt{3}}=\frac{AC}{OC}[/tex]

AC = [tex]\frac{OC}{\sqrt{3}}[/tex]  ------(1)

Similarly, tan(50°) = [tex]\frac{BC}{OC}[/tex]

BC = OC[tan(50°)] -------(2)

Now AC + BC = 30 cm

By substituting the values of AC and BC from equation (1) and (2),

[tex]\frac{OC}{\sqrt{3}}+OC(\text{tan}50)=30[/tex]

(1.769)OC = 30

OC = 16.96

1). cos(30°) = [tex]\frac{OC}{AO}[/tex]

[tex]\frac{\sqrt{3}}{2}= \frac{16.96}{OA}[/tex]

[tex]OA=19.58[/tex] cm

Therefore, distance between the ship and town A is 19.58 cm.

2). cos(50°) = [tex]\frac{OC}{OB}[/tex]

0.6428 = [tex]\frac{16.96}{OB}[/tex]

OB = 26.38 cm

Therefore, distance between the ship and town B is 26.38 cm.

Step-by-step explanation:

a the rate of changes = (185-146)/30

= 1.3° /minutes.

after 45 minutes = 1.3 ×45 = 58.5°

so, the temperature = 185 - 58.5

= 126.50°F

b. the time to reach 100°F =

(185-100)/ (1.3)

= 85/(1.3) = 65.38

after 65.38 minutes

Answer:

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Answer:

the graph looks like this:-

Step-by-step explanation:

for inequality 1

if we take x = 0 we get y = -4

and if we take y =0 we get x = 16

so we get 2 points (0, -4) and (16, 0) and the graph must pass thru these two.

now checking if the origin satisfies the inequality or not

take x and y = 0

0 + 0 is not greater than or equal to -16

so origin doesn't satisfy the inequality.

shade the graph on the side, of the line, opposite to where the origin is.

for inequality 2

if we take x = 0 we get y = 2

and if we take y =0 we get x = -⅔

so we get 2 points (0, 2) and (-⅔, 0) and the graph must pass thru these two.

the line should be a dotted line.

now checking if the origin satisfies the inequality or not

take x and y = 0

0 + 0 is less than 2

so origin satisfies the inequality.

shade the graph on that side of the line where the origin is.

[ red line shows graph 1 whereas the blue dotted line represents graph ]

Answer:

247372

Step-by-step explanation:

two hundreds forty seven thousand, three hundred and seventy two

The number of weddings in the UK in numerical form will be 247,372.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

Last year there were two hundred and forty-seven thousand, three hundred and seventy-two weddings in the UK.

Convert the statement into a number. Then we have

⇒ 247,372

The number of weddings in the UK in numerical form will be 247,372.

More about the Algebra link is given below.

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Answer:

(3 × 3) - (3 ÷ 3) = 8

Step-by-step explanation:

We want to find an expression that when solved will be equal to 8.

But we are restricted to using only the number "3" four times with any Maths operation.

Thus let's try;

(3 × 3) - (3 ÷ 3) = 9 - 1 = 8

Answer:

85 mi

Step-by-step explanation:

Let d = the distance in miles traveled

Let M = the time in hours for Maria to travel d miles

[tex]m+\frac{3}{4} =[/tex] time in hours for Ricky to travel d miles

(Note that [tex]\frac{3}{4}[/tex] hrs = 45 min)

----------------------

Maria's equation:

d = 51m

Ricky's equation:

d = 24 · [tex](m+\frac{3}{4} )[/tex]

----------------------

Substitution:

51m = 24 · [tex](m+\frac{3}{4} )[/tex]

51m = 24m + 45

6m = 10

m = [tex]\frac{5}{3}[/tex]

----------------------

d = 51m

d = 51 · [tex](\frac{5}{3})[/tex]

d = 85

----------------------

The distance traveled is 85 mi

If it takes Ricky, traveling at 24 mph, 45 minutes longer to go a certain distance than it takes Maria traveling at 51 mph, the distance traveled is 85 miles

Speed is the ratio of distance traveled to time taken. Mathematically:

Distance = Speed/Time

According to the given question:

Set up the Maria equation:

d = 51m

Set up Ricky's equation:

d = 24 · (m+3/4)

Substitute

51m = 24 · (m+3/4)

51m = 24m + 45

6m = 10

m = 5/3

Determine the required distance

d = 51m

d = 51 · 5/3

d = 85

Hence the distance traveled is 85 mile

Learn more on distance and speed here: https://brainly.com/question/26046491

Answer:

[tex]\implies \dfrac{2}{10}< \dfrac{3}{10} [/tex]

Step-by-step explanation:

We need to compare the given two fractions .The given fractions are ,

[tex]\implies \dfrac{3}{10} [/tex]

[tex]\implies \dfrac{1}{5} [/tex]

Firstly let's convert them into like fractions . By multiplying 1/5 by 2/2 . We have ,

[tex]\implies \dfrac{1}{5} =\dfrac{1*2}{5*2}=\dfrac{2}{10} [/tex]

Now on comparing 2/10 and 3/10 we see that ,

[tex]\implies 2< 3 [/tex]

Therefore ,

[tex]\implies \dfrac{2}{10}< \dfrac{3}{10} [/tex]