What is the range of function g?
g(x) = /x-1+2
A. y > 1
B. y > 2
C. y <2
D. y <1

Answer:

180 degree

Step-by-step explanation:

180 degee

......

......

.......

Answer:

Step-by-step explanation:

9^2

=9*9

=81

15^2

=15*15

=225

(0.2)^2

=0.2 * 0.2

=0.04

(0.7)

=0.7

Answer:

The value of m is 9.

Step-by-step explanation:

We need to set up an algebraic equation, then solve.

(-3 * m) + 7 = -20

-3m + 7 = -20

Subtract 7 from both sides so we can get -3m by itself. We are isolating it.

-3m + 7 - 7 = -20 - 7

-3m = -27

Divide by -3 on both sides.

m = 9

The value of m is 9.

Answer:

V=πr2h /3

so we just substate and we get

V≈130.9

Answer: 130.83 units cubed

Step-by-step explanation:

The formula for finding the volume of a cone is [tex]\pi r^2\frac{h}{3}[/tex]

We will use 3.14 for pi.

[tex]3.14r^2\frac{h}{3}[/tex]

Now let's sub in our variables and solve

[tex]3.14(5^2)(\frac{5}{3})\\3.14(25)(\frac{5}{3})\\78.5(\frac{5}{3})\\130 \frac{5}{6}[/tex]

5/6 is about .83

130.83

Answer:

I say number 2 idrk so I hope I helped >-<

Answer:

Step-by-step explanation:

first work what's in the brackets { 4 x 2 -10}^3

{4 x 2-1000}

4 x -998

Step-by-step explanation:

obtuse angle is an angle whose measure is more than 90 degree but less than 180 degree..

So,

170°

Answer:

4 months

Step-by-step explanation:

Let x be the number of months

Dusty started at 2 lbs, and gains 1 lb every month

So we can make the equation

2+x=6

x=4

At 4 months, Dusty was 6 lbs

Answer:

x = 10/11

Step-by-step explanation:

Your welcome! :)

Answer:

6,825

Step-by-step explanation:

The principlal is #65,000

Rate, = 2%

= 2/100

= 0.02

Time= 5+0.25

= 5.25

Simple interest= 65,000×0.02×5.25

= 6,825

Answer:

The number is four (4)

Step-by-step explanation:

look at the picture above, it explains everything

9514 1404 393

Answer:

  x = 64

Step-by-step explanation:

The two base angles in the isosceles obtuse triangle are equal, so are both 29°. The sum of these angles is 58°, which is the measure of the external acute angle at the upper left of the acute triangle.

The two base angles of the acute isosceles triangle are equal, so are both 58°. The angle marked x° has a measure that makes the sum of angles in that triangle be 180°.

  x° = 180° -2(58°)

  x° = 64°

Answer:

1/2 times 1/9

which equals 1/18

Step-by-step explanation:

5/10 equals 1/2 and /9 equals *1/9

Answer: i think its 1/9

The answers isssssssss

$300

:)

Answer:

n < 17

Step-by-step explanation:

2n-9<25

Add 9 to each side

2n-9+9<25+9

2n < 34

Divide each side by 2

2n/2 < 34/2

n < 17

Answer:

n < 17

Step-by-step explanation:

Move the constant to the right -hand side and change its sign

2n<25+9

Then add the numbers

2n < 34

Divide both sides of the inequality by 2

so that would be n<17

Answer:

I don't know what your school is doing but what happened to me was that I just waited for the test to be unlocked and I was working from home so I was able to keep my phone and I didn't need to be in a meeting

Answer:

The graph is in the second attached image.

Step-by-step explanation:

In the first attached image, you have three equation graphed, the first is in red color, it's the original equation:

I graphed this to obtain a clear relation between the equation and its derivatives, the second graphed equation is in blue color and it's the first derivative:

And at last, we have in green color the second derivative:

As you can see, you only need the first and the second derivatives in the exercise, by this reason, in the second attached image you have the graph as you need to show in this exercise.

Answer:

m<1 = 60

m<2 = 30

m<3 = 80

Step-by-step explanation:

1. Solve for angle (1)

The sum of angles in any triangle is (180) degrees. As one can see, there is a (30) degree angle in this triangle, and a (90) degree angle. Bear in mind that the box around an angle indicates that it is a (90) degree angle. One can form an equation and solve for the unknown angle using this given information;

(30) + (m<1) + (90) = 180

Simplify,

120 + m<1 = 180

Inverse operations,

m<1 = 60

2. Solve for angle (2)

The vertical angles theorem states that when two lines intersect, the angles opposite each other are congruent. One can apply this theorem here by stating the following,

m<2 = 30

Thus one gets their answer, the measure of angle (2) must be (30) degrees by the vertical angles theorem.

3. Solve for angle (3)

As states above, the sum of angles in a triangle is (180) degrees. Since one has found the measure of angle (2), one can form an equation and solve for the measure of angle (3) using the given information, combined with the information found.

(m<2) + (70) + (m<3) = 180

Susbtitute,

30 + 70 + (m<3) = 180

Simplify,

100 + m<3 = 180

Invers eoperations,

m<3 = 80

Answer:

Los costos de fabricación fijo y variables al 80 y 100% de su capacidad son:

80%:        Fijos  =  $169,000,000.00        Variables  =  $180,000,000.00

100%:        Fijos  =  $169,000,000.00        Variables  =  $225,000,000.00

Explicación:

Los costos totales de fabricación (CT) vienen dados por la suma de los costos fijos (CF) y los costos variables (CV), recordando que los costos fijos son aquellos en los que se incurre independientemente de que se esté operando o no; mientras que los costos variables son aquellos que dependen del nivel de actividad pues corresponden a consumibles en el proceso productivo.

En el caso estudio, se sabe que los costos variables de fabricación totalizan $180,000,000.00 al nivel de actividad de 80%. Ya que estos costos incrementan o disminuyen en relación con el nivel de actividad, planteamos una regla de tres simple para calcular los costos variables en los niveles de actividad 90% y 100%

Si al    80%    de actividad    ----------------    los CV son    $180,000,000.00

al    90%    de actividad        ----------------    los CV serán    x

x  =  [(90)(180,000,000.00)]/(80)  =  202,500,000.00

Los costos variables de fabricación al nivel de actividad de 90% son  $202,500,000.00

Si al    80%    de actividad    ----------------    los CV son    $180,000,000.00

al    100%    de actividad       ----------------    los CV serán    x

x  =  [(100)(180,000,000.00)]/(80)  =  225,000,000.00

Los costos variables de fabricación al nivel de actividad de 100% son  $225,000,000.00

Para conocer los costos fijos basta recordar que al nivel de actividad de 90% lo costos de fabricación totales son $371,500,000.00. Este monto es la suma de los costos fijos y los costos variables; así que:

CT  =  CV  +  CF             ⇒                CV  =  CT  -  CF          ⇒    

CV  =  371,500,000.00  -  202,500,000.00  =  169,000,000.00

Los costos fijos de fabricación son de $169,000,000.00

Conclusión:

Los costos de fabricación fijo y variables al 80 y 100% de su capacidad son:

80%:        Fijos  =  $169,000,000.00        Variables  =  $180,000,000.00

100%:        Fijos  =  $169,000,000.00        Variables  =  $225,000,000.00

Step-by-step explanation:

Maple calculator used.........................

Answer:

Step-by-step explanation:

[tex]f(x)={x^2\sqrt{1+x}\over{(1+x^2)^{3\over{2}}}}\\\\f^\prime (x)=\frac{{{(x^2\sqrt{1+x})^\prime (1+x^2)^{\frac{3}{2}}+ (x^2\sqrt{1+x})}((1+x^2)^{\frac{3}{2}}})^\prime}{((1+x^2)^\frac{3}{2})^2}}}[/tex]

[tex](x^2 \sqrt{1+x})^\prime=2x\sqrt{1+x}+ \frac{x^2}{2\sqrt{1+x}}[/tex]

[tex]((1+x^2)^{\frac{3}{2}})^\prime=\frac{3}{2}(1+x^2)^{\frac{1}{2}} (2x)=3x(1+x^2)^{\frac{1}{2}}[/tex]

[tex]f^\prime(x)=\frac{\{(1+x^2)^{\frac{3}{2}}\}(2x\sqrt{1+x}+\frac{x^2}{2\sqrt{1+x}})+(x^2 \sqrt{1+x})(3x\sqrt{1+x^2})}{(1+x^2)^{3}}}[/tex]

[tex]\sqrt{1+x^2}=\sqrt{(1+x)(1-x)}[/tex]

[tex]f^\prime (x)=x\sqrt{1+x}~\frac{(1+x^2)^{\frac{3}{2}}(2+\frac{x^2}{2(1+x)})+3x^2\sqrt{1-x}}{(1+x^2)^3}[/tex]

Answer:

E is the subset of I

S is the subset of T

R ⊂ P

Step-by-step explanation:

Answer:

Alternate exterior

Step-by-step explanation:

Angles 2 and 7 are on exterior sides of the transversal and also are opposite to one another. They are classified as alternate exterior.

Answer:

alternate exterior angles

Step-by-step explanation:

2 and 7 are on opposite sides of the transversal so they are called alternate

They are on the outside of the parallel lines so the are called exterior

9514 1404 393

Answer:

  (x, y) = (2, 3)

Step-by-step explanation:

The first step is to find the least common multiple of the denominators of each of the equations. If the denominators have no common factors, a reasonable choice is their product. Here, it works to start with the fractions that must be added, then compare the LCM found to the denominator on the right to see if any further factors must be included.

First equation:

  LCM = 3×4 = 12

  12(2x/3 -y/4) = 12(7/12) . . . . . multiply the equation by 12

 8x -3y = 7 . . . . . . . . . simplify

Second equation:

  LCM = 4×5 =20

  20(3x/4 -2y/5) = 20(3/10) . . . . multiply equation by 20

  15x -8y = 6 . . . . . . simplify

Solve by elimination

We can eliminate the y-variable by subtracting 3 times the second equation from 8 times the first:

  8(8x -3y) -3(15x -8y) = 8(7) -3(6)

  19x = 38 . . . . . simplify

  x = 2 . . . . . . . divide by 19

Substituting into the first equation gives ...

  8(2) -3y = 7

  3y = 9 . . . . . . add 3y-7

  y = 3 . . . . . divide by 3

The solution is ...

  (x, y) = (2, 3)

_____

There are many ways to solve such a system of equations. Using the LCM to eliminate fractions is one way to start. You can also do the arithmetic with the fractions intact, though most folks don't care to. In addition to the elimination method used here, you can use matrix or graphical methods, substitution, or any of the variations of Cramer's Rule.

Answer:

71

-133

Step-by-step explanation:

Given the polynomial :

3x³– 4x² + 7x + 5, when x = 3 and also when

x = –3.

Put x = 3

3(3)³– 4(3)² + 7(3) + 5

3(27) - 4(9) + 21 + 5

81 - 36 + 21 + 5

= 71

Put x = - 3

3(-3)³– 4(-3)² + 7(-3) + 5

3(-27) - 4(9) - 21 + 5

-81 - 36 - 21 + 5

= - 133

Answer:

Step-by-step explanation:

yes

Step-by-step explanation:

Hey there!

LHS

[tex] = \frac{ \cos(a) }{ \tan(a) } [/tex]

Use tan A = sin A/cosA

[tex] = \cos(a) \times \frac{ \cos(a) }{ \sin(a) } [/tex]

[tex] = \frac{ { \cos(a) }^{2} }{ \sin(a) } [/tex]

Then, Use formula cos²A = 1-sin²A and sinA = √(1-cos²A)

[tex] = \frac{1 - { \sin(a) }^{2} }{ \sqrt{ - { \cos(a) }^{2} } } [/tex]

Proved!

Hope it helps!