Answer:
2a^4c-2ac^2-15
Step-by-step explanation:
Sorry, I not sure if this is right or not cause I don't know if the exponent for -4a^4c is that or -4a^4c-15, but I'm just going to go with -4a^4c. However aside from that you just combine like terms.
Answer:
[tex]2a^4c-2ac^2-15[/tex]
Step-by-step explanation:
[tex]6a^4c+8ac^2-4a^4c-15-10ac^2[/tex]
We need to organize this expression into groups of like terms, so we can combine them easier. There are 2 groups of like terms,
[tex]6a^4c-4a^4c[/tex] and [tex]8ac^2-10ac^2[/tex]
[tex]6a^4c-4a^4c+8ac^2-10ac^2-15[/tex]
Add similar elements:
[tex]2a^4c+8ac^2-10ac^2-15[/tex]
Add, [tex]8ac^2-10ac^2=-2ac^2[/tex]
[tex]=2a^4c-2ac^2-15[/tex]
OAmalOHopeO
find m∠H
What does m∠H happened to equal
Answer:
[tex]m\angle H = 30^o[/tex]
Step-by-step explanation:
Given
See attachment
Required
Find [tex]m\angle H[/tex]
To calculate [tex]m\angle H[/tex], we make use of:
[tex]\cos(\theta) = \frac{Adjacent}{Hypotenuse}[/tex]
So, we have:
[tex]\cos(H) = \frac{GH}{HI}[/tex]
This gives:
[tex]\cos(H) = \frac{10\sqrt3}{20}[/tex]
[tex]\cos(H) = \frac{\sqrt3}{2}[/tex]
Take arccos of both sides
[tex]m\angle H = cos^{-1}(\frac{\sqrt3}{2})[/tex]
[tex]m\angle H = 30^o[/tex]
A student researcher compares the ages of cars owned by students and cars owned by faculty at a local state college. A sample of 187 cars owned by students had an average age of 7.9 years. A sample of 221 cars owned by faculty had an average age of 5.04 years. Assume that the population standard deviation for cars owned by students is 3.07 years, while the population standard deviation for cars owned by faculty is 2.53 years. Determine the 98% confidence interval for the difference between the true mean ages for cars owned by students and faculty. Step 3 of 3 : Construct the 98% confidence interval. Round your answers to two decimal places.
Answer:
Hence the confidence interval (2.2, 3.52).
Step-by-step explanation:
Hence,
The point estimate = [tex]\bar x_{1} - \bar x_{2}[/tex]
= 7.9 - 5.04
= 2.86
Given CI level is 0.98, hence α = 1 - 0.98 = 0.02
α/2 = 0.02/2 = 0.01, tc = t(α/2, df) = 2.326
Margin of Error
ME = tc x sp
ME = 2.326 \ 0.2817
ME = 0.6552
CI = ([tex]\bar x_{1} - \bar x_{2}[/tex] - tc x sp , [tex]\bar x_{1} - \bar x_{2}[/tex] + tc x sp)
CI = (7.9 - 5.04 - 2.326 x 0.2817 , 7.9 - 5.04 - 2.326 x 0.2817
CI = (2.2 , 3.52)
what is the relationship and what does X equal?
help! :)
Answer:
4x + 3 = 59
x = 14
Step-by-step explanation:
The vertical angles theorem states that when two lines intersect, the angles opposite each other are congruent. One can apply this here by stating the following:
4x + 3 = 59
Solve for (x), use inverse oeprations:
4x + 3= 59
4x = 56
x = 14
Answer:
Relationship : Vertical angle
Step-by-step explanation:
(4x + 3) = 59
4x = 59 - 3
4x = 56
x = 56/4
x = 14
What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?
1
–1
i
–i
Answer:
Answer is -1
Step-by-step explanation:
i1 = i
i2 = -1
i3 = -i
i4 = 1
i0 × i1 × i2 × i3 × i4 = 1 × i × (- 1) × (- i) × 1 = i2 = - 1
Answer:the answer is -1
Step-by-step explanation:
Type the correct answer in each box. Use numerals instead of words.
What is the equation of the quadratic function shown in the graph?
Answer:
y - 8 = -2(x + 1)^2
Step-by-step explanation:
The vertex of this parabola is (-1, 8). It opens downward, so the x^2 term has a negative coefficient. The zeros are (-3, 0) and (1, 0), and the y-intercept is (0, 7).
Through the vertex form of the equation of a parabola we get:
y - (8) = a(x - (-1)) + 7, or
y - 8 = a(x + 1)^2. Find coefficient a by substituting the coordinates (-3, 0) in this equation:
0 - 8 = a(-3 + 1)^2, or
-8 = a(-2)^2, or a = -2
The desired equation is
y - 8 = -2(x + 1)^2
x^{2}[(y'−x^{2})+3xy=cosx, (x>0)
The given differential equation is
x ² (y' - x ²) + 3xy = cos(x)
Expanding and rearranging terms, we get
x ² y' + 3xy = cos(x) + x ⁴
Multiply both sides by x, which is motivated by the fact that (x ³)' = 3x ².
x ³ y' + 3x ²y = x cos(x) + x ⁵
The left side is the derivative of a product:
(x ³y)' = x cos(x) + x ⁵
Integrate both sides with respect to x :
∫ (x ³y)' dx = ∫ (x cos(x) + x ⁵) dx
x ³y = cos(x) + x sin(x) + 1/6 x ⁶ + C
Solve for y. Since x > 0, we can safely divide both sides by x ³.
y = cos(x)/x ³ + sin(x)/x ² + 1/6 x ³ + C/x³
Which of the following
statements is true about
angle K?
K
R
a. Angle K is obtuse
b. angle K is acute
c. angle K is greater than
90
d. angle K is a right angle
Answer:
angle k is acute.
Step-by-step explanation:
it is less than 90 degrees
Answer:
a., b.
Step-by-step explanation:
Angle K looks like an acute angle with measure between 0 and 90 degrees.
Answer: a., b.
Find an equation of the line through these points (15,2.2) (5,1.6). Write answer in a slope-intercept form
Answer:
[tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}[/tex]
Step-by-step explanation:
Hi there!
Slope-intercept form: [tex]y=mx+b[/tex] where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept (the value of y when x is 0)
1) Determine the slope (m)
[tex]m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1}[/tex] where two given points are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug in the given points (15,2.2) and (5,1.6):
[tex]m=\frac{\displaystyle 1.6-2.2}{\displaystyle 5-15}\\\\m=\frac{\displaystyle -0.6}{\displaystyle -10}\\\\m=\frac{\displaystyle 0.6}{\displaystyle 10}\\\\m=\frac{\displaystyle 0.3}{\displaystyle 5}\\\\m=\frac{\displaystyle 3}{\displaystyle 50}[/tex]
Therefore, the slope of the line is [tex]\frac{\displaystyle 3}{\displaystyle 50}[/tex]. Plug this into [tex]y=mx+b[/tex]:
[tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+b[/tex]
Plug in a given point and solve for b:
[tex]1.6=\frac{\displaystyle 3}{\displaystyle 50}(5)+b\\\\1.6=\frac{\displaystyle 3}{\displaystyle 10}+b\\\\1.6-\frac{\displaystyle 3}{\displaystyle 10}=\frac{\displaystyle 3}{\displaystyle 10}+b-\frac{\displaystyle 3}{\displaystyle 10}\\\\\frac{\displaystyle 13}{\displaystyle 10}=b[/tex]
Therefore, the y-intercept is [tex]\frac{\displaystyle 13}{\displaystyle 10}[/tex]. Plug this back into [tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+b[/tex]:
[tex]y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}[/tex]
I hope this helps!
PLEASE HELP
Complete the table to find the different combinations of coin quantities that have a sum of $2.41. (See photo above)
Answer:
1st row 56 pennies
2nd row 36 pennies
3rd row 14 dimes
4th row 4 quarters
5th row 5 nickels
Step-by-step explanation:
1st row $1.85 + 56 cents = $2.41
2nd row $2.05 + 36 cents = $2.41
3rd row is $1.01 + $1.40 = $2.41
4th row $1.41 + $1.00 = 2.41
5th row $2.16 + 25 cents = $2.41
Which set of angles are supplementary
The table below shows the age of some participants in a quiz competition and the number of questions they could answer correctly: Age (years) (x) 15 21 17 22 16 19 18 Number of questions they could answer (y) 17 17 17 17 17 17 17 What is the correlation coefficient for the data, and what does it represent? (5 points) 0; it represents no correlation between x and y 1; it represents a linear positive correlation between x and y −1; it represents a linear negative correlation between x and y 1; it represents a linear negative correlation between x and y
Your answer is:
A) 0; it represents no correlation between x and y
keep dreaming
A certain brand of coffee comes in two sizes. An 11.5-ounce package costs $.4.24 . A 27.8-ounce package costs $9.98.
Find the unit price for each size. Then state which size is the better buy based on the unit price.
Round your answers to the nearest cent.
Answer:
Small (11.5) is 37 cents per ounce.
Large (27.8) is 36 cents per ounce.
27.8 ounces is the better buy.
A scientist runs an experiment involving a culture of bacteria. She notices that the mass of the bacteria in the culture increases exponentially with the mass increasing by 249% per week. What is the 1-week growth factor for the mass of the bacteria
9514 1404 393
Answer:
3.49
Step-by-step explanation:
The growth factor is one more than the growth rate:
growth factor = 1 + growth rate
= 1 + 249% = 1 +2.49
growth factor = 3.49
Roll a pair of fair dice. Let X be the number of ones in the outcome and let Y be the number of twos in the outcome. Find E[XY].
Answer:
E(XY)=1/18
Step-by-step explanation:
x y P(x,y) xy*P(X,Y)
0 0 4/9 0
0 1 2/9 0
1 0 2/9 0
1 1 1/18 1/18
2 0 1/36 0
0 2 1/36 0
1 1/18
from above:
E(XY)=1/18
Norman and Suzanne own 35 shares of a fast food restaurant stock and 63 shares of a toy company stock. At the close of the markets on a particular day in 2004, their stock portfolio consisting of these two stocks was worth $1596.00. The closing price of the fast food restaurant stock was $19 more per share than the closing price of the toy company stock on that day. What was the closing price of each stock on that day? The price per share of the fast food restaurant stock is
Answer:
closing price of the fast food stock was $997.50
closing price of the toy company stock was $598.50
the price per fast food share was $28.50
Step-by-step explanation:
x = price per share fast food
y = price per share toy company
35x + 63y = 1596
x = y + 19
=>
35(y+19) + 63y = 1596
35y + 665 + 63y = 1596
98y + 665 = 1596
98y = 931
y = $9.50
=>
x = 9.5 + 19 = $28.50
the value of the whole fast food stock was
35x = 35×28.5 = $997.50
the cake if the whole toy company stock was
63y = 63×9.5 = $598.50
y+2 2y2-y+3 y-2
In the equation
1,2 - 1
+
the value of a is:
„V+1
1 - ע
Answer:
The answer:
I think the choose (1) 1
sin x =.3 what is the cos x =?
Answer:
If you're asking what cosine 3 is it's 0.9999986292247
Step-by-step explanation:
I don't really understand the question
Safety regulations require that the time between airplane takeoffs (on the same runway) will be at least 2 minutes. When taking off, the run time of an airplane on the runway is 27 seconds. Planes are on average waiting 4 minutes and 21 seconds for take-off. On average there are 21 planes taking off per hour. How many planes are either on the runway or waiting to take off
Answer:
Number of planes on the runway or waiting to take off is approximately 2
Step-by-step explanation:
Given the data in the question;
On average there are 21 planes taking off per hour
rate of flow = frequency of take off = 21 planes / hr
= 21 planes per 60 minutes
= 0.35 planes/min
Now, we get the throughput time
throughput time = total time for take off = waiting time on runway + run time on runway
= (4 minutes and 21 seconds) + 27 seconds
= 4.35 minutes + 0.45 minutes
= 4.8 minutes
Now, using Little's law;
Number of planes on the runway or waiting to take off will be;
N = Rate of flow × throughput time
we substitute
N = ( 0.35 planes/min ) × 4.8 min
N = 1.68 planes ≈ 2 planes
Therefore, Number of planes on the runway or waiting to take off is approximately 2
Evaluate I=∫(sinx+9y)dx + (4x+y)dy for the nonclosed path ABCD in the figure.
Close the path by connecting D to A. Then by Green's theorem, the integral over the closed path ABCDA - which I'll just abbreviate C - is
[tex]\displaystyle \oint_C (\sin(x)+9y)\,\mathrm dx + (4x+y)\,\mathrm dy \\\\ = \iint_{\mathrm{int}(C)}\frac{\partial(4x+y)}{\partial x} - \frac{\partial(\sin(x)+9y)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = -5\iint_{\mathrm{int}(C)}\mathrm dx\,\mathrm dy[/tex]
(where int(C ) denotes the region interior to the path C )
The remaining double integral is -5 times the area of the trapezoid, which is
[tex]\displaystyle -5\iint_{\mathrm{int}(C)}\mathrm dx\,\mathrm dy = -\frac52\times(12+4)\times4=-160[/tex]
To get the line integral you want, just subtract the integral taken over the path DA. On this line segment, we have x = 0 and dx = 0, so this integral reduces to
[tex]\displaystyle\int_{DA}y\,\mathrm dy = \int_{12}^0y\,\mathrm dy = -\int_0^{12}y\,\mathrm dy = -72[/tex]
Then
[tex]\displaystyle \int_{ABCD} (\sin(x)+9y)\,\mathrm dx + (4x+y)\,\mathrm dy = -160 - (-72) = \boxed{-88}[/tex]
If 1 kilogram (kg) is equal to about 2.2046 pounds (lbs.), what is the value of 1kg/2.2046lbs? What is the value of 2.2046lbs/1kg?
Step-by-step explanation:
The relation between kg and lbs is :
1 kg = 2.2046 lbs
We need to find the values of 1kg/2.2046lbs and 2.2046lbs/1kg.
So,
[tex]\dfrac{1\ kg}{2.2046\ lbs}=\dfrac{2.2046\ lbs}{2.2046\ lbs}\\\\=1[/tex]
and
[tex]\dfrac{2.2046\ lbs}{1\ kg}=\dfrac{2.2046\ lbs}{2.2046\ lbs}\\\\=1[/tex]
Hence, this is the required solution.
Answer:
Both are same as 1.
Step-by-step explanation:
1 kg = 2.2046 lbs
So,
[tex]\frac{1 kg}{2.2046 lbs }=\frac{1 kg }{1 kg} = 1[/tex]
And
[tex]\frac{2.2046 lbs}{1 kg }=\frac{1 kg }{1 kg} = 1[/tex]
Three ounces of cinnamon cost $2.40. If there are 16 ounces in 1 pound, how much does cinnamon cost per pound?
Based on the graph, what is one solution to the equation f(x) = g(x)?
x= -4
x = 2.5
x= -5.1
x = 2.75
Answer:
x= -5.1
Step-by-step explanation:
The solution to f(x) = g(x) is where to two graphs intersect
The graphs meet at
about x=2 and x = -5
The best answer listed is x = -5.1
Answer:
x = −5.1
Step-by-step explanation:
I took the practice test
0.45 0.40 0.11 This question uses the following probability model for the blood type of a randomly chosen person in the United States: Maria has type A blood. She can safely receive blood transfusions from people with blood types O and A. The probability that a randomly chosen American can donate blood to Maria is ______. (Give your answer to 2 decimal places.)
Answer:
[tex]P(O\ or\ A) = 0.85[/tex]
Step-by-step explanation:
Given
See attachment
Required
[tex]P(O\ or\ A)[/tex]
From the question, we understand that she can only get blood from O or A groups. So, the probability is represented as:
[tex]P(O\ or\ A)[/tex]
This is calculated as:
[tex]P(O\ or\ A) = P(O) + P(A)[/tex]
Using the American row i.e. the blood must come from an American.
We have:
[tex]P(O) = 0.45[/tex]
[tex]P(A) = 0.40[/tex]
So, we have:
[tex]P(O\ or\ A) = 0.45 + 0.40[/tex]
[tex]P(O\ or\ A) = 0.85[/tex]
annual cost of 35,000 expected to save 40,000 during the first year how many months will the take to recover investment
Answer:
500000
Step-by-step explanation:
A formula for the normal systolic blood pressure for a man age A, measured in mmHg, is given as P = 0.006A*2-0.02A + 120. Find the age of a man whose normal blood pressure measures 129 mmHg. Round your answer to the nearest year. The man would be ? years old.
Answer:
The man would be 40 years old.
Step-by-step explanation:
Blood pressure as function of age:
Is given by the following equation:
[tex]P = 0.006A^2 - 0.02A + 120[/tex]
Find the age of a man whose normal blood pressure measures 129 mmHg.
This is A for which P = 129. So
[tex]129 = 0.006A^2 - 0.02A + 120[/tex]
[tex]0.006A^2 - 0.02A - 9 = 0[/tex]
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]
[tex]\Delta = b^{2} - 4ac[/tex]
In this question:
Quadratic equation with [tex]a = 0.006, b = -0.02, C = -9[/tex]. So
[tex]\Delta = (-0.02)^2 - 4(0.006)(-9) = 0.2164[/tex]
[tex]A_{1} = \frac{-(-0.02) + \sqrt{0.2164}}{2*(0.006)} = 40.4[/tex]
[tex]A_{2} = \frac{-(-0.02) - \sqrt{0.2164}}{2*(0.006)} = -37.1[/tex]
Age has to be a positive number, so rounding to the nearest year:
The man would be 40 years old.
Suppose f"(x) = -9 sin(3x) and f'(0) = -4, and f(0) = -2
Find f(pi/4)
Answer:
9sin (3)and f,(0)=4,AND f(0)=2
the diameter of a circle is 7 inches.find it's area to the nearest 10th
Answer: d=7 inches
r=7/2
r=3.5
A=πr²
A=3.14(3.5inch)²
A=3.14×12.25inch²
A=38.465inch²
A≈38.47inch²
Select the correct answer.
Given the following formula, solve for a.
Answer: option C is correct
Step-by-step explanation:[tex]s=( \alpha +\beta +c)/2\\2s=\alpha +\beta +c\\2s-\beta -c=\alpha \\\alpha =2s-\beta -c[/tex]
The minimum number of parallel faces that a prism should have is
Answer:
The minimum number of parallel faces that a prism should have is three pairs
Answer:
The minimum number of parallel faces that a prism should have is three faces
Expresa de. Forma fraccionaria y decimal 7%
Answer:
7% = .07 = [tex]\frac{7}{100}[/tex]
Step-by-step explanation:
