Answer this is an example 4 you
To do this problem, you need to change the way the fractions are displayed so that you can simplify them.
The first step is to change them to improper fractions: fractions like 4/3 that represent more than 100% (parts adding to more than one whole).
For example, to change the first fraction in this way, multiply the number in front (2) by the bottom number:
2 * 3 = 6
This means the 2 can also represent 6 / 3. Remember that 1 equals 3/3 so 2 equals 6/3. Now add this to the 1/3 you started with, and you end up with 7/3.
Do the same for the other fraction.
Now that you have both fractions written in this way, you can multiply each by the other's denominator to arrive at their LCD (least common denominator). It won't always be least, but you can always simplify further. In this case, the numbers are small enough that it likely won't matter.
You will end up with a fraction of halves: some number x, over 2, meaning x number of halves.
Your other fraction is 7/3. So the common denominator is the bottom numbers multiplied together: 2 * 3 = 6.
To change 7/3 to a fraction of sixths, you multiply the whole thing by two. This gets the bottom number to be six.
7 * 2 = 14
3 * 2 = 6
So this fraction can also be written as 14/6. Once again, do the same to the other fraction (but multiply by 3, to get the other fraction into sixths also, since it is currently halves).
Now you have two fractions that are both in parts of six. A ratio (x:y) is nothing more than a fraction itself. So if you had for example the ratio
2/5 : 10/5
This ratio could also be written as 1/5 : 5/5, or 1/5 to 1. Both numerators (the top number) are divisible by 2, so you can divide them both by 2 and end up with a simplified version of the same ratio.
Whatever ratio you end up with (14/6 : some other fraction), do the same thing to it. See if any of the numbers share a common factor, and simplify where possible. If it's not possible to simplify further, you're done.
One number is 9 times another. Their product is 27 times their sum. Find the numbers.
the answer is not 3 btw
Answer:
270 & 30
Step-by-step explanation:
let the number is n,
the equation :
n× 1/9 n= 27(n +1/9 n)
1/9 n² = 27n + 3n
1/9 n² = 30n
1/9n²- 30n = 0
n(1/9n -30)= 0
n = 0 or
1/9n = 30 => n = 30×9 = 270
270 is a number,
the other : 270/9 = 30
WILL GRANT BRAILIEST PLZ REAL ANSWERS ONLY OR REPORTING!
Hello,
If the question is simplify then
we suppose x not equal to 5 and x not equal to -5
[tex]\dfrac{x^2-10x+25}{(x-5)(x+5)} \\\\=\dfrac{(x-5)^2}{(x-5)(x+5)} \\\\=\dfrac{x-5}{x+5} \\\\[/tex]
else
if the question is to find the euclidian 's quotient then
[tex]\dfrac{x^2-10x+25}{(x-5)(x+5)} \\\\= 1 + \dfrac{-10x+30}{x^2-25} \\\\=1-\frac{10}{x+5} \\[/tex]
euclian's quotient is 1
remainder is -10/(x+5)
Helppp and explain pls and thankyou ,I will mark brainlist
Answer:
4x = 6 + x
3x = 6
x = 2
2 hours..$8
Step-by-step explanation:
Which of the following equations have no solutions?
Choose all answers that apply:
Α.
5x + 5 = -42 – 5
B
-4x + 5= -42 - 4
–4x + 5 = -4x – 5
D
4x + 5 = -4x + 5
Answer: b and c
a) 5x + 5 = -4x - 5
9x = - 10
x = -10/9
-
b) - 4x + 5 = -4x - 4
0x = -9 (no solution)
-
c) -4x + 5 = -4x - 5
0x = -10 (no solution)
-
d) 4x + 5 = -4x + 5
8x = 0
x = 0
-
hope it helps.
Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.
If you were asked to equate the sides of an equation, how would you do that
Answer:
you would divide an equation from the multiple and then you would simplify the equation for an answer
What is the value of the expression shown below?
(3/6) 2 + 7 x 4 -5
A 6 1/4
B 6 1/2
C 23 1/4
D 23 1/2
Answer:
24
Step-by-step explanation:
(3/6) 2 + 7 × 4 - 5
0.5 × 2 + 7 × 4 - 5
1 + 7 × 4 - 5
1 + 28 - 5
29 - 5
24
Answer this question plz
Answer:
i) 9xy
ii) 75
Step-by-step explanation:
i) add those factor
ii) get that factor
hope it helps
please mark as barinliest
Thankyou.. :)
Reese read twice as many pages Saturday than she read Sunday. If she read a total of 78 pages over the weekend, how many pages did Reese read Sunday?
Given:
Reese read twice as many pages Saturday than she read Sunday.
She read a total of 78 pages over the weekend.
To find:
The number of pages she read on Sunday.
Solution:
Let x be the number of pages she read on Sunday.
Reese read twice as many pages Saturday than she read Sunday. So, the number of pager she read on Saturday is 2x.
Total number of page she read over the weekend is:
[tex]Total=x+2x[/tex]
[tex]Total=3x[/tex]
She read a total of 78 pages over the weekend.
[tex]3x=78[/tex]
[tex]x=\dfrac{78}{3}[/tex]
[tex]x=26[/tex]
Therefore, Reese read 26 pages on Sunday.
find m to cos²x-(m²-3)sinx+2m²-3=0 have root
Answer:
[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex] would ensure that at least one real root exists for this equation when solving for [tex]x[/tex].
Step-by-step explanation:
Apply the Pythagorean identity [tex]1 - \sin^{2}(x) = \cos^{2}(x)[/tex] to replace the cosine this equation with sine:
[tex](1 - \sin^{2}(x)) - (m^2 - 3)\, \sin(x) + 2\, m^2 - 3 = 0[/tex].
Multiply both sides by [tex](-1)[/tex] to obtain:
[tex]-1 + \sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 3 = 0[/tex].
[tex]\sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 2 = 0[/tex].
If [tex]y = \sin(x)[/tex], then this equation would become a quadratic equation about [tex]y[/tex]:
[tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex].
[tex]a = 1[/tex].[tex]b = m^{2} - 3[/tex].[tex]c = -2\, m^{2} + 2[/tex].However, [tex]-1 \le \sin(x) \le 1[/tex] for all real [tex]x[/tex].
Hence, the value of [tex]y[/tex] must be between [tex](-1)[/tex] and [tex]1[/tex] (inclusive) for the original equation to have a real root when solving for [tex]x[/tex].
Determinant of this quadratic equation about [tex]y[/tex]:
[tex]\begin{aligned} & b^{2} - 4\, a\, c \\ =\; & (m^{2} - 3)^{2} - 4 \cdot (-2\, m^{2} + 2) \\ =\; & m^{4} - 6\, m^{2} + 9 - (-8\, m^{2} + 8) \\ =\; & m^{4} - 6\, m^{2} + 9 + 8\, m^{2} - 8 \\ =\; & m^{4} + 2\, m^{2} + 1 \\ =\; &(m^2 + 1)^{2} \end{aligned}[/tex].
Hence, when solving for [tex]y[/tex], the roots of [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] in terms of [tex]m[/tex] would be:
[tex]\begin{aligned}y_1 &= \frac{-b + \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) + \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) + (m^{2} + 1)}{2} = 2\end{aligned}[/tex].
[tex]\begin{aligned}y_2 &= \frac{-b - \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) - \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) - (m^{2} + 1)}{2} \\ &= \frac{-2\, m^{2} + 2}{2} = -m^{2} + 1\end{aligned}[/tex].
Since [tex]y = \sin(x)[/tex], it is necessary that [tex]-1 \le y \le 1[/tex] for the original solution to have a real root when solved for [tex]x[/tex].
The first solution, [tex]y_1[/tex], does not meet the requirements. On the other hand, simplifying [tex]-1 \le y_2 \le 1[/tex], [tex]-1 \le -m^{2} + 1 \le 1[/tex] gives:
[tex]-2 \le -m^{2} \le 0[/tex].
[tex]0 \le m^{2} \le 2[/tex].
[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].
In other words, solving [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] for [tex]y[/tex] would give a real root between [tex]-1 \le y \le 1[/tex] if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].
On the other hand, given that [tex]y = \sin(x)[/tex] for the [tex]x[/tex] in the original equation, solving that equation for [tex]x\![/tex] would give a real root if and only if [tex]-1 \le y \le 1[/tex].
Therefore, the original equation with [tex]x[/tex] as the unknown has a real root if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].
When do you need to state a domain in your final answer?
Answer:
Not sure what you are asking.
Domain is all x values .
It can be stated in coordinates (x,y). X is the input. Y is output
It can be stated in Domain Notations such as {x | x ≥ 0}
Which expression has a value of 15 when n = 7?
1: 43 minus 5 n
2: 3 n minus 5
3: 6 n minus 28
4: 19 minus StartFraction 28 Over n EndFraction
Answer:
[tex]19-\frac{28}{n}[/tex] is the expression with the value of 15 when n = 7
Step-by-step explanation:
To find the expression whose value is 15, substitute the value of n = 7 in each given expression.
Expression 1:
[tex]43-5n[/tex]
Substitute the value of n & simplify,
[tex]43-5(7)[/tex]
[tex]43-35=8[/tex]
Since the value of the expression is 8 which is not equal 15.
Hence expression [tex]43-5n[/tex] does not have value of 15 when n = 7.
Expression 2:
[tex]3n-5[/tex]
Substituting the value of n & simplify,
[tex]3(7)-5[/tex]
[tex]21-5=16[/tex]
Since the value of the expression is 16 which is not equal 15.
Hence expression [tex]3n-5[/tex] does not have value of 15 when n = 7.
Expression 3:
[tex]6n-28[/tex]
Substituting the value of n & simplify,
[tex]6(7)-28[/tex]
[tex]42-28=14[/tex]
Since the value of the expression is 14 which is not equal 15.
Hence expression [tex]6n-28[/tex] does not have value of 15 when n = 7.
Expression 4:
[tex]19-\frac{28}{n}[/tex]
Substituting the value of n & simplify,
[tex]19-\frac{28}{7}[/tex]
[tex]19-4=15[/tex]
Since the value of the expression is 15 which is equal 15.
Hence expression [tex]19-\frac{28}{n}[/tex] has the value of 15 when n = 7.
Find the length of the segment that joins the points (-5,4) and (7,-1)
Answer:
13
Step-by-step explanation:
Calculate the length using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (- 5, 4) and (x₂, y₂ ) = (7, - 1)
d = [tex]\sqrt{(7-(-5))^2+(-1-4)^2}[/tex]
= [tex]\sqrt{(7+5)^2+(-5)^2}[/tex]
= [tex]\sqrt{12^2+25}[/tex]
= [tex]\sqrt{144+25}[/tex]
= [tex]\sqrt{169}[/tex]
= 13
IM AM SO CONFUSED
Find the solution set.
8x2 - 2x – 1=0
Separate the two values with a comma.
Hello,
Answer (1/2,-1/4)
[tex]8x^2-2x-1=0\\\\8x^2-4x+2x-1=0\\\\4x(2x-1)+2x-1=0\\\\(2x-1)(4x+1)=0\\\\sol=\{\dfrac{1}{2} ,-\dfrac{1}{4} \}\\[/tex]
GIVING BRAINLIEST ANSWER PLZ ';CCC
Answer:
slope= difference in y ÷difference in x
=y-y1÷x-x1
=-3-(-1)÷-3-1
=-3+1÷-3-1
=-2÷-4
=1/2
Step-by-step explanation:
hope this is helpful
Y2 -Y1 ÷ X2-X1
-1 - 1 ÷ -3 - -3= 0.5 or 1/2
Help me please and thank you :)
Answer:
A
Step-by-step explanation:
We have the equation:
[tex]\displaystyle \frac{3}{8}y=2+x[/tex]
And we want to determine whether or not this represents a direct proportion.
First, let's solve for y. Multiply both sides by 8/3:
[tex]\displaystyle y=\frac{16}{3}+\frac{8}{3}x[/tex]
Remember that direct proportions must pass through the origin point on a graph. In other words, their y-intercept or constant value is zero.
Since the constant value here is not zero (it is 16/3), the equation is not direct proportion.
Our answer is A.
Solve the qn in attachment .
Answer:
[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]
Step-by-step explanation:
The given expression to us is ,
[tex]\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}[/tex]
Now take the LCM as ( x - 1 ) and Simplify , we have ,
[tex]\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}[/tex]
Simplifying further , we get ,
[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]
Hence the second option is correct.
Answer:
[tex] \frac{ \frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1} } \\ = \frac{ \frac{3 - 4(x - 1)}{x - 1} }{ \frac{2(x - 1)}{x - 1} } \\ = \frac{3 - 4x + 4}{2x - 2} \\ \frac{ - 4x + 7}{2(x - 1)} \\ option \: b \: is \: your \: answer \\ thank \: you[/tex]
Someone help me asap
Answer:
A
Step-by-step explanation:
There are 270 minutes in 4.5 hrs.
divide that by 45, you get 6.
50*3^6 is 36,450
An elevator is moving up at a rate of 5 feet each second. The elevator is now at street level. When will the elevator be 30 feet above street level? Write a division sentence using integers to represent this situation.
Answer:
Time = (30 ÷ 5) seconds
Step-by-step explanation:
It is moving up at the rate of 5 ft/s.
This means;
Distance moved ÷ time taken = 5 ft/s
Thus, for a distance of 30 ft above street level, the time taken will be calculated from
30 ÷ time taken = 5
Time to reach the given distance = 30 ÷ 5
In division sentence, it is composed of division symbol and equal to sign.
Question 22 (5 points)
If the legs of a right triangle are 20 units and 21 units, what's the length of the
hypotenuse?
29 units
4.4 units
6.4 units
22 units
through my working i got to 41² is the hypotenuse.
21²+20²=c²
factor out the square
(21+20)²=c²
41²=c²
and 41² is 1681
Answer:
29 units
Step-by-step explanation:
i just took the quiz
10 pointssss!!!!!:))
write the formula of the function y whose graph is shown.
a).
[tex]y = \frac{2}{x} [/tex]
b).
[tex]y = \frac{1}{ x } + 2[/tex]
c).
[tex]y = \frac{1}{x - 2} [/tex]
plss, I need helpp!!!!
9514 1404 393
Answer:
(a) y = 2/x
Step-by-step explanation:
The vertical and horizontal asymptotes are the axes, so there is neither a vertical nor a horizontal offset to the parent function y = 1/x. There is a vertical stretch by a factor of 2, so the describing function is ...
y = 2/x
Use the substitution method to solve the system of equations.
A. (5,-7)
B. (-1,-5)
C. (-1,5)
D. (2,-1)
Answer:
correct ans is d
Step-by-step explanation:
click the photo to see process
The pair of equations y = 0 and y = -7 has how many solutions?
Answer:
2 solutions so it can be inferred that it might be a quadratic
Step-by-step explanation:
Answer:
no solutions
Step-by-step explanation:
y = 0 and y = - 7 are horizontal parallel lines.
Since they are parallel, they never intersect and so have no solutions.
Three friends went to a book shop the first bought three bros and four pencils for $30.00. The second bought two Bros and five pencils for $27.00 . If the third bought a bro and a pencil only how much did they pay .
Answer:
total 66$
Step-by-step explanation:
let price of bro s be x and pencil be y
according to Qn
at 1 cond
3x+4=30____(1)
2x+5y=27____(2)
solve botth and get value of each bros and pencil and then at last add,30$,27$,6$,3$
Maths assignment
( x+y,x-y)=(3,1)
Step-by-step explanation:
I hope this will help you
If a circle has a diameter of 16 feet, which expression gives its area in square
feet?
A. 8^2•r
B. 16^2 •r
C.8•r
D. 16•r
Answer:
Area of a circle is denoted by: πr^2 where r is the radius of the circle. = 16/2 = 8 feet.
Step-by-step explanation:
Find the missing Angles
1. a = 68
b = 112
c = 68
2. a = 127
3. a = 35
b = 40
c = 35
d = 70
4. a = 20
b = 70
c = 20
d = 70
e = 110
5. a = 90
b = 90
c = 42
d = 48
e = 132
6. a = 70
b = 55
c = 25
Area of this figure
Tres ómnibus de tres empresas diferentes salen simultáneamente de la estación terminal a las 9 hs a que hora habrá una nueva Coincidencia si una empresa sale cada 90 minutos otro cada 120 minutos y el tercero cada 180 minutos
Respuesta:
3.00 p. M.
Explicación paso a paso:
El autobús sale en el Times simultáneamente a las 9 a.m.
Si cada autobús sale de la siguiente manera:
Bus A = cada 90 minutos
BUS B = cada 120 minutos
Bus C = cada 180 minutos
Para obtener la hora, los 3 buses volverán a salir simultáneamente:
Obtenga el mínimo común múltiplo de:
90 = 90, 180, 270, 360, 450, 540
120 = 120, 240, 360, 480, 600, 720
180 = 180, 360, 540, 720, 900
El mínimo común múltiplo es 360 minutos; por lo tanto, los 3 autobuses saldrán después de 360 minutos;
360/60 = 6 horas
9.00 a.m + 6 horas = 3.00 p.m
A farmer in China discovers a mammal
hide that contains 37% of its original
amount of C-14.
N = Noekt
No = inital amount of C-14 (at time
t=0)
N = amount of C-14 at time t
k= 0.0001
t = time, in years
Answer:
Step-by-step explanation:
I'm going to take a giant leap here and guess that you are looking for how old this mammal hide is. At least that's what I'm going to work out for you. Filling in the formula is relatively easy as long as we remember that the initial amount of hide was 100%:
[tex]37=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get
[tex].37=e^{-.0001t}[/tex] In order to get that t down from its current position, we have to take the natural log of both sides. The reason we do natural log as opposed to common log is because the natural log will cancel out the e:
[tex]ln(.37)=ln(e^{-.0001t})[/tex] and again, because the log cancels out the e we have:
ln(.37) = -.0001t and divide both sides by -.0001 to get
t = 9942.5 years
Answer:
answer is 9943
Step-by-step explanation:
The owner of a new pet store wishes to display tropical fish in display tanks. The above table shows the species that cannot live together. What is the minimum number of different tanks needed to safely house all the fish?
Answer:
The minimum number of different tanks needed to safely house all the fish is:
3 tanks.Step-by-step explanation:
To identify the minimum number of different tanks, we're gonna concentrate in a fish species, in this case can be the A: as you see in the table, the A species can live with all the fish excepting the F and G, by their side, the F and G can't live together , by this reason, this three species must live in a different tank, in the next form:
Tank 1: A Tank 2: F Tank 3: GNow the B species, it can live with A, F and G, but for this example we can put in the tank 1 (the tank of the A species). The C especies can live with A, F and G, but how we have A and B together, we're gonna put the C especies in the tank 3 (the tank of the G especies). The D species can live with A and G, we're gonna put in the tank 1 because can live with B species too. The E species can live with A and F, we're gonna put in the tank 2 (the tank of the F species) because the E species can't live with D that is in the in the tank 1. Al last, the H species just can live with A, E, F, and H species, by this reason, the only tank that can be put is the tank 2. In this form, the order is the next:
Tank 1: A, B, D. Tank 2: F, E, H. Tank 3: G, C.And the owner of the pet store must buy three different tanks to display these tropical fish.
