The surface area of a sphere is 4πr2, where r is the radius of the sphere. The cost of a sphere is 2 per square foot, so the cost of a sphere with radius r is 8πr2. Selim can spend 20 per sphere, so he can purchase a sphere with radius r such that 8πr2≤20. This inequality can be solved for r to get r≤8π20=2π5. The diameter of a sphere is 2r, so the maximum diameter of the spheres Selim can purchase is 22π5=10π≈3.162 feet.
Amir is sorting his stamp collection. he made a chart of the fraction of stamps from each country in his collection. 7/12 of Amir's stamps are either from either Morocco or Spain.
Amir is sorting his stamp collection. He made a chart of the fraction of stamps from each country in his collection. 7/12 of Amir's stamps are either from either Morocco or Spain. The long answer to this question is given below:Answer:7/12 of Amir's stamps are either from Morocco or Spain.
5/12 of his stamps are from Spain and the remaining 2/12 of his stamps are from Morocco. The denominator of the given fraction is 12. Therefore, the numerator of the fraction represents the number of stamps from either Morocco or Spain. Let's consider the given fraction; 7/12The numerator of this fraction represents the number of stamps from either Morocco or Spain. Let S be the number of stamps from Spain.
Let M be the number of stamps from Morocco. Using the given information, we have: S + M = 7/12..... (1)Also, S/12 represents the fraction of stamps from Spain and 2/12 represents the fraction of stamps from Morocco. We can represent the number of stamps from Spain and Morocco in the following manner: S = 5/12 and M = 2/12Let's substitute these values in equation (1).We get:5/12 + 2/12 = 7/12Hence, 7/12 of Amir's stamps are either from either Morocco or Spain. Out of the 7/12 of the stamps, 5/12 are from Spain, and the remaining 2/12 are from Morocco.
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Kyle Lowry shoots a basketball towards the net, hoping to make a 3 pointer. The ball reaches its highest point of 12 m above the ground 0.5 s after it is released from his hands. The ball lands on the ground after 1.3 seconds. Determine an equation in vertex form that models the height of the basketball above the ground versus time. Include a sketch with your solution.
We are to determine an equation in vertex form that models the height of the basketball above the ground versus time. We can determine this using the formula:h(t) = -16t² + vt + h₀
We are given that the basketball reaches its highest point of 12 m above the ground 0.5 s after it is released from his hands. Thus, the initial height is:h₀ = 12 mWe are also given that the ball lands on the ground after 1.3 seconds. Thus, the time it took for the ball to reach the ground is:t = 1.3 sLet's find the initial vertical velocity using the information that the basketball reaches its highest point 0.5 seconds after it is released.
The vertical velocity of the basketball at its highest point is zero since it stops before coming down.So we know:
v + (-9.8)(0.5) = 0v = 4.9 m/s
Substituting the given information into the equation above, we obtain:
h(t) = -16t² + vt + h₀h(t) = -16t² + (4.9)t + 12
The vertex form of this equation can be determined by completing the square. To complete the square, we can add and subtract the square of half of the coefficient of t from the equation above
:h(t) = -16(t² - 0.30625t) + 12
To complete the square, we add and subtract
(0.30625/2)² = 0.02368164062:h(t) = -16(t² - 0.30625t + 0.02368164062 - 0.02368164062) + 12h(t) = -16(t - 0.153125)² + 12
The vertex of this equation is the point (0.153125, 12) and is the highest point of the basketball. The coefficient of t² is negative, which means that the graph of this equation is a downward-facing equation .
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The Indian currency has notes of ₹5
, ₹10
, ₹20
, ₹50
, and ₹100
. Vicky has ₹300
and Ricky has ₹260
. Both of them have notes of the same denominations.
What denominations of notes can they have? Write in increasing order.
PLEASE PLEASE TRY TO GIVE ME THE ANSWER AS QUICK AS POSSIBLE PLEASE FRIENDS PLEASE!
The possible denominations of notes that Vicky and Ricky can have, in increasing order, are:
Vicky: ₹50, ₹100
Ricky: ₹10, ₹20, ₹50, ₹100
To determine the possible denominations of notes that Vicky and Ricky can have, we need to find combinations of notes that add up to their respective amounts.
Let's consider Vicky first. With ₹300, the possible combinations of notes are:
3 number of notes of ₹100 (₹100 + ₹100 + ₹100)
1 note of ₹100 and 2 notes of ₹100 (₹100 + ₹100 + ₹100)
two notes of ₹100 and 5 notes of ₹50 (₹100 + ₹100 + ₹50 + ₹50 + ₹50 + ₹50 + ₹50)
Now let's consider Ricky. With ₹260, the possible combinations of notes are:
2 notes of ₹100 and 3 notes of ₹20 taking their sum (₹100 + ₹100 + ₹20 + ₹20 + ₹20)
1 note of ₹100, 3 notes of ₹50, and 1 note of ₹10 (₹100 + ₹50 + ₹50 + ₹50 + ₹10)
2 notes of ₹100, 2 notes of ₹20, and 1 note of ₹10 (₹100 + ₹100 + ₹20 + ₹20 + ₹10)
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If f(x)=x-1/3 and g(x)=3x+1 what is (f times g)(x)?
3x+1
x-3
3x
x
The expression (f times g)(x) represents the product of the functions f(x) and g(x). In this case, f(x) = x - 1/3 and g(x) = 3x + 1. To find the product, we substitute g(x) into f(x) and simplify the expression.
When we substitute g(x) into f(x), we get:
(f times g)(x) = f(g(x)) = f(3x + 1)
Now, substituting the expression for f(x) into f(g(x)), we have:
f(g(x)) = (3x + 1) - 1/3
Simplifying further, we combine like terms:
= 3x + 1 - 1/3
Thus, the product of f(x) and g(x), (f times g)(x), simplifies to:
(f times g)(x) = 3x + 1 - 1/3
(f times g)(x) equals 3x + 1 - 1/3.
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The area of a rectangle is 384 square inches and length is 8 inches greater than width. What are the dimensions
The dimensions of the rectangle are 16 inches in width and 24 inches in length.
Let's assume the width of the rectangle is x inches. According to the problem, the length is 8 inches greater than the width, so the length can be represented as (x + 8) inches.
The formula for the area of a rectangle is length multiplied by width. In this case, the area is given as 384 square inches. So, we can set up the equation:
Length * Width = Area
(x + 8) * x = 384
Expanding the equation:
x^2 + 8x = 384
Rearranging the equation to solve for x:
x^2 + 8x - 384 = 0
We can solve this quadratic equation by factoring or using the quadratic formula. Factoring it, we find:
(x - 16)(x + 24) = 0
So, x = 16 or x = -24.
Since dimensions cannot be negative, we discard the negative solution. Therefore, the width of the rectangle is 16 inches.
Substituting this value back into the equation for the length:
Length = x + 8 = 16 + 8 = 24 inches
Hence, the dimensions of the rectangle are 16 inches in width and 24 inches in length, which gives an area of 384 square inches.
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A force of 80. Newtons pushes a 50. -kilogram object across a level floor for 8. 0 meters. The work done is
The work done is 400.0 Joules A force of 80 Newtons pushes a 50-kilogram object across a level floor for 8.0 meters.
To find the work done, we can use the formula:work = force x distance x cos(theta)where force is 80 N, distance is 8.0 m, and theta is the angle between the force and the displacement. Since the force is applied in the direction of motion, theta is 0° and cos(0°) is 1.
we can simplify the formula as:work = force x distance x cos(theta)work = 80 N x 8.0 m x cos(0°)work = 640.0 JHowever, we need to check the units of our answer to make sure they are in Joules (J). The units of force are Newtons (N), the units of distance are meters (m), and the units of cos(theta) are dimensionless. Therefore, our answer is in Joules (J).So, the work done is 640.0 Joules.
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_ questions can only be answered in your head
A- random
B- on-the-page
C-out-of-left-field
D- From-my-brain
Random questions can be solved in your head. option A
What is random questions?In common usage, randomness is the apparent or actual lack of pattern or predictability in information.
A random sequence of events, symbols or steps often has no order and does not follow an intelligible pattern or combination. Individual random events are, by definition, unpredictable, but if the probability distribution is known, the frequency of different outcomes over repeated events (or "trials") is predictable
A random question has no particular pattern therefore it can be asked any how.
Therefore, we can conclude that random questions can only be answered in your heard with any research.
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The first side of a triangle measures 5 in. less than the second side, the third side is 3 in. more than the first side, and the perimeter is 17 in. Set up an equation that relates the sides of the triangles in terms of the perimeter of the triangle.
All the sides of the triangles in terms of the perimeter of the triangle are,
The value of second side = 3.33 in.
The value of first side = 1.67 in.
And, The value of third side = 1.33 in.
We have,
The first side of a triangle measures 5 in. less than the second side, the third side is 3 in. more than the first side, and the perimeter is 17 in.
Let us assume that,
The value of second side = x
Hence, The value of first side = x - 5
And, The value of third side = 3 + (x - 5) = x - 2
So, We get;
x + (x - 5) + (x - 2) = 17
3x - 7 = 17
3x = 17 - 7
x = 10/3
x = 3.33
Therefore, All the sides of the triangles in terms of the perimeter of the triangle are,
The value of second side = 3.33 in.
Hence, The value of first side = 3.33 - 5 = 1.67 in.
And, The value of third side = 3 + (x - 5) = 3.33 - 2 = 1.33 in.
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B.
zoom in
Find the value of the variables for
which ABCD must be a parallelogram.
~ 3x
X
3
3y
3y
D
21
Required
X =
?/1
I
22
Required
y =
?/1
.
D
Given a quadrilateral ABCD, with the sides AB and DC parallel and equal in length. Let us denote angle BAD as ∠α and angle ADC as ∠β. Now, we have to find the values of the variables x and y such that ABCD is a parallelogram.
Parallelogram has a pair of parallel sides. So, we have AB ∥ CD. It is given that ∠α = ∠β and AB = CD. So, by angle-angle-side rule, the two triangles ABD and DCA are congruent.
In triangle ABD, we have:∠DAB = 180° - ∠α = 180° - ∠β (as ∠α = ∠β)⇒ ∠DAB + ∠CDA = 180° (linear pair of angles)⇒ ∠CDA = ∠β.In triangle DCA, we have:∠CDA = ∠β (as obtained above)⇒ ∠CAD = ∠α (as ∠α = ∠β)⇒ ∠BDC = 180° - ∠α = 180° - ∠β (linear pair of angles)⇒ ∠BDC = ∠DAB.In quadrilateral ABCD, the adjacent angles are supplementary. So, we have:∠BDC + ∠BCD = 180° (adjacent angles are supplementary)⇒ ∠DAB + ∠BCD = 180° (as ∠BDC = ∠DAB)⇒ ∠BCD = 180° - ∠DAB.In triangle ACD, we have:∠C = ∠C (common)⇒ ∠CAD + ∠BCD = 180° (angles of a triangle add up to 180°)⇒ ∠α + (180° - ∠DAB) = 180°⇒ ∠α + ∠β = 180°.
Now, we can solve for x and y.In triangle ABD, we have:AB = BD⇒ 3x = 21 - x⇒ 4x = 21⇒ x = 21/4.In triangle DCA, we have:CD = DA⇒ 3y = 22 - y⇒ 4y = 22⇒ y = 11/2. Therefore, the value of x is 21/4 and the value of y is 11/2.
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What objects and activities foster a child's
ability to meet their basic needs at Level 1?
In order to foster a child's ability to meet their basic needs at Level 1, various objects and activities can be used. Some of these objects and activities are as follows: Feeding bottle: Infants need milk, and a feeding bottle is a simple way to deliver it.
Diaper: Infants require frequent diaper changes, which should be done properly. Clothing: Infants need comfortable clothing that is easy to change. Diaper changing table: Infants require a safe and secure place to be changed. Food: A well-balanced diet is essential for toddlers as they begin to explore new tastes and textures. Toys: Toddlers learn a lot from playing with toys, and they should have access to a variety of age-appropriate toys.
Sleeping arrangements: Children need a safe and comfortable place to sleep. Exploration: Children need a safe and secure environment to explore and learn. They need to be allowed to explore and learn at their own pace. Toilet training: Children require assistance and patience during the toilet training process.
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Explain the process of solving a system of equations using substitution
One variable, from either of the equations, the subject of that equation and substitute it in the other equation.
We have,
To describe the process of solving a system of equations using substitution.
Now,
For any given system of linear equations, we use a method called substitution method for solving the equations.
We can make one variable, from either of the equations, the subject of equation and substitute it in the other equation.
This way, we get to find the value of the remaining variable and next we substitute this value in one of the equations to get the value of the variable left.
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5. If two angles
are not adjacent, then they do not form
a linear pair.
Converse statement
inverses statement
Contrapositive statement
conditional statement
The given statement describes a relationship between two angles that are not adjacent, stating that they do not form a linear pair. The different types of logical statementsstatements from this statement are the converse statement, inverse statement, contrapositive statement, and conditional statement.
Converse statement: The converse of a conditional statement switches the hypothesis and the conclusion. In this case, the converse statement would be: If two angles do not form a linear pair, then they are not adjacent.
Inverse statement: The inverse of a conditional statement negates both the hypothesis and the conclusion. The inverse statement would be: If two angles are adjacent, then they form a linear pair.
Contrapositive statement: The contrapositive of a conditional statement switches and negates both the hypothesis and the conclusion. The contrapositive statement would be: If two angles form a linear pair, then they are adjacent.
Conditional statement: The original statement itself is the conditional statement. It follows the form: If two angles are not adjacent, then they do not form a linear pair.
These different logical statements provide alternative ways to express the relationship between angles that are not adjacent and their formation of a linear pair.
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Examine the reasons why so many artists were seeking a different world
During the late 19th and early 20th centuries, many artists were seeking a different world due to several reasons.
1. Social and Political Changes During the late 19th and early 20th centuries, social and political changes were occurring at a rapid pace. The industrial revolution led to the growth of cities, which, in turn, caused a breakdown in traditional society. As a result, many artists were seeking a different world that was more in line with their ideals.2. Technological Advancements Inventions such as the telegraph and the telephone enabled artists to communicate with one another and share their ideas. Artists were inspired by new technologies and used them to create new forms of art.3. World War I World War I was a traumatic event that had a significant impact on the artistic community. Many artists were disillusioned by the horrors of war and sought to create a new world that was free from conflict and violence.4. Industrialization and Urbanization .The growth of industry and the shift from rural to urban life had a profound effect on the artistic communit.5. Romanticism .Romanticism was a cultural movement that emphasized emotion, imagination, and individualism. Many artists were inspired by the romantic ideal and sought to create works that expressed their innermost feelings and thoughts. The movement emphasized the importance of nature, beauty, and the sublime, which were seen as antidotes to the dehumanizing effects of industrialization and urbanization.
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Santos takes the train into the city five days a week for work. For one work week he kept track of how many minutes the train ride was : 48,51,48,48,50
Calculate the mean median range in the range of the train ride times for the week
The mean train ride time for the week was 49.4 minutes, with a median of 48 minutes. The range of the train ride times was 3 minutes.
The mean, median, and range of Santos' train ride times for the week were as follows:
Mean: 49.4 minutes
The mean is calculated by adding up all the values and dividing the sum by the total number of values. In this case, the sum of the train ride times (48 + 51 + 48 + 48 + 50) is 245 minutes. Dividing this sum by the total number of days (5), we get the mean of 49.4 minutes.
Median: 48 minutes
The median is the middle value in a sorted list of numbers. To find the median, we arrange the train ride times in ascending order: 48, 48, 48, 50, 51. Since there is an odd number of values, the middle value is the median. In this case, the median is 48 minutes.
Range: 3 minutes
The range is the difference between the largest and smallest values in a set. To calculate the range, we subtract the smallest value (48 minutes) from the largest value (51 minutes). In this case, the range of the train ride times for the week is 3 minutes.
In summary, the mean train ride time for the week was 49.4 minutes, with a median of 48 minutes. The range of the train ride times was 3 minutes. These metrics provide insights into the average, central tendency, and variability of Santos' train rides throughout the week.
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Ms. Seema’s annual salary is Rs 288000. Her annual savings is Rs 72000. The ratio of her annual spending to her annual saving is ____________ *
1 : 3
2 : 3
3 : 1
None of these
We have to find the ratio of Ms Seema's annual spending to her annual savings given that Ms. Seema's annual salary is Rs 288000 and her annual savings is Rs 72000.
The first step is to determine the annual spending of Ms. Seema.Subtracting the annual savings of Ms. Seema from her annual salary, we can determine her annual spending. Annual spending = Rs 288000 - Rs 72000 = Rs 216000We now know that Ms. Seema's annual spending is Rs 216000 per year and her annual savings is Rs 72000 per year.
We can now compute the ratio of her annual spending to her annual savings. Annual spending : Annual savings= 216000 : 72000= 3 : 1Therefore, the ratio of Ms. Seema's annual spending to her annual savings is 3 : 1. It implies that her annual spending is three times the annual savings.In conclusion, the ratio of Ms. Seema's annual spending to her annual savings is 3 : 1.
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Derek had two lights, a blue light, and a green light. The blue light flashed every 4 seconds and the green light flashed every 7 seconds. If Derek turned both lights on at the same time, how many seconds will it take for both lights to flash together at the same time?
Both lights will flash together at the same time after 28 seconds.
To find the amount of time it will take for both lights to flash together at the same time,
we need to find the least common multiple (LCM) of the two flashing times, 4 and 7.
The first few multiples of 4 are: 4, 8, 12, 16, 20, 24, 28, ...
The first few multiples of 7 are: 7, 14, 21, 28, 35, ...
The least common multiple of 4 and 7 is 28.
Therefore, both lights will flash together at the same time after 28 seconds.
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step by step explanation for expressions d and e Thank you loads!!!
Answer:
Step-by-step explanation:
D)
[tex]\frac{4\sqrt{b} }{\sqrt{3}-b }[/tex] > in order to get rid of root on bottom like this, you
need to multiply top and bottom by conjugate
√3 +b
[tex]=\frac{4\sqrt{b} }{\sqrt{3}-b }\frac{\sqrt{3}+b}{\sqrt{3}+b}[/tex] > Distribute on top and FOIL bottom
[tex]=\frac{4\sqrt{3b}+4b\sqrt{b} }{3 -b^{2} }[/tex] >This is simplified, you cannot combine anything else
E)
[tex]\frac{3\sqrt{a^{2} } } {\sqrt{3} } / 2a^{\frac{3}{2} }[/tex] >√a² = a
[tex]=\frac{3a } {\sqrt{3} } / 2a^{\frac{3}{2} }[/tex] >Division of fraction keep change flip
[tex]=\frac{3a } {\sqrt{3} } * \frac{1}{2a^{\frac{3}{2}} }[/tex] >Because 2a is not in parenthesis 3/2 exp.
is only for a
[tex]=\frac{3a } {\sqrt{3} } * \frac{1}{2\sqrt{a^{3} } }[/tex] > You can make 1 set of a² so 1 comes out but 1 stays
[tex]=\frac{3a } {\sqrt{3} } * \frac{1}{2a\sqrt{a } }[/tex] >put like items under root
[tex]=\frac{3a } {2a\sqrt{3a} }[/tex] >multiply top and bottom by root
[tex]=\frac{3a } {2a\sqrt{3a} }*\frac{\sqrt{3a}}{\sqrt{3a}}[/tex] >multiply
[tex]=\frac{3a\sqrt{3a} } {2a(3a)} }[/tex] >3a cancels
[tex]=\frac{\sqrt{3a} } {2a} }[/tex] >This is simplified
A mixture of raisins and almonds is to be sold for $2.55/kg. Almonds sell for $9/kg , and raisins sell for $1.50/kg. If a 20kg mixture, in total, is to be created, how many kg of this mixture should be almonds?
To create a 20kg mixture of raisins and almonds that sells for $2.55/kg, the amount of almonds in the mixture should be 15kg.
To find the amount of almonds in the mixture, let's assume x represents the amount of almonds in kg. Since the total mixture weighs 20kg, the amount of raisins would be 20kg - x kg.
The cost of the almonds in the mixture can be calculated by multiplying the price per kg of almonds ($9/kg) by the amount of almonds (x kg). Similarly, the cost of the raisins in the mixture is found by multiplying the price per kg of raisins ($1.50/kg) by the amount of raisins (20kg - x kg).
According to the given condition, the total cost of the mixture is $2.55/kg multiplied by the total weight of the mixture (20kg).
Setting up the equation:
($9/kg * x kg) + ($1.50/kg * (20kg - x kg)) = $2.55/kg * 20kg
Simplifying and solving the equation, we find x = 15kg.
Therefore, 15kg of the mixture should be almonds.
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Two number cubes, each with faces labeled 1 through 12, are rolled at the same time.
Enter the probability that both number cubes land with the number 11 facing up in one roll.
Based on the information, the probability is 1/144, or approximately 0.0069.
How to calculate the probabilityEach number cube has 12 possible outcomes, as there are 12 faces labeled from 1 to 12.
The probability of rolling an 11 on one number cube is 1 out of 12, as there is only one face labeled 11 out of the 12 possible outcomes.
Since the two number cubes are rolled simultaneously, the total number of possible outcomes is the product of the possible outcomes for each cube, which is 12 * 12 = 144.
The number of favorable outcomes, in this case, is 1, as both number cubes need to show 11.
Therefore, the probability that both number cubes land with the number 11 facing up in one roll is:
Number of favorable outcomes / Total number of possible outcomes
= 1 / 144
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Quadrilateral ABCD is congruent to quadrilateral
AMCG. Determine mZDAB.
12 cm
M
28
620
C
А
B
13 су
10 cm
16 cm
810
D
To determine the measure of angle DAB, we need to use the congruence of quadrilaterals ABCD and AMCG.
Quadrilateral ABCD is congruent to quadrilateral AMCG.
Since the two quadrilaterals are congruent, their corresponding angles are equal. Therefore, we can write:
m∠DAB = m∠MAC
However, the measure of angle MAC is not given in the given information. Therefore, without additional information, we cannot determine the exact measure of angle DAB.
The options provided in the question do not correspond to the measure of angle DAB. Therefore, the correct answer cannot be determined based on the given information.
It is important to have additional information about the measures of angles or the side lengths in order to determine the measure of angle DAB accurately.
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Maggie is working at a store that pays by the hour and by commission (pay for how much you sell). Maggie wants to go this weekend to the lake with her friends but she needs to make at least $225 today. She gets paid $15 per hour plus $25 for every sale she makes. What are all the possible values of the number of sales that Maggie can make to go to the lake if she is scheduled to work from 8am until 4pm?
Maggie can make anywhere from 5 to 4 sales to earn at least $225 and go to the lake with her friends.
Maggie gets paid $15 per hour plus $25 for every sale she makes. The number of sales she makes can be represented by x.
In order to calculate Maggie's earnings in terms of commission, we can use the equation 25x.
To calculate Maggie's earnings in terms of hourly pay, we can use the equation 15(8), since she works from 8am until 4pm, which is 8 hours. This simplifies to 120.The total amount Maggie earns can be represented by the equation:
Total earnings = 25x + 120
To find the minimum number of sales Maggie needs to make to earn at least $225, lets set up the inequality:
25x + 120 ≥ 225
Subtracting 120 from both sides, we get:
25x ≥ 105
Dividing both sides by 25, we get:
x ≥ 4.2
Maggie cannot make a fraction of a sale, so we can round up to find the minimum number of sales she needs to make, which is 5 sales.
To find the maximum number of sales Maggie can make, lets consider the fact that she is scheduled to work from 8am until 4pm, which is 8 hours. If she makes 0 sales, she will earn $120 (her hourly pay for 8 hours of work).
To find the maximum number of sales, we can set up the equation:25x + 120 ≤ 225
Subtracting 120 from both sides, we get:
25x ≤ 105
Dividing both sides by 25, we get:
x ≤ 4.2
Maggie cannot make a negative number of sales, so we can round down to find the maximum number of sales she can make, which is 4 sales.
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The possible values of the number of sales that Maggie can make to go to the lake are 5 and 4.
Given:
Maggie gets paid $15 per hour plus $25 for every sale she makes.
She needs to make at least $225 today.
She is scheduled to work from 8 am until 4 pm.
To find:
All the possible values of the number of sales that Maggie can make to go to the lake.
Solution:
Let's consider x to be the number of sales that Maggie makes.
To determine the minimum amount she needs to earn:
Her hourly wage for 8 hours of work = $15 × 8 = $120
Total earnings that she needs = $225 - $120 = $105
If y is the number of sales she needs to make to earn $105, then:
$25y = $105
Dividing both sides by $25, we get:
y = 4.2
This means she needs to make at least 5 sales.
Let's calculate the maximum number of sales that she can make. If she has to earn $240 for 8 hours of work:
Total earnings required = $240 - $120 = $120
$25y = $120
Dividing both sides by $25, we get:
y = 4.8
This means the maximum number of sales she can make is 4.
As such, the possible values of the number of sales that Maggie can make to go to the lake are 5 and 4.
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A ship’s sonar detects a submarine 880 feet below a point on the ocean’s surface 1450 ft dead ahead of the ship. To the nearest degree, find the angle x. A right triangle. Angle x is opposite to side with length 880 feet. Another side is 1450 feet. The hypotenuse is not labeled. A. 59º b. 37º c. 31º d. 53º.
The measure of the angle x is 59 degrees. Option A
How to determine the valuesThe different trigonometric identities are listed as;
sinecosinetangentcotangentsecantcosecantFrom the information given, we have that;
The measure of the adjacent is 880 feet
The opposite side is the ocean's surface = 1450 feet
The angle is x
Using the tangent identity, we have;
tan θ = opposite/adjacent
Now, we have to substitute the values, we get;
tan x = 1450/880
Divide the values, we get;
tan x = 1. 6477
Take the tangent inverse, we get;
x = 59 degrees
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A mark of humility is a willingness to resolve differences. How does the Apostle Paul show humility in Acts 15:36-39 and 2 Timothy 4:11?
The Apostle Paul demonstrates humility in Acts 15:36-39 and 2 Timothy 4:11 through his willingness to resolve differences. In these passages, Paul's actions and attitudes reflect his humility and his desire for reconciliation and unity among believers.
In Acts 15:36-39, Paul and Barnabas had a disagreement regarding taking John Mark on a missionary journey. Barnabas wanted to bring John Mark along, but Paul did not because John Mark had previously left them on a previous journey. Despite the disagreement, Paul shows humility by accepting Barnabas' decision and allowing him to take John Mark as his companion, while Paul chooses Silas as his own companion. This act demonstrates Paul's willingness to prioritize unity and reconciliation over personal preferences.
In 2 Timothy 4:11, Paul shows humility by reconciling with John Mark. He requests Timothy to bring Mark with him because Paul considers Mark to be helpful in his ministry. This shows a change in Paul's attitude towards Mark, indicating that he was willing to put aside any past differences and extend forgiveness and acceptance. Paul's willingness to reconcile and work alongside Mark reveals his humility and his understanding of the importance of resolving differences for the sake of the Gospel and the unity of believers.
Overall, both passages highlight Paul's humility through his willingness to resolve differences and prioritize unity, showcasing his desire for reconciliation and harmony among fellow believers.
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Underline the prepositional phrases
i) I was proven innocent by virtue of the law.
ii) Don’t leave without your coat
i) I was proven innocent by virtue of the law.
ii) Don’t leave without your coat.
In sentence (i), the prepositional phrase "by virtue of" introduces the reason or cause for being proven innocent. It indicates that the law is the basis or foundation for the proof.
In sentence (ii), the prepositional phrase "without your coat" indicates the absence or lack of something. It specifies that the action of leaving should not occur unless the person has their coat with them.
Prepositional phrases consist of a preposition (such as "by," "of," or "without") followed by a noun or pronoun object. They provide additional information about location, time, manner, or other relationships in a sentence. Recognizing and understanding prepositional phrases helps in comprehending the structure and meaning of sentences.
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James copied a symbol on each of 12 equal-sized strips of paper. He put a dot on 2 of them, a dash on 2 of them, and a pound sign on 8 of them. Then, he put all the strips in a hat and pulled out 3 at random. How many different symbol combinations were possible?
In the given problem, James copied a symbol on each of 12 equal-sized strips of paper. He put a dot on 2 of them, a dash on 2 of them, and a pound sign on 8 of them. Then, he put all the strips in a hat and pulled out 3 at random. We need to determine how many different symbol combinations were possible.
First, we can determine the total number of combinations possible. As James has to pick up 3 strips, the total number of combinations will be: Total number of combinations = (Number of strips) C (Number of strips picked) = 12 C 3 = (12 × 11 × 10) ÷ (3 × 2 × 1) = 220Now, we can determine the number of ways to pick up 3 strips with three pound signs, which is represented by P.P.P. We need to choose 3 strips from the 8 strips with the pound sign. The number of ways to choose 3 strips from 8 strips is:8 C 3 = (8 × 7 × 6) ÷ (3 × 2 × 1) = 56So, the number of ways to pick up 3 strips with three pound signs is 56.Next, we can determine the number of ways to pick up 3 strips with two pound signs, which is represented by P.P.x. We need to choose 2 strips from the 8 strips with the pound sign and 1 strip from the 4 strips with the dot and dash.
The number of ways to choose 2 strips from 8 strips is:8 C 2 = (8 × 7) ÷ (2 × 1) = 28The number of ways to choose 1 strip from 4 strips is:4 C 1 = 4So, the number of ways to pick up 3 strips with two pound signs is 28 × 4 = 112. (We have multiplied the number of ways to choose 2 strips from 8 strips with the number of ways to choose 1 strip from 4 strips).Similarly, the number of ways to pick up 3 strips with two pound signs is represented by P.x.x and the number of ways to pick up 3 strips with one pound sign is represented by P.x.x. They can be calculated in the same way.So, the number of ways to pick up 3 strips with two pound signs (P.P.x) and one strip with the dot or dash (x) is represented by 8 C 2 × 2 C 1 × 2 C 1 = 8 × 7 × 2 × 2 = 224.The number of ways to pick up 3 strips with two pound signs (P.P.x) and one strip with the dot or dash (x) is represented by 8 C 1 × 2 C 2 × 2 C 1 = 8 × 1 × 2 = 16.The number of ways to pick up 3 strips with one pound sign (P.x.x) and two strips with the dot or dash (x.x) is represented by 8 C 1 × 2 C 1 × 2 C 1 = 8 × 2 × 2 = 32.The number of ways to pick up 3 strips with three dots or dashes (x.x.x) is represented by 2 C 3 = 0. (As there are only 2 strips with dot or dash).Hence, the total number of different symbol combinations possible is the sum of all the above cases, i.e.,Total number of different symbol combinations possible = P.P.P + P.P.x + P.x.x + P.x.x + P.x.x + x.x.x= 56 + 112 + 224 + 16 + 32 + 0= 440
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Las aspas de un ventilador de techo están girando alrededor de un eje fijo estas parten del reposo con aceleración angular constante en un tiempo están girando 10 revoluciones por segundo y dan 60 vueltas después Irán a 15 revoluciones por segundo
The question provides that the blades of a ceiling fan rotate around a fixed axis and begin to rotate with a constant angular acceleration such that they are rotating at 10 revolutions per second after a certain period of time.
After 60 turns, the fan will be rotating at 15 revolutions per second.
Solution:The given data is:Initial angular speed, ω₁ = 0 (since they start from rest)
Final angular speed, ω₂ = 15 revolutions/sec
Angular acceleration, α = constant
Number of revolutions for the first part, n₁ = 60
Number of revolutions for the second part, n₂ = (total revolutions) - (n₁) = (60 + 10) - 60 = 10 revolutions
Using the formula for the angular velocity, ω = ω₀ + αt
and the formula for the number of revolutions, n = ωt / 2π
We can find out the time required to reach a final speed of 15 rev/s as follows:15 = 0 + αt ⇒ t = 15 / α
The total time required to reach a speed of 15 rev/s would be the sum of the time required to reach a speed of 10 rev/s and the time required to reach 15 rev/s.t = t₁ + t₂ ⇒ t₂ = t - t₁
We can find the value of t₁ from the formula for the number of revolutions during the first part of the motion as follows:n₁ = ω₁t₁ / 2π0 = αt₁² / 2 + ω₁t₁ / 2π ⇒ t₁ = 0
Using the formula for the number of revolutions, we can find the value of t₂ as follows:n₂ = (ω₁t₂ + 1/2 αt₂²) / 2π ⇒ t₂ = 20/α
The value of α can be found by equating the two formulas for t₂ obtained above:
20/α = 15 / α + t₁⇒ α = 100 / 3 rad/s²
We can now substitute this value in the formulas for t and t₂ to find the times required to reach speeds of 10 and 15 rev/s respectively.t₁ = 0 s, t₂ = 60 / 3 = 20 s
Answer: The time required for the blades of the ceiling fan to rotate with a constant angular acceleration before rotating at 10 revolutions per second is 0 seconds and the time required to reach a speed of 15 revolutions per second is 20 seconds.
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A cylinder is 12 cm tall and has a diameter of 3 cmWhat is it's surface area?thx
The surface area of a cylinder can be calculated by adding the areas of its curved surface and its two bases.
Calculate the area of the curved surface: The curved surface area of a cylinder is given by the formula 2πrh,
where r is the radius and h is the height. In this case, the radius is half the diameter, so r = 3/2 cm. The height is 12 cm. Therefore, the curved surface area is[tex]2π(3/2)(12) cm².[/tex]
Calculate the area of the two bases: The base of a cylinder is a circle, so its area is given by the formula πr².
In this case, the radius is 3/2 cm. Therefore, the area of each base is π(3/2)² cm².
Add the area of the curved surface and the two bases to find the total surface area: Surface Area = Curved Surface Area + 2(Base Area).
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Ayako claims that there are centers of dilations through which a dilation of line n by a factor of 1. 5 leaves Line n unchanged. Determine whether each point below represents a center of dilation that supports Ayako's claim. Select Yes or No for each point
Points 1 and 3 are centers of dilation supporting Ayako's claim, as they lie on line n. Point 2 is not a center of dilation that supports the claim.
To determine whether each point represents a center of dilation that supports Ayako's claim, we need to understand the properties of dilation. Dilation is a transformation that changes the size of an object without altering its shape. The center of dilation is the fixed point about which the dilation occurs, and the scale factor determines the amount of change in size.
For a dilation of line n by a factor of 1.5 to leave line n unchanged, the center of dilation must lie on line n.
Let's evaluate each point:
1. Yes: If a point lies on line n, it can be a center of dilation that supports Ayako's claim.
2. No: If a point is not on line n, it cannot be a center of dilation that supports Ayako's claim.
3. Yes: If a point lies on line n, it can be a center of dilation that supports Ayako's claim.
In summary, point 1 and point 3 represent centers of dilation that support Ayako's claim, while point 2 does not. The center of dilation must be on line n to leave the line unchanged when dilated by a factor of 1.5.
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Someone help me do this
Answer:
I believe it's A
Step-by-step explanation:
What happens to the value of f(x) = log4x as x approaches [infinity]?.
As x approaches infinity, the value of the function f(x) = log4x approaches infinity as well. The logarithm function with a base greater than 1 increases without bound as its input increases, so the value of log4x becomes arbitrarily large as x becomes larger.
The logarithm function log4x represents the exponent to which the base 4 must be raised to obtain x. As x approaches infinity, the function evaluates the behavior of the logarithm for extremely large values.
In this case, as x becomes larger and larger, log4x increases without bound. This means that there is no finite limit or specific value that f(x) approaches as x approaches infinity. Instead, f(x) grows infinitely, indicating that the function's value becomes arbitrarily large as x becomes larger. Therefore, the value of f(x) = log4x approaches infinity as x approaches infinity.
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