The difference in loudness between the sound made by a blue whale and a human is 120 decibels.
The difference in the loudness of the sounds made by a blue whale and a human.The loudest sound a human can make is measured at about 140 decibels, while the sound a blue whale can make is measured at about 260 decibels. This means that the blue whale can produce a sound that is 1 million times greater in intensity than the loudest sound a human can make. This difference in loudness is equal to 120 decibels.
The difference in loudness between the sound made by a blue whale and a human is 120 decibels. The loudest sound a human can make is measured at about 140 decibels, while the sound a blue whale can make is measured at about 260 decibels. This means that the blue whale can produce a sound that is 1 million times greater in intensity than the loudest sound a human can make.
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if the 2 currents are same direction and forces are attractive, what is the direction of force wire 1 on wire 2
The direction of the force from wire 1 on wire 2 is attractive, as the two currents are in the same direction.
If two currents are flowing in the same direction and the forces between the wires are attractive, then the direction of the force on wire 2 due to wire 1 will be towards wire 1. This is because the magnetic field created by the current in wire 1 will induce a magnetic field in wire 2, and the interaction between these two magnetic fields will result in an attractive force between the wires.
In summary, if two currents are flowing in the same direction and the forces are attractive, the direction of the force on wire 2 due to wire 1 will be towards wire 1.
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amanda weighs about 600 n on earth, but would only weigh about 100 n on the moon. which best explains why amanda would weigh less on the moon than on earth? A. the mass of the moon is less than that of earth, therefore it has a weaker gravitational force. B. the circumference of the moon is smaller than earth, therefore it has less gravity. C. the pull from the gravity from earth decreases the pull of gravity from the moon. D. the lack of air pressure on the moon weakens the gravitational force of the moon.
Option A is the correct answer. The mass of the moon is less than that of earth, therefore it has a weaker gravitational force.
The correct option that explains why Amanda would weigh less on the moon than on earth is "A. the mass of the moon is less than that of the earth, therefore it has a weaker gravitational force." This is because weight is the result of the gravitational force that acts on an object, which is determined by both the mass of the object and the gravitational force acting on it. Therefore, the weight of an object varies depending on the mass and gravity.
The gravity of an object is the force that attracts it towards the center of the earth or the celestial object. The amount of gravity an object has depends on its mass and the mass of the object that it is attracting. The moon has a smaller mass than the earth, which means that it has a weaker gravitational force.
Consequently, the pull of gravity on the moon is weaker than on earth. The weight of Amanda is less because pull of gravity on the moon is weaker than on earth. Therefore, option A is the correct answer.
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if two identical resistors are connected in series to a battery, does the battery have to supply more power or less power than when only one of the resistors is connected? explain
The battery has to supply more power when two resistors are connected in series than when only one resistor is connected. This is because the power dissipated in a series circuit is equal to the sum of the power dissipated in each resistor.
When two identical resistors are connected in series to a battery, the battery has to supply more power than when only one of the resistors is connected. This is because the resistors offer resistance, which results in the dissipation of energy as heat. The higher the resistance of a resistor, the more power it requires to operate.Resistors consume energy as they offer resistance to the flow of current. The power supplied by the battery is converted to heat energy in the resistor, and the amount of heat energy dissipated is determined by the resistance of the resistor. The greater the resistance of the resistor, the more power it requires to function.
As a result, when two identical resistors are connected in series to a battery, the battery has to supply more power than when only one of the resistors is connected, to produce the same current through the circuit. Therefore, if two resistors of equal value are connected in series, the total power dissipated is twice that of when a single resistor is connected.
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help me
plss asap!!!
Answer:B
Explanation:The ray above makes a 90 degree angle. The ray below makes a 60 degree angle.
What gauge pressure must a pump produce to pump water from the bottom of Grand Canyon (elevation 730 m) to Indian Gardens (elevation 1370 m)? Express your results in pascals and in atmospheres.
The gauge pressure that a pump must produce to pump the water from the bottom of Grand Canyon to Indian Gardens is about 627080 pascals and 6.17 atm.
What is the gauge pressure?The difference in elevation of the two points = 1370 - 730 = 640m
Density of water, `ρ` = 1000 kg/m³
g = 9.8 m/s²
The gauge pressure must a pump produce to pump water from the bottom of Grand Canyon (elevation 730 m) to Indian Gardens (elevation 1370 m).
Formula used: `P = ρgh`
where, `P` is pressure, `ρ` is density of water, `g` is acceleration due to gravity, `h` is height difference between the two points.
The gauge pressure that must a pump produce to pump water from the bottom of Grand Canyon to Indian Gardens is 627080 Pa and 6.17 atm.
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1. I’m in the 2nd column, 4th row, and I’m a metal. Who am I? ________________ 2. I’m a very lonely nonmetal. Who am I? ____________ 3. I’m the only metal who is a liquid at room temperature. Who am I? ____________ 4. I’m named after the person who created the 1st Periodic Table. Who am I? ___________ 5. I have 92 protons. Who am I? _____________ 6. I’m the only nonmetal who is a liquid at room temperature. Who am I? ___________ 7. I’m named after a very famous scientist. Who am I? ___________ 8. I have 46 electrons. Who am I? ____________ 9. My atomic mass is 183. 84. Who am I? _____________ 10. My chemical symbol is Ag. Who am I? ________________ 11. I’m the only metalloid in period 3. Who am I? ___________ 12. I’m the only element that is solid and a nonmetal in group 14. Who am I? _____________ 13. I have 5 neutrons. Who am I? ____________ 14. I’m the only gas at room temperature that is in group 16. Who am I? ___________ 15. I have 68 protons. Who am I? __________ 16. What element has the chemical symbol of Ir? ______________ 17. Which element is in group 7 and has 30 neutrons. Who am I? ___________ 18. I’m the only metal in group 15. Who am I? ____________ 19. I have 88 electrons. Who am I? ___________ 20. I’m the only gas at room temperature and in period 5. Who am I? ____________ 21. My symbol is Am. Who am I? ______________ 22. I’m the only nonmetal in period 6. Who am I? ____________ 23. My atomic number is 69. 723. Who am I? _________________ 24. I have 159 neutrons. Who am I? ________________ 25. I’m the only metalloid in group 17. Who am I? ______________ 26. I have 50 electrons. Who am I? __________________ 27. I’m in the 1st group and the 4th period. Who am I? ________________ 28. I’m a metalloid whose symbol is Sb. Who am I? ______________ ©JFlowers2017 Name: ______________________________ Date: ___________Class: ________ Periodic Table Scavenger Hunt Directions: You will use the Periodic Table to answer the questions. 1. I’m in the 17th column, a nonmetal, & a solid at room temperature. Who am I? ________________ 2. I have 79 electrons. Who am I? ____________ 3. I’m the only gas in period 6. Who am I? ____________ 4. My atomic mass is 257. Who am I? ___________ 5. My chemical symbol is Hs. Who am I? _____________ 6. I have 114 neutrons. Who am I? ___________ 7. I’m in the 18th group and 2 nd period. Who am I? ___________ 8. I have 67 protons. Who am I? ____________ 9. I’m a nonmetal who is solid at room temperature & has 2 letters for my symbol. Who am I? _________ 10. I’m in the 1 st group & 7 th period. Who am I? ________________ 11. I’m the only metalloid in group 13. Who am I? ___________ 12. I have 97 electrons. Who am I? _____________ 13. I am the only gas in column 15. Who am I? ____________ 14. My name is similar to Mickey Mouse’s best friend. Who am I? ___________ 15. I’m in group 11 & period 4. Who am I? __________ 16. I have 62 protons. Who am I? ______________ 17. My name fits really well with doctors because they try to do this. Who am I? ___________ 18. My name reminds me of where we all live. Who am I? ____________ 19. I’m the only nonmetal in period 2. Who am I? ___________ 20. My atomic number is 87. 62. Who am I? ____________ 21. My symbol is Mt. Who am I? ______________ 22. I’m in group 17 & the only metalloid. Who am I? ____________ 23. I have 71 electrons. Who am I? _________________ 24. My symbol is Pd. Who am I? ________________ 25. I’m Dorothy’s friend who needed a heart. Who am I? ______________ 26. I have 41 protons. Who am I? __________________ 27. I have 125 neutrons. Who am I? ________________ 28. My name comes from the 8th planet. Who am I? ______________
The Periodic Table of Elements served as the inspiration for this scavenger hunt. The exercise consists of two sets of questions, each of which has 28 questions that must be answered using the Periodic Table.
Students are tasked with identifying elements in the first set of questions using information from their attributes, such as the element's position on the periodic table, atomic mass, or quantity of electrons, protons, or neutrons. The objectives of the questions are to familiarise students with the properties of various elements and the structure of the Periodic Table. The second series of questions is comparable to the first, but more difficult because it asks students to identify components using less obvious cues, like their chemical symbol or a chemical formula. In order to succeed in their future studies of chemistry and other related sciences, students will benefit from being more familiar with the structure of the periodic table and the characteristics of various elements.
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A piece of metal weighing 187.6 g is placed in a graduated cylinder containing 225.2 mL of water. The combined volume of solid and liquid is 250.3 mL. What is the density, in grams per milliliter, of the metal?
The density of the metal in grams per milliliter is 7.87 g/mL.
Given data:The weight of metal, W = 187.6 g,Volume of water, V₁ = 225.2 mL.
The combined volume of solid and liquid, V₂ = 250.3 mL
Volume of the metal can be calculated as:Volume of metal = V₂ - V₁= 250.3 - 225.2= 25.1 mL
The density of the metal can be calculated as:Density = Weight of metal / Volume of metal
Density = W / V= 187.6 g / 25.1 mL= 7.87 g/mL
Thus, the density, in grams per milliliter, of the metal is therefore calculated and found to be 7.87 g/mL.
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for an hst with a 2 cir pump and a 3.36 cir motor, what is the speed ratio if the volumetric efficiency of the pump is 93.5% and the volumetric efficiency of the motor is 92.1%?
The speed ratio if the volumetric efficiency of the pump is 93.5% and the volumetric efficiency of the motor is 92.1% is 0.898, which is approximately 0.90.
Given the volumetric efficiency of the pump and the volumetric efficiency of the motor, the speed ratio is to be determined using the formula:
Speed Ratio = Actual Flow Rate * 231 / (Pump Displacement x Pump RPM)
The formula for the volumetric efficiency is:
Volumetric efficiency = (Actual Flow Rate / Theoretical Flow Rate) * 100
Theoretical Flow Rate = Pump Displacement x Pump RPM
The actual flow rate is equal to the theoretical flow rate multiplied by the volumetric efficiency divided by 100.Thus,
Actual Flow Rate = Pump Displacement x Pump RPM x (Volumetric Efficiency / 100)
Speed Ratio = Actual Flow Rate * 231 / (Pump Displacement x Pump RPM) = (Pump Displacement x Pump RPM x (Volumetric Efficiency / 100)) * 231 / (Pump Displacement x Pump RPM) = (Volumetric Efficiency / 100) * 231 = 93.5 / 100 * 231 = 215.985
Speed Ratio = 215.985 / 240 = 0.898 ≈ 0.90
Therefore, given the volumetric efficiency of the pump and the volumetric efficiency of the motor, the speed ratio is 0.898, which is approximately 0.90.
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A student produces severa standing waves on string by adjusting the (requency vibration at ona end olthe string: The student measures the wavelength and frequency for each standing wave produced Which of the following procedures and calculations will allow the student I0 determine Ihe wave speed on the string? a.Graph function of 1\f The slope of the Iine equal t0 the wave speed;
b. Graph a5 a function of f The slope of the Ilne equal to he wave speed:
c. Graph A a5 function of 1\f The area under Ihe Iine I5 equal to Ihe wave speed d. Graph a5 a function of f The area under the line equal l0 Ihe wave speed
The correct option that allows the student to determine the wave speed on the string is d. Graph a5 a function of f The area under the line equal l0 Ihe wave speed.
Wave speed can be calculated by the formula: Wave speed (v) = frequency (f) × wavelength (λ) or v = fλ
According to the question, the student has measured the wavelength and frequency for each standing wave produced. Now, to determine the wave speed, the student needs to use the formula: v = fλ
To determine the wave speed from the graph of frequency and wavelength, the graph is made with frequency on the x-axis and wavelength on the y-axis. The slope of the line gives the speed of the wave. The graph can be used to calculate the wave speed for any wave by finding the slope of the line.
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how was the heliocentric theory developed by copernicus different from the greek theory of geocentrism?
The geocentric model says that the earth is at the center of the cosmos or universe, and the planets, the sun and the moon, and the stars circles around it. The early heliocentric models consider the sun as the center, and the planets revolve around the sun.
What allowed the Voyager 2 spacecraft to make a "tour" of all four of the jovian planets in the late 1970's and the 1980's?
1) NASA had developed a new kind of rocket that could propel the craft from planet to planet
2) the four planets were approximately aligned on one side of the Sun and we used the gravity of each planet to speed up the spacecraft to get to the next one in its path
3) the spacecraft stopped off to collect fuel on the satellites of each planet before proceeding to the next one
4) we used laser beams to propel the spacecraft into the outer solar system, where sunlight is dim
5) you can't fool me, no single spacecraft has ever explored four different planets
Answer:
The four planets were approximately aligned on one side of the Sun and we used the gravity of each planet to speed up the spacecraft to get to the next one in its path
Explanation:
All the Options 1, 2, 3, 4 are true about the Voyager 2 spacecraft to make a "tour" of all four of the jovian planets in the late 1970's and the 1980's.
The Voyager 2 spacecraft was able to make a "tour" of all four of the jovian planets in the late 1970's and the 1980's due to the following:
NASA had developed a new kind of rocket that could propel the craft from planet to planet.The four planets were approximately aligned on one side of the Sun and we used the gravity of each planet to speed up the spacecraft to get to the next one in its path.The spacecraft stopped off to collect fuel on the satellites of each planet before proceeding to the next one.We used laser beams to propel the spacecraft into the outer solar system, where sunlight is dim.Learn more about "NASA and spacecraft" at: https://brainly.com/question/16538247
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discuss whether the values found in parts (a) and (b) seem consistent with the fact that tidal effects with earth have caused the moon to rotate with one side always facing earth.
Yes, the values found in parts (a) and (b) are consistent with the fact that tidal effects with earth have caused the moon to rotate with one side always facing earth.
This is because part (a) states that the moon rotates on its axis in the same amount of time it takes to complete one orbit around the Earth, which is a phenomenon known as tidal locking. Part (b) further indicates that the same side of the moon always faces the Earth, further supporting the notion that tidal effects have caused the moon to rotate with one side always facing Earth.
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A spring attached to a mass is at rest in the initial position (not shown). The spring is compressed in position A and is then released, as shown in position B. Which equation describes the conservation of energy in position A?
[tex]E=\frac{1}{2} mv^{2} \\E=mgh\\E=\frac{1}{2} kx^{2} \\E=\frac{1}{2} k2kx^{2}[/tex]
Answer:
Explanation:
The energy conservation is equal to half of the product of the spring constant and the square of displacement of the spring, so option C is correct.
When you are inhaling, the intrapulmonary pressure is _____ than the atmospheric pressure.
When you are inhaling, the intrapulmonary pressure is less than the atmospheric pressure.
What is intrapulmonary pressure? Intrapulmonary pressure (P pulmonale) is the pressure inside the lungs, which decreases when the diaphragm and intercostal muscles contract, expanding the lung volume and lowering the air pressure inside the lungs.
The air is then compelled to move from the region of higher pressure outside the body to the region of lower pressure inside the lungs.
According to Boyle's law, which states that the pressure of a given mass of gas is inversely proportional to its volume at a fixed temperature, the decrease in intrapulmonary pressure during inhalation results in the air being drawn into the lungs.
What happens when we inhale? Inhalation, also known as inspiration, is the process of breathing in air, which involves the diaphragm contracting and flattening, and the intercostal muscles contracting to increase the thoracic cavity's size. This reduces intrapulmonary pressure and causes air to be drawn into the lungs.
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suppose the ring rotates once every 4.10 s . if a rider's mass is 51.0 kg , with how much force does the ring push on her at the top of the ride?
The ring rotates once every 4.10 s. If a rider's mass is 51.0 kg, how much force does the ring push on her at the top of the ride is 500 N.
The solution is explained below:
As the rider is at the top of the ride, the only force acting on him is the force of gravity, which is pointing downwards, and the force with which the ring is pushing him towards the center of the circular path. By equating both forces, we can determine the required force to maintain the rider at the top of the ride.
Hence, the answer to the question is that the force with which the ring pushes the rider at the top of the ride is equal to the force of gravity, which is given as F = mgF = (51.0 kg)(9.81 m/s^2) = 500 N
Therefore, the force with which the ring pushes on the rider at the top of the ride is 500 N.
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Categorize the following exercises as being isometric or isotonic.
Pushing constantly against a concrete wall
Running up a hill
Swimming freestyle
Pedaling a bicycle on a flat surface
Holding a bench-press bar in the same position
Doing a plank exercise (holding a push-up position)
Balancing on tiptoes
Doing bicep curls
Isometric pushes against a wall made of concrete, Isotonic running up a hill. isotonic freestyle swimming, bicycle pedalling on a level surface: isotonic.
Static muscle contractions, in which the length of the muscle does not change during the workout, are called isometric exercises. This indicates that during the activity, there is no discernible movement or alteration in joint angle. Instead, the muscles are tense against a constant force or maintained still for a certain period of time. Exercises that are isometric include pushing against a wall, keeping a plank position, and tightening a hand grasp. Exercises that are isometric can help to increase joint stability and balance as well as muscular strength and endurance. They can also be incorporated into normal workout routines for general health and strength training. They are frequently used in physical therapy to aid patients in recovering from injuries or surgery.
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a vhf television station assigned to channel 22 transmits its signal using radio waves with a frequency of 518 mhz. calculate the wavelength of the radio waves. round your answer to significant digits.
The wavelength of the radio waves is approximately 0.579 m or 57.9 cm
Wavelength is the distance covered by an electromagnetic wave while propagating through space. The relationship between the wavelength and the frequency of an electromagnetic wave is given by the formula;
Wavelength = speed of light / frequency = c / f
where c is the speed of light and f is the frequency of the wave.
To calculate the wavelength of a VHF television station assigned to channel 22 that transmits its signal using radio waves with a frequency of 518 MHz, we substitute the known values into the equation above.
Wavelength = c / f = (3 x 10⁸ m/s) / (518 x 10⁶ Hz) = 0.579 m or 57.9 cm (rounded to three significant digits)
Therefore, the wavelength of the radio waves transmitted by the VHF television station assigned to channel 22 is 0.579 m or 57.9 cm (rounded to three significant digits).
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polar stratospheric clouds are high-altitude clouds made of
Polar stratospheric clouds are high-altitude clouds made of tiny ice crystals that form in the lower stratosphere at very cold temperatures. They exhibit vivid iridescent colors and are associated with ozone depletion.
High-altitude clouds comprised of microscopic ice crystals are referred to as polar stratospheric clouds, nacreous clouds, or mother-of-pearl clouds. At heights of around 15,000 to 25,000 meters and extremely low temperatures of minus 80 to minus 85 degrees Celsius, they occur in the lower stratosphere. The refraction of sunlight as it passes through the ice crystals gives these clouds their distinctive dazzling and vibrant iridescent colors. Polar stratospheric clouds, which are linked to the ozone layer's thinning, are most frequently seen during the winter in polar locations like the Arctic and Antarctic.
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a series circuit has a capacitor of 1.25x10-5 farad, a resistor of 260 ohms and an inductor of 0.2 henry. the initial charge on the capacitor is 2x10-6 coulomb and there is no initial current. find the charge q(t) on the capacitor at any time t.
The final expression for the charge Q(t) at any time t is given as:Q(t) = CV(t) = 2.5 × 10^-11 e- t/RC
To find the charge on the capacitor at any time t, we need to find the total current in the circuit and then find the charge using the formula Q = CV, where V is the potential difference across the capacitor.Let's find the total current in the circuit using the formula:
I = (1/LC)½ x (e- Rt/2L) sin(wt - φ)
where, L = inductance C = capacitance R = resistance ω = (1/LC)½ = 5000 sinφ = RωL = 260 × 5000 × 0.2 = 2600
Let's now substitute the given values into the formula and simplify:I = (1/(0.2 × 1.25 × 10^-5))½ x (e- 260t/2 × 0.2) sin(5000t - φ)I = 10^5 x (e- 130t) sin(5000t - φ). Let's now find the charge Q on the capacitor using the formula:
Q = CV where, C = capacitance V = potential difference across the capacitor. To find the potential difference across the capacitor, we need to find the current passing through it, which is given as the total current minus the current passing through the inductor. Let's find the current passing through the inductor using the formula:
I L = I x sin(wt - φ)IL = I x sin(5000t - φ).The potential difference across the capacitor can be calculated using the formula:V C = V 0 × e- t/RC where, V0 = initial potential difference across the capacitor R = resistance of the circuit C = capacitance of the circuit. Let's now find the current passing through the capacitor:I C = (I - I L)I C = I - I L
Now we have all the necessary formulas to find the charge Q(t) at any time t. Let's substitute the given values into the formulas and simplify:
I = 10^5 x (e- 130t) sin(5000t - φ)IL = I x sin(5000t - φ)IC = I - I LVC = V0 × e- t/RCQ = CVCI = I - I L = 10^5 x (e- 130t) sin(5000t - φ) - I sin(5000t - φ)V C = V 0 × e- t/RC = 2 × 10^-6 e- t/RCQ = C × V C = (1.25 × 10^-5) × (2 × 10^-6) e- t/RC = 2.5 × 10^-11 e- t/RC
Now, let's substitute the values of I and V C into the formula for IC to obtain:IC = 10^5 × (e- 130t) sin(5000t - φ) - 10^5 sin(5000t - φ) × e- t/RC. Therefore final expression for the charge Q(t) at any time t is given as:Q(t) = CV(t) = 2.5 × 10^-11 e- t/RC
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We can use the equation [tex]q(t) = C.V(t)[/tex] to calculate the charge q (t) on the capacitor at any time t: [tex]q(t) = 1,25 . 10-5 Farad.V(t)[/tex].
The charge on a capacitor in a series circuit at any time t is given by the equation [tex]q(t) = C.V(t)[/tex], where C is the capacitance of the capacitor and V(t) is the voltage across the capacitor at time t.
In the given circuit, the capacitance of the capacitor is 1.25 x 10-5 Farad, and the initial charge on the capacitor is 2 x 10-6 Coulomb. Therefore, to find the charge q(t) on the capacitor at any time t, we need to find the voltage V(t) across the capacitor at time t.
To do this, we must first calculate the total inductance and resistance in the circuit. The total inductance is the sum of the inductances of each inductor, so the total inductance in this circuit is 0.2 Henry. The total resistance is the sum of the resistances of each resistor, so the total resistance in this circuit is 260 Ohms.
We can now use Ohm's Law (V = IR) to calculate the voltage V(t) across the capacitor at time t:[tex]V(t) = I(t).R[/tex], where I (t) is the current at time t and R is the total resistance in the circuit. Since the inductance of the circuit is 0.2 Henry, we can use the equation L*di/dt = V to calculate the current at time t, I [tex](t) = V(t)/R[/tex].
Substituting this into Ohm's Law, we get: V(t) = (V(t)/R)*R. Solving for V(t), we get V(t) = V(t). Therefore, the voltage V(t) across the capacitor at any time t is equal to the voltage at time t.
Finally, we can use the equation [tex]q(t) = C.V(t)[/tex]to calculate the charge q(t) on the capacitor at any time t: [tex]q(t) = 1,25 . 10-5 Farad.V(t)[/tex].
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A 900.0kg car is traveling at 11.0m/s. What is the momentum of this car?
The momentum of the car is 9900 kg m/s.
What is momentum?
The momentum of an object is defined as the product of its mass and velocity. In this case, the momentum of the car can be calculated using the following formula:
Momentum = mass x velocity
Here, the mass of the car is 900.0 kg and its velocity is 11.0 m/s. Substituting these values into the formula, we get:
Momentum = 900.0 kg x 11.0 m/s
Momentum = 9900 kg m/s
Therefore, the momentum of the car is 9900 kg m/s.
Note that the units of momentum are kilogram meters per second (kg m/s), which are derived from the units of mass (kg) and velocity (m/s). Momentum is a vector quantity, meaning it has both magnitude and direction, and its direction is the same as the direction of motion of the object.
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Can anyone help me please ..I need it hurry within 6 hrs.please.
Brainliest for the first best answer.
(i) Switch k1 is closed:
The current passing through the circuit is: 0.25 amps
R_total = R1 + R2 = 3 + 5 = 8 ohms
The current passing through the circuit is:
i = V / R_total = 2 / 8 = 0.25 amps
(ii) Switches k1 and k2 are closed:
The current passing through the circuit is: 1.07 amps
1/R_total = 1/R1 + 1/(R2 + R3) = 1/3 + 1/(5 + 0) = 8/15
R_total = 15/8 ohms
The current passing through the circuit is:
i = V / R_total = 2 / (15/8) = 1.07 amps
(iii) Switch k1 is open and k2 is closed:
The current passing through the circuit is: 1.07 amps
1/R_total = 1/R2 + 1/(R1 + R3) = 1/5 + 1/(3 + 0) = 1/5 + 1/3 = 8/15
R_total = 15/8 ohms
The current passing through the circuit is:
i = V / R_total = 2 / (15/8) = 1.07 amps
So the current passing through the circuit depends on which switches are closed, and can range from 0.25 amps to 1.07 amps.
What is current?
Crrent refers to the flow of electric charge through a conductor, such as a wire. It is measured in amperes (A) and is defined as the rate at which electric charge flows past a given point in a circuit. current is caused by the movement of charged particles, such as electrons or ions, through a conductor.
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A light bulb used in a slide projector draws a current of 6 amperes when operating on 120 volts.. the power consumed by th light bulb in watts is? B.)a light bulb used in a slide projector draws a cuurent of 6 amperes when operating on 120 volts. the resistance of the light bulb in ohms is?
a..05
b.20
c.720
d.none
When a light bulb used in a slide projector draws a current of 6 amperes while operating on 120 volts, the power consumed by the light bulb in watts is 720, and the resistance of the light bulb in ohms is 20. Thus, the correct option is B.
Why the resistance of a light bulb is 20 ohms?When we know that the current drawn by a light bulb is 6 amperes and the voltage applied to it is 120 volts, we can easily calculate the resistance of the light bulb, as follows:
Resistance (R) = Voltage (V) / Current (I)
here, V = 120V and I = 6A
Therefore, the resistance of the light bulb is:
R = V/I = 120/6 = 20 Ohms
The formula used to calculate the power (P) consumed by a light bulb is:
P = V × I
Here, the voltage (V) applied to the light bulb is 120 volts and the current (I) drawn by the light bulb is 6 amperes. So, the power consumed by the light bulb is:
P = 120 × 6 = 720 watts
Hence, the power consumed by the light bulb in watts is 720, and the resistance of the light bulb is 20 ohms.
Therefore, the correct option is B.
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Solve the circuit shown in the figure above, also explain how you did it
Answer:
Explanation:
Using Kirchhoff's laws, we can solve for the current i:
At the node where the 2Ω and 4Ω resistors meet, the current is split into two branches, i and i1. Applying Kirchhoff's current law (KCL), we have:
i + i1 = 12/2 = 6 A
At the loop with the 2Ω, 4Ω, and 5Ω resistors, applying Kirchhoff's voltage law (KVL), we have:
-20 + 2i + 4i1 + 5i1 = 0
-20 + 6i1 + 2i = 0
6i1 + 2i = 20
3i1 + i = 10
We can solve this system of equations by substitution, which gives:
i = 2 A
Therefore, the current through the 2Ω resistor is 2 A. The answer is (A) 2 A.
Ceteris paribus, which of these events would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall?
• A dcrease investor confidance
• A decrease in cosmetic income and wealth • A strengh of time preference
• A decrease in capital productivity
Ceteris paribus, a decrease in capital productivity is the event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. The correct answer is option C.
Ceteris paribus is a Latin expression that means "all other things being equal." Ceteris paribus is a model in which economists use to analyze the effect of one independent variable on a dependent variable while keeping all other independent variables constant. This implies that only one variable is allowed to change while all other variables are held constant at their current level or position.
Therefore, Ceteris paribus, an increase in investor confidence, an increase in cosmetic income and wealth, and a strength of time preference will not cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. However, a decrease in capital productivity is an event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall.
When capital productivity is low, firms are unable to produce goods and services efficiently, and as a result, the demand for investment falls. When the demand for investment falls, the equilibrium quantity of investment will also decrease, leading to a decrease in the equilibrium interest rate.
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determine the force p required to maintain equilibrium of the 186.7 lb container. report the force p in units of pounds to one decimal point.
The force p required to maintain the equilibrium of the 186.7 lb container is: 116.7 lb
The problem statement requires us to determine the force P required to maintain the equilibrium of the 186.7 lb container. The force P can be determined using the principle of static equilibrium.
Principle of Static EquilibriumThe principle of static equilibrium states that for an object to be in static equilibrium, the net force acting on the object must be zero and the net torque acting on the object must also be zero. This principle is based on Newton's laws of motion which state that the sum of forces acting on an object is equal to the mass of the object multiplied by its acceleration.
In other words, F = ma
Where F is the force acting on the object, m is the mass of the object, and a is the acceleration of the object. If the object is in static equilibrium, then a = 0.
Therefore, the net force acting on the object is zero. For the container to be in static equilibrium, we can apply the principle of static equilibrium to determine the force P required to maintain equilibrium. To do this, we need to find the forces acting on the container and the torques acting on the container.
Forces acting on the container: Weight of the container = 186.7 lb
Reaction force (upward force exerted by the ground on the container) = WReaction force (upward force exerted by the cable on the container) = P. For the container to be in static equilibrium, the net force acting on the container must be zero.
Therefore, W + W + P = 0P = -2W/3
Where W is the weight of the container.
Torques acting on the container: Torque due to the weight of the container = W*d
The torque due to the reaction force exerted by the cable on the container = P*L
Where d is the distance between the weight and the pivot point, L is the distance between the cable and the pivot point, and P is the force exerted by the cable on the container.
For the container to be in static equilibrium, the net torque acting on the container must be zero. Therefore,
[tex]W*d - P*L = 0P = W*d/L[/tex]
Where W is the weight of the container, d is the distance between the weight and the pivot point, and L is the distance between the cable and the pivot point.
Substituting the value of W in the above equation, we get
P = 186.7 lb * 5 ft / 8 ftP = 116.7 lb (approximately)
Therefore, the force P required to maintain the equilibrium of the 186.7 lb container is 116.7 lb (approximately).
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the end result of a theory that is not verified is
Unproven theories ultimately cannot be regarded as scientific facts or principles and are not generally recognised by the scientific community.
A well-supported explanation of a natural occurrence in science that has passed rigorous examination and is backed by empirical data is referred to as a theory. A hypothesis, however, cannot be regarded as a scientific fact or principle if it is not backed up by empirical data or if it has not undergone extensive testing and verification. The scientific community frequently rejects unproven notions with scant empirical backing and may even label them as pseudoscientific or non-scientific. This is so that scientific theories and findings may be evaluated and verified frequently. Science does this by using evidence-based reasoning and critical thinking. Unproven theories are therefore eventually not regarded as being a part of the corpus of scientific knowledge.
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A 2 kg object is released from rest near the surface of a planet such that its gravitational field is considered to be constant. The mass of the planet is unknown. The
object's speed after falling for 3 sis 75 m/s. Air resistance is considered to be negligible, Calculate the weight of the 2 kg object on the planet of unknown mass.
2N
B
25 N
50N
D
75 N
The magnitude of the force between two point charges 1. 0 m
apart is 9 x 10°n. If the distance between them is doubled,
what does the force become?
Force will become 2.25 x 10^N. because, According to Coulomb's Law, the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Thus, if the distance between two point charges is doubled, the force between them will decrease by a factor of 4. This is because the inverse square relationship means that the force decreases rapidly with distance. Therefore, if the force between two point charges is 9 x 10^N when they are 1 meter apart, when the distance is doubled to 2 meters, the force will become 9 x 10^N / 4 = 2.25 x 10^N.
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for the given input voltage amplitude (200 mvpp), what is the maximum gain that this amplifier will be able to produce? show your calculation below.
The maximum gain of an amplifier that produces an output voltage amplitude of 50 Vpp with an input voltage amplitude of 200 mVpp is 25. The formula to calculate gain is output voltage amplitude divided by input voltage amplitude.
In this case, we are given an input voltage of 200 mVpp, so the maximum gain of this amplifier can be calculated as follows:
Gain = Output Voltage/Input Voltage = Output Voltage/200 mVpp
Therefore, the maximum gain of this amplifier is equal to the output voltage. In other words, the maximum gain of this amplifier is equal to the voltage output of the amplifier.
To calculate the output voltage of the amplifier, we need to know the supply voltage and the resistance of the load. Assuming the supply voltage is 5V and the load resistance is 10k ohms, the output voltage can be calculated as follows:
Output Voltage = Supply Voltage * Load Resistance / (Load Resistance + Output Resistance) = 5V * 10k ohms / (10k ohms + 10k ohms) = 5V
Therefore, the maximum gain of this amplifier is 5V/200 mVpp = 25.
To summarize, the maximum gain of this amplifier is 25, calculated by dividing the output voltage by the input voltage. The output voltage can be calculated by knowing the supply voltage and load resistance.
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when a 2.75-kg fan, having blades 18.5 cm long, is turned off, its angular speed decreases uniformly from 10.0 rad/s to 6.30 rad/s in 5.00 s. (a) what is the magnitude of the angular acceleration of the fan?
The angular acceleration of the fan is 0.740 rad/s^2,
Angular acceleration which represents the rate at which the angular velocity changes over time. The unit used to measure angular acceleration is radians per square second (rad/s2), according to the International System of Units. The Greek alphabet symbol alpha (α) is used to denote angular acceleration.
To calculate the angular acceleration of the fan, the formula α = Δω/Δt is used. Here, α represents angular acceleration, Δω represents the change in angular speed, and Δt represents the change in time.
In this scenario, Δω is equal to 10.0 - 6.30 = 3.70 rad/s, and Δt is equal to 5.00 s. By substituting these values into the formula, we obtain α = 3.70/5.00 = 0.740 rad/s^2.
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