what is the relationship between the edge length of a unit cell and atomic radius in a hexagonal closest packed crystal structure?

o-xylene, m-xylene, and p-xylene are structural isomers.

o-xylene, m-xylene, and p-xylene are examples of aromatic isomers, also known as ortho-, meta-, and para-xylene, respectively. These isomers are classified as aromatic because they are part of a family of compounds known as aromatic hydrocarbons, which contain a ring of six carbon atoms bonded to each other in a specific way.

o-xylene, m-xylene, and p-xylene are also examples of structural isomers. Structural isomers are compounds that have the same molecular formula but differ in the arrangement of their atoms. In the case of o-xylene, m-xylene, and p-xylene, the atoms are arranged differently around the ring of six carbon atoms.

o-xylene, m-xylene, and p-xylene are not optical isomers, which are also known as enantiomers. Optical isomers are compounds that are mirror images of each other but are not superimposable. Optical isomers are important in medicinal chemistry because they can have different biological properties even though they have the same molecular formula and structure.

o-xylene, m-xylene, and p-xylene are also not geometric isomers. Geometric isomers are compounds that have the same molecular formula and the same arrangement of atoms, but differ in the orientation of their atoms or groups of atoms in space. Geometric isomers are often found in compounds with cis-trans double bonds or ring structures.

The formula unit of a salt that is not correct is [tex]Ca_{2} O[/tex] in option C.

A salt is almost always made up of a metal and a nonmetal element. The salts as we know them are mostly ionic in nature and they are known to be able to dissolve in solution when they are put into solution.

We know that the salt that they meant to show in option C is calcium oxide and the foregoing can not be the correct formula since both the calcium and the oxygen ions are divalent. The correct formula of the salt would be CaO.

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Answer: Dinitrogen trioxide

Explanation:

if the reaction yields 21.1l of nitrogen gas, 40.81g  mass of nan3 in grams would be required to produce this volume at stp

mass of NaN3 (g) = moles of NaN3 (ma) x molar mass of Na N3 (g/mol) = 0-678 mol 65 g/mol =40.81g. A chemical compound's molar mass is described as the weight of a sample of that chemical divided by the quantity of substance in that sample, which is the quantity of moles in that sample, evaluated in moles. The molar mass of a substance is a mass property, not a molecular property. It is the connection between pressure, volume, moles, and temperature. is the volume that one mole of the a chemical substance or a chemical compound takes up. As a result, at STP, the molar volume of a gas is 22.4 litres.

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The total binding energy of 80Zr is therefore approximately 4.58MeV.

An isotope is an atom of a particular element that has a different number of neutrons than other atoms of that same element. This difference in the number of neutrons causes the isotopes to have different atomic masses. Isotopes of an element can be either stable or unstable. Stable isotopes are not radioactive and do not decay, while unstable isotopes are radioactive and undergo radioactive decay.

The total binding energy of 80Zr can be estimated using the mass defect of the two isotopes. According to the semi-empirical mass formula, the binding energy of a nucleus is related to its mass defect. The mass defect of the two nuclei can be calculated by subtracting the mass of the separate nuclei from the mass of the combined nucleus.

The mass of 40Ca is 39.96259 amu and the mass of 80Zr is 79.91652 amu. The combined mass of the two nuclei is 119.87911 amu.
The mass defect of the combined nucleus is therefore 119.87911 - 39.96259 - 79.91652 = 0.005 amu,
or 0.005 x 931.5 MeV/amu = 4.58MeV.
The total binding energy of 80Zr is therefore approximately 4.58MeV.

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Sulfur hexafluoride gas has a mass of 2.8 g and a molecular weight of 0.019 when it is collected at in an evacuated flask with volume of 5.0L

To calculate the moles of sulfur hexafluoride gas, we use the equation given by ideal gas: PV =nRT

Given Pressure of sulfur hexafluoride (P) = 0.090 atm

Volume of the sulfur hexafluoride gas (V) = 5.0 L

Gas constant (R) = 0.0821

Temperature of sulfur hexafluoride gas (T) = 14C+273 = 287K

n = PV/RT = 0.090x5/0.0821x287 = 0.019mol

To calculate mass n = given mass/Molar mass

Molar mass of sulfur hexafluoride = 146.0 g/mol

mass = nxM = 0.019x146 = 2.8g

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complete question: Sulfur hexafluoride gas is collected at 14.0°C in an evacuated flask with a measured volume of 5.0L. When all the gas has been collected, the pressure in the flask is measured to be 0.090atm . Calculate the mass and number of moles of sulfur hexafluoride gas that were collected. Be sure your answer has the correct number of significant digits.

Answer: 8N (8 kg/ms")

Explanation: F= M*A

F= (2KG)*(4/MS") = 8N

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To balance this chemical equation, we need to make sure that there is the same number of atoms of each element on both sides of the arrow.

We can start by looking at the nitrogen atoms. There is one nitrogen atom on the left side of the arrow, but there are two nitrogen atoms on the right side of the arrow. To balance the equation, we can add a coefficient of 2 in front of N₂ on the left side of the arrow:

2N₂(g) + H₂(g) → NH3(g)

Next, we can look at the hydrogen atoms. There are two hydrogen atoms on the left side of the arrow, but there is only one hydrogen atom on the right side of the arrow. To balance the equation, we can add a coefficient of 3 in front of NH3 on the right side of the arrow:

2N₂(g) + H₂(g) → 3NH3(g)

Now the equation is balanced, with two nitrogen atoms and two hydrogen atoms on each side of the arrow. The smallest possible whole number stoichiometric coefficients are 2 for N₂ and 3 for NH3.

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(a) sp2- hybrid orbital of C1 and p-orbital of O1 , because, central atom i.e. carbon has sp2-hybridization and in surrounded oxygen atom last electrons enters in p-orbital. (b) 1200 bond angle, because shape is trigonal planar.

Atomic orbitals are generally specific through a mixture of numerals and letters that constitute precise residences of the electrons related to the orbitals—for example, 1s, 2p, 3d, 4f. The numerals, referred to as primary quantum numbers, imply strength degrees in addition to relative distance from the nucleus. The simple names s orbital, p orbital, d orbital, and f orbital refer to orbitals with angular momentum quantum number ℓ = 0, 1, 2, and 3 respectively.

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The amount of gtt/min that should fall into the drip chamber is given as follows:

20.8.

The amount of gtt/min that should fall into the chamber is found applying the proportions considering the amounts given in the problem.

The provider has ordered an i.v. of 5% dextrose in lactated ringer's solution at 125 ml/hr, and the i.v. tubing delivers 10 gtt/ml, hence the amount of gtt per hour is obtained as follows:

gtt/hr = 125 x 10 = 1250.

An hour is composed by 60 minutes, hence, applying this proportion, the amount of gtt/min that should fall into the drip chamber is calculated as follows:

gtt/min = 1250/60 = 20.8.

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Two isomeric monobromination products should result from the allylic bromination of methylene cyclohexane, according to expectations. The final product will be 1-(bromomethyl)cyclohexene.

N-Bromosuccinimide, also known as NBS, is a chemical reagent utilized mostly in organic chemistry's electrophilic addition, electrophilic substitution, and radical substitution processes. It is regarded as an easy way to get bromine radicals. NBS interacts with the substance in an aqueous solution in alkenes to produce bromohydrins as the end result.

Allylic bromination is defined as the reaction employing NBS that results in the substitution of a bromine atom for hydrogens on a carbon next to a double bond.

Following  drawing of the methylene cyclohexane extended structure, the reaction will be carried out using the reagent NBS.

The IUPAC name of the product is 1-(bromomethyl)cyclohexene.

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The statement given is "False" that The Aerobic decomposition of biomass produces significant quantities of Methane.

What is aerobic decomposition?

The decay or breaking down of organic material in the presence of free or dissolved oxygen (DO).

What does aerobic decomposition produce?

Compost, water (both liquid leachate and gaseous vapor), and volatilized gases are all products of aerobic composting (ammonia, carbon dioxide and, occasionally, gases perceived as odors). Digestate and biogas are created during anaerobic digestion.

Is aerobic decomposition faster than anaerobic?

You can get finished compost sooner if there is enough air available because aerobic decomposers function faster and more effectively than their anaerobic cousins.

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Answer:

39.0

Explanation:

Substance is fast acting, either immediately suffocating the victim or causing massive burning is chemical weapons.

Chemicals used to intentionally kill or damage people through their poisonous qualities are known as chemical weapons. Chemical weapons also include weapons, apparatus, and other gear made expressly for turning hazardous substances into weapons.

What chemical weapon has the highest lethality?

What VX is VX is a nerve toxin that was created by humans for use in chemical warfare. The most dangerous and quickly acting of the known chemical warfare agents are nerve agents.

Basically, these weapons were just common munitions like grenades and artillery rounds that had well-known industrial chemicals added to them. Among the chemicals employed were chlorine, mustard gas, which causes terrible skin burns, and phosgene, a choking toxin.

The most critical effects are paralysis of the respiratory muscles and inhibition of the respiratory center. Ultimately, death results due to respiratory paralysis. If the concentration of the nerve agent is high, death is immediate.

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The pressure that the gas exerts at the higher temperature would be 20.83 atm.

According to Gay-Lussac's law, the pressure that a gas will exert on its container is directly proportional to the temperature of the gas, provided that the volume remains constant throughout.

This law can be mathematically expressed as:

[tex]p_1/t_1 = p_2/t_2[/tex]

Where:

In this case, the initial temperature is given as 18 [tex]^oC[/tex], the initial pressure is given as 2.5 atm, and the final temperature is given as 150 [tex]^oC[/tex], We are to find the final pressure.

[tex]p_2[/tex] = [tex]p_1t_2/t_1[/tex]

   = 2.5x150/18

   = 20.83 atm

In other words, the new pressure that the gas will exert at a temperature of 150 [tex]^oC[/tex] would be 20.83 atm.

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Ore veins and disseminated deposits are  differ in terms of their size, shape, and distribution.

An ore vein is a large, continuous body of mineral deposits that are typically found in fractures or voids in rock formations. Ore veins are typically formed when minerals that are dissolved in water fill a void or crack in a rock formation. Ore veins are typically quite large and can be several meters in width and several kilometers in length. They are also typically found at depths of several hundred meters or more. Ore veins are generally easier to mine because they are more concentrated and can be more easily accessed through underground mining methods.

A disseminated deposit, on the other hand, is a type of mineral deposit that is dispersed or scattered throughout a larger rock formation. Disseminated deposits are usually smaller and less concentrated than ore veins and are typically found at shallower depths. They are often harder to mine because the minerals are not as concentrated and are more dispersed throughout the rock formation

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Kc for the reverse reaction is the negative of Kc for the forward reaction is the false statement.

The equilibrium constant of any chemical reaction is the value of its own reactions quotient at chemicals equilibrium, a State approaches by a dynamically chemicals systems after sufficient times has elapsed at which is in its compositions has no measurable tendency towards furthermore change.

As we know,

Value of Kc for the reverse reaction is always in the from of reciprocal.

Let's take

A<----------------> B,Kc

For reversion reaction we have to take

B<------------------>A,1/Kc

In this equation all the statement are correct.

Thus Kc for the reverse reaction is the negative of Kc for the forward reaction is the correct answer.

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The rate of appearance of o2 at that moment is 2.80 mol/min.

Calculation :

Recall

aA+bB→ cC+dD

[tex]\frac{d[A]}{a.dt}[/tex] =  [tex]\frac{d[B]}{b.dt}[/tex] =  [tex]\frac{d[C]}{c.dt}[/tex]  =  [tex]\frac{d[D]}{d.dt}[/tex]

Then

[tex]\frac{d[NO_{2} ]}{2.dt}[/tex] =   [tex]\frac{d[NO_{2} ]}{4.dt}[/tex]

Replacing :

[tex]\frac{1.4}{2}[/tex] =   [tex]\frac{d[NO_{2} ]}{4.dt}[/tex]  .......   [tex]\frac{d[NO_{2} ]}{dt}[/tex] = 2.8

Degradation is the first step in the recycling of nutrients that an organism (plant or animal) uses to build its body. This is the process by which dead tissue is broken down and transformed into simpler organic forms.They are the food source for many species that underlie ecosystems.

Decomposition or putrefaction is the process by which dead organic matter breaks down into simple organic or inorganic matter such as carbon dioxide, water, simple sugars and inorganic salts. This process is part of the nutrient cycle and is essential for recycling the finite substances that occupy the physical space of the biosphere. An organism's body begins to decompose shortly after death. Animals such as earthworms also help break down organic matter.

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The velocity of an  object is the ratio of the distance to the time. The distance travelled by Kangaroo is 396 m in 12 seconds. So its velocity is 33 m/s.

Velocity is a physical quantity and it is the measure of distance travelled per unit time. Velocity is the rate of speed and it  is a vector quantity.The velocity can be expressed in terms of m/s, Km/hr etc.

Mathematically, velocity is the ratio of distance to the time.

Given that, distance covered by kangaroo is 396 meters.

time taken = 12 s.

therefore, velocity can be calculated as follows:

velocity = distance/time

             = 396 m / 12 s

             = 33 m/s.

Therefore, the velocity of the kangaroo is 33 m/s.

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The frequency of the light emitted by hydrogen is equal to 4.57 Hz.

The frequency of the wave can be defined as the number of oscillations of a wave per second. The frequency has S.I. units of s⁻¹ or Hertz.

The wavelength can be described as the distance between two adjacent crests on a wave.

The relation between frequency, wavelength, and speed of light (c) can be shown as:

c = νλ

Given, the wavelength of the light emitted by H-atom, ν = 6.56 × 10⁻⁷ m

The speed of light, [tex]c =3 \times 10^8\; m/s[/tex]

The frequency of the light emitted by hydrogen atoms can determine from the above-mentioned relationship:

ν= c/λ = 3 ×10⁸/6.56 × 10⁻⁷ = 4.57 Hz

Therefore, the frequency of the emitted light is equal to 4.57 Hz.

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The enthalpy of vaporization for this compound is 22.0 kJ/mol.

Vaporization is a process in which a liquid or solid is transformed into a gaseous state. It occurs when molecules in the liquid or solid absorb enough energy to break their intermolecular bonds and become a gas. This process can be carried out either through the application of heat or pressure, or through a process known as sublimation, which occurs when a solid is exposed to a vacuum.

ΔHₙ = ΔHₓ - ΔHₐ

Where, ΔHₙ = Enthalpy of vaporization

ΔHₓ = Enthalpy of sublimation (32.4 kj/mol)

ΔHₐ = Enthalpy of fusion (10.4 kj/mol)

ΔHₙ = 32.4 - 10.4

ΔHₙ = 22.0 kJ/mol

The enthalpy of vaporization for this compound is the difference between the enthalpy of sublimation and the enthalpy of fusion. Therefore, the enthalpy of vaporization for this compound is 22.0 kJ/mol.

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1.62 moles of air the toy now contain. At STP, moles can be converted to gas volume and gas volume to moles using molar volume.

An experimental gas law known as Avogadro's law or Avogadro-hypothesis Ampère's connects the volume of a gas to the amount of gas material present. The law is an instance of the ideal gas theory.

At constant temperature and pressure, volume is directly proportional to the number of moles of the gas.

The formula used for solving this type of problems is:

v1 / v2 = n1/ n2

let's plug in the given values in the formula:

5.17 / 8.00 = 1.05 m / n2

n2 = 8.00 * 1.05  /  5.17

n2 = 1.62 moles

So, the toy contains 1.62 moles of air when it's volume is 8.00 Liter.

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The initial and final states if an electron in hydrogen emits a photon with a wavelength of 656 nm  is n = 3 to n = 2.

given that :

wavelength of the photon emitted λ = 656 nm = 656 × 10⁻⁹ m

the energy of the photon is given as :

E = hc / λ

  = (6.626 × 10⁻³⁴ × 3 ×10⁸ ) / 656 × 10⁻⁹

  = 3 × 10⁻¹⁹ J  = 1.9 eV

En = - 13.6 / n² eV

where n = 1,2,3 ....

1) n = 2 to n = 1

E2 - E1 = - 13.6 eV ( 1 / 4 - 1/ 1)

           = 10.2 eV

2) n = 3 to n = 2

E3 - E2 = -13.6 eV ( 1/3² - 1/ 2² )

            = 1.9 eV

Thus the initial and the final states are n = 3 to n = 2.

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The pH change is +0.125 when 20.0 ml of 0.100 m naoh is added to 80.0 ml of a buffer solution consisting of 0.166 m nh3 and 0.186 m nh4cl.

Find the moles of NaOH and the moles of your initial acid and base, calculate the new molarities, and use the henderson-hasselbalch equation with your new concentrations. So I used the pKa of NH4Cl for the initial pH. (9.3). pH = 9.3 + log (0.169M/0.183M), and I measured 9.265, which is slightly different. Then, using M = mol/L 0.1M = x mol/0.02L, I calculated the moles of NaOH, which were 0.002. I used the same method to determine the moles of NH3 and NH4Cl, which were 0.0135 and 0.01464, respectively, after determining the moles of NaOH.When a strong base is added to a buffer, the acidic component reacts with the added base, releasing OH- ions and increasing the moles of acid and base, respectively. With this information, I added the number of moles of NaOH to the moles of NH3 0.0135 + 0.002 = 0.0155 moles and subtracted the number of moles of NaOH from the moles of NH4Cl 0.01464 - 0.002 = 0.01264 moles, then calculated the molarities by dividing the moles by (0.08 L + 0.02 L to account for the addition of NaOH), and calculated the new concentrations.[NH3] = 0.155M, [NH4Cl] = 0.1264M, now that we have the new concentrations of acid and base, substitute them into the H-H equation to get the new pH: pH = 9.3 + log (0.155/0.1264) = 9.39.9.39 - 9.265 = a pH change of +0.125.

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The speed of sound in given substances from slowest to fastest: 25°C air, 50°C air, water, steel.

Sound can transmit through liquids, gases, solids, and plasma as longitudinal waves, these are also known as compression waves. Sound waves need a medium to travel so they can be propagated through solids as longitudinal and transverse waves.

Longitudinal sound waves exhibit alternating pressure deviations leading to compression and rarefaction, while transverse waves exhibit alternating shear stress perpendicular to the propagation path.

Waves can cause matter to move up and down but can not carry along with them. As the temperature of the air increases the molecules start to vibrate faster eventually the speed of the sound increase.

The speed of sound is lowest in gases, faster in water, and fastest in steel (solid).

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A radioactive atom emits a cluster of neutrons and protons-235  heavier than an alpha particle in a process known as cluster decay.

Cluster decay, also known as heavy particle radioactivity or heavy ion radioactivity, is a very uncommon form of nuclear decay in which an atomic nucleus generates a small "cluster" of neutrons and protons, more than in an alpha particle but less than a typical binary fission fragment. The cluster size is also produced by ternary fission into three fragments. When the parent nucleus loses protons, it becomes the daughter nucleus, which has an atomic number Zd = Z + Ze and a mass number Ad = A Ae, where Ae = Ne + Ze. [1] For instance

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The solubility of a gas is directly proportional to the pressure and proportional to the temperature.

As we increase the pressure of a gas its collision frequency increases hence solubility increases as we decreases the pressure the solubility decreases. Collision frequency is defined as the collision of atoms on increasing pressure atoms start moving from one place to another. The relationship pressure is linear with solubility. It is defined by Henry's law.

The effect of temperature depends on the nature of solute and solvent.

Basically, as we increase the temperature in gas phase solubility also increases.

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The chloride ions  in a mixture of 2mol of barium chloride and 1 mol of potassium chloride are 3 moles

Generally, Barium chloride is an inorganic compound with the formula BaCl2. It is a white solid that is highly soluble in water. It is commonly used as a test for detecting the presence of sulfates in a solution and as a precursor to other barium compounds. Barium chloride is toxic if ingested, so it should be handled with caution.

There are a total of 3 moles of chloride ions in the mixture of 2 moles of barium chloride and 1 mole of potassium chloride.

Barium chloride contains 2 moles of chloride ions, and potassium chloride contains 1 mole of chloride ions, for a total of 2 + 1 = 3 moles of chloride ions.

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The formula for PPM  =100 /1,000,000=0.01 PPM = 100 / 1 , 000 , 000 = 0.01 . i.e concentrations of arsenic should be less than 0.01 *1000 therefore it should be less than 10 ml for 1000ml of water.

This stands for "parts per million" and can alternatively be written as mg/L (milligrams per liter). The mass of a chemical or contamination per volume of water is the unit of measurement here. On a lab report, ppm or mg/L both signify the same thing. It provides information about a substance's density when it is dissolved in water. Examples include total alkalinity, calcium hardness, and free chlorine. A substance has a PPM of 1 if it makes up one millionth of the entire amount of water.

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