What is the equation of the line that is horizontal and goes through the y-axis
at -4?

Answer:

wait you can message me if you want

btw can u make me the brainless huhu

Answer:

D. 14

make y the subject of the formula in equation 1 and then substitute it in equation 2

Answer:

-3/2

Step-by-step explanation:

Visualize it or write it out.

Answer:

[tex]NK \approx 7.001[/tex], [tex]MK = 2[/tex], [tex]MF \approx 7.001[/tex], [tex]A_{AMNFD} = 49.007[/tex]

Step-by-step explanation:

According to the statement, we find the following inputs:

[tex]\angle MDK = \angle DMF = 45^{\circ}[/tex] (Due to the condition of isosceles trapezoid)

[tex]MD = 9[/tex]

[tex]NF = 5[/tex]

Given than longer base and shorter base are parallel to each other, we conclude that:

[tex]\angle KND = 180^{\circ} -\angle NKD - \angle KDN[/tex]

[tex]\angle KND = 180^{\circ}-90^{\circ}-45^{\circ}[/tex]

[tex]\angle KND = 45^{\circ}[/tex]

[tex]\angle FND = 90^{\circ}-\angle KND[/tex]

[tex]\angle FND = 45^{\circ}[/tex] (By definition of complementary angles)

[tex]\angle FND = \angle NFM = 45^{\circ}[/tex] (Due to the condition of isosceles trapezoid)

[tex]\angle MDK = \angle DMF = \angle FND = \angle NFM = 45^{\circ}[/tex]

[tex]\angle NOF = \angle MOD = \angle MOF = \angle FOD = 90^{\circ}[/tex] (By definitions of complementary and vertical angles and the theorem that states that sum of internal angles within a triangle equals 180º)

[tex]MO = DO = \frac{\sqrt{2}}{2}\cdot MD[/tex] (By theorem for 45-45-90 Right Triangle)

[tex]NO = OF = \frac{\sqrt{2}}{2}\cdot NF[/tex] (By theorem for 45-45-90 Right Triangle)

If we know that [tex]MD = 9[/tex] and [tex]NF = 5[/tex], then we find that:

[tex]DO = MO \approx 6.364[/tex]

[tex]NO = OF \approx 3.536[/tex]

The value of MK is obtained from the following relationship:

[tex]MK = \frac{MD-NF}{2}[/tex]

[tex]MK = \frac{9-5}{2}[/tex]

[tex]MK = 2[/tex]

And the value of KD is calculated from this expression:

[tex]KD = MD-MK[/tex]

[tex]KD = 9-2[/tex]

[tex]KD = 7[/tex]

Now by the Pythagorean Theorem we find that:

[tex]NK = \sqrt{(NO+DO)^{2}-KD^{2}}[/tex]

[tex]NK = \sqrt{9.9^{2}-7^{2}}[/tex]

[tex]NK \approx 7.001[/tex]

And considering the symmetry characteristics of an isosceles trapezoid, we determine MF:

[tex]MF = NO + DO \approx 7.001[/tex]

Lastly, the area of the isosceles trapezoid is determined by the following formula:

[tex]A_{AMNFD} = NF\cdot NK + MK\cdot NK[/tex]

[tex]A_{AMNFD} = NK\cdot (NF+MK)[/tex]

If we know that [tex]NK \approx 7.001[/tex], [tex]NF = 5[/tex] and [tex]MK = 2[/tex], then the area of the figure is:

[tex]A_{AMNFD} = (7.001)\cdot (5+2)[/tex]

[tex]A_{AMNFD} = 49.007[/tex]

Answer:

√13

Step-by-step explanation:

length √(2^2+3^2)=√13.

Answer:

10:7

Step-by-step explanation:

Option c is the correct answer. A gym charges a membership fee of $50, plus a monthly charge of $20 per month.

Relationships between two variables that are proportional occur when their ratios are equal. Another way to consider them is that in a proportionate relationship, one variable is consistently equal to the other's constant value. That constant is known as the "constant of proportionality".

So a non-proportional relationship is basically a line that does not cross the origin of a graph. So using the linear exhaustion of a line, y=mx+b, a proportional relationship would be something along the lines of y=mx+0 because b, which is the w intercept is 0. I

Having said that, here is the equation for a line:

a) would be y=1.75x (because it is only charging per drink, and nothing else, there is no b value or y-intercept). This means this is a

b) would be y=0.10x (because it is only charging per amount of texts, and nothing else, there is again no b value, so the y-intercept is 0, crossing the origin). (THIS IS ALSO NOT THE ANSWER)

c) y=20x+50 (x is the number of months, which then determine the amount of money you spend at the gym based on how many months you go there. Plus, you have to add in the cost of the gym membership as well, being 50$. So, in this case, because 50 is being added to the 20x, the b value or y-intercept would be 50.

To know more about proportional relationships follow

https://brainly.com/question/28777033

#SPJ2

Answer:

The angle of CAD is 100°.

Step-by-step explanation:

Given that total angles in a triangle is 180° so you will have to find the angle of CAB :

∠CAB + ∠ACB + ∠ABC = 180°

∠CAB + 80° + 20° = 180°

∠CAB + 100° = 180°

∠CAB = 180° - 100°

∠CAB = 80°

Next, you have to subtract it from 180° because straight line have a degree of 180°

∠CAD = 180° - 80°

∠CAD = 100°

Answer:

I hope this is good enough:

Step-by-step explanation:

I dis graph it just use demo's graphing system.

Answer:

If I know I will defiantly answer .but where is the question

Answer: 17 years

Step-by-step explanation:

Exponential equation for compund amount( compunded continuously):

[tex]A=Pe^{rt}[/tex] , where P= Principal value , r= rate of interest , t= time.

Given: A= 2P

r =4%= 0.04

To find : t

Substitute all values in the formula , we get

[tex]2P=Pe^{0.04t}\\\\\Rightarrow\ 2=e^{0.04t}[/tex]

Taking natural log on both sides

[tex]\ln2=\ln e^{0.04t }\\\\\Rightarrow\ 0.693147=0.04t\\\\\Rightarrow\ t=\dfrac{ 0.693147}{0.04}\\\\\Rightarrow\ t=17.3286\approx17[/tex]

hence, it will take 17 years (approx).

Step-by-step explanation:

An object moving along the x-axis is said to exhibit simple harmonic motion if its position as a function of time varies as

x(t) = x0 + A cos(ωt + φ).

The object oscillates about the equilibrium position x0.  If we choose the origin of our coordinate system such that x0 = 0, then the displacement x from the equilibrium position as a function of time is given by

x(t) = A cos(ωt + φ).

A is the amplitude of the oscillation, i.e. the maximum displacement of the object from equilibrium, either in the positive or negative x-direction.  Simple harmonic motion is repetitive.  The period T is the time it takes the object to complete one oscillation and return to the starting position.  The angular frequency ω is given by ω = 2π/T.  The angular frequency is measured in radians per second.  The inverse of the period is the frequency f = 1/T.  The frequency f = 1/T = ω/2π of the motion gives the number of complete oscillations per unit time.  It is measured in units of Hertz, (1 Hz = 1/s).

The velocity of the object as a function of time is given by

v(t) = dx(t)/dt = -ω A sin(ωt + φ),

and the acceleration is given by

a(t) = dv(t)/dt = -ω2A cos(ωt + φ) = -ω2x.

Answer:

-14/15

Step-by-step explanation:

Answer:First three terms: 11,20,29 .

Step-by-step explanation:

Write a systems of equations. tn=a+(n−1)d. sn=n2 (2a+(n−1)d). So,. 110=11+(n−1)d 726=n2(22+(n−1)d).

I hope this is right

Answer:

The second vendor because when you purchase 6 liters, it costs less to get it from the second vednor.

Step-by-step explanation:

Compare the price at 6 liters.

3.80(3)= $11.40

$2.70(4)= $10.80

Answer:

4y + x = 8

Step-by-step explanation:

firstly, we choose any 2 points on the line

point 1 = (0,2)

point 2 = (4,1)

x1 = 0, x2 = 4

y1 = 2, y2 = 1

from,

[tex] \dfrac{y2 - y1}{x2 - x1} = \dfrac{y- y1}{x- x1} [/tex]

[tex] \dfrac{1 - 2}{4 - 0} = \dfrac{y- 2}{x- 0} [/tex]

[tex] \dfrac{ - 1}{4} = \dfrac{y- 2}{x- 0} [/tex]

Cross multiplying,

-1(x) = 4(y - 2)

-x = 4y - 8

4y + x = 8

Answer:

10.6

Step-by-step explanation:

range is the difference between the lowest and the highest number

example: the lowest number wold be 1.1 and the highest is 11.7 you need to subtract them and then you have your answer!!!

The range of the given set of data is 10.8.

The given data is 2.3, 4.5, 6.7, 1.1, 11.6, 4.5, 11.7, 8.5, 3.2, 6.7, 7.9.

We need to find the range of the given data.

The range is the difference between the highest and lowest values within a set of numbers. To calculate the range, subtract the smallest number from the largest number in the set.

From the given set of data, we can see that the lowest observation is 1.1 and the highest observation is 11.7.

Now, range=11.7-1.1=10.8

Therefore, the range of the given set of data is 10.8.

To learn more about the range of the data visit:

https://brainly.com/question/20607770.

Answer:

b = 5

Step-by-step explanation:

[tex]4b - 2b = 13 - 3 \\ 2b = 10 \\ b = 5[/tex]

Answer:

Your answer is:  [tex]2j^{2}(j-4)[/tex]

Factor [tex]2j^{2}[/tex]out of [tex]2j^{3} -8j^{2}[/tex]

Step-by-step explanation:

Hope this helped : )

Answer:

z³ - 2z² - 3z

Step-by-step explanation:

(z² - 3z)(z+1) = (z²*z) + (z²*1) + (-3z*z) + (-3z*1) = z³ + z² - 3z² - 3z

= z³ -2z² - 3z

Answer:

Today : Saturday, 07 November 2020

Hour: 20.04 WIB (Indonesia)

_______________________________

(z² - 3z) (z + 1)

= z³ + z² - 3z² - 3z

= z³ - 2z² - 3z

Answer:

Learn vocabulary, terms, and more with flashcards, games, and other study tools. ... The Fee that a driver pays to have automobile insurance is called a ... She receives 7% on her first $1,000 in sales and 15% on the balance of her sales. ... The Jackson's sublet their summer cottage during the winter and spring months.

Step-by-step explanation:

Answer:

11.39

Step-by-step explanation:

Have a great day! :)

Answer:

( 6, -3 )

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

4x - 2 and 3x + 6 are alternate angles and congruent, thus

4x - 2 = 3x + 6 ( subtract 3x from both sides )

x - 2 = 6 ( add 2 to both sides )

x = 8

Answer:

A

move the numbers around and you'll get it

Answer:

- 6

Step-by-step explanation:

;)

Answer:

The temperature, in December is 47 °F

Step-by-step explanation:

The given data for the temperature are;

Month             [tex]{}[/tex]         Temp (°F)

April                   [tex]{}[/tex]          59

May               [tex]{}[/tex]               68

June             [tex]{}[/tex]                71

July                  [tex]{}[/tex]             78

August              [tex]{}[/tex]            74

Let x represent the month, and f(x) = y represent the temperature, we have;

y = a·x² + b·x + c

When x = 1, we have, f(1) = a·1² + b·1 + c = 59

f(1) = a + b + c = 59...(1)

When x = 2, we have, f(2) = a·2² + b·2 + c = 68

f(2) = 4·a + 2·b + c = 68...(2)

When x = 3, we have, f(3) = a·3² + b·3 + c = 71

f(3) = 9·a + 3·b + c = 71...(3)

When x = 4, we have, f(4) = a·4² + b·4 + c = 78

f(3) = 16·a + 4·b + c = 78...(4)

When x = 5, we have, f(5) = a·5² + b·5 + c = 74

f(3) = 25·a + 5·b + c = 74...(5)

Subtracting equation (3) from equation (5), we get;

25·a + 5·b + c - (9·a + 3·b + c) = 74 - 71

16·a + 2·b = 3...(6)

Subtracting equation (1) from equation (2), we get;

4·a + 2·b + c - (a + b + c) = 68 - 59

3·a + b = 9...(7)

Multiply equation (7) by 2 and substract from equation (6) gives;

16·a + 2·b - 2 × (3·a + b) = 3 - 2 × 9

16·a + 2·b - 6·a - 2·b = 3 - 2 × 9

16·a - 6·a + 2·b  - 2·b = 3 - 2 × 9 = -15

10·a = -15

a = -15/10 = -1.5

a = -1.5

From, 3·a + b = 9, we have;

3 × (-1.5) + b = 9

b = 9 + 4.5 =13.5

b = 13.5

From, a + b + c = 59, we have;

-1.5 + 13.5 + c = 59

c = 59 - (-1.5 + 13.5) = 47

c = 47

The quadratic equation becomes, y = a·x² + b·x + c = -1.5·x² + 13.5·x + 47

f(x) = y = -1.5·x² + 13.5·x + 47

For December, we have, x = 9, and f(x) = -1.5×9² + 13.5×9 + 47 = 47

The temperature, in December = 47 °F