it is easier to climb up a slanted slope than a vertical slope
Answer:
Yes, it is easier to climb a slanted slope than a vertical or more steep slope.
Explanation:
On a vertical slope, you are climbing higher instead of farther so on each step gravity weighs you down much more than on a gentle slope
The speed of revolution of particle going around a circlr is doubled and its angular speed is havled. What happen to the centripetal acceleration?
a) unchanged
b) doubles
c) halves
d) becomes four times
Answer: The correct answer is C
Explanation:
What is the relationship between kinetic and potential energy of a falling object
Answer:
See the explanation below.
Explanation:
According to the law of energy conservation. This can be transformed from potential energy to kinetic or vice versa.
For example, when you have a body at rest at a height with respect to the ground level, this body possesses potential energy with respect to the ground, but the moment that the body falls the potential energy decreases as it loses height with respect to the ground, but as the potential energy decreases, the kinetic energy increases, that is to say, the potential energy is transformed into kinetic energy as the body is falling.
As the energy relationship is maintained we can say that the potential and kinetic energies are equal.
[tex]E_{pot}=m*g*h\\E_{kin}=\frac{1}{2} *m*v^{2} \\E_{pot}=E_{kin}[/tex]
Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal. How long is it in the air?
Given :
Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal.
To Find :
How long is it in the air.
Solution :
We know, the formula of time of flight is :
[tex]T = \dfrac{2usin\ \theta}{g}\\\\T = \dfrac{2\times 30\times sin\ 30^o}{9.8}\\\\T = 3.06\ seconds[/tex]
Therefore, the ball is in air for 3.06 seconds.
which property of an object is not changed by a force
Putting the selected answers in parenthesis
A cation has a (Negative, Positive, Neutral) charge, because they have (Lost, Maintained, Gained) electrons. An anion has a (Negative, Positive, Neutral) charge, because they have (Lost, Maintained, Gained) electrons. An atom with the same number and protons and neutrons have a (Negative, Positive, Neutral) charge.
Answer:
gimmie
Explanation:
calculate the net force
250N left force and right force is 150N
Answer
100N on the left force
Explanation:
You have to subtract 250 - 100 and the reamaining would be 100 and that 100 would go to the left force since it was the higher number
Why are doorknobs placed at the edge of a door rather than in the center
Answer: so it can reach the frame
Explanation:
Answer:
To increase force on the door
what two charactoristic are needed to describe a force
Answer:
An applied force, A resistive force
Explanation:
An applied force is an interaction of one object on another that causes the second object to change its velocity.
A resistive force passively resists motion and works in a direction opposite to that motion.
1+1=?
FIRST ONE TO ANSWER GETS BRAINLIEST!
Answer:
Thx for points merry Christmas answer 2
Explanation:
Answer:2
Explanation:
Two motorcycles are traveling due east with different velocities. However, 3.63 seconds later, they have the same velocity. During this 3.63-second interval, motorcycle A has an average acceleration of 4.55 m/s2 due east, while motorcycle B has an average acceleration of 18.9 m/s2 due east. (a) By how much did the speeds differ at the beginning of the 3.63-second interval, and (b) which motorcycle was moving faster
Answer:
52.095 m/s
Motorcycle a was moving faster
Explanation:
We start by using one of the equations of motion
V = u + at
If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as
V(a) = u(a) + a(a).t
If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as
V(b) = u(b) + a(b).t
Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have
0 = u(a) - u(b) + a(a).t - a(b).t
-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have
u(b) - u(a) = [a(a) - a(b)]t
Since we have the values for acceleration and the time, we substitute so that
u(b) - u(a) = (4.55 - 18.9)3.63
u(b) - u(a) = -14.35 * 3.63
u(b) - u(a) = -52.095, or we rearrange to get
u(a) - u(b) = 52.095 m/s
A 5.0-g object carries a net charge of 3.8 micro-Coulomb. It acquires a speed v when accelerated from rest through a potential difference V. A 2.0-g object acquires twice the speed under the same circumstances. What is its charge?
Answer:
The value is [tex]q_2 = 6.1 *10^{-6} \ C[/tex]
Explanation:
From the question we are told that
The mass of the object is [tex]m_1 = 5.0 \ g = 0.005 \ kg[/tex]
The net charge is [tex]q = 3.8 \mu C= 3.8 *10^{-6} \ C[/tex]
The mass of the second object is [tex]m_1 = 2.0 \ g = 0.002 \ kg[/tex]
Generally for the first object the potential energy gained at the end of its acceleration is equal to its kinetic energy
i.e
[tex]\frac{ 1}{ 2} * m_1 * v^2_1 = q_1 * \Delta V \ \ --- (1)[/tex]
Here [tex]v_1[/tex] is the velocity of the first object
[tex]\Delta V[/tex] is the potential difference through which it is accelerated
Generally for the second object the potential energy gained at the end of its acceleration is equal to its kinetic energy
i.e
[tex]\frac{ 1}{ 2} * m_2 * v^2_2 = q_2 * \Delta V[/tex]
Here [tex]v_2[/tex] is the velocity of the second object and from the question it is
[tex]v_2 = 2 v_1[/tex]
[tex]\Delta V[/tex] is the potential difference through which it is accelerated
So
[tex]\frac{ 1}{ 2} * m_2 * (2v)^2_1 = q_2 * \Delta V[/tex]
=> [tex]m_2 * 2v^2_1 = q_2 * \Delta V \ \ ---(2)[/tex]
Generally dividing equation 2 by equation 1
[tex]\frac{2m_2 v^2_1 }{ \frac{1}{2} * m_1 * v_1^2} = \frac{q_2 \Delta V }{ q_1 * \Delta V}[/tex]
=> [tex]q_2 = \frac{4m_2 * q_1 }{m_1}[/tex]
=> [tex]q_2 = \frac{4* 0.002 * 3.8 *10^{-6} }{0.005}[/tex]
=> [tex]q_2 = 6.1 *10^{-6} \ C[/tex]
=> [tex]q_2 = 6.1 *10^{-6} \ C[/tex]
A solid disk with a mass of 0.8 kg and a radius of 12cm is rotating at a rate of 2.6 rev/s. Another disk with half the mass and half the radius is dropped on top of the first disk. What is the new angular speed of both disks when they are rotating together?
Answer:
The new angular speed of both disks when they are rotating together is 2.311 revolutions per second.
Explanation:
This situation can be analyzed by the Principle of Conservation of Angular Momentum since there are no external forces and moments being exerted on the system, whose definition is presented below:
[tex]I_{o}\cdot \omega_{o} = I_{f}\cdot \omega_{f}[/tex] (1)
Where:
[tex]\omega_{o}[/tex], [tex]\omega_{f}[/tex] - Initial and final angular speeds, measured in revolutions per second.
[tex]I_{o}, I_{f}[/tex] - Initial and final moments of inertia, measured in kilograms per square meter.
The initial and final moments of inertia of the system are, respectively:
[tex]I_{o} = \frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}[/tex] (2)
[tex]I_{f} = \frac{1}{2}\cdot \left[m_{o}\cdot r_{o}^{2}+\frac{1}{2}\cdot m_{o}\cdot \left(\frac{1}{2}\cdot r_{o} \right)^{2}\right][/tex]
[tex]I_{f} = \frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}+\frac{1}{16}\cdot m_{o}\cdot r_{o}^{2}[/tex]
[tex]I_{f} = \frac{9}{16}\cdot m_{o}\cdot r_{o}^{2}[/tex] (3)
By applying (2) and (3) in (1), we obtain the following expression:
[tex]\frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}\cdot \omega_{o} = \frac{9}{16}\cdot m_{o}\cdot r_{o}^{2}\cdot \omega_{f}[/tex]
[tex]\frac{1}{2}\cdot \omega_{o} = \frac{9}{16}\cdot \omega_{f}[/tex]
[tex]\omega_{f} = \frac{8}{9}\cdot \omega_{o}[/tex] (4)
If we know that [tex]\omega_{o} = 2.6\,\frac{rev}{s}[/tex], then the new angular speed of both disks when they are rotating together is:
[tex]\omega_{f} = \frac{8}{9}\cdot \left(2.6\,\frac{rev}{s} \right)[/tex]
[tex]\omega_{f} = 2.311\,\frac{rev}{s}[/tex]
The new angular speed of both disks when they are rotating together is 2.311 revolutions per second.
What happens to the molecules of water when it moves from a liquid to a gas?
A. Water molecules condense and move slower.
B. Water molecules spread out and move slower.
C. Water molecules spread out and move faster.
D. Water molecules condense and move faster.
its A or D but im not sure which one ik it moves fast
What is the flash of light commonly associated with thunderstorms called?
a. Downdrafts
b. Updrafts
c. Return stroke
d. Thunder
e. Step-leader
Answer:
C.
Explanation:
Return stroke
A return stroke is termed to be the most visible part of a lightning, which in itself is accompanied by a thunderstorm. Lightning causes thunder, which like I said, is a sound from the shock wave that develops like gases in the areas of the discharge. While experiencing a sudden increase in its pressure. Lightning occurs naturally and is electrically charged.
The maximum electric field strength in air is 3.0 Mv/m . Stronger electric fields ionize the air and create a spark. What is the maximum power that can be delivered by a 1.5cm diameter laser beam propagating through air?
Answer:
The value is [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]
Explanation:
From the question we are told that
The maximized electric field strength is [tex]E = 3.0 \ MV/m = 3.0 *10^{6} \ V/m[/tex]
The diameter is [tex]d = 1.5\ cm = 0.015 \ m[/tex]
Generally the cross -sectional area is mathematically represented as
=> [tex]A = \frac{\pi * d^2 }{4}[/tex]
=> [tex]A = \frac{3.142 * 0.015^2 }{4}[/tex]
=> [tex]A = 0.0001767 \ m^2[/tex]
Generally the maximum power is mathematically represented as
[tex]P_{max} = \frac{E_{max}^2}{ 2 * \mu_o * c } * A[/tex]
Here c is the speed of light with value [tex]c = 3.0 *10^{8} \ m/s[/tex]
[tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4 \pi *10^{-7} \ H/m[/tex]
[tex]P_{max} = \frac{ (3.0 *10^{6})^2}{ 2 * (4 \pi *10^{-7}) * 3.0 *10^{8} } * 0.0001767[/tex]
=> [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]
The maximum power that can be delivered by a laser beam propagating through air is equal to [tex]2.11 \times 10^6\;Watts[/tex]
Given the following data:
Electric field strength in air = 3.0 Mv/m = [tex]3 \times 10^6\;v/m[/tex]Diameter = 1.5 cm to m = 0.015 meter.Radius = [tex]\frac{Diameter}{2} = \frac{0.015}{2} = 0.0075\;meter[/tex]
Scientific data:
Permeability of free space = [tex]1.25663706 \times 10^{-6}\;H/m[/tex]Speed of light = [tex]3 \times 10^8\;m/s[/tex]To determine the maximum power that can be delivered by a laser beam propagating through air:
First of all, we would solve for the area of the laser beam as follows:
[tex]Area = \pi r^2\\\\Area = 3.142 \times 0.0075^2\\\\Area = 3.142 \times 0.00005625\\\\Area = 1.77 \times 10^{-4}\;m^2[/tex]
Now, we can determine the maximum power that can be delivered by a laser beam:
Mathematically, maximum power is given by the formula:
[tex]P_{max} = \frac{AE_{max}^2}{2 \mu_o c}[/tex]
Substituting the given parameters into the formula, we have;
[tex]P_{max} = \frac{1.77 \times 10^{-4} \;\times \;(3 \times 10^6)^2}{2 \;\times \;1.25663706 \times 10^{-6} \; \times \;3 \times 10^8}\\\\P_{max} = \frac{1.77 \times 10^{-4} \;\times \;9 \times 10^{12}}{753.982236}\\\\P_{max} = \frac{1593000000}{753.982236}\\\\P_{max} = 2.11 \times 10^6\;Watts[/tex]
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A 96 kg man lying on a surface of negligible friction shoves a 75 g stone away from himself, giving it a speed of 7.2 m/s. What speed does the man acquire as a result?
Answer:
7.21m/s
Explanation:
Using the law of conservation of momentum expressed as;
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the mass of the man and the stone respectively
u1 and u2 are their respective initial velocities
v is their final common velocity
Given
m1 = 96kg
m2 = 75g = 0.075kg
u1 = ?
u2 = 0m/s (initial speed of the stone)
v = 7.2m/s
Substitute into the firmula and get u1
96u1 + 0.075(0) = (96 + 0.075)(7.2)
96u1 = 96.075(7.2)
u1 = 691.74/96
u1 = 7.21m/s
Hence the man acquired a speed of 7.21m/s
Drag each label to the correct location on the chart.
Sort the items based on whether they are simple machines or compound machines.
Answer:
whatttttttttttttttttttttttttttt are the items we have to classify into simple machines and compound machine
When an element ejects an alpha particle, the mass number of that element
A.reduce by 4.
B.remains unchanged.
C.increase by 1.
D. reduce by 1.
Answer:
A.reduce by 4.
Explanation:
In Chemistry, an alpha particle which is typically a helium nucleus has an atomic mass (number of nucleons) of four (4). Therefore, the ejection of an alpha particle by any chemical element simply means that, the mass number of that particular chemical element would be reduced by four (4).
Basically, this process is referred to as an alpha decay and can be defined as a radioactive disintegration of a chemical element that causes it to emit an alpha particle and as a result reducing its mass number by four (4).
Hence, when an element ejects an alpha particle, the mass number of that element reduces by 4.
A 10.0kg object is moving at 1 m/s when a force is applied in the direction of the objects motion, causing it to speed up to 4 m/s. If the force was applied for 5s what is the magnitude of the force
Answer:
F = 6[N].
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is conserved before and after applying a force to a body. We must remember that the impulse can be calculated by means of the following equation.
[tex]P=m*v\\or\\P=F*t[/tex]
where:
P = impulse or lineal momentum [kg*m/s]
m = mass = 10 [kg]
v = velocity [m/s]
F = force [N]
t = time = 5 [s]
Now we must be clear that the final linear momentum must be equal to the original linear momentum plus the applied momentum. In this way we can deduce the following equation.
[tex](m_{1}*v_{1})+F*t=(m_{1}*v_{2})[/tex]
where:
m₁ = mass of the object = 10 [kg]
v₁ = velocity of the object before the impulse = 1 [m/s]
v₂ = velocity of the object after the impulse = 4 [m/s]
[tex](10*1)+F*5=10*4\\10+5*F=40\\5*F=40-10\\5*F=30\\F=6[N][/tex]
what would the net force be on the box in the problems shown below.( both force and direction).
Answer:
4
Explanation:
The net force on the box a will be 20 N to the left and that on box b is 6 N downwards. The net force on box c is 90 N to the left and that on box d is zero.
What is net force?Force is an external agent acting on a body to change its motion or to deform it. The net force acting on a body depends on all the the forces with their magnitudes and directions.
If two same or different forces acts from the same direction they will add up and net force will be their sum. If they acts from the different directions, they will cancel each other in magnitudes.
In box a, the equal forces of 20 N opposes from each direction cancel and the net force will be 20 N to the left. I box b the 15 N cancel each other. Where the 4N and 2 N add up to have net force of 6 N downwards.
In box c, 10 N from opposite direction cancels and the 60 N and 30 N to the left add ups to have the net force of 90 N to the left. On box d, 5 N from opposite directions cancels as 12 N. Hence, net force is zero.
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An observer sitting on shore sees a canoe traveling 5.0 m/s east, and a sailboat traveling 15.0 m/s west. What is the velocity of the sailboat as observed on the canoe (relative to the canoe)?
Answer:
Vs/c = 20 [m/s]
Explanation:
This is a problem of relative velocities, as velocity is a vector we can use addition or subtraction of vectors for the solution.
We are asked for the velocity of the sailboat with respect to an observer located in the canoe.
[tex]V_{s/c}=V_{sailboat}-V_{canoe}\\V_{s/c}=15-(-5)\\V_{s/c}=20[m/s][/tex]
Why is the speed of the canoe negative?, it is negative because the canoe moves in the opposite direction to the sailboat.
A car starts from point A, goes 100 km to point B, immediately turns around, and returns to point A. The round trip takes 4 hours.
What is the average speed of the car?
Answer:
50 km/h
Explanation:
200 km = 4 hours
200/4=50
50km/h
I need help ASAP!
1. Two wave pulses move towards each other as shown below. The pulses have the same width and amplitudes.
What is the resulting wave pattern when the centers of the two pulses meet?
Answer:
b.
Explanation:
The resulting wave pattern when the centers of the two pulses meet is undergo constructive interference.
When two waves meet?Waves are pulses of energy that propagate through space periodically. When two waves overlap in the same region of space, interference occurs, which results in another wave with different intensity. These variations in the intensity of the resulting wave are called interference fringes.
The two pulses propagate with the same phase and in opposite directions, when they meet, they suffer constructive interference, which will cause the sum of the amplitudes. After interference, each wave goes its way as if nothing happened.
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When a object is electrically charged, ____ have been added or removed.
A) Neutrons
B) Electrons
C)Protons
Answer:
B, electrons.
Explanation:
An electrical charge is created when electrons are transferred to or removed from an object. Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.
TRUE/FALSE, the scientific question is written like “I wonder if [dependent variable] is affected by [independent variable].”
what is mean by combination reaction ?
[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]
Those reaction in which two or more substances combine to form a one new substance are called Combination reaction
In this reaction, We can add :
Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.[tex] \underline{\green{\large \sf For\: example :}} [/tex]
[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]
In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.
A 300 kg piano needs to be moved to the other side of the room. The maximum static frictional force is equal to 90 N and the kinetic frictional force is equal to 70 N. Calculate the acceleration of the piano for an applied force of 100 N.
Answer:
a = 0.1 m/s²
Explanation:
If the maximum static frictional force is 90 N, this means that any applied force that will overcome this force, will cause the piano to slide, so kinetic frictional force applies.Under these conditions, the net force in the horizontal direction is just the difference between the applied force (which is larger that the static friction force) and the kinetic frictional force, as follows:[tex]F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)[/tex]
By the same token, according Newton's 2nd Law, this force is just equal to the product of the mass of the piano, times the acceleration, as follows:[tex]F_{net} = m* a = 300 Kg * a = 30 N (2)[/tex]
Solving for a:[tex]a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)[/tex]
Help me please
What is the shape of the velocity vs time graph for an object going at constant speed?
A- A curve that rises gradually to the right
B- A curve that decreases gradually to the right
C- A straight line that rises gradually to the right
D- A strait line that decreases gradually to the right
E- A straight line that is level and neither increases or decreases going to the right
Answer: a or b can u pls give me brainlest
Explanation:A straight line is a curve with constant slope. Since slope is acceleration on a velocity-time graph, each of the objects represented on this graph is moving with a constant acceleration.
32. Which type of electromagnetic wave is used for nuclear power and medical treatment?
A. UV wave
B.Radio wave
C.Visible light wave
D. Gamma ray
Which of the following is a way that microwaves and x-rays are similar?
A. They both have technological uses.
B. They are both high energy waves,
C. They are both safe to be exposed to at high doses
D. They are both used to transmit information.
Answer:
Answers at the bottom!!
Explanation:
For the first answer: Gamma ray
Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.
For the second answer: They both have technological uses.
In my opinion I'm pretty sure it's A because we do use microwaves and x-rays as technological uses.
Hope this helps!!
Happy Holidays and Season Greeting!!
ii Feliz Navidad a todos !!
Gamma rays and x-rays consist of high-energy waves that can travel great distances at the speed of light and generally have a great ability to penetrate other materials. For that reason, gamma rays (such as from cobalt-60) are often used in medical applications to treat cancer and sterilize medical instruments.
What are gamma rays ?"A gamma ray (g) is a packet of electromagnetic energy (photon) emitted by the nucleus of some radionuclides following radioactive decay." Gamma photons are the most energetic photons in the electromagnetic spectrum.
What are x-rays ?"An X-ray, or, much less commonly, X-radiation, is a penetrating form of high-energy electromagnetic radiation." Most X-rays have a wavelength ranging from 10 picometers to 10 nanometers, corresponding to frequencies in the range 30 petahertz to 30 exahertz and energies in the range 145 eV to 124 keV.
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They both have technological uses.
Microwaves and x-rays have in common is all electromagnetic waves, electric and magnetic fields that oscillate together, perpendicular to each other.
What is technological usage?
"The application of practical sciences to industry or commerce." The methods, theory, and practices governing such application. a highly developed technology. The total knowledge and skills available to any human society for industry, art, science, etc.
What are technological uses of microwave and x-ray ?Microwaves are used in spacecraft communication, and much of the world's data, TV, and telephone communications are transmitted long distances by microwaves between ground stations and communications satellites. Microwaves are also employed in microwave ovens and in radar technology.
They are used on such products as aircraft and rocket parts and structures, canned and packaged foods, electronics, semiconductors and microchips, thermal insulations, and automobile tires. Material processing technologies use X-ray systems to automatically control the density or thickness of layers of substances.
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