World Languages High School

Choose the adverb and the adjective it modifies.

The donkey was carrying a fairly heavy load.

Adverb:

Adjective:
It’s language arts btw

Answers

Answer 1

In the sentence "The donkey was carrying a fairly heavy load," the adverb "fairly" modifies the adjective "heavy."

How to explain the information

In the sentence "The donkey was carrying a fairly heavy load," we have the adverb "fairly" modifying the adjective "heavy."

An adverb is a word that modifies or describes a verb, an adjective, or another adverb. In this case, the adverb "fairly" is modifying the adjective "heavy" by indicating the degree or extent to which the load is heavy. It suggests that the load is not extremely heavy, but still has a considerable weight.

The adverb "fairly" answers the question "to what extent" or "how much" the load is heavy. Without the adverb, the sentence would simply state that the donkey was carrying a "heavy load," leaving out the specific degree of heaviness. The inclusion of the adverb adds more information and provides a clearer picture of the load's weight.

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Related Questions

3-the-lamps are connected in parallel. The first lamp has a current of 2. A.


The second lamp has a voltage equal to 10V and a resistance equal to 6 Ohm. The


third-lamp has a current equal to 4A Find in this scheme the total voltage, the current


for all·lamps, the total resistance.

Answers

Total Voltage: 10V

Total Current: Approximately 7.67A

Total Resistance: 2 Ohm

How to solve for the volgtage and resistance

The total voltage in the circuit is equal to the voltage across any of the lamps. In this case, the second lamp has a voltage of 10V, so the total voltage in the circuit is 10V.

Current for all lamps (I):

Since the lamps are connected in parallel, the total current flowing through the circuit is the sum of the individual currents through each lamp.

The first lamp has a current of 2A, the second lamp's current is not given, and the third lamp has a current of 4A. To find the total current, we need to calculate the current through the second lamp.

Since the second lamp has a resistance of 6 Ohm and a voltage of 10V, we can use Ohm's Law (V = I * R) to find the current through the second lamp:

10V = I * 6 Ohm

I = 10V / 6 Ohm

I ≈ 1.67A

Now we can calculate the total current:

Total Current (I) = 2A (first lamp) + 1.67A (second lamp) + 4A (third lamp)

Total Current ≈ 7.67A

Total Resistance (R):

In a parallel circuit, the total resistance is calculated using the reciprocal of the sum of the reciprocals of the individual resistances.

The second lamp has a resistance of 6 Ohm, so the total resistance is:

1 / Total Resistance = (1 / 6 Ohm) + (1 / 6 Ohm) + (1 / 6 Ohm)

1 / Total Resistance = 3 / 6 Ohm

1 / Total Resistance = 1 / 2 Ohm

Total Resistance = 2 Ohm

To summarize:

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