Thirty less than four times a number is fifty

Answer:

Step-by-step explanation:

the equation is 8 cause 10 equals 8

Given:

Principal = $14850

Rate of interest = 4% compounded semiannually.

Time = 3 years

To find:

The amount after 3 years.

Solution:

Formula for amount is:

[tex]A=P\left(1+\dfrac{r}{n}\right)^{nt}[/tex]

Where, P is principal, r is the rate of interest in decimal, n is the number of times interest compounded and t is the number of years.

The interest is compounded semiannually, so n=2.

Putting [tex]P=14850, r=4, n=2, t=3[/tex] in the above formula, we get

[tex]A=14850\left(1+\dfrac{0.04}{2}\right)^{2(3)}[/tex]

[tex]A=14850\left(1+0.02\right)^{6}[/tex]

[tex]A=14850\left(1.02\right)^{6}[/tex]

On further simplification, we get

[tex]A=14850(1.12616242)[/tex]

[tex]A=16723.511937[/tex]

[tex]A\approx 16723.51[/tex]

Therefore, the amount in the account after three years is $16723.51.

Answer:

$101

Step-by-step explanation:

Given

[tex]y = 8.50x + 33[/tex]

[tex]x \to[/tex] age above 40

Required

Insurance for 48 years old

First, we solve for x

[tex]x = 48 - 40[/tex]

[tex]x = 8[/tex]

So, we have:

[tex]y = 8.50x + 33[/tex]

[tex]y = 8.50 * 8 + 33[/tex]

[tex]y = 68 + 33[/tex]

[tex]y = 101[/tex]

Answer:

Area = 96 square m

Step-by-step explanation:

[tex]Area = base \times height = 12 \times 8 = 96 \ m^2[/tex]

Answer:

The area of parallelogram is 96 m ².

Step-by-step explanation:

According to the question , we have given a parallelogram with base 12 m and height is 8 m. We need to find the area of parallelogram.

Using Formula

Area of parallelogram = Base × Height

Substitute the values into this formula

Area of parallelogram = 12 m × 8 m

multiply, we get

Area of parallelogram = 96 m²

Therefore, The area of parallelogram is 96 m ².

Answer:

x = 40

3x=120

x+40 = 120

Step-by-step explanation:

The angles are vertical angles which means they are equal

3x= x+80

Subtract x from each side

3x-x =x+80-x

2x = 80

Divide by 2

2x/2 = 80/2

x = 40

3x = 3(40) =120

x+80 = 40+80 = 120

9514 1404 393

Answer:

  12

Step-by-step explanation:

The square can be completed by adding and subtracting the square of half the linear term's coefficient.

  f(x) = x^2 -8x +(-8/2)^2 +28 -(-8/2)^2

  f(x) = (x^2 -8x +16) +(28 -16)

  f(x) = (x -4)^2 +12

The minimum value of the function is 12, when the squared term is zero.

Answer:

0.999945 = 99.9945% probability that at least two of the alarms are triggered.

Step-by-step explanation:

For each alarm, there are only two possible outcomes. Either it is triggered, or it is not. The probability of an alarm being triggered is independent of any other alarm, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

A home security system is designed to have a 90% reliability rate.

This means that [tex]p = 0.9[/tex]

Suppose that 6 home equipped with this system experience an attempted burglary.

This means that [tex]n = 6[/tex]

Find the probability that at least two of the alarms are triggered.

This is:

[tex]P(X \geq 2) = 1 - P(X < 2)[/tex]

In which

[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{6,0}.(0.9)^{0}.(0.1)^{6} = 0.000001[/tex]

[tex]P(X = 1) = C_{6,1}.(0.9)^{1}.(0.1)^{5} = 0.000054[/tex]

[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.000001 + 0.000054 = 0.000055[/tex]

Then

[tex]P(X \geq 2) = 1 - P(X < 2) = 1 - 0.000055 = 0.999945[/tex]

0.999945 = 99.9945% probability that at least two of the alarms are triggered.

Answer:

y= -6/7

Step-by-step explanation:

.............. I did it, trust me

Answer:

its 2/3 because if u divied the width u get that

Step-by-step explanation:

you welcome i tried

Answer:

Robert had 78 coins or c=78

Step-by-step explanation:

The volume of a hemisphere is given by :

[tex]V=\dfrac{2}{3}\pi r^3[/tex]

Taking differentiation,

[tex]\dfrac{dV}{dr}=2\pi r^2[/tex]

So,

[tex]dV=2\pi r^2\times dr[/tex]

Put r = 21 m and dr = 0.03 cm = 0.0003 m

[tex]dV=2\pi \times 21^2\times 0.0003\\\\dV=0.831\ m^3[/tex]

Hence, this is the required solution.

Answer:

375 divided by 3= x. 375/3= 125, the cube root is 5. X=5

Step-by-step explanation:

hope it helped

Answer:

1. 3x^3= 375  

2. =>x^3= 375/3

3. => x^3= 125

4. =>x^3=( 5)^3

5. =>x=5

Step-by-step explanation:

No explanation

Answer:

actually, the answers are "No, the slopes are not equal"

and "Yes, the slopes are negative reciprocals".

Reason: just did it!!!!

Answer:

"No, the slopes are not equal"

and "Yes, the slopes are negative reciprocals".

Step-by-step explanation:

Answer:

28.45

Step-by-step explanation:

33.04-1.75=31.29

31.29/1.10=28.45

Answer:

The answer is A

Step-by-step explanation: a net of a pyramid will always have a square and 4 triangles around it.

Answer:

a)

X      P[X]

0       5/14

1        15/28

2       3/28

b)

The expected value is 0.75

Step-by-step explanation:

Ok, we know that out of 8 cameras, 3 are defective.

So first let's find the probability for a camera randomly selected to be defective.

This is just the quotient between the number of defective cameras and the total number of cameras.

p = 3/8

then the probability that a camera is not defective is:

q = 5/8.

Ok, now we draw 2 cameras at random from the box.

We can define X as the number of defective cameras in these two drawn, we can have 3 possible values of X.

X = 0  (neither of the cameras is defective)

X = 1 (one of the cameras is defective)

X = 2 (both of the cameras is defective).

Let's find the probabilities for each case.

X = 0.

In this case, we first draw a non-defective camera, with a probability of:

P = 5/8.

The second camera drawn must be also non-defective, but now there are 4 non-defective cameras in the box and a total of 7 cameras (because one was already drawn).

Then the probability now is:

Q = 4/7

The joint probability is the product of the two individual probabilities:

P[0] = P*Q = (5/8)*(4/7) = (5/14)

X = 1

Here we have two cases:

the first is defective and the second is non-defective

the first is non-defective and the second is defective

So we just have a factor of 2, to consider both cases

Assuming the first case

Probability of drawing first a defective camera is equal to the quotient between the number of defective cameras  and the total number of cameras:

P = 3/8

For the second draw we want to get a non-defective camera, here the probability is equal to the number of non-defective cameras remaining (5) and the total number of cameras (7, because we drawn one)

Q = 5/7

The joint probability, taking in account the permutation, is

P[1] = 2*P*Q = 2*(3/8)*(5/7) = (15/28)

finally, for X = 2

This is the case where we draw two defective cameras, we can use a similar approach as the one used in the first case:

For the first camera:

P = 3/8

For the second camera:

Q = 2/7

Joint probability:

P[2] = (3/8)*(2/7) = 3/28

then we have the table:

X      P[X]

0       5/14

1        15/28

2       3/28

b)

The expected value for an event that has the outcomes:

{x₁, x₂, ..., xₙ}

Each one with the correspondent probability

{p₁, p₂, ..., pₙ}

is defined as:

EV = x₁*p₁ + x₂*p₂ + ... + xₙ*pₙ

Then in our case, the expected value is just:

EV = 0*P[0] + 1*P[1] + 2*P[2]

EV = 0  + 15/28  + 2*3/28

EV = (15 + 6)/28 = 21/28 = 0.75

Solution :

Given that there is only one set which can contain all the five correct answers. While guessing that I am likely to choose only one sequence of the answers as another, then the probability of getting all the five answers correct  is given by :

Given : X [tex]\sim[/tex] binomial [tex]$\left( 5 , \frac{1}{3} \right)$[/tex]

P (X = 5)

[tex]$= \ ^5C_5\left({\frac{1}{3}\right)^5\left(\frac{2}{3}\right)^0$[/tex]

= 0.00412

Thus the probability is 0.00412

Step-by-step explanation:

answer is in photo above

Answer:

-2/5

Step-by-step explanation:

Answer:

C = 16pi

Step-by-step explanation:

C = 2*pi*r  where r =8

C =2*pi*8

C = 16pi

Answer:

[tex]c = 16\pi[/tex]

Step-by-step explanation:

1: Substitute:

[tex]c = 2\pi \: r \\ r = 8 \\ c = 2\pi \times 8[/tex]

2: Solve the equation:

[tex]c = 2\pi \times 8[/tex]

Calculate:

[tex]c = 16\pi[/tex]

Answer:

[tex]v = \pi \: r {}^{2} \: \frac{h}{3} \: = \: 3.14 \times \: 2 {}^{2} \times \frac{9}{3} = 37.68[/tex]

Step-by-step explanation:

Answer:

The answer is "Option 2".

Step-by-step explanation:

Please find the complete question in the attached file.

When there is a mean value k in a set of data. Otherwise, we will assert with certainty that at least one of the values is k. They can't say anything at all about the maximum or even the minimum using knowledge only. Nevertheless, we know that certain numbers cannot be over and that all numbers cannot be below than mean. Mean also no value throughout the data set must be equal.

Answer:

z (max) =  17461.54  $

x₁   =  29.23 acres

x₂  =  0

x₃  =  3.07

Step-by-step explanation: INCOMPLETE QUESTION.

As the problem statement establishes:  "Each crop requires labor, fertilizer, and insecticide"  and information about quantities and availability does not exist. To build a model and that such model would be feasible I copy from the internet the following data. We assume the problem is to maximize the number of acres to plant with a maximum of profit ( we will use as profit the numbers 550  ;  350 ; 450 for  acres of corn, peanuts, and cotton)

Then z =  550*x₁  +  350*x₂  +  450*x₃    to maximize

                                            labor (h)      fertilizer ( tn)    Insecticide (Tn)

acres of corn         (x₁)               2                     4                        3

acres of peanut     (x₂)              3                     3                        2

acres of cotton      (x₃)              2                     1                         4

Availability         acres 40       120                120                      100

Constraints:

1) Size of the farm 120 acres

x₁  +  x₂   +   x₃   ≤   40

2) labor   120 h

2*x₁  +  3*x₂  +  2*x₃    ≤   120

3) Fertilizer  120 Tn

4*x₁  +  3*x₂  +  1*x₃      ≤   120

4) Insecticide 100 Tn

3*x₁   +  2*x₂  +  4*x₃     ≤  100

The Model is:

z =  550*x₁  +  350*x₂  +  450*x₃    to maximize

Subject to:

x₁  +  x₂   +   x₃   ≤   40

2*x₁  +  3*x₂  +  2*x₃    ≤   120

4*x₁  +  3*x₂  +  1*x₃      ≤   120

3*x₁   +  2*x₂  +  4*x₃     ≤  100

x₁    ≥   0  ;   x₂   ≥   0  ;   x₃   ≥   0

After 3 iterations using an on-line solver optimal solution is:

z (max) =  17461.54  $

x₁   =  29.23 acres

x₂  =  0

x₃  =  3.07

Answer:

its c

Step-by-step explanation:

Answer:

−(−4y−2+sin2(x))=0

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

that is the procedure above

The area of this circle with a radius of 13 inches is, C)530.66 inches

The circumference of a circle is the distance around the circle which is 2πr.

The diameter of a circle is the largest chord that passes through the center of a circle it is 2r.

A circle with center A is given and the length of the line segment(radius),

AB = AD = AC = 13 inches.

We know, The area of a circle is,

= πr².

= π(13)² sq in.

= 530.66 sq in.

We can also find the perimeter or the circumference of the circle by the formula 2πr,

= 2π×13.

= 26π.

= 81.64 inches.

learn more about circles here :
https://brainly.com/question/11833983

#SPJ7

Answer:

Therefore, 7/4 simplified to lowest terms is 7/4.

Answer:

16/3

Step-by-step explanation:

When multiplyin fractions by whole numbers, you can make the whole number a fraction by simply making the denominator 1, than you will multiply numerators by numerators and denominators by denominators, therefore

8 x 2 = 16

1 x 3 = 3

16/3

Answer:

that's my answer

Step-by-step explanation:

i hope it helps