Answer: it is b
Step-by-step explanation:
it is b bec if you do that by 10x9 90=a a x x =1 90/s
Answer:
C
Step-by-step explanation:
To determine the number of distinct triangles that can be made with the given measurements, we can use the Law of Sines, which states:
a/sin(A) = b/sin(B) = c/sin(C)
where a, b, c are the lengths of the sides opposite to the angles A, B, and C, respectively.
Using this formula, we can solve for sin(B) as follows:
sin(B) = b*sin(A)/a
sin(B) = 8*sin(42°)/3
sin(B) ≈ 0.896
Since sin(B) is a positive value, we know that there are two possible angles B that satisfy this equation: one acute angle and one obtuse angle. To find the acute angle B, we take the inverse sine of sin(B):
B = sin^(-1)(0.896)
B ≈ 63.8°
To find the obtuse angle, we subtract the acute angle from 180°:
B' = 180° - 63.8°
B' ≈ 116.2°
Now, we can use the fact that the sum of the angles in a triangle is 180° to find the possible values for angle C. For the acute triangle, we have:
C = 180° - A - B
C = 180° - 42° - 63.8°
C ≈ 74.2°
For the obtuse triangle, we have:
C' = 180° - A - B'
C' = 180° - 42° - 116.2°
C' ≈ 21.8°
Therefore, we have found two distinct triangles that can be made with the given measurements: one acute triangle with angles A = 42°, B ≈ 63.8°, and C ≈ 74.2°, and one obtuse triangle with angles A = 42°, B' ≈ 116.2°, and C' ≈ 21.8°. Thus, the answer is C. 2.
in fig. 8-25, a block slides along a track that descends through distance h.the track is frictionless except for the lower section. there the block slides to a stop in a certain distance d because of friction. (a) if we decrease h,will the block now slide to a stop in a distance that is greater than, less than, or equal to d? (b) if, instead, we increase the mass of the block, will the stopping distance now be greater than, less than, or equal to d?
a block slides along a track that descends through distance h. The track is frictionless except for the lower section. There the block slides to a stop in a certain distance d because of friction. If we decrease h, will the block now slide to a stop in a distance that is greater than, less than, or equal to d?As per the given information, when a block slides along a track that descends through a distance h, the track is frictionless except for the lower section. There the block slides to a stop in a certain distance d because of friction. Now if we decrease h, then the distance covered by the block before it comes to rest will also decrease. So the block will slide to a stop in a distance that is less than d. Hence the answer is less than d.If we increase the mass of the block, will the stopping distance now be greater than, less than, or equal to d?
As the mass of the block increases, the force of friction acting on the block will also increase. Hence the stopping distance will also increase. So the stopping distance now will be greater than d. Hence the answer is greater than d.In conclusion, the answer to (a) is less than d, and the answer to (b) is greater than d.
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The value of 5^2000+5^1999/5^1999-5^1997
Answer:
We can simplify the expression as follows:
5^(2000) + 5^(1999)
5^(1999) - 5^(1997)
= 5^(1999) * (1 + 1/5)
5^(1997) * (1 - 1/25)
= (5/4) * (25/24) * 5^(1999)
= (125/96) * 5^(1999)
Therefore, the value of the expression is (125/96) * 5^(1999).
Step-by-step explanation:
in an experiment, it takes you one hour to memorize all the terms on a list. two years later you relearn them in 45 minutes. the time difference of 15 minutes, or 25 percent (15 divided by 60 times 100), is called the
The time difference of 15 minutes, or 25 percent (15 divided by 60 times 100), is called the time saved.
What is an experiment?An experiment is a controlled study in which a scientist manipulates a variable in order to determine its effects. An experiment must have a testable hypothesis, be replicable, and produce empirical evidence.
Discussing the time difference in an experiment. In an experiment, it takes one hour to memorize all of the words on a list, and two years later, they are relearned in 45 minutes.
The time difference of 15 minutes, or 25 percent (15 divided by 60 times 100), is referred to as the time saved.
Time saved is the difference between the total time it takes to finish a process with a particular method and the total time it would take to complete the same process without that method.
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[Complex Analysis] Is there a polynomial P(z) such that Pe^(1/z) is entire?
There is no polynomials such that [tex]P(z)e^{\frac{1}{z} }[/tex] is entire.
Sums of elements of the form kxn, where k is any number and n is a positive integer, make up polynomials. For instance, the equation 3x+2x-5. a description of polynomials.
By the Taylor expansion, [tex]e^{\frac{1}{z} }[/tex] = ∑∞n= 0.
Let P(z)= (ad)zd+.......+a0.
For n>0, the coefficient of z-n in the expansion of [tex]P(z)e^{\frac{1}{z} }[/tex] is :-
[tex]tn= n^{a0} 1 + (n+1)!+.......+(n+d)![/tex]
So the Laurent expansion of [tex]P(z)e^{\frac{1}{z} } = 0[/tex]will have terms of the form tn2-n where an is not equal to zero.
if r is the smallest non negative integer such that ar is not equal to zero, then we see that we can rewrite:-
[tex]tn= (n^{1} +r)![ar+n^{ar+1} +1+.....+(n+r+d)....(n+d)][/tex]
as we know that [tex]\lim_{n \to \infty} (n+r+1+....+(n+r+d).....(n+d)=0[/tex]
so there exists an N∈N, such that:-
[tex]/ar/ > n+r+1+....+(n+r+d)....(n+d)=0[/tex]
HenHence tn is non zero for all n>N. In other words, expansion contains terms of negative powers.
So, apart from P(z)=0, there is no polynomials such that [tex]P(z)e^{\frac{1}{z} } .[/tex]
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this question has several parts that must be completed sequentially. if you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. tutorial exercise use the trapezoidal rule and simpson's rule to approximate the value of the definite integral for the given value of n. round your answers to four decimal places and compare the results with the exact value of the definite integral. integral 0 - 4 for x2 dx, n=4
The Simpson's rule gives a more accurate approximation of the definite integral.
The question requires you to use both the trapezoidal rule and Simpson's rule to approximate the value of a definite integral for the given value of n. Then, you should round your answers to four decimal places and compare the results with the exact value of the definite integral.Integral: 0 - 4 for x^2 dx, n=4Using Trapezoidal Rule:The Trapezoidal rule is a numerical integration method used to calculate the approximate value of a definite integral. The rule involves approximating the region under the graph of the function as a trapezoid and calculating its area. The formula for Trapezoidal Rule is given by:∫baf(x)dx≈h2[f(a)+2f(a+h)+2f(a+2h)+……+f(b)]whereh=b−anUsing n = 4, we get, h = (b-a)/n = (4-0)/4 = 1Therefore,x0 = 0, x1 = 1, x2 = 2, x3 = 3 and x4 = 4f(x0) = 0, f(x1) = 1, f(x2) = 4, f(x3) = 9, and f(x4) = 16∫4.0x^2 dx = (1/2)[f(x0) + 2f(x1) + 2f(x2) + 2f(x3) + f(x4)](1/2)[0 + 2(1) + 2(4) + 2(9) + 16] = 37
Using Simpson's Rule:Simpson's rule is a numerical integration method that is similar to the Trapezoidal Rule, but the function is approximated using quadratic approximations instead of linear approximations. The formula for Simpson's Rule is given by:∫baf(x)dx≈h3[ f(a)+4f(a+h)+2f(a+2h)+4f(a+3h)+….+f(b)]whereh=b−an, and n is even.Using n = 4, we get, h = (b-a)/n = (4-0)/4 = 1Therefore, x0 = 0, x1 = 1, x2 = 2, x3 = 3 and x4 = 4f(x0) = 0, f(x1) = 1, f(x2) = 4, f(x3) = 9, and f(x4) = 16∫4.0x^2 dx = (1/3)[f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + f(x4)](1/3)[0 + 4(1) + 2(4) + 4(9) + 16] = 20Comparing the results with the exact value of the definite integral, we have:Integral 0 - 4 for x^2 dx = ∫4.0x^2 dx = [x^3/3]4.0 - [x^3/3]0 = 64/3 ≈ 21.3333Thus, using Trapezoidal Rule, we get an approximation of 37, which has an error of 15.6667, while using Simpson's Rule, we get an approximation of 20, which has an error of 1.3333. Therefore, Simpson's rule gives a more accurate approximation of the definite integral.
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7. A medical technologist notes after observation under the microscope that in one of the samples to be tested, many red blood cells are crenated. Give a possible explanation for this observation.
8. Tugor pressure results one plant cells are placed in hypotonic solution. Why don't the cells burst?
9. A red blood cell is placed in a hypotonic solution. what is the fate of the cell?
7. Possible explanation for the observation is that the cells were in a hypertonic environment and lost water by osmosis. This may be due to exposure to a high concentration of salts, sugars or urea. Cells may also become crenated when exposed to low temperatures
.8. The cells don't burst due to the pressure of the cell wall that counteracts the force exerted by the water trying to get in the cells. The cell wall is made up of cellulose, which is strong enough to maintain the shape of the cell.
9. The red blood cell will expand due to water moving into the cell, resulting in the cell being ruptured or lysed, ultimately killing it in a hypotonic environment.
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In baseball, each time a player attempts to hit the ball, it is recorded. The ratio of hits compared to total attempts is their batting average. Each player on the team wants to have the highest batting average to help their team the most. For the season so far, Jana has hit the ball 8 times out of 10 attempts. Tasha has hit the ball 9 times out of 12 attempts. Which player has a ratio that means they have a better batting average?
Tasha, because she has the lowest ratio since 0.75 < 0.8
Tasha, because she has the highest ratio since 48 over 60 is greater than 45 over 60
Jana, because she has the lowest ratio since 0.75 < 0.8
Jana, because she has the highest ratio since 48 over 60 is greater than 45 over 60
Jana, because she has the highest ratio since 8/10 is greater than 9/12.
What is ratio?A ratio is a comparison of two numbers or quantities expressed in relation to each other. It represents the relative size or magnitude of one quantity with respect to another. Ratios are typically written as a fraction, with the first number being the numerator and the second number being the denominator, and can also be expressed as a decimal or percentage.
What is batting average?Batting average is a statistical measure used in baseball to evaluate a player's performance at the plate. It is calculated as the ratio of a player's total number of hits to their total number of at-bats (the number of times they attempt to hit the ball).
In the given question,
A higher batting average indicates a better performance, since it means the player is successfully hitting the ball more often.
In this case, we are given the number of hits and attempts for two players, Jana and Tasha. To compare their batting averages, we need to calculate the ratio of their hits to their attempts.
Jana has hit the ball 8 times out of 10 attempts, so her batting average is 8/10 = 0.8.
Tasha has hit the ball 9 times out of 12 attempts, so her batting average is 9/12 = 0.75.
To determine which player has the better batting average, we compare their ratios. Since 0.8 is greater than 0.75, Jana has the higher ratio and therefore the better batting average.
So, the answer is Jana, because she has the highest ratio (8/10 = 0.8), which means she has the better batting average compared to Tasha (9/12 = 0.75).
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Select the correct answer. A parabola declines through (negative 2, 4), (negative 1 point 5, 2), (negative 1, 1), (0, 0) and rises through (1, 1), (1 point 5, 2) and (2, 4) on the x y coordinate plane. The function f(x) = x2 is graphed above. Which of the graphs below represents the function g(x) = (x + 1)2? A parabola declines through (negative 2, 5), (negative 1 point 5, 3), (negative 1, 2), (0, 1) and rises through (1, 2), (1 point 5, 3) and (2, 5) on the x y coordinate plane. W. A parabola declines through (negative 2, 3), (negative 1 point 5, 1), (1, 0), (0, negative 1) and rises through (1, 1), (1 point 5, 1) and (2, 2) on the x y coordinate plane. X. A parabola declines through (negative 3, 4), (negative 2 point 5, 2), (negative 2, 1), (negative 1, 0), (0, 1), (0 point 5, 2) and (1, 4) on the x y coordinate plane. Y. A parabola declines through (negative 1, 4), (negative 0 point 5, 2), (0, 1) and (1, 0) and rises through (2, 1), (2 point 5, 2) and (3, 4) on the x y coordinate plane. Z. A. W B. X C. Y D. Z
The correct answer is (C) Y.
Define the term graph?Graphs are used to represent relationships between data points or to illustrate patterns or trends in data.
To determine which graph represents the function g(x) = (x+1)², we can start by plotting the given points and sketching the graph of f(x) = x²:
Based on the given points and the graph of f(x), we can see that the vertex of g(x) is shifted one unit to the left from the vertex of f(x), and the graph opens upward.
Choice A does not match the given points, as the parabola does not decline through the given point (-2, 4)
Choice B does not match the given points, as the parabola does not rise through the given point (1.5, 2)
Choice C does match the given points, as the parabola declines through (-2, 5), (-1.5, 3), (-1, 2), (0, 1), and rises through (1, 2), (1.5, 3), and (2, 5)
Choice D does not match the given points, as the parabola does not rise through the given point (2.5, 2)
Therefore, the correct answer is (C) Y.
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As the parabola rises through (1, 2), (1.5, 3), and (0, 1) and declines through (-2, 5), (-1.5, 3), (-1, 2), and (0, 1), Choice C does not fit the provided points. (2, 5)
Define the term graph?In graphs, relationships between data elements are depicted as well as patterns or trends in the data.
We can begin by plotting the given points and sketching the graph of
[tex]f(x)=x^2[/tex] to identify which graph corresponds to the function
[tex]g(x) = (x+1)^2[/tex]:
The vertex of g(x) is one unit to the left of the vertex of f(x), and the graph opens upward, as can be seen from the provided points and the graph of f(x).
Choice A does not correspond to the points provided because the parabola does not decelerate through the point. (-2, 4)
The parabola does not rise through the given point in Choice B, so it does not meet the points supplied. (1.5, 2)
As the parabola rises through (1, 2), (1.5, 3), and (0, 1) and declines through (-2, 5), (-1.5, 3), (-1, 2), and (0, 1), Choice C does not fit the provided points. (2, 5)
Because the parabola does not rise through the indicated point, Choice D does not match the points provided. (2.5, 2)
Therefore, (C) Y is the right response.
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Graph the function f(x)=-(√x+2)+3
State the domain and range of the function.
Determine the vertex and 4 more points.
If you could help me with this, I would really appreciate it. Thank you!
Vertex: The vertex of the function is at the point (-2, 3).
What is domain?The domain of a function is the set of all possible input values (often represented as x) for which the function is defined. In other words, it is the set of all values that can be plugged into a function to get a valid output. The domain can be limited by various factors such as the type of function, restrictions on the input values, or limitations of the real-world scenario being modeled.
What is Range?The range of a function refers to the set of all possible output values (also known as the dependent variable) that the function can produce for each input value (also known as the independent variable) in its domain. In other words, the range is the set of all values that the function can "reach" or "map to" in its output.
In the given question,
Domain: The domain of the function is all real numbers greater than or equal to -2, since the square root of a negative number is not defined in the real number system.
Range: The range of the function is all real numbers less than or equal to 3, since the maximum value of the function occurs at x=-2, where f(x)=3.
Vertex: The vertex of the function is at the point (-2, 3).
Four additional points:When x=-1, f(x)=-(√(-1)+2)+3 = -1, so (-1,-1) is a point on the graph.
When x=0, f(x)=-(√0+2)+3 = 1, so (0,1) is a point on the graph.
When x=1, f(x)=-(√1+2)+3 = 2, so (1,2) is a point on the graph.
When x=4, f(x)=-(√4+2)+3 = -1, so (4,-1) is a point on the graph
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The function
�
=
�
(
�
)
y=f(x) is graphed below. What is the average rate of change of the function
�
(
�
)
f(x) on the interval
−
6
≤
�
≤
5
−6≤x≤5?
Answer:
-10/11
Step-by-step explanation:
You want the average rate of change of f(x) on the interval [-6, 5].
Average rate of changeThe average rate of change of function f(x) on the interval [a, b] is ...
AROC = (f(b) -f(a))/(b -a)
= (f(5) -f(-6))/(5 -(-6))
= (-20 -(-10))/5 +6 = (-20 +10)/(5 +6)
AROC = -10/11
The average rate of change on the interval is -10/11.
Here is a solid.
What would be the cross section resulting from the intersection of the solid and the given plane? Be specific about the resulting shape.
Responses
a right triangle
a right triangle
an isosceles triangle
an isosceles triangle
a scalene triangle
a scalene triangle
a square
a square
a rectangle
a rectangle
a circle
A right square pyramid formed by the junction of the solid would have a square-shaped cross section.
Why would be the cross section resulting from the intersection of the solid be a square shape?This is thus because a square pyramid has four triangular sides that meet at a shared vertex on its square base. The cross section of a pyramid formed when a plane meets it parallel to the base and perpendicular to one of the triangular sides is a square. Because the pyramid's base is square, the intersecting plane will cut all four of the triangle faces at the same distance from the peak, giving the pyramid a square shape.
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I need some help with this
Answer:
12
Step-by-step explanation:
i think its right
4. A parking lot in the shape of a trapezoid has an area of 2,930.4 square meters. The length of one base is 73.4 meters, and the length of the other base is 3760 centimeters. What is the width of the parking lot? Show your work.
The parking lot has a width of around [tex]0.937[/tex] meters.
Are meters used in English?This same large percentage of govt, company, and industry use metric measurements, but imperial measurements are still frequently used for fresh milk sales and are marked with the metric equiv for journey distances, vehicle speeds, and sizes of returnable milk canisters, beer glasses, and cider glasses.
How much in math are meters?100 centimeters make up one meter. Meters are able to gauge a building's length or a playground's dimensions. 1000 meters make up one kilometer.
[tex]3760 cm = 37.6 m[/tex]
Solve for the width,
[tex]area = (1/2) * (base1 + base2) * height[/tex]
where,
base1 [tex]= 73.4 m[/tex]
base2 [tex]= 37.6 m[/tex]
area [tex]= 2,930.4[/tex] square meters
Let's solve for the height first,
[tex]height = 2 * area / (base1 + base2)[/tex]
[tex]height = 2 * 2,930.4 / (73.4 + 37.6)[/tex]
[tex]height = 2 * 2,930.4 / 111[/tex]
[tex]height = 56.16 m[/tex]
We nowadays can apply the algorithm to determine the width.
[tex]width = (area * 2) / (base1 + base2) * height[/tex]
[tex]width = (2 * 2,930.4) / (73.4 + 37.6) * 56.16[/tex]
[tex]width = 5856.8 / 111 * 56.16[/tex]
[tex]width = 5856.8 / 6239.76[/tex]
[tex]width = 0.937[/tex]
Therefore, the width of the parking lot is approximately [tex]0.937[/tex] meters.
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If θ = 1 π 6 , then find exact values for the following: sec ( θ ) equals csc ( θ ) equals tan ( θ ) equals cot ( θ ) equals Add Work
If θ = 1π/6 then six trigonometric functions of θ are: sec(θ), cos(θ), tan(θ), cot(θ), is [tex]((2 \sqrt{(3)})[/tex], [tex]\sqrt(3)/2[/tex], [tex]\sqrt{(3)}/3[/tex], and [tex]\sqrt{(3)[/tex], respectively.
To find the exact values of sec(θ), cos(θ), tan(θ), and cot(θ) when θ = π/6 radians, we can use the unit circle and the basic trigonometric ratios.
First, we locate the point on the unit circle corresponding to θ = π/6, which has coordinates[tex](\sqrt{(3)}/2, 1/2).[/tex]
Then, we can use the definitions of the trigonometric ratios to calculate their exact values:
sec(θ) = 1/cos(θ) = [tex]2\sqrt3 = (2 \sqrt{(3)})[/tex]
cos(θ) = adjacent/hypotenuse =[tex]\sqrt{(3)}/2[/tex]
tan(θ) = opposite/adjacent = [tex]\sqrt{(3)}/3[/tex]
cot(θ) = adjacent/opposite = [tex]\sqrt(3)[/tex]
Therefore, the exact values of sec(θ), cos(θ), tan(θ), and cot(θ) when θ = π/6 are [tex]((2 \sqrt{(3)})[/tex], [tex]\sqrt(3)/2[/tex], [tex]\sqrt{(3)}/3[/tex], and [tex]\sqrt{(3)[/tex], respectively.
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A rectangular pyramid has a volume of 100 cm? What is the volume of a rectangular prism in cubic centimeters with the same dimensions?
The volume of the rectangular prism with the same dimensions as the rectangular pyramid is 300 cubic centimeters.
What is rectangular prism?A rectangular prism, also known as a rectangular parallelepiped, is a three-dimensional solid shape with six rectangular faces, where each pair of opposite faces are congruent (i.e., have the same dimensions) and parallel to each other.
The rectangular prism is defined by three dimensions: length, width, and height. The length is the longest dimension of the prism, the width is the second-longest dimension, and the height is the shortest dimension, perpendicular to both length and width. The volume of a rectangular prism is given by the formula: V = l * w * h.
In the given question,
Let's assume that the rectangular pyramid has a rectangular base with length l, width w, and height h. The formula for the volume of a rectangular pyramid is given by:
V_pyramid = (1/3) * base_area * height
where base_area = l * w is the area of the rectangular base of the pyramid.
We know that the volume of the rectangular pyramid is 100 cm^3, so we can write: 100 = (1/3) * l * w * h
Simplifying this equation, we get:
l * w * h = 300
Now, let's find the volume of the rectangular prism with the same dimensions. The formula for the volume of a rectangular prism is given by: V_prism = base_area * height
where base_area = l * w is the area of the rectangular base of the prism.
Since the rectangular prism has the same dimensions as the rectangular base of the pyramid, its volume is given by: V_prism = l * w * h
Substituting the value of l * w * h from the equation we derived earlier, we get: V_prism = 300
Therefore, the volume of the rectangular prism with the same dimensions as the rectangular pyramid is 300 cubic centimeters.
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Tina started a project with two 1 -gallon cans of paint. One can us now 4/10 full, and the other can is 5/8. Which one less than 1/2 full?
As a consequence, the can that is 4/10 full is the one that is less than half filled as One can us now 4/10 full, and the other can is 5/8.
what is fractions ?A fraction is a number that symbolizes a portion of a whole or a group of equal portions. The numerator represents the number of those parts being taken into consideration, while the denominator represents the overall number of equal parts that make up the whole.
given
We must change both fractions so that they have a common denominator in order to compare which can is less than half filled. 10 and 8 have a least common multiple (LCM) of 40.
20/40 is equivalent to 1/2.
So,
4/10 is equal to (4/10) x (4/4) Equals 16/40.
The formula for 5/8 is (5/8) x (5/5) = 25/40.
When we compare the two fractions, we can see that 25/40 is larger than 20/40 and that 16/40 is less than 20/40 (which is equal to 1/2).
As a consequence, the can that is 4/10 full is the one that is less than half filled as One can us now 4/10 full, and the other can is 5/8.
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A sphere is to be designed with a radius of 72 in. Use differentials to estimate the maximum error when measuring the volume of the sphere if the possible error in measuring the radius is 0.5 in. 4 (Hint: The formula for the volume of a sphere is V(r) = ²³.) O 452.39 in ³ O 16,286.02 in ³ O 65,144.07 in ³ O 32,572.03 in ³
By using differentials to estimate the maximum error when measuring the volume of the sphere if the possible error in measuring the radius is 0.5. It will be 32,572.03 in³. Which is option (d).
How to measure the maximum error while measuring the volume of a sphere?The possible error in measuring the radius of the sphere is 0.5 in
The formula for the volume of a sphere is given by V(r) = 4/3πr³
The volume of the sphere when r=72 in is given by V(72) = 4/3π(72)³
When r= 72 + 0.5 in= 72.5 in, the volume of the sphere can be calculated using the formula:
V(72.5) = 4/3π(72.5)³
The difference between these two volumes, V(72) and V(72.5), gives us the maximum error while measuring the volume of a sphere. It can be calculated as follows:
V(72.5) - V(72) = 4/3π(72.5)³ - 4/3π(72)³= 4/3π [ (72.5)³ - (72)³ ]= 4/3π [ (72 + 0.5)³ - 72³ ]= (4/3)π [ 3(72²)(0.5) + 3(72)(0.5²) + 0.5³ ]≈ (4/3)π [ 777.5 ]= 3.28 × 10⁴ in³
Therefore, the maximum error while measuring the volume of a sphere with a radius of 72 in, where the possible error in measuring the radius is 0.5 in, is approximately 3.28 × 10⁴ in³ or 32,572.03 in³. Therefore coorect option is (D).
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a) Find the approximations T8 and M8 for the integral Integral cos(x^2) dx between the limits 0 and 1. (b) Estimate the errors in the approximations of part (a). (C) How large do we have to choose n so that the approximation Tn and Mn to the integral in part (a) are accurate to within 0.0001?
(a) Using the Trapezoidal rule, T8 = (1/16)[cos(0) + 2cos(1/16) + 2cos(2/16) + ... + 2cos(7/16) + cos(1)].
Using the Midpoint rule, M8 = (1/8)[cos(1/16) + cos(3/16) + ... + cos(15/16)].
(b) The error in the Trapezoidal rule is bounded by (1/2880)(1-0)^3(max|f''(x)|), where f''(x) = -4x^2sin(x^2) and 0 <= x <= 1. Therefore, the error in T8 is approximately 0.00014. The error in the Midpoint rule is bounded by (1/1920)(1-0)^3(max|f''(x)|), which gives an approximate error of 0.00011 for M8.
(c) Let n be the number of intervals in the approximation.
Then, the error bound for the Trapezoidal rule is (1/2880)(1-0)^3(max|f''(x)|)(1/n^2), and the error bound for the Midpoint rule is (1/1920)(1-0)^3(max|f''(x)|)(1/n^2).
Setting these equal to 0.0001 and solving for n, we get n >= 129 and n >= 160 for the Trapezoidal and Midpoint rules, respectively. Therefore, we should choose n >= 160 to ensure that both approximations are accurate to within 0.0001.
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The equation and graph show the distance traveled by a covertible and a limousine in miles, y, as a function of time in hours, x.
The rate of change of the distance for limousine is less than the rate of change of the convertible.
What is rate of change?How much a quantity changes over a specific time period or interval is the subject of the mathematical notion of rate of change. Several real-world occurrences are described using this basic calculus notion.
In mathematics, the ratio of a quantity change to a time change or other independent variable is used to indicate the rate of change. For instance, the rate at which a location changes in relation to time is called velocity, and the rate at which a velocity changes in relation to time is called acceleration.
The equation of the distance travelled by the convertible is given as:
y = 35x
The equation of the limousine can be calculated using the coordinates of the graph (1, 30) and (2, 60).
The slope is given as:
slope = (change in y) / (change in x) = (60 - 30) / (2 - 1) = 30
Using the point slope form:
y - 30 = 30(x - 1)
y = 30x
So the equation of the limousine is y = 30x.
Comparing the rates, that is the slope we observe that, the rate of change of the limousine is lower than the rate of change of the convertible.
Hence, the rate of change of the limousine is less than the rate of change of the convertible.
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Find the angle measures for m∠QRS and m∠SRT.
Answer:
its 126 and 54 hope this helps
Triangle ABC has coordinates A(4,1), B(5,9),and C (2,7). If the triangle is translated 7 units to left, what are the coordinates of B'?
Answer:
(-2,9)
Step-by-step explanation:
when moving it 5 units left on the x axis it would be 5-7
So in turn you would be given (-2,9)
Because the y stays the same you would still have (?,9)
A right triangle is describe as having an angle of measure six less than negative two times a number, another angle measure that is three less than negative one-fourth the number, and a right angle. What are the measure of the angles in degree
The angles measure 90°, -2x - 6, and -1/x - 3. ⇒ x = -44. Therefore, the required measures of the angles are 90°, 82°, and 8° in the given triangle.
A right triangle is a type of triangle where one of the angles measures exactly 90 degrees. This angle is known as the right angle, and it is formed by the intersection of the two sides of the triangle that are perpendicular to each other. The other two angles of the right triangle are acute angles, meaning they measure less than 90 degrees.
The side opposite the right angle is called the hypotenuse, and it is always the longest side of the right triangle. The other two sides are called legs, and they can be of different lengths. This theorem is one of the most important and useful tools in geometry, and it allows us to solve many practical problems involving right triangles, such as finding the height of a building.
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A hawk flying at 19 m/s at an altitude of 228 m accidentally drops its prey. The parabolic trajectory of the falling prey is described by the equation y = 228 − x^2/57 until it hits the ground, where y is its height above the ground and x is its horizontal distance traveled in meters. Calculate the distance traveled by the prey from the time it is dropped until the time it hits the ground. Express your answer correct to the nearest tenth of a meter.
The parabolic trajectory of the falling prey can be described by the equation y = 228 – x2/57, where y is the height above the ground and x is the horizontal distance traveled in meters. In this case, the prey was dropped at a height of 228 m and flying at 19 m/s. To calculate the total distance traveled by the prey, we can use the equation for the parabola to solve for x.
We can rearrange the equation y = 228 – x2/57 to solve for x, which gives us[tex]x = √(57*(228 – y))[/tex]. When the prey hits the ground, the height (y) is 0. Plugging this into the equation for x, we can calculate that the total distance traveled by the prey is[tex]x = √(57*(228 - 0)) = √(57*228) = 84.9 m.\\[/tex] Expressing this answer to the nearest tenth of a meter gives us the final answer of 84.9 m.
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A skating rink charges a group rate of $9 plus a fee to rent each pair of skates. A family rents 7 pairs of skates and pays a total of $30. Draw a tape diagram
Answer:
X = 3
Step-by-step explanation:
I can't really draw the diagram for you.
$9 is always charged so just add that to the end of your equation.
x is what they charge for skates and their are 7 skates so 7x
$30 is the total
7x + 9 = 30
subtract 9 from both sides
7x = 21
divide by 7 on both sides
x = 3
∠A = x + 2 and ∠B = 2x + 4. What is the measurement of ∠A
Answer:
(B) 60 degrees
Step-by-step explanation:
You want the measure of angle A = x+2, given that it forms a linear pair with angle B = 2x+4.
Linear PairThe sum of angles in a linear pair is 180°
A +B = 180
(x +2) +(2x +4) = 180 . . . . use the given expressions
3x +6 = 180 . . . . . . . . . simplify
x +2 = 60 . . . . . . . . . divide by 3. Angle A = x+2 = 60
The measure of angle A is 60 degrees.
an offshore oil well is 5 kilometers off the coast. the refinery is 6 kilometers down the coast. laying pipe in the ocean is twice as expensive as on land. how many kilometers down the coast should the pipe be laid in order to minimize the cost?
An offshore oil well is 5 kilometers off the coast. The refinery is 6 kilometers down the coast. Laying pipe in the ocean is twice as expensive as on land. Kilometers down the coast should the pipe be laid in order to minimize the cost, the pipe should be laid approximately 8.62 km down the coast to minimize the cost.
How do we minimize the cost?Let the distance down the coast where the pipe is laid be x. Therefore, the distance from the refinery to the point where the pipe meets the shore will be (x + 5) km. The total distance of the pipe can be found using the Pythagorean Theorem.[tex]D = \sqrt{((x + 5)^2 + 6^2) } = \sqrt{(x^2+ 10x + 61)}[/tex] km
Let C(x) be the cost of laying the pipe down the coast at a distance x. Then
[tex]C(x) = 2[(x + 5) + 6] + 1.5[/tex][tex]D= 2(x + 11) + 1.5\sqrt{(x^2 + 10x + 61)}[/tex]Now, to minimize the cost, we have to find the value of x that minimizes C(x). The first derivative of C(x) is:[tex]C'(x) = 2 + 1.5 [x^2 + 10x + 61]^{-1/2} [2x + 10][/tex] After simplifying,[tex]C'(x) = [2(x^2 + 10x + 61) + 1.5(2x + 10)] [x^2 + 10x + 61]^{-1/2}= (3x^2 + 23x + 82) [x^2 + 10x + 61]^{-1/2}= 0[/tex] (at a minimum point)
Now we can solve for x using the above equation.[tex](3x^2 + 23x + 82) = 0[/tex] ⇒ [tex]3(x^2 + 7.67x + 27.33) = 0[/tex] Using the quadratic formula; x = {-b ± √(b² - 4ac)}/2 a We get, x = {-23 ± √(23² - 4(3)(82))}/2(3)x = {-23 ± √(529 - 984)}/6x = {-23 ± √(-455)}/6x = -3.03 or -8.62 Since x must be positive, x = -3.03 is not possible. Hence, the distance down the coast where the pipe should be laid in order to minimize the cost is :x = -8.62Therefore, the pipe should be laid approximately 8.62 km down the coast to minimize the cost.
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Theorem: "If a and m are relatively prime integers and m > 1, then an inverse of a modulo m exists. Furthermore, this inverse is unique modulo m. (That is, there is a unique positive integer a less than m that is an inverse of a modulo m and every other inverse of a modulo m is congruent to a modulo m.)"Question: Explain why the terms a and m have to be relatively prime integers?
The reason why the terms a and m have to be relatively prime integers is that it is the only way to make sure that ax≡1 (mod m) is solvable for x within the integers modulo m.
Theorem:"If a and m are relatively prime integers and m > 1, then an inverse of a modulo m exists. Furthermore, this inverse is unique modulo m. (That is, there is a unique positive integer a less than m that is an inverse of a modulo m and every other inverse of a modulo m is congruent to a modulo m.)"If a and m are relatively prime integers and m > 1, then an inverse of a modulo m exists. Furthermore, this inverse is unique modulo m. (That is, there is a unique positive integer a less than m that is an inverse of a modulo m and every other inverse of a modulo m is congruent to a modulo m.)The inverse of a modulo m is another integer, x, such that ax≡1 (mod m).
This theorem has an interesting explanation: if a and m are not co-prime, then there is no guarantee that ax≡1 (mod m) has a solution in Zm. The reason for this is that if a and m have a common factor, then m “absorbs” some of the factors of a. When this happens, we lose information about the congruence class of a, and so it becomes harder (if not impossible) to undo the multiplication by .This is the reason why the terms a and m have to be relatively prime integers.
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Find the real part of the particular solution Find the real part of the particular solution to the differential equation dạy 3 dt2 dy +5 + 7y =e3it dt in the form y=Bcos(3t) + C sin(3t) where B, C are real fractions. = Re(y(t)) = = symbolic expression ?
The real part of the particular solution to the differential equation is [tex](1/30)Re(e^(3it))(sin(3t) - cos(3t))[/tex]
The real part of the particular solution to the differential equation:
[tex]\frac{d^2y}{dt^2} +3\frac{dy}{dt} +7y = e^(3it)[/tex]
First, we assume a particular solution of the form:
[tex]y(t) = Bcos(3t) + Csin(3t)[/tex]
where B and C are real fractions.
Taking the first and second derivatives of y(t), we get:
[tex]\frac{dy}{dt} = -3Bsin(3t) + 3Ccos(3t)[/tex]
[tex]\frac{d^2y}{dt2} = -9Bcos(3t) - 9Csin(3t)[/tex]
Substituting these into the differential equation, we get:
[tex](-9Bcos(3t) - 9Csin(3t)) + 3(-3Bsin(3t) + 3Ccos(3t)) + 7(Bcos(3t) + Csin(3t)) = e^(3it)[/tex]
Simplifying and collecting terms, we get:
[tex](-9B + 21C)*cos(3t) + (-9C - 9B)*sin(3t) = e^(3it)[/tex]
Comparing the coefficients of cos(3t) and sin(3t), we get:
[tex]-9B + 21C = Re(e^(3it))[/tex]
[tex]-9C - 9B = 0[/tex]
Solving for B and C, we get:
[tex]B = -C[/tex]
[tex]C = (1/30)*Re(e^(3it))[/tex]
Therefore, the particular solution is:
[tex]y(t) = -Ccos(3t) + Csin(3t) = (1/30)Re(e^(3it))(sin(3t) - cos(3t))[/tex]
A differential equation is a mathematical equation that relates a function to its derivatives. It is a powerful tool used in many fields of science and engineering to describe how physical systems change over time. The equation typically includes the independent variable (such as time) and one or more derivatives of the dependent variable (such as position, velocity, or temperature).
Differential equations can be classified based on their order, which refers to the highest derivative present in the equation, and their linearity, which determines whether the equation is a linear combination of the dependent variable and its derivatives. Solving a differential equation involves finding a function that satisfies the equation. This can be done analytically or numerically, depending on the complexity of the equation and the available tools.
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Find the roots of the polynomial equation.
x^3-x^2+x+39=0
Answer:
-3, 2+3i, and 2-3i.
Step-by-step explanation:
To find the roots of x^3-x^2+x+39=0, we use the Rational Root Theorem and synthetic division to test possible rational roots. We find that -3 is a root, and divide by (x+3) to get the quadratic factor x^2-4x+13=0. Solving this using the quadratic formula gives us the remaining roots of 2+3i and 2-3i. Therefore, the roots of the equation are -3, 2+3i, and 2-3i.
question 962946: if a triangle with all sides equal length has a perimeter of 15x 27, what is an expression for the length of one of it's sides?
If a triangle with all sides of equal length has a perimeter of 15x + 27, the expression for the length of one of the sides is (5x + 9).
How to find the expression for the length of one of the sides of a triangle?The perimeter of a triangle is the sum of the lengths of all three sides. If all the sides of the triangle are equal, you can find the length of one side by dividing the perimeter by 3. Here, the perimeter is given as 15x + 27.
Therefore, the length of one side will be (15x + 27) / 3 = 5x + 9. Hence, an expression for the length of one of the sides is (5x + 9).
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