Answer:
\n
Explanation:
readline() method is used to read one line from a file. It returns that line from the file.
This line from the file is returned as a string. This string contains a \n at the end which is called a new line character.
So the readline method reads text until an end of line symbol is encountered, and this end of line character is represented by \n.
For example if the file "abc.txt" contains the lines:
Welcome to abc file.
This file is for demonstrating how read line works.
Consider the following code:
f = open("abc.txt", "r") #opens the file in read mode
print(f.readline()) # read one line from file and displays it
The output is:
Welcome to abc file.
The readline() method reads one line and the print method displays that line.
Ann, a user, reports that she is no longer able to access any network resources. Upon further investigation, a technician notices that her PC is receiving an IP address that is not part of the DHCP scope. Which of the following explains the type of address being assigned?
A. Unicast address
B. IPV6
C. DHCP6
D. APIPA
Answer: APIPA
Explanation:
Automatic Private IP Addressing (APIPA) is a Windows based operating systems feature that allows a computer to assign itself automatically to an IP address even though there is DHCP server to perform the function.
From the information that has been provided in the question, we can see that the type of address that is used is APIPA.
Explain how Deep Packet Inspection works (DPI). How is this technology beneficial to Perimeter Security? Lastly, describe a scenario where the use of DPI may be considered a privacy concern.
Answer:
Answered below
Explanation:
Deep packet inspection is a kind of data processing that thoroughly inspects data sent over a computer network and acts on it by rerouting, logging or blocking it. Uses of DPI include;
To ensure that data is in the correct format, internet censorship, to check for malicious code, and also eavesdropping.
DPI uses port mirroring and optical splitter to acquire packets for inspection. It combines the functionality of an intrusion detection system and intrusion prevention system with a traditional stateful firewall.
DPI is therefore helpful in perimeter security by keeping unauthorized users out and at the same time protecting authorized users from attack. Privacy concerns have been raised over the inspection of content layers of internet protocols such as in the case of censorship and government regulations and control.
what level of security access should a computer user have to do their job?
Answer:
A computer user should only have as much access as required to do their job.
Explanation:
A computer user should not be able to access resources outside of their job requirement, as this poses a potential attack vector for an insider threat. By limiting the scope of resources to just what is needed for the user's specific job, the threat to the system or company can be mitigated with additional access control features for the computer user. Never allow permission higher than what are needed to accomplish the task.
Cheers.
Append newValue to the end of vector tempReadings. Ex: If newValue = 67, then tempReadings = {53, 57, 60} becomes {53, 57, 60, 67}.
#include
#include
using namespace std;
int main() {
vector tempReadings(3);
int newValue = 0;
unsigned int i = 0;
tempReadings.at(0) = 53;
tempReadings.at(1) = 57;
tempReadings.at(2) = 60;
newValue = 67;
/* Your solution goes here */
for (i = 0; i < tempReadings.size(); ++i) {
cout << tempReadings.at(i) << " ";
}
cout << endl;
return 0;
}
2.Remove the last element from vector ticketList.
#include
#include
using namespace std;
int main() {
vector ticketList(3);
unsigned int i = 0;
ticketList.at(0) = 5;
ticketList.at(1) = 100;
ticketList.at(2) = 12;
/* Your solution goes here */
for (i = 0; i < ticketList.size(); ++i) {
cout << ticketList.at(i) << " ";
}
cout << endl;
return 0;
}
3. Assign the size of vector sensorReadings to currentSize.
#include
#include
using namespace std;
int main() {
vector sensorReadings(4);
int currentSize = 0;
sensorReadings.resize(10);
/* Your solution goes here */
cout << "Number of elements: " << currentSize << endl;
return 0;
}
4. Write a statement to print "Last mpg reading: " followed by the value of mpgTracker's last element. End with newline. Ex: If mpgTracker = {17, 19, 20}, print:
Last mpg reading: 20
#include
#include
using namespace std;
int main() {
vector mpgTracker(3);
mpgTracker.at(0) = 17;
mpgTracker.at(1) = 19;
mpgTracker.at(2) = 20;
/* Your solution goes here */
return 0;}
Answer:
Following are the code to this question:
In question 1:
tempReadings.push_back(newValue); //using array that store value in at 3 position
In question 2:
ticketList.pop_back(); //defining ticketList that uses the pop_back method to remove last insert value
In question 3:
currentSize = sensorReadings.size(); /defining currentSize variable holds the sensorReadings size value
In question 4:
cout<<"Last mpg reading: "<<mpgTracker.at(mpgTracker.size()-1)<<endl;
//using mpgTracker array with at method that prints last element value
Explanation:
please find the attachment of the questions output:
In the first question, it uses the push_back method, which assigns the value in the third position, that is "53, 57, 60, and 67 "In the second question, It uses the pop_back method, which removes the last element, that is "5 and 100"In the third question, It uses the "currentSize" variable to holds the "sensorReadings" size value, which is "10".In the fourth question, It uses the mpgTracker array with the "at" method, which prints the last element value, which is "20".Using data from interviews with ESCO executives conducted in late 2012, this study examines the market size, growth forecasts, and industry trends in the United States for the ESCO sector.
Thus, It uses the "currentSize" variable to holds the "sensorReadings" size value, which is "10". In the fourth question, It uses the mpgTracker array with the "at" method, which prints the last element value, which is "20".
There are numerous types of gateways that can operate at various protocol layer depths.
Application layer gateways (ALGs) are also frequently used, albeit most frequently a gateway refers to a device that translates the physical and link layers. It is best to avoid the latter because it complicates deployments and is a frequent source of error.
Thus, Using data from interviews with Gateway executives conducted in late 2012, this study examines the market size, growth Esco size and industry trends in the United States for the Gateway.
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Review the given requirements using the checklist and discover possible problems with them. The following requirements are for a library system which is an interactive system providing access to a large document database and which allows the automated ordering and electronic delivery of documents to local and remote end-users. Some requirements for this system are: Req. 1 The user interface shall be html. Users shall access the system via standard web browsers such as Netscape and Internet Explorer. Req. 2 The system shall primarily an end-user system. Users shall use the system within the constraints of the permissions assigned by the administrator to identify, locate, order and receive documents. Req. 3 Users shall communicate with the system mainly via the html interface. Req. 4 User shall provide input to the system via the html interface. Req. 5 The system shall give output to the user via the html interface, email and print. The print output shall mainly be documents.
Answer:
Redundancy
Req. 1 and Req. 3 are seemed to say the same thing. We need to remove the first sentence in Req. 1
Conflict and understandability
Req. 1 states that access is through web browser while Req. 4 states that access is via html. We have to re-write the Req. 3 to make it clear that users do not actually have to write directly html to communicate with the system.
Completeness
Req. 5 states that print out will “mainly” be documents. What else might be printed? What other inputs will be produced?
Either remove mainly or clarify other print out.
What version of html or web browser is assumed in Req. 1 and Req. 3?
Explanation:
Given an array of integers check if it is possible to partition the array into some number of subsequences of length k each, such that:
Each element in the array occurs in exactly one subsequence
For each subsequence, all numbers are distinct
Elements in the array having the same value must be in different subsequences
If it is possible to partition the array into subsequences while satisfying the above conditions, return "Yes", else return "No". A subsequence is formed by removing 0 or more elements from the array without changing the order of the elements that remain. For example, the subsequences of [1, 2, 3] are D. [1], [2], [3]. [1, 2], [2, 3], [1, 3], [1, 2, 3]
Example
k = 2.
numbers [1, 2, 3, 4]
The array can be partitioned with elements (1, 2) as the first subsequence, and elements [3, 4] as the next subsequence. Therefore return "Yes"
Example 2 k 3
numbers [1, 2, 2, 3]
There is no way to partition the array into subsequences such that all subsequences are of length 3 and each element in the array occurs in exactly one subsequence. Therefore return "No".
Function Description
Complete the function partitionArray in the editor below. The function has to return one string denoting the answer.
partitionArray has the following parameters:
int k an integer
int numbers[n]: an array of integers
Constraints
1 sns 105
1 s ks n
1 s numbers[] 105
class Result
*Complete the 'partitionArray' function below.
The function is expected to return a STRING
The function accepts following parameters:
1. INTEGER k
2. INTEGER ARRAY numbers
public static String partitionArray (int k, List
public class Solution
Answer:
Explanation:
Using Python as our programming language
code:
def partitionArray(A,k):
flag=0
if not A and k == 1:
return "Yes"
if k > len(A) or len(A)%len(A):
return "No"
flag+=1
cnt = {i:A.count(i) for i in A}
if len(A)//k < max(cnt.values()):
return "No"
flag+=1
if(flag==0):
return "Yes"
k=int(input("k= "))
n=int(input("n= "))
print("A= ")
A=list(map(int,input().split()))[:n]
print(partitionArray(A,k))
Code Screenshot:-
Write a program that reads the input.txt file character by character and writes the content of the input file to output.txt with capitalize each word (it means upper case the first letter of a word and lowercase remaining letters of the word)
Answer:
def case_convertfile( file_name):
with open(" new_file","x") as file:
file.close( )
with open("file_name", "r") as txt_file:
while True:
word = txt_file.readline( )
word_split= word.split(" ")
for word in word_split:
upper_case = word.uppercase( )
file= open("new_file","w+")
file= open("new_file","a+")
file.write(upper_case)
txt_file.close( )
file.close( )
Explanation:
This python function would open an existing file with read privilege and a new file with write and append privileges read and capitalize the content of the old file and store it in the new file.
Q2) Answer the following:
1- Expression d=i++; causes:
a. The value of i incremented by 1
b- The value of i assigned to d
C- The value of i assigned to d then i incremented by 1
d- The value ol i incremented by 1 then assigned to d.
CO
SA
Answer:
D
Explanation:
The value of i is incremented by one then assigned to d
Your car must have two red stoplights, seen from ______ feet in the daytime, that must come on when the foot brake is pressed.
A. 100
B. 200
C. 300
D. 400
Answer:
the answer is 300 feet in the daytime
Scams where people receive fraudulent emails that ask them to supply account information are called ________.
Answer:
"Phishing" will be the correct approach.
Explanation:
This aspect of cyber attacks or fraud is called phishing, whereby clients or users are questioned for personally identifiable information about them.Attackers could very well-currently the most frequently use phishing emails to exchange malicious programs that could operate effectively in what seems like several different ways. Others would get victims to steal user credentials including payment details.Individually or in a group find as many different examples as you can of physical controls and displays.a. List themb. Try to group them, or classify them.c. Discuss whether you believe the control or display is suitable for its purpose.
Answer:
Open ended investigation
Explanation:
The above is an example of an open ended investigation. In understanding what an open ended investigation is, we first of all need to understand what open endedness means. Open endedness means whether one solution or answer is possible. In other words it means that there may be various ways and alternatives to solve or answer a question or bring solution to an investigation.
From the definition, we can deduce that an open ended investigation is a practical investigation that requires students to utilize procedural and substantive skills in arriving at conclusion through evidence gathered from open ended research or experiment(as in not close ended, not limited to ready made options, freedom to explore all possibilities). This is seen in the example question where students are asked to explore the different examples of physical controls and displays and also discuss their observations. Here students are not required to produce a predefined answer but are free to proffer their own solutions
the part of the computer that contains the brain , or central processing unit , is also known the what ?
Answer:
system unit
Explanation:
A system unit is the part of a computer that contains the brain or central processing unit. The primary device such as central processing unit as contained in the system unit perform operations hence produces result for complex calculations.
The system unit also house other main components of a computer system like hard drive , CPU, motherboard and RAM. The major work that a computer is required to do or performed is carried out by the system unit. Other peripheral devices are the keyboard, monitor and mouse.
Which of the following statements is true of an encrypted file? * The file can be read only by a user with the decryption key The file can be read by the creator and system administrator The file can not be opened again The file can be opened but not read again
Answer:
The file can be read only by a user with the decryption key
Explanation:
The way encryption works is it scrambles the data in a file following the rules of the encryption algorithm using a certain key to tell it how to scramble everything.
Without the key, the computer doesn't know how to decrypt it.
This is true no matter who has access to the file, be it a system administrator, a hacker, or even a legitimate user who has somehow lost access to the key
Strictly speaking, encryption can be broken, but, especially with modern encryption, that's a matter of centuries, and isn't really feasible
The statement that is true of an encrypted file is that The file can be read only by a user with the decryption key.
What is decryption key?A decryption key is known to be a key that is given to Customers by a specific Distributor.
This key allows Customers to open and access the Software that they bought. The decryption key is a mechanism that permit that a file can be read only by a user.
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Input a list of positive numbers, find the mean (average) of the numbers, and output the result. Use a subprogram to input the numbers, a function to find the mean, and a subprogram to output the result. Use a subprogram to Input the numbers, a Function to find the mean and a subprogram to output the Result.
Answer:
def inputNumber():
l = []
num = int(input("Enter the number of integers you want to enter\n"))
for i in range(0,num):
print("Enter the ", i+1, " integers ")
a = float(input())
l.append(a)
return l
def averageCalculator(l):
total = 0
for i in l:
total += i
avg = total/len(l)
return avg
def printoutput(avg):
print("The average of numbers is ", avg)
l = inputNumber()
avg = averageCalculator(l)
printoutput(avg)
Explanation:
A subprogram may be considered as a method where we pass some values in the arguments and return some value.
The answer is written in python language, where we have used
inputNumber() subprogram to get the input from the user.
function averageCalculator() to calculate the average.
printoutput() subprogram to print the output or the average of the numbers.
Please refer to the attached image for better understanding of the indentation of code.
Now, let us learn about them one by one:
inputNumber(): We get the number of values to be entered as an integer value and then get the numbers as float.
Store the values in a list and return the list to the caller main program.
averageCalculator(l): Contains a list as argument as we got from inputNumber(). It sums all the numbers and divides with total number to find the average. Returns the average value to the caller main program.
printoutput(avg): Contains an argument which is the average calculated in the averageCalculator(). It prints the argument passed to it.
You bought a monochrome laser printer two years ago. The printer has gradually stopped feeding paper. Which printer component should you check first
Answer:
Pick up roller
Explanation:
you should first check the pickup roller component. This component is the part of the printer that picks paper up from the paper tray. The pickup roller links the printer and the paper. When the printer printer is running, the roller would take paper from the paper tray for the printer to print on. One of the issues it can have is Paper jam where the roller would stop turning so that it will no longer be picking papers up from the tray.
Bharath has made a table of content for his document in Open Office, in which he wants to make few changes, but he is unable to make the changes. Give reason. Explain how he can make the necessary changes
Answer:
H cannot update it because it is probably protected.
If you cannot click in the table of contents, it is probably because it is protected. To disable this protection, choose Tools > Options > OpenOffice.org Writer > Formatting Aids, and then select Enable in the Cursor in protected areas section. If you wish to edit the table of contents without enabling the cursor, you can access it from the Navigator.
Explanation:
. To update a table of contents when changes are made to the document:
Right-click anywhere in the TOC.
From the pop-up menu, choose Update Index/Table. Writer updates the table of contents to reflect the changes in the document.
You can also update the index from the Navigator by right-clicking on Indexes > Table of Contents1 and choosing Index > Update from the pop-up menu.
How can technology efforts be reconciled to improve hazard/disaster preparedness, response, and mitigation to insure systems sustainability, data integrity, and supply chain protection?
Answer:
Prediction
With regard to preparedness for hazard/disaster, technology such as AI are being explored to see how they can help to predict natural disaster.
If there is a breakthrough in this space, it will drastically reduce the negative impact of natural disasters such as floods and earthquakes as people will become ready to respond to them and mitigate their effects where possible.
In agriculture, there are factors which come together to bring about flooding. Flooding is one of the major disasters which cripples entire value chains. With a potential threat anticipated or predicted by AI, businesses can invest in technologies that can help protect the farms, farmland and other resources critical to such a supply chain.
AI-powered technologies that provide prediction services often combine this advanced computing prowess with the ability to process big data.
Technology can reach places that are unreachable by humans
AI-powered robots will soon become the norm.
Presently there are self-learning and self instructing robots powered by Artificial Intelligence that have applications in warfare, manufacturing, deepsea diving and intelligence gathering, and transportation. It is not out of place to predict that in the next decade, scientists would have perfected rescue robots that can go into very unstable terrain that have been damaged by flood or earthquake and attempt a rescue of lives and property at a scale that has never been possible before.
Connectivity
Connectivity helps people access to aid, resources that are critical for survival, transmission and receipt of life--saving information etc. CISCO has successfully used its technology called TacOps (short for Tactical Operations) successfully 45 times on over 5 continents.
Cheers!
3. How many bytes of storage space would be required to store a 400-page novel in which each page contains 3500 characters if ASCII were used? How many bytes would be required if Unicode were used? Represent the answer in MB
Answer:
A total of 79.3mb will be needed
The fact that the speed of a vehicle is lower than the prescribed limits shall relieve the driver from the duty to decrease speed when approaching and crossing an intersection. True or false
Explanation:
the answer is false ........
The fact that the speed of a vehicle is lower than the prescribed limits shall relieve the driver from the duty to decrease speed when approaching and crossing an intersection is not true.
What is intersection in the traffic rules?An intersection serves as the point where many lanes cross on the road which is a point where driver is required to follow the traffic rules.
However, the above statement is not true because , a driver can decide not decrease speed when approaching and crossing an intersection, even though it is a punishable offense in traffic rules.
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What command would you use to place the cursor in row 10 and column 15 on the screen or in a terminal window
Answer:
tput cup 10 15
Explanation:
tput is a command for command line environments in Linux distributions. tput can be used to manipulate color, text color, move the cursor and generally make the command line environment alot more readable and appealing to humans. The tput cup 10 15 is used to move the cursor 10 rows down and 15 characters right in the terminal
Which of the following peripheral devices can be used for both input and output? mouse touch screen on a tablet computer printer CPU
Answer:
mouse printer CPU touch screen
Explanation:
on a tablet computer hope this helps you :)
An organization is planning to implement a VPN. They want to ensure that after a VPN client connects to the VPN server, all traffic from the VPN client is encrypted. Which of the following would BEST meet this goal?a. Split tunnelb. Full tunnelc. IPsec using Tunnel moded. IPsec using Transport mode
Answer:
B. Full tunnel.
Explanation:
In this scenario, an organization is planning to implement a virtual private network (VPN). They want to ensure that after a VPN client connects to the VPN server, all traffic from the VPN client is encrypted. The best method to meet this goal is to use a full tunnel.
A full tunnel is a type of virtual private network that routes and encrypts all traffics or request on a particular network. It is a bidirectional form of encrypting all traffics in a network.
On the other hand, a split tunnel is a type of virtual private network that only encrypts traffic from the internet to the VPN client.
Hence, the full tunnel method is the most secured type of virtual private network.
If the processor has 32 address lines in its address bus; i.e. 32-bit address range, what is its address space or range; i.e. what is the smallest and largest address that can be represented
Answer:
The answer is "0 to 4294967295"
Explanation:
Given bit:
32 bits
Calculating smallest and largest bits:
In any processor, it works only on the 0 and 1 bit and it also stores 0 and 1 values. so, the smallest address in bit value is= 0 and the largest bit value can be defined as follows:
largest address value in bits:
[tex]\Longrightarrow 2^{32}-1\\\\\Longrightarrow 4294967296 -1\\\\\Longrightarrow 4294967295\\\\[/tex]
smallest address= 0
largest address = 4294967295
A computer uses a programmable clock in square-wav e mode. If a 500 MHz crystal is used, what should be the value of the holding register to achieve a clock resolution of (a) a millisecond (a clock tick once every millisecond)
Answer:
500,000
Explanation:
A computer uses a programmable clock in square-wave mode. If a 500 MHz crystal is used, what should be the value of the holding register to achieve a clock resolution of (a) a millisecond (a clock tick once every millisecond)
1 millisecond = 1 million second = 1,000,000
For a 500 MHz crystal, Counter decrement = 2
Therefore value of the holding register to a clock resolution of 1,000,000 seconds :
1,000,000/2 = 500,000
Generating a signature with RSA alone on a long message would be too slow (presumably using cipher block chaining). Suppose we could do division quickly. Would it be reasonable to compute an RSA signature on a long message by first finding what the message equals (taking the message as a big integer), mod n, and signing that?
Answer:
Following are the algorithm to this question:
Explanation:
In the RSA algorithm can be defined as follows:
In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.
Computing N = PQ.
In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,
[tex]\lambda (N) = \ lcm( \lambda (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)[/tex] where [tex]\lambda[/tex] is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from [tex]1<E < \lambda (N)[/tex]and [tex]gcd(E, \lambda (N) ) = 1;[/tex] that is [tex]E \ \ and \ \ \lambda (N)[/tex]. D was its complex number equivalent to E (modulo [tex]\lambda (N)[/tex] ); that is d was its design multiplicative equivalent of E-1.
It's more evident as a fix for d provided of DE ≡ 1 (modulo [tex]\lambda (N)[/tex] ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.
In some situations it's was shown that far lower E values (such as 3) are less stable.
E is eligible as a supporter of the public key.
D is retained as the personal supporter of its key.
Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and [tex]\lambda (N)[/tex] will also be confined as they can be used in measuring D. The Euler totient operates [tex]\varphi (N) = (P-1)(Q - 1)[/tex] however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).
It applies because [tex]\varphi (N)[/tex], which can always be split into [tex]\lambda (N)[/tex], and thus any D satisfying DE ≡ 1, it can also satisfy (mod [tex]\lambda (N)[/tex]). It works because [tex]\varphi (N)[/tex], will always be divided by [tex]\varphi (N)[/tex],. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D > [tex]\lambda (N)[/tex] ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D< [tex]\lambda (N)[/tex]. if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo [tex]\lambda (N)[/tex].
As there are common threads (P− 1) and (Q – 1) which are present throughout the [tex]N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1))[/tex], it's also possible, if there are any, for all the common factors [tex](P -1) \ \ \ and \ \ (Q - 1)[/tex]to become very small, if necessary.
Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module [tex]\varphi (N)[/tex]) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.
By using ____, you can use reasonable, easy-to-remember names for methods and concentrate on their purpose rather than on memorizing different method names.
Answer:
Polymorphism
Explanation:
If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.
The information regarding the polymorphism is as follows:
The person has various attributes at the same timeFor example, a man could be a father, a husband, an entrepreneur at the same time.In this, the similar person has different types of behavior in different situations.Therefore we can conclude that If we use polymorphism so we can apply the names that could be easy to remember for the methods' purpose.
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Your system is infected with a virus that can modify signature each time it is executed to fool antivirus software. Which type of virus is this?
Answer:Polymorphic Virus
Explanation:
Malware that can change its signature each time is polymorphic
CHALLENGE ACTIVITY 3.7.2: Type casting: Reading and adding values.
Assign totalowls with the sum of num_owls A and num_owls_B.
Sample output with inputs: 34
Number of owls: 7
1. total_owls -
2.
3. num_owls A - input
4. num_owls_B - input
5.
6. " Your solution goes here
7.
8. print("Number of owls:', total_owls)
Answer:
total_owls = 0
num_owls_A = int(input())
num_owls_B = int(input())
total_owls = num_owls_A + num_owls_B
print("Number of owls:", total_owls)
Explanation:
Initialize the total_owls as 0
Ask the user to enter num_owls_A and num_owls_B, convert the input to int
Sum the num_owls_A and num_owls_B and set it to the total_owls
Print the total_owls
avg_owls=0.0
num_owls_zooA = int(input())
num_owls_zooB = int(input())
num_owls_zooC = int(input())
num_zoos = 3
avg_owls = (num_owls_zooA + num_owls_zooB + num_owls_zooC) / num_zoos
print('Average owls per zoo:', int(avg_owls))
There is a problem while you are trying the calculate the average owls per zoo.
As you may know, in order to calculate the average, you need to get the total number of owls in all the zoos, then divide it to the number of zoos. That is why you need to sum num_owls_zooA + num_owls_zooB + num_owls_zooC and divide the result by num_zoos
Be aware that the average is printed as integer value. That is why you need to cast the avg_owls to an int as int(avg_owls)
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Enum fruit_tag {
BLUEBERRY,
BANANA,
PINEAPPLE,
WATERMELON
};
typedef enum fruit_tag fruit_t;
void printFruit(fruit_t myFruit) {
switch(myFruit) {
case BLUEBERRY:
printf("a blueberry");
break;
case BANANA:
printf("a banana");
break;
case PINEAPPLE:
printf("a pineapple");
break;
case WATERMELON:
printf("a watermelon");
break;
}
}
void compareFruit(fruit_t fruit1, fruit_t fruit2) {
if (fruit1 > fruit2) {
printFruit(fruit1);
printf(" is larger than ");
printFruit(fruit2);
}
else {
printFruit(fruit1);
printf(" is smaller than ");
printFruit(fruit2);
}
}
int main(void) {
fruit_t myFruit = PINEAPPLE;
fruit_t otherFruit = BLUEBERRY;
compareFruit(myFruit, otherFruit);
return 0;
What is the output?
Answer:
The output is "a pineapple is larger than a blueberry ".
Explanation:
In the given C language code Enum, typedef, and two methods "printfruit and compareFruit" is declared, that can be defined as follows:
In the enum "fruit_tag" there are multiple fruit name is declared that use as the datatypes. In the next line, the typedef is defined, that enum to define another datatype that is "fruit_t". In the next step, the printFruit method is defined that accepts "myFruit" variable in its parameter and use the switch case to to check value. In the "compareFruit" method, it accepts two parameters and uses the if-else block to check its parameters value and print its value. In the main method, two variable "myFruit and otherFruit" variable is declared that stores the values and pass into the "compareFruit" method and call the method.The breastbone or ________________ extends down the chest.
Answer:
The sternum or breastbone is a long flat bone located in the central part of the chest.
The sternum or breastbone is a long flat bone located in the central part of the chest.
In the middle of the chest, there is a long, flat bone known as the sternum or breastbone. It forms the front of the rib cage and is joined to the ribs by cartilage, assisting in the protection of the heart, lungs, and major blood arteries from harm. It is one of the longest and largest flat bones in the body, somewhat resembling a necktie. The manubrium, body, and xiphoid process are its three regions.
Therefore, the sternum or breastbone is a long flat bone located in the central part of the chest.
Learn more about the breastbone here:
https://brainly.com/question/32917871.
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