Answer:
x = 2Step-by-step explanation:
Given:
log ₄ (2x) = 1Solving for x:
2x = 4¹2x = 4x = 2Answer:
128 on edg
Step-by-step explanation:
i thought it was 2 aswell double checked it on a graphing calculator its 128
Last year there were 221 students and 12 teachers at Hilliard School. This year there are 272 students. The principal wants to keep the same student to teacher ratio as last year. Which proportion can the principal use to find x, the number of teacher needed this year?
Answer:
3264:221
Step-by-step explanation:
If by last year there were 221 students and 12 teachers at Hilliard School, then;
221students = 12teachers
To find the equivalent ratio for 272students, we can say;
272students = x teachers
Divide both expressions
221/272 = 12/x
Cross multiply
221 * x = 272 * 12
221x = 3264
x = 3264/221
x = 3264:221
This gives the required proportion
can you help me with this question please?
Answer:
(1, -3)
Step-by-step explanation:
You can see where the two lines intersect - that's the solution.
Y varies directly as x and k = 5
Y=kx
Find y when x = 5
Answer:
y = 25
Step-by-step explanation:
Given y = kx and k = 5 then
y = 5x ← equation of variation
When x = 5 , then
y = 5 × 5 = 25
is 65.4279 irrational or rational? Explain
The triangles are similar.
What is the value of x?
Enter your answer in the box.
A menu at a local diner has 12 appetizers, 8 entrees, and 4 choice of desserts. How many different meal combinations are possible when you select one appetizer, one entrée, and one dessert from the menu?
Answer:
12* 8 * 4 = 384
Step-by-step explanation:
[tex]solve : - \\ \\ (19 {}^{2} + 21 {}^{2} ) = {?}[/tex]
[tex] \sf Q) \: 19^{2} + 21^{2} = {?}[/tex]
[tex] \sf \to 19^{2} + 21^{2} [/tex]
[tex] \sf \to 361 + 441[/tex]
[tex] \sf \to 802[/tex] is the solution.
OAA', OBB', and OCC' are straight lines. Triangle ABC is mapped onto Triangle A'B'C' by an enlargement with center O. What is the scale factor of enlargement.
Answer:
(D) 2
Step-by-step explanation:
The scale factor of the enlargement of ΔABC to ΔA'B'C' is given by the ratio of the length of the corresponding sides of ΔA'B'C' and ΔABC
Therefore, we have;
[tex]The \ scale \ factor = \dfrac{Length \ of \overline {B'C'}}{Length \ of \overline {BC}} = \dfrac{Length \ of \overline {A'C'}}{Length \ of \overline {AC}} = \dfrac{Length \ of \overline {A'B'}}{Length \ of \overline {AB}}[/tex]
[tex]\dfrac{Length \ of \overline {B'C'}}{Length \ of \overline {BC}} = \dfrac{2 \ units}{1 \ unit} = 2[/tex]
[tex]\dfrac{Length \ of \overline {A'C'}}{Length \ of \overline {AC}} = \dfrac{4 \ units}{2 \ units} = 2[/tex]
[tex]\dfrac{Length \ of \overline {A'B'}}{Length \ of \overline {AB}} = \dfrac{2 \cdot \sqrt{5} \ units}{\sqrt{5} \ units} = 2[/tex]
Therefore, the scale factor = 2
Write an equation for the quadratic graphed below: x-intercepts: (-1,0) and (4,0); y-intercept: (0,1)
Answer:
y = (1/4)x² - (5/4)x + 1
Step-by-step explanation:
The x-intercepts of the quadratic equation are simply it's roots.
Thus, we have;
(x + 1) = 0 and (x - 4) = 0
Now, formula for quadratic equation is;
y = ax² + bx + c
Where c is the y intercept.
At y-intercept: (0,1), we have;
At (-1,0), thus;
0 = a(1²) + b(1) + 1
a + b = -1 - - - (1)
At (4,0), thus;
0 = a(4²) + b(4) + 1
16a + 4b = -1
Divide both sides by 4 to get;
4a + b = -1/4 - - - (2)
From eq 1, b = -1 - a
Thus;
4a + (-1 - a) = -1/4
4a - 1 - a = -1/4
3a - 1 = -1/4
3a = 1 - 1/4
3a = 3/4
a = 1/4
b = -1 - 1/4
b = -5/4
Thus;
y = (1/4)x² - (5/4)x + 1
if f(x)=x^2-11 for what values of x is f(x) < 25
Answer: D
Step-by-step explanation:
5²-11=14
6^2-11= 25
14>25
as the question asks for something lower than 25 not lower/equal to the answer is D.
The range of values for which f(x) < 25 are -6 < x < 6. The correct answer choice is e).
To find the values of x for which f(x) < 25, we substitute the expression for f(x) into the inequality and solve for x.
Given f(x) = x² - 11, we need to find the values of x that make f(x) less than 25.
x² - 11 < 25
Adding 11 to both sides, we have:
x² < 36
To determine the values of x that satisfy this inequality, we take the square root of both sides. Since the square root of a number can be positive or negative, we consider both positive and negative solutions.
x < √36
x > -√36
Simplifying, we get:
x < 6
x > -6
Therefore, the correct answer choice is e) -6 < x < 6, as it represents the range of values for which f(x) < 25. This means that x can take any value between -6 and 6 (excluding -6 and 6) for the inequality to hold true.
To learn more about function click on,
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The side length of the cube is 5 cm. Find the volume of the cube.
Answer:
125 cm³
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightGeometry
Volume of a Cube Formula: V = a³
a is a side lengthStep-by-step explanation:
Step 1: Define
Identify variables
a = 5 cm
Step 2: Find Volume
Substitute in variables [Volume of a Cube Formula]: V = (5 cm)³Evaluate exponents: V = 125 cm³Answer:
[tex]\huge\boxed{V=125cm^3}[/tex]
Step-by-step explanation:
The formula of a volume of a cube with edge [tex]a[/tex]:
[tex]V=a^3[/tex]
We have [tex]a=5cm[/tex].
Therefore the volume is:
[tex]V=(5cm)^3=5cm\cdot5cm\cdot5cm=125cm^3[/tex]
which one ?
it says i need 20 characters so i’m just typing this
is my answers correct?
Answer:
Saleh is x years old. And 10 years ago he was 100 years old.
Suha is x years old. Saleh is 10 years younger than Suha. Saleh is 100 years old.
Two square based pyramids are joined, total volume is 2700mm, perpendicular height of top pyramid is 16mm, perpendicular height of bottom pyramid is 20mm, length and width of joint base area both x, find x. Please help me
Answer: 15 m
Step-by-step explanation:
Given
Total volume of the combined pyramid is [tex]V=2700\ mm^3[/tex]
Height of top and bottom pyramid is
[tex]h_t=16\ mm[/tex]
[tex]h_b=20\ mm[/tex]
If the base has a side length of x, its area must be [tex]x^2[/tex]
Volume of square prism is given by
[tex]\Rightarrow V=\dfrac{1}{3}Bh\quad [\text{B=base area}]\\\\\text{Total volume will be the sum of the two pyramids}\\\\\Rightarrow 2700=\dfrac{1}{3}\times x^2\times 16+\dfrac{1}{3}\times x^2\times 20\\\\\Rightarrow 2700=\dfrac{1}{3}\times x^2\times (16+20)\\\\\Rightarrow x^2=225\\\Rightarrow x=15\ mm[/tex]
Thus, the value of [tex]x[/tex] is 15 m.
The dimensions of the rectangular pool shown below are 60 yards by 30
yards. A fence will be built around the outside of the deck. The ratio of the
dimensions of the pool to the dimensions of the fence is .. How many yards
of fence should be purchased to enclose the deck?
Answer:
ok so we have to find the perimiter so
60+60=120
30+30=60
120+60=180
Hope This Helps!!!
If 5 ^ (3k - 1) - 5 ^ (b - 3) , what is the value of b?
Answer:
-1
Step-by-step explanation:
1. Sets the exponents equal
3b-1 = b-3
2. collect like terms and calculate it
3b-b=1-3
2b= -2
(divide both side by 2)
b=-1
find the inverse matrix or type none use decimals [3 2
4 1]
Answer:
none
Step-by-step explanation:
accellus
The inverse matrix or type none of the given matrix is given as [tex]\rm A^{-1} = \dfrac{1}{-5}\begin{bmatrix}3& 4\\2 & 1 \\\end{bmatrix}\\[/tex].
What is the matrix?A matrix is a specific arrangement of items, particularly numbers. A matrix is a row-and-column mathematical structure. The a_{ij} element in a matrix, such as M, refers to the i-th row and j-th column element.
The matrix is given below.
[tex]A = \begin{bmatrix}3& 2\\4 & 1 \\\end{bmatrix}[/tex]
Then the transpose of a will be
[tex]\rm adj \ A = \begin{bmatrix}a_{11} & a_{21} \\a_{12} & a_{22} \\\end{bmatrix}\\\\\rm adj \ A = \begin{bmatrix}3& 4\\2 & 1 \\\end{bmatrix}[/tex]
Then the value of matrix A will be
[tex]\rm \left| A \right|= \begin{vmatrix}3& 2\\4 & 1\end{vmatrix}\\\\\left| A \right|= 3*1 - 4*2\\\\|A| = -5[/tex]
Then the inverse matrix is defined as
A⁻¹ = Adj A / |A|
Then we have
[tex]\rm A^{-1} = \dfrac{\begin{bmatrix}3& 4\\2 & 1 \\\end{bmatrix}}{-5}\\\\\\A^{-1} = \dfrac{1}{-5}\begin{bmatrix}3& 4\\2 & 1 \\\end{bmatrix}\\[/tex]
More about the matrix link is given below.
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Check the box labeled Show Altitude of Triangle ABC. The altitude divides into and through the point you determined in question 2. Measure and record the side lengths of and . Then measure and record the side lengths of and .
Answer:
Step-by-step explanation:
Step-by-step explanation:
.hhx cvs Gunther b but kcm
PLS HELP ASAP, I give 15 pts!
Suppose an isosceles triangle ABC has A=pi/4 and b=c=3. What is the length of a^2?
A. 3^2(2 - sqr2)
B. 3^2( sqr2 - 2)
C. 3^2(2 + sqr2)
D. 3^2 sqr2
Answer:
I believe it would be A 3^2(2-sqr2)
Sketch the graph of each of the following quadratic functions: (a) f(x) = -2x² + 7x + 4 for -1 ≤ x ≤ 5.
Help me with this ques pleasee,i'll mark u as the brainliest!!
Answer:
Please find attached the graph of the function created with MS Excel showing the relevant points required to draw an approximate graph of the function on a graph paper
Step-by-step explanation:
The given quadratic function is f(x) = -2·x² + 7·x + 4
The range of the input (x) values = -1 ≤ x ≤ 5
The coefficient of the quadratic is negative -2, the graph is n shape
The intercept form of the function is given as follows;
-2·x² + 7·x + 4 = -1 × (2·x² - 7·x - 4)
-1 × (2·x² - 7·x - 4) = -1 × (2·x² + x - 8·x - 4)
-1 × (2·x² + x - 8·x - 4) = -1 × (x · (2·x + 1) - 4·(2·x + 1))
∴ -1 × (x · (2·x + 1) - 4·(2·x + 1)) = -1 × (2·x + 1)·(x - 4)
∴ f(x) = -2·x² + 7·x + 4 = -1 × (2·x + 1)·(x - 4)
At the x-intercepts, (2·x + 1) = 0 or (x - 4) = 0, which gives;
x = -1/2 or x = 4
Therefore, the x-intercepts are (-1/2, 0), (4, 0)
The equation in vertex form is given as follows;
f(x) = -2·x² + 7·x + 4 = -2·(x² - 7·x/2 + 2)
By applying completing the squares method, to x² - 7·x/2 - 2, we get;
Where x² - 7·x/2 - 2
x² - 7·x/2 = 2
x² - 7·x/2 + (-7/4)² = 2 + (-7/4)² = 81/15
(x - 7/4)² = 81/16
∴ (x - 7/4)² - 81/16 = 0 = x² - 7·x/2 - 2
∴ x² - 7·x/2 - 2 = (x - 7/4)² - 81/16
-2·(x² - 7·x/2 + 2) = -2·((x - 7/4)² - 81/16) = -2·(x - 7/4)² + 81/8
The vertex = (7/4, 81/8)
When x = 0, we get;
f(0) = -2 × 0² + 7 × 0 + 4 = 4
The y-intercept = (0, 4)
The sketch of the function should pass through the x-intercepts (-1/2, 0), (4, 0), the y-intercept (0, 4), and the y-intercept (0, 4), and the vertex, (7/4, 81/8) on a graph sheet
Please find attached a drawing of the function of the function created with MS Excel
A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made.
Answer:
0.7744 = 77.44% probability of getting two good coils when two coils are randomly selected
Step-by-step explanation:
For each coil, there are only two possible outcomes. Either it is good, or it is not. Since the coil taken is replaced, the probability of choosing a good coil on a trial is independent of any other trial, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
88 out of 100 are good:
This means that [tex]\pi = \frac{88}{100} = 0.88[/tex]
Find the probability of getting two good coils when two coils are randomly selected.
This is P(X = 2) when n = 2. So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{2,2}.(0.88)^{2}.(0.12)^{0} = 0.7744[/tex]
0.7744 = 77.44% probability of getting two good coils when two coils are randomly selected
(6ab-8a+8) - (7ab-1 )
Answer:
[tex]- ab - 8a + 9[/tex]
Step-by-step explanation:
[tex](6ab - 8a + 8) - (7ab - 1) \\ 6ab - 8a + 8 - 7ab + 1 \\ - ab - 8a + 9[/tex]
hope this helps you.
Answer:
-ab - 8a + 9
Step-by-step explanation:
(6ab - 8a + 8) - (7ab - 1) =
= 6ab - 8a + 8 - 7ab + 1
= -ab - 8a + 9
Are the two triangles similar. If so, State how
Answer:
SAS
Step-by-step explanation: every triangle contains a total of 180 degrees if you substract 180 by 60+70(which is 130) you would get 50 degrees which is the exact degree missing in the first triangle, so after confirming that both triangles have an equal degrees on each side the answer would be SAS (which stands for Side-Angle-Side), SAS is the answer you would give to triangles that are congruent(equal)
This year, Carlos planted 6 more than one-third of the cucumber plants he planted last year. How many cucumber
plants did he plant this year if last year he planted 12 plants?
06
09
O 10
12
Answer:
10
Step-by-step explanation:
last year he planted 12.
1/3 of that is 12/3 = 4.
6 more than that is 4 + 6 = 10.
Answer: C.) 10
Step-by-step explanation:
Find the values of x and y.
Answer:
since y is across from 60 so
y=60
and on the bottom it is 15 so
x+3=15
x=12
Hope This Helps!!!
Find the value of x from the following given figures.
solution :-
here,
We know that interior opposite angles are equal.
So,
110° = 50° + x (being interior opposite angles)
110° - 50° = x
60° = x
the value of x =60°
hope it is helpful to you ☺️
if f(x)=2x/x-5 find f^-1(x)
Answer:
[tex]f^{-1}[/tex] (x) = [tex]\frac{5x}{x-2}[/tex]
Step-by-step explanation:
let y = f(x) and rearrange making x the subject
y = [tex]\frac{2x}{x-5}[/tex] ( multiply both sides by x - 5 )
y(x - 5) = 2x ← distribute left side
xy - 5y = 2x ( subtract 2x from both sides )
xy - 2x - 5y = 0 ( add 5y to both sides )
xy - 2x = 5y ← factor out x from each term on the left side )
x(y - 2) - 5y ← divide both sides by y - 2
x = [tex]\frac{5y}{y-2}[/tex]
Change y back into terms of x with x = [tex]f^{-1}[/tex] (x) , then
[tex]f^{-1}[/tex] (x) = [tex]\frac{5x}{x-2}[/tex]
Look into the image. I hope it helps❤
#CarryOnLearningcan anyone please explain this?
Find the equation of locus of a point A(-3,2) and B(0,4).....
what is locus actually?
Answer:
Solution given:
Let there be a point P(x, y) equidistant from
A(-3, 2) and B(0,4),
so PA = PB,
[tex]\sqrt{(x+3)²+(y-2)²}=\sqrt{(x-0)²+(y-4)²}[/tex]
squaring both side
[tex](\sqrt{(x+3)²+(y-2)²})^{2}=(\sqrt{(x-0)²+(y-4)²})²[/tex]
x²+6x+9+y²-4y+4=x²+y²-8y+16
x²+6x+y²-4y-x²-y²+8y=16-4-9
6x-4y+8y=3
6x-4y=3 is a required locus
Actually:
A locus is a curve or other figure formed by all the points satisfying a particular equation of the relation between coordinates, or by a point, line, or surface moving according to mathematically defined conditions.
PLEASE HELP!
y = 2x − 1
y = 4x - 5
solve both :)
Answer:
x=2
Step-by-step explanation:
We have
y = 2x-1
y= 4x-5
Therefore, as 2x-1=y=4x-5, we can say that
2x-1=4x-5
add 1 to both sides to make one side have only x components
2x = 4x-4
subtract 4x from both sides to separate the x components
-2x = -4
divide both sides by -2 to separate the x
x = 2
Water is filling a swimming pool at a constant rate. After 4 hours, 2 inches of water have filled the pool. Write an equation that gives the amount of water, w, after t hours.
Answer:
Step-by-step explanation:
Inches per hour is the rate we are looking for here, which will then be the slope of the linear equation. Slope is the same thing as the rate of change. While this may not seem all that important right now, it's actually a HUGE concept in higher math, especially calculus!
If the pool is filling at a rate of 2 inches per every 4 hours, then by dividing, we get that the rate is 1 inch every 2 hours, which translates to a slope of 1/2. Creating an equation with this slope:
[tex]w=\frac{1}{2}t[/tex] Let's check it. We are told that after 4 hours there are 2 inches of water in the pool. That means if we plug in 4 for t and solve for w, we should get w = 2:
[tex]w=\frac{1}{2}(4)[/tex] and
w = 2. So we're good!