The weight of a small starbucks coffee is a normally distributed random variable with a mean of 325 grams and a standard deviation of 10 grams. Find the weight that corresponds to each event (round your final answers to 2 decimal places)
a. Highest 10 percent
b. Middle 50 percent
Answer:
the weight that corresponds to Highest 10% = 337.8
the weight that corresponds to Middle 50 % lies between 318.26 and 331.74
Step-by-step explanation:
From the information provided for us:
we have the mean = 325
the standard deviation = 10
The objective is to find the weight that corresponds to each event i.e for event (a) , highest 10%
So;
The probability of P (Z > z) = 10%
Same as:
0.1 = 1 - P( Z < z)
P( Z < z) = 1 - 0.1
P( Z < z) = 0.9
From the standard normal tables for z;
P( Z < 1.28) = 0.9
z = 1.28
Similarly. from the z formula; we have:
[tex]z = \dfrac{X - \mu}{\sigma}[/tex]
[tex]z \times \sigma = X - \mu[/tex]
[tex]z \times \sigma + \mu= X[/tex]
[tex]X= z \times \sigma + \mu[/tex]
X = (1.28 × 10) + 325
X = 12.8 + 325
X = 337.8
Therefore, the weight that corresponds to Highest 10% = 337.8
b. the weight that corresponds to Middle 50 % can be computed as follows:
the region of z values at 0.50 lies between -0.674 and +0.674
from the z formula; we have:
[tex]z = \dfrac{X - \mu}{\sigma}[/tex]
[tex]z \times \sigma = X - \mu[/tex]
[tex]z \times \sigma + \mu= X[/tex]
[tex]X= z \times \sigma + \mu[/tex]
X = -0.674 × 10 + 325 and X = 0.674 × 10 + 325
X = - 6.74 + 325 and X = 6.74 + 325
X = 318.26 and X = 331.74
the weight that corresponds to Middle 50 % lies between 318.26 and 331.74
how to find y in this equation 11=12-14y
What is the degree of the monomial 5x^4? A. Degree 20 B. Degree 5 C. Degree 9 D. Degree 4
Answer:
Solution : Degree 4
Step-by-step explanation:
We only have one variable in this case, x. Therefore we can take the degree of this variable to be our solution, 4. As you can see x^4 will have a degree of 4, as that is the exponent present.
please help!!!! Use the graph to complete the statement. O is the origin. Ry−axis ο Ry=x: (-1,2)
A. (1, -2) B. (-1, -2) C. (2, -1) D. (-2, -1)
Answer: D. (-2, -1)
Step-by-step explanation:
Here we do two reflections to the point (-1, 2).
First, we do a reflection over the line x = y. Remember that a reflection over a line keeps constant the distance between our point and the given line, so we have that for a pint (x, y), the reflection over the line y = x is:
Ry=x (x, y) = (y, x)
so for our point, we have:
Ry=x (-1, 2) = (2, -1)
Now we do a reflection over the y-axis, again, a reflection over a line keeps constant the distance between our point and the given line, so if we have a point (x,y) and we do a reflection over the y-axis, our new point will be:
Ry-axis (x,y) = (-x, y)
Then in our case:
Ry-axis (2, -1) = (-2, -1)
The correct option is D.
Given that the trinomial x^2+ 11x + 28 has a factor of x +4, what is the other factor?
Answer:
the other factor is (x+7)
Step-by-step explanation:
Given x^2+11x+28
factor into
x^2+7x + 4x + 28
=x(x+7) + 4(x+7)
= (x+4)(x+7)
Answer: the other factor is (x+7)
7 is subtracted from the quotient of 48 divided by the sum of 5 and differences of 11 and 8
Write it out as an equation:
(48 /(5+(11-8))) -7
Simplify:
(48/(5+3))-7
(48/8)-7
6-7 = -1
The answer is -1
The volume of a sphere whose diameter is 18 centimeters is π cubic centimeters. If its diameter were reduced by half, its volume would be of its original volume.
Answer:
3053.5517 cm^3 ; 1/8
Step-by-step explanation:
Given the following :
Volume (V) of sphere = (4/3)πr^3 where r = radius
Diameter of sphere = 18 ; radius(r) = diameter / 2 = 18/2 = 9cm
V = (4/3) × π × 9^3
V = 1.3333 × π × 729
V = 3053.5517 cm^3
When diameter(d) is reduced to half
d = d/2
Volume (V1) of sphere with diameter 'd' =
V1 = (4/3)π(d/2)^3
Volume (V2) of sphere with diameter 'd' reduced to half, d = d/2, d/2 * 1/2 = d/4
V2 = (4/3)π(d/4)^3
V1 / V2 = [(4/3)π(d/2)^3] / [(4/3)π(d/4)^3]
V1 / V2 = (d/2)^3 / (d/4)^3
V1 / V2 = [d^3 / 2^3] / [d^3 / 4^3]
V1 / V2 = 8 / 64
V1 / V2 = 1 / 8
Answer:
first blank is 972
second blank is 1/8
yup
Step-by-step explanation:
Can somebody please tell me if it’s right? i’ll mark u the brainliest
Answer:
Yes, you are correct.
Step-by-step explanation:
You are substituting the measure of angle x as the measure of angle a since they are congruent to each other.
solve the equation 3), x=???? Please help me!!!
Answer:
x = {π/4, 7π/6, 5π/4, 11π/6} +2kπ . . . for any integer k
Step-by-step explanation:
[tex]\dfrac{\sin^3{x}}{1+\cos{x}}+\dfrac{\cos^3{x}}{1+\sin{x}}=\cos{2x}+2\cos{x}-1\\\\\dfrac{\sin{x}(1-\cos^2{x})}{1+\cos{x}}+\dfrac{\cos{x}(1-\sin^2{x})}{1+\sin{x}}=\cos^2{x}-\sin^2{x}+2\cos{x}-1\\\\\sin{x}(1-\cos{x})+\cos{x}(1-\sin{x})=\cos^2{x}-\sin^2{x}+2\cos{x}-1\\\\\sin{x}+\cos{x}-2\sin{x}\cos{x}=2\cos{x}-2\sin^2{x}\qquad\text{use $1=s^2+c^2$}\\\\\sin{x}+2\sin^2{x}-\cos{x}-2\sin{x}\cos{x}=0\\\\\sin{x}(1+2\sin{x})-\cos{x}(1+2\sin{x})=0\\\\(\sin{x}-\cos{x})(1+2\sin{x})=0[/tex]
This will have solutions where the factors are zero.
sin(x) -cos(x) = 0
Dividing by cos(x), we have ...
tan(x) -1 = 0
x = arctan(1) = π/4, 5π/4
1 +2sin(x) = 0
sin(x) = -1/2
x = arcsin(-1/2) = 7π/6, 11π/6
The four solutions in the interval [0, 2π] are x = {π/4, 7π/6, 5π/4, 11π/6}. Solutions repeat every 2π radians.
_____
Additional comment
We have made use of the factoring of the difference of squares:
(1 -a^2) = (1 -a)(1 +a)
and we have made use of the cosine double angle identity:
cos(2x) = cos(x)^2 -sin(x)^2
The "Pythagorean" identity for sine and cosine was used several times:
1 = sin(x)^2 +cos(x)^2
15 points! :( help asap!:(
(-1,-5)
(0,-3)
(4,5)
(9,15)
Answer:
(0,-3)
Step-by-step explanation:
You can plug in x and y into the equations to see if it works.
(-1,5)
2(-1)-(-5)=-2+5=3 Yes
(-1)+2(-5)=-1-10=-11 No
So (-1,5) Does NOT work.
(0,3)
2(0)-(-3)=0+3=3 Yes
(0)+2(-3)=0-6=-6 Yes
So (0,-3) DOES work.
I need 51-55 Thanks You :D no
Answer:
Below
Step-by-step explanation:
All figures are squares. The area of a square is the side times itself
Let A be the area of the big square and A' the area of the small one in all the 5 exercices
51)
● (a) = A - A'
A = c^2 and A' = d^2
● (a) = c^2 - d^2
We can express this expression as a product.
● (b) = (c-d) (c+d)
■■■■■■■■■■■■■■■■■■■■■■■■■■
52)
● (a) = A-A'
A = (2x)^2 = 4x^2 and A'= y^2
● (a) = 4x^2 - y^2
● (b) = (2x-y) ( 2x+y)
■■■■■■■■■■■■■■■■■■■■■■■■■■
53)
● (a) = A-A'
A = x^2 and A' = y^2
● (a) = x^2-y^2
● (b) = (x+y) (x-y)
■■■■■■■■■■■■■■■■■■■■■■■■■■
54)
● (a) = A-A'
A = (5a)^2 = 25a^2 and A' =(2b)^2= 4b^2
● (a) = 25a^2 - 4b^2
● (a) = (5a-2b) (5a+2b)
■■■■■■■■■■■■■■■■■■■■■■■■■■
55)
● (a) = A - 4A'
A = (3x)^2 = 9x^2 and A'= (2y)^2 = 4y^2
● (a) = 9x^2 - 4 × 4y^2
● (a) = 9x^2 - 16y^2
● (a) = (3x - 4y) (3x + 4y)
If BH = 108, find DE.
Answer:
BH= 108 --> 1st until 6th space
so, 108/6 = 18 for each space
DE...?
DE only use 1 space so the answers is 18 unit
I hope this helps^_^
A wave has a time period of 0.2 s Calculate the frequency of the wave.
Answer:
[tex]\huge\boxed{f = 5\ Hz}[/tex]
Step-by-step explanation:
Given:
Time period = T = 0.2 sec
Required:
Frequency = f = ?
Formula:
f = 1/T
Solution:
f = 1/0.2
f = 5 Hertz
Answer:
[tex] \boxed{\sf Frequency \ (f) \ of \ the \ wave = 5 \ Hz} [/tex]
Given:
Time Period (T) = 0.2 s
To Find:
Frequency (f) of the wave
Step-by-step explanation:
[tex] \sf Frequency (f) = \frac{1}{Time Period (T)} [/tex]
[tex] \sf f = \frac{1}{0.2} [/tex]
[tex] \sf f = \frac{1}{0.2} \times \frac{10}{10} [/tex]
[tex] \sf f = \frac{10}{2} [/tex]
[tex] \sf f = \frac{ \cancel{2} \times 5}{ \cancel{2}} [/tex]
[tex] \sf f = 5 \: Hz[/tex]
Find the value of x so that the function has the given value.
j(x)=−4/5x+7; j(x)=−5
x=
Answer:
x = 3
Step-by-step explanation:
j(x) = 4/5(-5) + 7
= -4 + 7
= 3
Answer:
15
Step-by-step explanation: -4/5 x has to be -12 because -12+7 equals 5. Since we want to figure out x, we have to flip -4/5 x to 4/5x which would change the -12 to 12. What is a fourth of 12? It is three. 12+3 equals 15. This is the first right answer on all of the internet for this question!
Can someone help pls it’s a multiple choice question
a/4 + 4 = 6 please helppppp!
━━━━━━━☆☆━━━━━━━
▹ Answer
a = 8
▹ Step-by-Step Explanation
a/4 + 4 = 6
Multiply both sides:
a + 16 = 24
Subtract 16 from both sides:
16 - 16 = a
24 - 16 = 8
a = 8
Hope this helps!
CloutAnswers ❁
━━━━━━━☆☆━━━━━━━
Answer:
a = 8
Step-by-step explanation:
a/4 + 4 = 6
Subtract 4 from each side
a/4 + 4-4 = 6-4
a/4 = 2
Multiply each side by 4
a/4 * 4 = 2*4
a = 8
Question 5 of 10
Which type of unemployment is characterized by a worker looking for a job
when there is no reason that he or she should not find one?
A. Structural unemployment
B. Seasonal unemployment
C. Frictional unemployment
D. Periodic unemployment
How do the number line graphs of the solutions sets of Negative 23 greater-than x and x greater-than-or-equal-to negative 23 differ?
Answer:
For "Negative 23 greater-than x" , highlight the left half of the number line starting at -23 and use a parenthesis ) on -23.
For "x greater-than-or-equal-to negative 23", highlight the right half of the number line starting at -23, and use a square bracket [ on -23.
Step-by-step explanation:
Start by locating the number -23 on the number line. Please see attached image to accompany the explanation.
In the first case: "Negative 23 greater-than x" , which is expressed mathematically as:
[tex]-23 >x[/tex]
notice that "x" has to be strictly smaller than the number -23, therefore those sought x values must reside to the left of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself shouldn't be considered as part of the set, that symbol is by convention a parenthesis ).
In the second case: "x greater-than-or-equal-to negative 23", which is expressed mathematically as:
[tex]x\geq -23[/tex]
notice that "x" has to be greater than or equal to the number -23, therefore those sought x values must reside to the right of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself should be considered as part of the set, that symbol is by convention a square bracket [.
Answer:
the answer is A
Step-by-step explanation:
What decimal number does point A on the number line below represent? A vertical number line is shown from negative 2.00 to 0 to positive 2.00.There are tick marks to show increments of 1 over 4. Only the whole numbers are labeled. Point A is plotted at the third tick mark below negative 1.00. 0.25 −0.25 1.75 −1.75
Answer: 0.25
Step-by-step explanation:
To find : decimal number represented by point A on the given number line.
Given: Vertical number line is shown from negative 2.00 to 0 to positive 2.00.There are tick marks to show increments of 1 over 4.
Point A is plotted at the third tick .
That means, Point A is marked at 1 over 4.
1 over 4 = [tex]\dfrac{1}{4}=0.25[/tex] [divide 1 by 4]
Hence, the point A represents 0.25 on the given number line.
Answer:
Step-by-step explanation:
Where is the picture
If (x + 2) is a factor of x3 – 19x – p, find the value of p. Help please
If [tex]x-a[/tex] is a factor of a polynomial [tex]P(x)[/tex] then, [tex]a[/tex] is its root.
So [tex]-2[/tex] is a root of [tex]x^3-19x-p[/tex]
[tex](-2)^3-19\cdot(-2)-p=0\\-8+38-p=0\\p=30[/tex]
Indi, Mark, and Tess each pick a slip of paper with a subtraction
expression written on it. The person holding the card with the
greatest value wins a prize. Who wins the prize?
Answer:
Tess wins the prize.
Step-by-step explanation:
[tex]\boxed{\text{Indi}: 2-3}[/tex]
[tex]\boxed{\text{Mark}: -7-(-4)}[/tex]
[tex]\boxed{\text{Tess}: -1-(-7)}[/tex]
The expression of Indi's card is 2 - 3 = -1
The expression of Mark's card is -7 - (-4) = -7+4= -3
The expression of Tess's card is -1 - (-7) = -1+7= 6
A geometric sequence has a common ratio of 22 and the 12th12th term is −12,288.−12,288.
What is the explicit rule that describes this sequence?
Answer:
Tₙ = -3(2)ⁿStep-by-step explanation:
The explicit rule for determining the nth term of a geometric sequence is expressed as Tₙ = arⁿ⁻¹ where;
a is the first term of the geometric sequence
r is the common ratio
n is the number of terms
If a geometric sequence has a common ratio of 2 and the 12th term is −12,288, then;
T₁₂ = ar¹²⁻¹
T₁₂ = ar¹¹
Given T₁₂ = -12,288 and r = 2, we can calculate the first term a
-12,288 = a2¹¹
a = -12,288/2¹¹
a = -12,288/2048
a = -6
Since the explicit rule for determining the nth term of a geometric sequence is expressed as Tₙ = arⁿ⁻¹, then for the sequence given, the explicit rule will be;
Tₙ = -6(2)ⁿ⁻¹
Tₙ = -6 * 2ⁿ * 2⁻¹
Tₙ = -6 * 2ⁿ * 1/2
Tₙ = -3(2)ⁿ
Hence the explicit rule that describes this sequence is Tₙ = -3(2)ⁿ
7.If 18, a, b, - 3 are in A.P., then a+b = ?
(1 Point)
1212
1515
1616
1111
please give the answer as fast as you can
please
Answer: 15
Step-by-step explanation:
General terms in AP
f, f+d, f+2d, f+3d, .... , where f= first term and d= common difference.
The given A.P. : 18, a, b, - 3
here, f= 18
[tex]f+d= a ...(i)\\\\f+2d = b ...(ii)\\\\f+3d= -3 ...(iii)\\\\[/tex]
Put f= 18 in (iii) ,
[tex]18+3d=-3\\\\\Rightarrow\ 3d= -3-18\\\\\Rightarrow\ 3d= -21\\\\\Rightarrow\ d=-7[/tex]
Put f= 18 and d= -7 in (i) and (ii) , we get
[tex]a=18+(-7)=11\\\\b=18+2(-7)\\\\\Rightarrow\ b=18-14\\\\\Rightarrow\ b=4[/tex]
Now, [tex]a+b= 11+4=15[/tex]
Hence, the correct answer is "15".
Hiiii can you help me ?
Answer:
842, 743, 394, 305, 836
Step-by-step explanation:
We arbitrarily chose the ones digit to start with as 2. (It must be 5 or less.) The other two digits are chosen by a random number generator, as shown in the attached.
The 5 three-digit numbers we chose are ...
842, 743, 394, 305, 836
Answer:
The only criteria the question gives are that there must be 5 numbers, and the numbers must have 3 digits. The ones digit in the numbers should go up by 1.
So, we can have 111, 112, 113, 114, and 115.
Hope this helps!
Briefly describe this graph of a Femis wheel.
Answer: This is a periodic relation.
Step-by-step explanation:
This is a periodic relation, that can be modeled with a sinusoidal relation, that relates the height as a function of time.
Then we can write this as h(t) = A*sin(C*t + F) + B
Where A is the amplitude, C is a constant that depends on the period, F is a phase shift, and B is the midpoint of the function.
2*A is the distance between the maximum height and the minimum height.
B is the middle height of the Femis Wheel.
Tim owns a clothing store where he designs pairs of shorts, s, and T-shirts, t.
He sells the shorts for $12 and the T-shirts for $8 each. Tim can work 18
hours a day, at most. It takes him 30 minutes to design a T-shirt and 45
minutes to design a pair of shorts. He must design at least 12 items each
day, but he cannot design more than 30 items in one day. Which set of
inequalities below represents this scenario?
A. s 2 12 + $ ss 30 + tiss 24-0.66t, s2; 0; t2 0
B. s> 12-tss 30 - t Ss 24 -0.66t, s 2 0; t> 0
O c. s? 12-ts? 30-tss 24 -0.66t, s 2 0;t20
D. S 2 12-tss 30-ts 24 -0.66t, s 20; t 0
Answer:
The correct option is;
B. s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t
Step-by-step explanation:
The given parameters are;
The number of T-shirts, t, and shorts, s, Tim must design a day = 12
The maximum number of T-shirts and shorts Tim can design a day = 30
The maximum number of hours Tim can work = 18 hours
Therefore, we have;
The number of shorts Tim designs in a day is ≥ The minimum number of T-shirts and shorts Tim must design a day less the number of T-shirts Tim designs
Which gives;
s ≥ 12 - t
Also the number of shorts Tim designs in a day is ≤ The maximum number of T-shirts, and shorts, Tim can design a day less the number of T-shirts Tim designs
Which gives;
s ≤ 30 - t
The number of 45 minute period for the design of shorts in 18 hours = 18×60/45 = 24
The fraction of 36 minutes in 45 minutes = 36/45 = 0.667
Therefore we have;
The number of shorts Tim designs in a day is ≤ The number of 45 minute periods in 18 hours less the number of 36 minutes periods used to design T-shirts
Which gives;
s ≤ 24 - 0.66·t
The correct option is s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t.
Answer:
B. s> 12-tss 30 - t Ss 24 -0.66t, s 2 0; t> 0
Step-by-step explanation:
Hope this helps!!
Where can parentheses be placed in the expression so that it has a value of 26? 4+2 ⋅ 14−3
Answer: 4+2 x (14-3)
Step-by-step explanation:
Shea made 11 of her first 17 free-throw attempts. What is the minimum number of her next 20 free-throw attempts that she must make for her overall success rate to be at least $80\%$? Express your answer to the nearest whole number.
Answer:
19 throws.
Step-by-step explanation:
For her success rate to be 80% in 37 throws she must make 0.8 * 37
= 29.6 throw - that is 30 to nearest throw.
So for the next 20 throws she must make 30 - 11 = 19 throws.
Solve the equation. 0.15 = y-0.45
Answer:
0.6
Step-by-step explanation:
0.6-0.45=0.15
The value of y from the given equation is 0.60.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
The given equation is 0.15=y-0.45.
The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.
Here, 0.15=y-0.45
y=0.15+0.45
y=0.60
Therefore, the value of y is 0.60.
To learn more about an equation visit:
https://brainly.com/question/14686792.
#SPJ2
What is the answer that = n?
Answer:
n = 5
Step-by-step explanation:
To start off, we know that whenever the bases are the same, their exponents are equal to each other. Therefore, since both of the numbers bases are the same (both are z), we know that they will be equal.
The n can be distributed to the [tex]z^2[/tex] so that it now reads to be:
[tex]z^2^n = z^{10}[/tex]
Exponents are equal, so:
2n=10
Divide the 2 on both sides:
n=5
Answer:
n =5
Step-by-step explanation:
z^2^n
We know that a^b^c = a^ (b*c)
z^(2n)
This is equal to z^10
Since the bases are the same, the exponents are the same
2n = 10
Divide by 2
2n/2 = 10/2
n = 5
What is the smallest positive integer $n$ such that $\frac{n}{n+101}$ is equal to a terminating decimal?
Answer:
n = 24
Step-by-step explanation:
Given the fraction:
[tex]$\frac{n}{n+101}$[/tex]
To find:
Smallest positive integer [tex]$n$[/tex] such that the fraction is equal to a terminating decimal.
Solution:
The rule that a fraction is equal to a terminating decimal states that, the denominator must contain factors of only 2 and 5.
i.e. Denominator must look like [tex]2^m\times 5^n[/tex], only then the fraction will be equal to a terminating decimal.
Now, let us have a look at the denominator, [tex]n+101[/tex]
Let us use hit and trial method to find the value of [tex]n[/tex] as positive integer.
n = 1, denominator becomes 102 = [tex]2 \times 3 \times 17[/tex] not of the form [tex]2^m\times 5^n[/tex].
n = 4, denominator becomes 105 = [tex]5 \times 3 \times 7[/tex] not of the form [tex]2^m\times 5^n[/tex].
n = 9, denominator becomes 110 = [tex]2 \times 5 \times 11[/tex] not of the form [tex]2^m\times 5^n[/tex].
n = 14, denominator becomes 115 = [tex]5 \times 23[/tex] not of the form [tex]2^m\times 5^n[/tex].
n = 19, denominator becomes 120 = [tex]5 \times 3 \times 2^3[/tex] not of the form [tex]2^m\times 5^n[/tex].
n = 24, denominator becomes 125 = [tex]2^0 \times 5 ^3[/tex] It is of the form [tex]2^m\times 5^n[/tex].
So, the answer is n = 24