At room temperature the unit cell for this material is triclinic is 1 unit/cell.
What is the unit cell?In the problem statement we are given the following equation and information:
V = abc * sqrt(1 - cos^2 alpha - cos^2 beta - cos^2 gamma + 2cos alpha * cos beta * cos gamma)
= (0.497)(0.547)(1.729) √1 - cos2 48.4 - cos² 76.7 - cos² 62.5 + 2 cos 48.4 cos 76.7 cos 62.5
= 0.31n * m ^ 3
Next calculate the repeat unit weight for Nylon 6,6
m = 12A_{C} + 22A_{H} + 2A_{O} + 2A_{N}
= 12(12.01) + 22(1) + 2(16) + 2(14.01)
= 226.14g / m * ol
We can now calculate the number of repeat units per a unit cell. However we must convert V from n * m ^ 3 to c * m ^ 3 which results in V = 3.1 * 10 ^ - 22
n = (rho*VN)/m
= (1.213(3.1 * 10 ^ - 22)(6.02 * 10 ^ 23))/226.14
1 unit/cell.
The complete question is The density of totally crystalline nylon 6,6 at room temperature is 1.213g / c * m ^ 3 Also, at room temperature the unit cell for this material is triclinic with lattice parameters:
a = 0.497nm c = 48.4 deg
b = 0.547nm beta = 76.6 deg
c = 1.729nm y = 62.5 deg
If the volume of a triclinic unit cell, V tr i prime is a function of these lattice parameters as
V tri =abc sqrt 1-cos^ 2 a-cos^ 2 beta-cos^ 2 gamma+2 cos a cos beta cos gamma
determine the number of repeat units per unit cell.
Click on the link to access Table 4.3.
Atomic weights for several elements are included in the following table:
Carbon 12.01 g/mol
Chlorine 35.45 g/mol
Fluorine 19.00 g/mol
Hydrogen 1.008 g/mol
Oxygen 16.00 g/mol
Nitrogen 14.01 g/mol
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High level security concerns for Cloud computing may include: o Work on the tools and controls to put in place first, then take the time to establish your overall security strategy. o Finding ways to overcome the lack of security visibility in the Cloud, especially considering the sheer number of layers, tools and controls. o Effectively managing identity and defining access management, including the privileges and responsibilities of various network admins and users. o Consider the confidentiality aspects regarding your requirements for data encryption in transit and at rest balancing cost and risk. o Requiring the appropriate level of availability should be balanced regarding cost, risk and recovery these may be impacted by physical location and physical access.
o Integration strategy regarding APIs that should include a requirement to implement string encryption, activity monitoring, and access control. o Implementing a cloud-based enterprise will help guarantee regulatory compliance since the "shared responsibility model" makes much easier to meet CCPA, PCI-DSS and GDPR privacy mandates. o Strong cloud security policies can be integrated into the IT processes that teams use to build applications and deploy in the cloud infrastructure.
As CCPA, PCI-DSS, and GDPR privacy standards are greatly simplified by the "shared responsibility model," implementing a cloud-based enterprise security will assist ensure regulatory compliance.
By limiting other people's options, security is the capacity to tolerate potential harm from them. Security is advantageous to individuals, social groups, things, organizations, ecosystems, and any other phenomenon or institution that is vulnerable to unwelcome change. 2015 saw the assistance of Spanish volunteers in assisting refugees fleeing war and instability in Syria and Iraq to reach Lesbos Island. Security can indicate a number of other things in addition to defending against hostile forces, including the absence of harm, the presence of an essential good, resistance against potential damage or injury, concealment, containment, and even a state of mind. The phrase is sometimes utilized to describe structures and acts.
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refer to the exhibit. an engineer issued the ping 192.168.3.100 command from r1, and the ping was successful. are there any routes that would not be verified as working by that successful ping?
Yes, the static route for 192.168.2.0 is incorrectly configured.
What is a static route?Static routing is a routing method that requires manual configuration. The majority of network managers follow static routing. In areas with consistent network and environmental characteristics, this routing will be heavily used.
Static routing is fixed and unaffected by network changes, in contrast to dynamic routing. It is used on a router to increase routing effectiveness and to act as a fallback in case other data cannot be shared.
It takes advantage of the routes that connect the two routes, which are not immediately updatable. As a result, whenever the network changes, static routes must be manually reconfigured. Compared to dynamic maps, it takes little bandwidth. It can be applied to situations where network traffic is planned and predictable.
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a byte-addressable main memory of size 256mb with blocks of 32 bytes in size. the cache memory can hold up to 64 blocks
The main memory can hold a total of (256 * 1024 * 1024) / 32 = 8,388,608 blocks.
What are main and cache memory?he main memory in this system has a size of 256 megabytes, which is equal to 256 * 1024 * 1024 bytes. With blocks of 32 bytes in size, this means that the main memory can hold a total of (256 * 1024 * 1024) / 32 = 8,388,608 blocks.
The cache memory, on the other hand, can hold up to 64 blocks. This means that it can store a small fraction of the data that is stored in the main memory. In order to access data that is not stored in the cache, the system must fetch it from the main memory, which takes longer than accessing data directly from the cache.
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The principal disadvantages(s) with the waterfall development methodology is (are) _____.
a. a long time elapses between completion of the system proposal and the delivery of the system
b. if the team misses important requirements, expensive post-implementation programming may be needed
c. the design must be completely specified on paper before programming begins
d. all of the above
e. none of the above
Note that the principal disadvantage (s) with the waterfall development methodology is (are) "All the Above" (Option D).
What is the Waterfall Development Methodology?The Waterfall Development Methodology is a process for creating software that involves a series of steps that are followed in a specific order. It is called the "waterfall" method because each step flows into the next, like water flowing down a waterfall.
The first step in the Waterfall Development Methodology is to gather requirements, which means figuring out what the software should do. Next, a design is created, which outlines how the software will look and work. Then, the software is actually developed, which means writing the code and creating the software. After that, the software is tested to make sure it works correctly and any problems are fixed. Finally, the software is deployed, which means it is made available for people to use.
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Construct a Turing machine that generates all strings in reverse lexicographic order between the two provided strings X and Y. An input will be of the form "X,Y", where X is an element of {0, 1, 2}+ and Y is an element of {0, 1, 2}*. Your Turing machine must be a single tape, one way infinite, deterministic Turing machine. For this program you can use the left, right, and stay directives. When the Turing machine completes, the tape should contain a comma delimited list of all strings over {0, 1, 2}* in reverse lexicographic order starting with X and ending with Y. When your program completes it should accept the input and position the r/w head at the leftmost symbol of X.
The complete program regarding the quetions below
State q0:
Read 0: Move right and go to q0.
Read 1: Move right and go to q1.
Read 2: Move right and go to q2.
State q1:
Read 0: Move right and go to q1.
Read 1: Move right and go to q2.
Read 2: Move right and go to q3.
State q2:
Read 0: Move right and go to q2.
Read 1: Move right and go to q3.
Read 2: Move right and go to q4.
State q3:
Read 0: Move right and go to q3.
Read 1: Move right and go to q4.
Read 2: Move right and go to q5.
State q4:
Read 0: Move right and go to q4.
Read 1: Move right and go to q5.
Read 2: Move right and go to q6.
State q5:
Read 0: Move right and go to q5.
Read 1: Move right and go to q6.
Read 2: Move right and go to q7.
State q6:
Read 0: Move right and go to q6.
Read 1: Move right and go to q7.
Read 2: Move right and go to q8.
State q7:
Read 0: Move right and go to q7.
Read 1: Move right and go to q8.
Read 2: Move left and go to q7.
State q8:
Read 0: Move left and go to q8.
Read 1: Move left and go to q7.
Read 2: Move left and go to q6.
State q9:
Read 0: Move left and go to q9.
Read 1: Move left and go to q8.
Read 2: Move left and go to q5.
State q10:
Read 0: Move left and go to q10.
Read 1: Move left and go to q9.
Read 2: Move left and go to q4.
State q11:
Read 0: Move left and go to q11.
Read 1: Move left and go to q10.
Read 2: Move left and go to q3.
State q12:
Read 0: Move left and go to q12.
Read 1: Move left and go to q11.
Read 2: Move left and go to q2.
State q13:
Read 0: Move left and go to q13.
Read 1: Move left and go to q12.
Read 2: Move left and go to q1.
State q14:
Read 0: Move left and go to q14.
Read 1: Move left and go to q13.
Read 2: Move left and go to q0.
State q15:
Read 0: Move left and go to q15.
Read 1: Move left and go to q14.
Read 2: Stay in q15.
State q16:
Read 0: Print 0 and move left until the end of the string Y.
Read 1: Print 1 and move left until the end of the string Y.
Read 2: Print 2 and move left until the end of the string Y.
State q17:
Read 0: Print 0 and move left and go to q16.
Read 1: Print 1 and move left and go to q16.
Read 2: Print 2 and move left and go to q16.
What is program?
Program is a set of instructions that a computer can execute in order to carry out a specific task. Programs can range from simple ones, like a calculator, to complex ones, like a 3D modeling software. Programs are written in a programming language, such as Java or Python, and they are needed in order for a computer to understand how to carry out a job. Programs can also be broken down into smaller, more manageable chunks known as subprograms. Each subprogram is written with specific instructions that the computer can understand and execute
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Air at standard conditions flows steadily at low speed through a horizontal nozzle, discharging to atmosphere, where the pressure is Patm, meaning P2 = Patm. Inlet and exit areas of the nozzle are A1 = 0.10 m2 and A2 = 0.02 m2 , respectively.
Calculate the pressure required at the nozzle inlet, meaning P1, to yield an exit speed of 50 m/s.
Using Bernoulli equation we can say that the pressure required at the nozzle inlet, meaning P1, to yield an exit speed of 50 m/s is 1.48 kPa.
How do we calculate the pressure required at the nozzle inlet using Bernoulli equation?equations that control:
[tex]\frac{p_{1}}{\rho}+\frac{V_{1}^{2}}{2}+g z_{1}=\frac{p_{2}}{\rho}+\frac{V_{2}^{2}}{2}+g z_{2}[/tex]
Continuity for incompressible and uniform flow:
[tex]\sum_{\mathrm{CS}} \vec{V} \cdot \vec{A}=0[/tex]
We know that
1) Steady flow.
(2) Incompressible flow.
(3) Frictionless flow.
(4) Flow along a streamline.
(5)[tex]z_{1}=z_{2}[/tex]
(6) Uniform flow at sections (1) and (2).
The maximum speed of 50 m/s is well below 100 m/s, which corresponds to Mach number M≈0.3 in standard air. Hence, the flow may be treated as incompressible.
Apply the Bernoulli equation along a streamline between points (1) and (2) to evaluate [tex]p_{1}[/tex]
p1 − patm = p1 − p2 = ρ/2 (V2^2 −V1^2)
-ρV₁A₁ + ρV₂A₂ = 0 or V₁A₁ = V₂A₂
V₁ = V₂A₂/A₁ = 50 x 0.02/0.10 = 10 m/s
Since air at standard condition , ρ = 1.23 kg/m³
p1 − patm = ρ/2. (V₂²^2−V₁^²)
= 1/2 × 1.23 x (50² −10²)
= 1.48kPa
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you are using the vi editor to manage a text file on a linux system. you want to type new text into the file. when you type, you want the existing text that comes after the cursor to be pushed down.
The insert mode is used to type new text into the file in linux system.
What is insert mode in linux system?When inserting text into a file, you should be in insert mode. Command mode is the mode to be in when issuing commands such as moving the cursor, deleting text, copying and pasting, saving the file, and so on. Vi is in command mode when you open a file. Insert mode is required to enter text.In Insert mode, you can enter text, use the Enter key to move to a new line, navigate text with the arrow keys, and use vi as a free-form text editor. Press the Esc key once to return to Command mode.In vi, there are three modes of operation:
Mode of Command: When you launch vi, it is in Command Mode.Insert mode: You can insert text into the file using this mode.Last Line Mode (Escape Mode): While in Command Mode, type a colon [:] to enter Line Mode.The complete question:
"You're using the vi editor to manage a text file on a Linux system. You want to type new text into the file; when you type you want the existing text that comes after the cursor to be pushed down?
What mode do you need to be in to do this?"
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using the data below, what is the value of the mean absolute percent error (mape)? week time series value forecast 1 17 18.00 2 25 20.00 3 14 15.00 4 23 14.00
The value of the mean absolute percent error (mape)
What is mean?
Mean is an average value calculated by adding a set of numbers and then dividing by the number of items in the set. It is a measure of central tendency in a set of data and is often used to describe the overall trend or pattern in the data. Mean can also be used to compare sets of data and is often used to compare the performance of different groups of people or businesses.
The mean absolute percent error (MAPE) is a measure of the accuracy of a forecast. It is calculated by taking the mean of the absolute percent errors (the difference between the forecast and the actual value), divided by the mean of the actual values.
For the given data, the MAPE is calculated as follows:
MAPE = (|18.00 - 17| + |20.00 - 25| + |15.00 - 14| + |14.00 - 23|)/(17 + 25 + 14 + 23) = 0.30
Therefore, the mean absolute percent error (MAPE) for the given data is 0.30.
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Consider the following method. public static void addOneToEverything(int[] numbers) { for (int j = 0; j < numbers.length; j++) { numbers[j]++; } } Which of the following code segments, if any, can be used to replace the body of the method so that numbers will contain the same values? I. for (int num : numbers) { num++; } II. for (int num : numbers) { num[j]++; } III. for (int num : numbers) { numbers[num]++; } A I only B I and III only C II and III only D I, II, and III E None of the code segments will return an equivalent result. E None of the code segments will return an equivalent result
The code segments, if any, can be used to replace the body of the method so that numbers will contain the same values is E None of the code segments will return an equivalent result
What is an array?Using an entire set of values at once is possible with array programming, a technique used in computer science. These answers are frequently applied in scientific and engineering contexts. A data structure called an array consists of a set of elements (values or variables), each of which is identified by an array index or key.
Depending on the language, other data types that describe aggregates of values, like lists and strings, may overlap (or be identified with) array types. An array is a grouping of identically-typed elements that are stored in consecutive memory locations and can each be individually referred to using an index to a special identifier.
Based on the information, it should be noted that none of the code will return the same result as all the codes does not assign correct values to array.
Therefore, based on the information, the correct option is E.
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Some Linux systems use the __________________ script to perform the same actions each time a user logs out of her account.a. .bash_logoutb. .bash_rcc. /bin/bashoutd. /etc/logoff_bash
The bash rcc script is used by some Linux systems to carry out the same tasks each time a user logs out of her account.
The Linux family of open-source Unix-like operating systems is based on the Linux kernel, which Linus Torvalds initially made available on September 17, 1991. Linux distributions, which are how Linux is commonly packaged, frequently include the kernel and other system-supporting programmes and libraries, many of which are made available by the GNU Project. Although the Free Software Foundation likes to refer to their operating system as "GNU/Linux" to emphasise the importance of GNU software, many Linux versions have the term "Linux" in their names. This has caused some controversy. The most well-known Linux distributions are Debian, Fedora Linux, and Ubuntu. Lubuntu and Xubuntu are just two of the many distributions and modifications that make up Ubuntu.
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the operation of marine transportation determines the efficiency ofmoving goods. the progress in terminals, technologies and management principles improves the moving load, delivery speed in g
The movement of persons or cargo across waterways is referred to as marine transportation. The company that offers water transportation is called Marine Transport Management, Inc.
How significant is maritime transportation?International trade and the world economy are based on maritime transportation. The number is significantly higher for the majority of poor nations, where shipping accounts for over 80% of all international trade in products. Since 1968, UNCTAD has released the Review on Maritime Transport, which is its flagship report.
Operations and management in the maritime sector are what?The primary goal of this program is to equip you with the knowledge and abilities needed to land prestigious jobs in the offshore and maritime sectors. You will develop the self-assurance necessary for a senior position in the maritime industry in the interpersonal and cross-cultural competencies.
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an example of architecture with similar features to the persian fire temple pavilion featured in lecture was this early islamic tomb. tomb of ahmed
Tomb of ahmed is an example of architecture with similar features to the persian fire temple pavilion featured in lecture was this early islamic tomb.
Some information about Ahmad's Tomb:
Ahmad Shah's tomb, also known as Raja no Hajiro and Badshah no Hajiro (King's Mausoleum), is a collection of tombs built during the Medieval period in Ahmedabad. He is widely regarded as the founder of Ahmedabad, Gujarat. The exquisite artwork and architectural extravagance set the tomb apart from other tourist attractions and establishes it as a gold standard in Indian architecture.
Expectations when visiting Ahmad Shah's Tomb:
1. Ahmad Shah's tomb is one of Ahmedabad's most important tourist attractions.
2. The tomb is square in shape and has stone windows with lattice work. Women, on the other hand, are still not permitted in the central chamber of Ahmad Shah's Tomb.
3. Across the street is the Rani no Hajira, which houses the tombs of Ahmad Shah's queens. The tomb is in excellent condition, but the tombs of the queens have deteriorated.
4. Ahmad Shah's tomb is one of Ahmedabad's architectural wonders.
5. The artistic craftsmanship, latticed windows, and domes and minarets give the Tombs of Ahmad Shah an exquisite appearance. This tomb in Ahmedabad is a must-see for anyone interested in Mughal art and culture.
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Five telemetry signals, each of bandwidth 240 Hz, are to be transmitted simultaneously by binary PCM. The signals must be sampled at least 20% above the Nyquist rate. Framing and synchronizing requires an additional 0.5% extra bits. A PCM encoder is used to convert these signals before they are time-multiplexed into a single data stream. Determine the minimum possible data rate (bits per second) that must be transmitted, and the minimum bandwidth required to transmit the multiplex signal.
To determine the minimum data rate and minimum bandwidth required to transmit the multiplex signal, we need to first determine the minimum sampling rate required to sample each of the telemetry signals. The Nyquist rate is defined as half the bandwidth of the signal, so the Nyquist rate for each telemetry signal is 120 Hz. To sample at least 20% above the Nyquist rate, we need to sample at a rate of at least 120 Hz * 1.2 = 144 Hz.
Since there are 5 telemetry signals, the total number of samples per second is 5 * 144 = 720 samples/s. Since the signals are being encoded using binary PCM, each sample will require 1 bit to represent it. This means that the minimum data rate required to transmit the multiplex signal is 720 samples/s * 1 bit/sample = 720 bits/s.
To determine the minimum bandwidth required to transmit the multiplex signal, we need to consider the bandwidth required for the 5 telemetry signals as well as the additional bandwidth required for framing and synchronization. The total bandwidth required for the telemetry signals is 5 * 240 Hz = 1200 Hz. The additional bandwidth required for framing and synchronization is 1200 Hz * 0.5% = 6 Hz. The total minimum bandwidth required to transmit the multiplex signal is 1200 Hz + 6 Hz = 1206 Hz.
The maximum pace of data flow along a particular path is referred to as bandwidth in computing. Network bandwidth, data bandwidth, and digital bandwidth are three different types of bandwidth.
Contrary to this definition, bandwidth is used to refer to analog signal bandwidth measured in hertz, which is the frequency range between the lowest and highest attainable frequency while meeting a well-defined impairment level in signal power in the fields of signal processing, wireless communications, modem data transmission, digital communications, and electronics.
The actual bit rate that may be obtained is influenced by the channel noise as well as the signal bandwidth.
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