A(t) = 100t^2 + 500t + 625
3,025 square pixels
Answer:
A(t) equals 100t²+ 500t + 625.
The area of the square image after 3 seconds is 3,025 square pixels.
What is the value of the mean from the following set of data: 12,10, 11, 8, 6, 5, 3, 7, 9. Round to the nearest hundredth.
Answer:
7.88 or 7.9
Step-by-step explanation:
To find the mean, we need to do:
=> (12 + 10 + 11 + 8 + 6 + 5 + 3 + 7 + 9) / 9
=> 71/9
=> 7.88 or 7.9
I divided the sum of all numbers by 9 because we added 9 numbers.
James has a total of 66 dollars in his piggy bank. He only has one dollar bills and two dollar bills in his piggy bank. If there are a total of 49 bills in James's piggy bank, how many one dollar bills does he have?
Answer:
32 one-dollar bills.
Step-by-step explanation:
Let x represent one-dollar bills and y represent two-dollar bills.
He has a total of 49 bills. Therefore:
[tex]x+y=49[/tex]
The total amount of money James has is 66. x is worth one dollar, while y is worth two dollars. Therefore:
[tex]1x+2y=66\\x+2y=66[/tex]
We have a system of equations. Solve by substitution:
[tex]x+2y=66\\x+y=49\\x=49-y\\(49-y)+2y=66\\y=17\\x=49-17=32[/tex]
Therefore, James has 32 one-dollar bills and 17 two-dollar bills.
Checking:
[tex]32(1)+17(2)\stackrel{?}{=}66\\32(1)+17(2)\stackrel{\checkmark}{=}66\\\\32+17\stackrel{?}{=}49\\49\stackrel{\checkmark}{=}49[/tex]
If 2^x =30 find 2^(x+3) A)8 B)5 C)240 D)200 E)250 (Good Luck! Plz solve fast!)
Answer:
C
Step-by-step explanation:
So we already know that:
[tex]2^x=30[/tex]
And we want to find the value of:
[tex]2^{x+3}[/tex]
So, what you want to do here is to separate the exponents. Recall the properties of exponents, where:
[tex]x^2\cdot x^3=x^{2+3}=x^5[/tex]
We can do the reverse of this. In other words:
[tex]2^{x+3}=2^x\cdot 2^3[/tex]
If we multiply it back together, we can check that this statement is true.
Thus, go back to the original equation and multiply both sides by 2^3:
[tex]2^x(2^3)=30(2^3)\\[/tex]
Combine the left and multiply out the right. 2^3 is 8:
[tex]2^{x+3}=30(8)\\2^{x+3}=240[/tex]
The answer is C.
Answer:
the answer is c
Step-by-step explanation:
Write
801
1000
as a decimal number.
Answer:
0.801
Step-by-step explanation:
Answer:
0.801
Step-by-step explanation:
801/1000 = 0.801
A semicircular plate with radius 7 m is submerged vertically in water so that the top is 3 m above the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s2 for the acceleration due to gravity. Recall that the weight density of water is 1000 kg/m3.)
Answer:
F = 585844 N
Step-by-step explanation:
Given that:
A semicircular plate with radius 7 m is submerged vertically in water so that the top is 3 m above the surface.
The objective of this question is to express the hydrostatic force against one side of the plate as an integral and evaluate it.
To start with the equation of a circle: a² + b² = r²
The equation of circle with radius r = 7 can be expressed as:
a² + b² = 7²
a² + b² = 49
b² = 49 - a²
b = [tex]\sqrt{49 -a}[/tex]
NOW;
The integral of the hydrostatic force with a semicircular plate with radius 7 m and the top is 3 m above the surface can be calculated as follows:
[tex]\mathtt{F = 2 \rho g \int \limits^7_3 (a -3) \sqrt{49 -y^2} \ \ da}[/tex]
[tex]\mathtt{F = 2 \rho g \begin {pmatrix}\dfrac{\sqrt{49 -a^2} \ (2a^2-9a - 98)-(441 \times sin^{-1} (\dfrac{a}{3})) }{6} \end{pmatrix}}[/tex]
where;
density of water is 1000 kg/m3
and acceleration due to gravity is 9.8 m/s
Solving the integral; we have:
F = 2 × 1000 kg/m³ × 9.8 m/s × (29.89)
F = 585844 N
Findℒ{f(t)}by first using a trigonometric identity. (Write your answer as a function of s.)f(t) = 12 cost −π6
Answer:
[tex]L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ][/tex]
Step-by-step explanation:
Given that:
[tex]f(t) = 12 cos (t- \dfrac{\pi}{6})[/tex]
recall that:
cos (A-B) = cos AcosB + sin A sin B
∴
[tex]f(t) = 12 [cos\ t \ cos \dfrac{\pi}{6}+ sin \ t \ sin \dfrac{\pi}{6}][/tex]
[tex]f(t) = 12 [cos \ t \ \dfrac{3}{2}+ sin \ t \ sin \dfrac{1}{2}][/tex]
[tex]f(t) = 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t)[/tex]
[tex]L(f(t)) = L ( 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t) ][/tex]
[tex]L(f(t)) = 6 \sqrt{3} \ L [cos \ (t) ] + 6\ L [ sin \ (t) ][/tex]
[tex]L(f(t)) = 6 \sqrt{3} \dfrac{S}{S^2 + 1^2}+ 6 \dfrac{1}{S^2 +1^2}[/tex]
[tex]L(f(t)) = \dfrac{6 \sqrt{3} +6 }{S^2+1}[/tex]
[tex]L(f(t)) = \dfrac{6( \sqrt{3} \ S +1 }{S^2+1}[/tex]
[tex]L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ][/tex]
What inequality does this number line show?
Which equation will solve the following word problem? Jared has 13 cases of soda. He has 468 cans of soda. How many cans of soda are in each case? 13(468) = c 468c = 13 468/13 = c 13 = c/468
Answer:
c = 468 / 13
Step-by-step explanation:
If c is the number of cans of soda in each case, we know that the number of cans in 13 cases is 13 * c = 13c, and since the number of cans in 13 cases is 468 and we know that "is" denotes that we need to use the "=" sign, the equation is 13c = 468. To get rid of the 13, we need to divide both sides of the equation by 13 because division is the opposite of multiplication, therefore the answer is c = 468 / 13.
Answer:
468/13 = c
Step-by-step explanation: Further explanation :
[tex]13 \:cases = 468\:cans\\1 \:case\:\:\:\:= c\: cans\\Cross\:Multiply \\\\13x = 468\\\\\frac{13x}{13} = \frac{468}{13} \\\\c = 36\: cans[/tex]
50. Carrie is running for mayor in her local city election. In order to win, she must earn over 50% of the votes. ecides to hire a couple of Statistics students to help her measure the progress in her campaign through polling. She is hoping to find sufficient evidence (a=0.05) that she will in fact win the election with more than 50% of the vote. The Statistics students test the following hypotheses, where p represents the proportion of all voters who will vote for Jemmy. which of the following statements would be true if a Type I error is made? (Select all that apply.)
a. Carrie ends up winning the election.
b. The students find a p-value less than 0.05 .
c. Carrie ends up losing the election.
d. The students find a p-value greater than 0.05
e. The students make the conclusion that Carrie does not have more than 50% of the vote.
f. The students make the conclusion that Carrie will have more than 50% of the vote. e.
Answer:
b. The students find a p-value less than 0.05
c. Carrie ends up losing the election.
e. The students make the conclusion that Carrie does not have more than 50% of the vote.
Step-by-step explanation:
Null hypothesis is a statement that is to be tested against the alternative hypothesis and then decision is taken whether to accept or reject the null hypothesis.
Type I error is one in which we reject a true null hypothesis.
In the given scenario Type I error will be the one where students incorrectly estimates the p value and reject the null hypothesis when it was true. This error will result in losing the elections.
Which expression simplifies to 7W+5?
. – 2w + 3 + 5W – 2
C. -3w + 5(2W + 1)
Cual es la respuesta
Answer:
[tex]\large \boxed{\mathrm{-3w + 5(2w + 1)}}[/tex]
Step-by-step explanation:
-2w + 3 + 5w - 2
Combine like terms.
3w + 1
-3w + 5(2w + 1)
Expand brackets.
-3w + 10w + 5
Combine like terms.
7w + 5
Answer:
The answer is C.
-3w +5(2w +1)
Step-by-step explanation:
What is the rate of change from x = 0 to x = pi over 2 ? (6 points) trig graph with points at (0, -4) and (pi over 2, 0) and (pi, 4) and (3 pi over 2, 0) and (2 pi, -4)
Answer: [tex]\dfrac{8}{\pi}[/tex] .
Step-by-step explanation:
We know that the rate of change of function f(x) from x=a to x= b is given by :-
[tex]k=\dfrac{f(b)-f(a)}{b-a}[/tex]
The given points on graph : (0, -4) and (pi over 2, 0) and (pi, 4) and (3 pi over 2, 0) and (2 pi, -4).
The rate of change from x = 0 to x = pi over 2 will be :-
[tex]\dfrac{0-(-4)}{\dfrac{\pi}{2}-0}=\dfrac{4}{\dfrac{\pi}{2}}[/tex] [By using points (0, -4) and (pi over 2, 0) ]
[tex]=\dfrac{8}{\pi}[/tex]
Hence, the rate of change from x = 0 to x = pi over 2 is [tex]\dfrac{8}{\pi}[/tex] .
If Ac={vt2/r) and vt=2 and r=2 find Ac
a. 4
b. 2
C. 1
D. 8
given: [tex] Ac=\frac{vt2}r \quad vt=2 \quad r=2[/tex]
$\therefore Ac=\frac{(2)2}{2}=2$
If f(x)=ax^2+bx+c and f(0)=-4 and f(1)=-2 and f(2)=6, what is the value of A and B and C?
Hello There!!
I'm not a 100% sure this right.
Step-by-step explanation:
f(x)=ax2+bx+c for which f(1)=0, f(-2)=6 and f(2)=-14
0 = a +b +c
6 =4a -2b +c
-14=4a+2b +c
subtract third equation from second to get
20 = -4b and so b=-5
first equation is now 5 = a+c
second is now -4=4a+c
subtract to get -9=3a and so a=-3
equation one now is 0=-3-5+c or c=8 Hope This Helps!!
can you please help me with this
Answer:
[tex]\displaystyle A=\dfrac{1}{2}\int_\pi^{\frac{7\pi}{6}}{(\cos{\theta}+\sin{2\theta})^2}\,d\theta[/tex]
Step-by-step explanation:
The shaded area is the area of the curve bounded by θ = π and θ = 7π/6.* A differential of area in polar coordinates is ...
dA = (1/2)r^2·dθ
So, the shaded area is ...
[tex]\displaystyle\boxed{A=\dfrac{1}{2}\int_\pi^{\frac{7\pi}{6}}{(\cos{\theta}+\sin{2\theta})^2}\,d\theta}[/tex]
_____
* We found these bounds by trial and error using a graphing calculator to plot portions of the curve.
The height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning. When graphed, the function gives a line with a slope of −0.4. See the figure below. Suppose that the height of the candle after 11 hours is 16.6 centimeters. What was the height of the candle after 6 hours?
Answer:
height of the candle after 6 hours= 18.6 centimeters
Step-by-step explanation:
the function gives a line with a slope of −0.4.
the height of the candle after 11 hours is 16.6 centimeters.
after 6 hours, the height will be
But slope= y2-y1/x2-x1
Y2 is the unknown
Y1 = 16.6
X1= 11 hours
X2= 6 hours
y2-y1/x2-x1= -0.4
(Y2-16.6)/(6-11)= -0.4
(Y2-16.6)/(-5)= -0.4
(Y2-16.6)= -5( -0.4)
(Y2-16.6)= 2
Y2 = 2+16.6
Y2 = 18.6 centimeters
height of the candle after 6 hours= 18.6 centimeters
Suppose _ . Compute the following:
Step-by-step explanation:
f(x) = x² - 5x - 9
To solve both expressions first find f( -4) and f(5)
For f(- 4)
Substitute the value of x that's - 4 into the expression
That's
f(-4) = (-4)² - 5(-4) - 9
= 16 + 20 - 9
= 36 - 9
f(-4) = 27For f(-5)
Substitute 5 into f (x)
That's
f(5) = 5² - 5(5) - 9
= 25 - 25 - 9
f(5) = - 9A).f(-4) + f(5) = 27 - 9 = 18B). f(-4) - f(5) = 27 -- 9 = 27 + 9 = 36Hope this helps you
PLEASE HELP!! (3/5) - 50 POINTS -
Answer:
infinite number of solutions
Step-by-step explanation:
A dependent system is where the two equations are the same line has has an infinite number of solutions
Answer:
[tex]\boxed{\sf D) \ an\ infinite \ number \ of \ solutions}[/tex]
Step-by-step explanation:
A dependent system of equations has an infinite number of solutions.
When you graph the system of equations, both the equations represent the same line and have an infinite number of solutions.
you pick a card at random from an ordinary deck of 52 cards. If the card is an ace, you get 9 points; if not, you lose a point
Answer: a = 9, b = 48, c = -1
Step-by-step explanation:
"a" represents the points you receive if an Ace is picked. It is given that you get 9 points ----> a = 9
"b" represents the number of cards that are Not an Ace. 4 cards in the deck are Aces so 52 - 4 = 48 cards are Not an Ace -----> b = 48
"c" represents the points you receive if Not an Ace is picked. It is given that you lose 1 point ----> c = -1
Answer:
Here is the rest of the page
Step-by-step explanation:
PPPLLLEEEEAAAASSSSEEEEE ANSWER FAST
The following shape is based only on squares, semicircles, and quarter circles. Find the area of the shaded part.
Answer:
36.53 cm²
Step-by-step explanation:
Picture this repeated four times to make a circle. The circle would have a radius of 8. [tex]\pi[/tex]r² would give us 201.06. One quarter of that would be 50.265.
The area of the square is length times width, or 8X8=64.
64-50.265=13.735. That would be ONE of the non shaded sections of the square. If you take that away twice, the leftover part would be the shaded area.
64-13.735-13.735=36.53 cm²
Please help! Make sure to simplify
[tex] \frac{5b^{5}c}{4c^4} \times \frac{8c}{b^4}[/tex]
[tex]\frac{40b^{5}c^2}{4b^{4}c^4}[/tex]
[tex]{10b^{5-4}c^{2-4}}[/tex]
[tex]10bc^-2[/tex]
[tex]\frac{10b}{c^2}[/tex]
Step-by-step explanation:
[tex] \frac{5 {b}^{5} c}{ 4{c}^{4} } \times \frac{8c}{ {b}^{4} } [/tex]
First reduce the expression with b⁴
b⁴ will cancel b^5 remaining with one b
That's
[tex] \frac{5bc}{4 {c}^{4} } \times 8c[/tex]Next reduce 8 and 4 with their GCF which is 4
We have
[tex] \frac{5bc}{ {c}^{4} } \times 2c[/tex]Reduce the expression with c .
c will go into c⁴ remaining with c³
That's
[tex] \frac{5bc}{ {c}^{3} } \times 2[/tex]Simplify the expression again with c
That's
[tex] \frac{5b}{ {c}^{2} } \times 2[/tex]Multiply the expression
We have the final answer as
[tex] \frac{10b}{ {c}^{2} } [/tex]Hope this helps you
Write three fractions that are equivalent to 3 over 11 , but written in higher terms. One of them must
include one or more variables.
Answer:
Three fractions that are equivalent to [tex]\frac{3}{11}[/tex] are: [tex]\frac{6}{22}[/tex], [tex]\frac{24}{88}[/tex] and [tex]\frac{144}{528}[/tex].
Step-by-step explanation:
Equivalent fractions are set of fractions in which when simplified, they have the same answer.
Given: [tex]\frac{3}{11}[/tex]
i. multiply the numerator and denominator of [tex]\frac{3}{11}[/tex] by 2,
= [tex]\frac{3*2}{11*2}[/tex] = [tex]\frac{6}{22}[/tex]
i. multiply both the numerator and denominator of [tex]\frac{6}{22}[/tex] by 4,
= [tex]\frac{6*4}{22*4}[/tex]= [tex]\frac{24}{88}[/tex]
ii. multiply the numerator and denominator of [tex]\frac{24}{88}[/tex] by 6,
= [tex]\frac{24*6}{88*6}[/tex] = [tex]\frac{144}{528}[/tex]
So that;
[tex]\frac{3}{11}[/tex] = [tex]\frac{6}{22}[/tex] = [tex]\frac{24}{88}[/tex] = [tex]\frac{144}{528}[/tex].
Three fractions that are equivalent to [tex]\frac{3}{11}[/tex] are: [tex]\frac{6}{22}[/tex], [tex]\frac{24}{88}[/tex] and [tex]\frac{144}{528}[/tex].
Let f(x) = 8x3 + 16x2 − 15 and g(x) = 2x + 1. Find f of x over g of x
[tex]\dfrac{f(x)}{g(x)}=\dfrac{8x^3+16x^2-15}{2x+1}[/tex]
How many 4 digit palidromes are there?
To determine her water pressure, Denise divides up her day into three parts: morning, afternoon, and evening. She then measures her water pressure at 2 randomly selected times during each part of the day.What type of sampling is used?a. Simple random b. Cluster c. Stratified d. Convenience e. Systematic
Answer:
The correct answer is:
Stratified (c.)
Step-by-step explanation:
Stratified sampling technique is one in which the groups of data are divided into smaller groups or strata, based on shared common characteristics in these groups, and the samples randomly selected from each group in a proportional way. In this example, the sub-groups used is "times of the day" ie. morning, afternoon or evening. Other strata that can be used are; age, gender, continents etc. Stratification is done when the researcher wants to understand the relationships between the two or more groups. Stratified random sampling is also known as proportional random sampling or quota random sampling.
Triangle ABC has vertices A(0, 6) , B(−8, −2) , and C(8, −2) . A dilation with a scale factor of 12 and center at the origin is applied to this triangle. What are the coordinates of B′ in the dilated image? Enter your answer by filling in the boxes. B′ has a coordinate pair of ( , )
Answer:
[tex]B' = (-96,-24)[/tex]
Step-by-step explanation:
Given
[tex]A(0,6)[/tex]
[tex]B(-8,-2)[/tex]
[tex]C(8,-2)[/tex]
Required
Determine the coordinates of B' if dilated by a scale factor of 12
The new coordinates of a dilated coordinates can be calculated using the following formula;
New Coordinates = Old Coordinates * Scale Factor
So;
[tex]B' = B * 12[/tex]
Substitute (-8,-2) for B
[tex]B' = (-8,-2) * 12[/tex]
Open Bracket
[tex]B' = (-8 * 12,-2 * 12)[/tex]
[tex]B' = (-96,-24)[/tex]
Hence the coordinates of B' is [tex]B' = (-96,-24)[/tex]
Answer:
Bit late but the answer is (-4,-1)
Step-by-step explanation:
Took the test in k12
15+9=? (5+3) What number is missing from the expression?
Answer:
[tex] \boxed{ \boxed{ \bold{ \mathsf{3}}}}[/tex]Step-by-step explanation:
Let the missing number be 'x'
⇒[tex] \mathsf{15 + 9 = x(5 + 3)}[/tex]
Distribute x through the parentheses
⇒[tex] \mathsf{15 + 9 = 5x + 3x}[/tex]
Swap the sides of the equation
⇒[tex] \mathsf{5x + 3x = 15 + 9}[/tex]
Add the numbers
⇒[tex] \mathsf{5x + 3x = 24}[/tex]
Collect like terms
⇒[tex] \mathsf{8x = 24}[/tex]
Divide both sides of the equation by 8
⇒[tex] \mathsf{ \frac{8x}{8} = \frac{24}{8} }[/tex]
Calculate
⇒[tex] \mathsf{x = 3}[/tex]
Hope I helped!
Best regards!
Solve 13x + 14 = 12x -5 (make sure to type the number only)
Answer:
x = -19
Step-by-step explanation:
13x + 14 = 12x - 5
subtract 12x from both sides
x + 14 = -5
subtract 14 from both sides
x = -19
Answer:
x= -19
Step-by-step explanation:
13x+14=12x−5
Subtract 12x from both sides.
13x+14−12x=−5
Combine 13x and −12x to get x.
x+14=−5
Subtract 14 from both sides.
x=−5−14
Subtract 14 from −5 to get −19
x=−19
can anyone ans this question
Answer:
Question 1: the angle of y is the same as 49 degrees.
So, y = 49 degrees.
y + x = straight line
=> Straight line = 180 degrees
=> 49 + x = 180
=> 49 - 49 + x = 180 - 49
=> x = 131
Answer to Question 1:
x = 131 degrees
y = 49 degrees
Question 2: Angle x is the same as 119 degrees
x + y = straight line
=> Straight line = 180 degrees
=> 119 + y = 180
=> 119 - 119 + y = 180 - 119
=> y = 61
y + z = straight line
=> Straight line = 180 degrees
=> 61 + z = 180
=> 61 - 61 + z = 180 - 61
=> z = 119
Answer to Question 2:
x = 119 degrees
y = 61 degrees
z = 119 degrees
Test scores in a Test were normally distributed with a mean of 75 and a standard deviation of 10. Carl scored 90 in the Test . What is the z-score of Carl’s test score?
Answer:
Z-score = 1.5
Step-by-step explanation:
Z-score = (x-mean)/standard deviation
= (90-75)/10
= 1.5
A movie theater is having a special. If a group of four pays $7.25 each for tickets, each person can get popcorn and a drink for $5.75. Use the expression 4(5.75 + 7.25) to find the total cost for 4 friends.
Answer:
The price for 4 people is 52 dollars.
4 × (5.75 + 7.25) = 52
The total cost including drink and popcorn is $52 according to a given condition.
How to form an equation?Determine the known quantities and designate the unknown quantity as a variable while trying to set up or construct a linear equation to fit a real-world application.
In other words, an equation is a set of variables that are constrained through a situation or case.
Cost of movie ticket = $7.25/person
Cost of popcorn and drink = $5.75/person
Total cost per person = 5.75 + 7.25 = $13
Now,
Number of people = 4
So,
4(5.75 + 7.25) = 4(13) = $52
Hence "The total cost including drink and popcorn is $52 according to a given condition".
For more about the equation,
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