In the diagram, q1= +8.0 C, q2= +3.5 C, and q3 = -2.5 C. q1 to q2 is 0.10 m, q2 to q3 is 0.15 m. What is the net force on q2? Label sign for charges (+ or -). (Unit = N). pls help?
Answer:
f(t) = 28,7 [N]
Explanation: IMPORTANT NOTE: IN PROBLEM STATEMENT CHARGES ARE IN C (COULOMBS) AND IN THE DIAGRAM IN μC. WE ASSUME CHARGES ARE IN μC.
The net force on +q₂ is the sum of the force of +q₁ on +q₂ ( is a repulsion force since charges of equal sign repel each other ) and the force of -q₃ on +q₂ ( is an attraction force, opposite sign charges attract each other)
The two forces have the same direction to the right of charge q₂, we have to add them
Then
f(t) = f₁₂ + f₃₂
f₁₂ = K * ( q₁*q₂ ) / (0,1)²
q₁ = + 8 μC then q₁ = 8*10⁻⁶ C
q₂ = + 3,5 μC then q₂ = 3,5 *10⁻⁶ C
K = 9*10⁹ [ N*m² /C²]
f₁₂ = 9*10⁹ * 8*3,5*10⁻¹²/ 1*10⁻² [ N*m² /C²]* C*C/m²
f₁₂ = 252*10⁻¹ [N]
f₁₂ = 25,2 [N]
f₃₂ = 9*10⁹*3,5*10⁻⁶*2,5*10⁻⁶ /(0,15)²
f₃₂ = 78,75*10⁻³/ 2,25*10⁻²
f₃₂ = 35 *10⁻¹
f₃₂ = 3,5 [N]
f(t) = 28,7 [N]
Answer:
facts
Explanation:
A researcher is studying traffic patterns at an intersection before an upcoming construction project. As part of this investigation, the researcher writes a scientific question, develops a procedure to observe traffic specifically at this intersection, and draws a conclusion. Which type of investigation is the researcher conducting? descriptive comparative experimental procedural
Answer:
Procedural is the answer
hope this helps
What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)
at 308 K? Use the equation: -mv2
2
For m, use 0.02000 kg. Remember that R = 8.31 J/(mol-K).
= ER
3
2
nRT
A. 1540 m/s
B. 876 m/s
C. 87.6 m/s
O D. 15,400 m/s
Answer:
v = 876 m/s
Explanation:
It is given that,
Number of mol of Neon is 2 mol
Temperature, T = 308 K
Mass, m = 0.02 kg
Value of R - 8.31 J/mol-K
We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,
[tex]\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s[/tex]
So, the correct option is (B).
Find the x-component of this vector: 47.3 m 39.4 ° Remember, angles are measured from the + x axis. x-component (m)
The x-component of the vector is 36.55 m.
Components of vectorsThe components of a vector include both x and y components. The x-component is determined along x-axis, while y-component is determined along y-axis.
Vx = Vcosθ
Vy = Vsinθ
where;
Vx is the x-component of the vectorVy is the y-component of the vectorX-components of the vectorThe x-component of the vector is calculated as follows;
x = 47.3 x cos(39.4)
x = 36.55 m
Thus, the x-component of the vector is 36.55 m.
Learn more about x-component of vector here: https://brainly.com/question/13416288
fill in the term to complete each sentence
a wave carries___ from one place to another.
mechanical waves carry energy through___.
Energy
A material medium
A wave carries energy from one place to another. Mechanical waves carry energy through a material medium.
What is a wave?A wave is a phenomenon that flows across a material medium without leaving any lasting mark.
Mechanical or electromagnetic waves can be used to classify them. Transverse and longitudinal are the two main forms.
A wave carries energy from one place to another. Mechanical waves carry energy through a material medium.
Hence the correct options for the fill-in-the-blanks are energy and a material medium.
To learn more about the wave refer to the link;
brainly.com/question/3004869
