what needs to increase in order to make a substance more soluble?

Answers

Answer 1

By supplying more energy to counteract intermolecular interactions and increasing contact between solvent and solute, raising temperature, agitation, surface area, or lowering particle size can enhance solubility.

A substance's solubility refers to its capacity to dissolve in a solvent. Intermolecular forces between the solute particles are broken during the dissolving process, and new connections with the solvent molecules are created. Solubility can be raised by adding extra energy to break through these intermolecular connections. Although agitation and expanding surface area improve the contact between the solvent and solute, rising temperature releases more thermal energy to break the intermolecular interactions. By increasing surface area per unit volume, particle size reduction increases interaction with the solvent. Moreover, by giving the solute additional solvation sites, more solvents or surfactants can be added to increase solubility.

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Related Questions

If 110 grams of potassium chloride are mixed with 100 grams of water at 20°C, how much will not dissolve?

Answers

76 grams of potassium chloride will not dissolve in 100 grams of water at 20°C.

What is the solubility of the potassium chloride?

The solubility of potassium chloride in water at 20°C is approximately 34 grams per 100 grams of water.

So, if 100 grams of water can dissolve 34 grams of potassium chloride, then the maximum amount of potassium chloride that can be dissolved in 100 grams of water at 20°C is 34 grams.

Therefore, the amount of potassium chloride that will not dissolve in 100 grams of water at 20°C is:

110 grams - 34 grams = 76 grams

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11. C2 JUN 06 Q3
Classify the type of reaction occurring below.
CH₂CH₂CHCH₂OH
CH,
→CH₂CH₂C=CH₂ + H₂O
CH,
12.a) Draw the displayed formula, and name the ester formed when ethanoic acid reacts with propan-1-ol
in the presence of a suitable catalyst.
Name:
b) State the name of a suitable catalyst for this reaction.
[1]
24
...[2]
..[1]

Answers

Answer:

11.The type of reaction occurring is an elimination reaction.

12. a) The displayed formula and name of the ester formed when ethanoic acid reacts with propan-1-ol in the presence of a suitable catalyst are:

Displayed formula:

H H

│ │

H-C-C-OH + H-C-C-H → H-C-C-OC-C-H + H₂O

│ │

H CH₃

Name: Propan-1-yl ethanoate or propyl acetate

b) A suitable catalyst for this reaction is concentrated sulfuric acid (H₂SO₄).

TRUE OR FALSE: THE LIMITING REAGENT CONTROLS A REACTION’S THEORETICAL YIELD, BUT A NUMBER OF SIDE REACTIONS MAY ALSO OCCUR, CAUSING THE ACTUAL YIELD TO VARY.

Answers

Answer:

True. The limiting reagent is the reactant that is completely consumed in a chemical reaction and limits the amount of product that can be formed. The theoretical yield is the maximum amount of product that can be obtained from the limiting reagent, assuming that the reaction goes to completion and no side reactions occur. However, in practice, it is common for side reactions to occur, which can reduce the actual yield of the product. Therefore, while the limiting reagent does control the theoretical yield of a reaction, the actual yield may vary due to the presence of side reactions or other factors that can affect the efficiency of the reaction.

Explanation:

vinegar is a solution of acetic acid, hc2h3o2, dissolved in water. a 5.54-g sample of vinegar was neutralized by 30.10 ml of 0.100 m naoh. what is the percent by weight of acetic acid in the vinegar?

Answers

The percent by weight of acetic acid in the vinegar is  3.27% for the given 5.54-g sample of vinegar was neutralized by 30.10 ml of 0.100 m NaOH.

What is the percent of weight of acetic acid?

Vinegar is a solution of acetic acid, HC₂H₃O₂, dissolved in water. A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.100 M NaOH. Find the percentage of acetic acid by weight in vinegar. As per the question, vinegar is a solution of acetic acid, HC₂H₃O₂, dissolved in water.

A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.100 M NaOH.

Since NaOH and HC₂H₃O₂ reacts in a 1:1 molar ratio, moles of NaOH used = moles of HC₂H₃O₂ in vinegar

So,0.100 mol/L solution of NaOH = 0.100 mol/L solution of HC₂H₃O₂ in vinegar (as they react in 1:1 ratio).

Also, Volume of NaOH = 30.10 mL = 30.10/1000 = 0.0301L

Thus, Amount of HC₂H₃O₂ in vinegar = 0.100 mol/L × 0.0301 L = 0.00301 mol.

Molar mass of HC₂H₃O₂ = 60.05 g/mol.

Weight of HC₂H₃O₂ in 5.54 g vinegar = 0.00301 mol × 60.05 g/mol = 0.18086 g.

Percentage by weight of acetic acid in the vinegar = 0.18086 / 5.54 × 100 = 3.27%.

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The idea of __________ asserts that some evolutionary changes may not even involve intermediate forms.
punctuated equilibrium

Answers

The idea of punctuated equilibrium asserts that some evolutionary changes may not even involve intermediate forms.

What is punctuated equilibrium?

The idea of punctuated equilibrium is a theory in evolutionary biology that proposes that most evolutionary changes occur relatively rapidly, with long periods of stability punctuated by rare instances of rapid evolutionary change.

The theory was first introduced by Niles Eldredge and Stephen Jay Gould in 1972 as a challenge to the traditional Darwinian theory of gradualism, which posits that evolution proceeds slowly and steadily over long periods of time.

According to punctuated equilibrium, some evolutionary changes may not even involve intermediate forms.

There are several examples of punctuated equilibrium in the fossil record, including the Cambrian explosion, which saw the sudden appearance of most major animal phyla in a relatively short period of time, and the rapid diversification of mammals following the extinction of the dinosaurs at the end of the Cretaceous period.

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2. write the mechanism for the nitration of toluene showing explicitly why ortho and para products are favored over meta.

Answers

Nitration of toluene takes place in four steps which include formation of nitronium ion, formation of electrophile, deprotonation, and elimination of  HNO₃.

What is the mechanism of nitration?

The mechanism for the nitration of toluene showing explicitly why ortho and para products are favored over meta is as follows:

Step 1: Formation of the Nitronium Ion

NO₂⁺ is formed by nitric acid's reaction with sulfuric acid.

2HNO₃ + H₂SO₄ → 2 NO₂⁺ + 2HSO₄⁻ + H₃O⁺

The following is the formation of a nitronium ion:

Step 2: Formation of the electrophile

A nitronium ion is created, which is the electrophile. Because of the strong electron-releasing effect of the methyl group, the nitronium ion is drawn to the ring.

Due to the stability of the resulting carbocation, ortho and para products are favored over meta. In this, the bond on the methyl carbon is broken and the electrophile is added to it:

Step 3: Deprotonation: After the nitration reaction, an intermediate is formed in which a proton has been extracted from the methyl group. The formation of this intermediate indicates that the electrophile has been added to the ring's ortho or para positions.

Step 4: Elimination of HNO₃: An acid base reaction occurs to complete the nitration process, yielding nitrotoluene, HNO₃, and sulfuric acid. Here the intermediate is used to illustrate that the reaction has occurred with the ortho product. This reaction may also result in a para product in a similar manner.

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The Chernobyl nuclear disaster led to the release of massive radiation, specifically iodine-131 and cesium-137, which has been connected to a variety of environmental problems in the 30 years following the disaster. A meltdown in which of the following structures at a nuclear power plant, such as Chernobyl, would most likely lead to the accidental release of radiation?
Cooling tower
Turbine
Generator
Reactor core
Reactor core

Answers

Answer:

The meltdown in which of the following structures at a nuclear power plant, such as Chernobyl, would most likely lead to the accidental release of radiation is reactor core. Answer:e

Explanation:

What is the Chernobyl nuclear disaster?

The Chernobyl nuclear disaster was a catastrophic nuclear accident that occurred on April 26, 1986, at the No. 4 reactor in the Chernobyl Nuclear Power Plant, located in the northern Ukrainian Soviet Socialist Republic.

The explosion and subsequent fires resulted in the release of significant amounts of radioactive material into the atmosphere, as well as widespread contamination of the environment.

What was the cause of the Chernobyl nuclear disaster?

During a reactor systems test, an unforeseen combination of factors caused the core of one of Chernobyl's reactors to overheat and explode, releasing radioactive material into the surrounding area. The resulting steam explosion and fires killed two plant workers at the time of the accident and injured hundreds of others.

The explosion also resulted in the deaths of dozens of firefighters and other emergency workers in the aftermath of the disaster.

What was the impact of the Chernobyl nuclear disaster on the environment?

The Chernobyl nuclear disaster resulted in the release of significant quantities of radioactive material, including iodine-131 and cesium-137, which have been linked to a variety of environmental issues. These substances are still present in the environment, and their long-term effects on humans and wildlife are still being investigated.

However, the disaster has had a significant impact on the environment in the years following the accident, including the contamination of water and soil, the displacement of wildlife, and the potential long-term health effects on local populations.

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Now let's try one without any help from the simulation. Write a balanced chemical equation for the combustion reaction of ethane gas (C2H6) and oxygen gas (O2), then answer the following questions:(o) How many moles of carbon dioxide are produced from the combustion of 6.20 moles of ethane gas? (You may assume you have an excess of oxygen gas)(p) How many moles of carbon dioxide are produced from the combustion of 3.92 moles of oxygen gas? (You may assume you have an excess of ethane gas)(q) How many moles of carbon dioxide are produced from the combustion of 6.20 moles of ethane gas with 3.92 moles of oxygen gas?(r) How much excess reactant remains after the reaction described in (q)?(s) How much excess reactant remains after the combustion of 6.10 moles of ethane gas with 5.69 moles of oxygen gas?

Answers

The reaction is given by:C2H6(g) + 3O2(g) → 2CO2(g) + 3H2O(g), o) From the balanced chemical equation, we can see that 1 mole of ethane gas reacts with 3 moles of oxygen gas to produce 2 moles of carbon dioxide gas.  3.92 moles of oxygen gas will react with (1/3) × 3.92 = 1.307 moles of ethane gas. This will produce 1.307 × 2 = 2.614 moles of carbon dioxide gas. q) 6.20 moles of ethane gas will react with 6.20 × 3 = 18.60 moles of oxygen gas. This will produce 6.20 × 2 = 12.40 moles of carbon dioxide gas.r) This means that all the oxygen gas will be consumed in the reaction. Therefore, there will be no excess oxygen gas remaining after the reaction. s) 4.203 moles of ethane gas will be in excess after the reaction.

The equation is now balanced as there are equal numbers of each type of atom on both sides of the equation. 6.20 moles of ethane gas will react with 6.20 × 3 = 18.60 moles of oxygen gas. This will produce 6.20 × 2 = 12.40 moles of carbon dioxide gas. From the balanced chemical equation, we can see that 3 moles of oxygen gas react with 1 mole of ethane gas to produce 2 moles of carbon dioxide gas. Therefore From the balanced chemical equation, we can see that 1 mole of ethane gas reacts with 3 moles of oxygen gas to produce 2 moles of carbon dioxide gas.

From the balanced chemical equation, we can see that 1 mole of ethane gas reacts with 3 moles of oxygen gas to produce 2 moles of carbon dioxide gas. Therefore, 5.69 moles of oxygen gas will react with (1/3) × 5.69 = 1.897 moles of ethane gas. This will produce 1.897 × 2 = 3.794 moles of carbon dioxide gas. This means that 6.10 − 1.897 = 4.203 moles of ethane gas will be in excess after the reaction.

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Two protons are fired toward each other in a particle accelerator, with only the electrostatic force acting. Which of the following statements must be true about them as they move closer together? (There could be more than one correct choice.)
a. Their kinetic energy keeps increasing.
b. Their acceleration keeps decreasing.
c. Their kinetic energy keeps decreasing.
d. Their electric potential energy keeps decreasing.
e. Their electric potential energy keeps increasing.

Answers

When two protons are fired toward each other in a particle accelerator, with only the electrostatic force acting, then their kinetic energy keeps increasing, acceleration keeps decreasing, kinetic energy keeps decreasing, electric potential energy keeps decreasing.

How does the electrostatic force act?

The electrostatic force is a force that arises between electrically charged objects. It is the force exerted on a charged particle by other charged particles or electromagnetic fields. It is a fundamental force in nature that has an infinite range and can be either attractive or repulsive. The strength of the electrostatic force is proportional to the inverse square of the distance between the charged particles. As two charged particles move closer together, the force between them increases. Therefore, as the two protons move closer together, their kinetic energy and electric potential energy will increase.

According to Coulomb's law, the electrostatic force is inversely proportional to the square of the distance between the two charges. Therefore, as the distance between the two protons decreases, the electrostatic force acting between them will increase. As a result, their acceleration will keep decreasing. At the same time, as the protons move closer together, their kinetic energy will keep increasing while their electric potential energy will keep decreasing.

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The acceleration of a particle in an electric field depends on the charge-to-mass ratio of the particle.(a) compute e / m for a proton and find its acceleration in a uniform electric field of magnitude 100 n / c. (b) find the time it takes for a proton initially at rest in such a field to reach the speed of 0.01c

Answers

Answer:91

Explanation:because I am just very smart and this is the answer <3

Tripling the concentration of a reactant increases the rate of a reaction nine times. With this knowledge, answer the following questions: (a) What is the order of the reaction with respect to that reactant?
(b) Increasing the concentration of a reactant by a factor of four increases the rate of a reaction four times. What is the order of the reaction with respect to that reactant?

Answers

Answer:

a) Tripling the concentration of a reactant increases the rate of a reaction nine times.the order of the reaction with respect to that reactant is 2

b)Increasing the concentration of a reactant by a factor of four increases the rate of a reaction four times.the order of the reaction with respect to that reactant is 1.

Explanation:

a) The order of the reaction with respect to that reactant is 2. The rate law of the reaction with the stoichiometric coefficients a, b, and c would be as follows:

rate = k[A]^x[B]^y[C]^z

Where k is the rate constant and x, y, and z are the orders of the reaction with respect to the corresponding reactants. When [A] is tripled, the rate increases nine times, indicating that the rate is proportional to [A]^2. Therefore, the order of the reaction with respect to [A] is 2.

b) The order of the reaction with respect to that reactant is 1. The rate law of the reaction with the stoichiometric coefficients a, b, and c would be as follows:

rate = k[A]^x[B]^y[C]^z

When [A] is quadrupled, the rate increases four times, indicating that the rate is proportional to [A]. Therefore, the order of the reaction with respect to [A] is 1.

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Practice Problem 11.15b Propose an efficient synthesis for the following transformation. y The transformation above can be performed with some reagent or combination of the reagents listed below. Give the necessary reagent(s) in the correct order, as a string of letters (without spaces or punctuation, such as "EBF"). If there is more than one correct solution, provide just one answer. A B с Br2 HBr, ROOR cat. OsO4, NMO D HBr E H2, Pd F H2SO4, H2O, HgSO4 I 1) O3; 2) DMS H 1) xs NaNH2, 2) H20 1) R2BH; 2) H2O2, NaOH Practice Problem 11.18d Propose an efficient synthesis for the following transformation. The transformation above can be performed with some reagent or combination of the reagents listed below. Give the necessary reagent(s) in the correct order, as a string of letters (without spaces or punctuation, such as "EBF"). If there is more than one correct solution, provide just one answer. B с HBr, ROOR 1) O3; 2) DMS Br2, hv F D H2S04, H20, HgSO4 E H2, Lindlar's cat. HC=CNa I G HBr H NaOme 1) R2BH; 2) H2O2, NaOH Practice Problem 11.21a X Incorrect. Propose an efficient synthesis for the following transformation. The transformation above can be performed with some reagent or combination of the reagents listed below. Give the necessary reagent(s) in the correct order, as a string of letters (without spaces or punctuation, such as "EBF"). If there is more than one correct solution, provide just one answer. A B HBr, ROOR HC=CNa 1) R2BH; 2) H2O2, NaOH D HBr E CH3CH2Br H2S04, H2O, HgSO4 G NaOH н conc. H2SO4, heat I 1) LiAlH4; 2) H307 Practice Problem 11.21b Propose an efficient synthesis for the following transformation. :- The transformation above can be performed with some reagent or combination of the reag spaces or punctuation, such as "EBF"). If there is more than one correct solution, provide j B с t-BuOK 1) O3; 2) DMS Br2, hv D H2SO4, H20, HgSO4 E H2, Lindlar's cat. F HC=CNa H HBr, ROOR HBr I 1) R2BH; 2) H202, NaOH Practice Problem 11.21c Propose an efficient synthesis for the following transformation. SOH The transformation above can be performed with some reagent or combination of the reagents listed below. Give the necessary reagent(s) in the correct order, as a string of letters (without spaces or punctuation, such as "EBF"). If there is more than one correct solution, provide just one answer. B с HBr, ROOR HC=CNa 1) R2BH; 2) H202, NaOH F D HBr E CH3CH2Br H2SO4, H20, HgSO4 I G NaOH H conc. H2S04, heat 1) 03; 2) H20 Propose an efficient synthesis for the following transformation. - li The transformation above can be performed with some reagent or combination of the reagents listed below. Give the necessary reagent(s) in the correct order, as a string of letters (without spaces or punctuation, such as "EBF"). If there is more than one correct solution, provide just one answer. А B HBr conc. H2S04, heat HC=CNa D HBY, ROOR E Hy, Lindlar's cat. 1) O3; 2) DMS G Brą, hv H dilute H2SO4 I H2, Pt Practice Problem 11.25a Propose an efficient synthesis for the following transformation: % Br The transformation above can be performed with some combination of the reagents listed below. Give the necessary reagents in the correct order for each transformation, as a string of letters (without spaces or punctuation, such as "EBF"). If there is more than one correct solution, provide just one answer. А t-BuOK B OsO4, NMO c 1) O3; 2) DMS D H2, Pt E H2, Lindlar's cat F xs HBr I G 1) BH 3.THF; 2) H202, NaOH H MeONa Br2, hv Reagent(s);

Answers

The reagent(s) for the given transformation is "A B C D E F G H I", which is t-BuOK, OsO4, NMO, O3, DMS, H2, Pt, H2, Lindlar's cat., xs HBr, BH3.THF, H202, NaOH, MeONa, Br2, hv.

What is transformation?

Transformation is the process of changing something into a different form or state. It can involve altering the physical characteristics, behaviors, attitudes, or perceptions of an entity. Transformation is a process that occurs in a variety of contexts including business, education, technology, and personal development.

A) t-BuOK - For the given transformation, the initial step is to add an alkoxide, here t-BuOK, to the starting material.
B) OsO4, NMO - After the addition of the alkoxide, the resulting intermediate has to be oxidized by OsO4 and NMO reagents.
C) 1) O3; 2) DMS - The intermediate then has to be ozonolyzed using ozone and dimethyl sulfide (DMS).
D) H2, Pt - The ozonolysis will result in a mixture of aldehyde and ketone. The aldehyde has to be hydrogenated using H2 and Pt.
E) H2, Lindlar's cat. - The ketone has to be hydrogenated using H2 and Lindlar's catalyst.
F) xs HBr - The product of the hydrogenation has to be converted to a tertiary alcohol by an elimination reaction with HBr.
G) 1) BH3.THF; 2) H202, NaOH - The tertiary alcohol has to be oxidized to a tertiary ketone using BH3.THF, H202 and NaOH.
H) MeONa - The tertiary ketone has to be methylated using MeONa.
I) Br2, hv - The product of the methylation has to be brominated using Br2 and heat.
Therefore, the reagent(s) for the given transformation is "A B C D E F G H I", which is t-BuOK, OsO4, NMO, O3, DMS, H2, Pt, H2, Lindlar's cat., xs HBr, BH3.THF, H202, NaOH, MeONa, Br2, hv.

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Classify each titration curve as representing a strong acid titrated with a strong base, a strong base titrated with a strong acid, a weak acid titrated with a strong base, a weak basetaed with a strong acid, or a polyprotic acid titrated with a strong base. Strong acid/Strong base/ strong base Weak acid strong base Weak base Polyprotic acid strong acid strong acid strong base mL of titrant mL of titrant mL of titrant mL of titrant mL of titrant

Answers

When it comes to titration, a titration curve is the representation of the change in pH with regards to the volume of titrant added.

The point of equivalence is where the stoichiometric amount of titrant reacts completely with the analyte being titrated.

There are several types of titration curves. Below are the classifications of each titration curve:

Strong acid titrated with a strong base. The titration curve for this scenario starts out with a pH of around 3.0, which is the pH of a strong acid. The pH rises until the equivalence point is reached. The pH then drops steeply after the equivalence point.

Strong base titrated with a strong acid. In this titration curve, the pH starts off around  .11, which is the pH of a strong base. The pH drops rapidly until the equivalence point is reached. The pH then rises steeply after the equivalence point.

Weak acid titrated with a strong base. In this titration curve, the pH starts off slightly acidic due to the presence of the weak acid. The pH rises gradually until the equivalence point is reached. The pH then increases steeply after the equivalence point.

Weak base titrated with a strong acid. The pH starts off slightly basic in this titration curve due to the weak base. The pH decreases gradually until the equivalence point is reached. The pH then drops steeply after the equivalence point.

Polyprotic acid titrated with a strong base. In this titration curve, there are more than one equivalence point because the acid is capable of releasing more than one hydrogen ion.

Each equivalence point represents the point at which one mole of H+ is neutralized.

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If a solid piece of shiny sodium metal is exposed to chlorine gas, a large amount of heat is released and the white solid sodium chloride (table salt) forms. Based on this information, which of the following statements is TRUE? A) This process was exothermic_ B) This process represents a physical change: C) Mass is lost during this process_ D) This process was endothermic_

Answers

Option A is the correct statement for the process was exothermic that a large amount of heat is released when sodium metal is exposed to chlorine gas.

What happens when sodium is exposed to chlorine? Sodium metal reacts with chlorine gas to produce sodium chloride. When solid shiny sodium metal is exposed to chlorine gas, a large amount of heat is generated, and the white solid sodium chloride (table salt) is formed. So the process is an exothermic reaction.A chemical reaction in which heat is given out, such as the one between sodium and chlorine, is exothermic. When the products' energy is less than the reactants' energy, energy is given out from the system into the surroundings, resulting in an increase in temperature in the surroundings. Therefore, this process was an exothermic and the correct option is 'A'.

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Can any help with this chemistry question?? I have an exam tomorrow

Answers

Answer:

Explanation:

To calculate the standard enthalpy of formation for TICL(I), we need to use the given thermochemical equations and Hess's law. The equation for the formation of TICL(I) is:

C(s) + TiO₂ (s) + 2Cl(g) → TICL(I) + CO(g)

Using the given equations for the formation of CO(g) and TiO2(s), we can manipulate them to get the necessary reactants for the formation of TICL(I):

Ti(s) + O₂(g) → TiO₂(s) (reverse the equation)

C(s) + 1/2O₂(g) → CO(g) (multiply by 2)

Adding these two equations, we get:

Ti(s) + 2C(s) + O₂(g) → TiO₂(s) + 2CO(g)

This equation is the reverse of the equation given for the formation of TICL(I), so we need to flip its sign to get the correct value for the enthalpy change:

TICL(I) → C(s) + TiO₂ (s) + 2Cl(g) + CO(g)

ΔH° = -(-394 kJ/mol + 286 kJ/mol + 0 + (-221 kJ/mol))

ΔH° = -(-329 kJ/mol)

ΔH° = +329 kJ/mol

Therefore, the correct value for the standard enthalpy of formation for TICL(I) is +329 kJ/mol, which is option D.

What is the hybridization of the carbon that is attached to the oxygens in CH;COOH (acetic acid)? 4) Which molecule has the greatest dipole moment? A. CCl B. CH,Clz C. CFa D. BrzCClz CH,Fz

Answers

The carbon that is attached to the oxygens in CH₃COOH (acetic acid) is sp2 hybridized. This is because it is attached to three atoms (one oxygen and two hydrogens) and has a trigonal planar geometry.

The molecule with the greatest dipole moment is CH₂Cl₂(dichloromethane) because it has a tetrahedral geometry and the two C-Cl bonds are oriented in opposite directions, creating a net dipole moment. The other molecules (CCl₄, CF₄, and Br₂CCl₂) are all symmetric and have zero dipole moment.

A chemical concept known as hybridization describes the bonding and geometry of molecules. It entails combining atomic orbitals to create hybrid orbitals, which can more accurately capture the bonding in a molecule. The number of hybrid orbitals formed is equal to the number of atomic orbitals combined. Atomic orbitals with similar energy levels are merged to create the hybrid orbitals. An atom's geometry, bond angles, and polarity can all be impacted by hybridization, which can then have an impact on the molecule's reactivity and physical characteristics. Foreseeing the forms and characteristics of molecules as well as explaining their chemical behaviour requires an understanding of atom hybridization.

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20pcm3 og a gas has a pressure of 510mmhg what will be the volume of the pressure is increased to 780mmhg, assuming there is no change in temperature​

Answers

The volume of the gas will decrease from 20 cm³ to 13.08 cm³.

What is Boyle's law?

Boyle's law is a gas law that states that the product of the pressure and volume of a gas is constant at constant temperature.

What is the significance of assuming no change in temperature in this problem?

Assuming no change in temperature is significant because it allows us to apply Boyle's law to solve the problem. If the temperature were to change, we would need to use a different gas law, such as Charles's law or the combined gas law, to account for the change in temperature.

We can use Boyle's law to solve this problem, which states that the product of the pressure and volume of a gas is constant at constant temperature. Mathematically, we can express this as P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, respectively, and P₂ and V₂ are the final pressure and volume, respectively.

Using this equation, we can solve for V₂:

P₁V₁ = P₂V₂

V₂ = (P₁V₁)/P₂

Substituting the given values, we get:

V₂ = (510 mmHg x 20 cm³) / 780 mmHg

V₂ = 13.08 cm³

Therefore, if the pressure is increased from 510 mmHg to 780 mmHg at constant temperature, the volume of the gas will decrease from 20 cm³ to 13.08 cm³.

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students conducting research observe the rate of an enzyme-catalyzed reaction under various conditions with a fixed amount of enzyme in each sample. when will increasing the substrate concentration likely result in the greatest increase in the reaction rate?

Answers

Increasing the substrate concentration will likely result in the greatest increase in the reaction rate when the substrate concentration is lower than the concentration of the enzyme.

The concentration of the substrate affects the rate of reaction since there is a direct correlation between the number of enzyme-substrate complexes that are formed and the rate of reaction.

When there is more substrate, more enzyme-substrate complexes can form, resulting in an increase in the rate of reaction.

So, it is highly likely that when the substrate concentration is low, increasing the substrate concentration will result in the greatest increase in the reaction rate.

However, when the substrate concentration is already high, the reaction rate may not continue to increase as a result of increasing the substrate concentration.

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combining 50 ml of vinegar with 500 ml of milk causes the vinegar, which is an acid, to react with the milk. the milk sours and thickens, creating cottage cheese. what kind of change is this?
answer choices
chemical
mechanical
physical
potential

Answers

A chemical alteration has occurred. A new material, cottage cheese, with distinct qualities from the original milk and vinegar is produced when the acid in the vinegar and the proteins in the milk react.

The change described is a chemical change. When vinegar, which is an acid, is combined with milk, a reaction occurs between the acid and the proteins in the milk. This reaction causes the milk to sour and thickens, resulting in the formation of cottage cheese. This change cannot be easily reversed, and the resulting cottage cheese is a new substance with different properties than the original milk and vinegar. This is a chemical change because the molecules in the milk and vinegar are rearranged to form a new substance, which has different chemical and physical properties than the original substances. This process is different from a physical change, such as melting ice, which does not result in the formation of a new substance.

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Which of the following molecules would have the highest boiling point?
a) hexane
b) octane
c) 2-propylpentane
d) 2-methylhexane

Answers

The molecule which would have the highest boiling point is 2-methylhexane. Thus, the correct option will be D.

What is boiling point?

The boiling point is the temperature at which the vapor pressure of a liquid is equal to the external pressure. The boiling point of a liquid is a measure of its vapor pressure. The higher the boiling point, the higher the vapor pressure of the liquid, and the more heat is required to vaporize it.

The boiling point of a substance is affected by the strength and types of intermolecular forces. The stronger the intermolecular forces, the higher the boiling point. 2-methylhexane has highest boiling point because it has the highest number of carbons and branches, which contribute to its strong intermolecular forces that lead to a higher boiling point.

Therefore, the correct option is D.

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How would the Rf of eugenol increase or decrease if you ran your TLC plate in 40% ethyl acetate in hexanes? a.The Rf value would increase. b. The Rf value would decrease.c. The Rf would remain the same.

Answers

Answer: B (The Rf value would decrease)

Explanation:

The Rf (retention factor) value is a ratio of the distance traveled by the compound to the distance traveled by the solvent front in thin-layer chromatography (TLC). The polarity of the solvent affects the Rf value of a compound.

In general, if a more polar solvent is used in TLC, the Rf value of a compound will decrease, and if a less polar solvent is used, the Rf value will increase.

In this case, using 40% ethyl acetate in hexanes means using a more polar solvent compared to a pure hexanes solvent. As eugenol is a moderately polar compound, the increased polarity of the solvent will likely result in a decrease in the Rf value.

Therefore, the correct answer is b. The Rf value would decrease.

a sample of helium gas has a volume of 620. ml at a temperature of 500. k. if we decrease the temperature to 100. k while keeping the pressure constant, what will the new volume be?

Answers

The new volume of the helium gas sample will be  124 ml. This is due to the fact that when the temperature decreases while the pressure remains constant, the volume of a gas will increase.


According to Charles’s law, the volume of a given gas at a constant pressure is directly proportional to its absolute temperature. Therefore, a decrease in temperature, while holding constant the pressure of the helium gas, would result in a decrease in volume.

A constant pressure is the one under which the pressure of a substance remains unchanged as the temperature and/or volume of the substance change. Charles's law may be used to explain the properties of gases, particularly with constant pressure since it states that the volume of a given mass of a gas is directly proportional to its absolute temperature, provided that its pressure remains constant. It's written as:V1/T1 = V2/T2; whereV1 = 620 ml; T1 = 500K; T2 = 100KLet's put the values in the formula given above. The [tex][tex]620/T1 = V2/100V2 = 62,000/500V2 = 124 ml[/tex].[/tex]Therefore, the new volume of helium gas at a temperature of 100K would be 124 ml.

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What procedures can be performed on trials 2 and 3 so that the rate of dissolving is the same as trial 1? A student wants to determine how different factors affect the rate of dissolving solid in water: Trial Size of Particles Rate_of_Dissolving small 10 sec medium 20 sec large 30 sec 2 3 What procedures can be performed on trials 2 and 3 so that the rate of dissolving is the same as trial 1? A_ the student can increase the pressure B. the student can decrease the pressure C the student can decrease the temperature D. the student can increase the temperature'

Answers

The size of particles has an effect on the rate of dissolving, but temperature is also a significant factor that affects how quickly a solid will dissolve in water. Lowering the temperature slows down the movement.

What is the temperature ?

Temperature is a measure of the average kinetic energy of the particles in a substance or system. In simpler terms, it is a measure of how hot or cold something is. The temperature of a substance or system is commonly measured in degrees Celsius (°C) or degrees Fahrenheit (°F), and it can be influenced by various factors such as heat transfer, pressure, and the presence of other substances. Temperature is an important physical property that affects many aspects of daily life, including weather patterns, cooking, and the functioning of electronic devices. It is also a critical factor in many scientific processes, such as chemical reactions, phase transitions, and the behavior of materials at the atomic and molecular level.

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which scientist conducted the gold foil experiment and discovered that the atom has a positively charged nucleus?

Answers

Ernest Rutherford, a New Zealand physicist, conducted the gold foil experiment and discovered that the atom has a positively charged nucleus.

In 1911, he conducted an experiment in which he fired alpha particles at a thin sheet of gold foil. The majority of the particles went straight through the gold foil, but a small percentage of the particles bounced back. He discovered that the bouncing back was caused by a small, positively charged nucleus at the center of the atom. Rutherford's experiment was crucial to our understanding of the structure of the atom. Prior to his experiment, the prevailing model of the atom was that it was a solid, indivisible sphere.

However, Rutherford's experiment showed that the atom was mostly empty space, with a positively charged nucleus at its center. This discovery paved the way for future research into atomic structure and helped to lay the foundation for the development of nuclear physics.

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If 50 grams of water are saturated at 90°C with potassium nitrate and then cooled to 40°C, how much will precipitate?

Answers

Answer:

43.1gramms

Explanation:

change the temperatures to kelvin

90--363

40--313

50grams of water are saturated at 90 degree celcius.

then,

50___363

x_____313

then cross multiply

363x=15650

divide both sides by 363

x=43.1gramms

Electrons that inhabit different orbitals must have a different value for the:
a. principal quantum number
b. angular momentum quantum number
c. spin quantum number
d. none of the above

Answers

Answer:

D

Explanation:

I had this question before :)

what is BEFORE and AFTER when you put the baking soda in vinegar?​

Answers

When you mix baking soda and vinegar, a chemical reaction occurs that produces carbon dioxide gas, water, and a type of salt called sodium acetate.

What happens at the mixing of baking soda in vinegar?​

Before: Before mixing baking soda and vinegar, they are both in their separate states. Baking soda is a white powder, and vinegar is a clear liquid.

During: When you mix the baking soda and vinegar, the baking soda (sodium bicarbonate) reacts with the vinegar (acetic acid) to produce carbon dioxide gas (CO2), water (H2O), and sodium acetate (NaC2H3O2).

After: After the chemical reaction has taken place, you will see bubbles of carbon dioxide gas being released. The solution will also become cloudy as the sodium acetate precipitates out. The resulting mixture may feel warmer due to the exothermic nature of the reaction (meaning it releases heat).

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what is the difference in the various bohr radii rn for the hydrogen atom, where n is the principle quantum number, a. between r1 and r2? b. between r5 and r2? c. between r5 and r6? d. between r10 and r11?

Answers

The principle quantum number (n) of an electron in an atom determines the size of its associated Bohr radius. Specifically, the Bohr radius is inversely proportional to n, meaning the higher the n, the smaller the Bohr radius. Therefore, the difference between Bohr radii will increase with increasing n.

a. Between r1 and r2: The difference between r1 and r2 is that r2 is half the size of r1, as n has increased from 1 to 2.

b. Between r5 and r2: The difference between r5 and r2 is that r5 is a fifth of the size of r2, as n has increased from 2 to 5.

c. Between r5 and r6: The difference between r5 and r6 is that r6 is a sixth of the size of r5, as n has increased from 5 to 6.

d. Between r10 and r11: The difference between r10 and r11 is that r11 is an eleventh of the size of r10, as n has increased from 10 to 11.


a. The difference between r1 and r2 is calculated by substituting n = 1 and n = 2 respectively into the expression for the Bohr radius.

b. The difference between r5 and r2 is calculated by substituting n = 2 and n = 5 respectively into the expression for the Bohr radius.

c. The difference between r5 and r6 is calculated by substituting n = 5 and n = 6 respectively into the expression for the Bohr radius.

d. The difference between r10 and r11 is calculated by substituting n = 10 and n = 11 respectively into the expression for the Bohr radius.

The Bohr radius is given by the expression r = n2ℏ2me4πϵ0 where n is the principal quantum number, ℏ is the reduced Planck constant, me is the mass of the electron, π is the mathematical constant pi, and ϵ0 is the vacuum permittivity.

We can use this expression to calculate the Bohr radius for different values of n, and then calculate the differences between the Bohr radii for different values of n.

For example, the difference between r1 and r2 is given byr2 - r1 = 22ℏ2me4πϵ0 - 12ℏ2me4πϵ0= 4ℏ2me4πϵ0

Similarly, the difference between r5 and r2 is given byr5 - r2 = 52ℏ2me4πϵ0 - 22ℏ2me4πϵ0= 21ℏ2me4πϵ0

The differences between r5 and r6, and between r10 and r11 can be calculated in the same way.

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If a substance is removed from a reaction in equilibrium, the equilibrium will shift toward
the side where the concentration was ________.

Answers

If a substance is removed from a reaction in equilibrium, the equilibrium will shift towards the side where the concentration was higher.

What is substance?

A substance is a category of stuff with certain physical and chemical qualities as well as a set or definite composition. A substance might be an element or a compound. A substance made up of atoms with the same atomic number, or the same number of protons in their atomic nuclei, is referred to as an element.

This is known as the Le Chatelier's principle, which holds that a system in equilibrium would react to any stress by trying to counteract the stress and return to equilibrium. When a drug is removed from the reaction mixture, the system is put under stress due to the substance's lower concentration. The balance will change in a way that increases the production of the substance that was eliminated in order to counteract this drop.

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57.0 ml of 0.90 m solution of hcl was diluted by water. the ph of this diluted solution is 0.90. how much water was added to the original solution insert your answer rounded to 3 significant figure.

Answers

57.0 ml of 0.90 m solution of Hcl was diluted by water. the pH of this diluted solution is 0.90. 50.5 mL water was added to the original solution .

There are a few steps to solve this.

Here they are: First, calculate the initial concentration of HCl in the solution.

Molarity = moles of solute / volume of solution in liters.

The volume of the solution is 57.0 mL, which is 0.0570 L.

The molarity is 0.90 M. So,0.90 M = moles of HCl / 0.0570 L

Now we can solve for moles of HCl:

moles of HCl = 0.90 M x 0.0570 L = 0.0513 mol

Next, we need to use the pH to find the concentration of H+ ions.

pH = -log[H+]0.90 = -log[H+]

Solving for [H+],

we get:[H+] = 7.94 x 10^-1 M

Finally, we can use the concentration of H+ ions to find the new volume of the solution after dilution using the equation:[H+] x V = moles of HCl7.94 x 10^-1 M x V = 0.0513 mol

Solving for V,

we get: V = 6.47 x 10^-2 L

To find how much water was added,

we subtract the final volume from the initial volume:

Volume of water added = 57.0 mL - 6.47 mL = 50.5 mL (rounded to 3 significant figures)

Therefore, 50.5 mL of water was added to the original solution.

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