Answer:
Volume of stock solution needed = 6.0299 mL
Explanation:
Dilution consists of lowering the amount of solute per unit volume of solution. It is achieved by adding more diluent to the same amount of solute.
This is deduced when thinking that both the dissolution at the beginning and at the end will have the same amount of moles.
Data:
M1 = 6.01 M stock solution concentration
M2 = 0.3624 M diluted solution concentration
V2 =100 mL diluted solution volume
V1 = ? stock solution volume
M1 * V1 = M2 * V2
[tex]V1=\frac{M2*V2}{M1} =\frac{0.3624M*100mL}{6.01M} =6.0299 mL[/tex]
a fertilizer manufacturer makes a batch of 20kg of ammonium nitrate. what mass of ammonia in kg, does the manufacturer need to start with?
Answer:
[tex]m_{NH_3}=4.25kgNH_3[/tex]
Explanation:
Hello,
In this case, for the production of ammonium nitrate we shall consider the following chemical reaction:
[tex]NH_3+HNO_3\rightarrow NH_4NO_3[/tex]
Hence, since the molar mass of ammonium nitrate is 80 g/mol and the molar mass of ammonia is 17 g/mol, we could compute the required mass of ammonia to produce 20 kg of ammonium nitrate by using kilo-based units:
[tex]m_{NH_3}=20kgNH_4NO_3*\frac{1kmol}{80kgNH_4NO_3}*\frac{1kmolNH_3}{1kmolNH_4NO_3}*\frac{17kgNH_3}{1kmolNH_3} \\\\m_{NH_3}=4.25kgNH_3[/tex]
Best regards.
The tribute states of the ancient Aztec empire
were governed directly by the emperor.
made regular payments to the emperor.
acted as powerful independent city-states.
O surrounded the main Aztec city-state.
Answer:
made regular payments to the emperor.
Explanation:
The Aztec Empire was an alliance of three states: Mexico-Tenochtitlan, Texcoco, and Tlacopan. The area in and around the Valley of Mexico was ruled by these three city-states from 1428 to 1521. The state religion of the empire was polytheistic. The tribute states of the ancient Aztec empire made regular payments to the emperor.
Answer:
B
Explanation:
Identifying the Body's Responses to
Quick
Check
Which type of response identifies a specific pathogen in the body?
A(n)
response
Answer:
Specific Immune Response
Explanation:
A specific immune response identifies the pathogen which then allows it to produce antibodies that protect against that SPECIFIC pathogen.
Answer:
immuneExplanation:
what is the reaction?
Answer:
A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products. ... A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.
Explanation:
Hopefully this is what you needed
An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0 L tank?
Answer:
1.2 atm
Explanation:
Given data
Volume of the gas in the tank (V₁): 200.0 LPressure of ethylene gas in the tank (P₁): ?Volume of the gas in the torch (V₂): 300 LPressure of the gas in the torch (P₂): 0.8 atmIf we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.
[tex]P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm[/tex]
What is another term for anode?
Answer:positive electrode
Explanation:
Anode can also be referred to as positive electrode in a cell
which is a type of heat transfer that causes the air at the top floor of a building to be hotter than the bottom floor of a building
Answer: I believe it's convection
Good luck and I hope this helps!!
Answer: Convection
Explanation: Edge
Which of the following is not an indication of a chemical change?
A. Fracture Formation
B. Energy transfer
C. Precipitate formation.
D. Gas production
Answer:
C. precipitate formation.
Explanation:
options C is correct answer.
Answer:
C. precipitate formation.
Explanation:
2C 2 H 6 +7O 2 ***>4CO 2 +6H 2 O if 7.0 g of C 2 H 6 react with 18 g of O 2 , how many grams of water will be produced
Answer:
grams H₂O produced = 8.7 grams
Explanation:
Given 2C₂H₆(g) + 7O₂(g) => 4CO₂(g) + 6H₂O(l)
7g 18g ?g
Plan => Convert gms to moles => determine Limiting reactant => solve for moles water => convert moles water to grams water
Moles Reactants
moles C₂H₆ = 7g/30g/mol = 0.233mol
moles O₂ = 18g/32g/mol = 0.563mol
Limiting Reactant => (Test for Limiting Reactant) Divide mole value by respective coefficient of balanced equation; the smaller number is the limiting reactant.
moles C₂H₆/2 = 0.233/2 = 0.12
moles O₂/7 = 0.08
Limiting Reactant is O₂
Moles and Grams of H₂O:
Use Limiting Reactant moles (not division value) to calculate moles of H₂O.
moles H₂O = 6/7(moles O₂) = 6/7(0.562) moles H₂O = 0.482 mole H₂O yield
grams H₂O = (0.482mol)(18g·mol⁻¹) = 8.7 grams H₂O
Which shows an isomer of the molecule below?
Answer:
D
Explanation:
An isomer is a molecule with the same number of atoms as another compound, but they differ in arrangement of the atoms.
Answer:
D
Explanation:
A P E X
Plants remove carbon to the atmosphere during
Answer:
respiration
Explanation:
Plants give out carbon dioxide not only at night but during the day too. It happens because of the process of respiration in which plants take in oxygen and give out carbon dioxide. As soon as the sun rises another process called photosynthesis starts, in which carbon dioxide is taken in and oxygen is given out.
Plants use photosynthesis to capture carbon dioxide and then release half of it into the atmosphere through respiration. Plants also release oxygen into the atmosphere through photosynthesis
Question 17 In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce gaseous ammonia. This reaction is now the first step taken to make most of the world's fertilizer. Suppose a chemical engineer studying a new catalyst for the Haber reaction finds that 786. liters per second of dinitrogen are consumed when the reaction is run at 222.°C and 0.35atm. Calculate the rate at which ammonia is being produced. Give your answer in kilograms per second. Round your answer to 2 significant digits.
Answer:
Explanation:
N₂ + 3H₂ = 2 NH₃
1 vol 2 vol
786 liters 1572 liters
786 liters of dinitrogen will result in the production of 1572 liters of ammonia
volume of ammonia V₁ = 1572 liters
temperature T₁ = 222 + 273 = 495 K
pressure = .35 atm
We shall find this volume at NTP
volume V₂ = ?
pressure = 1 atm
temperature T₂ = 273
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
[tex]\frac{.35\times 1572}{495} =\frac{1\times V_2}{ 273 }[/tex]
[tex]V_2 =303.44[/tex] liter .
mol weight of ammonia = 17
At NTP mass of 22.4 liter of ammonia will have mass of 17 gm
mass of 303.44 liter of ammonia will be equal to (303.44 x 17) / 22.4 gm
= 230.28 gm
=.23 kg / sec .
Rate of production of ammonia = .23 kg /s .
Use the nuclear decay reaction in the picture to answer the following question.
i. How does the reaction demonstrate the laws of conservation of charge and conservation of nucleon number?
ii. What is the binding energy of one mole of atomic mass: 234, number of proton: 90, Thorium if the mass defect is 1.908 g/mol?
Answer:
1a. Both sides of the decay reaction have the same charge.
b. The number of nucleons on both sides are the same.
2. The binding energy of one mole of the atom is 17.172 × [tex]10^{16}[/tex] J.
Explanation:
1a. Considering the two sides of the decay reaction and with respect to the law of conservation of charge, it can be observed that both sides have the same charge. Charge can not be created or destroyed in the process.
b. The number of nucleons on both sides are equal. No nucleon is created or destroyed in the process.
2. Binding energy is the minimum energy required to separate an atom into its nucleons. From Einstein's energy equation;
E = Δm[tex]c^{2}[/tex]
Where E is the binding energy of the atom, Δm is the mass defect and c is the speed of light.
Given that: Δm = 1.908 g/mol and c = 3 × [tex]10^{8}[/tex]. So that:
E = 1.908 × [tex](3*10^{8}) ^{2}[/tex]
= 1.908 × 9 × [tex]10^{16}[/tex]
= 17.172 × [tex]10^{16}[/tex] J
The binding energy of one mole of the atom is 17.172 × [tex]10^{16}[/tex] J.
Please help! BRAINLIEST to correct answer!!!!
Answer:
Exothermic ProcessExplanation:
using the following balanced chemical equation: PCL5 -> PCL3 + CL2 and knowing that Keq = 7.9, [PCL3] = 0.054M and [CL2] = 0.34M
a. write the Keq expression for the reaction
b. find the [PCL5]
c circle the correct answer: the reaction favored is the (forward, reverse)
Answer:
see explanations
Explanation:
PCl₅ => PCl₃ + Cl₂
C(eq): [PCl₅] 0.054M 0.34M
a. Keq = [PCl₃][Cl₂]/[PCl₅]
b. 7.9 = (0.054)(0.34)/[PCl₅] => [PCl₅] = (0.054)(0.34)/(7.9) = 0.0023M
c. If [PCl₃] = 0.054M; [Cl₂] = 0.34M and [PCl₅] = 0.0023M then the reaction is at equilibrium and will not shift forward or in reverse. In order to determine if reaction is not at equilibrium, a set of concentration values needs to be given in problem, used to calculate Qeq and compared to the given Keq value. The following defines direction of shift ...
Keq < Qeq => rxn shifts left
Keq = Qeq => rxn is at equilibrium (no shift)
Keq > Qeq => rxn shifts right
NOTE: If Keq is listed first followed by Qeq in the above conditions, the inequality symbol indicates direction of shift.
What should happen if a good experiment is replicated?
The results will decrease.
The results will increase.
The results will be different.
The results will be similar.
Answer:
The results will be similar.
In the following reaction 6.13 g of water is actually produced, but the theoretical yield of water is 8.17 g. What is the percent yield of this reaction? *
85.0%
72.0%
75.0%
67.0%
Answer:
75.0%
Explanation:
Data obtained from the question. This includes the following:
Actual yield = 6.13g
Theoretical yield = 8.17g
Percentage yield =...?
The percentage yield can be obtain by using the following formula:
Percentage yield = Actual yield /Theoretical yield x 100
Percentage yield = 6.13/8.17 x 100
Percentage yield = 75.0%
Therefore, the percentage yield of water from the reaction above is 75.0%
A characteristic that describe a plant that can make its own food is
Answer:
Photosynthesis
this is correct
The percent yield of a reaction in which 52 grams of a reactant is expected to yield 30 grams of product is 25%. What is the actual yield of the reaction? A) 13 grams B) 120 grams C) 208 grams D) 7.5 grams
Answer:
D) 7.5 grams
Explanation:
Hello,
In this case, since the percent yield is defined by:
[tex]Y=\frac{m^{actual}}{m^{theoretical}} *100\%[/tex]
In such a way, since the percent yield is up to 25% and the expected or theoretical amount is 30 g of the product, the actual yield of the reaction is:
[tex]m^{actual}=\frac{Y*m^{theoretical}}{100\%} =\frac{25\%*30g}{100\%} \\\\m^{actual}=7.5g[/tex]
Therefore the answer is D) 7.5 grams.
Best regards.
If you start with 6 mol of nitrogen gas (N2+) what mass (g) of ammonia (NH4) will be produced?
Answer:
204g of NH3
Explanation:
The balanced equation for the reaction is given below:
N2 + 3H2 —> 2NH3
Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:
From the balanced equation above,
1 mole of N2 reacted to produce 2 moles of NH3.
Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.
Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:
Number of mole of NH3 = 12 moles.
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Mass of NH3 =..?
Mass = mole x molar mass
Mass of NH3 = 12 x 17
Mass of NH3 = 204g.
Therefore, 204g of NH3 will be produced from the reaction.
Creatinine, �!�!�!�, is a by-product of muscle metabolism, and creatinine levels in the body are known to be a fairly reliable indicator of kidney function. The normal level of creatinine in the blood for adults is approximately 1.0mg per deciliter (dL) of blood. If the density of blood is 1.025g/mL, calculate the molality of a normal creatinine level in a 10.0mL blood sample. What is the osmotic pressure (in atm) of this solution at 25.0°C?
Answer:
Explanation:
molecular weight of creatinine = 131
1 mg of creatinine = 1 x 10⁻³ / 131 = 7.63 x 10⁻⁶ mole of creatinine.
volume of solution = .1 L
mass of blood solution = .1 x 1025
= 102.5 g
mass of solvent = 102.5 g approximately
= .1025 kg
molality = mole of solute / mass of solvent in kg
= 7.63 x 10⁻⁶ / .1025 kg
= 74.44 x 10⁻⁶ .
Osmotic pressure :---
π V / T = nR π is osmotic pressure , V is volume of solution in liter , T is absolute temperature , n is molality .
π x .1 / 298 = 74.44 x 10⁻⁶ x .082
π = 18.19 x 10⁻³ atm
2. What happens to the pH when you add more H+ ions to a solution that has no buffers?
How is a niche different than a habitat?
A habitat is more than a physical place; it's a species' role in a specific place and it can change from niche to niche.
A niche is more than a physical place; it's a species' role in a specific place and it can change from habitat to habitat.
A niche and a habitat are the same.
A niche is just a physical place; a habitat is a species' role in a specific place.
Answer:
A niche is more than a physical place; it's a species' role in a specific place and it can change from habitat to habitat.
Explanation:
Niche: In biology, the term "niche" is described as a process through which different organisms tends to fit-in into a specific ecosystem or an ecological community. However, a niche is considered as the "evolutionary result" of a specific species behavioral, morphological, and physiological adaptations associated with its surroundings.
Habitat: In biology, the term "habitat" is described as an environmental or ecological area that is being inhabited by a specific species of plants, animals, or other organisms.
Therefore, a niche is entirely different from a habitat because an organism's niche tends to explain every different aspect of its life whereas its habitat explains the place it lives.
State whether the following is an example of a physical or chemical change:! 21. Burning a log: ________________________________! 22. Folding a piece of paper: _________________________! 23. Freezing water: _________________________! 24. Bending a copper wire. _________________________!
Answer:
Physical change
Explanation:
Because it doesn't require any chemical to change
Answer:
Physical change
Physical change
Physical change
Physical change
Explanation:
6. Find the partial pressures of the gases in a mixture with a total pressure of 101.3 kPa, if there are 7.8 mole of
Ng, 2.1 mole of 0, 0.090 mole of Ar, and 0.010 mol of Co,
3:20
5/10/2
19
110
112
Pause
break
16
X
14
&
*
A
%
7
9
5
6
O
8
4
{
о
Р
Answer:
Explanation:
Total mole of gases = 7.8 + 2.1 + .09 + .01 = 10
the partial pressures of the gases in a mixture
= mole fraction x Total pressure
mole fraction = mole of a gas in the mixture / total mole
partial pressure of Ng = [tex]\frac{7.8}{10} \times 101.3 kPa[/tex]
= 79.014 kPa
partial pressure of O = [tex]\frac{2.1}{10} \times 101.3 kPa[/tex]
= 21.273 kPa .
partial pressure of Ar = [tex]\frac{.09}{10} \times 101.3 kPa[/tex]
= .9117 kPa .
partial pressure of Co = [tex]\frac{.01}{10} \times 101.3 kPa[/tex]
= .1013 k Pa .
pls I need help with these ques. help plsssssssssssssss
Answer:
q1..no.2 and 4 are aromatic
Nitrogen gas was collected by water displacement. What was the pressure of the N2 collected if the temperature was 50 degrees celcius?
Answer:
Explanation:
Atmospheric pressure = 101.325 kPa
vapor pressure of water at 50°C = 12.332 kPa
pressure of N₂ = (Atmospheric pressure) - (vapor pressure of water at 50 oC)
pressure of N₂ = (101.325 kPa) - (12.332 kPa)
pressure of N₂ = 88.993 kPa
Therefore, the pressure of the N₂ collected if the temperature was 50 degrees celcius is 88.993 kPa0.5 moles of CO2 have a volume of 50 L and a pressure of 0.8210 atm. What must be the temperature of the gas?
Answer:
1000 K
Explanation:
Given data
Moles of carbon dioxide (n): 0.5 molesVolume of carbon dioxide (V): 50 litersPressure of carbon dioxide (P): 0.8210 atmospheresTemperature of carbon dioxide (T): ?We can find the temperature of carbon dioxide using the ideal gas equation.
[tex]P \times V = n \times R \times T\\T = \frac{P \times V}{n \times R} = \frac{0.8210atm \times 50L}{0.5mol \times \frac{0.08206atm.L}{mol.K} }=1000 K[/tex]
The temperature of the gas is 1000 K.
The first step that you will do in lab is to prepare approximately 20.0 mL each of the following solutions of NaOH, using the NaCl solution to dilute the concentrated (0.300 M) solution of NaOH. After you prepare each solution, transfer it to a clean 50 mL beaker on top of a labeled piece of paper. 0.200 M NaOH 0.150 M NaOH 0.100 M NaOH 0.050 M NaOH 0.025 M NaOH
Answer:
0.200 M NaOH: 13.3 mL of the concentrated solution and complete to 20.0mL
0.150 M NaOH: 10.0 mL of the concentrated solution and complete to 20.0mL
0.100 M NaOH: 6.67 mL of the concentrated solution and complete to 20.0mL
0.050 M NaOH: 3.33 mL of the concentrated solution and complete to 20.0mL
0.025 M NaOH: 1.67 mL of the concentrated solution and complete to 20.0mL
Explanation:
It is possible to prepare a solution from a more concentrated one. In the problem, the concentrated solution is 0.300M NaOH. Thus, to prepare 20.0mL of each of the solutions you will need:
0.200 M NaOH: 20.0mL × (0.200M / 0.300M) = 13.3 mL of the concentrated solution and complete to 20.0mL
The ratio between the concentrated solution and the solution you want to prepare is called "dilution factor"
0.150 M NaOH: 20.0mL × (0.150M / 0.300M) = 10.0 mL of the concentrated solution and complete to 20.0mL
0.100 M NaOH: 20.0mL × (0.100M / 0.300M) = 6.67 mL of the concentrated solution and complete to 20.0mL
0.050 M NaOH: 20.0mL × (0.050M / 0.300M) = 3.33 mL of the concentrated solution and complete to 20.0mL
0.025 M NaOH: 20.0mL × (0.025M / 0.300M) = 1.67 mL of the concentrated solution and complete to 20.0mL
In a titration, 100 mL of 0.026 M HCl (aq) is neutralized by 13 mL of KOH(aq). Calculate the molarity of KOH (aq).
Answer:
0.2M
Explanation:
Step 1:
Data obtained from the question.
Volume of acid (Va) = 100mL
Molarity of the acid (Ma) = 0.026 M
Volume of base (Vb) = 13mL
Molarity of the base (Mb) =..?
Step 2:
The balanced equation for the reaction. This is given below:
HCl + KOH —> KCl + H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 1
The mole ratio of the base (nB) = 1
Step 3:
Determination of the molarity of the base, KOH. This can be obtained as follow:
MaVa/MbVb = nA/nB
0.026 x100 / Mb x 13 = 1
Cross multiply to express in linear form
Mb x 13 = 0.026 x 100
Divide both side by 13
Mb = 0.026 x 100 / 13
Mb = 0.2M
Therefore, the molarity of the base, KOH is 0.2M
Answer:
0.2M
Explanation:
KOH(aq) + HCl(aq) ⇒ KCl(aq) + H2O(l)
We express the moles of analyte (HCl) and titrant based (KOH) on their molar concentration:
M1 * V1 = M2 * V2
The molarity of the solution is calculated with the following equation:
M2 = V1 x M1 / V2
Where:
V2 = valued sample volume
V1 = volume of titrant consumed (measured with the burette)
M1 = concentration of titrant solution
M2 = concentration of sample
M2 = 100mL * 0.026M / 13mL = 0.2M
