Write the equation in standard form.
x2 + 6 = 5x

Answer:

72 in. sq.

Step-by-step explanation:

6 x 6 = 36

6 x 6 = 36 / 2 = 18

6 x 6 = 36 / 2 = 18

18 + 18 + 36 = 72.

Hope this helps!

If there is something wrong just let me know.

Answer:

The slope, m is -3

[tex]{ \tt{ = \frac{3 - 0}{0 - 1} }} \\ = - 3[/tex]

The y-intercept is b = 3

Symbol of inequality:

[tex]{ \tt{x \geqslant 1}} \\ or : \\ { \tt{y \geqslant 3}}[/tex]

Step-by-step explanation:

a)

For each value of x, we need to solve for y.

Our equation is x² -2. This means that we multiply x by itself ( x * x = x²), and then subtract that value by 2.

Here is a list of the unfilled answers:

x = -2:

-2²-2 = -2 * -2 -2 = 4-2 = 2. -2 * -2 = 4 because two negatives multiplied together makes a positive.

x=-1:

-1²-2 = 1 -2 = -1

x=1

1²-2 = 1-2= -1

x=3:

3²-2  = 9-2 = 7

b)

In this graph, the y represents the vertical part and x represents the horizontal. For each value of y, there is a horizontal line that can be drawn. For example, when y=0, the bolded horizontal line near the bottom of the graph represents that. We then need to find the points on the line representing x²-2 where it touches the horizontal line of y=0. This happens when x=-1.5 and x=1.5, as it is between the positive/negative 1 and 2 values of x

Answer:

Assuming the base number is 1, if it becomes 5 then it is stretched. If the number become 1/5(less than 1) it is called compressed.

Step-by-step explanation:

Answer:

sorry I don't know the answer

Answer:

For the equation y=log(x-k), the domain depends on the value of K. Sliding K moves the left bound of the domain interval. The range and the right end behavior stay the same. For the equation y=log x+k, the domain is fixed, starting at an x-value of 0. The vertical asymptote is also fixed. The range of the equation depends on K.

Step-by-step explanation:

Answer:

There is significant evidence to conclude that carina e in New section is greater than 42.3

Step-by-step explanation:

Given :

Sample variance, s² = 48.3

Population variance, σ² = 42.3

Sample size, n = 28

α = 0.05

The hypothesis :

H0 : σ² = 42.3

H0 : σ² > 42.3

The test statistic, χ² : (n-1)*s²/σ²

χ² = [(28 - 1) * 48.3] / 42.3

χ² = (27 * 48.3) / 42.3

χ² = 1304.1 / 42.3

χ² = 30.829787

χ² = 30.830

The Critical value at α = 0.05 ; df = (28-1) = 27

Critical value(0.05, 27) = 27.587

Reject H0 if χ² statistic > Critical value

Since, 30.830 > 27.587 ; Reject H0 ; and conclude that variance in the new section is greater than 42.3

Answer:

I think the power is 4

Step-by-step explanation:

480J / 120 = 4

Put 2 mins into seconds which is 120 seconds

Sorry if it is wrong :)

Answer:

[tex]4\text{ watts}[/tex]

Step-by-step explanation:

In physics, the power of a machine is given by [tex]P=\frac{W}{\Delta t}[/tex], where [tex]W[/tex] is work in Joules and [tex]\Delta t[/tex] is time in seconds.

Convert 2 minutes into seconds:

2 minutes = 120 seconds.

Substitute [tex]W=480[/tex] and [tex]\Delta t=120[/tex] to solve for [tex]P[/tex]:

[tex]P=\frac{480}{120}=\boxed{4\text{ watts}}[/tex]

Answer:

5 cm

Step-by-step explanation:

V = l*w*h

360 = l*8*9

360= 72l

Divide each side by 72

360/72 = 72l/72

5=l

Answer:

[tex]length = 5cm[/tex]

Step-by-step explanation:

[tex]volume \: = l \times b \times h \\ l = \frac{v}{b \times h} \\ l = \frac{360 {cm}^{3} }{9cm \times 8cm} \\ l = \frac{360}{72} \\ l = 5cm[/tex]

Hope this helps you.

have a nice day!

Answer:

x = -1/2

Step-by-step explanation:

log x 9 = log x (3)² = 2log x ( 3 ) = 2×1/4 =1/2

Answer:4 ma boi

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

because I am god at meth and very smart

Answer:

A --> y=cot(x)

Step-by-step explanation:

if you graph tan(x), it has a period of just PI, because tan(x) is just sin(x)/cos(), and cot(x) is the same because it is just sec(x)/csc(x).

Answer:The value of x is 4.

Step-by-step explanation:

Given : Expression  .

To find : Solve for x ?

Solution :

Applying exponential property,  

Comparing the base,

Step-by-step explanation:

Answer:

a) Hence the probability that the average test score in the class of size 25 exceeds 80.

P ( X > 74) = 0.9838

P ( Z > 2.14) = 0.0162

b) Hence the probability that the average test score for the class of size 64

P ( X > 74) = 0.9838

P ( Z > 2.14) = 0.0003

c) Probability of the difference exceeding 2.2 = 0.9936

P (Z < 2.49) = 0.0064

Step-by-step explanation:

Let's assume a normal distribution.

Now,

a) For a class of 25

[tex]P ( X > 74) = P (Z > 80 - 74/ 14\sqrt(25) )\\\\= P (Z < 6 / 2.8)\\\\= P ( Z < 2.14)\\= 0.9838\\[/tex]

[tex]P ( Z > 2.14) = 1- 0.9838\\= 0.0162[/tex]

b)

Similarly:

For the class of 64

[tex]P ( X > 74) = P (Z > 80 - 74/ 14\sqrt(64) )\\\\= P (Z < 6 / 1.75)= P ( Z < 3.428)\\= 0.9838\\[/tex]

[tex]P ( Z > 2.14) = 1- 0.9997\\= 0.0003[/tex]

c) Probability of the difference exceeding 2.2

[tex]= P (Z > 2.2/\sqrt{14 * {(1/25) + (1/64}\\[/tex]

[tex]= P (Z > 2.49)\\= 0.9936[/tex]

P (Z < 2.49)

= 1 - 0.9936

= 0.0064

Answer:

x = 2 - sqrt(19/6)

x = 2 + sqrt(19/6)

Step-by-step explanation:

Answer:

add 4

subtract 24 from 5

2

Step-by-step explanation:

Answer:

Step-by-step explanation:

I dont know wish I could help, srry.

Answer:

the number before the first variable (first term)

Step-by-step explanation:

this appears to be an incomplete question. The numerical coefficient of a term is the number before the variable.

the constant is the number without a variable.

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

[tex](a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) = Q(x)[/tex]  is a differential equation.

If [tex]Q(x) \neq 0[/tex]

It is non homogeneous then,

The general solution  = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution =  complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

[tex]$(2D^3+15D^2+24D+11)y=0$[/tex]

Auxiliary equation,

[tex]$2m^3+15m^2+24m +11 = 0$[/tex]

-1  | 2    15    24     11

    | 0   -2    - 13    -11  

      2    13    11       0

∴ [tex]2m^2+13m+11=0[/tex]

The roots are

[tex]$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$[/tex]

[tex]$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$[/tex]

[tex]$=\frac{-13\pm9}{4}$[/tex]

[tex]$=-5.5, -1$[/tex]

So, [tex]m_1, m_2, m_3 = -1, -1, -5.5[/tex]

Then the general solution is :

[tex]$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$[/tex]

Answer:

esta padre tu pregunta si que bueno

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (- 4, 2 ) into the partial equation

2 = - 8 + c ⇒ c = 2 + 8 = 10

y = 2x + 10 ← equation of line

स्ज्द्ज्ज्ग्जेज्दिविफ्ज्र्ज्स्ज्स्ज्ग्झ्क्व्जेफिक

9514 1404 393

Answer:

Step-by-step explanation:

Two integer factors of 20 that differ by 8 are 2 and 10.

The garden is 10 feet long and 2 feet wide.

Answer:

The numerical limits for a C grade are 60.6 and 69.1.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 67 and a standard deviation of 7.3.

This means that [tex]\mu = 67, \sigma = 7.3[/tex]

Find the numerical limits for a C grade.

Below the 100 - 38 = 62th percentile and above the 18th percentile.

18th percentile:

X when Z has a p-value of 0.18, so X when Z = -0.915.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.915 = \frac{X - 67}{7.3}[/tex]

[tex]X - 67 = -0.915*7[/tex]

[tex]X = 60.6[/tex]

62th percentile:

X when Z has a p-value of 0.62, so X when Z = 0.305.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]0.305 = \frac{X - 67}{7.3}[/tex]

[tex]X - 67 = 0.305*7[/tex]

[tex]X = 69.1[/tex]

The numerical limits for a C grade are 60.6 and 69.1.

9514 1404 393

Answer:

Step-by-step explanation:

Let x represent the amount invested at 8%. Then the total interest earned is ...

  0.06(7000 -x) +0.08x = 480

  420 +0.02x = 480 . . . . . . . . . eliminate parentheses

  0.02x = 60 . . . . . . . . . . subtract 420

  x = 60/0.02 = 3000 . . . . . divide by the coefficient of x

$3000 was invested at 8%; $4000 was invested at 6%.

Answer:

f(2) = 13.6

Step-by-step explanation:

Using the recursive formula and f(1) = 4 , then

f(2) = 0.4 f(1) + 12 = (0.4) × 4) + 12 = 1.6 + 12 = 13.6

Answer:

Exactly 16%.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean of a certain set of measurements is 27 with a standard deviation of 14.

This means that [tex]\mu = 27, \sigma = 14[/tex]

The proportion of measurements that is less  than 13 is

This is the p-value of Z when X = 13, so:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{13 - 27}{14}[/tex]

[tex]Z = -1[/tex]

[tex]Z = -1[/tex] has a p-value of 0.16, and thus, the probability is: Exactly 16%.

Yes, The collection of nice Nepali songs is a set​.

A set is a collection of items where there are operations such as:

Union of sets, the intersection of sets, and the complement of sets.

We have,

A set would have a finite or infinite number of elements, depending on the number of songs in the collection.

Nepali songs refer to a specific, well-defined collection of songs that satisfy certain criteria (such as being popular, culturally significant, or critically acclaimed).

so,

It can be considered a set.

Thus,

Yes, The collection of nice Nepali songs is a set​.

Learn more about sets here:

https://brainly.com/question/8053622

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