The probability that there will be a tornado in Tulsa, Oklahoma, each day of the summer depends on the humidity of the day in question. If the air is dry on a given day, there is a 0.5 percent chance of a tornado in Tulsa, if the air is humid on that day. there is a 5 percent chance of a tomado. On July 1, 2019, local news reported that there was 40 percent chance of the air being humid. What is the probability that there was a
tornado in Tulsa on July 1, 2019?
a) 0.003
B) 0.020
C)0.023
D) 0.040
E) 0.060

Answer: (3,0) and (-12,0)

Step-by-step explanation:

The x-intercepts of the graph of f(x) = x² + 5x - 36 are (-9,0) and (4,0).

Option B is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

To find the x-intercepts of the function f(x) = x^2 + 5x - 36,

we need to set y = f(x) to 0 and solve for x.

So, we have:

x² + 5x - 36 = 0

We can factor the left side of the equation:

(x + 9)(x - 4) = 0

Using the zero product property, we get:

x + 9 = 0 or x - 4 = 0

Solving for x, we get:

x = -9 or x = 4

Therefore,

The x-intercepts of the graph of f(x) = x² + 5x - 36 are (-9,0) and (4,0).

Learn more about functions here:

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Answer:

x = 24.8

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

Sin theta = opp / hypotenuse

sin 75 = 24 /x

x sin 75 = 24

x = 24/ sin 75

x=24.84662

Rounding to the nearest tenth

x = 24.8

Answer:

A square is 4 even sides.

the circumference around the square area is 1600 meters. This means that each side is 400 meters.

Square meters is the area of the square.

400 x 400 = 160000 m^2

To get to Hectares, you divide the squared measurement by 10,000.

Answer:

160000m^2 = 16ha

Step-by-step explanation:

Bit of a nit pick first the word is perimeter not circumference circumference only applies to circles. 1600/4=400 (divide by 4 because a square has 4 sides) 400^2=160000 (A=L*H the length and height are the same so you square it) 160000/10000=16 (1 hectare = 10000m^2), Hope this helps. :)

Answer:

Step-by-step explanation:

I assume that you mean 4⅛ batches, not 41/8 batches.

4⅛ batches × (¾ stick)/batch = 33/8 batches × (¾ stick)/batch

= 99/32 sticks

= 3 and 3/32 sticks

Answer:

It will take them both 24 minutes to mow the lawn if they are working together.

Step-by-step explanation:

Given that Sam can mow a lawn in 40 minutes, and Melissa can mow the same lawn in 80 minutes, to determine how long does it take for both Sam and Melissa to mow the lawn if they are working together, the following calculation must be performed:

1/40 + 1/60 = 1 / X

3X + 2X = 120

X = 120/5

X = 24

Thus, it will take them both 24 minutes to mow the lawn if they are working together.

Answer:

Step-by-step explanation:

6 is the thousands place

0 (right next to it) is the 10 thousands place

9 is the hundred thousands place. There is only 1 nine present so the answer is unique.

Answer:

3 planters can be filled, with 288,156 gallons left over.

Step-by-step explanation:

Given that a dump truck with 1500 gallons of soil arrives on campus to fill in the new planters on the quad, and each planter needs 2 cubic yards of soil, to determine how many planters can be filled the following calculation must be performed:

1 cubic yard = 201.974 gallons

2 cubic yards = 403.948 gallons

1500 / 403.948 = X

3.71 = X

1500 - (403.948 x 3) = 288.156

Therefore, 3 planters can be filled, with 288,156 gallons left over.

what we know?:

* scale factor of 1/4

* the point (4, -8)

all we have to do is put 4/4 (because we are dilating by 1/4)

4/4= 1

same for the other one: -8/4= -2

FINAL ANSWER: (1, -2)

• 2xy + x ² y' = 0

This DE is exact, since

∂(2xy)/∂y = 2x

∂(x ²)/∂x = 2x

are the same. Then there is a solution of the form f(x, y) = C such that

∂f/∂x = 2xy   ==>   f(x, y) = x ² y + g(y)

∂f/∂y = x ² = x ² + dg/dy   ==>   dg/dy = 0   ==>   g(y) = C

==>   f(x, y) = x ² y = C

• sin(x) cos(y) + cos(x) sin(y) y' = 0

is also exact because

∂(sin(x) cos(y))/∂y = -sin(x) sin(y)

∂(cos(x) sin(y))/∂x = -sin(x) sin(y)

Then

∂f/∂x = sin(x) cos(y)   ==>   f(x, y) = -cos(x) cos(y) + g(y)

∂f/∂y = cos(x) sin(y) = cos(x) sin(y) + dg/dy   ==>   dg/dy = 0   ==>   g(y) = C

==>   f(x, y) = -cos(x) cos(y) = C

• x ² + y ² - 2xyy' = 0

is not exact:

∂(x ² + y ²)/∂x = 2x

∂(-2xy)/∂y = -2x

So we look for an integrating factor µ(x, y) such that

µ (x ² + y ²) - 2µxyy' = 0

becomes exact, which would require that these be equal:

∂(µ (x ² + y ²))/∂y = (x ² + y ²) ∂µ/∂y + 2µy

∂(-2µxy)/∂x = -2xy ∂µ/∂x - 2µy

Observe that if µ(x, y) = µ(x), then ∂µ/∂y = 0 and ∂µ/∂x = dµ/dx, so we would have

2µy = -2xy dµ/dx - 2µy

==>   -2xy dµ/dx = 4µy

==>   dµ/µ = -2/x dx

Integrating both sides gives

∫ dµ/µ = ∫ -2/x dx   ==>   ln|µ| = -2 ln|x|   ==>   µ = 1/x ²

So in the modified DE, we have

(1 + y ²/x ²) - 2y/x y' = 0

which is now exact and ready to solve, since

∂(1 + y ²/x ²)/∂y = 2y/x ²

∂(-2y/x)/∂x = 2y/x ²

We get

∂f/∂x = 1 + y ²/x ²   ==>   f(x, y) = x - y ²/x + g(y)

∂f/∂y = -2y/x = -2y/x + dg/dy   ==>   dg/dy = 0   ==>   g(y) = C

==>   f(x, y) = x - y ²/x = C

• exp(2x) (2 cos(y) - sin(y) y' ) = 0

is exact, since

∂(2 exp(2x) cos(y))/∂y = -2 exp(2x) sin(y)

∂(-exp(2x) sin(y))/∂x = -2 exp(2x) sin(y)

Then

∂f/∂x = 2 exp(2x) cos(y)   ==>   f(x, y) = exp(2x) cos(y) + g(y)

∂f/∂y = -exp(2x) sin(y) = -exp(2x) sin(y) + dg/dy   ==>   dg/dy = 0   ==>   g(y) = C

==>   f(x, y) = exp(2x) cos(y) = C

Given that y = 0 when x = 0, we find that

C = exp(0) cos(0) = 1

so that the particular solution is

exp(2x) cos(y) = 1

Answer:

x = 5/8

Step-by-step explanation:

x^3 = 125/512

Take the cube root of each side

x^3 ^1/3 = (125/512)^ 1/3

We know (a/b) ^1/3 = a^ 1/3  / b^1/3

x = (125) ^1/3 / (512)^ 1/3

x = 5/8

Answer:

x = 76.9

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp side / adj side

tan 70 = x/28

28 tan 70 = x

x=76.92936

Rounding to the nearest tenth

x = 76.9

Answer:

76.9

Step-by-step explanation:

SOH: Sin(θ) = Opposite / Hypotenuse

CAH: Cos(θ) = Adjacent / Hypotenuse

TOA: Tan(θ) = Opposite / Adjacent

Tan 70 = [tex]\frac{x}{28}[/tex]

(28) tan 70 = x

76.929 = x

Answer:

A. 21°, 69°

Step-by-step explanation:

If you work by process of elimination all you have to do is take 27 away from the bigger degree of the two and see if it is 2x as much as the smaller degree.

Ex.

1. 69°-27°= 42°, which is 2x as many as 21°.

Answer:

???

Step-by-step explanation:

[tex] \Large \mathbb{SOLUTION:} [/tex]

[tex] \begin{array}{l} \dfrac{1 + \sin 2A}{1 - \sin 2A} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \dfrac{1 + 2\sin A\cos A}{1 - 2\sin A\cos A} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \because \sin 2A = 2\sin A\cos A\ (\text{Double Angle Identity}) \\ \\ \text{Divide both numerator and denominator of} \\ \text{LHS by }\cos^2 A. \\ \\ \dfrac{\frac{1 + 2\sin A\cos A}{\cos^2 A}}{\frac{1 - 2\sin A\cos A}{\cos^2 A}} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \dfrac{\frac{1}{\cos^2 A} + \frac{2\sin A\cos A}{\cos^2 A}}{\frac{1}{\cos^2 A} - \frac{2\sin A\cos A}{\cos^2 A}} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2}\\ \\ \dfrac{\sec^2 A + 2\tan A} {\sec^2 A- 2\tan A} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \dfrac{1 + \tan^2 A + 2\tan A} {1 + \tan^2 A - 2\tan A} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \because \sec^2 A = 1 + \tan^2 A\ (\text{Pythagorean Identity}) \\ \\ \text{Rearranging, we get} \\ \\ \dfrac{\tan^2 A + 2\tan A + 1} {\tan^2 A - 2\tan A + 1} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} \\ \\ \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2} = \dfrac{(1 + \tan A)^2}{(1 - \tan A)^2}\\ \\ \text{LHS} = \text{RHS}_{\boxed{\:}}\end{array} [/tex]

Answer:

The zeroes are -6, 1/2 and 2.

Step-by-step explanation:

f(x) = 2x3 + 7x2 - 28x + 12 = 0

From the first and last coefficient 2 and 12, one guess for a zero is x = 2.

So substituting x = 2:

f(2) = 16+ 28 - 56 + 12 = 0

So x = 2 is a zero and x - 2 is a factor of f(x)

Performing long division:

x - 2)2x3 + 7x2 - 28x + 12( 2x2 + 11x - 6 <------- Quotient

       2x3  - 4x2

                 11x2 - 28x

                 11x2 - 22x

                          - 6x + 12

                           -6x + 12

                            .............

Now we solve

2x2 + 11x - 6 = 0

(2x - 1)(x + 6) = 0

2x - 1 = 0 or x + 6 = 0, so:

x = 1/2,  x = -6.

Answer: -6, 1/2, 2.

Step-by-step explanation:

{(x) = 2x3 + 7x2 - 28x + 12 = 0

From the first and last coefficient 2 and 12, one

guess for a zero is x=2.

So substituting x=2:

{(2) = 16+ 28 - 56 + 12 = 0

So x = 2 is a zero and x - 2 is a factor of f(x)

Performing long division:

X - 2)2x3 + 7x2 - 28x + 12(2x2 + 11x - 6 <

Quotient

Answer:

40

Step-by-step explanation:

(x+2)^5 use binomial theorem :

(a+b)^n = (n choose 0)*a^n*b^0 + (n choose 1)*a^(n-1)*b^1 + (n choose 2)*a^(n-2)*b^2) + ... + (n choose (n-1)*a^1*b^(n-1) + ( n choose n)*a^0*b^n

this seems like a lot but to break it down, notice how the exponent on 'a' decreases as the exponent on 'b' gets bigger.

also, the 'choose' formula is :

(n choose r ) = n!/ (n-r)!r!

now plug in your values

(x+2)^5 =

(5 choose 0)*x^5*2^0 + (5choose 1)*x^4*2^1 + (5 choose 2)*x^3*x^2 + (5 choose 3)*x^2*2^3 + (5 choose 4)*x^1*2^4 + (5 choose 5)*x^0*x^5

we only need the third term so we will solve for this :

(5 choose 2)*x^3*x^2

5 choose 2 = 5!/ (5-2)!2! = 5!/ 3!2! = 10

x^3 * 2^2 = 4x^3

10*4x^3 = 40x^3

Answer:

1364

Step-by-step explanation:

1, 3, 4, 7, 11, 18, 29, 47, 76, 123, 199, 322, 521, 843, 1364

a1+a2 = a3, a2+a3=a4 etcetera..

1+3 =4

3+4 =7

4+7=11

.

.

a13+a14 = a15

521+843 = 1364

so, 1364 is the answer

Answer:

your laptop is nice really

Answer:

The dimensions are:

l = 2*1.96 = 3.92 yd

h = 5/(1.96)² = 1.30 yd

w = 1.96 yd

Step-by-step explanation:

The volume is given by:

[tex]V=l*w*h[/tex]

Where:

We know that l = 2w, so we have:

[tex]V=2w^{2}*h[/tex]

[tex]10=2w^{2}*h[/tex]

[tex]5=w^{2}*h[/tex] (2)

Now, the surface of this parallelepiped is:

[tex]S=2wh+2lh+lw[/tex]

Using l = 2w:

[tex]S=2wh+4wh+2w^{2}[/tex]

Using (2) we obtain the surface equation in terms of w.

[tex]S=2w\frac{5}{w^{2}}+4w\frac{5}{w^{2}}+2w^{2}[/tex]    

[tex]S=2\frac{5}{w}+4\frac{5}{w}+2w^{2}[/tex]

We need to take the derivative with respect to w to minimize the surface area.

[tex]S=2\frac{5}{w}+4\frac{5}{w}+2w^{2}[/tex]  

[tex]S=\frac{30}{w}+2w^{2}[/tex]

[tex]\frac{dS}{dw}=-\frac{30}{w^{2}}+4w[/tex]

Now, let's equal it to zero.

[tex]0=-\frac{30}{w^{2}}+4w[/tex]  

[tex]\frac{30}{w^{2}}=4w[/tex]              

[tex]w^{3}=\frac{30}{4}[/tex]          

[tex]w=1.96\: yd[/tex]  

So, l = 2*1.96 = 3.92 yd and h = 5/(1.96)² = 1.30 yd

Therefore, the dimensions are:

l = 2*1.96 = 3.92 yd

h = 5/(1.96)² = 1.30 yd

w = 1.96 yd

I hope it helps you!

Answer:

The distance between two points (a, b) and (c, d) is given by:

[tex]d = \sqrt{(a - c)^2 + (b - d)^2}[/tex]

So the distance between the point (6, 5) and the line y = 5x - 10 can be thought as the distance between the point (6, 5) and the point (x, 5x - 10)

Where:

(x, 5x - 10) denotes all the points in the line y = 5x – 10

That distance is given by:

[tex]d = \sqrt{(x - 6)^2 + (5x - 10 - 5)^2} = \sqrt{(x - 6)^2 + (5x - 15)^2}[/tex]

Now we want to minimize this.

Because the distance is a positive quantity, we can try to minimize d^2 insted, so we have:

[tex]d^2 = (\sqrt{(x - 6)^2 + (5x - 15)^2})^2 = (x - 6)^2 + (5x - 15)^2}\\\\d^2 = x^2 - 2*x*6 + 36 + 25*x^2 - 2*15*x + (-15)^2\\\\d^2 = 26*x^2 - 42*x + 261[/tex]

Notice that this is a quadratic equation with a positive leading coefficient, which means that the arms of the graph will open upwards, then the minimum will be at the vertex of the parabola.

Remember that for a parabola:

y = a*x^2 + bx + c

the x-value of the vertex is:

x = -b/2a

Then for our parabola:

d^2 = 26*x^2 - 42*x + 261

The vertex is at:

x = -(-42)/(2*26) = 0.808

Then we just need to evaluate the distance equation in that value of x to get the shortest distance:

[tex]d = \sqrt{(0.808 - 6)^2 + (5*0.808 - 15)^2} = 12.129[/tex]

The shortest distance between the point A and the line is 12.129 units.

Answer:

Step-by-step explanation:

We have two sides; the Adjacent and the Hypotnuse

Meaning we will use Cos

Cos = A/H

Cos X = 16/19

Use the inverse of Cos to find the angle

X = cos-1 (16/19)

X = 0.45499141546

X = 0.45

Answer:

-10x -10y=20

-10x - 20=10y

-10x - 20/10=y

-10x - 2=y

y=-10x-2

-7x -7y=14

-7x - 14 = 7y

-7x - 14/7=y

-7x - 2=y

y=-7x-2

Answer:

The Answer Is Point B (2,0)

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

common ratio

2.1/0.7=3

6.3/2.1=3

18.9/6.3=3

therefore common ratio is equal to 3

Answer:

Step-by-step explanation:

The null and alternative hypothesis are usually used in hypothesis testing to present the claim being tested as give in terms of the mean or proportion :

Given that the mean score of high school students is 10 ; using a sample of 50 students, a mean of 8 was obtained ; we could want to test the claim that the mean score is less than 10.

Here; population mean, μ = 10 ; the claim is now that, μ < 10 based on what was observed about the sample.

H0 : μ = 10

H0 : μ < 10

If we wanted to test If the mean was greater than 10 ; then the sign is reversed

H0 : μ = 10

H0 : μ > 10

If we wanted to test If the score is just different from the mean score stated ; (it may be less than or greater than)

H0 : μ = 10

H0 : μ ≠ 10

the discrete compounding formula is f = p * (1 + r) ^ n

f is the future value

p is the present value

r is the interest rate per time period

n is then number of time periods

in your problem, you are given:

f = what you want to find

p = 5000

r = 30% per year / 100 = .3 per year (percent / 100 = rate).

n = 3 years

if you compound annually, the formula becomes:

f = 5000 * (1 + .3) ^ 3 = 10985

if you compound quarterly, the formula becomes:

f = 5000 * (1 + .3 / 4) ^ (3 * 4) = 11908.898

if you compound monthly, the formula becomes:

f = 5000 * (1 + .3 / 12) ^ (3 * 12) = 12162.67658

if you compound continuously, a different formula is used.

that formula is f = p * e ^ (r * n)

f is the future value

p is the present value

e is the scientific constant of 2.718281828.......

r is the interest rate per time period

n is the number of time periods.

with this formula, you leave the time periods in terms of years.

it will make no difference what time periods and compounding periods you use, the answer will be the same.

most of the time you will just give it the interest rate per year and the number of years.

the reason is as follows:

r * n = .3 * 3 = .9 when giving it rate and time in terms of years.

r * n = .3 / 4 * 3 * 4 = .9 when giving it rate and time in terms of quarters.

r * n = .3 / 12 * 3 * 12 = .9 when giving it rate and time in terms of months.

in your problem, the formula becomes f = 5000 * e ^ (.3 * 3) = 12298.01556.

the more compounding periods per year, the higher the future value.

the highest is when you compound continuously.

this is apparent from the data.