Answer:
5N up
Explanation:
10N up + 15N up = 25N up
25N up - 20N down = 5N up
Which of the following nuclear configurations is most stable?
Answer:
D. A nucleus of 2 protons and 2 neutrons.
Explanation:
A stable nucleus is one that do not disintegrate naturally, majorly due to the even number of its protons and neutrons. Thus they are not radioactive in nature.
From the given question, it would be observed that a nucleus of 2 protons and 2 neutrons would give a helium atom. And this is a stable atoms due to the magnetic number of the components of its nucleus.
Thus, the nuclear configuration that is most stable out of the given options is a nucleus of 2 protons and 2 neutrons. Option D.
The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis. Which best lists the titles of each column? Column 1 0 2 4. 6 8 10 Column 2 5 10 15 20 25 30 Column 1 should be titled "Time," and Column 2 should be titled "Velocity." Column 1 should be titled "Velocity," and Column 2 should be titled "Time." Column 1 should be titled "Time," and Column 2 should be titled "Acceleration." O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."
Answer:
Explanation:
Since we are looking at speed over a time unit, we have an acceleration graph. The definition of acceleration mathematically is:
[tex]a=\frac{v_f-v_0}{t}[/tex] (that's the change in velocity over the change in time). The slope of any line in this graph wil represent the acceleration. Slope is rise over run, or y over x. Therefore, if acceleration is velocity over time, then the y axis is the velocity axis and the x axis is the time axis. It makes perfect, beautiful sense!!
A 35-gram stainless steel ball on a track is moving at a velocity of 9 m/s. On the same track, a 75-gram stainless steel ball is moving at a velocity of –7 m/s. After colliding, the 35-gram ball moves at a velocity of –15 m/s. Assume there is no net force on the system.
What is the velocity of the 75-gram ball after the collision? Round to the nearest tenth.
Explanation:
the answer is in the above image
Given:
mass of first ball, m1 = 35g
mass of second ball, m2 = 75g
velocity of first ball before collision, u1 = 9m/s
velocity of second ball before collision, u2 = -7m/s
velocity of first ball after collision, v1 = -15m/s
velocity of second ball after collision, v2 = ? (To Find)
Now it is given that there is no net force on the system of two balls
according to the Law of Conservation of Momentum so, here momentum is constant before and after collision:
P1 = P2
m1u1 + m2u2 = m1v1 + m2v2
35g*9m/s + 75g*(-7m/s) = 35g*(-15m/s) + 75g*v2
v2 = (35g*9m/s + 75g*(-7m/s) - 35g*(-15m/s))/75g
v2 = 4.2m/s
therefore, the velocity of second ball after collision is 4.2m/s
What is the formula of conservation of momentum?
As a result, the equation of the law of conservation of momentum is as follows: m1 u1 + m2 u2 represents the total momentum of particles A and B before the collision, and m1 v1 + m2 v2 represents the total momentum of particles A and B after the collision.
What is momentum unit?Momentum. If the mass of an object is m and it has a velocity v, then the momentum of the object is defined to be its mass multiplied by its velocity. momentum = mv. Momentum has both magnitude and direction and thus is a vector quantity. The units of momentum are kg m s−1 or newton seconds, N s.
Learn more about Law of Conservation of Momentum here
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Calculate the change in the gravitational potential energy store of the following objects.
A cat with a mass of 3 kg climbs a tree, reaching a final height of 4.5 m (g = 9.8 N/kg).
Silver
Change in gravitational potential energy store =
Explanation:
Gravitational potential energy is energy an object possesses because of its position in a gravitational field. ... Since the force required to lift it is equal to its weight, it follows that the gravitational potential energy is equal to its weight times the height to which it is lifted. PE = kg x 9.8 m/s2 x m = joules.
So, the PE is
3 x 9.8 x 4.5 = 132.3 J
100 point!! Question song!
You gotta keep 'em separated
Like the latest fashion
Like a spreading disease
The kids are strappin' on their way to the classroom
Getting weapons with the greatest of ease
The gangs stake their own campus locale
And if they catch you slippin' then it's all over pal
If one guys colors and the others don't mix
They're gonna bash it up
Hey - man you talkin' back to me?
Take him out
You gotta keep 'em separated
Hey - man you disrespecting me?
Take him out
You gotta keep 'em separated
Hey they don't pay no mind
If you're under 18 you won't be doing any time
Hey, come out and play
By the time you hear the siren
It's already too late
One goes to the morgue and the other to jail
One guy's wasted and the other's a waste
It goes down the same as the thousand before
No one's getting smarter
No one's learning the score
Your never ending spree of death and violence and hate
Is gonna tie your own rope
Hey - man you disrespecting to me?
Take him out
You gotta keep 'em separated
Hey - man you talking back to me?
Take him out
You gotta keep 'em separated
Hey they don't pay no mind
If you're under 18 you won't be doing any time
Hey, come out and play
It goes down the same as the thousand before
No one's getting smarter
No one's learning the score
Your never ending spree of death and violence and hate
Is gonna tie your own rope
Hey - man you talkin' back to me?
Take him out
You gotta keep 'em separated
Hey - man you disrespecting me?
Take him out
You gotta keep 'em separated
Hey they don't pay no mind
If you're under 18 you won't be doing any time
Hey, come out and play
Answer:
It is a song called Come out and Play. It is released on 1994 in a Album called Smash. It comes under Punk-Rock.
I hope i answered your Question.
Answer:
Explanation:
Adding to the other answer, this song is about violence in streets and schools among young people involved in gangs; how they have little hope for their future. Band member Dexter got idea to make the song while he was in college.
A hypothesis is a(n) ______________, while a theory is a(n) ______________.
Which statement explains why a red rose does not appear to be orange?
O A. Orange light is absorbed by the rose.
B. Red light is transmitted through the rose.
C. Orange light is transmitted through the rose.
O D. Red light is absorbed by the rose.
Answer:
A
Explanation:
you see red because it's reflected and other colors are absorbed, light transmitted through something is when it travels through something like glass or a gem
in the compound CaCO3 at the end of the compound represents the number of
Answer:
Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3).
Solution —
Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g
No. of moles of CaCO3
= No. of molecules/Avogadro constant
= 6.022 × 1023/ 6.022 × 1023
= 1 mole
Mass of CaCO3
= No. of moles × molar mass
= 1 × 100 g = 100 g.
calculate the charge flow when the vurrent is 0.50A in the wites for 17s
Answer:
Quantity of charge = 8.5 Coulombs
Explanation:
Given the following data;
Current = 0.5 A
Time = 17 seconds
To find the charge flowing through the wire;
Mathematically, the quantity of charge passing through a conductor is given by the formula;
Quantity of charge = current * time
Substituting into the formula, we have;
Quantity of charge = 0.5 * 17
Quantity of charge = 8.5 Coulombs
calcula el peso de un perro cuya masa es de 25 kg en la tierra
Answer:
El peso = 245 Newton
Explanation:
Dados los siguientes datos;
Masa = 25 kg
Para encontrar el peso del perro en la tierra;
El peso se puede definir como la fuerza que actúa sobre un cuerpo o un objeto como resultado de la gravedad.
Matemáticamente, el peso de un objeto viene dado por la fórmula;
[tex] El \; peso = mg [/tex]
Dónde;
m es la masa del objeto.
g es la aceleración debida a la gravedad.
Sabemos que la aceleración debida a la gravedad es igual a 9,8 m / s² en el planeta Tierra.
Sustituyendo en la ecuación, tenemos;
[tex] W = 25 * 9.8[/tex]
El peso = 245 Newton
A sound wave has a frequency of 192 Hz and travels the length of a football field at a speed of 338.5 m/s. what is the wavelength of the wave?
Explanation:
everything can be found in the picture
An overworked computer software engineer works on the computer the whole day. He gets very tired after work. Somebody advised him to eat more carbohydrates and fats to get more energy. Do you think this will help him? Why?
Answer:
Following are the solution to the given question:
Explanation:
The answer is "Yes," as it will provide more fuel than a source of vitamins and minerals for him as carbohydrates. Whereas after carbohydrates supply energy, lipids were applied to long-term electricity. Obesity is caused by over intakes of carbohydrates and fats. They must therefore be given in the amount recommended. For its activity, the brain uses glucose. Nevertheless, he does not require sufficient fat since fat is difficult to absorb & fat may make him sound more tired. To recover rapidly, one should consume carbohydrates and meals rich in vitamins. Selection for fat in the form of nuts should be mainly.
A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?
Please provide the formula and the working
Answer:
Explanation:
The equation for acceleration is
[tex]a=\frac{v_f-v_0}{t}[/tex] where vf is the final velocity and v0 is the initial velocity. For us, the final velocity is 25 m/s and the initial is 0 because the train started from resting position. Filling in and solving for a:
[tex]a=\frac{25-0}{30.0}[/tex] so
a = .83 m/s/s
What is surface tension
Answer:
Surface tension is a fundamental property of the surface of liquid. Surface tension is responsible for the curvature of the surfaces of air and liquids. Surface tension is responsible for the ability of some solid objects to “float” on the surface of a liquid.
hope it helps
stay safe healthy and happy.Surface tension is the tendency of liquid surfaces at rest to shrink into the minimum surface area possible.Surface tension is what allows any object that is denser than water to float on water
hope this will help out
A person notices water waves on the surface of the pond. 18 waves pass by a person in 12 seconds. Calculate the frequency of these water waves. Give the unit.
Answer:
f = 1.5 Hz
Explanation:
Given that,
18 waves pass by a person in 12 seconds.
We need to find the frequency of these water waves.
We know that,
Frequency = no. of waves per second
So,
[tex]f=\dfrac{18}{12}\\\\f=1.5\ Hz[/tex]
So, the frequency of these water waves is equal to 1.5 Hz.
¡¡¡AYUDA CON ESTOS EJERCICIOS DE FÍSICA!!!
1. ¿Cuál es el valor del potencial eléctrico en un punto si para trasladar una carga de 5 μC desde el suelo hasta el, se realizó un trabajo de 40 X 10^(-6) J?
2. ¿Calcular el potencial eléctrico en un punto B que se encuentra a 50 cm de una carga positiva q = 8 X 10^(-6) C
3. Determina el valor de una carga transportada desde un punto a otro, al realizarse un trabajo de 8 x 10^(-5) J, si la diferencia de potencial es de 4 x 10^3 V.
Answer:
(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C
Explanation:
(a) charge, q = 5 μC , Work, W = 40 x 10-^(-6) J
The electric potential is given by
W = q V
[tex]40\times10^{-6}=5 \times10^{-6}\times V\\\\V = 8 V[/tex]
(b)
charge, q = 8 x 10^(-6) C, distance, r = 50 cm = 0.5 m
Let the potential is V.
[tex]V =\frac{k q}{r}\\\\V =\frac{9\times 10^{9}\times 8\times 10^{-6}}{0.5}\\\\V =144000 V[/tex]
(c)
Work, W = 8 x 10^(-5) J, Potential difference, V = 4000 V
Let the charge is q.
W= q V
[tex]8\times10^{-5}= q\times 4000\\\\q =2\times 10^{-8} C[/tex]
Consider the case in which the clay is launched along Path Y. The sphere of clay is launched with an initial velocity of v0 and collides with the rod at a distance of l from the pivot. The length of the rod is L. The rotational inertia of the rod about the joint is IR, and the mass of the clay is mc. The clay is considered a point mass. What is the angular speed f of the clay-rod system immediately after the collision
Answer:
w = [tex]\frac{m}{ml^2 + I R^2 }[/tex] v l
Explanation:
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
L₀ = m v l
Final moment. After the collision with the clay stuck to the rod
L_f = I_{total} w
angular momentum is conserved
L₀ = L_f
m v l = I_total w
w = [tex]\frac{m}{I_{total} }[/tex] v l
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
I_rod = I R²
I_total = m l² + IR²
we substitute
w = [tex]\frac{m}{ml^2 + I R^2 }[/tex] v l
The angular speed f of the clay-rod system immediately after the collision
[tex]w=\dfrac{m}{ml^2+IR^2}VI[/tex]
What is angular speed?Angular speed is defined as the rate of change of angular displacement,Angular Speed (ω) is the scalar measure of rotation rate. In one complete rotation, angular distance travelled is 2π and time is time period (T)
Let's form a system formed by the clay sphere and the rod, in this case the angular momentum is conserved
initial instant. Before the crash
[tex]L_o=mvl[/tex]
Final moment. After the collision with the clay stuck to the rod
[tex]L_o = L_f m v l = I_{total} w[/tex]
[tex]w=\dfrac{m}{I_{total}} Vl[/tex]
the total moment of inertia is the sum of the moments of inertia of the two bodies
the moment of inertia of the rod is
[tex]I_rod = I R^2 I_{total} = m l^2 + IR^2[/tex]
we substitute
[tex]w=\dfrac{m}{ml^2+IR^2}VI[/tex]
Hence the angular speed f of the clay-rod system immediately after the collision
[tex]w=\dfrac{m}{ml^2+IR^2}VI[/tex]
To know more about Angular speed follow
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It is said that people often behave in unusual ways during a full moon. a)
Calculate the gravitational force that the moon would exert on a 50.0 kg
student in your physics class. The Moon is 3.84 x 108 m away from Earth
and has a mass of 7.35 x 1022 kg.
Answer: baby moon gravity
Sorry I dont know how to do it :/
Explanation:
moon + gravity = baby moon gravity
A pool ball moving 1.33 m/s strikes an identical ball at rest. Afterward, the first ball moves 0.750 m/s at a 33.30 angle. What is the velocity of the other ball?
Explanation:
We need to apply the conservation law of linear momentum to two dimensions:
Let [tex]p_{1}[/tex] = momentum of the 1st ball
[tex]p_{2}[/tex] = momentum of the 2nd ball
In the x-axis, the conservation law can be written as
[tex](p_{1} \cos \theta_{1})_{i} + (p_{2} \cos \theta_{2})_{i} = (p_{1} \cos \theta_{1})_{f} + (p_{2} \cos \theta_{2})_{f} [/tex]
or
[tex](m_{1}v_{1})_{i}= (m_{1}v_{1}\cos \theta_{1})_{f} + (m_{2}v_{2}\cos \theta_{2})_{f} [/tex]
Since we are dealing with identical balls, all the m terms cancel out so we are left with
[tex](v_{1})_{i} = (v_{1})_{f}\cos \theta_{1} + (v_{2})_{f}\cos \theta_{2}[/tex]
Putting in the numbers, we get
[tex]1.33 = (0.750) \cos(33.30) + (v_{2})_{f} \cos \theta_{2}[/tex]
[tex] = > (v_{2})_{f} \cos \theta_{2} = 0.703[/tex]
In the y-axis, there is no initial y-component of the momentum before the collision so we can write
[tex]0 = (v_{1}\sin \theta_{1})_{f} + (v_{2}\sin \theta_{2})_{f} [/tex]
or
[tex] = > (v_{2})_{f} \sin \theta_{2} = (0.750) \sin(33.30) = 0.412[/tex]
Taking the ratio of the sine equation to the cosine equation, we get
[tex] \frac{ \sin \theta _{2}}{ \cos \theta_{2} } = \tan \theta_{2} = \frac{0.412}{0.703} = 0.586[/tex]
or
[tex] \theta_{2} = { \tan}^{ - 1} (0.586) = 30.4[/tex]
Solving now for [tex](v_{2})_{f}[/tex],
[tex](v_{2})_{f} = \frac{0.412}{ \sin(30.4) } = 0.815 \: \frac{m}{s} [/tex]
Which one of the following is NOT an example of
force?
A Magnetism
B. Mass
C Weight
D. Effort
What is the momentum, in kg m/s, of a tyre of mass 6 kg rolling along at a velocity of 3m/s?
Answer:
p = 18 kg-m/s
Explanation:
Given that,
The mass of tyre, m = 6 kg
The velocity of the tyre, v = 3 m/s
We need to find the momentum of the tyre. We know that, the momentum of an object is equal to the product of mass and velocity. SO,
p = mv
[tex]p=6\ kg\times 3\ m/s\\\\=18\ kg-m/s[/tex]
So, the momentum of the tyre is equal to 18 kg-m/s.
Cuanto cambia la entropía de 0.50 kg de vapor de mercurio [Lv: 2.7 x 10⁵ j/kg ] al calentarse en su punto de ebullición de 357° C?
Answer:
La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.
Explanation:
Por definición de entropía ([tex]S[/tex]), medida en joules por Kelvin, tenemos la siguiente expresión:
[tex]dS = \frac{\delta Q}{T}[/tex] (1)
Donde:
[tex]Q[/tex] - Ganancia de calor, en joules.
[tex]T[/tex] - Temperatura del sistema, en Kelvin.
Ampliamos (1) por la definición de calor latente:
[tex]dS = \frac{L_{v}}{T}\cdot dm[/tex] (1b)
Donde:
[tex]m[/tex] - Masa del sistema, en kilogramos.
[tex]L_{v}[/tex] - Calor latente de vaporización, en joules
Puesto que no existe cambio en la temperatura durante el proceso de vaporización, transformamos la expresión diferencial en expresión de diferencia, es decir:
[tex]\Delta S = \frac{\Delta m \cdot L_{v}}{T}[/tex]
Como vemos, el cambio de la entropía asociada al cambio de fase del mercurio es directamente proporcional a la masa del sistema. Si tenemos que [tex]m = 0.50\,kg[/tex],[tex]L_{v} = 2.7\times 10^{5}\,\frac{J}{kg}[/tex] and [tex]T = 630.15\,K[/tex], entonces el cambio de entropía es:
[tex]\Delta S = \frac{(0.50\,kg)\cdot \left(2.7\times 10^{5}\,\frac{J}{kg} \right)}{630.15\,K}[/tex]
[tex]\Delta S = 214.235 \,\frac{J}{K}[/tex]
La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.
Air pollution is an example of a. The underground economy. B. An external shock. C. A nonmarket activity. D. A negative externality.
Answer:
D. A negative externality.
Explanation:
Particulate pollution is a form of pollution that is responsible for the degradation of the environment.
Particulate matter is also referred to as particle pollution or atmospheric aerosol particles and it can be defined as a complex microscopic mixture of liquid droplets and solid particles that are suspended in air.
An externality is typically an unwarranted cost or benefit by a manufacturer or producer of goods and services that affects a third party.
In Economics, an externality could either be positive or negative depending on its effect on a third party.
A negative externality arises when the production or consumption of a finished product or service has negative impact (cost) on a third party.
In conclusion, air pollution is an example of a negative externality because it causes harm to a third party.
The X and Y components of a vector are described in the image below. Which of the following will be accurate when solving for the magnitude and direction of the vector.
I NEED AN ANSWER RIGHT NOW PLEASE
volume of CO2 at STP of 27.0 g
Answer:
Volume of CO2 at STP = 13.8 liter (Approx.)
Explanation:
Given:
Mass of CO2 = 27 gram
Find:
Volume of CO2 at STP
Computation;
We know that;
At STP, Volume of 1 mol of gas = 22.4 liter
Molar mass of CO2 = 44 g/mole
So,
Volume of CO2 at STP = [Mass of CO2 / Molar mass of CO2 ][22.4]
Volume of CO2 at STP = [27/44][22.4]
Volume of CO2 at STP = [0.6136][22.4]
Volume of CO2 at STP = 13.8 liter (Approx.)
E
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A wave has a frequency of 30 Hz and a wavelength of 10 m. What's its speed?
Answer:
Speed = 300 m/s
Explanation:
Given the following data;
Frequency = 30 Hz
Wavelength = 10 m
To find the speed of the wave;
Mathematically, the speed of a wave is given by the formula:
[tex] Speed = wavelength * frequency [/tex]
Substituting into the formula, we have;
[tex] Speed = 10 * 30 [/tex]
Speed = 300 m/s
Which of the following would require a centripetal force?
A) All of these require a centripetal acceleration
B) An airplane slowing down
C) A train speeding up
D) A car turning right
Which is not true of friction? A. Causes wear and tear of the surfaces B. Helps us to fall easily on roads C. Produces heat D. Produces light E. Stops bodies when they move over each other.
Answer:
B.
Hope this helps
un movil que parte del reposo alcanza una velocidad de 75 m/s en 13 segundos ¿cual su aceleracion y el espacio que recorrio en los 13 segundos
Answer:
Acceleration = 5.77 m/s²
Distance cover in 13 seconds = 487.56 meter
Explanation:
Given:
Final velocity of mobile device = 75 m/s
initial velocity of mobile device = 0 m/s
Time taken = 13 seconds
Find:
Acceleration
Distance cover in 13 seconds
Computation:
v = u + at
75 = 0 + (a)(13)
13a = 75
a = 5.77
Acceleration = 5.77 m/s²
s = ut + (1/2)(a)(t²)
s = (0)(t) + (1/2)(5.77)(13²)
Distance cover in 13 seconds = 487.56 meter
Find new resistance of wire if it is stretched to twice its
original length. Original resistance was 20 ohm. Also how its
resistivity will change
Answer:
Original Length = L1
Stretched length =L2
From
R = pl/A
R=Resistance
p=Resistivity
A=Cross-sectional Area
l= length of wire
We can see that Resistance is directly Proportional to Length... Meaning that Resistance Increases also as Length increases.
R1/L1 = R2/L2
From the question... The key to note is this sentence
"The Stretched length is TWICE the Original Length"
Meaning
L2 = 2L1 (So replace L2 as 2L1 when solving)
R1=20ohms
Let R2 = k
Applying the formula
20/L1 = k/2L1
kL1 = 20x 2 L1
KL1 = 40L1
L1 cancels on both sides
k=40ohms.
So As the length doubled... The Resistance did too
from 20ohms to 40ohms