What is the 8th term of the sequence? −16, 24, −36, 54, ... −729/8 2187/8 −2187/8 729/8

Answer:

[tex]x=-\frac{16}{23}[/tex]

I hope this helps!

Answer:

Step-by-step explanation:

3x² + 7x - 6 = 3x² + 9x - 2x - 2*3

                  = 3x (x + 3) - 2(x +3)

                  = (3x - 2)(x + 3)

Area of the rectangle = 3x² + 7x - 6

length * width = 3x² + 7x - 6

length * (x + 3) = (3x -2)(x +3)

          length = [tex]\frac{(3x-2)(x+3)}{(x+3)}[/tex]

          length = (3x - 2)

Answer:

m∠D = 97.34°

Step-by-step explanation:

Concept used"

sum of all angles of Quadrilateral is 360 degrees.

If any Quadrilateral is inscribed in circles then sum of opposite angle of that Quadrilateral is 180 degrees

________________________________________________

Given

Quadrilateral ABCD is inscribed in a circle

thus,

pair of opposite angles will be

m∠A and m∠C

m∠B and m∠D

thus,

m∠B + m∠D = 180

Thus,

m∠A + m∠C = 180

64+  (9x - 1) = 180

9x = 180 - 63 + 1 = 118

x = 118/9 = 13.11

thus, value of

m∠B is (6x + 4)°

m∠B = (6*13.11 + 4)°  = 82.66°

m∠B + m∠D = 180

82.66 + m∠D = 180

m∠D = 180 - 82.66 = 97.34°

Thus,

m∠D is 97.34°

Answer:

[tex](x + 6)^2 = 49[/tex]

[tex]x = 1[/tex]    or [tex]x = -13[/tex]

Step-by-step explanation:

Given

[tex]12x = 13 - x^2[/tex]

Using Completing the Square

[tex]12x = 13 - x^2[/tex] ---- Add [tex]x^2[/tex] to both sides

[tex]x^2 + 12x = 13 - x^2 + x^2[/tex]

[tex]x^2 + 12x = 13[/tex]

Divide the coefficient of x by 2; then add the square to both sides

[tex]x^2 + 12x + 6^2 = 13 + 6^2[/tex]

[tex]x^2 + 12x + 36 = 13 + 36[/tex]

[tex]x^2 + 12x + 36 = 49[/tex]

Factorize

[tex]x^2 + 6x + 6x + 36 = 49[/tex]

[tex]x(x + 6) + 6(x + 6) = 49[/tex]

[tex](x + 6)(x + 6) = 49[/tex]

[tex](x + 6)^2 = 49[/tex]

Hence, the equation is [tex](x + 6)^2 = 49[/tex]

Solving further

Take square root of both sides

[tex](x + 6) = \sqrt{49}[/tex]

[tex]x + 6 = \±7[/tex]

[tex]x = \±7- 6[/tex]

This implies that

[tex]x = 7 - 6[/tex]     or [tex]x = -7 -6[/tex]

[tex]x = 1[/tex]    or [tex]x = -13[/tex]

HEnce, the solutions are [tex]x = 1[/tex]    or [tex]x = -13[/tex]

Answer:

(x+6)^2=49 and  x=−6±7

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

The exterior angles are out of the triangle at all times and it adds up to make 180 with anyone of the inside angle of the triangle.

The pair also rests on the same flat/straight line and that makes a pair.

Therefore we can say that it is formed by a linear pair/group with one of the interior/inside angles of the triangle.

So, the correct answer would be D.

The true statement about an exterior angle of a triangle is C; It forms a linear pair with one of the interiior angles of the triangle .

An exterior angle of a triangle is equal to the sum of the opposite interior angles.

We know that the exterior angles are out of the triangle at all times and it adds up to make 180 with anyone of the inside angle of the triangle.

The pair also rests on the same straight line and that makes a pairs.

Therefore we can say that it is formed by a linear pair with one of the interior angles of the triangle.

So, the correct answer would be C.

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Answer:

b y=2.4x -1.8

Step-by-step explanation:

the equation y=2.4x -1.8 represents 2.4 from it

Answer:

2

Step-by-step explanation:

Basically,

You just have to find 30% of 15...

So

The formula is...

BASE x PERCENT= AMOUNT

x times 0.3= 15

0.3/15=0.02

0.02 x 100= 2

So

Joey got called back for approximately 2 auditions.

Answer:

  tan(α) = 1/tan(90°-α)

Step-by-step explanation:

The tangent of one is the reciprocal of the tangent of the other.

__

In a right triangle, ...

  tan = opposite/adjacent

For the two complementary acute angles in such a triangle, opposite and adjacent are swapped. That is the tangent of one is the inverse of the tangent of the other. (That inverse is also known as the cotangent.)

  tan(α) = cot(90°-α) = 1/tan(90°-α)

Answer:

9). h² - 7h + 11

10). 2a² + 14a + 16

11). 3

12). 2h + 4x - 3

Step-by-step explanation:

9). If j(x) = x² + x - 1

  j(h - 4) = (h - 4)² +(h - 4) - 1

             = h² - 8h + 16 + h - 4 - 1

             = h² - 7h + 11

10). If f(x) = 2x² + 2x - 8

     f(a + 3) = 2(a + 3)² + 2(a + 3) - 8

                 = 2(a² + 6a + 9) + 2a + 6 - 8

                 = 2a² + 12a + 18 + 2a - 2

                 = 2a² + 14a + 16

11). If f(x) = 3x - 1

   [tex]\frac{f(x+h)-f(x)}{h}=\frac{3(x+h)-1-(3x-1)}{h}[/tex]

                     [tex]=\frac{3x+3h-1-3x+1}{h}[/tex]

                     = 3

12). If, f(t) = 2t² - 3t + 7

     [tex]\frac{f(x+h)-f(x)}{h}=\frac{2(x+h)^{2}-3(x+h)+7-(2x^2-3x+7)}{h}[/tex]

                        [tex]=\frac{2(x^2+h^2+2hx)-3x-3h+7-2x^2+3x-7}{h}[/tex]

                        [tex]=\frac{2x^2+2h^2+4hx-3x-3h+7-2x^2+3x-7}{h}[/tex]

                        [tex]=\frac{2h^2+4hx-3h}{h}[/tex]

                        = 2h + 4x - 3

[tex](3x^2 - 4x + 1) + (-x^2 + x - 9)=\\3x^2-4x+1-x^2+x-9=\\2x^2-3x-8[/tex]

Answer:

You just answered my question so you can ask yours, what a sped. Now i'm doing the same thing.

Step-by-step explanation:

Answer:

A & C

Step-by-step explanation:

-9 is a whole number is rational

Answer:

72°

Step-by-step explanation:

From the figure given, angle D intercepts arc ABC. According to the Inscribed Angle Theorem:

m < D = ½(ABC) = ½(AB + BC)

Thus,

[tex] 56 = \frac{1}{2}(AB + 40) [/tex]

Solve for AB

[tex] 56 = \frac{AB + 40}{2} [/tex]

Multiply both sides by 2

[tex] 56*2 = \frac{AB + 40}{2}*2 [/tex]

[tex] 112 = AB + 40 [/tex]

Subtract both sides by 40

[tex] 112 - 40 = AB + 40 - 40 [/tex]

[tex] 72 = AB [/tex]

Arc AB = 72°

Answer:

The correct statements are b, c and e.

Step-by-step explanation:

Consider the dot plot for Noah and Jada's score in the trivia game.

From the dot plot it is quite clear that the data form a bell-shaped curved or a normal curve.

For the normal distribution:

Mean = Median = Mode

Noah's mean score = 5

Jada's mean score = 3

The standard deviation of a data set is the measure of dispersion of the observations of that data set from their mean.

On closely studying the graphs we can see that the Noah and Jada's scores are almost at a same distance from the mean, i.e. the spread of Noah's score is same as the spread of Jada's score.

So, the correct statements are:

b. The standard deviation of Noah's scores is equal to the standard deviation of Jada's scores.

c. The mean of Noah's scores is greater than the mean of Jada's scores.

e. Using only Noah's scores, the mean is equal to the median

Answer:

The value of k is 16, the angle of OLN and MNL is 72° .

Step-by-step explanation:

Given that alternate interior angles are the same. So we can assume that ∠OLN and ∠MNL have the same angle. In order to find k, we have to let ∠OLN = ∠MNL :

[tex]4k + 8 = 5k - 8[/tex]

[tex]5k - 4k = 8 + 8[/tex]

[tex]k = 16[/tex]

Next, we have to find the angle of OLN and MNL :

[tex]OLN = 4k + 8 = 4(16) + 8 = 72[/tex]

[tex]MNL = 5k - 8 = 5(16) - 8 = 72[/tex]

Answer:

30x+160

simple all you had to do is 10*3x and 8x2=16 and 10*16 and you will get 30x+160

Step-by-step explanation:

Answer:

30x + 80x^2

Step-by-step explanation:

10 (3x + 8x^2)

10 * 3x + 10 * 8x^2

30x + 80x^2

The equation that could best represent the line of best fit for the given data is; y = 0.625x

The formula for the equation of a line in slope intercept form is;

y = mx + c

where;

m is slope

c is y-intercept which is the point where the line intersects the y-axis

Now, in this question, we see that the line intersects the y-axis at 0. Thus;

y-intercept; c = 0

Now, let us find the slope from the formula;

m = (y₂ - y₁)/(x₂ - x₁)

Using the first and penultimate coordinate which are;

(0, 0) and (8, 5), we have;

m = (5 - 0)/(8 - 0)

m = 0.625

Thus, the equation is;

y = 0.625x

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Answer:

y=0.625x

Step-by-step explanation:

plato

Answer:

3, 10, 1080

Step-by-step explanation:

A coefficient, is the number that is multiplying a variable, such as x. A constant is any other number, not multiplying a variable.

For part one, the number multiplying the variable x is 3, so 3 is the coefficient.

For part two, the only number not multiplying a variable is the 10, so that is the constant.

To find how many miles she drove, we first need to subtract the first 30 dollars from the final payment.

300-30=270

We than need to divide 270 by .25, because that is how much it costed per mile.

270/.25=1080

Answer:

In the first question shown, the answer is 3

In the second question shown, the answer is 10

In the third question shown, the answer is 1080 miles

Step-by-step explanation:

First question - 3 is the number before x, making it the coefficient

Second question - 10 is the only number without a variable, making it a constant

Third question - .25 * 1080 = 270. 270 + 30 = 300.

Answer:

c=13.42

Step-by-step explanation:

[tex]A^2+B^2=C^2\\6^2+14^2=C^2\\C^2=144+36\\C^2=180\\\sqrt{c^2}=\sqrt{180} \\c=13.42[/tex]

Answer:

9.83 miles

Step-by-step explanation:

Distance covered on Monday = 4.25 miles

Distance covered on Tuesday = 2.66 miles

Distance covered on Wednesday

= 4.25 - 1.33 = 2.92 miles

Total distance covered in Three days = 9.83miles

Answer:

Step-by-step explanation:

[tex] \mathsf{3(2 \frac{1}{2} - 1) + \frac{3}{10} }[/tex]

Convert mixed number to improper fraction

[tex] \mathrm{3( \frac{5}{2} - 1) + \frac{3}{10} }[/tex]

Calculate the difference

⇒[tex] \mathrm{3( \frac{5 \times 1}{2 \times 1} - \frac{1 \times 2}{1 \times 2} }) + \frac{3}{10} [/tex]

⇒[tex] \mathrm{ 3 \times( \frac{5}{2} - \frac{2}{2}) } + \frac{3}{10} [/tex]

⇒[tex] \mathrm{3 \times ( \frac{5 - 2}{2} ) + \frac{3}{10} }[/tex]

⇒[tex] \mathrm{3 \times \frac{3}{2} + \frac{3}{10} }[/tex]

Calculate the product

⇒[tex] \mathrm{ \frac{3 \times 3}{1 \times 2} + \frac{3}{10} }[/tex]

⇒[tex] \mathrm{ \frac{9}{2} + \frac{3}{10}} [/tex]

Add the fractions

⇒[tex] \mathsf{ \frac{9 \times 5}{2 \times 5} + \frac{3 \times 1}{10 \times 1} }[/tex]

⇒[tex] \mathrm{ \frac{45}{10} + \frac{3}{10} }[/tex]

⇒[tex] \mathrm{ \frac{45 + 3}{10 } }[/tex]

⇒[tex] \mathrm{ \frac{48}{10} }[/tex]

Reduce the numerator and denominator by 2

⇒[tex] \mathrm{ \frac{24}{5} }[/tex]

Further more explanation:

Addition and Subtraction of like fractions

While performing the addition and subtraction of like fractions, you just have to add or subtract the numerator respectively in which the denominator is retained same.

For example :

Add : [tex] \mathsf{ \frac{1}{5} + \frac{3}{5} = \frac{1 + 3}{5} } = \frac{4}{5} [/tex]

Subtract : [tex] \mathsf{ \frac{5}{7} - \frac{4}{7} = \frac{5 - 4}{7} = \frac{3}{7} }[/tex]

So, sum of like fractions : [tex] \mathsf{ = \frac{sum \: of \: their \: number}{common \: denominator} }[/tex]

Difference of like fractions : [tex] \mathsf{ \frac{difference \: of \: their \: numerator}{common \: denominator} }[/tex]

Addition and subtraction of unlike fractions

While performing the addition and subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus, obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator.

For example:

[tex] \mathsf{add \: \frac{1}{2} \: and \: \frac{1}{3} }[/tex]

L.C.M of 2 and 3 = 6

So, ⇒[tex] \mathsf{ \frac{1 \times 3}{2 \times 3} + \frac{1 \times 2}{3 \times 2} }[/tex]

⇒[tex] \mathsf{ \frac{3}{6} + \frac{2}{6} }[/tex]

⇒[tex] \frac{5}{6} [/tex]

Multiplication of fractions

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

When any number or fraction is divided by a fraction, we multiply the dividend by reciprocal of the divisor. Let's consider a multiplication of a whole number by a fraction:

[tex] \mathsf{4 \times \frac{3}{2} = \frac{4 \times 3}{2} = \frac{12}{2} = 6}[/tex]

Multiplication for [tex] \mathsf{ \frac{6}{5} \: and \: \frac{25}{3} }[/tex] is done by the similar process

[tex] \mathsf{ = \frac{6}{5} \times \frac{25}{3} = 2 \times 5 \times 10}[/tex]

Hope I helped!

Best regards!

Answer: 1880 pounds

Step-by-step explanation: when you take the average adult weight, around 160 lbs. you multiply that by eight. you get 1280. then you estimate that each of the children weigh around 100 lbs, then you add 600 to 1280 and get 1,880 lbs

Mistake found

3x-2(2x-4)=2

3x - 4x - 8 = 2 instead of 3x - 4x + 8 = 2

Correct answer

x= -13 y= -30

Answer:

See below.

Step-by-step explanation:

So we have the system of equations:

[tex]3x-2y=21 \text{ and } y=2x-4[/tex]

The student took the following steps:

[tex]3x-2(2x-4)=21\\3x-4x-8=21\\-x-8=21\\-x=29\\x=-29\\y=2(-29)-4=-58-4=-62[/tex]

The student's mistake is in step 2. He/she distributed incorrectly. You are supposed to distribute the -2 to both terms, so it should be -4x plus 8, since -2 times -4 is positive 8. Fixing that mistake, we will have:

[tex]3x-2(2x-4)=21\\3x-4x+8=21 \\-x+8=21\\-x=13\\x=-13\\y=2(-13)-4=-26-4=-30[/tex]

Thus, the final answers should be (-13, -30).

Answer:

D. 2,-1

Step-by-step explanation:

When a line is reflected by y=x, the x and y switch.

Answer:

x = ±4

Step-by-step explanation:

4x^2 = 64

Divide each by 4

4x^2 /4= 64/4

x^2 = 16

Take the square root of each side

sqrt(x^2) = ±sqrt(16)

x = ±4

Answer:

[tex]\boxed{\boxed{x=\pm 4}}[/tex]

Step-by-step explanation:

[tex]4x^2 = 64[/tex]

Divide both sides by 4.

[tex](4x^2)/4 = 64/4[/tex]

Simplify.

[tex]x^2 =16[/tex]

Take the square root on both sides.

[tex]\sqrt{x^2 } =\pm \sqrt{16}[/tex]

Simplify.

[tex]x=\pm 4[/tex]

Answer:

Area of quadrilateral ABCD = 29.79 units² (Approx)

Step-by-step explanation:

Area of triangle ABD

s = (3.48+8.66+8.6) / 2

s = 10.37

Area of triangle ABD = √10.37(10.37-8.66)(10.37-8.6)(10.37-3.48)

Area of triangle ABD = √212.4616

Area of triangle ABD = 14.5760625 unit²

Area of triangle ACD

s = (3.54+8.84+8.6) / 2

s = 10.49

Area of triangle ACD = √10.49(10.49-8.6)(10.49-8.84)(10.49-3.54)

Area of triangle ACD = √227.3558

Area of triangle ACD = 15.0783222 unit²

Area of quadrilateral ABCD = Area of triangle ABD + Area of triangle ACD

Area of quadrilateral ABCD = 14.5760625 unit² + 15.0783222 unit²

Area of quadrilateral ABCD = 29.6542units²

Area of quadrilateral ABCD = 29.79 units² (Approx)

Answer:

Lets start with the top row.

First, add the two values.

5+14=19

Now, divide each value by the total.

5/19=0.26315789473

Round the decimal to the nearest hundredth.

5/19=0.26

14/19=0.73684210526

Round it to the nearest hundredth.

14/19=0.74

Now, The second row.

Add the two values.

16+7=23

Divide the first value by the total.

16/23=0.69565217391

Round it to the nearest hundredth.

16/23=0.70

Divide the second value by the total.

7/23=0.30434782608

Round to the nearest hundredth.

7/23=0.30

Done!

Answer:

Row 1: 0.26 0.74

Row 2: 0.70 0.30

Step-by-step explanation:

Khan

Step-by-step explanation:

Since it's a direct variation

y = kx

where k is the constant of proportionality

To find the value of y when x = –0.5 we must first find the relationship between the variables

When

x = 3

y = 2

2 = 3k

Divide both sides by 3

[tex]k = \frac{3}{2} [/tex]

So the formula for the variation is

When x = - 0.5 or - 1/2

[tex]y = \frac{3}{2} ( - \frac{1}{2} )[/tex]

We have the final answer as

Hope this helps you

Answer:

318

Step-by-step explanation:

Bob=x

Marc=x+30

Donny=3(x+30)

x+x+30+3x+90=500

5x=500-120

5x=380

x=76

Bob has x = 76

Marc has x+30=106

Donny has 3*112=318

318+106+76=500