What is the weight of a 3.5 kg dog on the moon? acceleration of gravity is 1.63 m/s?)

Answers

Answer 1

1.98 kilograms

weight on the moon = (weight on Earth / acceleration of Earth's gravity) x acceleration of the moon's gravity

weight on the moon = (12 kg. / 9.81 m/s^2) x 1.63 m/s^2

weight on the moon = 1.98 kg.

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Answer 2
1.98 kilograms. I just answered that question like an hour ago and got it right

Related Questions

Which scientist is credited with having the greatest contribution to early microscopy and was the first to observe and describe single-celled organisms?

Answers

Answer:

Antonie van Leeuwenhoek

Explanation:

Option B.
Consider a setup in which two springs are attached to a mass in parallel.
Convince yourself that in this setup, the compression of each spring must be the same. Using
this fact, derive the effective spring constant for springs in parallel
This is asking, "ll1 replace the two springs by a single imaginary spring, what would its spring
constant be such that the force stays the same?" Your answer should only depend on k, and k

Answers

Answer:

it would be...

Explanation:

 what is the difference between repelling and attracting

Answers

Answer:

Attracting means pulling toward you and repelling means pushing away

Explanation:

Answer: Repelling is when something will not connect with another object. The force will cause a repel between the two objects. Attracting is when something is attracted or being pulled to another object.

Explanation: Hope this helps!

What on earth is equal to 9.8m/s/s

Answers

Answer:

Acceleration due to gravity

Vesta is a minor planet (asteroid) that takes 3.63 years to orbit the Sun.
Calculate the average sun -Vesta distance

Answers

Using Kepler's third law, the average sun -Vesta distance is 2.36 AU.

According to Kepler's laws, the square of the period of revolution of planets are proportional to the cube of their average distances from the sun. Hence, we can write; [tex]T^{2} =r^{3}[/tex]

Where;

T = period of the planet

r = average distance of the planet

When;

T =  3.63 years

r = [tex]\sqrt[3]{T^2}[/tex]

r = [tex]\sqrt[3]{(3.63)^2}[/tex]

r = 2.36 AU

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