PLEASE HELP ITS TIMED LITTERALY IM BEGGING :(( 32 points WITH BRAINLIEST!!

Answer:

14

Step-by-step explanation:

Triangle=180

180-90 (RA) = 90

90-41= 39

(2x+11)=39

2x=28

x=14

===================================================

Work Shown:

A = probability of landing on an odd number

A = 5/9 because there are 5 odd numbers out of 9 total

B = probability of getting heads

B = 1/2

C = landing on 3 on the spinner

C = 1/9

Multiply the values of A,B,C

A*B*C = (5/9)*(1/2)*(1/9) = (5*1*1)/(9*2*9) = 5/162

Note: The fraction 5/162 converts to the approximate decimal 0.03086 which then converts to 3.086%, when rounding to the nearest tenth of a percent we get 3.1%

Answer:

164/3

Step-by-step explanation:

Answer:

c) 72

hope this helps!

please give brainiest<3

Answer:

72

Step-by-step explanation:

Substitution:

4^3 + 4 x 6 - 16

64+24-16=72

Answer:

15 players on each team

Step-by-step explanation:

- 2 players from EACH team is subtracted= 2(players)x6(teams) = 12 players in total off the field

- now there are only 78 players on the field

(78+12)/6= 15

-Adding the amount of players on the feild and the players that were sent for equitment is 90. Then dividing 90 by the amount of teams there are, 6

Answer:

should be 3/7 I think that's right

Answer:

HCF×LCM=a×b

6×60=a×b

a×b=360

So the numbers are whose product is 360 and LCM is 60

These two numbers can be 6,60 or 12,30

Answer:

8:6

Step-by-step explanation:

If 8 out of 14 students are boys then the remaining number of students must be girls

So

14-8= 6

There are 6 girls out of the 14

So as a ratio of boys to girls

8:6

Answer:

8 : 6 <or> 4 : 3

Step-by-step explanation:

8 : 6 <or> 4 : 3

Since there are 8 boys out of 14, if you minus them , the answer will be the number of girls out of 14.

Answer:

[tex] \frac{15 \sqrt{209} }{209} [/tex]

Step-by-step explanation:

Objective: Understand and work with trig identies.

Recall multiple trig identies and manipulate them to get from cosecant to secant.

Given

[tex] \csc(a) = \frac{60}{16} [/tex]

Apply reciprocal identity csc a = 1/sin a.

[tex] \sin(a) = \frac{16}{60} [/tex]

Apply pythagorean identity to find cos a.

[tex]( \frac{16}{60}) {}^{2} + \cos(x) {}^{2} = 1[/tex]

[tex] \frac{256}{3600} + \cos(x) {}^{2} = 1[/tex]

[tex] \cos(x) {}^{2} = \frac{3600}{3600} - \frac{256}{3600} [/tex]

We can simplify both expression

[tex] \cos(x) {}^{2} = \frac{225}{225} - \frac{16}{225} [/tex]

[tex] \cos(x) = \frac{ \sqrt{209} }{15} [/tex]

Cosine is positve on quadrant 1 so that cos(a)

Apply reciprocal identity sec a= 1/ cos a.

The answer is

[tex] \sec(a) = \frac{15}{ \sqrt{209} } [/tex]

Rationalize the denominator.

[tex] \frac{15}{ \sqrt{209} } \times \frac{ \sqrt{209} }{ \sqrt{209} } = \frac{15 \sqrt{209} }{209} [/tex]

Answer:

x=5

Step-by-step explanation:

7x - 4y = 23 and x + y = 8

Multiply the second equation by 4

4x + 4y = 32

Add this to the first equation

7x - 4y = 23

4x + 4y = 32

------------------------

11x    = 55

Divide each side by 11

11x/11 = 55/11

x = 5

Answer:

[tex]\huge\boxed{x=5}[/tex]

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}7x-4y=23\\x+y=8&|\text{subtract}\ x\ \text{from both sides}\end{array}\right\\\left\{\begin{array}{ccc}7x-4y=23&(1)\\y=8-x&(2)\end{array}\right\\\\\text{substitute (2) to (1):}\\\\7x-4(8-x)=23\qquad|\text{use the distributive property}\\\\7x+(-4)(8)+(-4)(-x)=23\\\\7x-32+4x=23\qquad|\text{combine like terms}\\\\(7x+4x)-32=23\qquad|\text{add 32 to both sides}\\\\11x-32+32=23+32\\\\11x=55\qquad|\text{divide both sides by 11}\\\\\dfrac{11x}{11}=\dfrac{55}{11}\\\\x=5[/tex]

Answer:

Step-by-step explanation:

Domain of a function is defined by the set of x-values (input values) and Range is the set of y-values (output values) of the function.

1). The range and domain of P = {(x, y)| y = 3}

Domain: Set of all real numbers

Range: {y: y=3}

2). The domain set of C = {(2, 5), (2, 6), (2, 7)}

 Domain: {2}

3). The range set of E = {(3, 3), (4, 4), (5, 5), (6, 6)}

  Range: {3, 4, 5, 6}

4). The range and domain set of F = {(x, y)| x + y = 10}

   Domain = Range = {All real numbers}

Answer:

hypotenuse = 7.3

Step-by-step explanation:

here 7 and 2 are the legs og the right triangle .we should find hypotenuse.

let the legs of the right triangle be a nd b respectively . And c be hypotenuse

using pythagoras theorem to find hypotenuse

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

[tex]\sqrt{53}[/tex] = c

7.28 = c

7.3 =c

Answer:

7.3

Step-by-step explanation:

[tex]7^{2} + 2^{2} = x^{2} \\ 53 = x^{2}\\\sqrt{53} = \sqrt{x^{2}} \\x = 7.3[/tex]

Answer:

p=1

Step-by-step explanation:

2/5 + p = 4/5 + 3/5p

Multiply each side by 5 to clear the fractions

5(2/5 + p) = 5(4/5 + 3/5p)

2 +5p = 4 + 3p

Subtract 3p from each side

2+5p-3p = 4+3p-3p

2+2p = 4

Subtract 2 from each side

2+2p -2 = 4-2

2p =2

Divide by 2

2p/2 = 2/2

p=1

[tex]\huge\mathbb{\fcolorbox{red}{lavenderblush}{✰Answer}}[/tex]

Answer:

D

Step-by-step explanation:

x=16

y=4

4=16-12

4=4

Answer:

D

Step-by-step explanation:

Answer:

[tex]S' = (-5,-5)[/tex]

[tex]Q"=(-5,-5)[/tex]

Step-by-step explanation:

Given

[tex]S = (5,-5)[/tex]

[tex]Q= (5,5)[/tex]

Solving (a): Reflect S across y-axis

The rule to reflect across y-axis is:

[tex](x,y) \to (-x,y)[/tex]

So, we have:

[tex]S(5,-5) \to S'(-5,-5)[/tex]

Hence:

[tex]S' = (-5,-5)[/tex]

Solving (b): Reflect Q across x and y-axis

The rule to reflect across x-axis is:

[tex](x,y) \to (x,-y)[/tex]

So:

[tex]Q(5,5) \to Q'(5,-5)[/tex]

The rule to reflect across y-axis is:

[tex](x,y) \to (-x,y)[/tex]

So:

[tex]Q'(5,-5) \to Q"(-5,-5)[/tex]

Hence:

[tex]Q"=(-5,-5)[/tex]

i dont get it either

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

10 people can go to the amusement park

Step-by-step explanation:

363 - 5.50 = 357.5

357.5 / 35.75 = 10

Answer:

c = 60°

Step-by-step explanation:

Since the measures are among a 90° angle, we need to subtract 30° from 90° which equals 60°

c = 60°

Answer:

$63.30

Step-by-step explanation:

Assuming the $60 is excluding taxes:

60 * 1.055 = $63.30

Answer:

See below.

Step-by-step explanation:

No, a reasonable estimate is around 7 * 6 = 42.

Round $6.99 to $7 and multiply by the 6 family members.

Answer:

if this was a equation you would first subtract 12 from the other number then divide it by 3

Answer:

3(x+4)

Step-by-step explanation:

Check 3(x+4), when you use the distributive property, you get 3x + 12, so this is correct. (sorry, I'm really bad at explaining...)

Answer:

c

Step-by-step explanation:

i hope it helped ᘳ◕ᴥ◕ᘰ

Hope this help!!!

Have a nice day!!!!

Answer:

-5, -3

Step-by-step explanation:

Answer:

119.4

Step-by-step explanation:

The Area of the Rectangle : 132 cm

Area of the Circle : 12.6 cm

Shade=  MINUS - 132 cm  - 12.5 cm = 119.4!

Happy To Help! :)

Answer: 23.4 ft^3

Step-by-step explanation: The perimeter of the base is 10.7, it is a square so the 4 sides of the base are equal. One side of the base is equal to 2.675 if the perimeter (4 sides) is equal to 10.7, so plug that and the height into the formula for the volume of a square pyramid to get 23.38, or 23.4 to the nearest tenth.

Answer:

v ≈ 34.95ft^3

Step-by-step explanation:

h = 9.8ft

A^B = 10.7ft

V=A^B

h/3 = 10.7 • 9.8/3

≈34.95333ft^3

≈34.95ft^3

Answer:

Step-by-step explanation:

Corresponding sides have same ratio:

Find AB:

Find AD:

Now the ratio:

Correct choice is F

Answer:

(x, y) = (10, 290)

Step-by-step explanation:

From the table

Total fees = fixed + variable

Fixed:

When number of times Ahmed mowed, x = 0

y = 40

When x = 2, y = 65

Rate of change = y2 - y1

= 65 - 40

= 25

y = 40 + 25x

Where,

y = total fees charged

40 = fixed fee

25x = variable fee

Total amount Ahmed will make for mowing 10 times

when x = 10

y = 40 + 25x

y = 40 + 25(10)

= 40 + 250

= 290

y = 290

(x, y) = (10, 290)

Answer:

the answer is plane try I'm pretty sure it's that.

Answer:

3h³k² + 18h³k + 27h³

Step-by-step explanation:

Given

3h³(k + 3)² ← expand factor using FOIL

= 3h³(k² + 6k + 9) ← distribute parenthesis

= 3h³k² + 18h³k + 27h³